Trv1_.xtv

Trv1_.xtv

第 回 PBF 選手権日本代表選抜試合 ( ウィメンズ ) Round 00 年 月 0 日 ( 土 ) 0 0 0 0 Board () v:=+0 - -W Contract - -W IMP C - 0 - T 0 C 0 W 0-0 0 0 0 Board () v:=-0 - -W Contract - -W IMP 0 0 0 0 0 0 0 0 0 0 0 0 Board () v:=+0

IMP 第 1 金曜朝シニア Round 1 ection 01 年 月 日 ( 金 ) v:=+0 W Contract W IMP 1 H H 0 1 H 0 0 H 0 1 H 0 1 H 0 0 H 0 0 H 0 0 v:=+0 W Contract W IMP 1 T 00

IMP 第 1 金曜朝シニア Round 1 ection 01 年 月 日 ( 金 ) v:=+0 W Contract W IMP 1 T 0 1 T 1 0 T 10 T T 0 T 0 T 1 0 T 1 0 v:=0 W Contract W IMP 1 H 0 0 1 H W 0 1 H W 0 1 H 0 0 H 0 0 H 0 0 H W 0 1 H 0 0 v:=+0 W Contract

[] x < T f(x), x < T f(x), < x < f(x) f(x) f(x) f(x + nt ) = f(x) x < T, n =, 1,, 1, (1.3) f(x) T x 2 f(x) T 2T x 3 f(x), f() = f(t ), f(x), f() f(t )

1 1.1 [] f(x) f(x + T ) = f(x) (1.1), f(x), T f(x) x T 1 ) f(x) = sin x, T = 2 sin (x + 2) = sin x, sin x 2 [] n f(x + nt ) = f(x) (1.2) T [] 2 f(x) g(x) T, h 1 (x) = af(x)+ bg(x) 2 h 2 (x) = f(x)g(x)

No ( FAX ) (

13-1 03-3862-9111 ( FAX03-3862- ) 9140 13-2 03-3219-8080 13-3 03-3293-1711 250 13-4 03-3292-2051 1-8 8111 13-5 8 11 28 ( 8 111 03-3261-5511 2 18 41 9 91 15 41 15 41 47 13-6 47 9 4 4 03-5343-5611 F 47 47

BHP1610_20.indd

IMP 第 1 金曜朝シニア Round 3 ection 01 年 月 日 ( 金 ) 3 KJ KJ J KJ 3 3 v:= T T T T T T 10 0 K K K 3 J3 K

IMP 第 1 金曜朝シニア Round 3 ection 01 年 月 日 ( 金 ) K 3 J3 KJ J3 KJ 3 K v:=+10 1 3T 30 1 D -1 0-3 D -1 0-3 3T 0 3T -1 0-3T 0 3T -1 0-3T -1 0 - J KJ 3 J KJ 3 K 3 v:=+0 1 D W-1 0 0 1 3 3 3 3 D W-1 0 0 3 D W- 0-1

取扱説明書 [N-03A]

235 1 d dt 2 1 i 236 1 p 2 1 ty 237 o p 238 1 i 2 1 i 2 1 u 239 1 p o p b d 1 2 3 0 w 240 241 242 o d p f g p b t w 0 q f g h j d 1 2 d b 5 4 6 o p f g p 1 2 3 4 5 6 7 243 244 1 2 1 q p 245 p 246 p p 1

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取扱説明書[N906i]

237 1 dt 2 238 1 i 1 p 2 1 ty 239 240 o p 1 i 2 1 u 1 i 2 241 1 p v 1 d d o p 242 1 o o 1 o 2 p 243 1 o 2 p 1 o 2 3 4 244 q p 245 p p 246 p 1 i 1 u c 2 o c o 3 o 247 1 i 1 u 2 co 1 1 248 1 o o 1 t 1 t

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6,,3,4,, 3 4 8 6 6................................. 6.................................. , 3, 6 = 3, 3,,,, 3,, 9, 3, 9, 3, 3, 4, 43, 4, 3, 9, 6, 6,, 0 p, p, p 3,..., p n N = p p p 3 p n + N p n N p p p,

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error_g1.eps

Runge-Kutta Method Runge-Kutta Method x n+ = x n +hf(t n x n ) dx dt dx x(t+h) x(t) (t) = lim dt h h t = t n h > dx dt (t x(t n +h) x(t n ) n) = lim x(t n+) x(t n ) h h h x = f(tx) x(t n+ ) x(t n ) f(t

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曲面のパラメタ表示と接線ベクトル

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1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0

1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0 0 < t < τ I II 0 No.2 2 C x y x y > 0 x 0 x > b a dx

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20103n=3,280 7 3 40 30.2 3.4 16.9 43.1 n=3,280 2.2 8.1 n=3,280 69.8 9.6 6.9 4.7 3.3 30 19 0.3 60 28.0 0.7 20-24 19 0.3 1.4 25-29 60 28.0 3.9 30-34 1.7 20-24 5.7 35-39 2.7 25-29 8.2 40-44 4.5 30-34 n=2,288

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名古屋工業大の数学 2000 年 ~2015 年 大学入試数学動画解説サイト

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8 300 mm 2.50 m/s L/s ( ) 1.13 kg/m MPa 240 C 5.00mm 120 kpa ( ) kg/s c p = 1.02kJ/kgK, R = 287J/kgK kPa, 17.0 C 118 C 870m 3 R = 287J

26 1 22 10 1 2 3 4 5 6 30.0 cm 1.59 kg 110kPa, 42.1 C, 18.0m/s 107kPa c p =1.02kJ/kgK 278J/kgK 30.0 C, 250kPa (c p = 1.02kJ/kgK, R = 287J/kgK) 18.0 C m/s 16.9 C 320kPa 270 m/s C c p = 1.02kJ/kgK, R = 292J/kgK

F S S S S S S S 32 S S S 32: S S rot F ds = F d l (63) S S S 0 F rot F ds = 0 S (63) S rot F S S S S S rot F F (63)

211 12 1 19 2.9 F 32 32: rot F d = F d l (63) F rot F d = 2.9.1 (63) rot F rot F F (63) 12 2 F F F (63) 33 33: (63) rot 2.9.2 (63) I = [, 1] [, 1] 12 3 34: = 1 2 1 2 1 1 = C 1 + C C 2 2 2 = C 2 + ( C )

t = h x z z = h z = t (x, z) (v x (x, z, t), v z (x, z, t)) ρ v x x + v z z = 0 (1) 2-2. (v x, v z ) φ(x, z, t) v x = φ x, v z

I 1 m 2 l k 2 x = 0 x 1 x 1 2 x 2 g x x 2 x 1 m k m 1-1. L x 1, x 2, ẋ 1, ẋ 2 ẋ 1 x = 0 1-2. 2 Q = x 1 + x 2 2 q = x 2 x 1 l L Q, q, Q, q M = 2m µ = m 2 1-3. Q q 1-4. 2 x 2 = h 1 x 1 t = 0 2 1 t x 1 (t)

1 1 u m (t) u m () exp [ (cπm + (πm κ)t (5). u m (), U(x, ) f(x) m,, (4) U(x, t) Re u k () u m () [ u k () exp(πkx), u k () exp(πkx). f(x) exp[ πmxdx

1 1 1 1 1. U(x, t) U(x, t) + c t x c, κ. (1). κ U(x, t) x. (1) 1, f(x).. U(x, t) U(x, t) + c κ U(x, t), t x x : U(, t) U(1, t) ( x 1), () : U(x, ) f(x). (3) U(x, t). [ U(x, t) Re u k (t) exp(πkx). (4)

fem.dvi

2.3 FreeFEM++ 2.3.1 FreeFEM++ 4] FreeFEM 6 O. (Pironneau) F. (Hecht, 6 2.3.2 FreeFEM++ http://www.freefem.org/ FreeFEM++ FreeFEM++-cs http://www.ann.jussieu.fr/ lehyaric/ffcs/index.htm FreeFEM++-cs 2.3.3

1 1 sin cos P (primary) S (secondly) 2 P S A sin(ω2πt + α) A ω 1 ω α V T m T m 1 100Hz m 2 36km 500Hz. 36km 1

sin cos P (primary) S (secondly) 2 P S A sin(ω2πt + α) A ω ω α 3 3 2 2V 3 33+.6T m T 5 34m Hz. 34 3.4m 2 36km 5Hz. 36km m 34 m 5 34 + m 5 33 5 =.66m 34m 34 x =.66 55Hz, 35 5 =.7 485.7Hz 2 V 5Hz.5V.5V V

IMP 第 1 金曜朝シニア Round ection A 201 年 月 日 ( 金 ) A Q2 6 A AQ 6 QJ J AJ Q J2 Av:= QJ6 J2 6 2 A J2 Q2

IMP 第 1 金曜朝シニア Round ection A 201 年 月 日 ( 金 ) A62 2 Q Q6 AQ6 J 2 J6 J 2 J Q Av:= 1 W 200 1 1 W 200 1 2 W 20 6 2 W 200 1 1T 1 0 6 1T 1 0 6 6 D 2 0 2 6 Dx 00 2 Q Q A6 AJ2 J6 J J2 A 62 Q Q6 Av:=+0 1 T 1 0

f(x) = x (1) f (1) (2) f (2) f(x) x = a y y = f(x) f (a) y = f(x) A(a, f(a)) f(a + h) f(x) = A f(a) A x (3, 3) O a a + h x 1 f(x) x = a

3 3.1 3.1.1 A f(a + h) f(a) f(x) lim f(x) x = a h 0 h f(x) x = a f 0 (a) f 0 (a) = lim h!0 f(a + h) f(a) h = lim x!a f(x) f(a) x a a + h = x h = x a h 0 x a 3.1 f(x) = x x = 3 f 0 (3) f (3) = lim h 0 (

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Radiation from moving charges#1 Liénard-Wiechert potential Yuji Chinone 1 Maxwell Maxwell MKS E (x, t) + B (x, t) t = 0 (1) B (x, t) = 0 (2) B (x, t)

Radiation from moving harges# Liénard-Wiehert potential Yuji Chinone Maxwell Maxwell MKS E x, t + B x, t = B x, t = B x, t E x, t = µ j x, t 3 E x, t = ε ρ x, t 4 ε µ ε µ = E B ρ j A x, t φ x, t A x, t

講座の記録

201711grade1ouyou.pdf

2017 11 26 1 2 52 3 12 13 22 23 32 33 42 3 5 3 4 90 5 6 A 1 2 Web Web 3 4 1 2... 5 6 7 7 44 8 9 1 2 3 1 p p >2 2 A 1 2 0.6 0.4 0.52... (a) 0.6 0.4...... B 1 2 0.8-0.2 0.52..... (b) 0.6 0.52.... 1 A B 2

取扱説明書[N-02B]

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lecture

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1-1. 1, 2, 3, 4, 5, 6, 7,, 100,, 1000, n, m m m n n 0 n, m m n 1-2. 0 m n m n 0 2 = 1.41421356 π = 3.141516 1-3. 1 0 1-4. 1-5. (1) + b = b +, (2) b = b, (3) + 0 =, (4) 1 =, (5) ( + b) + c = + (b + c),

x A Aω ẋ ẋ 2 + ω 2 x 2 = ω 2 A 2. (ẋ, ωx) ζ ẋ + iωx ζ ζ dζ = ẍ + iωẋ = ẍ + iω(ζ iωx) dt dζ dt iωζ = ẍ + ω2 x (2.1) ζ ζ = Aωe iωt = Aω cos ωt + iaω sin

2 2.1 F (t) 2.1.1 mẍ + kx = F (t). m ẍ + ω 2 x = F (t)/m ω = k/m. 1 : (ẋ, x) x = A sin ωt, ẋ = Aω cos ωt 1 2-1 x A Aω ẋ ẋ 2 + ω 2 x 2 = ω 2 A 2. (ẋ, ωx) ζ ẋ + iωx ζ ζ dζ = ẍ + iωẋ = ẍ + iω(ζ iωx) dt dζ

p-sylow :

p-sylow :15114075 30 2 20 1 2 1.1................................... 2 1.2.................................. 2 1.3.................................. 3 2 3 2.1................................... 3 2.2................................

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発達障害_表01

H 0 H = H 0 + V (t), V (t) = gµ B S α qb e e iωt i t Ψ(t) = [H 0 + V (t)]ψ(t) Φ(t) Ψ(t) = e ih0t Φ(t) H 0 e ih0t Φ(t) + ie ih0t t Φ(t) = [

3 3. 3.. H H = H + V (t), V (t) = gµ B α B e e iωt i t Ψ(t) = [H + V (t)]ψ(t) Φ(t) Ψ(t) = e iht Φ(t) H e iht Φ(t) + ie iht t Φ(t) = [H + V (t)]e iht Φ(t) Φ(t) i t Φ(t) = V H(t)Φ(t), V H (t) = e iht V (t)e

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14 in ヨーロッパ遠征チーム応援ツアー 選抜チームのオランダ遠征に帯同し 応援してあげてください ヨーロッパのトップレベルのチームを相手に戦う子ども達を間近で応援してあげてください 遠征チームは 元日本サッカー協会ジュニアナショナルコーチで U-12日本選抜監督も務めた 品村敏明氏が総監督として率います ヨーロッパ選手権予選 ドイツ対ベルギー も観戦予定 美味しいお食事も付いています

Maxwell

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No.004 [1] J. ( ) ( ) (1968) [2] Morse (1997) [3] (1988) 1

No.004 [1] J. ( ) ( ) (1968) [2] Morse (1997) [3] (1988) 1 1 (1) 1.1 X Y f, g : X Y { F (x, 0) = f(x) F (x, 1) = g(x) F : X I Y f g f g F f g 1.2 X Y X Y gf id X, fg id Y f : X Y, g : Y X X Y X Y (2) 1.3

x () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x

[ ] IC. f(x) = e x () f(x) f (x) () lim f(x) lim f(x) x + x (3) lim f(x) lim f(x) x + x (4) y = f(x) ( ) ( s46). < a < () a () lim a log xdx a log xdx ( ) n (3) lim log k log n n n k=.3 z = log(x + y ),

(1) 1 y = 2 = = b (2) 2 y = 2 = 2 = 2 + h B h h h< h 2 h

6 6.1 6.1.1 O y A y y = f() y = f() b f(b) B y f(b) f() = b f(b) f() f() = = b A f() b AB O b 6.1 2 y = 2 = 1 = 1 + h (1 + h) 2 1 2 (1 + h) 1 2h + h2 = h h(2 + h) = h = 2 + h y (1 + h) 2 1 2 O y = 2 1

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NewBead_no27_0623.indd

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DVIOUT

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橡アロマセラピー症状別処方例.PDF

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DII_カタログ.pdf

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