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3 A I (MHC-I; HLA-A, B, C H-2K, D, L ) II (MHC-II; HLA-DR, DQ, DP I-A, I-E ) CHO CHO m CHO CHO CHO B MHCI MHCII MHC-I MHC-II B (APC) T α β2 α α1, α2 α3 α β α β α1, α2, β1 β α1α2 ΙΙ α1β1 3
4 B B CD4 TCR MHC-II CD4 C CD8 m TCR MHC-I CD8 αβ α, β α β β β 4
5 5 α γ
6 N CHO B N C 1 2m MHC-I 2 3 TAP C NK KIR) CD8 A(P1) B(P2) F(P9) TCR CD8 T A C P9 P8 P7 P6 P5 P4 P3 P2 P1 N α α1, α2, α3 β β
7 7 α β γ α α α α α α α αα α β α α
8 NH or 9 -COOH A2.1 (A*0201) A2.5 (A*0205) A3.1 (A*0301) A11 (A*1101) A68 (A*6801) B7 (B*0701) B8 (B*0801) B27.1(B*2705) B35 (B*3501) B37 (B*3701) B51 (B*5101) B52 (B*5201) B53 (B*5301) M, P, S P E, S S E M, P, S P, S E P, S P M M P, S ? or or A, r R, k D L, M, i V, L, I, Q L L, I V, t P R P D, E A Q P F R, k K, R Y, F, L K, R V, i F, M, I, L V, L, I, A L Y, K K R, K L, I, a, v, m L, I K, R Y, M, L, I I, V I, L, V M: 8
9 9 γ γ α α α β α α
10 10 TAP MHC-I LMP) MHC-II 1 2 HSP-70 HSP CD4 CD4 T + MHC-II TCR Ii 2 m NK CD8 CD8 + T TCR ph CLIP? KIR MHC-I MHC-II + Ii ERp57 GP96
11 11 γ γ β β
12 12 α β α β α α β β α β β α α β α β α α α β
13 A B P-2 Pro P-1 Ly P1Tyr P2 Val P3 Ly 1- P4 Gln P 4 P5 An P6 Gln P 6 P7 Thr P 7 P8 Ly P9 Leu 1-N P 9 P11 Thr P10 Ala 1 1 TCR V CD4 T N 1- C MHC-II C 2 C V 2 CD4 αβ α β 13
14 14 α β αβ
15 15 xaxxxxxxxbx AxxBxCxxD xxaxxbxxx AxxBxCDxx AxxBxCDxx xxaxxbxcxx xxaxxbxcxx AxxBxCxxx xxaxxbxxxxc xxaxxbxxcxd xxxxaxxxxxxxxbx xxabcdexx xxxxaxxbxxxcxxx xxxxaxxbxxxcxxx L,I,V,Y Y,F L,I,V W,Y I,L,M,F,V W,F,M,Y,I F,I,L,M W Y,F F,S L,I,V,W,F M,Y,A,p,g R,K,D,E,P L,I,V,F,A M,L D,E D,M,Q,S,E W,H,R,K F,L,I,Y,W L,I,M M,V,L Q,N,L,t V,E,D R,L,I,M h,v R,K,D,E Ā,G,S - T,S,N,V T,V,N,S,R N,D,T N,S,Q R,K L,I E,D A,G,S,T C,A,P R,T,V,L,I, F,M,Y,w - L,M,A - L,Q,M,N R,W,Q,L Y,F,L,M D,E
16 16 β
17 β α α α αβ αβ β α α α β α 17
18 A CD3 T C C TCR V V CDR3 CDR1,2 1 CDR1,2 2 B 1- TCR V CDR3 N CDR1 CDR2 MHC-I TCR V CDR3 CDR2 CDR1 C 2- CHO MHC-I C N 1- CDR2 CDR1 CDR3 CDR2 TCR V MHC-II CDR1 CDR3 TCR V 1- C 18
19 19
20 20
21 21
22 22
23 23
第86回日本感染症学会総会学術集会後抄録（I）
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1 1 3 ABCD ABD AC BD E E BD 1 : 2 (1) AB = AD =, AB AD = (2) AE = AB + (3) A F AD AE 2 = AF = AB + AD AF AE = t AC = t AE AC FC = t = (4) ABD ABCD 1 1
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