Dynkin Serre Weyl
|
|
- みりあ くまじ
- 5 years ago
- Views:
Transcription
1 Dynkin Naoya Enomoto paper Dynkin Introduction Dynkin Lie Lie paper 1 0 Introduction 3 I ( ) Lie Dynkin 4 1 ( ) Lie Lie ( ) Killing form sl 2 (C) ( ) Lie Cartan ( ) Killing ( ) sl Dynkin Dynkin henon@s00x0427.mbox.media.kyoto-u.ac.jp 1 1
2 Dynkin Serre Weyl A n 1 sl n B n so 2n C n sp 2n D n so 2n G E 6, E 7, E 8, F II Dynkin Dynkin 32 III Dynkin 32 7 SO(3) 32 IV Dynkin 32 V Quiver Dynkin 32 VI Painlevé Dynkin 32 2
3 0 Introduction 3
4 I ( ) Lie Dynkin Dynkin Lie Dynkin 1 ( ) Lie ( ) Lie ( ) Killing sl 2 (C) 1.1 Lie ( ) Lie Lie 1.1. ( ) g Lie g [, ] : g g C (L1)[ ] [x, y] = [y, x] (L2)[Jacobi ] [x, [y, z]] + [y, [z, x]] + [z, [x, y]] = 0 (x, y, z g) (1.1) Lie (1) g 1, g 2 Lie f([x, y]) = [f(x), f(y)] f : g 1 g 2 Lie V End(V ) [A, B] := AB BA Lie f : g End(V ) Lie Lie g (2) g ad : g End(g); g ad g = [g, ] (1.2) g g (3) Lie g h [h, h] h Lie g a [g, a] a a g (4) g [x, y] = 0 Lie Lie Lie Lie Lie 1.3. Lie Lie (1) Lie (2) (3) 3 (4) Lie g g = a 0 a 1 a 2 a r = {0} a i /a i+1 Lie g Lie 4 Lie g τ(g) g 4
5 ( 5 )Lie 1.4. gl n (k) Lie sl n (k) := {x gl n (k) tr(x) = 0} (1.3) so n (k) := {x gl n (k) t x + x = 0} (1.4) sp 2m (k) := {x gl 2m (k) t xj + Jx = 0} (n = 2m) (1.5) J = ( 0 E m E m 0 ) 1.2 Killing form g Killing g ( ) 1.5. Lie g ( ), g- [x, y], z = x, [y, z] Rad, := {x g g y x, y = 0} Rad, = {0}, Remark 1.6., Rad, (ad, g) g Lie Rad, = g {0}, (g, V ) Lie B V (x, y) := tr(π(x)π(y)) (x, y g) g ad B(x, y) := tr(ad x ad y ) (x, y g) (1.6) g Killing 1.8. Cartan s criterion Lie g (1) g (2) Killing B Cartan Lie Remark Schur 1.9. g Lie g Killing 5 n 5
6 [ ] g 2 0 g Remark g = g g g Schur Schur Schur (g, V ) End g (V ) = C Id V g End g (g) = C Id g [ ] T End(V ) T λ v( 0) 1 T v = λv T := T λid V T End(V ) Ker T V V {0} 0 v Ker T Ker T = V T = 0 T = λid V g 1.3 sl 2 (C) sl 2 (C) Lie Lie sl 2 sl 2 = {X M 2 (K) tr X = 0} Lie 3 ( ) ( ) ( e =, f =, h = ) (1.7) [h, e] = 2e, [h, f] = 2f, [e, f] = h (1.8) sl 2 (C) ( ) sl 2 (C) (sl 2, V ) h v hv = cv ev, fv c + 2, c 2 (sl 2, V ) (1) V h ev 0 = 0 v 0 ( ) (2) v 0 ( ) n n Z 0 dim V = n + 1 sl 2 [ ] [ ] h(ev) = ([h, e] + eh)v = 2ev + cev = (c + 2)ev, h(fv) = ([h, f] + fh)v = 2fv + cv = (c 2)v h v {v, ev, e 2 v, } V 0 e k+1 v = 0 v 0 := e k v 6
7 ev 0 = 0 h n {v 0, fv 0, f 2 v 0, } r f r+1 v 0 = 0 f r v 0 0 {f i v 0 i r} sl 2 - V V = r i=0 C(f i v 0 ) v i = f i v 0 0 = (ef r+1 r r+1 e)v 0 ( f r+1 v 9 = fv r = 0, ev 0 = 0) = [e, f r+1 ]v 0 = (r + 1)(h r)v 0 ( [e, f k ] = k(h (k 1)) ) = (r + 1)(n r)v 0 v 0 0 (r + 1)(n r) = 0 r 0 r n = r dim V = r + 1 = n + 1 (1)(2) [ ] Remark [e, f k ] = k(h (k 1)) hf = f(h 2), (h + 2)f = fh [e, f n ] = [e, f]f n 1 + f[e, f]f n f n 1 [e, f] = hf n 1 + fhf n f n 1 h ( [e, f] = h) = hf n 1 + (h + 2)f n (h + 2(n 1))f n 1 ( f ) = (nh + n(n 1))f n 1 = nf n 1 (h 2(n 1) + (n 1)) ( f ) = nf n 1 (h (n 1)) Remark sl 2 h e Cv 0 f Cv 1 fig. Cv 2 sl 2 Cv r Remark
8 m( ) m( ) e f k m k m V m k 0 k 1 k 2 k 3 V 3 V 2 V 1 V 0 V [0] V [1] V [2] V [3] V [m] V [m] V = V m, V = m Z V k m = dim V [m] m=0 V [m] dim V 0 = k m, dim V 1 = m:even m:odd m k m 2 ( ) Lie Lie Killing sl Cartan ( ) Lie Lie 2.1. g Lie h Cartan 2 (1) h (2) g ad H (H h) Remark 2.2. Cartan 2 Cartan h 1, h 2 6 ϕ Inn(g) ϕ(h 1 ) = h 2 Cartan g 6 8
9 ad(h) gl(g) g ad(h) (root space decomposition) x g ad(h) [h, x] = λ h x λ h = α(h) α : h h λ h C α h (h ) α g α = {x g [h, x] = α(h)x h h} 2.3. Φ = {α h α 0, g α {0}} α Φ g g α α g ad(h) ( ) g = g 0 g α Remark 2.4. g 0 X g [h, X] = 0 ( h h) h g 0 h h = g 0 ( ) g = h g α α Φ α Φ 2.2 ( ) Killing Killing g Lie Cartan h g ( ) g = h g α α Φ 2.5. (1) [g α, g β ] g α+β (2) dim g α = dim g α (3) Killing B g α g α := {x g B(x, y) = 0 y g α } g α = β α g β (4) B h B h h 9
10 [ ] (1) B h h, x g α, y g β [h, [x, y]] = [[h, x], y] + [x, [h, y]] ( Jacobi ) = [α(x)x, y] + [x, β(h)y] ( x g α, y g β ) = (α(h) + β(h))[x, y] = (α + β)(h)[x, y] (2),(3) (1) x g α, y g β ad(x) ad(y)g γ = [x, [y, g γ ]] g α+β+γ g ad(x) ad(y) α + β 0 0 β α B(x, y) = tr(ad(x) ad(y)) = 0 g β g α g α β α g β dim g = n B dim g α = n dim g α g α β α g β dim g α β α dim g β = n dim g α dim g α dim g α α α (2) dim g α = dim g β (3) (4) (3) α = 0 β α h = α Φ g α h h = {0} (4) Remark 2.6. (1) α, β Φ α + β Φ g α+β = 0 Hom(V V, C) = Hom(V, V ) {V } {V = V } 10
11 B h h φ h 1 t φ h B(t φ, h) = φ(h) Killing sl (1) Φ h dim h = j Φ j 1 (2) α Φ α Φ (3) α Φ, x g α, y g α [x, y] = B(x, y)t α (4) α Φ dim([g α, g α ]) = 1 t α (5) α Φ α(t α ) = B(t α, t α ) 0 (6) α Φ 0 x α g α y α g α x α, y α, h α = [x α, y α ] 3 Lie sl 2 (C) Lie 2t α (7) h α = B(t α, t α ), t α = t α α(h α ) = 2 [ ] (1) Φ h g C g C Φ β 1,, β k h 1,, h k h h 1,, h j x 1 β i (h 1 ) + + x j β i (h j ) = 0 (1 i k) k(< j) x 1,, x j C = x 1 h x j h j 0 C h α(c) = 0 ( α Φ) g g g g = h + α Φ g α [C, g] = [C, h] + α [C, g α ] = [C, h] + α α(c)g α = 0 [C, g] = 0 H g (2) dim g α = dim g α α Φ dim g α 0 dim g α 0 α Φ (3) α Φ, x g α, y g α h h B(h, [x, y]) = B([h, x], y) ( B ) = α(h)b(x, y) ( x g α ) = B(t α, h)b(x, y) ( t α ) = B(B(x, y)t α, h) [x, y] g 0 = h, B(x, y)t α h [x, y] B(x, y)t α h h B h h [x, y] = B(x, y)t α (4) (3) [g α, g α ] t α [g α, g α ] 0 0 x g α B(x, g α ) = 0 B(x, g) = 0 B B(x, y) 0 y g α [x, y] = B(x, y)t α 0 (5) α(t α ) = 0 x g α, y g α [t α, x] = α(t α )x = 0, [t α, y] = α(t α )y = 0 x, y (4) B(x, y) 0 B(x, y) = 1 [x, y] = t α S = x, y, t α g 3 Lie 11
12 [S, S] = t α [g, DS] = 0 S Lie ad(t α ) t α h Cartan ad(t α ) ad(t α ) = 0 t α = 0 α = 0 (6) 0 x α g α y g α B(x α, y α ) = 2 B(t α, t α ) (5) B(t α, t α ) 0 (4) B(x, y) 0 (3) h α = 2t α B(t α, t α ) [x α, y α ] = B(x α, y α )t α = h α [h α, x α ] = 2 α(t α ) [t α, x α ] = 2 α(t α ) α(t α)x α = 2x α [h α, y α ] = 2y α S α = x α, y α, h α = sl 2 (7) h α α(h α ) = 2 α(t α ) α(t α) = 2 h h B(t α, h) = α(h) B t α = t α B(t α + t α, h) = α(h) α(h) = ( ) sl 2 g sl S α = x α, y α, h α = sl 2 (1) α Φ dim g α = 1 0 x α x α x α [x α, y α ] = h α y α g α (2) α φ cα Φ c = ±1 (3) α, β Φ β(h α ) Z β β(h α ) Φ (4) α, β, α + β Φ [g α, g β ] = g α+β (5) α, β Φ β ±α p, q Z β pα, β + qα Φ p i q i β + iα Φ β(h α ) = p q (6) g Lie {g α } α Φ [ ] (1),(2) (3) (6) sl 2 (1),(2) STEP.1 sl 2 M 12
13 M = h c 0 g cα x α, y α, h α S α = sl2 X, Y, H sl 2 ad xα, ad yα, ad hα g sl 2 - M g sl 2 - m M m = j m j (m j g cj α c j = 0 h ) ad(h α )(m) = [h α, m] = j [h α, m j ] = j c j α(h α )m j M ad(x α )(m) = [x α, m] = j [x α, m j ] g α+cj α ad(y α )(m) = [y α, m] = j [y α, m j ] g α+cj α M sl 2 STEP.2 2c Z ad hα v g cα ad(h α )(v) = [h α, v] = cα(h α )v = 2cv 2c Z STEP.3 (1),(2) V m, V [m], k m M Remark1.14 h V 0 = h g k/2 = V k V ±2 = g ±α h α h V [0] h h α h t α h α α(h) = B(t α, h) = 0 α(h) = 0 [x α, h] = α(h)x α = 0 [y α, h] = 0 h 1 h V [0] dim h = l h α h - l 1 h α h l 1 V [0] = k 0 h α, x α, y α = S α V [2] 1 V [2] = k 2 l = dim h = dim V 0 = m:even k m k 0 = l 1, k 2 = 1, k m = 0 (m : even, m 4) dim g α = dim V 2 = k 2 + k 4 + = 1 dim g 2α = dim V 4 = k 4 + k 6 + = 0 dim g 3α = dim V 6 = k 6 + k 8 + = 0 2α, 3α, 2α, 3α, 1 2α 2 α 1 2 α 0 = dim g (1/2)α = dim V 1 = m:odd k m 13
14 (1),(2) k m = 0 (m : odd) (3) (6) sl 2 β ±α K = i Z g β+iα sl 2 - g β+iα {0} i dim g β+iα = 1 (1) g β+iα 0 β(h α ) + 2i i Z 0 1 i 1 i 2 ad hα m, m 2,, m p, q β + iα β pα,, β + qα (β(h α ) + 2q) = β(h α ) 2p β(h α ) = p q (5) p q p q β β(h α )α = β (p q)α (3) (4) dim g α+β = 1 ad xα (g β ) {0} (6) h [x α, y α ] = h α 2.4 g Lie h Cartan g ( ) g = h g α Φ h α 1,, α r Φ h g Killing form B (α, β) := B(t α, t β ) h (, ) t α α(h) = B(t α, h) ( h h) h β Φ k β = c i α i α Φ 2.9. c i Q Proof k (β, α j ) = c i (α i, α j ) (j = 1, 2,, k) 14
15 β(h α ) Z 2(β, α j ) k (α j, α j ) = 2(α i, α j ) (α j, α j ) c i (j = 1, 2,, k) ( ) 2(β, α) (α, α) = 2β(t α) B(t α, t α ) = β(h α) Z ( ) B α 1,, α k h ( ) c i Q ad h h 0- g α α(h) B(h, h ) = tr(ad h ad h ) = α Φ α(h)α(h ) γ, δ h (γ, δ) = α φ α(t γ )α(t δ ) = α Φ(α, γ)(α, δ) β Φ (β, β) = α Φ(α, β) 2 0 E = α 1,, α k R (γ, γ) 0 ( γ E) (γ, γ) = 0 α Φ (α, γ) = 0 B γ = 0 k E (, ) α 1,, α k Φ E 2.5 g ( ) Lie g Cartan h ad(h) g g = h α Φ g α g α = {x g [h, x] = α(h)x h h} g 0 = h Φ = {α h α 0, g α {0}} h g g Φ g Killing h h h {α 1,, α l } h R Φ h R C αβ = 2(β, α) (α, α) 15
16 C αβ = β(h α ) C αβ Z β C αβ α Φ C αβ α σ α Φ h R Φ 4 (R1) Φ 0 / Φ (R2) α Φ, c R cα Φ c = ±1 (R3) α, β Φ α Φ σ α Φ (R4) E R Φ C αβ = α, β := 2(α, β) (α, α) Z E Φ 4 ( ) Lie g Cartan h Φ Dynkin Lie E R l (, ) l E E ( 7 ) 3.1. E Φ E ( ) (R1) Φ 0 / Φ (R2) α Φ, c R cα Φ c = ±1 (R3) α, β Φ α Φ σ α Φ (R4) E R Φ C αβ = α, β := 2(α, β) (α, α) Z Remark 3.2. E (, ) 0 α E α E P α β E P α σ α (β) σ α (β) = β 2(α, β) (α, α) α = β C αβα E = Rα P α β = cα + γ σ α (β) = cα + γ = β 2cα (α, β) = c(α, α) c = (α, β)/(α, α) C αβ 7 Lie E 16
17 4 1 1 E = R 2 E = R 2 A 1 A 1 A 1 A E Φ Φ Φ 1, Φ 2 Φ 1 Φ 2 = φ, Φ 1 Φ 2 = Φ, Φ 1 Φ A 2 B 2 (= C 2 ) 2 G Dynkin 8 G 2 17
18 3.2 α, β Φ (α, β) 0 α, β α, β α β ( ) α α (α, β) = α β cos θ (cos θ) 2 = (α, β) > 0 ( ) (α, β)2 α 2 β 2 = C αβc βα 4 C αβ, C βα 0 cos θ 1 C αβ C βα = 1, 2, 3 ( ), ( ) C αβ C βα α, β θ C αβ C βα (cos θ) 2 θ C αβ C βα β / α 1 1/4 π/ /2 π/ /4 π/ β β β π/3 π/4 α α π/6 α 3.4. α, β Φ (1) (α, β) > 0 α β Φ (2) (α, β) < 0 α + β Φ (3) Z p, q 0 β + iα Φ q i p [ ] (1) (α, β) > 0 α β C βα = 1 (R3) Φ σ β (α) = α C βα β = α β 18
19 α > β β α Φ (R2) α β = (β α) Φ (2) (1) β β (3) I = {i Z β + iα Φ} Φ E I p, q β Φ 0 I p, q 0 p, q p, q I = {i Z q i p, β + iα / Φ} r, s q < s r < p, β + rα / Φ, β + (r + 1)α Φ, β + sα / Φ, β + (s 1)α Φ β + rα = (β + (r + 1)α) α, β + sα = (β + (s 1)α) + α (1)(2) (α, β + (r + 1)α) 0, (α, β + (s 1)α) 0 (r s + 2)(α, α) 0 r s + 2 > 0, (α, α) > 0 {β + iα q i p} β α (1) C αβ = q p (2) β α- 4 [ ] (1) α σ α Φ β α- σ α (β + pα) = β qα σ α (α) = α C αβ p = q C αβ = q p (2) β = β + pα C αβ = C αβ + 2p = p + q C αβ 3 α- p + q + 1 p + q + 1 = C αβ α β α- β 2α β α β β α β β α α β 3α β 2α β α β α 19
20 3.3 (E, Φ) 3.6. v V α Φ (v, α) 0 v Remark 3.7. ( ) E\ P α α Φ Φ (E, Φ) v 3.8. (1) Φ + = Φ + (v) := {α Φ (v, α) > 0} Φ Φ = Φ + Φ = Φ + Φ Φ +, Φ (2) α Φ + α = β 1 + β 2 (β i Φ + ) α Φ + Π = Π(Π) (3) Φ Π Φ + Π = Π(Φ + ) Π Φ 3.9. S Φ Φ 2 (i) S E (ii) β Φ β = m α α α S m α Z m α 0 m α (1) Π Φ α β Π (α, β) 0 (2) S Φ + α β S (α, β) 0 S [ ] (1) (α, β) > 0 α β, (α β) = β α Φ (α, v) = (β, v) (α β, v) = 0 α β Φ v (α, v) (β, v) v (α, v) > 0, (β, v) > 0 (α β, v) = (α, v) (β, v), (β α, v) = (β, v) (α, v) (α, v), (β, v) α β Φ + β α Φ + α = (α β) + β, β = α + (β α) α, β Π (2) α S C αα = 0 (C α Q) λ = C C α 0 αα, µ = C C α 0 αα λ + µ = α S C αα = 0 0 (λ, λ) = (λ, µ) = C α 0,C α 0 C α ( C α )(α, α ) 0 20
21 C α C α α α (α, α ) 0 (λ, λ) = 0 λ = µ = 0 Φ + = Φ + (v) C α (v, α) = (v, λ) = 0 = (v, µ) = C α (v, α) C α 0 C α 0 α S Φ + (v, α) > 0 α S C α = 0 [ 3.9 ] Π v Π(Φ + (v)) Π β Φ + β Π β = β 1 + β 2 (β i Φ + (v)) (v, β) = (v, β 1 ) + (v, β 2 ) > (v, β i ) (i = 1, 2) (v, β i ) > 0 β = m α α (0 m α Z) α Π β Φ β Φ + (R1) Φ E Φ Π Π E (i) (ii) S Φ (i),(ii) E S dual S v = u S u α S (v, α) > 0 (ii) β Φ (v, β) = m α (v, α) 0 α S v (ii) Φ + (v) = {β Φ β = α S M αα m α 0} S Φ + (v) S α = β 1 +β 2 (β i Φ + ) β 1, β 2 S α = β 1 + β 2 α 0 α β i α 0 S Π(Φ + (v)) dim E S = Π(Φ + (v)) 4 Dynkin 4.1 Dynkin Φ Π = {α 1,, α l } (R3) C ij = 2(α i, α j ) (α i, α i ) Z (i, j)- l C Cartan Cartan (C1) C ii = 2 (C2) i j C ij = 0, 1, 2, 3 (C3) C ij = 0 C ji = 0 ( C ij = 2 C ji = 1 C ij = 3 C ji = 1 ) 21
22 Cartan Dynkin (D1) l α 1,, α l (D2) i j α i α j max( C ij, C ji ) (D3) i j C ij 2 ( C ij 2) α i α j α j α i Dynkin Lie 4.2 = {α 1,, α l } E [ ] := {ε 1,, ε l } (ε i = α i / α i ) 4.1. E Γ ε- (A1) {ε 1,, ε l } (A2) ε i, ε j = 0, 1/2, 1/ 2, 3/2 ε i, ε j (i j) π(1 1/m ij ) (m ij = 2, 3, 4, 6) ε- Γ Dynkin ε- Γ = [ ] Dynkin ε ε- [A l ] [B l ] = [C l ] [D l ] [E 6 ] [E 7 ] [E 8 ] [F 4 ] [G 2 ] 4.3. (1) Γ ε- Γ Γ Γ ε- 22
23 (2) Γ = {ε 1,, ε n } ε- ε i, ε j = 0 (i j) (i, j) n (3) ε- Γ = η 1,, η m } η i, η i+1 0 (1 i m 1), η m, η 1 = 0 (1) n (2) ε = ε i 0 < ε = n + 2 i<j ε i, ε j (A1) ε i, ε j = 0 ε i, ε j 1/2 (A2) ε i, ε j = 0 (i, j) (i < j) n n n n < n (3) (2) ε- ε i, ε j = 0 (i, j) (i < j) (2) (1) ε- ε- ε (1) Γ ε- ε Γ ε 3 (2) ε ε- ε 3 (3) ε- Γ Γ = [G 2 ] ε Γ {η Γ ε, η = 0, ε η} = {η 1,, η k } (3) η i, η j = 0 (i j) ε, η i, η j {η 1,, η k } c i = η i, ε, k ε = ε c i η i η i, ε = 0 (1 i k) (A1) ε 0 1 = ε 2 = ε 2 + k c 2 i ε- η i ε 4c 2 i k 4 c 2 i = 4(1 ε 2 ) < 4 (1) ε- 6 (2),(3) 4.5. ε- Γ [A k ] Γ ε 1 ε 2 ε k 23
24 k ε = ε i Γ = Γ Γ Γ {ε} ε- ε- [A k ] 1 ε- ε 2 = k + 2 ε i, ε j = k (k 1) = 1 1 i<j k ε Γ {ε} (A1) η Γ η, ε i 0 i (1 i k) 2 2 η 3 { 0 η, ε i = η, ε i i (A2) [G 2 ] ε- Γ Γ Γ 2 ε- Γ, Γ Γ Γ Γ 9 [A k ] ε- Γ, Γ [A k ] Γ 4.6. ε- Γ [B l ] (l 2), [F 4 ] Γ 9 24
25 ε 1 ε p η q η 1 ε = ε = p iε i, η = p i 2 p q iη i i(i + 1) = 1 p(p + 1) 2 η = 1 q(q + 1) 2 ε, η = pε p, qη q = pq 2 p 2 q 2 = ε, η 2 < ε 2 η 2 = 2 p(p + 1)q(q + 1) 4 ε = η 2pq < (p + 1)(q + 1) 2 (p 1)(q 1) < 2 { p q = 2 p = q = 2 [B l ] [F 4 ] Γ Γ ε- [A l ] Γ 2 [A k ] 4 1 [A k ] 4.7. ε- [D l ] (l 4), [E l ] (l = 6, 7, 8) Γ η 1 ψ η q 1 ε 1 ε p 1 ξ r 1 ξ 1 25
26 p 1 q 1 r 1 ε = iε i, η = iη i, ξ = iξ i ε, η, ξ ε = ε/ ε, η = η/ η, ξ = ξ/ ξ, c 1 = ε, ψ, c 2 = η, ψ, c 3 = ξ, ψ, ψ = ψ c 1 ε c 2 η c 3 ξ ε, η, ξ, ψ ε = η = ξ = 1 p 1 ε 2 = 1 = ψ 2 = ψ 2 + c c c 2 3 p 2 i 2 i(i + 1) = 1 p(p 1) 2 ε, ψ = (p 1)ε p 1, ψ = 1 (p 1) 2 c 2 1 = c 2 2 = 1 2 ε, ψ 2 ε 2 = 1 ( 1 1 ) 2 p ( 1 1 ) c 2 3 = 1 ( 1 1 ) q 2 r {( ) ( ) ( ) } < 1 2 p q r 1 p + 1 q + 1 r > 1 p q r( 2) 3/r r < 3 r = 2 q < 4 q = 2, < 1 p + 1 q 2 q q = 2 p Γ [D l ] (l = p + 2) q = 3 1/p > 1/6 p < 6 p = 3, 4, 5 [E 6 ], [E 7 ], [E 8 ] (p, q, r) = (3, 3, 2), (4, 3, 2), (5, 3, 2) Dynkin [B l ], [F 4 ], [G 2 ] Dynkin [B l ] 2 B l, C l Dynkin (B 2 = C 2 )[F 4 ], [G 2 ] Dynkin 26
27 5 5.1 Dynkin Cartan Lie g Cartan h Cartan Lie Lie g Cartan h Lie 5.1. k Lie g( ) Weyl Lie Dynkin 5.2. (1) g Lie (2) g (3) g (4) Dynkin Dynkin Cartan Dynkin Dynkin Cartan Killing Cartan Dynkin Dynkin Dynkin 5.3. Dynkin Lie 27
28 5.2 Serre Lie Serre 5.4. Π = {α 1,, α l } h i := α h [e i, f i ] = h i e i g αi, f i g αi Lie g Serre g {h i, e i, f i 1 i l} [h i, h j ] = 0 (5.1) [h i, e j ] = a ij e j, [h i, f j ] = a ij f j (5.2) [e i, f j ] = δ ij h i (5.3) (ad ei ) aij+1 (e j ) = 0, (ad fi ) aij+1 (f j ) = 0 (i j) (5.4) 2 Serre 5.3 Weyl 5.5. (E, Φ) W = W (Φ) := σ α α Φ Φ Weyl 5.6. Weyl (1) W (2) W (Π) = Φ E W Weyl (3) W = σ αi α i Π (4) W E 6 Lie 4 A l, B l, C l, D l 5 E 6, E 7, E 8, F 4, G 2 Lie Lie A l B l C l D l sl l+1 (k) so 2l+1 (k) sp 2l (k) so 2l (k) Caylay Jordan l = 1 A 1 sl 2 Dynkin 1 D 1 so 2 (C) = {X M 2 (R) t X + X = 0} C 2 Lie 1 D 1 Dynkin B 1,C 1 so 3, sp 2 3 sl 2 = so3 = sp2 28
29 2 D 2 so 4 so 4 = sl2 sl 2 2 D 2 = A 1 A 1 B 2, C 2 so 5, sp 4 so 5, sp 4 Dynkin = 3 D 3 so 6 so 6 = sl4 A 3 Dynkin = 6.1 A n 1 sl n A Lie Lie 10 A n 1 Lie sl n = {X M n (C) tr X = 0} Cartan h = {X sl n X } E ij (i, j)- h = diag(h 1,, h n ) trh = 0 h h n = 0 [h, E ij ] = (h i h j )E ij (i j) i j α ij h α ij : h h = diag(h 1,, h n ) h i h j C 10 B,C,D 29
30 E ij C g αij h h g 0 sl n sl n = h E ij C i j h = g 0, g αij = E ij C Φ = {α ij i j} A n 1 Cartan fig. Cartan Killing h = diag(h 1,, h n ), h = diag(h 1,, h n) B(h, h ) = tr(ad h ad h ) = i j (h i h j )(h i h j) ( ) n = 2(n 1) h i h i 2 h i h j i j ( n n ) ( n = 2n h i h i 2 h i = 2n h i ) n h i h i ( tr h = tr h = 0 ) α ij (h) = h i h j α ij h t αij Killing h i h j = α ij (h) = B(t αij, h) = 2n n (t αij ) k h k k=1 t αij = 1 diag(0,, 1,, 1,, 0) 2n (α ij, α ij ) = B(t αij, t αij ) = 1 4n 2 (2n 2) = 1 n 30
31 h αij = 2t αij B(t αij, t αij ) = 2n 1 diag(0,, 1,, 1,, 0) = diag(0,, 1,, 1,, 0) 2n ε i = α i,i+1 Π = {ε i 1 i n 1} Π h i < j α ij = ε i + ε i ε j 1 i < j Φ + = {α ij i < j} Cartan (ε i, ε j ) = B(α i,i+1, α j,j+1 ) = 1 2n 4n 2 [diag(e ii E i+1,i+1 ) diag(e jj E j+1,j+1 )] ([ ] ) = 1 2 i = j 2n 1 i = j ± 1 0 otherwise C ij = 2(ε i, ε j ) (ε i, ε i ) = 2 i = j 1 i = j ± 1 0 otherwise Cartan Dynkin A n B n so 2n C n sp 2n 6.4 D n so 2n 6.5 G E 6, E 7, E 8, F 4 31
32 II Dynkin Dynkin III Dynkin 7 SO(3) IV Dynkin V Quiver Dynkin VI Painlevé Dynkin 32
Step 2 O(3) Sym 0 (R 3 ), : a + := λ 1 λ 2 λ 3 a λ 1 λ 2 λ 3. a +. X a +, O(3).X. O(3).X = O(3)/O(3) X, O(3) X. 1.7 Step 3 O(3) Sym 0 (R 3 ),
1 1 1.1,,. 1.1 1.2 O(2) R 2 O(2).p, {0} r > 0. O(3) R 3 O(3).p, {0} r > 0.,, O(n) ( SO(n), O(n) ): Sym 0 (R n ) := {X M(n, R) t X = X, tr(x) = 0}. 1.3 O(n) Sym 0 (R n ) : g.x := gxg 1 (g O(n), X Sym 0
More information1 G K C 1.1. G K V ρ : G GL(V ) (ρ, V ) G V 1.2. G 2 (ρ, V ), (τ, W ) 2 V, W T : V W τ g T = T ρ g ( g G) V ρ g T W τ g V T W 1.3. G (ρ, V ) V W ρ g W
Naoya Enomoto 2002.9. paper 1 2 2 3 3 6 1 1 G K C 1.1. G K V ρ : G GL(V ) (ρ, V ) G V 1.2. G 2 (ρ, V ), (τ, W ) 2 V, W T : V W τ g T = T ρ g ( g G) V ρ g T W τ g V T W 1.3. G (ρ, V ) V W ρ g W W G- G W
More information量子力学 問題
3 : 203 : 0. H = 0 0 2 6 0 () = 6, 2 = 2, 3 = 3 3 H 6 2 3 ϵ,2,3 (2) ψ = (, 2, 3 ) ψ Hψ H (3) P i = i i P P 2 = P 2 P 3 = P 3 P = O, P 2 i = P i (4) P + P 2 + P 3 = E 3 (5) i ϵ ip i H 0 0 (6) R = 0 0 [H,
More informationi Version 1.1, (2012/02/22 24),.,..,.,,. R-space,, ( R- space),, Kahler (Kähler C-space)., R-space,., R-space, Hermite,.
R-space ( ) Version 1.1 (2012/02/29) i Version 1.1, (2012/02/22 24),.,..,.,,. R-space,, ( R- space),, Kahler (Kähler C-space)., R-space,., R-space, Hermite,. ii 1 Lie 1 1.1 Killing................................
More informationO x y z O ( O ) O (O ) 3 x y z O O x v t = t = 0 ( 1 ) O t = 0 c t r = ct P (x, y, z) r 2 = x 2 + y 2 + z 2 (t, x, y, z) (ct) 2 x 2 y 2 z 2 = 0
9 O y O ( O ) O (O ) 3 y O O v t = t = 0 ( ) O t = 0 t r = t P (, y, ) r = + y + (t,, y, ) (t) y = 0 () ( )O O t (t ) y = 0 () (t) y = (t ) y = 0 (3) O O v O O v O O O y y O O v P(, y,, t) t (, y,, t )
More information1. 1 A : l l : (1) l m (m 3) (2) m (3) n (n 3) (4) A α, β γ α β + γ = 2 m l lm n nα nα = lm. α = lm n. m lm 2β 2β = lm β = lm 2. γ l 2. 3
1. 1 A : l l : (1) l m (m 3) (2) m (3) n (n 3) (4) A 2 1 2 1 2 3 α, β γ α β + γ = 2 m l lm n nα nα = lm. α = lm n. m lm 2β 2β = lm β = lm 2. γ l 2. 3 4 P, Q R n = {(x 1, x 2,, x n ) ; x 1, x 2,, x n R}
More information,. Black-Scholes u t t, x c u 0 t, x x u t t, x c u t, x x u t t, x + σ x u t, x + rx ut, x rux, t 0 x x,,.,. Step 3, 7,,, Step 6., Step 4,. Step 5,,.
9 α ν β Ξ ξ Γ γ o δ Π π ε ρ ζ Σ σ η τ Θ θ Υ υ ι Φ φ κ χ Λ λ Ψ ψ µ Ω ω Def, Prop, Th, Lem, Note, Remark, Ex,, Proof, R, N, Q, C [a, b {x R : a x b} : a, b {x R : a < x < b} : [a, b {x R : a x < b} : a,
More information微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 初版 1 刷発行時のものです.
微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. ttp://www.morikita.co.jp/books/mid/00571 このサンプルページの内容は, 初版 1 刷発行時のものです. i ii 014 10 iii [note] 1 3 iv 4 5 3 6 4 x 0 sin x x 1 5 6 z = f(x, y) 1 y = f(x)
More information医系の統計入門第 2 版 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 第 2 版 1 刷発行時のものです.
医系の統計入門第 2 版 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. http://www.morikita.co.jp/books/mid/009192 このサンプルページの内容は, 第 2 版 1 刷発行時のものです. i 2 t 1. 2. 3 2 3. 6 4. 7 5. n 2 ν 6. 2 7. 2003 ii 2 2013 10 iii 1987
More information2016 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 1 16 2 1 () X O 3 (O1) X O, O (O2) O O (O3) O O O X (X, O) O X X (O1), (O2), (O3) (O2) (O3) n (O2) U 1,..., U n O U k O k=1 (O3) U λ O( λ Λ) λ Λ U λ O 0 X 0 (O2) n =
More informationd ϕ i) t d )t0 d ϕi) ϕ i) t x j t d ) ϕ t0 t α dx j d ) ϕ i) t dx t0 j x j d ϕ i) ) t x j dx t0 j f i x j ξ j dx i + ξ i x j dx j f i ξ i x j dx j d )
23 M R M ϕ : R M M ϕt, x) ϕ t x) ϕ s ϕ t ϕ s+t, ϕ 0 id M M ϕ t M ξ ξ ϕ t d ϕ tx) ξϕ t x)) U, x 1,...,x n )) ϕ t x) ϕ 1) t x),...,ϕ n) t x)), ξx) ξ i x) d ϕi) t x) ξ i ϕ t x)) M f ϕ t f)x) f ϕ t )x) fϕ
More information1 Part I (warming up lecture). (,,...) 1.1 ( ) M = G/K :. M,. : : R-space. R-space..
( ) ( ) 2012/07/14 1 Part I (warming up lecture). (,,...) 1.1 ( ) M = G/K :. M,. : : R-space. R-space.. 1.2 ( ) ( ): M,. : (Part II). 1 (Part III). : :,, austere,. :, Einstein, Ricci soliton,. 1.3 : (S,
More information四変数基本対称式の解放
The second-thought of the Galois-style way to solve a quartic equation Oomori, Yasuhiro in Himeji City, Japan Jan.6, 013 Abstract v ρ (v) Step1.5 l 3 1 6. l 3 7. Step - V v - 3 8. Step1.3 - - groupe groupe
More informationX G P G (X) G BG [X, BG] S 2 2 2 S 2 2 S 2 = { (x 1, x 2, x 3 ) R 3 x 2 1 + x 2 2 + x 2 3 = 1 } R 3 S 2 S 2 v x S 2 x x v(x) T x S 2 T x S 2 S 2 x T x S 2 = { ξ R 3 x ξ } R 3 T x S 2 S 2 x x T x S 2
More information24 I ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x
24 I 1.1.. ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x 1 (t), x 2 (t),, x n (t)) ( ) ( ), γ : (i) x 1 (t),
More informationA11 (1993,1994) 29 A12 (1994) 29 A13 Trefethen and Bau Numerical Linear Algebra (1997) 29 A14 (1999) 30 A15 (2003) 30 A16 (2004) 30 A17 (2007) 30 A18
2013 8 29y, 2016 10 29 1 2 2 Jordan 3 21 3 3 Jordan (1) 3 31 Jordan 4 32 Jordan 4 33 Jordan 6 34 Jordan 8 35 9 4 Jordan (2) 10 41 x 11 42 x 12 43 16 44 19 441 19 442 20 443 25 45 25 5 Jordan 26 A 26 A1
More information( ),.,,., C A (2008, ). 1,, (M, g) (Riemannian symmetric space), : p M, s p : M M :.,.,.,, (, ).,, (M, g) p M, s p : M M p, : (1) p s p, (
( ),.,,., C A (2008, ). 1,,. 1.1. (M, g) (Riemannian symmetric space), : p M, s p : M M :.,.,.,, (, ).,,. 1.2. (M, g) p M, s p : M M p, : (1) p s p, (2) s 2 p = id ( id ), (3) s p ( )., p ( s p (p) = p),,
More information数学Ⅱ演習(足助・09夏)
II I 9/4/4 9/4/2 z C z z z z, z 2 z, w C zw z w 3 z, w C z + w z + w 4 t R t C t t t t t z z z 2 z C re z z + z z z, im z 2 2 3 z C e z + z + 2 z2 + 3! z3 + z!, I 4 x R e x cos x + sin x 2 z, w C e z+w
More information1 1.1 ( ). z = a + bi, a, b R 0 a, b 0 a 2 + b 2 0 z = a + bi = ( ) a 2 + b 2 a a 2 + b + b 2 a 2 + b i 2 r = a 2 + b 2 θ cos θ = a a 2 + b 2, sin θ =
1 1.1 ( ). z = + bi,, b R 0, b 0 2 + b 2 0 z = + bi = ( ) 2 + b 2 2 + b + b 2 2 + b i 2 r = 2 + b 2 θ cos θ = 2 + b 2, sin θ = b 2 + b 2 2π z = r(cos θ + i sin θ) 1.2 (, ). 1. < 2. > 3. ±,, 1.3 ( ). A
More informationA
A 2563 15 4 21 1 3 1.1................................................ 3 1.2............................................. 3 2 3 2.1......................................... 3 2.2............................................
More informationt = h x z z = h z = t (x, z) (v x (x, z, t), v z (x, z, t)) ρ v x x + v z z = 0 (1) 2-2. (v x, v z ) φ(x, z, t) v x = φ x, v z
I 1 m 2 l k 2 x = 0 x 1 x 1 2 x 2 g x x 2 x 1 m k m 1-1. L x 1, x 2, ẋ 1, ẋ 2 ẋ 1 x = 0 1-2. 2 Q = x 1 + x 2 2 q = x 2 x 1 l L Q, q, Q, q M = 2m µ = m 2 1-3. Q q 1-4. 2 x 2 = h 1 x 1 t = 0 2 1 t x 1 (t)
More informationI A A441 : April 21, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka ) Google
I4 - : April, 4 Version :. Kwhir, Tomoki TA (Kondo, Hirotk) Google http://www.mth.ngoy-u.c.jp/~kwhir/courses/4s-biseki.html pdf 4 4 4 4 8 e 5 5 9 etc. 5 6 6 6 9 n etc. 6 6 6 3 6 3 7 7 etc 7 4 7 7 8 5 59
More informationsusy.dvi
1 Chapter 1 Why supper symmetry? 2 Chapter 2 Representaions of the supersymmetry algebra SUSY Q a d 3 xj 0 α J x µjµ = 0 µ SUSY ( {Q A α,q βb } = 2σ µ α β P µδ A B (2.1 {Q A α,q βb } = {Q αa,q βb } = 0
More informationzz + 3i(z z) + 5 = 0 + i z + i = z 2i z z z y zz + 3i (z z) + 5 = 0 (z 3i) (z + 3i) = 9 5 = 4 z 3i = 2 (3i) zz i (z z) + 1 = a 2 {
04 zz + iz z) + 5 = 0 + i z + i = z i z z z 970 0 y zz + i z z) + 5 = 0 z i) z + i) = 9 5 = 4 z i = i) zz i z z) + = a {zz + i z z) + 4} a ) zz + a + ) z z) + 4a = 0 4a a = 5 a = x i) i) : c Darumafactory
More informationφ s i = m j=1 f x j ξ j s i (1)? φ i = φ s i f j = f x j x ji = ξ j s i (1) φ 1 φ 2. φ n = m j=1 f jx j1 m j=1 f jx j2. m
2009 10 6 23 7.5 7.5.1 7.2.5 φ s i m j1 x j ξ j s i (1)? φ i φ s i f j x j x ji ξ j s i (1) φ 1 φ 2. φ n m j1 f jx j1 m j1 f jx j2. m j1 f jx jn x 11 x 21 x m1 x 12 x 22 x m2...... m j1 x j1f j m j1 x
More informationnewmain.dvi
数論 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. http://www.morikita.co.jp/books/mid/008142 このサンプルページの内容は, 第 2 版 1 刷発行当時のものです. Daniel DUVERNEY: THÉORIE DES NOMBRES c Dunod, Paris, 1998, This book is published
More informationx () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x
[ ] IC. f(x) = e x () f(x) f (x) () lim f(x) lim f(x) x + x (3) lim f(x) lim f(x) x + x (4) y = f(x) ( ) ( s46). < a < () a () lim a log xdx a log xdx ( ) n (3) lim log k log n n n k=.3 z = log(x + y ),
More information(Compton Scattering) Beaming 1 exp [i (k x ωt)] k λ k = 2π/λ ω = 2πν k = ω/c k x ωt ( ω ) k α c, k k x ωt η αβ k α x β diag( + ++) x β = (ct, x) O O x
Compton Scattering Beaming exp [i k x ωt] k λ k π/λ ω πν k ω/c k x ωt ω k α c, k k x ωt η αβ k α x β diag + ++ x β ct, x O O x O O v k α k α β, γ k γ k βk, k γ k + βk k γ k k, k γ k + βk 3 k k 4 k 3 k
More information1 (1) ( i ) 60 (ii) 75 (iii) 315 (2) π ( i ) (ii) π (iii) 7 12 π ( (3) r, AOB = θ 0 < θ < π ) OAB A 2 OB P ( AB ) < ( AP ) (4) 0 < θ < π 2 sin θ
1 (1) ( i ) 60 (ii) 75 (iii) 15 () ( i ) (ii) 4 (iii) 7 1 ( () r, AOB = θ 0 < θ < ) OAB A OB P ( AB ) < ( AP ) (4) 0 < θ < sin θ < θ < tan θ 0 x, 0 y (1) sin x = sin y (x, y) () cos x cos y (x, y) 1 c
More information1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2
2005 9/8-11 2 2.2 ( 2-5) γ ( ) γ cos θ 2πr πρhr 2 g h = 2γ cos θ ρgr (2.1) γ = ρgrh (2.2) 2 cos θ θ cos θ = 1 (2.2) γ = 1 ρgrh (2.) 2 2. p p ρgh p ( ) p p = p ρgh (2.) h p p = 2γ r 1 1 (Berry,1975) 2-6
More information211 kotaro@math.titech.ac.jp 1 R *1 n n R n *2 R n = {(x 1,..., x n ) x 1,..., x n R}. R R 2 R 3 R n R n R n D D R n *3 ) (x 1,..., x n ) f(x 1,..., x n ) f D *4 n 2 n = 1 ( ) 1 f D R n f : D R 1.1. (x,
More informationSO(n) [8] SU(2)
SO(n) [8] 1 2 1.1.............................. 3 1.2.............................. 6 1.3 SU(2)............................. 7 1.4 -...................... 10 1.5 SO(3).............................. 11
More informationK g g g g; (x, y) [x, y] g Lie algebra [, ] bracket (i) [, ] (ii) x g [x, x] = 0 (iii) ( Jacobi identity) [x, [y, z]] + [y, [z, x]] +
2015 X V 1. 19 Sophus Lie [Hu] James Humphreys, Introduction to Lie Algebras and Representation Theory, Graduate Texts in Mathematics Volume 9 1972, Springer [Sa],, 2002, [Hu] 14.3 78 [Sa] 13 167 [Hu]
More informationE1 (4/12)., ( )., 3,4 ( ). ( ) Allen Hatcher, Vector bundle and K-theory ( HP ) 1
E1 (4/12)., ( )., 3,4 ( ). ( ) Allen Hatcher, Vector bundle and K-theory ( HP ) 1 (4/12) 1 1.. 2. F R C H P n F E n := {((x 0,..., x n ), [v 0 : : v n ]) F n+1 P n F n x i v i = 0 }. i=0 E n P n F P n
More information1 X X A, B X = A B A B A B X 1.1 R R I I a, b(a < b) I a x b = x I 1.2 R A 1.3 X : (1)X (2)X X (3)X A, B X = A B A B = 1.4 f : X Y X Y ( ) A Y A Y A f
1 X X A, B X = A B A B A B X 1.1 R R I I a, b(a < b) I a x b = x I 1. R A 1.3 X : (1)X ()X X (3)X A, B X = A B A B = 1.4 f : X Y X Y ( ) A Y A Y A f 1 (A) f X X f 1 (A) = X f 1 (A) = A a A f f(x) = a x
More information201711grade1ouyou.pdf
2017 11 26 1 2 52 3 12 13 22 23 32 33 42 3 5 3 4 90 5 6 A 1 2 Web Web 3 4 1 2... 5 6 7 7 44 8 9 1 2 3 1 p p >2 2 A 1 2 0.6 0.4 0.52... (a) 0.6 0.4...... B 1 2 0.8-0.2 0.52..... (b) 0.6 0.52.... 1 A B 2
More informationSO(2)
TOP URL http://amonphys.web.fc2.com/ 1 12 3 12.1.................................. 3 12.2.......................... 4 12.3............................. 5 12.4 SO(2).................................. 6
More informationAkito Tsuboi June 22, T ϕ T M M ϕ M M ϕ T ϕ 2 Definition 1 X, Y, Z,... 1
Akito Tsuboi June 22, 2006 1 T ϕ T M M ϕ M M ϕ T ϕ 2 Definition 1 X, Y, Z,... 1 1. X, Y, Z,... 2. A, B (A), (A) (B), (A) (B), (A) (B) Exercise 2 1. (X) (Y ) 2. ((X) (Y )) (Z) 3. (((X) (Y )) (Z)) Exercise
More informationII Lie Lie Lie ( ) 1. Lie Lie Lie
II Lie 2010 1 II Lie Lie Lie ( ) 1. Lie Lie 2. 3. 4. Lie i 1 1 2 Lie Lie 4 3 Lie 8 4 9 5 11 6 14 7 16 8 19 9 Lie 23 10 Lie 26 11 Lie Lie 31 12 Lie 35 1 1 C Lie Lie 1.1 Hausdorff M M {(U α, φ α )} α A (1)
More information直交座標系の回転
b T.Koama x l x, Lx i ij j j xi i i i, x L T L L, L ± x L T xax axx, ( a a ) i, j ij i j ij ji λ λ + λ + + λ i i i x L T T T x ( L) L T xax T ( T L T ) A( L) T ( LAL T ) T ( L AL) λ ii L AL Λ λi i axx
More informationMacdonald, ,,, Macdonald. Macdonald,,,,,.,, Gauss,,.,, Lauricella A, B, C, D, Gelfand, A,., Heckman Opdam.,,,.,,., intersection,. Macdona
Macdonald, 2015.9.1 9.2.,,, Macdonald. Macdonald,,,,,.,, Gauss,,.,, Lauricella A, B, C, D, Gelfand, A,., Heckman Opdam.,,,.,,., intersection,. Macdonald,, q., Heckman Opdam q,, Macdonald., 1 ,,. Macdonald,
More information7 π L int = gψ(x)ψ(x)φ(x) + (7.4) [ ] p ψ N = n (7.5) π (π +,π 0,π ) ψ (σ, σ, σ )ψ ( A) σ τ ( L int = gψψφ g N τ ) N π * ) (7.6) π π = (π, π, π ) π ±
7 7. ( ) SU() SU() 9 ( MeV) p 98.8 π + π 0 n 99.57 9.57 97.4 497.70 δm m 0.4%.% 0.% 0.8% π 9.57 4.96 Σ + Σ 0 Σ 89.6 9.46 K + K 0 49.67 (7.) p p = αp + βn, n n = γp + δn (7.a) [ ] p ψ ψ = Uψ, U = n [ α
More information, = = 7 6 = 42, =
http://www.ss.u-tokai.ac.jp/~mahoro/2016autumn/alg_intro/ 1 1 2016.9.26, http://www.ss.u-tokai.ac.jp/~mahoro/2016autumn/alg_intro/ 1.1 1 214 132 = 28258 2 + 1 + 4 1 + 3 + 2 = 7 6 = 42, 4 + 2 = 6 2 + 8
More information1 8, : 8.1 1, 2 z = ax + by + c ax by + z c = a b +1 x y z c = 0, (0, 0, c), n = ( a, b, 1). f = n i=1 a ii x 2 i + i<j 2a ij x i x j = ( x, A x), f =
1 8, : 8.1 1, z = ax + by + c ax by + z c = a b +1 x y z c = 0, (0, 0, c), n = ( a, b, 1). f = a ii x i + i
More informationJuly 28, H H 0 H int = H H 0 H int = H int (x)d 3 x Schrödinger Picture Ψ(t) S =e iht Ψ H O S Heisenberg Picture Ψ H O H (t) =e iht O S e i
July 8, 4. H H H int H H H int H int (x)d 3 x Schrödinger Picture Ψ(t) S e iht Ψ H O S Heisenberg Picture Ψ H O H (t) e iht O S e iht Interaction Picture Ψ(t) D e iht Ψ(t) S O D (t) e iht O S e ih t (Dirac
More informatione a b a b b a a a 1 a a 1 = a 1 a = e G G G : x ( x =, 8, 1 ) x 1,, 60 θ, ϕ ψ θ G G H H G x. n n 1 n 1 n σ = (σ 1, σ,..., σ N ) i σ i i n S n n = 1,,
01 10 18 ( ) 1 6 6 1 8 8 1 6 1 0 0 0 0 1 Table 1: 10 0 8 180 1 1 1. ( : 60 60 ) : 1. 1 e a b a b b a a a 1 a a 1 = a 1 a = e G G G : x ( x =, 8, 1 ) x 1,, 60 θ, ϕ ψ θ G G H H G x. n n 1 n 1 n σ = (σ 1,
More information−g”U›ß™ö‡Æ…X…y…N…g…‰
1 / 74 ( ) 2019 3 8 URL: http://www.math.kyoto-u.ac.jp/ ichiro/ 2 / 74 Contents 1 Pearson 2 3 Doob h- 4 (I) 5 (II) 6 (III-1) - 7 (III-2-a) 8 (III-2-b) - 9 (III-3) Pearson 3 / 74 Pearson Definition 1 ρ
More informationII A A441 : October 02, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka )
II 214-1 : October 2, 214 Version : 1.1 Kawahira, Tomoki TA (Kondo, Hirotaka ) http://www.math.nagoya-u.ac.jp/~kawahira/courses/14w-biseki.html pdf 1 2 1 9 1 16 1 23 1 3 11 6 11 13 11 2 11 27 12 4 12 11
More information2 7 V 7 {fx fx 3 } 8 P 3 {fx fx 3 } 9 V 9 {fx fx f x 2fx } V {fx fx f x 2fx + } V {{a n } {a n } a n+2 a n+ + a n n } 2 V 2 {{a n } {a n } a n+2 a n+
R 3 R n C n V??,?? k, l K x, y, z K n, i x + y + z x + y + z iv x V, x + x o x V v kx + y kx + ky vi k + lx kx + lx vii klx klx viii x x ii x + y y + x, V iii o K n, x K n, x + o x iv x K n, x + x o x
More informationDVIOUT-fujin
2005 Limit Distribution of Quantum Walks and Weyl Equation 2006 3 2 1 2 2 4 2.1...................... 4 2.2......................... 5 2.3..................... 6 3 8 3.1........... 8 3.2..........................
More information2 1 κ c(t) = (x(t), y(t)) ( ) det(c (t), c x (t)) = det (t) x (t) y (t) y = x (t)y (t) x (t)y (t), (t) c (t) = (x (t)) 2 + (y (t)) 2. c (t) =
1 1 1.1 I R 1.1.1 c : I R 2 (i) c C (ii) t I c (t) (0, 0) c (t) c(i) c c(t) 1.1.2 (1) (2) (3) (1) r > 0 c : R R 2 : t (r cos t, r sin t) (2) C f : I R c : I R 2 : t (t, f(t)) (3) y = x c : R R 2 : t (t,
More information(iii) 0 V, x V, x + 0 = x. 0. (iv) x V, y V, x + y = 0., y x, y = x. (v) 1x = x. (vii) (α + β)x = αx + βx. (viii) (αβ)x = α(βx)., V, C.,,., (1)
1. 1.1...,. 1.1.1 V, V x, y, x y x + y x + y V,, V x α, αx αx V,, (i) (viii) : x, y, z V, α, β C, (i) x + y = y + x. (ii) (x + y) + z = x + (y + z). 1 (iii) 0 V, x V, x + 0 = x. 0. (iv) x V, y V, x + y
More informationuntitled
0. =. =. (999). 3(983). (980). (985). (966). 3. := :=. A A. A A. := := 4 5 A B A B A B. A = B A B A B B A. A B A B, A B, B. AP { A, P } = { : A, P } = { A P }. A = {0, }, A, {0, }, {0}, {}, A {0}, {}.
More information2011 8 26 3 I 5 1 7 1.1 Markov................................ 7 2 Gau 13 2.1.................................. 13 2.2............................... 18 2.3............................ 23 3 Gau (Le vy
More informationD 24 D D D
5 Paper I.R. 2001 5 Paper HP Paper 5 3 5.1................................................... 3 5.2.................................................... 4 5.3.......................................... 6
More informationchap10.dvi
. q {y j } I( ( L y j =Δy j = u j = C l ε j l = C(L ε j, {ε j } i.i.d.(,i q ( l= y O p ( {u j } q {C l } A l C l
More information(2 X Poisso P (λ ϕ X (t = E[e itx ] = k= itk λk e k! e λ = (e it λ k e λ = e eitλ e λ = e λ(eit 1. k! k= 6.7 X N(, 1 ϕ X (t = e 1 2 t2 : Cauchy ϕ X (t
6 6.1 6.1 (1 Z ( X = e Z, Y = Im Z ( Z = X + iy, i = 1 (2 Z E[ e Z ] < E[ Im Z ] < Z E[Z] = E[e Z] + ie[im Z] 6.2 Z E[Z] E[ Z ] : E[ Z ] < e Z Z, Im Z Z E[Z] α = E[Z], Z = Z Z 1 {Z } E[Z] = α = α [ α ]
More informationII Time-stamp: <05/09/30 17:14:06 waki> ii
II waki@cc.hirosaki-u.ac.jp 18 1 30 II Time-stamp: ii 1 1 1.1.................................................. 1 1.2................................................... 3 1.3..................................................
More informationA 2 3. m S m = {x R m+1 x = 1} U + k = {x S m x k > 0}, U k = {x S m x k < 0}, ϕ ± k (x) = (x 0,..., ˆx k,... x m ) 1. {(U ± k, ϕ± k ) 0 k m} S m 1.2.
A A 1 A 5 A 6 1 2 3 4 5 6 7 1 1.1 1.1 (). Hausdorff M R m M M {U α } U α R m E α ϕ α : U α E α U α U β = ϕ α (ϕ β ϕβ (U α U β )) 1 : ϕ β (U α U β ) ϕ α (U α U β ) C M a m dim M a U α ϕ α {x i, 1 i m} {U,
More informationtomocci ,. :,,,, Lie,,,, Einstein, Newton. 1 M n C. s, M p. M f, p d ds f = dxµ p ds µ f p, X p = X µ µ p = dxµ ds µ p. µ, X µ.,. p,. T M p.
tomocci 18 7 5...,. :,,,, Lie,,,, Einstein, Newton. 1 M n C. s, M p. M f, p d ds f = dxµ p ds µ f p, X p = X µ µ p = dxµ ds µ p. µ, X µ.,. p,. T M p. M F (M), X(F (M)).. T M p e i = e µ i µ. a a = a i
More informationII R n k +1 v 0,, v k k v 1 v 0,, v k v v 0,, v k R n 1 a 0,, a k a 0 v 0 + a k v k v 0 v k k k v 0,, v k σ k σ dimσ = k 1.3. k
II 231017 1 1.1. R n k +1 v 0,, v k k v 1 v 0,, v k v 0 1.2. v 0,, v k R n 1 a 0,, a k a 0 v 0 + a k v k v 0 v k k k v 0,, v k σ kσ dimσ = k 1.3. k σ {v 0,...,v k } {v i0,...,v il } l σ τ < τ τ σ 1.4.
More informationall.dvi
72 9 Hooke,,,. Hooke. 9.1 Hooke 1 Hooke. 1, 1 Hooke. σ, ε, Young. σ ε (9.1), Young. τ γ G τ Gγ (9.2) X 1, X 2. Poisson, Poisson ν. ν ε 22 (9.) ε 11 F F X 2 X 1 9.1: Poisson 9.1. Hooke 7 Young Poisson G
More information1 1.1 H = µc i c i + c i t ijc j + 1 c i c j V ijklc k c l (1) V ijkl = V jikl = V ijlk = V jilk () t ij = t ji, V ijkl = V lkji (3) (1) V 0 H mf = µc
013 6 30 BCS 1 1.1........................ 1................................ 3 1.3............................ 3 1.4............................... 5 1.5.................................... 5 6 3 7 4 8
More informationn 2 + π2 6 x [10 n x] x = lim n 10 n n 10 k x 1.1. a 1, a 2,, a n, (a n ) n=1 {a n } n=1 1.2 ( ). {a n } n=1 Q ε > 0 N N m, n N a m
1 1 1 + 1 4 + + 1 n 2 + π2 6 x [10 n x] x = lim n 10 n n 10 k x 1.1. a 1, a 2,, a n, (a n ) n=1 {a n } n=1 1.2 ( ). {a n } n=1 Q ε > 0 N N m, n N a m a n < ε 1 1. ε = 10 1 N m, n N a m a n < ε = 10 1 N
More information7
01111() 7.1 (ii) 7. (iii) 7.1 poit defect d hkl d * hkl ε Δd hkl d hkl ~ Δd * hkl * d hkl (7.1) f ( ε ) 1 πσ e ε σ (7.) σ relative strai root ea square d * siθ λ (7.) Δd * cosθ Δθ λ (7.4) ε Δθ ( Δθ ) Δd
More informationV(x) m e V 0 cos x π x π V(x) = x < π, x > π V 0 (i) x = 0 (V(x) V 0 (1 x 2 /2)) n n d 2 f dξ 2ξ d f 2 dξ + 2n f = 0 H n (ξ) (ii) H
199 1 1 199 1 1. Vx) m e V cos x π x π Vx) = x < π, x > π V i) x = Vx) V 1 x /)) n n d f dξ ξ d f dξ + n f = H n ξ) ii) H n ξ) = 1) n expξ ) dn dξ n exp ξ )) H n ξ)h m ξ) exp ξ )dξ = π n n!δ n,m x = Vx)
More information..3. Ω, Ω F, P Ω, F, P ). ) F a) A, A,..., A i,... F A i F. b) A F A c F c) Ω F. ) A F A P A),. a) 0 P A) b) P Ω) c) [ ] A, A,..., A i,... F i j A i A
.. Laplace ). A... i),. ω i i ). {ω,..., ω } Ω,. ii) Ω. Ω. A ) r, A P A) P A) r... ).. Ω {,, 3, 4, 5, 6}. i i 6). A {, 4, 6} P A) P A) 3 6. ).. i, j i, j) ) Ω {i, j) i 6, j 6}., 36. A. A {i, j) i j }.
More informationN cos s s cos ψ e e e e 3 3 e e 3 e 3 e
3 3 5 5 5 3 3 7 5 33 5 33 9 5 8 > e > f U f U u u > u ue u e u ue u ue u e u e u u e u u e u N cos s s cos ψ e e e e 3 3 e e 3 e 3 e 3 > A A > A E A f A A f A [ ] f A A e > > A e[ ] > f A E A < < f ; >
More informationn (1.6) i j=1 1 n a ij x j = b i (1.7) (1.7) (1.4) (1.5) (1.4) (1.7) u, v, w ε x, ε y, ε x, γ yz, γ zx, γ xy (1.8) ε x = u x ε y = v y ε z = w z γ yz
1 2 (a 1, a 2, a n ) (b 1, b 2, b n ) A (1.1) A = a 1 b 1 + a 2 b 2 + + a n b n (1.1) n A = a i b i (1.2) i=1 n i 1 n i=1 a i b i n i=1 A = a i b i (1.3) (1.3) (1.3) (1.1) (ummation convention) a 11 x
More informationmeiji_resume_1.PDF
β β β (q 1,q,..., q n ; p 1, p,..., p n ) H(q 1,q,..., q n ; p 1, p,..., p n ) Hψ = εψ ε k = k +1/ ε k = k(k 1) (x, y, z; p x, p y, p z ) (r; p r ), (θ; p θ ), (ϕ; p ϕ ) ε k = 1/ k p i dq i E total = E
More informationA A = a 41 a 42 a 43 a 44 A (7) 1 (3) A = M 12 = = a 41 (8) a 41 a 43 a 44 (3) n n A, B a i AB = A B ii aa
1 2 21 2 2 [ ] a 11 a 12 A = a 21 a 22 (1) A = a 11 a 22 a 12 a 21 (2) 3 3 n n A A = n ( 1) i+j a ij M ij i =1 n (3) j=1 M ij A i j (n 1) (n 1) 2-1 3 3 A A = a 11 a 12 a 13 a 21 a 22 a 23 a 31 a 32 a 33
More informationall.dvi
38 5 Cauchy.,,,,., σ.,, 3,,. 5.1 Cauchy (a) (b) (a) (b) 5.1: 5.1. Cauchy 39 F Q Newton F F F Q F Q 5.2: n n ds df n ( 5.1). df n n df(n) df n, t n. t n = df n (5.1) ds 40 5 Cauchy t l n mds df n 5.3: t
More informationV 0 = + r pv (H) + qv (T ) = + r ps (H) + qs (T ) = S 0 X n+ (T ) = n S n+ (T ) + ( + r)(x n n S n ) = ( + r)x n + n (d r)s n = ( + r)v n + V n+(h) V
I (..2) (0 < d < + r < u) X 0, X X = 0 S + ( + r)(x 0 0 S 0 ) () X 0 = 0, P (X 0) =, P (X > 0) > 0 0 H, T () X 0 = 0, X (H) = 0 us 0 ( + r) 0 S 0 = 0 S 0 (u r) X (T ) = 0 ds 0 ( + r) 0 S 0 = 0 S 0 (d r)
More informationA S- hara/lectures/lectures-j.html r A = A 5 : 5 = max{ A, } A A A A B A, B A A A %
A S- http://www.math.kyushu-u.ac.jp/ hara/lectures/lectures-j.html r A S- 3.4.5. 9 phone: 9-8-444, e-mail: hara@math.kyushu-u.ac.jp, http://www.math.kyushu-u.ac.jp/ hara/lectures/lectures-j.html Office
More informationuntitled
- k k k = y. k = ky. y du dx = ε ux ( ) ux ( ) = ax+ b x u() = ; u( ) = AE u() = b= u () = a= ; a= d x du ε x = = = dx dx N = σ da = E ε da = EA ε A x A x x - σ x σ x = Eε x N = EAε x = EA = N = EA k =
More informationNote.tex 2008/09/19( )
1 20 9 19 2 1 5 1.1........................ 5 1.2............................. 8 2 9 2.1............................. 9 2.2.............................. 10 3 13 3.1.............................. 13 3.2..................................
More information1
1 Borel1956 Groupes linéaire algébriques, Ann. of Math. 64 (1956), 20 82. Chevalley1956/58 Sur la classification des groupes de Lie algébriques, Sém. Chevalley 1956/58, E.N.S., Paris. Tits1959 Sur la classification
More informationn ( (
1 2 27 6 1 1 m-mat@mathscihiroshima-uacjp 2 http://wwwmathscihiroshima-uacjp/~m-mat/teach/teachhtml 2 1 3 11 3 111 3 112 4 113 n 4 114 5 115 5 12 7 121 7 122 9 123 11 124 11 125 12 126 2 2 13 127 15 128
More informationNo δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i x j δx j (5) δs 2
No.2 1 2 2 δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i δx j (5) δs 2 = δx i δx i + 2 u i δx i δx j = δs 2 + 2s ij δx i δx j
More informationmain.dvi
SGC - 70 2, 3 23 ɛ-δ 2.12.8 3 2.92.13 4 2 3 1 2.1 2.102.12 [8][14] [1],[2] [4][7] 2 [4] 1 2009 8 1 1 1.1... 1 1.2... 4 1.3 1... 8 1.4 2... 9 1.5... 12 1.6 1... 16 1.7... 18 1.8... 21 1.9... 23 2 27 2.1
More information1 Introduction 1 (1) (2) (3) () {f n (x)} n=1 [a, b] K > 0 n, x f n (x) K < ( ) x [a, b] lim f n (x) f(x) (1) f(x)? (2) () f(x)? b lim a f n (x)dx = b
1 Introduction 2 2.1 2.2 2.3 3 3.1 3.2 σ- 4 4.1 4.2 5 5.1 5.2 5.3 6 7 8. Fubini,,. 1 1 Introduction 1 (1) (2) (3) () {f n (x)} n=1 [a, b] K > 0 n, x f n (x) K < ( ) x [a, b] lim f n (x) f(x) (1) f(x)?
More informationI A A441 : April 15, 2013 Version : 1.1 I Kawahira, Tomoki TA (Shigehiro, Yoshida )
I013 00-1 : April 15, 013 Version : 1.1 I Kawahira, Tomoki TA (Shigehiro, Yoshida) http://www.math.nagoya-u.ac.jp/~kawahira/courses/13s-tenbou.html pdf * 4 15 4 5 13 e πi = 1 5 0 5 7 3 4 6 3 6 10 6 17
More informationSO(3) 49 u = Ru (6.9), i u iv i = i u iv i (C ) π π : G Hom(V, V ) : g D(g). π : R 3 V : i 1. : u u = u 1 u 2 u 3 (6.10) 6.2 i R α (1) = 0 cos α
SO(3) 48 6 SO(3) t 6.1 u, v u = u 1 1 + u 2 2 + u 3 3 = u 1 e 1 + u 2 e 2 + u 3 e 3, v = v 1 1 + v 2 2 + v 3 3 = v 1 e 1 + v 2 e 2 + v 3 e 3 (6.1) i (e i ) e i e j = i j = δ ij (6.2) ( u, v ) = u v = ij
More information2
III ( Dirac ) ( ) ( ) 2001. 9.22 2 1 2 1.1... 3 1.2... 3 1.3 G P... 5 2 5 2.1... 6 2.2... 6 2.3 G P... 7 2.4... 7 3 8 3.1... 8 3.2... 9 3.3... 10 3.4... 11 3.5... 12 4 Dirac 13 4.1 Spin... 13 4.2 Spin
More informationDecember 28, 2018
e-mail : kigami@i.kyoto-u.ac.jp December 28, 28 Contents 2............................. 3.2......................... 7.3..................... 9.4................ 4.5............. 2.6.... 22 2 36 2..........................
More informationII 2 3.,, A(B + C) = AB + AC, (A + B)C = AC + BC. 4. m m A, m m B,, m m B, AB = BA, A,, I. 5. m m A, m n B, AB = B, A I E, 4 4 I, J, K
II. () 7 F 7 = { 0,, 2, 3, 4, 5, 6 }., F 7 a, b F 7, a b, F 7,. (a) a, b,,. (b) 7., 4 5 = 20 = 2 7 + 6, 4 5 = 6 F 7., F 7,., 0 a F 7, ab = F 7 b F 7. (2) 7, 6 F 6 = { 0,, 2, 3, 4, 5 },,., F 6., 0 0 a F
More informationSO(3) 7 = = 1 ( r ) + 1 r r r r ( l ) (5.17) l = 1 ( sin θ ) + sin θ θ θ ϕ (5.18) χ(r)ψ(θ, ϕ) l ψ = αψ (5.19) l 1 = i(sin ϕ θ l = i( cos ϕ θ l 3 = i ϕ
SO(3) 71 5.7 5.7.1 1 ħ L k l k l k = iϵ kij x i j (5.117) l k SO(3) l z l ± = l 1 ± il = i(y z z y ) ± (z x x z ) = ( x iy) z ± z( x ± i y ) = X ± z ± z (5.118) l z = i(x y y x ) = 1 [(x + iy)( x i y )
More information1 Abstract 2 3 n a ax 2 + bx + c = 0 (a 0) (1) ( x + b ) 2 = b2 4ac 2a 4a 2 D = b 2 4ac > 0 (1) 2 D = 0 D < 0 x + b 2a = ± b2 4ac 2a b ± b 2
1 Abstract n 1 1.1 a ax + bx + c = 0 (a 0) (1) ( x + b ) = b 4ac a 4a D = b 4ac > 0 (1) D = 0 D < 0 x + b a = ± b 4ac a b ± b 4ac a b a b ± 4ac b i a D (1) ax + bx + c D 0 () () (015 8 1 ) 1. D = b 4ac
More information6 6.1 L r p hl = r p (6.1) 1, 2, 3 r =(x, y, z )=(r 1,r 2,r 3 ), p =(p x,p y,p z )=(p 1,p 2,p 3 ) (6.2) hl i = jk ɛ ijk r j p k (6.3) ɛ ijk Levi Civit
6 6.1 L r p hl = r p (6.1) 1, 2, 3 r =(x, y, z )=(r 1,r 2,r 3 ), p =(p x,p y,p z )=(p 1,p 2,p 3 ) (6.2) hl i = jk ɛ ijk r j p k (6.3) ɛ ijk Levi Civita ɛ 123 =1 0 r p = 2 2 = (6.4) Planck h L p = h ( h
More informationK E N Z U 2012 7 16 HP M. 1 1 4 1.1 3.......................... 4 1.2................................... 4 1.2.1..................................... 4 1.2.2.................................... 5................................
More informationx V x x V x, x V x = x + = x +(x+x )=(x +x)+x = +x = x x = x x = x =x =(+)x =x +x = x +x x = x ( )x = x =x =(+( ))x =x +( )x = x +( )x ( )x = x x x R
V (I) () (4) (II) () (4) V K vector space V vector K scalor K C K R (I) x, y V x + y V () (x + y)+z = x +(y + z) (2) x + y = y + x (3) V x V x + = x (4) x V x + x = x V x x (II) x V, α K αx V () (α + β)x
More informationTOP URL 1
TOP URL http://amonphys.web.fc2.com/ 1 30 3 30.1.............. 3 30.2........................... 4 30.3...................... 5 30.4........................ 6 30.5.................................. 8 30.6...............................
More informationv v = v 1 v 2 v 3 (1) R = (R ij ) (2) R (R 1 ) ij = R ji (3) 3 R ij R ik = δ jk (4) i=1 δ ij Kronecker δ ij = { 1 (i = j) 0 (i
1. 1 1.1 1.1.1 1.1.1.1 v v = v 1 v 2 v 3 (1) R = (R ij ) (2) R (R 1 ) ij = R ji (3) R ij R ik = δ jk (4) δ ij Kronecker δ ij = { 1 (i = j) 0 (i j) (5) 1 1.1. v1.1 2011/04/10 1. 1 2 v i = R ij v j (6) [
More information8.1 Fubini 8.2 Fubini 9 (0%) 10 (50%) Carathéodory 10.3 Fubini 1 Introduction 1 (1) (2) {f n (x)} n=1 [a, b] K > 0 n, x f n (x) K < ( ) x [a
% 100% 1 Introduction 2 (100%) 2.1 2.2 2.3 3 (100%) 3.1 3.2 σ- 4 (100%) 4.1 4.2 5 (100%) 5.1 5.2 5.3 6 (100%) 7 (40%) 8 Fubini (90%) 2007.11.5 1 8.1 Fubini 8.2 Fubini 9 (0%) 10 (50%) 10.1 10.2 Carathéodory
More information1 n A a 11 a 1n A =.. a m1 a mn Ax = λx (1) x n λ (eigenvalue problem) x = 0 ( x 0 ) λ A ( ) λ Ax = λx x Ax = λx y T A = λy T x Ax = λx cx ( 1) 1.1 Th
1 n A a 11 a 1n A = a m1 a mn Ax = λx (1) x n λ (eigenvalue problem) x = ( x ) λ A ( ) λ Ax = λx x Ax = λx y T A = λy T x Ax = λx cx ( 1) 11 Th9-1 Ax = λx λe n A = λ a 11 a 12 a 1n a 21 λ a 22 a n1 a n2
More informationDirac 38 5 Dirac 4 4 γ µ p µ p µ + m 2 = ( p µ γ µ + m)(p ν γ ν + m) (5.1) γ = p µ p ν γ µ γ ν p µ γ µ m + mp ν γ ν + m 2 = 1 2 p µp ν {γ µ, γ ν } + m
Dirac 38 5 Dirac 4 4 γ µ p µ p µ + m 2 p µ γ µ + mp ν γ ν + m 5.1 γ p µ p ν γ µ γ ν p µ γ µ m + mp ν γ ν + m 2 1 2 p µp ν {γ µ, γ ν } + m 2 5.2 p m p p µ γ µ {, } 10 γ {γ µ, γ ν } 2η µν 5.3 p µ γ µ + mp
More informationIA 2013 : :10722 : 2 : :2 :761 :1 (23-27) : : ( / ) (1 /, ) / e.g. (Taylar ) e x = 1 + x + x xn n! +... sin x = x x3 6 + x5 x2n+1 + (
IA 2013 : :10722 : 2 : :2 :761 :1 23-27) : : 1 1.1 / ) 1 /, ) / e.g. Taylar ) e x = 1 + x + x2 2 +... + xn n! +... sin x = x x3 6 + x5 x2n+1 + 1)n 5! 2n + 1)! 2 2.1 = 1 e.g. 0 = 0.00..., π = 3.14..., 1
More information1 Euclid Euclid Euclid
II 2000 1 Euclid 1 1.1..................................... 1 1.2..................................... 8 1.3 Euclid............. 19 1.4 3 Euclid............................ 22 2 28 2.1 Lie Lie..................................
More information006 11 8 0 3 1 5 1.1..................... 5 1......................... 6 1.3.................... 6 1.4.................. 8 1.5................... 8 1.6................... 10 1.6.1......................
More information