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物理化学I-第12回(13).ppt

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Chap. 1 NMR

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2 Zn Zn + MnO 2 () 2 O 2 2 H2 O + O 2 O 2 MnO 2 2 KClO 3 2 KCl + 3 O 2 O 3 or 3 O 2 2 O 3 N 2 () NH 4 NO 2 2 O + N 2 ( ) MnO HCl Mn O + CaCl(ClO

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(Compton Scattering) Beaming 1 exp [i (k x ωt)] k λ k = 2π/λ ω = 2πν k = ω/c k x ωt ( ω ) k α c, k k x ωt η αβ k α x β diag( + ++) x β = (ct, x) O O x

Compton Scattering Beaming exp [i k x ωt] k λ k π/λ ω πν k ω/c k x ωt ω k α c, k k x ωt η αβ k α x β diag + ++ x β ct, x O O x O O v k α k α β, γ k γ k βk, k γ k + βk k γ k k, k γ k + βk 3 k k 4 k 3 k

第１部　一般的コメント

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1 1.1 ( ). z = a + bi, a, b R 0 a, b 0 a 2 + b 2 0 z = a + bi = ( ) a 2 + b 2 a a 2 + b + b 2 a 2 + b i 2 r = a 2 + b 2 θ cos θ = a a 2 + b 2, sin θ =

1 1.1 ( ). z = + bi,, b R 0, b 0 2 + b 2 0 z = + bi = ( ) 2 + b 2 2 + b + b 2 2 + b i 2 r = 2 + b 2 θ cos θ = 2 + b 2, sin θ = b 2 + b 2 2π z = r(cos θ + i sin θ) 1.2 (, ). 1. < 2. > 3. ±,, 1.3 ( ). A

128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds = 0 (3.4) S 1, S 2 { B( r) n( r)}ds

127 3 II 3.1 3.1.1 Φ(t) ϕ em = dφ dt (3.1) B( r) Φ = { B( r) n( r)}ds (3.2) S S n( r) Φ 128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds

第１章　国民年金における無年金

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橡実験IIINMR.PDF

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橡ミュラー列伝Ⅰ.PDF

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機器分析化学 ３．核磁気共鳴（NMR)法（1）

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koji07-01.dvi

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Microsoft Word - 章末問題

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タイトル

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3 3. 3.. H H = H + V (t), V (t) = gµ B α B e e iωt i t Ψ(t) = [H + V (t)]ψ(t) Φ(t) Ψ(t) = e iht Φ(t) H e iht Φ(t) + ie iht t Φ(t) = [H + V (t)]e iht Φ(t) Φ(t) i t Φ(t) = V H(t)Φ(t), V H (t) = e iht V (t)e

* n x 11,, x 1n N(µ 1, σ 2 ) x 21,, x 2n N(µ 2, σ 2 ) H 0 µ 1 = µ 2 (= µ ) H 1 µ 1 µ 2 H 0, H 1 *2 σ 2 σ 2 0, σ 2 1 *1 *2 H 0 H

1 1 1.1 *1 1. 1.3.1 n x 11,, x 1n Nµ 1, σ x 1,, x n Nµ, σ H 0 µ 1 = µ = µ H 1 µ 1 µ H 0, H 1 * σ σ 0, σ 1 *1 * H 0 H 0, H 1 H 1 1 H 0 µ, σ 0 H 1 µ 1, µ, σ 1 L 0 µ, σ x L 1 µ 1, µ, σ x x H 0 L 0 µ, σ 0

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NHK 204 2 0 203 2 24 ( ) 7 00 7 50 203 2 25 ( ) 7 00 7 50 203 2 26 ( ) 7 00 7 50 203 2 27 ( ) 7 00 7 50 I. ( ν R n 2 ) m 2 n m, R = e 2 8πε 0 hca B =.09737 0 7 m ( ν = ) λ a B = 4πε 0ħ 2 m e e 2 = 5.2977

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Microsoft Word - 11問題表紙（選択）.docx

A B A.70g/cm 3 B.74g/cm 3 B C 70at% %A C B at% 80at% %B 350 C γ δ y=00 x-y ρ l S ρ C p k C p ρ C p T ρ l t l S S ξ S t = ( k T ) ξ ( ) S = ( k T) ( ) t y ξ S ξ / t S v T T / t = v T / y 00 x v S dy dx

平成１９年度

1 2 3 4 H 3 H CC N + 3 O H 3 C O CO CH 3 CH O CO O CH2 CH 3 P O O 5 H H H CHOH H H H N + CHOH CHOH N + CH CH COO- CHOH CH CHOH 6 1) 7 2 ) 8 3 ) 4 ) 9 10 11 12 13 14 15 16 17 18 19 20 A A 0 21 ) exp( )

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橡災害.PDF

1 2 3 4 5 6 7 8 9 10 11 12 2.1 2.2 2.2.1 13 2.2.2 2.2.3 14 2.3 2.3.1 2.3.2 all or nothing 2.4. 2.4.1 15 i) ii) iii) iv) 2.5 2.4.2 2.2 2.5 2.5.1 16 2.5.2 2.6 2.6.1 2.4 2.6.2 2.6.3 2.6.4 17 18 3.2.1 Hazard

廃棄物処理施設生活環境影響調査指針

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「産業上利用することができる発明」の審査の運用指針（案）

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ml DNA DNA

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Gmech08.dvi

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1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2

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