2 (f4eki) ρ H A a g. v ( ) 2. H(t) ( ) Chapter 5 (f5meanfp) ( ( )? N [] σ e = 8π ( ) e mc 2 = cm 2 e m c (, Thomson cross secion). Cha
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1 P a θ T P M Chapter 4 (f4a) (f4cone) ( θ) () g M θ (f4b) T M L
![2 (f4eki) ρ H A a g. v ( ) 2. H(t) ( ) Chapter 5 (f5meanfp) ( ( )? N [] σ e = 8π ( ) e 2 2 3 mc 2 = 6.](/docs-images/43/23149233/images/2-0.png "65 0 25 cm 2 e m c (, Thomson cross secion). Chapter 6 (f6coin) (f4end)?")
2 2 (f4eki) ρ H A a g. v ( ) 2. H(t) ( ) Chapter 5 (f5meanfp) ( ( )? N [] σ e = 8π ( ) e mc 2 = cm 2 e m c (, Thomson cross secion). Chapter 6 (f6coin) (f4end)? /2 6 0 /2 /
![N [] σ e = 8π ( ) e 2 2 3 mc 2 = 6.](/docs-images/43/23149233/images/page_2.jpg "65 0 25 cm 2 e m c (, Thomson cross secion).")
3 3 /2 () x x x x D = x x D 2 ( 2 0 ) III : T a 3/2 III name= F7A (f6a) l ( l ) σ (= cm 2 ) n( cm 3 ) l = σn R = cm c = cm/sec (f7b). :T = 27.3 :R = m 2. g = 9.8m/s 2 R = m name= F7B Chapter 7 (f7a) : I II ( ) (f7d) name= F7D
4 4 Chapter 8 (f8a) x = A sin ωt + B cos ωt A, B, ω t (f8b) a = 5 exp[ t 20 ] 0 (f9b) (R, θ(t)) t R θ(t) ω(t) = dθ(t) (x, y) (R, θ) x = R cos θ y = R sin θ x y F x, F y m Chapter 9 (f9a) x = v 0 t, y = y 0 2 gt2 m v 0, y 0, g (f9c) (f9b) d 2 θ 2 = g R sin θ θ R g t (f9kep)
5 5 I II ( ) III T a T a3/2 (r, θ) t : r = r(t), θ = θ(t). ( ) l 2. = C( + ϵ cos θ) r C, ϵ (< ) l l (l ) m,m 2 x,x 2. V,V 2 CM V CM = m V + m 2 V 2 m + m 2 2. V CM 3. T CM T CM T = T CM + 2 (m + m 2 )V 2 CM 4. F,F 2 () M dv CM = F M = m + m 2, F = F + F 2 5. Chapter 0 (f0a) x (Center of Mass) (f0bt) (=eject) ( ;satellite () X CM = m x + m 2 x 2 m + m 2
6 6. M V m ( eject) V + U V 0 ( assumed) U 2. U/V 0 m d da (A B) = B + A db (fvec) m = m v = 3i + 2j k m 2 = 2m v 2 = 2i + 2j + 4k Chapter (feqmo) (x, y, z) θ (x, y, z ) x = x cos θ + y sin θ () y = y cos θ x sin θ (2) z = z (3) F x = F x cos θ + F y sin θ (4) F y = F y cos θ F x sin θ (5) F z = F z (6) (fvec4) f A B d df (fa) = A + f da (fvec6) r(t) v = dr/ t v = v ˆv = v/v d θ v(t) v(t+) d θ n v(t) v R v(t+) a = dv v2 ˆv + R n (7) R n
7 7. v = vˆv dˆv ˆv dˆv n dˆv = v R n 4. (7) Chapter 3 (f3a.tex). 2 mv2 + mgh = ( ) m, v, h, g T () U() T + U = ( ) (fvec2) kg ( m sec r = ti + (t + t2 2 )j ( 4 πt sin π2 2 )k.. t = 0 t = t = (fvec3), (λ, ϕ ) (λ 2, ϕ 2 ) 2. (f3b). m T = 2 mv2 F v dt = F v. 2. T = T 2 T = 2 F ds
8 8 mg ( ) 2 mv2 + mgh = ( ) h ( ) (f3c) M( M) m( m) M m 2 mv2 + U(r) = ( ) r U(r) (f3e) i 2 m ivi 2 + (f3f) i,j Gm im j r ij = ( ) a ( ) G σ (f3h) M R m M ( r r < R r > R ) (f3d) O kx m( m) k, x O m 2 mv2 + U(x) = ( ) U(x) Chapter 4 (f4ae) m F r(t) v(t) ( ( )
9 9 ). F 2. F U : 2 mv2 + U = ( ) gradient( ) C r G (f4c) N m i (i =, 2,..., N) Ψ = N i= Gm i r i r i (f4e) (f4b) mv2 GmM r = E m (a, 0, 0) ( a, 0, 0) (x, y, 0) (f4f). M R 2. (f4d) m Ψ = Gm r
10 0 Chapter 8-9 (f8a) l m (f8e) (f8b) τ = xf y yf x F θ r F r 0 F θ r F r 0 R I F ω R F (f8c) R V (f8d) ( ) ( M) ω a b (f9a) CM R CM ( O CM ). O CM L = m i r i V i i
11 l = i m i r i V i (f9e) (r i, V i CM ) L = MR CM V CM + l ( M = m i ) 2. CM M dv CM = i F i dl/ = ()= r i F i CM dl = i r i F i F8D (f9f) I 0 (turn table) (mono rail) m ω r. dr dω ω (f9b) M (f9c) M ( )
12 2 (a-f4a.tex). 2. x 8x 00 2 x = = 25[kg ] (8) 3. l l/4 x l = mg l 4 x = 25g[N] (9) g (a-f4b.tex) L R F p F F L R F p»» = LF = RF p. MgL sin θ T a cos θ T = L Mg tan θ (0) a 2. l H T l Mg H T = Mg H l ()
![l l/4 x l = mg l 4 x = 25g[N] (9) g (a-f4b.](/docs-images/43/23149233/images/page_12.jpg "tex) L R F p F F L R F p»» = LF = RF p.")
13 3 l H x h x = a sin θ h = L cos θ θ dx dθ = a cos θ, dh dθ = L sin θ, (2) θ x = (a cos θ) θ h = (L sin θ) θ H l = h x = L sin θ a cos θ (3) () ( ) T = L Mg tan θ (4) a (a-f4cone.tex) l h T l Mg h T = Mg h (5) l h l l = 2πr θ () h h = r/ tan θ l = 2π r h = r/ tan θ T = Mg 2π tan θ ϕ M 2π m = M( ϕ/2π) F F = m g tan θ T F F T sin( ϕ) F T = Mg/2π tan θ (6) (7)
14 4 (a-f4eki.tex) t DeltaH E = ( ) ( ) = gh m (8) E 2 = 2 ( m)v2 (9) E = E 2 v = 2gH (a-f5meanfp.tex) l = Nσ N cm (20) (a-f6coin.tex) ( ) (a-f6a.tex) N N l N = (R/l) 2 l/c t = l c ( ) 2 R l l.8cm t sec (2.8 ) 3 (a-f7a.tex) T F = mrω 2 = mr T = a 3/2 F m/r 2 ( ) 2 2π T
15 5 (a-f7b.tex) (a) a = v2 R = Rω2 = m/s 2 ω = 2π/T = 2π/27.3day (b) 2 (a) a = 9.8 ( ) 2 R = m/s 2 R (a-f7d.tex) R = m v 2 /R v 2 R = g g = 9.8m/s 2 v = gr = km/s (a-f8a.tex) v = dx = Aω cos ωt Bω sin ωt a = dv = Aω2 sin ωt Bω 2 cos ωt = ω 2 x (a-f8b.tex) t = 0 T 0 T 0 dv = T 0 ( 5 exp t ) 20 ( v(t ) = 4 4 exp T ) 20 T v 4
16 6 (a-f9a.tex) F x = mẍ = 0, F y = mÿ = mg (a-f9b.tex) dx dy = R sin θ dθ = R cos θ dθ (2) (22) a a x = d2 x 2 = R cos θ a y = d2 y 2 = R sin θ ( ) 2 dθ R sin θ d2 θ 2 (23) ( ) 2 dθ + R cos θ d2 θ 2 (24) F = ma ( ) ( = Rω 2 F x F y cos θ sin θ ) ( + R dω sin θ cos θ ) (25) ω = dθ/ F r = Rω 2 F θ = Rdω/ (a-f9c.tex) mrω 2ˆr mg cos θ T )ˆr T T = mg cos θ + mrω 2 ˆθ mr θ mg sin θ d 2 θ 2 = g R sin θ (a9kep.tex). (r(t), θ(t)) t t (/2)r rω t ( ) r 2 ω = r 2 θ = (26)
17 7 dθ/ = θ = ω r ω τ r ω t 2. F = ( F x F y ) x = r cos θ, y = r sin θ θ r 2 θ = l ẋ = ṙ cos θ l sin θ, ẏ = ṙ sin θ + l cos θ (28) r r ẍ = r cos θ l2 cos θ r 3, ÿ = r sin θ l2 sin θ r 3 (29) = ( mẍ mÿ ) (27) r = C( + ϵ cos θ), r = Cϵl2 cos θ r 2 (30) F = ( F x F y ) = mcl2 r 2 ( cos θ sin θ ) = mcl2 r 2 ˆr (3) ˆr r 2 (a-f9e.tex) θ = 0 θ = π r = C + e, r 2 = C e, (32) a = r + r 2 2 = C e 2 (33) P F +P F 2 = QF +QF 2 QF = a ()OF = a r OF Q b = QO b 2 = a 2 (a r ) 2 = C 2 ( e 2 ) 2 e2 C 2 ( e 2 ) 2 = C2 e 2 (34)
18 8 b = C e 2 = a e 2 (35) T πab h 2 = πab T = πa2 e 2 T (36) ht over2 = πa 3/2 C (37) C h 2 /GM 2 mv2 + ( 2 mv2 2 = GmM ) r r 2 (38) v = h/r v 2 = h/r 2 C h 2 C = GM (39) T 2 a 3 = 4 GM (40) (a-f0a.tex) (a-f0b.tex) MV = (M m)(v + U) + m(v V 0 )
19 9 U = m M m V 0 (a-feqmo.tex) (a-fvec4.tex) d (fa) f(t + t)a(t + t) f(t)a(t) = lim t 0 t f(t + t)a(t + t) f(t + t)a(t) + f(t + t)a(t) f(t)a(t) = lim t 0 t f(t + t)(a(t + t) A(t)) + (f(t + t) f(t))a(t) = lim t 0 t + t) A(t) = lim f(t + t)a(t + lim t 0 t t 0 (4) (42) (43) f(t + t) f(t) A(t) (44) t = f(t) da + df A (45) (a-fvec.tex) m v + m 2 v 2 = (m + m 2 )v v = 3 i + 2j k
20 20 (a-fvec6.tex) v = vˆv v = v = v v a = dv = d (vˆv) = dv dˆv ˆv + v dˆv/t n a = dv v2 ˆv + R n R ( R ) ˆv ˆv = ˆv dˆv + dˆv dˆv ˆv = 2ˆv = 0 dˆv/ dˆv = lim t 0 ˆv(t + t) ˆv(t) t θ θ ( d ) θ R v t θ = v t dˆv/ = (v/r)n R v(t) v(t+) n v(t) v v(t+) d θ d θ R (a-fvec2.tex) ( ) 2 πt v = i + ( + t)j cos k π 2 a = j + (sin π ) 2 t k
21 2 t = t = 0 t = r 0 i j 4 π k 2 v i + j 2 π k i + 2j v π 2 5 a j j + k 2 mv π 2 2 a = j + k = a ˆv + ( ) a = a v/v = 2/ i + 5 j + k v 2 /R R = 5 30/6 (a-fvec3.tex) 2 r = (cos ϕ cos λ, cos ϕ sin λ, sin ϕ ) r 2 = (cos ϕ 2 cos λ 2, cos ϕ 2 sin λ 2, sin ϕ 2 ) l = Rθ R θ θ cos θ = cos ϕ cos λ cos ϕ 2 cos λ 2 + cos ϕ sin λ cos ϕ sin λ 2 + sin ϕ sin ϕ 2 = cos ϕ cos ϕ 2 cos(λ λ 2 ) + sin ϕ sin ϕ 2 (a3b.tex). dt = d ( ) 2 mv v = mv dv = v F (46) dt = d ( ) 2 mv v = mv dv = v F (47) 2. T 2 T = 2 mv 2 2 mv (48)
22 22 (z ) F ds = mgdz s = xi + yj + zk, ds = dxi + dyj + dzk, (49) 2 F = F x i + F y j + F z k = mgk, (50) z2 F ds = mg dz = mg(z 2 z ) (5) z z z 2 z F ds = 0 2 mv + mgz = 2 mv 2 + mgz 2 (52) h = z 2 = z 3 z + z 4 z z 2 z n (a3b.tex). dt = d ( ) 2 mv v = mv dv = v F (53) dt = d ( ) 2 mv v = mv dv = v F (54) 2. T 2 T = 2 mv 2 2 mv (55) (z ) F ds = mgdz s = xi + yj + zk, ds = dxi + dyj + dzk, (56) 2 F = F x i + F y j + F z k = mgk, (57) F ds = mg z2 z dz = mg(z 2 z ) (58)
23 23 z z 2 z F ds = 0 2 mv + mgz = 2 mv 2 + mgz 2 (59) h = z 2 = z 3 z + z 4 z z 2 z n (a3c.tex) m dv = GmM r 3 r v, r r = v G v ( ) ( ) d 2 mv2 = G mm r 3 v r = GmM r 3 r ds ds 2 T = mv 2 /2 T = ( ) ( ) 2 mv2 2 2 mv2 = 2 G mm r 3 r ds ( ) e r e ds = dre r + dye e r = 0 2 G mm r 3 r ds = T = 2 2 G mm r 3 r (dre r + dye ) = G mm r 2 dr = GmM 2 [ ] 2 ( = GmM ) r r 2 r ( ) 2 mv2 GmM ( ) = 2 r 2 2 mv2 GmM r U(r) = GmM r G mm r 3 rdr
24 24 (a3d.tex) U(x) = F ds = x x 0 ksds = 2 kx2 ( ) F = kx A B A B A B A C B A B C (a3e.tex) dt = ( ) d 2 m iv i v i i = ( ) dv i v i m i i () = ( ) v i G m im j r ij r 3 i ij j i (60) (6) (62) dt = Gm m 2 r2 3 v r 2 G m m 3 r3 3 v r 3... G m 2m r 3 2 G m 3m r 3 3 = (i,j) v 2 r 2 G m 2m 3 r23 3 v 2 r v 3 r 3 G m 3m 2 r32 3 v 3 r G m im j rij 3 (v i v j ) r ij (63) dv = = (i,j) (i,j) ( d G m ) imj r ij G m imj r 2 ij dr ij (64) (65)
25 25 r 2 ij = r ij r ij 2r ij dr ij = 2r ij dr ij = 2r ij (v i v j ) dv = (i,j) G m im j r 3 ij r ij (v i v j ) (66) (63) d(t + V )/ = 0 (a3f.tex) dc a z dc r dm ρ dθ dc z dm dc z = Gdm r 2 a r = Gaσdρdθ r 3 σ dm = σdxdy = σρdρdθ (ρ, θ) (x, y) r 2 = a 2 + ρ 2 rdr = ρdρ C z = 0 2πGaσ r 3 ρdρ = a 2πGaσ r 3 rdr = 2πGρ (a3h.tex) m = f4f f4f
26 26 (a4ae.tex). P P 2 F F P 2 P 2 W = P F ds = F ds P 2 (67) F W F 2. ( m) m dv = F (68) v v v 2 = v v mv dv ( ) d 2 mv2 = v F (69) = v F (70) t P t 2 P 2 t2 ( ) d t2 t 2 mv2 = v F (7) t [ ] t2 t2 2 mv2 v F (72) t t = v = ds 2 mv2 2 P 2 2 mv2 = F ds (73) P v v 2 t t 2 ( ) O R F U U R U(R) = R m (73) R O F ds (74) 2 mv2 2 O P 2 2 mv2 = F ds + F ds (75) P O P P 2 = F ds + F ds (76) O O = U(P ) U(P 2 ) (77)
27 27 2 mv2 2 + U(P 2 ) = 2 mv2 + U(P ) (78) 2 mv2 + U = (79) (a4b.tex) E = 2 v2 GmM R = 2 mv v R v ( ) m M (a) E < 0 v E = 0 v = 0 E > 0 E > 0 2GM v > R (b) E < 0 E = GmM/r max r max = GmM E = GM v 2 /2 GM/R (a4c.tex) () C = N i= Gm i ri 3 r i Ψ = C ds = N i= ( Gmi r 3 i ) r i ds Ψ = ) N i= Gm i r i (
28 28 (a4d.tex) x C = Ψ x 2 + y 2 + z 2 = r 2 C x = Gmx r 3 C x = Ψ x = Gm x 2x = 2r r x r = Gm r r 2 x C = Gm r 3 x y z = Gmr r 3 (a4e.tex) Ψ = G, r, Ψ 2 = G, r 2 Ψ(x, y, z) = Ψ + Ψ 2 (80) r 2 = (x a) 2 + y 2 + z 2 r 2 = (x + a) 2 + y 2 + z 2 { } Ψ = Gm (x a)2 + y 2 + z + 2 (x + a)2 + y 2 + z 2 (a4f.tex) r P Ψ dψ = Gdm l (8) dm l P O P z (r, θ, φ) ρ dm = ρr 2 sin θdθdφ Ψ = 2π 0 dφ π 0 ( ) dθ GρR2 sin θ l (82)
29 29 φ OP = r l 2 = r 2 + R 2 2rR cos θ θ l ldl = rr sin θdθ ( Ψ = dl 2πGρR ) r P l = r R r + R P l = R r R + r (83) ρ = M/4πR 2 P Ψ = GM r P Ψ = GM R F = Ψ = { GM r 3 r 0 (84) (85) (86) (a8a.tex) v = (l/2)ω T = 2 ( ) 2 l 2 ω 2 = ml2 ω 2 4 v = lω T = 2 (lω)2 = ml2 ω 2 2 (a8b.tex) (a8c.tex) R 2 V 2 l = mv R = mv 2 R 2 =
30 30 E = 2 mv 2 GmM R = 2 mv 2 2 GmM R 2 = x = R /R 2 V 2 = V x x V R 2 V g = 2GmM R a = V /V g a 2 = a 2 x 2 x x = (x )(a 2 x + a 2 ) = 0 x = a2 a 2 = V 2 /(2GM/R ) V 2/(2GM/R ) (a8d.tex) I = 2ma 2 I = 2mb 2 Iω = I ω ω 2ma 2 ω = 2mb 2 ω (87) ω = (a 2 /b 2 )ω (a8e.tex) I dω = F R dω = F R = ( ) I t ω = F R I t + ω 0 t = 0 ω = 0 ω 0 = 0 ω = (F R/I)t (a9a.tex)
31 3 (a9b.tex) N i= x CM = m ix i N i= mi xdm dm ( ) D y dm θ R x dm = M σ = 2M/πR 2 ( ) == D xσdxdy = D xσrdrdθ = π/2 π/2 dθ R 0 dr σr 2 cos θ = 2 3 σr3 t = sin θ x CM = 4R 3π ( ) y CM = 0 (a9c.tex) I = i m i () 2 (88) I = dm(r sin θ) 2 (89) = R dr π dθ 2π ρr 4 sin 3 θ (90) ρ = 3M/4πR 3
32 32 cos θ = µ sin θdθ = dµ I = R dr dµ 2π 0 0 ρr 4 ( µ 2 ) (9) I = 2 5 MR2 (92) (a9d.tex) R CM I (a9f.tex) I = MR 2 CM + I (93) = MR 2 + R2 + R2 2 M (94) 2 = 3R2 + R2 2 M (95) 2 (a) I 0 + mr 2 dr I 0 + m(r + dr) 2 v r = dr/ (b) (c) L = mr 2 ω (I 0 + mr 2 )ω = [I 0 + m(r + dr) 2 ](ω + dω) (96) dω = 2mωr dr I 0 + mr2 (97) dω = 2mωr I 0 + mr 2 v r (98) τ tab = I 0 dω = 2mI 0ωrv r I 0 + mr 2 (99) (τ tab + τ m = 0) τ m = d (mr2 ω) (00) = 2mrω dr dω + mr2 (0) = 2mI 0ωrv r I 0 + mr 2 (02)
2 Chapter 4 (f4a). 2. (f4cone) ( θ) () g M. 2. (f4b) T M L P a θ (f4eki) ρ H A a g. v ( ) 2. H(t) ( )
http://astr-www.kj.yamagata-u.ac.jp/~shibata f4a f4b 2 f4cone f4eki f4end 4 f5meanfp f6coin () f6a f7a f7b f7d f8a f8b f9a f9b f9c f9kep f0a f0bt version feqmo fvec4 fvec fvec6 fvec2 fvec3 f3a (-D) f3b
1 180m g 10m/s 2 2 6 1 3 v 0 (t=0) z max t max t z = z max 1 2 g(t t max) 2 (6) 1.3 2 3 3 r = (x, y, z) e x, e y, e z r = xe x + ye y + ze z. (7) v =
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A 2. x F (t) =f sin ωt x(0) = ẋ(0) = 0 ω θ sin θ θ 3! θ3 v = f mω cos ωt x = f mω (t sin ωt) ω t 0 = f ( cos ωt) mω x ma2-2 t ω x f (t mω ω (ωt ) 6 (ωt)3 = f 6m ωt3 2.2 u ( v w) = v ( w u) = w ( u v) ma22-9
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m dv = mg + kv2 dt m dv dt = mg k v v m dv dt = mg + kv2 α = mg k v = α 1 e rt 1 + e rt m dv dt = mg + kv2 dv mg + kv 2 = dt m dv α 2 + v 2 = k m dt d
m v = mg + kv m v = mg k v v m v = mg + kv α = mg k v = α e rt + e rt m v = mg + kv v mg + kv = m v α + v = k m v (v α (v + α = k m ˆ ( v α ˆ αk v = m v + α ln v α v + α = αk m t + C v α v + α = e αk m
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24.15章.微分方程式
m d y dt = F m d y = mg dt V y = dy dt d y dt = d dy dt dt = dv y dt dv y dt = g dv y dt = g dt dt dv y = g dt V y ( t) = gt + C V y ( ) = V y ( ) = C = V y t ( ) = gt V y ( t) = dy dt = gt dy = g t dt
1.1 ft t 2 ft = t 2 ft+ t = t+ t 2 1.1 d t 2 t + t 2 t 2 = lim t 0 t = lim t 0 = lim t 0 t 2 + 2t t + t 2 t 2 t + t 2 t 2t t + t 2 t 2t + t = lim t 0
A c 2008 by Kuniaki Nakamitsu 1 1.1 t 2 sin t, cos t t ft t t vt t xt t + t xt + t xt + t xt t vt = xt + t xt t t t vt xt + t xt vt = lim t 0 t lim t 0 t 0 vt = dxt ft dft dft ft + t ft = lim t 0 t 1.1
( : December 27, 2015) CONTENTS I. 1 II. 2 III. 2 IV. 3 V. 5 VI. 6 VII. 7 VIII. 9 I. 1 f(x) f (x) y = f(x) x ϕ(r) (gradient) ϕ(r) (gradϕ(r) ) ( ) ϕ(r)
( : December 27, 215 CONTENTS I. 1 II. 2 III. 2 IV. 3 V. 5 VI. 6 VII. 7 VIII. 9 I. 1 f(x f (x y f(x x ϕ(r (gradient ϕ(r (gradϕ(r ( ϕ(r r ϕ r xi + yj + zk ϕ(r ϕ(r x i + ϕ(r y j + ϕ(r z k (1.1 ϕ(r ϕ(r i
I 1
I 1 1 1.1 1. 3 m = 3 1 7 µm. cm = 1 4 km 3. 1 m = 1 1 5 cm 4. 5 cm 3 = 5 1 15 km 3 5. 1 = 36 6. 1 = 8.64 1 4 7. 1 = 3.15 1 7 1 =3 1 7 1 3 π 1. 1. 1 m + 1 cm = 1.1 m. 1 hr + 64 sec = 1 4 sec 3. 3. 1 5 kg
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http://www2.math.kyushu-u.ac.jp/~hara/lectures/lectures-j.html 1 1 1.1 ɛ-n 1 ɛ-n lim n a n = α n a n α 2 lim a n = 1 n a k n n k=1 1.1.7 ɛ-n 1.1.1 a n α a n n α lim n a n = α ɛ N(ɛ) n > N(ɛ) a n α < ɛ
sec13.dvi
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Gmech08.dvi
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1 [ 1] (1) MKS? (2) MKS? [ 2] (1) (42.195k) k 2 (2) (3) k/hr [ 3] t = 0 10 ( 1 velocity [/s] 8 4 O
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: 2014 4 10 1 2 2 3 2.1...................................... 3 2.2....................................... 4 2.3....................................... 4 2.4................................ 5 2.5 Free-Body
I.2 z x, y i z = x + iy. x, y z (real part), (imaginary part), x = Re(z), y = Im(z). () i. (2) 2 z = x + iy, z 2 = x 2 + iy 2,, z ± z 2 = (x ± x 2 ) +
I..... z 2 x, y z = x + iy (i ). 2 (x, y). 2.,,.,,. (), ( 2 ),,. II ( ).. z, w = f(z). z f(z), w. z = x + iy, f(z) 2 x, y. f(z) u(x, y), v(x, y), w = f(x + iy) = u(x, y) + iv(x, y).,. 2. z z, w w. D, D.
( ) a, b c a 2 + b 2 = c 2. 2 1 2 2 : 2 2 = p q, p, q 2q 2 = p 2. p 2 p 2 2 2 q 2 p, q (QED)
rational number p, p, (q ) q ratio 3.14 = 3 + 1 10 + 4 100 ( ) a, b c a 2 + b 2 = c 2. 2 1 2 2 : 2 2 = p q, p, q 2q 2 = p 2. p 2 p 2 2 2 q 2 p, q (QED) ( a) ( b) a > b > 0 a < nb n A A B B A A, B B A =
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: January 14, 28..,. A = (a ij ) ij m n. ( ). B m n, C n l. A = max{ a ij }. ij A + B A + B, AC n A C (1) 1. m n (A k ) k=1,... m n A, A k k, A. lim k A k = A. A k = (a (k) ij ) ij, A k = (a ij ) ij, i,
(1) D = [0, 1] [1, 2], (2x y)dxdy = D = = (2) D = [1, 2] [2, 3], (x 2 y + y 2 )dxdy = D = = (3) D = [0, 1] [ 1, 2], 1 {
![(1) D = [0, 1] [1, 2], (2x y)dxdy = D = = (2) D = [1, 2] [2, 3], (x 2 y + y 2 )dxdy = D = = (3) D = [0, 1] [ 1, 2], 1 {](/thumbs/94/118399854.jpg "(1) D = [0, 1] [1, 2], (2x y)dxdy = D = = (2) D = [1, 2] [2, 3], (x 2 y + y 2 )dxdy = D = = (3) D = [0, 1] [ 1, 2], 1 {")
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1 1 1 1 1 1 2 f z 2 C 1, C 2 f 2 C 1, C 2 f(c 2 ) C 2 f(c 1 ) z C 1 f f(z) xy uv ( u v ) = ( a b c d ) ( x y ) + ( p q ) (p + b, q + d) 1 (p + a, q + c) 1 (p, q) 1 1 (b, d) (a, c) 2 3 2 3 a = d, c = b
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1 1.1 ( ). z = a + bi, a, b R 0 a, b 0 a 2 + b 2 0 z = a + bi = ( ) a 2 + b 2 a a 2 + b + b 2 a 2 + b i 2 r = a 2 + b 2 θ cos θ = a a 2 + b 2, sin θ =
1 1.1 ( ). z = + bi,, b R 0, b 0 2 + b 2 0 z = + bi = ( ) 2 + b 2 2 + b + b 2 2 + b i 2 r = 2 + b 2 θ cos θ = 2 + b 2, sin θ = b 2 + b 2 2π z = r(cos θ + i sin θ) 1.2 (, ). 1. < 2. > 3. ±,, 1.3 ( ). A
III 1 (X, d) d U d X (X, d). 1. (X, d).. (i) d(x, y) d(z, y) d(x, z) (ii) d(x, y) d(z, w) d(x, z) + d(y, w) 2. (X, d). F X.. (1), X F, (2) F 1, F 2 F
III 1 (X, d) d U d X (X, d). 1. (X, d).. (i) d(x, y) d(z, y) d(x, z) (ii) d(x, y) d(z, w) d(x, z) + d(y, w) 2. (X, d). F X.. (1), X F, (2) F 1, F 2 F F 1 F 2 F, (3) F λ F λ F λ F. 3., A λ λ A λ. B λ λ
4 2 4.1: =, >, < π dθ = dφ = 0 3 4 K = 1/R 2 rdr + udu = 0 dr 2 + du 2 = dr 2 + r2 1 R 2 r 2 dr2 = 1 r 2 /R 2 = 1 1 Kr 2 (4.3) u iu,r ir K = 1/R 2 r R
1 4 4.1 1922 1929 1947 1965 2.726 K WMAP 2003 1. > 100Mpc 2. 10 5 3. 1. : v = ȧ(t) = Ha [ ] dr 2. : ds 2 = c 2 dt 2 a(t) 2 2 1 kr 2 + r2 (dθ 2 + sin 2 θdφ 2 ) a(t) H k = +1 k *1) k = 0 k = 1 dl 2 = dx
x A Aω ẋ ẋ 2 + ω 2 x 2 = ω 2 A 2. (ẋ, ωx) ζ ẋ + iωx ζ ζ dζ = ẍ + iωẋ = ẍ + iω(ζ iωx) dt dζ dt iωζ = ẍ + ω2 x (2.1) ζ ζ = Aωe iωt = Aω cos ωt + iaω sin
2 2.1 F (t) 2.1.1 mẍ + kx = F (t). m ẍ + ω 2 x = F (t)/m ω = k/m. 1 : (ẋ, x) x = A sin ωt, ẋ = Aω cos ωt 1 2-1 x A Aω ẋ ẋ 2 + ω 2 x 2 = ω 2 A 2. (ẋ, ωx) ζ ẋ + iωx ζ ζ dζ = ẍ + iωẋ = ẍ + iω(ζ iωx) dt dζ
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V(x) m e V 0 cos x π x π V(x) = x < π, x > π V 0 (i) x = 0 (V(x) V 0 (1 x 2 /2)) n n d 2 f dξ 2ξ d f 2 dξ + 2n f = 0 H n (ξ) (ii) H
199 1 1 199 1 1. Vx) m e V cos x π x π Vx) = x < π, x > π V i) x = Vx) V 1 x /)) n n d f dξ ξ d f dξ + n f = H n ξ) ii) H n ξ) = 1) n expξ ) dn dξ n exp ξ )) H n ξ)h m ξ) exp ξ )dξ = π n n!δ n,m x = Vx)
5.. z = f(x, y) y y = b f x x g(x) f(x, b) g x ( ) A = lim h g(a + h) g(a) h g(x) a A = g (a) = f x (a, b)............................................
5 partial differentiation (total) differentiation 5. z = f(x, y) (a, b) A = lim h f(a + h, b) f(a, b) h........................................................... ( ) f(x, y) (a, b) x A (a, b) x (a, b)
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) ] [ h m x + y + + V x) φ = Eφ 1) z E = i h t 13) x << 1) N n n= = N N + 1) 14) N n n= = N N + 1)N + 1) 6 15) N n 3 n= = 1 4 N N + 1) 16) N n 4
![) ] [ h m x + y + + V x) φ = Eφ 1) z E = i h t 13) x << 1) N n n= = N N + 1) 14) N n n= = N N + 1)N + 1) 6 15) N n 3 n= = 1 4 N N + 1) 16) N n 4](/thumbs/92/107866707.jpg ") ] [ h m x + y + + V x) φ = Eφ 1) z E = i h t 13) x << 1) N n n= = N N + 1) 14) N n n= = N N + 1)N + 1) 6 15) N n 3 n= = 1 4 N N + 1) 16) N n 4")
1. k λ ν ω T v p v g k = π λ ω = πν = π T v p = λν = ω k v g = dω dk 1) ) 3) 4). p = hk = h λ 5) E = hν = hω 6) h = h π 7) h =6.6618 1 34 J sec) hc=197.3 MeV fm = 197.3 kev pm= 197.3 ev nm = 1.97 1 3 ev
数値計算：常微分方程式
( ) 1 / 82 1 2 3 4 5 6 ( ) 2 / 82 ( ) 3 / 82 C θ l y m O x mg λ ( ) 4 / 82 θ t C J = ml 2 C mgl sin θ θ C J θ = mgl sin θ = θ ( ) 5 / 82 ω = θ J ω = mgl sin θ ω J = ml 2 θ = ω, ω = g l sin θ = θ ω ( )
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1 I 1.1 ± e = = - = C C MKSA [m], [Kg] [s] [A] 1C 1A 1 MKSA 1C 1C +q q +q q 1
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1 I 1.1 ± e = = - =1.602 10 19 C C MKA [m], [Kg] [s] [A] 1C 1A 1 MKA 1C 1C +q q +q q 1 1.1 r 1,2 q 1, q 2 r 12 2 q 1, q 2 2 F 12 = k q 1q 2 r 12 2 (1.1) k 2 k 2 ( r 1 r 2 ) ( r 2 r 1 ) q 1 q 2 (q 1 q 2
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