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1 f() = + b + c n. f n < λ < 1 λ u, v R n f((1 λ)u + λv) (1 λ)f(u)+λf(v) (.1) f u = v f ( 1) f f : 1. (1 λ)u + λv u, v (1 λ)f(u)+λf(v) f(u),f(v) (.1)
2 14 f (u, f(u)) (v, f(v)) f f(a) 1 f(a)+1 f(b) f f(b) 1 a + 1 b O a 1 a + 1 b b.: 1 λ = 1 f (u, f(u)) (v, f(v)) f f(, ) = f u =(1, ) v =(, ).3: z = λ (1 λ)u + λv =(1 λ) + λ =
3 f((1 λ)u + λv) =f(1 + λ, ) = 1 + λ (1 λ)f(u)+λf(u) =(1 λ) 1+λ =1+λ u v f.3 f u =(u 1, ),v =(v 1, ) (u, f(u)) (v, f(v)).1..1 f (a, b, f(a, b)) f z = f(a, b)+f (a, b)( a)+f (a, b)( b). f, (a, b), (, ) R, f(, ) f(a, b)+f (a, b)( a)+f (a, b)( b) (.). n. f (, ) f (, ) f(, ) = f (, )
4 16 f (, ) n f u =( 1,..., n ) f 1 (u) f (u) f(u) =. f n (u) 3. f(, ) = +3 (5, 3) f =, f =6 f (5, 3) 5 1 f(5, 3) = = = f (5, 3) (.1.) 1. n f u, v R n f(v) f(u)+ f(u) (v u) f(u) (v u) f(u) (v u).. u, v R n,< λ < 1 f f((1 λ)u + λv) =f(u + λ(v u)) = f(u)+ f(u) {λ(u v)} + o(λ u v ) (1 λ)f(u)+λf(v) f ((1 λ)u + λv) = f (u + λ(v u)) = f(u)+λ f(u) (v u)+o(λ v u ), λf(v) λf(u)+λ f(u) (v u)+o(λ v u ), f(v) f(u)+ f(u) (v u)+ o(λ v u ) λ λ o(λ u v ) λ
5 f() = f() = f () = 1+, f () = 1 (1 + ) 3 f () > f() 1 h h (t) (t 1 <t h (t 1 ) h (t )) t R h (t) h() = 4 h () =4 3 h () =1 g(, ) = +.1.1, 1 1,. f (, ), [ ] f (, ) f (, ) f(, ) = f (, ) f (, ). f = f
6 18,,, f(, ) = f(, ) = [ f(, ) = [ ] ] 6 6. n f u =( 1,..., n ),. f 1 1 (u) f 1 (u)... f 1 n (u) f. f(u) = 1 (u).... f n 1 (u) f n n (u). n f (1). f a R n, t u f(a)u u R n (). f = a R n, t u f(a)u > u u R n.. b, c R n h(t) =f ((1 t)b + tc) f b, c R n h(t)
7 .. 19 h 1 h(t) h (t) { a =(1 t)b + tc = b + t(c b) u = c b h (t) = t u f(a)u 4. f(, ) = + f(, ) = +4 f(, ) = 4 f. u = t (u 1,u ) (, ) t u 1 u f(, )u =[u 1 u ] =u 1 4u 1 u +4u 4 u u 1 4u 1 u +4u =(u 1 u 1 u +u )= { (u 1 u ) + u } f u.. A t uau
8 . A u =(u 1,u,...,u n ) u 1,...,u n p(u) = t uau 5. A =, 1 u =(, ) t uau =[ ] =[ ] = + 1 B = t ubu =[ ] =[ ] = + + = +. A u R n t uau A A u u R t uau > A A
9 .. 1 u R t uau A 6. 5 A = 1 u =(, ) t uav = + + > (u ) A 1 1 B = 1 1 t ubu = + u =(1, ) t ubu =1> u =(, 1) t ubu = 1 < B 3 ( ). n f f a R n f(a) f = a R n f(a),,.,? 5
10 4. A (1). A A (). A A (3). A A. A n n A P, P 1 AP = Λ, Λ A P 1 = t P v = t Pu u = Pv t uau = t (Pv)A(Pv)= t v( t P AP )v = t vλv = λ 1 v λ n v n v =(v 1,...,v n ) λ 1,...,λ n A t uau u (1) 7. f(, ) = f(, ) =, 6 f(, ) = 6 6 4, 8 f, [. ] a b A =, a. (, ) R, b d [ ]A ( = a +b + d = a + b ) + a ( = a + b a A A ad b a (ad b ) ) + 1 a A (.3)
11 (1). A > a> A (). A > a< A (3). A < A. (1) A > a> (, ) (, ) [ ]A > ( a + b ) + 1 a a A ( a + b ) + 1 a a A = ( + b ) =, = a (, ) =(, ) (.3) (, ) (, ) [ ]A > (, ) =(1, ) a > 4 A > () (3) f(, ) = 6 f(, ) =3> f (, ) =6>
12 4 3 f(v) f(u)+ f(u) (u v) t u f(a)u f(a) u n f(a) = t u f(a)u > u = u n f(a) f(a) f(a) = f (a) f (a) f(a) = f (a) f (a) f (a) f (a) t uau =[ ] a c b d = a +(b + c) + d
chapter4.PDF
4. 4.1. 4.2. 63 4 1 4.3. 4.3.1. 4 a) 1 5 b) 1 c) d) 1 4.3.2. a) b) c) a) 10 18 b) 2 17 2 1 54 2 1 c) 11 4 1 1 (TB) (FB) TB FB 4.3.3. 4.3.4. 1 18 16 4.3.5. a) b) 18 16 a) b) c) 1 18 16 2 1 18 16 3 18 16
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No. 1 2 No. 3 4 5 6 7 8 9 10 11 12 No. 13 14 15 16 17 18 19 20 21 22 23 24 25 26 No. 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 No. 44 45 46 47 48 49 50 51 52 No. 53 54 55 56 57 58 59 60 61 62
lecture
5 3 3. 9. 4. x, x. 4, f(x, ) :=x x + =4,x,.. 4 (, 3) (, 5) (3, 5), (4, 9) 95 9 (g) 4 6 8 (cm).9 3.8 6. 8. 9.9 Phsics 85 8 75 7 65 7 75 8 85 9 95 Mathematics = ax + b 6 3 (, 3) 3 ( a + b). f(a, b) ={3 (a
VI VI.21 W 1,..., W r V W 1,..., W r W W r = {v v r v i W i (1 i r)} V = W W r V W 1,..., W r V W 1,..., W r V = W 1 W
3 30 5 VI VI. W,..., W r V W,..., W r W + + W r = {v + + v r v W ( r)} V = W + + W r V W,..., W r V W,..., W r V = W W r () V = W W r () W (W + + W + W + + W r ) = {0} () dm V = dm W + + dm W r VI. f n
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13-1 03-3862-9111 ( FAX03-3862- ) 9140 13-2 03-3219-8080 13-3 03-3293-1711 250 13-4 03-3292-2051 1-8 8111 13-5 8 11 28 ( 8 111 03-3261-5511 2 18 41 9 91 15 41 15 41 47 13-6 47 9 4 4 03-5343-5611 F 47 47
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6 6 6 6 1 2 3 4 5 6 7 8 R B1 B1 1 2 3 4 5 6 7 8 9
6 6 6 6 1 2 3 4 5 6 7 8 R B1 B1 1 2 3 4 5 6 7 8 9 B1F 7306730 96730 1F & 1069 2F & & 93069 3F 4F 1069 969 5F 6F 7F & & 8F 8F 9F 8306515 96.0534582130 1068 1066 4.0534582180 83069 0120-53-4305 0534542218
2
2 3 4 5 6 7 0 10 20 30 40 50 60 70 9 10 11 12 13 14 15 86.0% 14.0% 79.5% 20.5% 60 111 16 .. 17 ** p
limit&derivative
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1 y(t)m b k u(t) ẋ = [ 0 1 k m b m x + [ 0 1 m u, x = [ ẏ y (1) y b k m u
( ) LPV( ) 1 y(t)m b k u(t) ẋ = [ 0 1 k m b m x + [ 0 1 m u, x = [ ẏ y (1) y b k m u m 1 m m 2, b 1 b b 2, k 1 k k 2 (2) [m b k ( ) k 0 b m ( ) 2 ẋ = Ax, x(0) 0 (3) (x(t) 0) ( ) V (x) V (x) = x T P x >
1 3 3 5 6 9 10 12 13 14 15 17 18 18 19 20 22 24 25 28 28 29 30 31 31 32 32 33 33 2 34 35 35 36 36 36 39 40 41 41 42 43 43 44 44 45 48 50 50 51 51 51 52 53 55 57 59 61 63 65 67 69 71 73 75 77 3 82 84 86
II 2 3.,, A(B + C) = AB + AC, (A + B)C = AC + BC. 4. m m A, m m B,, m m B, AB = BA, A,, I. 5. m m A, m n B, AB = B, A I E, 4 4 I, J, K
II. () 7 F 7 = { 0,, 2, 3, 4, 5, 6 }., F 7 a, b F 7, a b, F 7,. (a) a, b,,. (b) 7., 4 5 = 20 = 2 7 + 6, 4 5 = 6 F 7., F 7,., 0 a F 7, ab = F 7 b F 7. (2) 7, 6 F 6 = { 0,, 2, 3, 4, 5 },,., F 6., 0 0 a F
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Chap9.dvi
.,. f(),, f(),,.,. () lim 2 +3 2 9 (2) lim 3 3 2 9 (4) lim ( ) 2 3 +3 (5) lim 2 9 (6) lim + (7) lim (8) lim (9) lim (0) lim 2 3 + 3 9 2 2 +3 () lim sin 2 sin 2 (2) lim +3 () lim 2 2 9 = 5 5 = 3 (2) lim
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![24 I ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x](/thumbs/94/118744578.jpg "24 I ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x")
24 I 1.1.. ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x 1 (t), x 2 (t),, x n (t)) ( ) ( ), γ : (i) x 1 (t),
HITACHI 液晶プロジェクター CP-AX3505J/CP-AW3005J 取扱説明書 -詳細版- 【技術情報編】
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取扱説明書 -詳細版- 液晶プロジェクター CP-AW3019WNJ
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Catalog No.AR006-e DIN EN ISO 9001 JIS Z 9901 Certificate: 販売終了
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HITACHI 液晶プロジェクター CP-EX301NJ/CP-EW301NJ 取扱説明書 -詳細版- 【技術情報編】 日本語
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1 1 3 ABCD ABD AC BD E E BD 1 : 2 (1) AB = AD =, AB AD = (2) AE = AB + (3) A F AD AE 2 = AF = AB + AD AF AE = t AC = t AE AC FC = t = (4) ABD ABCD 1 1
ABCD ABD AC BD E E BD : () AB = AD =, AB AD = () AE = AB + () A F AD AE = AF = AB + AD AF AE = t AC = t AE AC FC = t = (4) ABD ABCD AB + AD AB + 7 9 AD AB + AD AB + 9 7 4 9 AD () AB sin π = AB = ABD AD
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1 1 y = y() y, y,..., y (n) : n y F (, y, y,..., y (n) ) = 0 n F (, y, y ) = 0 1 y() 1.1 1 y y = G(, y) 1.1.1 1 y, y y + p()y = q() 1 p() q() (q() = 0) y + p()y = 0 y y + py = 0 y y = p (log y) = p log
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頼美麗-三校.indd
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(1) 3 A B E e AE = e AB OE = OA + e AB = (1 35 e ) e OE z 1 1 e E xy e = 0 e = 5 OE = ( 2 0 0) E ( 2 0 0) (2) 3 E P Q k EQ = k EP E y 0
(1) 3 A B E e AE = e AB OE = OA + e AB = (1 35 e 0 1 15 ) e OE z 1 1 e E xy 5 1 1 5 e = 0 e = 5 OE = ( 2 0 0) E ( 2 0 0) (2) 3 E P Q k EQ = k EP E y 0 Q y P y k 2 M N M( 1 0 0) N(1 0 0) 4 P Q M N C EP
6 2 2 x y x y t P P = P t P = I P P P ( ) ( ) ,, ( ) ( ) cos θ sin θ cos θ sin θ, sin θ cos θ sin θ cos θ y x θ x θ P
6 x x 6.1 t P P = P t P = I P P P 1 0 1 0,, 0 1 0 1 cos θ sin θ cos θ sin θ, sin θ cos θ sin θ cos θ x θ x θ P x P x, P ) = t P x)p ) = t x t P P ) = t x = x, ) 6.1) x = Figure 6.1 Px = x, P=, θ = θ P
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del.dvi
(2013, c ) http://istksckwanseiacjp/ ishiura/lc/ 1 2, 8, 16 2 10 (2 ) 11 2, 8, 16 10 (decimal) 1192 10 = 1 10 3 + 1 10 2 + 9 10 1 + 2 10 0 (a n 1 a n 2 a 1 a 0 ) 10 = 8 (octal) n 1 i=0 a i 10 i 710 8 =
Holton semigeostrophic semigeostrophic,.., Φ(x, y, z, t) = (p p 0 )/ρ 0, Θ = θ θ 0,,., p 0 (z), θ 0 (z).,,,, Du Dt fv + Φ x Dv Φ + fu +
Holton 9.2.2 semigeostrophic 1 9.2.2 semigeostrophic,.., Φ(x, y, z, t) = (p p 0 )/ρ 0, Θ = θ θ 0,,., p 0 (z), θ 0 (z).,,,, Du Dt fv + Φ x Dv Φ + fu + Dt DΘ Dt + w dθ 0 dz = 0, (9.2) = 0, (9.3) = 0, (9.4)
平成23年度記録
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( ) ー ( () ) 250 200 150 100 50 0 51 20 54 59 33 35 91 92 93 98 99 94 6 7 7 8 9 11 18 17 18 20 22 23 10 9 8 9 9 9 62 40 66 74 41 47 21 22 23 24 25 26 10 8 6 4 2 0 m3/s 7 41.3 5 5 18.4
x () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x
[ ] IC. f(x) = e x () f(x) f (x) () lim f(x) lim f(x) x + x (3) lim f(x) lim f(x) x + x (4) y = f(x) ( ) ( s46). < a < () a () lim a log xdx a log xdx ( ) n (3) lim log k log n n n k=.3 z = log(x + y ),
(1) 1 y = 2 = = b (2) 2 y = 2 = 2 = 2 + h B h h h< h 2 h
6 6.1 6.1.1 O y A y y = f() y = f() b f(b) B y f(b) f() = b f(b) f() f() = = b A f() b AB O b 6.1 2 y = 2 = 1 = 1 + h (1 + h) 2 1 2 (1 + h) 1 2h + h2 = h h(2 + h) = h = 2 + h y (1 + h) 2 1 2 O y = 2 1
Case 1 a,b,α, β α α + β β α = ua + vb β = sa + tb α α + β β = (ua + vb (ua + vb + (sa + tb (sa + tb = (u a a + uva b + uvb a + v b b + (s a a + sta b
Bogoliubov H = a a + aa < 0 H 0 >, < 1 H 1 >, < H > < H 0 > a H = α α α α, α = 1, α, α = α, α = 0 α α α H = α α Postulate( a,b α, β a, a = b, b = 1, a, b = b, a = 0 α, α = β, β = 1, α, β = β, α = 0 α,
sekibun.dvi
a d = a + a+ (a ), e d = e, sin d = cos, (af() + bg())d = a d = log, cosd = sin, f()d + b g()d d 3 d d d d d d d ( + 3 + )d ( + )d ( 3 )d (e )d ( sin 3 cos)d g ()f (g())d = f(g()) e d e d ( )e d cos d
日立液晶プロジェクター CP-AW2519NJ 取扱説明書- 詳細版-
PAGE UP DOWN D- ESC ENTER 1 1 2 2 3 COMPUTER IN1 USB TYPE A DC5V 0.5A USB TYPE B HDMI COMPUTER IN2 LAN CONTROL MONITOR OUT MIC AUDIO IN1 AUDIO IN3 AUDIO OUT R R L L S-VIDEO AUDIO IN2 VIDEO PAGE UP DOWN
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Microsoft Word - CTCWEB講座（4章照査）0419.doc
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橡いつとき.PDF
1997 A6 30 TC tokimekiclub@geocities.co.jp 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56
2 (2016 3Q N) c = o (11) Ax = b A x = c A n I n n n 2n (A I n ) (I n X) A A X A n A A A (1) (2) c 0 c (3) c A A i j n 1 ( 1) i+j A (i, j) A (i, j) ã i
[ ] (2016 3Q N) a 11 a 1n m n A A = a m1 a mn A a 1 A A = a n (1) A (a i a j, i j ) (2) A (a i ca i, c 0, i ) (3) A (a i a i + ca j, j i, i ) A 1 A 11 0 A 12 0 0 A 1k 0 1 A 22 0 0 A 2k 0 1 0 A 3k 1 A rk
January 27, 2015
e-mail : kigami@i.kyoto-u.ac.jp January 27, 205 Contents 2........................ 2.2....................... 3.3....................... 6.4......................... 2 6 2........................... 6
5 1.2, 2, d a V a = M (1.2.1), M, a,,,,, Ω, V a V, V a = V + Ω r. (1.2.2), r i 1, i 2, i 3, i 1, i 2, i 3, A 2, A = 3 A n i n = n=1 da = 3 = n=1 3 n=1
4 1 1.1 ( ) 5 1.2, 2, d a V a = M (1.2.1), M, a,,,,, Ω, V a V, V a = V + Ω r. (1.2.2), r i 1, i 2, i 3, i 1, i 2, i 3, A 2, A = 3 A n i n = n=1 da = 3 = n=1 3 n=1 da n i n da n i n + 3 A ni n n=1 3 n=1
1/68 A. 電気所 ( 発電所, 変電所, 配電塔 ) における変圧器の空き容量一覧 平成 31 年 3 月 6 日現在 < 留意事項 > (1) 空容量は目安であり 系統接続の前には 接続検討のお申込みによる詳細検討が必要となります その結果 空容量が変更となる場合があります (2) 特に記載
1/68 A. 電気所 ( 発電所, 変電所, 配電塔 ) における変圧器の空き容量一覧 平成 31 年 3 月 6 日現在 < 留意事項 > (1) 空容量は目安であり 系統接続の前には 接続検討のお申込みによる詳細検討が必要となります その結果 空容量が変更となる場合があります (2) 特に記載のない限り 熱容量を考慮した空き容量を記載しております その他の要因 ( 電圧や系統安定度など ) で連系制約が発生する場合があります
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欧州特許庁米国特許商標庁との共通特許分類 CPC (Cooperative Patent Classification) 日本パテントデータサービス ( 株 ) 国際部 2019 年 7 月 31 日 CPC 版が発効します 原文及び詳細はCPCホームページのCPC Revision
欧州特許庁米国特許商標庁との共通特許分類 CPC (Cooperative Patent Classification) 日本パテントデータサービス ( 株 ) 国際部 2019 年 7 月 31 日 CPC 2019.08 版が発効します 原文及び詳細はCPCホームページのCPC Revisions(CPCの改訂 ) をご覧ください https://www.cooperativepatentclassification.org/cpcrevisions/noticeofchanges.html
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