:30 12:00 I. I VI II. III. IV. a d V. VI
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1 :30 12:00 I. I VI II. III. IV. a d V. VI
2 I. Backus-Naur BNF X [ S ] a S S ; X X X, S [, a, ], ; BNF X (parse tree) (1) [a;a] (2) [[a]] (3) [a;[a]] (4) [[a];a] : [a] X [ S ] X a II. x(z yz yy yx)*x (L) xy(x (y*z) z)*y*yx (R) (B) (N) (1) xyyzzyyx (2) xyzzxyyx (3) xyxyxyyx (4) xyxyxxyx III. (1) (4) C (A) (E) (1) (4) 2
3 (1) #include <stdio.h> int main{void ( printf{"hello World!\n"; return 0; ) (2) printf #include <stdio.h> int main(void) { printf("hello, World!"); printf(); return 0; (3) #include <stdio.h> int main(void) { printf("hello! World\n"); return 0; (4) for ; #include <stdio.h> int main(void) { int i = 0; for (i < 5; i++) { printf("hello World!\n"); return 0; (1) (4) (A) (B) (C) (D) (E) 3
4 IV. BNF E id E ** E E & E E $$ E E < E ( E ) id 1 ** & $$ < ** & & $$ $$ < a ** b ** c a ** (b ** c) a & b & c (a & b) & c a $$ b $$ c a $$ (b $$ c) a < b < c a ** b & c (a ** b) & c a & b ** c a & (b ** c) a ** b $$ c (a ** b) $$ c a $$ b ** c a $$ (b ** c) a ** b < c (a ** b) < c a < b ** c a < (b ** c) a & b $$ c (a & b) $$ c a $$ b & c a $$ (b & c) a & b < c (a & b) < c a < b & c a < (b & c) a $$ b < c (a $$ b) < c a < b $$ c a < (b $$ c) (1) (5) < > \ ** & $$ < ( ) id < < < < < < ** (1) > > > < > < > & < (2) > (3) < > < > $$ < < (4) > < > < > < < < < (5) < > < > ( < < < < < < ) > > > > > > id > > > > > > 4
5 V. BNF S if E then S else S I begin L end II write E III F id IV ( E ) V L S L ; S E F E + F E - F S, F, L, E if, then, else, begin, end, write, id, (, ), ;, +, - start symbol S I, II (1) L BNF L S L VI L ε VII ; S L VIII E E (IX, X, XI, XII,...) (2) (4) (1) E L BNF $ (2) Follow(L ) (3) Follow(E ) (4) L, L, VI, VII, VIII (5) S, F, E, E BNF I V (1) BNF (IX, X, XI, XII,...) 5
6 S F L L E E if then else begin end write id ( ) ; + - $ (6) S, F, E, E1, L, L1 F, L, L1 S, F, E, E1, L, L1 S, F, E, E, L, L :, 1 ASCII id C id ID $ EOF yylex token eat token reporterror #include <stdio.h> /* printf(), EOF */ #include <stdlib.h> /* exit() */ #include <string.h> /* strcmp() */ #include <ctype.h> /* isalpha() */ /* */ #define IF 257 /* if */ #define THEN 258 /* then */ #define ELSE 259 /* else */ #define BEGIN 260 /* begin */ #define END 261 /* end */ #define WRITE 262 /* write */ #define ID 263 /* id */ int token; /* */ /* */ void reporterror(void); int yylex(void); void eat(int t); void S(void); void F(void); void E(void); void E1(void); 6
7 void L(void); void L1(void); /* **************************************************************** */ /* S, F, E, E1, L, L1 */ /* **************************************************************** */ /* */ void reporterror(void) { printf(" \n"); exit(0); /* */ int main() { /* main */ token = yylex(); /* */ S(); if (token == EOF) { printf("!\n"); else { reporterror(); int yylex(void) { /* */ int c; char buf[256]; do { /* */ c = getchar(); while (c == c == \t c == \n ); if (isalpha(c)) { /* */ char* ptr = buf; ungetc(c, stdin); while (1) { c = getchar(); if (!isalpha(c) &&!isdigit(c)) break; *ptr++ = c; *ptr = \0 ; ungetc(c, stdin); if (strcmp(buf, "if") == 0) return IF; if (strcmp(buf, "then") == 0) return THEN; if (strcmp(buf, "else") == 0) return ELSE; if (strcmp(buf, "begin") == 0) return BEGIN; if (strcmp(buf, "end") == 0) return END; if (strcmp(buf, "write") == 0) return WRITE; return ID; else { /* */ return c; /* ; */ 7
8 void eat(int t) { /* token token */ if (token == t) { /* */ token = yylex(); return; else { reporterror(); 8
9 VI. LR BNF LR E a I E E II E E III E * IV ( E ) V I, II E (, ), *,, a a 1 start symbol E bison LR : bison -v LR $ ( ) * a E 0 shift 2 shift 1 goto 3 1 reduce I 2 shift 2 shift 1 goto 4 3 shift 5 shift 2 shift 7 shift 6 shift 1 goto 8 4 shift 2 shift 9 shift 7 shift 6 shift 1 goto 8 5 accept 6 shift 2 shift 1 goto 10 7 reduce IV 8 reduce III shift 7 reduce III goto 8 9 reduce V 10 reduce II shift 2 reduce II shift 7 reduce II shift 1 goto 8 : shift s s goto s s reduce X X 9
10 ? (1) a a * a * (2) a a a a * a (3) a a a a * (1) (A). 0 E 3 6 (B). 0 E 3 E 8 6 (C). 0 E 3 a 1 * 7 6 (D). 0 E 3 E 8 * 7 6 (2) (A). 0 E 3 * 7 (B). 0 E 3 E 8 * 7 (C). 0 E 3 E 8 E 8 * 7 (D). 0 E 3 E 8 E 8 E 8 * 7 (3) (A). 0 E 3 * 7 (B). 0 E 3 6 E 10 * 7 (C). 0 E 3 6 E 10 6 E 10 * 7 (D). 0 E 3 6 E 10 E 8 6 E 10 * 7 10
11
12
13 I. Backus-Naur (1) (2) (3) (4) (3 4) II. (3 4) (1) (2) (3) (4) III. (2 4) (1) (2) (3) (4) IV. (1) (2) (3) (4) (5) (2 5) V. (3, 3, 5, 4, 6, 5) E (1) E (2) { (3) {
14 (4) L L (5) S F E E if then else begin end write id ( ) ; + - $ void F(void) { if (token == ID) { else if (token == ( ) { else reporterror(); /* */ /* */ void L(void) { /* */ void L1(void) { /* */ (6) VI. LR (4 3) (1) (2) (3)
15
I. Backus-Naur BNF : N N 0 N N N N N N 0, 1 BNF N N 0 11 (parse tree) 11 (1) (2) (3) (4) II. 0(0 101)* (
2016 2016 07 28 10:30 12:00 I. I VI II. III. IV. a d V. VI. 80 100 60 1 I. Backus-Naur BNF : 11011 N N 0 N N 11 1001 N N N N 0, 1 BNF N N 0 11 (parse tree) 11 (1) 1100100 (2) 1111011 (3) 1110010 (4) 1001011
:30 12:00 I. I VI II. III. IV. a d V. VI
2018 2018 08 02 10:30 12:00 I. I VI II. III. IV. a d V. VI. 80 100 60 1 I. Backus-Naur BNF N N y N x N xy yx : yxxyxy N N x, y N (parse tree) (1) yxyyx (2) xyxyxy (3) yxxyxyy (4) yxxxyxxy N y N x N yx
I. Backus-Naur BNF S + S S * S S x S +, *, x BNF S (parse tree) : * x + x x S * S x + S S S x x (1) * x x * x (2) * + x x x (3) + x * x + x x (4) * *
2015 2015 07 30 10:30 12:00 I. I VI II. III. IV. a d V. VI. 80 100 60 1 I. Backus-Naur BNF S + S S * S S x S +, *, x BNF S (parse tree) : * x + x x S * S x + S S S x x (1) * x x * x (2) * + x x x (3) +
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パソコン機能ガイド
PART12 ii iii iv v 1 2 3 4 5 vi vii viii ix P A R T 1 x P A R T 2 xi P A R T 3 xii xiii P A R T 1 2 3 1 4 5 1 6 1 1 2 7 1 2 8 1 9 10 1 11 12 1 13 1 2 3 4 14 1 15 1 2 3 16 4 1 1 2 3 17 18 1 19 20 1 1
パソコン機能ガイド
PART2 iii ii iv v 1 2 3 4 5 vi vii viii ix P A R T 1 x P A R T 2 xi P A R T 3 xii xiii P A R T 1 2 1 3 4 1 5 6 1 2 1 1 2 7 8 9 1 10 1 11 12 1 13 1 2 3 14 4 1 1 2 3 15 16 1 17 1 18 1 1 2 19 20 1 21 1 22
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困ったときのQ&A
ii iii iv NEC Corporation 1997 v P A R T 1 vi vii P A R T 2 viii P A R T 3 ix x xi 1P A R T 2 1 3 4 1 5 6 1 7 8 1 9 1 2 3 4 10 1 11 12 1 13 14 1 1 2 15 16 1 2 1 1 2 3 4 5 17 18 1 2 3 1 19 20 1 21 22 1
活用ガイド （ハードウェア編）
(Windows 98) 808-877675-122-A ii iii iv NEC Corporation 1999 v vi PART 1 vii viii PART 2 PART 3 ix x xi xii P A R T 1 2 1 3 4 1 5 6 1 7 8 1 9 10 11 1 12 1 1 2 3 13 1 2 3 14 4 5 1 15 1 1 16 1 17 18 1 19
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i 1 1 2 3 6 6 7 8 10 10 11 12 12 12 13 2 15 15 16 17 17 18 19 20 20 21 ii CONTENTS 25 26 26 28 28 29 30 30 31 32 35 35 35 36 37 40 42 44 44 45 46 49 50 50 51 iii 52 52 52 53 55 56 56 57 58 58 60 60 iv
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i 1 1 2 2 3 3 4 4 4 5 7 8 8 9 9 10 11 13 14 15 16 17 19 ii CONTENTS 2 21 21 22 25 26 32 37 38 39 39 41 41 43 43 43 44 45 46 47 47 49 52 54 56 56 iii 57 59 62 64 64 66 67 68 71 72 72 73 74 74 77 79 81 84
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7 i 7 1 2 3 4 5 6 ii 7 8 9 10 11 1 12 13 14 iii.......................................... iv................................................ 21... 1 v 3 6 7 3 vi vii viii ix x xi xii xiii xiv xv 26 27
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1 2 3 4 5 6 7 8 9 10 I II III 11 IV 12 V 13 VI VII 14 VIII. 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 _ 33 _ 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 VII 51 52 53 54 55 56 57 58 59
平成18年版 男女共同参画白書
i ii iii iv v vi vii viii ix 3 4 5 6 7 8 9 Column 10 11 12 13 14 15 Column 16 17 18 19 20 21 22 23 24 25 26 Column 27 28 29 30 Column 31 32 33 34 35 36 Column 37 Column 38 39 40 Column 41 42 43 44 45
困ったときのQ&A
ii iii iv NEC Corporation 1998 v C O N T E N T S PART 1 vi vii viii ix x xi xii PART 2 xiii PART 3 xiv P A R T 1 3 1 2 PART 3 4 2 1 1 2 4 3 PART 1 4 5 5 6 PART 1 7 8 PART 1 9 1 2 3 1 2 3 10 PART 1 1 2
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ii iii iv CON T E N T S iii iv v Chapter1 Chapter2 Chapter 1 002 1.1 004 1.2 004 1.2.1 007 1.2.2 009 1.3 009 1.3.1 010 1.3.2 012 1.4 012 1.4.1 014 1.4.2 015 1.5 Chapter3 Chapter4 Chapter5 Chapter6 Chapter7
活用ガイド （ソフトウェア編）
(Windows 95 ) ii iii iv NEC Corporation 1999 v P A R T 1 vi P A R T 2 vii P A R T 3 P A R T 4 viii P A R T 5 ix x P A R T 1 2 3 1 1 2 4 1 2 3 4 5 1 1 2 3 4 6 5 6 7 7 1 1 2 8 1 9 1 1 2 3 4 5 6 1 2 3 4
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Step2 入門
ii iii iv v vi NEC Corporation 1999 vii C O N T E N T S PART 1 PART 2 PART 3 viii PART 4 ix C O N T E N T S PART 5 x PART 6 xi C O N T E N T S PART 7 xii PART 8 PART 9 xiii C O N T E N T S xiv xv PART
橡Pro PDF
1 void main( ) char c; /* int c; */ int sum=0; while ((c = getchar())!= EOF) if(isdigit(c) ) sum += (c-'0'); printf("%d\n", sum); main()int i,sum=0; for(i=0;i
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