D:/BOOK/MAIN/MAIN.DVI
|
|
- きのこ こいたばし
- 7 years ago
- Views:
Transcription
1 8 2 F (s) =L f(t) F (s) =L f(t) := Z 0 f()e ;s d (2.2) s s = + j! f(t) (f(0)=0 f(0) _ = 0 d n; f(0)=dt n; =0) L dn f(t) = s n F (s) (2.3) dt n Z t L 0 f()d = F (s) (2.4) s s =s f(t) L _ f(t) Z Z ;s L f(t) _ df() = 0 d ;s 0 e;s d = f()e ; f() de;s d 0 d 0 Z = f()e + s f()e ;s d = ;f(0) + sf (s) (2.5) 0 f(t) n L d n f(t) = ;s n; f(0) ; s n;2 f(0) _ dn; f(0) ;; dt n dt n; + s n F (s) (2.6) (f(0) = 0 0) (2.6) (2.3) f(t) g(t) = _g(t) Z t 0 _ f(0) = 0 d n; f(0)=dt n; = f()d G(s)
2 2.3 v R (t) =Ri R (t) (2.5) Z v C (t) = t i C ( )d (2.6) C 0 v L (t) =L d dt i L(t) (2.7) (a) (b) (c) 2.7 R []C [F]L [H]v R (t)v C (t) v L (t) [V]i R (t)i C (t)i L (t) [A] 2. RL 2.8 RL u(t) vin(t) y(t) i(t) (a) 2.8 u(t) = vin(t)y(t) = i(t) ( ) 2.8 RL L _y(t) +Ry(t) =u(t) (2.8) (b) (2.8) u(s) y(s) P (s)
3 2.4 () 5 () 2.3 f r (t) ( r (t)) () c f r (t) =;c _z(t) (2.34) r (t) =;c (t) _ (2.35) (a) (b) 2.3 () 2.3 (a) 2.3 (a) M z(t) =f (t) ; c _z(t) (2.36) u(t) =f (t) y(t) =z(t) M y(t) +c _y(t) =u(t) (2.37) (b) (2.37) P (s) P (s) = Ms 2 (2.38) + cs (b) u(t) = (t)y(t) =
4 3. 37 (p i ) k i =(s ; p i )y(s) (3.30) s=p i bs + b0 y(s) = (s ; p)(s ; k p2) = s ; k2 p + s ; p2 (3.3) s ; p (s ; p)y(s) =k + k2(s ; p) s ; p2 (3.32) s = p k =(s ; p)y(s) s=p i k k2 (3.3) (3.32) (3.33) (3.30) k = sy(s) s=0 = s + s=0 = k2 =(s +)y(s) s=; = s s=; = ; (b) p i (i = 2 n) p = p 2 = = p` (3.27) y(s) = k ` (s ; p )` + + k 2 (s ; p ) 2 + k s ; p + k`+ s ; p`+ + k`+2 s ; p` k n s ; p n (3.34) y(s) y(t) =L ; y(s) = k `t` + + k 2 t + k e pt `! +k`+ e p`+t + k`+2 e p`+2t + + k n e pnt (3.35)
5 38 3 k i 8 >< >: (p i ) d`;i f(s ; p )`y(s)g k i = (` ; i)! ds`;i k j =(s ; p j )y(s) s=pj s=pi (i = 2 `) (j = ` + `+2 n) b2s2 + bs + b0 y(s) = (s ; p) 2 k2 (s ; p3) = (s ; p) 2 k k3 + s ; p + s ; p3 (3.37) (s ; p) 2 (s ; p) 2 k3(s ; p)2 y(s) =k2 + k(s ; p) + s ; p3 (3.38) s = p k2 =(s ; p) 2 y(s) s=p k2 (3.38) s df(s ; p) 2 y(s)g ds (3.36) (3.37) (3.38) (3.39) = k + k3f2(s ; p)(s ; p3) ; (s ; p)2 g (s ; p3) 2 (3.40) (3.40) s = p k = df(s ; p)2 y(s)g ds s=p (3.4) k k3 pi (3.36)
6 44 3 (a) T> 0 (b) T< T T > 0 T < 0 T > 0 T T > 0 t = T y(t) y = K 63.2 % 3.6 y(t) = K T e;t=t (t 0) (3.52) RL S ON () (2) (3) u(t) e(t) y(t) i(t) RL T S ON i(t) i R
7 (a) 0 < (b) ; <<0 (c) 3.4 y(t) =KL ; s ; 2 (d) ;! n (s +! n ) 2 ; s +! n = K ; e ;!nt (! n t +) (3.57) (3.57) = y = K ( 3.4 (c)) = ; ( 3.4 (d)) (iii) jj > P (s) (2 ) p = ;( + p 2 ; )! n p 2 = ;( ;p 2 ; )! n t 0
8 48 3 ; y(t) =KL s + p2 p ; p ; p 2 s ; p s ; p 2 ; + e! nt ; ; ; e ;! nt # = K " ; e;!nt 2 (3.58) =p 2 ; jj >>0 (3.58) > y = K ( 3.4 (c)) <; ( 3.4 (d)) 2 (a) Tp (3.54)(3.57)(3.58) 0 << 0 << (3.54) y(t) =K ( ; e ;!nt p ; 2 sin! dt + cos! d t!) y(t) _y(t) = K! n p ; 2 e;!nt sin! d t (3.59) T p! d t = (sin! d t =0 t>0) T p T p = = (3.60)! d! np ; 2 (b) Amax y max y max = y(t p )=K ; +e ;!ntp (3.6) y = K A max
9 A max = y max ; y = Ke ;!ntp = Kexp ; p ; 2! (3.62) (c) (3.59) i y i! d t i =(2i ; ) (i = 2 ) t i y(t) i A i = A i+ =A i = A i+ A i y i = y(t i )=K ; +e ;!nti (3.63) A i = y i ; y = Ke ;!nti (3.64) = e;!nti+ e ;!nti = exp ; 2 p ; 2 0 =log e 2! (3.65) 0 = ; (3.66) p ; () () <0 () =0 () 0 << A max 0 <<!! A max = Kexp ; 2 = exp ; p ; p 2 ; 2 y = K
10 6. 09 u(t) =Asin!t (A >0!>0) y(t) u(t) =Asin!t u(s) =A!=(s 2 +! 2 ) y(t) y(s) =P (s)u(s) = k = A! +! s + A! s 2 +! 2 = A(j ;!) k2 = 2 2( +! 2 ) k s + + k2 s + j! + k3 = ; A(j +!) 2( +! 2 ) k3 s ; j! y(t) y(t) =L ; [y(s)] = k e ;t + k 2e ;j!t + k 3e j!t (6.2) = A! +! 2 e;t + A (sin!t ;! cos!t) (t 0) (6.3) +! 2 (6.3) e ;t = 0 y(t) u(t) = A sin!t y(t) = A (sin!t ;! cos!t) +! 2 = B(!) sin(!t + G p(!)) (= y app(t)) (6.4) A B(!) = p +! 2 Gp(!) =tan; (;!) =;tan ;! (a) u(t) = sin0:t 6.2 (b) P (s) ==(s +) u(t) = sin0t 6.2 A =! =0: 0 u(t)y(t) y(t) y app(t) 6.2 u(t) y(t)
11 6. 3 P (j!)= N (j!)n2(j!) N m (j!) D(j!)D2(j!) D n (j!) = jn (j!)je j\n(j!) jn2(j!)je j\n2(j!) jn m (j!)je j\nm(j!) jd(j!)je j\d(j!) jd2(j!)je j\d2(j!) jd n (j!)je j\dn(j!) jn (j!)jjn2(j!)jjn m (j!)j = jd(j!)jjd2(j!)jjd n (j!)j exp ( j mx nx \N i (j!) ; \D i (j!) i= i=!) (6.20) (6.9) jp (j!)j \P (j!) jp jn (j!)jjn2(j!)jjn m (j!)j (j!)j = jd(j!)jjd2(j!)jjd n (j!)j mx (6.2) \P (j!)= \N i (j!) ; \D i (j!) (6.22) i= i= P (s) ==(s +)(s +2) P (s) = D(s) =s + D2(s) =s +2 D (s)d 2(s) p jd (j!)j = +! 2 \D (j!) = tan ;! jd 2(j!)j = p +4! 2 \D 2(j!) = tan ; 2! P (s) jp (j!)j = jd = ; (j!)jjd 2(j!)j p( (6.23) +! 2 )( + 4! 2 ) \P (j!) =; \D (j!)+\d 2(j!) = ; tan ;! + tan ; 2! (6.24) (6.23) (6.5) = tan ;! 2 = tan ; 2! nx
12 8 6 M p jp (0)j =! p u(t) y(t) u(t) () P (s) = +Ts jp (j!)j \P (j!) (6.27) jp (j!)j = p +(!T ) 2 \P (j!)=;tan;!t (6.28) (6.28) ( 20log!T << 0 jp (j!)j = 20log 0 = 0 [db] \P (j!) = ;tan ; 0=0[deg] 8 <!T = : 20log 0jP (j!)j =20log 0 p = ;3:0 [db] 2 \P (j!)=;tan ; =;45 [deg] 8 <!T >> : 20log 0jP (j!)j = 20log 0!T = ;20log 0!T [db] \P (j!) = ;tan ; = ;90 [deg] ! ==T 0[dB] ;20 [db/dec] 0 <! =5T 0 [deg]! 5=T ;90 [deg] (20 )
13 20 6! b jp (j!)j () T (!<< =T 0 [db] 0 [rad]!>> =T ) () ()! c ==T () (6.27) (=2 0) =2 6.6 P (s) ==( + 0s) (2 )
14 7. 37 (P (s)c(s) ) P (s)c(s) P (s)c(s) (; 0) (a) (b) 7.5 P (s)c(s) 7.2 P P (s) = +Ts T >0 C(s) =kp kp > 0 7. L(s) :=P (s)c(s) =kp =( + Ts) jl(j!)j \L(j!) jl(j!)j = kp p +(!T) 2 \L(j!) =;tan;!t! =0 jl(j!)j = kp \L(j!) = 0 [deg]! = jl(j!)j =0 \L(j!) =;90 [deg] L(j!) kp L(j!) = +j!t = kp ( ; j!t) +(!T) 2 L(j!) Im L(j!) =0! =0 P (j!)c(j!) 7.6 kp > 0 P (j!)c(j!) (; 0) kp > 0
15 P (s)c(s) P (s)c(s) P P (s) = (s +) 3 (7.) C(s) =k P k P > 0 (7.2) 7. k P k P > 0 L(s) :=P (s)c(s) jl(j!)j \L(j!) jl(j!)j = k P j +j!j 3 = k P ( +! 2 ) 3=2 \L(j!) =;3tan;! (7.3)! =0 jl(j!)j = k P \L(j!) = 0 [deg]! = jl(j!)j =0 \L(j!) =;270 [deg] L(j!) L(j!) = kp D(j!) D(j!) =(; 3!2 )+j!(3 ;! 2 ) D(j!) Im D(j!) =0 0 <!<! = p 3 \L(j!) =;80 [deg] p! =! pc! pc = 3 7.! =! pc jl(j! pc)j = k P ( +! 2 pc) 3=2 = kp 8 < (7.4) 0 <k P < 8 7. k P =8
16 D =0 2 Ann Bn Cn D u(t) y(t) ( ) 3 (2.) n>m() D = (2.39) (t) =0 J (t) =;c _ (t) ; M`g(t) + (t) (8.3) x(t) u(t) y(t) " # " # x (t) (t) x(t) = = x 2(t) _(t) u(t) = (t) y(t) =(t) _x (t) = (t) _ =x 2(t) _x 2(t) = (t) = ;;c (t) _ ; M`g(t) + (t) J = ; M`g J x(t) ; c J x2(t) + J u(t) y(t) =(t) =x (t) (8.3) A = 4 ; M`g ; c 5 B = 4 5 C = 0 D =0 (8.4) J J J 2 MATLAB 8.5. (73 ) 3
17 D = P{D P{D u(t) =k P e(t) ; k D _y(t) e(t) =r ; y(t) (8.28) u(t) = (t)y(t) =(t) x (t) =(t) x 2(t) = _ (t) (8.28) P{D u(t) =k P ; r ; x (t) ; k Dx 2(t) = ;k P " # x (t) ;k D + k P r x 2(t) = Kx(t) +Hr K = ;k P ;k D H = kp (8.29) (8.27) r =0(8.27) H =0 u(t) =Kx(t) (8.30) (8.30) x(t) (8.30) (8.) ; _x(t) = A + BK x(t) (8.3) A + BK K t! x(t)! 0 (8.30) K
18 y(t) =x (t) =(t) r (8.45)(8.46) K y(t) r = 8.6 Q = diag q q > 0 0 R = (r = x(0) = 0) Z t u(t) =Kx(t) +k I w(t) w(t) := e( )d e(t) =r ; y(t) (8.47) 0 x(t) = y(t) (5.0) (8.47) _y(t)t I{PD x e (t) = x(t) T w(t)t 8.7
19 () P (s) = s ;2 +2 2s + (2) P (s) = ;p 2j ; 3s 2 +2s C 2.2 P (s) = CLs 2 + RCs + Cs 2.3 () P (s) = RCs + (2) P (s) = RCs P (s) = Js 2 + cs 2.5 P (s) = Ms + c 2.6 P (s) = Ms 2 +(c + c 2 )s + k T (t) = 2 M _z(t)2 U (t) =0D(t) = 2 c _z(t)2 q(t) =z(t)(t) =f (t) (2.46) (2.36) r T = M c K = 2.9! n = p = R C K = c CL 2 L 2.0 ;:043 0:5935j0:4793 0:752j;:0000 :442j P (s) = s 2 ; :2j s () ; s s s ; (2) s s s 4 (3) s s s 2 +4 (4) ; s +3 s s 2 +6s +0 (5) 6 s +5 (s +2) 3 (6) s 2 +4s () f (t) =2+3e;2t (2) f (t) = t2 2 e ;t (3) f (t) =cos5t + 5 sin5t (4) f (t) =e ;t 2cos2t + 32 sin2t 3.4 () y(t) = 3 2 ( ; e ;2t ) (2) y(t) =2; 3e;t + e;2t cos2t + 2 sin2t (3) y(t) = 2( ; te;t ; e;t ) (4) y(t) =; e;t 3.5 () y = 2 (2) y =2
20 203 K 3.6 y(t) =L; y(t) = K +Ts T e ;t=t y(0) = K T 3.7 () P (s) = Ls + R T = L R (2) y(t) =K( ; e;t=t )= R ( ; e ;Rt=L )(t 0)y = R (3) R T L T R = =50[]L = RT =0:2 [H] y 3.9 R 2r L r C k 3.0 ()! n = M = c K = 2p km k (2) K = y =0:04! d = A max = 6:28 = ; log e = 2:77 T p T p K (3)! n = q! d = 6:87 = = 0:404 k = = 25! n K M = k =! n 2 0:530c =2! nm = 2:94 3. () (2) (3) (4) () s = ; p 3j 2 (2) s = ; p , 4.4 () k P > ; 2 5 (2) k P > ; <k I < 2 5 (2 + 5k P ) () C(s) =2e = 2 C(s) =5e = () C(s) =2y = 5 5 C(s) =5y = G yr(s) = 0s +6:25 s 3 +2s 2 +2s +6:25, G yd(s) = (2) e =0 (2) y =0 5s s 3 +2s 2 +2s +6:25, s 3 +2s 2 +2s G er(s) = s 3 +2s 2 +2s +6:25, G ;5s ed(s) = s 3 +2s 2 +2s +6:25 G yr(s)gyd (s)
21 () y(t) = 2 et ; 2 (cost +sint) t! et! y(t) y(t) (6.7) 6.2 () jp (j!)j = p 25 +! 2, \P! (j!)=;tan; 5 (2) jp (j!)j = p 25 +! 2, \P (j!) =! tan; 5 (3) 2 jp (j!)j = p 4+! 4, \P 2! (j!)=;tan; 2 ;! 2 (4) jp (j!)j =! 2s +! 2 (9 +! 2 )(6 +! 2 )(25 +! 2 ), \P (j!) = 90 + tan ;! ; tan ;! ;! 3 tan; ;! 4 tan; 5 (5) jp (j!)j = ( +! 2 ) 5, \P (j!)=;0tan;! 6.3 y(t) = sin(t + ), = tan ; 2 ; tan; B(! ) A = 0, B(! 2) A =, B(! 3) A = 0, B(! 4) A = 6.5 P (j!) ==( + j!t) =x + jy jp (j!)j ==p +(!T ) 2 = px 2 + y 2 \P (j!)=;tan ;!T =tan ; y=x y=x = ;!T p +(!T ) 2 = p px +(;y=x) 2 = 2 + y 2 00 (x ; =2) 2 + y 2 =(=2) () P (j!) = e ;j!l = cos!l ; jsin!l jp (j!)j =\P (j!) = ;!L 6.8 (a) (2) jp (j!)j ==p +(!T ) 2 \P (j!) =;(!L +tan ;!T ) 6.8 (b) =0) =0) 7.2 () 0 <k P < 8 (! =! pc = p 5 Im P (j! pc)c(j! pc) (2) 0 <k P < 6(! =! pc = p 2 Im P (j! pc)c(j! pc)
22 7.3 () 8>< >: 8>< >:!gc =!pc = 0 [rad/s] k G M =80; P 20log 0 4 qk [db] =2 ; P 02 [rad/s] (k P > 0 4 ) P M = 80 ; 4tan ; q (2) k P = k =2 ; P [deg] (k P > 0 4 ) P k P =8:5 P M =49:98 [deg]pi k P =5:8T I =0:85 P M =50:23 [deg]pid k P =8:5T I =0:85T D =0:04 P M =50:30 [deg] S(s)T (s) 8 8. () (2.36) x(t) = T z(t) _z(t) Z t _x(t) =" 0 0 ;c=m y(t) = 0 x(t) # x(t) +" 0 =M # u(t) P (s) ==(Ms 2 + cs) (2) RCL (2.20)(2.2) T x(t) = i( )d i(t) 0 _x(t) =" 0 ;=CL ;R=L y(t) = =C 0 x(t) 8.2 e At = e ;2t" # ;3t" 3 ;2 # ; + e # x(t) +" 0 =L # u(t) P (s) ==(CLs 2 + RCs +) ;6 ;2 6 3
213 March 25, 213, Rev.1.5 4........................ 4........................ 6 1 8 1.1............................... 8 1.2....................... 9 2 14 2.1..................... 14 2.2............................
More information214 March 31, 214, Rev.2.1 4........................ 4........................ 5............................. 7............................... 7 1 8 1.1............................... 8 1.2.......................
More information2012 September 21, 2012, Rev.2.2
212 September 21, 212, Rev.2.2 4................. 4 1 6 1.1.................. 6 1.2.................... 7 1.3 s................... 8 1.4....................... 9 1.5..................... 11 2 12 2.1.........................
More information( ) 5. VSS (VIM ) 10. ( ) 11. (ANN ) ( )
1.... ( ) 5. VSS.. 8. 9. (VIM ) 1. ( ) 11. (ANN ) 1. 1. ( ) 1 Lagrange 1..1 Lagrange q, Lagrange D(q)q + C(q; _q)_q + G(q) = (1.1) D(q)q C(q; _q)_q G(q) ( ) D(q) D(q) m ; M < M m (D(q)) (1.) (D(q)) M
More information[1.1] r 1 =10e j(ωt+π/4), r 2 =5e j(ωt+π/3), r 3 =3e j(ωt+π/6) ~r = ~r 1 + ~r 2 + ~r 3 = re j(ωt+φ) =(10e π 4 j +5e π 3 j +3e π 6 j )e jωt
3.4.7 [.] =e j(t+/4), =5e j(t+/3), 3 =3e j(t+/6) ~ = ~ + ~ + ~ 3 = e j(t+φ) =(e 4 j +5e 3 j +3e 6 j )e jt = e jφ e jt cos φ =cos 4 +5cos 3 +3cos 6 =.69 sin φ =sin 4 +5sin 3 +3sin 6 =.9 =.69 +.9 =7.74 [.]
More informationDE-resume
- 2011, http://c-faculty.chuo-u.ac.jp/ nishioka/ 2 11 21131 : 4 1 x y(x, y (x,y (x,,y (n, (1.1 F (x, y, y,y,,y (n =0. (1.1 n. (1.1 y(x. y(x (1.1. 1 1 1 1.1... 2 1.2... 9 1.3 1... 26 2 2 34 2.1,... 35 2.2
More informationS I. dy fx x fx y fx + C 3 C dy fx 4 x, y dy v C xt y C v e kt k > xt yt gt [ v dt dt v e kt xt v e kt + C k x v + C C k xt v k 3 r r + dr e kt S dt d
S I.. http://ayapin.film.s.dendai.ac.jp/~matuda /TeX/lecture.html PDF PS.................................... 3.3.................... 9.4................5.............. 3 5. Laplace................. 5....
More information(3) (2),,. ( 20) ( s200103) 0.7 x C,, x 2 + y 2 + ax = 0 a.. D,. D, y C, C (x, y) (y 0) C m. (2) D y = y(x) (x ± y 0), (x, y) D, m, m = 1., D. (x 2 y
[ ] 7 0.1 2 2 + y = t sin t IC ( 9) ( s090101) 0.2 y = d2 y 2, y = x 3 y + y 2 = 0 (2) y + 2y 3y = e 2x 0.3 1 ( y ) = f x C u = y x ( 15) ( s150102) [ ] y/x du x = Cexp f(u) u (2) x y = xey/x ( 16) ( s160101)
More informationLCR e ix LC AM m k x m x x > 0 x < 0 F x > 0 x < 0 F = k x (k > 0) k x = x(t)
338 7 7.3 LCR 2.4.3 e ix LC AM 7.3.1 7.3.1.1 m k x m x x > 0 x < 0 F x > 0 x < 0 F = k x k > 0 k 5.3.1.1 x = xt 7.3 339 m 2 x t 2 = k x 2 x t 2 = ω 2 0 x ω0 = k m ω 0 1.4.4.3 2 +α 14.9.3.1 5.3.2.1 2 x
More informationhttp://www.ike-dyn.ritsumei.ac.jp/ hyoo/wave.html 1 1, 5 3 1.1 1..................................... 3 1.2 5.1................................... 4 1.3.......................... 5 1.4 5.2, 5.3....................
More informationS I. dy fx x fx y fx + C 3 C vt dy fx 4 x, y dy yt gt + Ct + C dt v e kt xt v e kt + C k x v k + C C xt v k 3 r r + dr e kt S Sr πr dt d v } dt k e kt
S I. x yx y y, y,. F x, y, y, y,, y n http://ayapin.film.s.dendai.ac.jp/~matuda n /TeX/lecture.html PDF PS yx.................................... 3.3.................... 9.4................5..............
More informationhttp://www.ns.kogakuin.ac.jp/~ft13389/lecture/physics1a2b/ pdf I 1 1 1.1 ( ) 1. 30 m µm 2. 20 cm km 3. 10 m 2 cm 2 4. 5 cm 3 km 3 5. 1 6. 1 7. 1 1.2 ( ) 1. 1 m + 10 cm 2. 1 hr + 6400 sec 3. 3.0 10 5 kg
More informationC:/KENAR/0p1.dvi
2{3. 53 2{3 [ ] 4 2 1 2 10,15 m 10,10 m 2 2 54 2 III 1{I U 2.4 U r (2.16 F U F =, du dt du dr > 0 du dr < 0 O r 0 r 2.4: 1 m =1:00 10 kg 1:20 10 kgf 8:0 kgf g =9:8 m=s 2 (a) x N mg 2.5: N 2{3. 55 (b) x
More information,, 2. Matlab Simulink 2018 PC Matlab Scilab 2
(2018 ) ( -1) TA Email : ohki@i.kyoto-u.ac.jp, ske.ta@bode.amp.i.kyoto-u.ac.jp : 411 : 10 308 1 1 2 2 2.1............................................ 2 2.2..................................................
More information211 kotaro@math.titech.ac.jp 1 R *1 n n R n *2 R n = {(x 1,..., x n ) x 1,..., x n R}. R R 2 R 3 R n R n R n D D R n *3 ) (x 1,..., x n ) f(x 1,..., x n ) f D *4 n 2 n = 1 ( ) 1 f D R n f : D R 1.1. (x,
More informationNote.tex 2008/09/19( )
1 20 9 19 2 1 5 1.1........................ 5 1.2............................. 8 2 9 2.1............................. 9 2.2.............................. 10 3 13 3.1.............................. 13 3.2..................................
More information( ) 2.1. C. (1) x 4 dx = 1 5 x5 + C 1 (2) x dx = x 2 dx = x 1 + C = 1 2 x + C xdx (3) = x dx = 3 x C (4) (x + 1) 3 dx = (x 3 + 3x 2 + 3x +
(.. C. ( d 5 5 + C ( d d + C + C d ( d + C ( ( + d ( + + + d + + + + C (5 9 + d + d tan + C cos (sin (6 sin d d log sin + C sin + (7 + + d ( + + + + d log( + + + C ( (8 d 7 6 d + 6 + C ( (9 ( d 6 + 8 d
More information.. p.2/5
IV. p./5 .. p.2/5 .. 8 >< >: d dt y = a, y + a,2 y 2 + + a,n y n + f (t) d dt y 2 = a 2, y + a 2,2 y 2 + + a 2,n y n + f 2 (t). d dt y n = a n, y + a n,2 y 2 + + a n,n y n + f n (t) (a i,j ) p.2/5 .. 8
More information曲面のパラメタ表示と接線ベクトル
L11(2011-07-06 Wed) :Time-stamp: 2011-07-06 Wed 13:08 JST hig 1,,. 2. http://hig3.net () (L11) 2011-07-06 Wed 1 / 18 ( ) 1 V = (xy2 ) x + (2y) y = y 2 + 2. 2 V = 4y., D V ds = 2 2 ( ) 4 x 2 4y dy dx =
More information24.15章.微分方程式
m d y dt = F m d y = mg dt V y = dy dt d y dt = d dy dt dt = dv y dt dv y dt = g dv y dt = g dt dt dv y = g dt V y ( t) = gt + C V y ( ) = V y ( ) = C = V y t ( ) = gt V y ( t) = dy dt = gt dy = g t dt
More informationII K116 : January 14, ,. A = (a ij ) ij m n. ( ). B m n, C n l. A = max{ a ij }. ij A + B A + B, AC n A C (1) 1. m n (A k ) k=1,... m n A, A k k
: January 14, 28..,. A = (a ij ) ij m n. ( ). B m n, C n l. A = max{ a ij }. ij A + B A + B, AC n A C (1) 1. m n (A k ) k=1,... m n A, A k k, A. lim k A k = A. A k = (a (k) ij ) ij, A k = (a ij ) ij, i,
More information08-Note2-web
r(t) t r(t) O v(t) = dr(t) dt a(t) = dv(t) dt = d2 r(t) dt 2 r(t), v(t), a(t) t dr(t) dt r(t) =(x(t),y(t),z(t)) = d 2 r(t) dt 2 = ( dx(t) dt ( d 2 x(t) dt 2, dy(t), dz(t) dt dt ), d2 y(t) dt 2, d2 z(t)
More informationI 1
I 1 1 1.1 1. 3 m = 3 1 7 µm. cm = 1 4 km 3. 1 m = 1 1 5 cm 4. 5 cm 3 = 5 1 15 km 3 5. 1 = 36 6. 1 = 8.64 1 4 7. 1 = 3.15 1 7 1 =3 1 7 1 3 π 1. 1. 1 m + 1 cm = 1.1 m. 1 hr + 64 sec = 1 4 sec 3. 3. 1 5 kg
More information1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0
1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0 0 < t < τ I II 0 No.2 2 C x y x y > 0 x 0 x > b a dx
More informationIA hara@math.kyushu-u.ac.jp Last updated: January,......................................................................................................................................................................................
More informationchap1.dvi
1 1 007 1 e iθ = cos θ + isin θ 1) θ = π e iπ + 1 = 0 1 ) 3 11 f 0 r 1 1 ) k f k = 1 + r) k f 0 f k k = 01) f k+1 = 1 + r)f k ) f k+1 f k = rf k 3) 1 ) ) ) 1+r/)f 0 1 1 + r/) f 0 = 1 + r + r /4)f 0 1 f
More informationc 2009 i
I 2009 c 2009 i 0 1 0.0................................... 1 0.1.............................. 3 0.2.............................. 5 1 7 1.1................................. 7 1.2..............................
More informationn ξ n,i, i = 1,, n S n ξ n,i n 0 R 1,.. σ 1 σ i .10.14.15 0 1 0 1 1 3.14 3.18 3.19 3.14 3.14,. ii 1 1 1.1..................................... 1 1............................... 3 1.3.........................
More information振動と波動
Report JS0.5 J Simplicity February 4, 2012 1 J Simplicity HOME http://www.jsimplicity.com/ Preface 2 Report 2 Contents I 5 1 6 1.1..................................... 6 1.2 1 1:................ 7 1.3
More information<4D F736F F D B B BB2D834A836F815B82D082C88C602E646F63>
信号処理の基礎 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. http://www.morikita.co.jp/books/mid/081051 このサンプルページの内容は, 初版 1 刷発行時のものです. i AI ii z / 2 3 4 5 6 7 7 z 8 8 iii 2013 3 iv 1 1 1.1... 1 1.2... 2 2 4 2.1...
More information<4D F736F F D B B83578B6594BB2D834A836F815B82D082C88C60202E646F63>
MATLAB/Simulink による現代制御入門 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. http://www.morikita.co.jp/books/mid/9241 このサンプルページの内容は, 初版 1 刷発行当時のものです. i MATLAB/Simulink MATLAB/Simulink 1. 1 2. 3. MATLAB/Simulink
More information6. Euler x
...............................................................................3......................................... 4.4................................... 5.5......................................
More information2 0.1 Introduction NMR 70% 1/2
Y. Kondo 2010 1 22 2 0.1 Introduction NMR 70% 1/2 3 0.1 Introduction......................... 2 1 7 1.1.................... 7 1.2............................ 11 1.3................... 12 1.4..........................
More information閨75, 縺5 [ ィ チ573, 縺 ィ ィ
39ィ 8 998 3. 753 68, 7 86 タ7 9 9989769 438 縺48 縺55 3783645 タ5 縺473 タ7996495 ィ 59754 8554473 9 8984473 3553 7. 95457357, 4.3. 639745 5883597547 6755887 67996499 ィ 597545 4953473 9 857473 3553, 536583, 89573,
More informationuntitled
II(c) 1 October. 21, 2009 1 CS53 yamamoto@cs.kobe-u.ac.jp 3 1 7 1.1 : : : : : : : : : : : : : : : : : : : : : : 7 1.2 : : : : : : : : : : : : : : : : 8 1.2.1 : : : : : : : : : : : : : : : : : : : 8 1.2.2
More informationA大扉・騒音振動.qxd
H21-30 H21-31 H21-32 H21-33 H21-34 H21-35 H21-36 H21-37 H21-38 H21-39 H21-40 H21-41 H21-42 n n S L N S L N L N S S S L L log I II I L I L log I I H21-43 L log L log I I I log log I I I log log I I I I
More information2019 1 5 0 3 1 4 1.1.................... 4 1.1.1......................... 4 1.1.2........................ 5 1.1.3................... 5 1.1.4........................ 6 1.1.5......................... 6 1.2..........................
More information006 11 8 0 3 1 5 1.1..................... 5 1......................... 6 1.3.................... 6 1.4.................. 8 1.5................... 8 1.6................... 10 1.6.1......................
More information() (, y) E(, y) () E(, y) (3) q ( ) () E(, y) = k q q (, y) () E(, y) = k r r (3).3 [.7 ] f y = f y () f(, y) = y () f(, y) = tan y y ( ) () f y = f y
5. [. ] z = f(, y) () z = 3 4 y + y + 3y () z = y (3) z = sin( y) (4) z = cos y (5) z = 4y (6) z = tan y (7) z = log( + y ) (8) z = tan y + + y ( ) () z = 3 8y + y z y = 4 + + 6y () z = y z y = (3) z =
More information2011de.dvi
211 ( 4 2 1. 3 1.1............................... 3 1.2 1- -......................... 13 1.3 2-1 -................... 19 1.4 3- -......................... 29 2. 37 2.1................................ 37
More information1 8, : 8.1 1, 2 z = ax + by + c ax by + z c = a b +1 x y z c = 0, (0, 0, c), n = ( a, b, 1). f = n i=1 a ii x 2 i + i<j 2a ij x i x j = ( x, A x), f =
1 8, : 8.1 1, z = ax + by + c ax by + z c = a b +1 x y z c = 0, (0, 0, c), n = ( a, b, 1). f = a ii x i + i
More informationB ver B
B ver. 2017.02.24 B Contents 1 11 1.1....................... 11 1.1.1............. 11 1.1.2.......................... 12 1.2............................. 14 1.2.1................ 14 1.2.2.......................
More informationgenron-3
" ( K p( pasals! ( kg / m 3 " ( K! v M V! M / V v V / M! 3 ( kg / m v ( v "! v p v # v v pd v ( J / kg p ( $ 3! % S $ ( pv" 3 ( ( 5 pv" pv R" p R!" R " ( K ( 6 ( 7 " pv pv % p % w ' p% S & $ p% v ( J /
More informationCSE2LEC2
" dt = "r(t "T s dt = "r(t "T s T T s dt T "T s = "r ln(t "T s = "rt + rt 0 T = T s + Ae "rt T(0 = T 0 T(0 = T s + A A = T 0 "T s T(t = T s + (T 0 "T s e "rt dy dx = f (x, y (Euler dy dx = f (x, y y y(x
More information入試の軌跡
4 y O x 4 Typed by L A TEX ε ) ) ) 6 4 ) 4 75 ) http://kumamoto.s.xrea.com/plan/.. PDF) Ctrl +L) Ctrl +) Ctrl + Ctrl + ) ) Alt + ) Alt + ) ESC. http://kumamoto.s.xrea.com/nyusi/kumadai kiseki ri i.pdf
More information4.2.................... 20 4.3.................. 21 4.4 ( )............... 22 4.5 ( )...... 24 4.6 ( )........ 25 4.7 ( )..... 26 5 28 5.1 PID........
version 0.01 : 2004/04/16 1 2 1.1................. 2 1.2.......................... 3 1.3................. 5 1.4............... 6 1.5.............. 7 2 9 2.1........................ 9 2.2......................
More informationさくらの個別指導 ( さくら教育研究所 ) A AB A B A B A AB AB AB B
1 1.1 1.1.1 1 1 1 1 a a a a C a a = = CD CD a a a a a a = a = = D 1.1 CD D= C = DC C D 1.1 (1) 1 3 4 5 8 7 () 6 (3) 1.1. 3 1.1. a = C = C C C a a + a + + C = a C 1. a a + (1) () (3) b a a a b CD D = D
More information36 th IChO : - 3 ( ) , G O O D L U C K final 1
36 th ICh - - 5 - - : - 3 ( ) - 169 - -, - - - - - - - G D L U C K final 1 1 1.01 2 e 4.00 3 Li 6.94 4 Be 9.01 5 B 10.81 6 C 12.01 7 N 14.01 8 16.00 9 F 19.00 10 Ne 20.18 11 Na 22.99 12 Mg 24.31 Periodic
More information(u(x)v(x)) = u (x)v(x) + u(x)v (x) ( ) u(x) = u (x)v(x) u(x)v (x) v(x) v(x) 2 y = g(t), t = f(x) y = g(f(x)) dy dx dy dx = dy dt dt dx., y, f, g y = f (g(x))g (x). ( (f(g(x)). ). [ ] y = e ax+b (a, b )
More information1.1 ft t 2 ft = t 2 ft+ t = t+ t 2 1.1 d t 2 t + t 2 t 2 = lim t 0 t = lim t 0 = lim t 0 t 2 + 2t t + t 2 t 2 t + t 2 t 2t t + t 2 t 2t + t = lim t 0
A c 2008 by Kuniaki Nakamitsu 1 1.1 t 2 sin t, cos t t ft t t vt t xt t + t xt + t xt + t xt t vt = xt + t xt t t t vt xt + t xt vt = lim t 0 t lim t 0 t 0 vt = dxt ft dft dft ft + t ft = lim t 0 t 1.1
More informationp06.dvi
I 6 : 1 (1) u(t) y(t) : n m a n i y (i) = b m i u (i) i=0 i=0 t, y (i) y i (u )., a 0 0, b 0 0. : 2 (2), Laplace, (a 0 s n +a 1 s n 1 + +a n )Y(s) = (b 0 s m + b 1 s m 1 + +b m )U(s),, Y(s) U(s) = b 0s
More informationDecember 28, 2018
e-mail : kigami@i.kyoto-u.ac.jp December 28, 28 Contents 2............................. 3.2......................... 7.3..................... 9.4................ 4.5............. 2.6.... 22 2 36 2..........................
More information24 I ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x
24 I 1.1.. ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x 1 (t), x 2 (t),, x n (t)) ( ) ( ), γ : (i) x 1 (t),
More informationt θ, τ, α, β S(, 0 P sin(θ P θ S x cos(θ SP = θ P (cos(θ, sin(θ sin(θ P t tan(θ θ 0 cos(θ tan(θ = sin(θ cos(θ ( 0t tan(θ
4 5 ( 5 3 9 4 0 5 ( 4 6 7 7 ( 0 8 3 9 ( 8 t θ, τ, α, β S(, 0 P sin(θ P θ S x cos(θ SP = θ P (cos(θ, sin(θ sin(θ P t tan(θ θ 0 cos(θ tan(θ = sin(θ cos(θ ( 0t tan(θ S θ > 0 θ < 0 ( P S(, 0 θ > 0 ( 60 θ
More informationPart () () Γ Part ,
Contents a 6 6 6 6 6 6 6 7 7. 8.. 8.. 8.3. 8 Part. 9. 9.. 9.. 3. 3.. 3.. 3 4. 5 4.. 5 4.. 9 4.3. 3 Part. 6 5. () 6 5.. () 7 5.. 9 5.3. Γ 3 6. 3 6.. 3 6.. 3 6.3. 33 Part 3. 34 7. 34 7.. 34 7.. 34 8. 35
More informationII No.01 [n/2] [1]H n (x) H n (x) = ( 1) r n! r!(n 2r)! (2x)n 2r. r=0 [2]H n (x) n,, H n ( x) = ( 1) n H n (x). [3] H n (x) = ( 1) n dn x2 e dx n e x2
II No.1 [n/] [1]H n x) H n x) = 1) r n! r!n r)! x)n r r= []H n x) n,, H n x) = 1) n H n x) [3] H n x) = 1) n dn x e dx n e x [4] H n+1 x) = xh n x) nh n 1 x) ) d dx x H n x) = H n+1 x) d dx H nx) = nh
More information構造と連続体の力学基礎
II 37 Wabash Avenue Bridge, Illinois 州 Winnipeg にある歩道橋 Esplanade Riel 橋6 6 斜張橋である必要は多分無いと思われる すぐ横に道路用桁橋有り しかも塔基部のレストランは 8 年には営業していなかった 9 9. 9.. () 97 [3] [5] k 9. m w(t) f (t) = f (t) + mg k w(t) Newton
More information4.6: 3 sin 5 sin θ θ t θ 2t θ 4t : sin ωt ω sin θ θ ωt sin ωt 1 ω ω [rad/sec] 1 [sec] ω[rad] [rad/sec] 5.3 ω [rad/sec] 5.7: 2t 4t sin 2t sin 4t
1 1.1 sin 2π [rad] 3 ft 3 sin 2t π 4 3.1 2 1.1: sin θ 2.2 sin θ ft t t [sec] t sin 2t π 4 [rad] sin 3.1 3 sin θ θ t θ 2t π 4 3.2 3.1 3.4 3.4: 2.2: sin θ θ θ [rad] 2.3 0 [rad] 4 sin θ sin 2t π 4 sin 1 1
More information2 1 κ c(t) = (x(t), y(t)) ( ) det(c (t), c x (t)) = det (t) x (t) y (t) y = x (t)y (t) x (t)y (t), (t) c (t) = (x (t)) 2 + (y (t)) 2. c (t) =
1 1 1.1 I R 1.1.1 c : I R 2 (i) c C (ii) t I c (t) (0, 0) c (t) c(i) c c(t) 1.1.2 (1) (2) (3) (1) r > 0 c : R R 2 : t (r cos t, r sin t) (2) C f : I R c : I R 2 : t (t, f(t)) (3) y = x c : R R 2 : t (t,
More information,. Black-Scholes u t t, x c u 0 t, x x u t t, x c u t, x x u t t, x + σ x u t, x + rx ut, x rux, t 0 x x,,.,. Step 3, 7,,, Step 6., Step 4,. Step 5,,.
9 α ν β Ξ ξ Γ γ o δ Π π ε ρ ζ Σ σ η τ Θ θ Υ υ ι Φ φ κ χ Λ λ Ψ ψ µ Ω ω Def, Prop, Th, Lem, Note, Remark, Ex,, Proof, R, N, Q, C [a, b {x R : a x b} : a, b {x R : a < x < b} : [a, b {x R : a x < b} : a,
More information<4D F736F F D B B83578B6594BB2D834A836F815B82D082C88C60202E646F63>
単純適応制御 SAC サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. http://www.morikita.co.jp/books/mid/091961 このサンプルページの内容は, 初版 1 刷発行当時のものです. 1 2 3 4 5 9 10 12 14 15 A B F 6 8 11 13 E 7 C D URL http://www.morikita.co.jp/support
More information30 (11/04 )
30 (11/04 ) i, 1,, II I?,,,,,,,,, ( ),,, ϵ δ,,,,, (, ),,,,,, 5 : (1) ( ) () (,, ) (3) ( ) (4) (5) ( ) (1),, (),,, () (3), (),, (4), (1), (3), ( ), (5),,,,,,,, ii,,,,,,,, Richard P. Feynman, The best teaching
More information381
P381 P386 P396 P397 P401 P423 P430 P433 P435 P437 P448 P451 P452 381 382 383 384 385 3.0mm 5.0mm 3.0mm 5.0mm SK SK3.0mm SK5.0mm 3.0mm PUR PUR3.0mm 2.0mm 2.0mm3.0mm 2.5mm 2.5mm3.0mm 3.0mm 5.0mm 3.0mm 1.8mm
More information2.2 ( y = y(x ( (x 0, y 0 y (x 0 (y 0 = y(x 0 y = y(x ( y (x 0 = F (x 0, y(x 0 = F (x 0, y 0 (x 0, y 0 ( (x 0, y 0 F (x 0, y 0 xy (x, y (, F (x, y ( (
(. x y y x f y = f(x y x y = y(x y x y dx = d dx y(x = y (x = f (x y = y(x x ( (differential equation ( + y 2 dx + xy = 0 dx = xy + y 2 2 2 x y 2 F (x, y = xy + y 2 y = y(x x x xy(x = F (x, y(x + y(x 2
More information( )
18 10 01 ( ) 1 2018 4 1.1 2018............................... 4 1.2 2018......................... 5 2 2017 7 2.1 2017............................... 7 2.2 2017......................... 8 3 2016 9 3.1 2016...............................
More informationPII S (96)
C C R ( 1 Rvw C d m d M.F. Pllps *, P.S. Hp I q G U W C M H P C C f R 5 J 1 6 J 1 A C d w m d u w b b m C d m d T b s b s w b d m d s b s C g u T p d l v w b s d m b b v b b d s d A f b s s s T f p s s
More informationM3 x y f(x, y) (= x) (= y) x + y f(x, y) = x + y + *. f(x, y) π y f(x, y) x f(x + x, y) f(x, y) lim x x () f(x,y) x 3 -
M3............................................................................................ 3.3................................................... 3 6........................................... 6..........................................
More information< 1 > (1) f 0 (a) =6a ; g 0 (a) =6a 2 (2) y = f(x) x = 1 f( 1) = 3 ( 1) 2 =3 ; f 0 ( 1) = 6 ( 1) = 6 ; ( 1; 3) 6 x =1 f(1) = 3 ; f 0 (1) = 6 ; (1; 3)
< 1 > (1) f 0 (a) =6a ; g 0 (a) =6a 2 (2) y = f(x) x = 1 f( 1) = 3 ( 1) 2 =3 ; f 0 ( 1) = 6 ( 1) = 6 ; ( 1; 3) 6 x =1 f(1) = 3 ; f 0 (1) = 6 ; (1; 3) 6 y = g(x) x = 1 g( 1) = 2 ( 1) 3 = 2 ; g 0 ( 1) =
More informationK E N Z OU
K E N Z OU 11 1 1 1.1..................................... 1.1.1............................ 1.1..................................................................................... 4 1.........................................
More information23 7 28 i i 1 1 1.1................................... 2 1.2............................... 3 1.2.1.................................... 3 1.2.2............................... 4 1.2.3 SI..............................
More informationkeisoku01.dvi
2.,, Mon, 2006, 401, SAGA, JAPAN Dept. of Mechanical Engineering, Saga Univ., JAPAN 4 Mon, 2006, 401, SAGA, JAPAN Dept. of Mechanical Engineering, Saga Univ., JAPAN 5 Mon, 2006, 401, SAGA, JAPAN Dept.
More information名古屋工業大の数学 2000 年 ~2015 年 大学入試数学動画解説サイト
名古屋工業大の数学 年 ~5 年 大学入試数学動画解説サイト http://mathroom.jugem.jp/ 68 i 4 3 III III 3 5 3 ii 5 6 45 99 5 4 3. () r \= S n = r + r + 3r 3 + + nr n () x > f n (x) = e x + e x + 3e 3x + + ne nx f(x) = lim f n(x) lim
More information2 Chapter 4 (f4a). 2. (f4cone) ( θ) () g M. 2. (f4b) T M L P a θ (f4eki) ρ H A a g. v ( ) 2. H(t) ( )
http://astr-www.kj.yamagata-u.ac.jp/~shibata f4a f4b 2 f4cone f4eki f4end 4 f5meanfp f6coin () f6a f7a f7b f7d f8a f8b f9a f9b f9c f9kep f0a f0bt version feqmo fvec4 fvec fvec6 fvec2 fvec3 f3a (-D) f3b
More information128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds = 0 (3.4) S 1, S 2 { B( r) n( r)}ds
127 3 II 3.1 3.1.1 Φ(t) ϕ em = dφ dt (3.1) B( r) Φ = { B( r) n( r)}ds (3.2) S S n( r) Φ 128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds
More informationA (1) = 4 A( 1, 4) 1 A 4 () = tan A(0, 0) π A π
4 4.1 4.1.1 A = f() = f() = a f (a) = f() (a, f(a)) = f() (a, f(a)) f(a) = f 0 (a)( a) 4.1 (4, ) = f() = f () = 1 = f (4) = 1 4 4 (4, ) = 1 ( 4) 4 = 1 4 + 1 17 18 4 4.1 A (1) = 4 A( 1, 4) 1 A 4 () = tan
More informationx i [, b], (i 0, 1, 2,, n),, [, b], [, b] [x 0, x 1 ] [x 1, x 2 ] [x n 1, x n ] ( 2 ). x 0 x 1 x 2 x 3 x n 1 x n b 2: [, b].,, (1) x 0, x 1, x 2,, x n
1, R f : R R,.,, b R < b, f(x) [, b] f(x)dx,, [, b] f(x) x ( ) ( 1 ). y y f(x) f(x)dx b x 1: f(x)dx, [, b] f(x) x ( ).,,,,,., f(x)dx,,,, f(x)dx. 1.1 Riemnn,, [, b] f(x) x., x 0 < x 1 < x 2 < < x n 1
More informationanalog-control-mod : 2007/2/4(8:44) 2 E8 P M () r e K P ( ) T I u K M T M K D E8.: DC PID K D E8. (E8.) P M () E8.2 K P D () ( T ) (E8.2) K M T M K, T
analog-control-mod : 2007/2/4(8:44) E8 E8. PID DC. PID 2. DC PID 3. E8.2 DC PID C8 E8. DC PID E6 DC P M () K M ( T M ) (E8.) DC PID C8 E8. r e u E8.2 PID E8. PID analog-control-mod : 2007/2/4(8:44) 2 E8
More informationIII Kepler ( )
III 9 8 3....................................... 3.2 Kepler ( ).......................... 0 2 3 2.................................. 3 2.2......................................... 7 3 9 3..........................................
More information[] x < T f(x), x < T f(x), < x < f(x) f(x) f(x) f(x + nt ) = f(x) x < T, n =, 1,, 1, (1.3) f(x) T x 2 f(x) T 2T x 3 f(x), f() = f(t ), f(x), f() f(t )
1 1.1 [] f(x) f(x + T ) = f(x) (1.1), f(x), T f(x) x T 1 ) f(x) = sin x, T = 2 sin (x + 2) = sin x, sin x 2 [] n f(x + nt ) = f(x) (1.2) T [] 2 f(x) g(x) T, h 1 (x) = af(x)+ bg(x) 2 h 2 (x) = f(x)g(x)
More information( ) ( )
20 21 2 8 1 2 2 3 21 3 22 3 23 4 24 5 25 5 26 6 27 8 28 ( ) 9 3 10 31 10 32 ( ) 12 4 13 41 0 13 42 14 43 0 15 44 17 5 18 6 18 1 1 2 2 1 2 1 0 2 0 3 0 4 0 2 2 21 t (x(t) y(t)) 2 x(t) y(t) γ(t) (x(t) y(t))
More informationB. 41 II: 2 ;; 4 B [ ] S 1 S 2 S 1 S O S 1 S P 2 3 P P : 2.13:
B. 41 II: ;; 4 B [] S 1 S S 1 S.1 O S 1 S 1.13 P 3 P 5 7 P.1:.13: 4 4.14 C d A B x l l d C B 1 l.14: AB A 1 B 0 AB 0 O OP = x P l AP BP AB AP BP 1 (.4)(.5) x l x sin = p l + x x l (.4)(.5) m d A x P O
More informationBut nothing s unconditional, The Bravery R R >0 = (0, ) ( ) R >0 = (0, ) f, g R >0 f (0, R), R >
2 2 http://www.ozawa.phys.waseda.ac.jp/inde2.html But nothing s unconditional, The Bravery > (, ( > (, f, g > f (,, > sup f( ( M f(g( (i > g [, lim g( (ii g > (, ( g ( < ( > f(g( (i g < < f(g( g(
More informationTCSE4~5
II. T = 1 m!! U = mg!(1 cos!) E = T + U! E U = T E U! m U,E mg! U = mg!(1! cos)! < E < mg! mg! < E! L = T!U = 1 m!! mg!(1! cos) d L! L = L = L m!, =!mg!sin m! + mg!sin = d =! g! sin & g! d =! sin ! = v
More informationFr
2007 04 02 12 1 2 2 3 2.1............................ 4 3 6 3.1............................. 7 3.2....................... 9 3.3............................. 10 4 Frenet 12 5 14 6 Frenet-Serret 15 6.1 Frenet-Serret.......................
More informationv_-3_+2_1.eps
I 9-9 (3) 9 9, x, x (t)+a(t)x (t)+b(t)x(t) = f(t) (9), a(t), b(t), f(t),,, f(t),, a(t), b(t),,, x (t)+ax (t)+bx(t) = (9),, x (t)+ax (t)+bx(t) = f(t) (93), b(t),, b(t) 9 x (t), x (t), x (t)+a(t)x (t)+b(t)x(t)
More informationsikepuri.dvi
2009 2 2 2. 2.. F(s) G(s) H(s) G(s) F(s) H(s) F(s),G(s) H(s) : V (s) Z(s)I(s) I(s) Y (s)v (s) Z(s): Y (s): 2: ( ( V V 2 I I 2 ) ( ) ( Z Z 2 Z 2 Z 22 ) ( ) ( Y Y 2 Y 2 Y 22 ( ) ( ) Z Z 2 Y Y 2 : : Z 2 Z
More informationII Karel Švadlenka * [1] 1.1* 5 23 m d2 x dt 2 = cdx kx + mg dt. c, g, k, m 1.2* u = au + bv v = cu + dv v u a, b, c, d R
II Karel Švadlenka 2018 5 26 * [1] 1.1* 5 23 m d2 x dt 2 = cdx kx + mg dt. c, g, k, m 1.2* 5 23 1 u = au + bv v = cu + dv v u a, b, c, d R 1.3 14 14 60% 1.4 5 23 a, b R a 2 4b < 0 λ 2 + aλ + b = 0 λ =
More information1 1 H Li Be Na M g B A l C S i N P O S F He N Cl A e K Ca S c T i V C Mn Fe Co Ni Cu Zn Ga Ge As Se B K Rb S Y Z Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb T e
No. 1 1 1 H Li Be Na M g B A l C S i N P O S F He N Cl A e K Ca S c T i V C Mn Fe Co Ni Cu Zn Ga Ge As Se B K Rb S Y Z Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb T e I X e Cs Ba F Ra Hf Ta W Re Os I Rf Db Sg Bh
More informationOABC OA OC 4, OB, AOB BOC COA 60 OA a OB b OC c () AB AC () ABC D OD ABC OD OA + p AB + q AC p q () OABC 4 f(x) + x ( ), () y f(x) P l 4 () y f(x) l P
4 ( ) ( ) ( ) ( ) 4 5 5 II III A B (0 ) 4, 6, 7 II III A B (0 ) ( ),, 6, 8, 9 II III A B (0 ) ( [ ] ) 5, 0, II A B (90 ) log x x () (a) y x + x (b) y sin (x + ) () (a) (b) (c) (d) 0 e π 0 x x x + dx e
More informationchap9.dvi
9 AR (i) (ii) MA (iii) (iv) (v) 9.1 2 1 AR 1 9.1.1 S S y j = (α i + β i j) D ij + η j, η j = ρ S η j S + ε j (j =1,,T) (1) i=1 {ε j } i.i.d(,σ 2 ) η j (j ) D ij j i S 1 S =1 D ij =1 S>1 S =4 (1) y j =
More informationF8302D_1目次_160527.doc
N D F 830D.. 3. 4. 4. 4.. 4.. 4..3 4..4 4..5 4..6 3 4..7 3 4..8 3 4..9 3 4..0 3 4. 3 4.. 3 4.. 3 4.3 3 4.4 3 5. 3 5. 3 5. 3 5.3 3 5.4 3 5.5 4 6. 4 7. 4 7. 4 7. 4 8. 4 3. 3. 3. 3. 4.3 7.4 0 3. 3 3. 3 3.
More information応力とひずみ.ppt
in yukawa@numse.nagoya-u.ac.jp 2 3 4 5 x 2 6 Continuum) 7 8 9 F F 10 F L L F L 1 L F L F L F 11 F L F F L F L L L 1 L 2 12 F L F! A A! S! = F S 13 F L L F F n = F " cos# F t = F " sin# S $ = S cos# S S
More informationlaplace.dvi
Λ 2.1 2004.2.20 1 Λ 1 2 Ay = u 2 2 A 2 u " # a 11 a 12 A = ; u = a 21 a 22 " # u 1 u 2 y Ay = u (1) A (1) y = A 1 u y A 2 x i i i =1; 2 Ax 1 = 1 x 1 ; Ax 2 = 2 x 2 (2) x 1 x 2 =0 (3) (3) (2) x 1 x 2 x
More informationf(x) = x (1) f (1) (2) f (2) f(x) x = a y y = f(x) f (a) y = f(x) A(a, f(a)) f(a + h) f(x) = A f(a) A x (3, 3) O a a + h x 1 f(x) x = a
3 3.1 3.1.1 A f(a + h) f(a) f(x) lim f(x) x = a h 0 h f(x) x = a f 0 (a) f 0 (a) = lim h!0 f(a + h) f(a) h = lim x!a f(x) f(a) x a a + h = x h = x a h 0 x a 3.1 f(x) = x x = 3 f 0 (3) f (3) = lim h 0 (
More information小川/小川
T pt T T T T p T T T T T p T T T T T T p p T T T p p T p B T T T T T pt T Tp T p T T psp T p T p T p T p T p Tp T p T p T T p T T T T T T T Tp T p p p T T T T p T T T T T T T p T T T T T p p T T T T T
More informationmeiji_resume_1.PDF
β β β (q 1,q,..., q n ; p 1, p,..., p n ) H(q 1,q,..., q n ; p 1, p,..., p n ) Hψ = εψ ε k = k +1/ ε k = k(k 1) (x, y, z; p x, p y, p z ) (r; p r ), (θ; p θ ), (ϕ; p ϕ ) ε k = 1/ k p i dq i E total = E
More informationI ( ) 1 de Broglie 1 (de Broglie) p λ k h Planck ( Js) p = h λ = k (1) h 2π : Dirac k B Boltzmann ( J/K) T U = 3 2 k BT
I (008 4 0 de Broglie (de Broglie p λ k h Planck ( 6.63 0 34 Js p = h λ = k ( h π : Dirac k B Boltzmann (.38 0 3 J/K T U = 3 k BT ( = λ m k B T h m = 0.067m 0 m 0 = 9. 0 3 kg GaAs( a T = 300 K 3 fg 07345
More informationarma dvi
ARMA 007/05/0 Rev.0 007/05/ Rev.0 007/07/7 3. : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : 3. : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : 3.3 : : : :
More information