F = 0 F α, β F = t 2 + at + b (t α)(t β) = t 2 (α + β)t + αβ G : α + β = a, αβ = b F = 0 F (t) = 0 t α, β G t F = 0 α, β G. α β a b α β α β a b (α β)
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1 t F := t 2 + at + b D := a 2 4b F = 0 a, b 1.1 F = 0 α, β α β a, b /stlasadisc.tex, cusp.tex, toileta.eps, toiletb.eps, fromatob.tex 1
2 F = 0 F α, β F = t 2 + at + b (t α)(t β) = t 2 (α + β)t + αβ G : α + β = a, αβ = b F = 0 F (t) = 0 t α, β G t F = 0 α, β G. α β a b α β α β a b (α β) 2 (α β) 2 = (α + β) 2 4αβ = a 2 4b = D. 1.2 t t + c c s = F (t) (t, s)- s t = 0 t 2 + at + b = ( t + a ) 2 a 2 4b 2 4 = ( t a ) 2 D t = c F F (c) s = F (t) (c, F (c)) c F = 0 (c, 0) t- F (c) = 0, F (c) = 0 F = 0 c R : F (c) = 0, F (c) = 0 2
3 R : c 2 + ac + b = 0, 2c + a = 0 c = a/2 0 = ( a ) 2 ( + a a ) + b = D D F (t) = 0, F (t) = 0 t F D ±D 2 t F := t 3 + pt 2 + qt + r F = 0 p, q, r 2.1 F = 0 α, β, γ (α β)(β γ)(γ α) p, q, r F = 0 F α, β, γ (t α)(t β)(t γ) = t 3 (α + β + γ)t 2 + (αβ + βγ + γα)t αβγ F = t 3 + pt 2 + qt + r G : α + β + γ = p, αβ + βγ + γα = q, αβγ = r 3
4 F = 0 F (t) = 0 t α, β, γ G t F = 0 α, β, γ G. α β p, q r (α β)(β γ)(γ α) p, q r D = (α β) 2 (β γ) 2 (γ α) 2 ( α, β, γ p, q, r 2.2 t t + c c t 3 + pt 2 + qt + r = ( t + p ) ) 3 + (q p2 t p r. t F F = t 3 + qt + r p = F (t) = 0, F (t) = 0 t t 3 + qt + r = 0, 3t 2 + q = 0 4
5 t 2 = q/3 0 = q 3 t + qt + r = 2 3r qt + r t = 3 2q. 4q r 2 = 0 t D = (α β) 2 (β γ) 2 (γ α) 2 p, q, r D 4q r 2 q, r q = αβ + βγ + γα, r = αβγ α + β + γ = 0 D = (4q r 2 ) D > 0 D < (q, r)- D = 4q r 2 = 0 parameter (t α) 2 (t β), 2α + β = 0 F = t 3 + qt + r q = 3α 2, r = 2α 3 α 1 α α ᾱ z = x+iy z = x iy z, w z + w = z + w, zw = z w 5
6 1 + 2 r 1 + (1 + 1) q : qr D = (1 + 1) D = (1 + 1) D = , (1 + 1) 2 \ / \ / 3 0 (q, r) , (1 + 1) ,
7 (1 + 1) : qr D = F = t 3 + qt + r q, r α, β, γ = α β t = α + β, q = αβ + βγ + γα = αβ (α + β) 2, r = αβγ = αβ(α + β) s = αβ q = s t 2, r = st 4q r 2 = (s + 2t 2 ) 2 (4s t 2 ) (s, t) (q, r) = (s t 2, st) (s, t) 3 ; 3 t F F = 0 t t + c c F F = t 4 + xt 2 + yt + z 7
8 r t e d c b a s c e b a q d 3.1 3: (s, t) (q, r) = (s t 2, st) F = 0 α, β, γ, δ = (α β)(α γ)(α δ) (β γ)(β δ) (γ δ) 2 D α + β + γ + δ = 0, αβ + αγ + αδ + βγ + βδ + γδ = x, βγδ + αγδ + αβδ + αβγ = y, αβγδ = z D x, y, z F (t) = 0, F (t) = 0 t t 4 + xt 2 + yt + z = 0, 4t 3 + 2xt + y = 0 t t t t 3 t t 4 = t t 3 t t 2 8
9 t t 3 = t t 2 t t t 2 t x, y, z t 256z 3 128x 2 z 2 + (144y 2 x + 16x 4 )z 4y 2 x 3 27y 4 D z z/4 F = t 4 + xt 2 + yt + z 4, D := 4z 3 8x 2 z 2 + (36y 2 x + 4x 4 )z (27y 2 + 4x 3 )y xyz- D = 0 S t 4 + xt 2 + yt + z/4 = (1 + 1) (1 + 1) + (1 + 1) (1 + 1) (1 + 1) t 4 (x, y, z) = (0, 0, 0) (1 + 1) 9
10 (1 + 1) + (1 + 1) (1 + 1) (1 + 1) 4. (x, y, z)- S 2(1 + 1) (1 + 1) + (1 + 1) S : , , (1 + 1) S (1 + 1) + (1 + 1) (1 + 1) S γ = α, δ = β (t α) 2 (t β) 2, 2α + 2β = 0 t 4 2α 2 t 2 +α 4 F = t 4 +xt 2 +yt+z/4 = 0 P : (x, y, z) = (x, 0, x 2 ), x < 0 10
11 (1 + 1) 4: xyz S : D = , γ = δ = α (t α) 3 (t β), 3α + β = 0 F C : (x, y, z) = ( 6α 2, 8α 3, 12α 4 ) xy- z (1 + 1) α = β = iη, γ = δ = iη (t iη) 2 (t + iη) 2 = (t 2 + η 2 ) 2 = t η 2 t η 4 4 F P + : (x, y, z) = (x, 0, x 2 ), x > 0 11
12 3.4 S : D = 0 D = 0 S δ = γ (t α)(t β)(t γ) 2, α + β + 2γ = 0 F = t 4 + xt 2 + yt + z/4 x = 3 4 α2 1 2 αβ 3 4 β2, y = 1 4 (α + β)( β + α)2, z = (α + β) 2 αβ α, β α, β α < β < γ α, β α < γ < β α, β γ < α < β α, β 2 + (1 + 1) x, y, z α, β α β α + β = a, αβ = b a, b x = 3 4 a2 + b, y = 1 4 a(a2 4b), z = 4a 2 b ab- 5 α = β a 2 4b = 0, α = γ 3a 2 + 4b = 0. a, b 6 : x α = 3 2 a, x β = 1, y α = 1 4 (3a2 4b), y β = a, z α = 2ab, z β = a2. 12
13 b a 2 4b = (1 + 1) a a 2 + 4b = : S (a, b) 6: ( (1 + 1) (1 + 1) 7 swallowtail P P P C 13
14 P C 7: 4 14
ax 2 + bx + c = n 8 (n ) a n x n + a n 1 x n a 1 x + a 0 = 0 ( a n, a n 1,, a 1, a 0 a n 0) n n ( ) ( ) ax 3 + bx 2 + cx + d = 0 4
20 20.0 ( ) 8 y = ax 2 + bx + c 443 ax 2 + bx + c = 0 20.1 20.1.1 n 8 (n ) a n x n + a n 1 x n 1 + + a 1 x + a 0 = 0 ( a n, a n 1,, a 1, a 0 a n 0) n n ( ) ( ) ax 3 + bx 2 + cx + d = 0 444 ( a, b, c, d
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漸化式のすべてのパターンを解説しましたー高校数学の達人・河見賢司のサイト
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88 th Annual Meeting of the Zoological Society of Japan Abstracts 88 th Annual Meeting of the Zoological Society of Japan Abstracts 88 th Annual Meeting of the Zoological Society of Japan Abstracts 88
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88 th Annual Meeting of the Zoological Society of Japan Abstracts 88 th Annual Meeting of the Zoological Society of Japan Abstracts 88 th Annual Meeting of the Zoological Society of Japan Abstracts 88
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x, y x 3 y xy 3 x 2 y + xy 2 x 3 + y 3 = x 3 y xy 3 x 2 y + xy 2 x 3 + y 3 = 15 xy (x y) (x + y) xy (x y) (x y) ( x 2 + xy + y 2) = 15 (x y)
x, y x 3 y xy 3 x 2 y + xy 2 x 3 + y 3 = 15 1 1977 x 3 y xy 3 x 2 y + xy 2 x 3 + y 3 = 15 xy (x y) (x + y) xy (x y) (x y) ( x 2 + xy + y 2) = 15 (x y) ( x 2 y + xy 2 x 2 2xy y 2) = 15 (x y) (x + y) (xy
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BD = a, EA = b, BH = a, BF = b 3 EF B, EOA, BOD EF B EOA BF : AO = BE : AE, b : = BE : b, AF = BF = b BE = bb. () EF = b AF = b b. (2) EF B BOD EF : B
2000 8 3.4 p q θ = 80 B E a H F b θ/2 O θ/2 D A B E BD = a, EA = b, BH = a, BF = b 3 EF B, EOA, BOD EF B EOA BF : AO = BE : AE, b : = BE : b, AF = BF = b BE = bb. () EF = b AF = b b. (2) EF B BOD EF :
1 Abstract 2 3 n a ax 2 + bx + c = 0 (a 0) (1) ( x + b ) 2 = b2 4ac 2a 4a 2 D = b 2 4ac > 0 (1) 2 D = 0 D < 0 x + b 2a = ± b2 4ac 2a b ± b 2
1 Abstract n 1 1.1 a ax + bx + c = 0 (a 0) (1) ( x + b ) = b 4ac a 4a D = b 4ac > 0 (1) D = 0 D < 0 x + b a = ± b 4ac a b ± b 4ac a b a b ± 4ac b i a D (1) ax + bx + c D 0 () () (015 8 1 ) 1. D = b 4ac
VI VI.21 W 1,..., W r V W 1,..., W r W W r = {v v r v i W i (1 i r)} V = W W r V W 1,..., W r V W 1,..., W r V = W 1 W
3 30 5 VI VI. W,..., W r V W,..., W r W + + W r = {v + + v r v W ( r)} V = W + + W r V W,..., W r V W,..., W r V = W W r () V = W W r () W (W + + W + W + + W r ) = {0} () dm V = dm W + + dm W r VI. f n
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No δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i x j δx j (5) δs 2
No.2 1 2 2 δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i δx j (5) δs 2 = δx i δx i + 2 u i δx i δx j = δs 2 + 2s ij δx i δx j
(iii) 0 V, x V, x + 0 = x. 0. (iv) x V, y V, x + y = 0., y x, y = x. (v) 1x = x. (vii) (α + β)x = αx + βx. (viii) (αβ)x = α(βx)., V, C.,,., (1)
1. 1.1...,. 1.1.1 V, V x, y, x y x + y x + y V,, V x α, αx αx V,, (i) (viii) : x, y, z V, α, β C, (i) x + y = y + x. (ii) (x + y) + z = x + (y + z). 1 (iii) 0 V, x V, x + 0 = x. 0. (iv) x V, y V, x + y
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