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1 8016! [! A] (1) (3) 3 3 (1) f0x 1=(1+a)(1-x)+(-a)x=(-1-a+-a)x+a+1=(-3a+1)x+a+1 =(- a+ )x+a+1 (1) 0 ( x ( 1f0x1 a( 1 3 f 0x1f00=a+1= 1 a+ a 1 3 f 0x1f01=-a+= 1 a+ 0 ( x ( 1 f0x 1 ) 0a+ 1 a 3 a( 1 3 a+1) 0a ( a ( 1 3 a 1 3 -a+) 0a a ( = 1 4 ( a ( = (3) 1 4 (a( 1 3 g 1 0a 1=a+1g 89 4 = 3 g = a ( g 1 0a 1=-a+g 89 3 = 3 g 89 = ( a ( g 0a1 = 3 = 3
2 (1) A B () { 0 } "0" 0 A X { 0 } + =3 () U8 =U7 U8 B U8 \B + =0 () A X { 0 } A= { 0 }A + = () A B u=a3b + =4 x p q r px qx+u8 ru8 x x+u8 =x+u7 x+u8 x=a-u7 a qpp q p q U8 x=u7 x x=au7 a=0a=a-u7 a-x x U8 x p r 1 (1)\]WX3 (1) a 1 x x +(0-a )x-0a (0 x +4ax)0 (1) (x-a )(x+0) ( 0 =-0 ( x ( a 1 x(x+4a) ) 0 x( =-4a =0 ( x a1(a 1-0 ( -4a ( ( a ( = 1
3 0 ( a -0)0 (-4a+0) a - a+ = a -4a+0 a -4a+0 = (a-) +16 a a= = = a= = = a 0 a ABC AB =4 BC=6 CA= 10 3 (BC) =(AB) +(AC) - AB! AC cos4bac cos4bac = 010/31 6 = -1 % 4% 10/3 3 = sin4bac =U 1-0cos4BAC 1 = U = U 3 ABC 1 %AC % (sin4bac )%AB = 1 % 10 3 % U 3 %4 = 40 U 9 BC R = sin4bac = 6/ sin 4BAC =3% 3 U = 9 U 4 4BOD=%4BAD=4BAC cos4bod=cos4bac = -1 3 = = U = U BD=U 0OD1 + 0OB 1 -OD% OB cos4bod =U RU1- cos4bod =U % 9 U 4 sin4bca = AB R + sin 4BCA sin 4BCD = AB BD = 4 3U3 = 4 U 3 9 % U3 =3 U3 =U sin4bcd=sin4bad= BD R = U
4 DBC = 1 %CD % (sin4bdc )%BD= 1 %3 U3 %3U3 % (sin4bdc ) ABC = 1 %AC % (sin4bac )%AB = 1 % 10 3 %4%(sin4BAC ) 4BDC=4BAC ABC DBC = = C D O A 4 B 0 (1) (1) 1 3 (3) (1) 0 1 % 70%%
5 3 4 % % % % 3 % 4 % 6 % 7 % (1) N b N M a M 0 M % 1 NM % 3 ON 4 % 1 3 (3) Y X Y X 89 9 = = 81 9 W Z = 9 9 V U =1 Nx i y i = 9 x i +3i n
6 89 9 X= s x Y= s y = x s = ] 1 n 60-1 x1 x n 1 7 s y 8s x 9 Y X = 9 89 = x x y s x s = ] 1 n 60-1 y1 y y - n y1 7 p i q i = 9 p i +3 NZ= s px = 1 n {( p1-p)( x1-x)+!!! +( pn-p )( xn-x)} NW= s py = 1 n {( p1-p)( y1-y)+!!! +( pn-p)( yn-y)} = 1 n W Z = s py = 9 s px s NU= px sps x s NV= py sps y V U = s py sx s s = 9 % 9 =1 px y 9 {( p1-p)( x1-x)+!!! +( pn-p )( xn-x)} 9 (1) (3)!
7 (1) (1) (1) (1) (1) 30 (1) (3) (1) 1 3 (3) (1) R= = 1 7U3 sin 60, =7 PB=aPA=bb=3a (7U3 ) = a + b -abcos60,= 4 9 b + b - 3 b = 7 9 PABS= 1 PA!PB sin60, = U 3 4 ab b + PA=U =b=3u1 (7U3 ) = a + b -abcos60,= a + b -ab= 0a-b 1 +abab=147-0a-b 1 (147
8 ab a=b b =(7U3 ) S PA=b=7U3 =U (3) sin4pba(1pa4pba=90,sin4pba=1 PA =14= PABS = 1 AB!PA sin4pab= 1 %7 U3 %14sin30, = 7 U 3 %14% 1 = 49 U3 = U (1) 0 (1) (3) (1) A B 1 % 7 11 A B 7 1 % 11 A B 7 1 % % 1 8 (3+3+4) = = A 4 1 B 11 A B 4 1 % 11 = 33 = A B 33 & 4 1 = 11 =
9 (3) A 3 1 B 11 3 A B 1 % 11 = 44 = A 1 B 4 11 A B B 1 % 4 11 = = 1 = B A 33 & 1 = 4 11 = UV P(UV)=P(U)P U (V)P U (V) U V UV P(BA)=P(B )%P(BA) P(BA)= 33 P(B)= 1 P(BA)= 33 & 1 = 4 11 = 0 (1) (1) 9x+197y=1x+y y= 1 9 x+y= 1-13y y=9mm 9 y x m=1 y=-7x=1 m=-1y x=1= y=-7= x x y 9x+197y=10x+y y= 9 9 x+y= 10-13y y=9m=(13%7+1)mm 10-m=13(y+7m)
10 m=-3 y= y x=-3-y=-47 x=-47= y== x x y =1% 4 +1% 3 +0% +1% 1 +1% 0 =7=4%4+%4+3=1% 4 +% % (4) = ( 4) (6) =3% 6-1 =1/ (6) =4% 6-1 =/ (6) =3% % 6 - =1/+3/36=7/ (6) =4% % 6 - =4/6+3/36=7/36=3/ (6) =3% % 6-3 =3/36+3/16=7/ (6) =4% % 6-3 =4/36+3/16=9/7=1/8 0 3 (1) 9x+197y=1x y (1) DAC=4DBC=4DCA=4ABD= 0 EC AE = CBE ABE ABE = 1 AB%BE%(sin4ABE) CBE = 1 + EC AE = 1 = CB%BE%(sin4CBE )4ABE =4CBE CBE ABE = CB AB = 4 ACDFE FA DF! EC AE! GD CG = 3 % 1 % GD CG =1 + CG DG = 1 3 =
11 (1) AB G AGD DF FA! AB BG! GC CD = 3 % AB BG % 1 = 1+ BG = 3 4 AB = 3 = 4GAE =4GDB AGCQ DGB + GC AG = GB DG AG =7GB =3 GC = 1 DC DG = 3 DC DC = U7 = U ABC4A 4B 4C ABCR R= BC sin 4A = AB sin 4C R= sin 4A = 4 sin4c =sin4a sin 4C R sin4c sin4c =14C=90, R 4 = sin4a = 1 sin4c = 1 4A=30, 4BAC =4A = 30, =, 4ABC=60,AD=DC4ABD=4DBC=30,4ACD=4ABD=30,=4CAB ABSDC+ AH BH = GC DG = 1 3 AH BH = AH BA+ AH = AH 4+ AH = AH== D D C G F F E A E H A B C B G (1) AGD
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II (1 4 ) 1. p.13 1 (x, y) (a, b) ε(x, y; a, b) f (x, y) f (a, b) A, B (6.5) y = b f (x, b) f (a, b) x a = A + ε(x, b; a, b) x a x a A = f x (a, b) y x 3 3y 3 (x, y) (, ) f (x, y) = x + y (x, y) = (, )
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A. A. A-- [ ] f(x) x = f 00 (x) f 0 () =0 f 00 () > 0= f(x) x = f 00 () < 0= f(x) x = A--2 [ ] f(x) D f 00 (x) > 0= y = f(x) f 00 (x) < 0= y = f(x) P (, f()) f 00 () =0 A--3 [ ] y = f(x) [, b] x = f (y)
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