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- りえ ごみぶち
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3 18 1 2,000,000 2,000, (1) 6 JCOSSAR 2007pp
4 LCC (1) (2) 2
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9 ) 2) 3) LCC LCC LCC 1
10 1) Vol.42No.5pp ) )
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13 6 7 1) 6 JCOSSAR 2007pp
14 1) 3.1 2) RC 3),4) (A) 5)(B) (A)(B) (A) (B),,,, 6
15 3.1 (B) 3.2 6) 7)14) 15) 7
16 X(t+1) t X(t) RC 9) H9 H )14) a,b,c,d,e RC MCI 16)17) 1) pp )
17 3) No pp ) No pp ) ) pp ) JCOSSAR'95 pp , ) RC Vol.47App ) RC 41 4 pp ) RC Vol.7pp ) No pp ) BMS LCC Vol.11pp ) No pp ) No pp ) Hiroshi IIZUKAA STATISTICAL STUDY ON LIFE TIME OF BRIDGESProc. of JSCENo.392-9Vol.5No.1pp.51-60April ) Vol. 63No. 1pp )
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22 A B C D E 14
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26 LCC LCC 18
27 n0,1,2,n=0 n=n N+1 X n 5 Bridge Health Index BHI MCI MCI n n X n
28 5.2.2 RC n=0,1,2, X 0,X 1, 1 2 n-1 X n-1 =i X n-1 X n-1 =i n X n =j p ij p ij n-1 X n-1 =i 20
29 p ij =P(X n =j X n-1 =i),i,js (5.2.1) i j p ij K n-1 n KK i i j
30 n X n =i n=0 n=n' n' X n' =i p in' =P[X n' =i] i K n' K p(n)=p 1n,p 2n,,p Kn n n+1 X n+1 =i n X n i n+1 X n+1 j p ij =P(X n+1 =j X n =i),i,js (5.2.3) 22
31 n+1 X n+1 =j n X n =i p in n X n =i n+1 X n+1 =j p ij p in jn+1 =P(X n =i)p(x n+1 =j X n =i)=p in p ij (5.2.4) p jn+1=p(x n+1 =j)=p in p ij (5.2.5) p 1n+1,p 2n+1,,p Kn+1 = (5.2.6) P(n+1)=p(n)P (5.2.7) n P(n+1)=p(n)P=[p(n-1)P}P ==p(0)[p} n+1 (5.2.8) p(0) P P n X n =i m j p (m) ij p (m) ij i j m p (m) ij (5.2.9) P (m) m m P (m) P m = P (m-1) P= P (m-2) P (2) == PP (m-1) (5.2.10) Chapman-Kolmogorov Chapman-Kolmogorov (5.2.11) 23
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34 D X Z T = C RC C RC C C C C RC C 1 N ( i = 1, L, N )i J X i = ( X i1, L, X ij) X ij j T = 0 i K S Y i( S) = ( Yi 1( S), L, YiK( S)) Yik ( S) k 26
35 M Z = ( Z 1, L, Z ) Z im m i i im X = ( X 1, L, X ) Z = ( Z 1, L, Z ) i i ij i i im ii ( = 1, K, N) ρ i α ( ) ρ = exp X α + Z β, i = 1, K, N (5.3.1) i i i = ( α1, L, α J ) J = ( 1, L, M ) M β β β N i T T T T (Right Censoring)
36 N T = ( T %, L, 1 T % N) i c i c= ( c1, L, c N ) i T i c i T % i i = 1, L, N if, T% if, T% i i > c i c i (5.3.2) T = 0 c i T = 0 T% i( ci ) Ti = min{ T% i, ci} (5.3.3) i D i D i = 1{ T i = T% i } (5.3.4) i D i 1 if, Ti = T% i( lifetime) = 0 if, Ti = ci( Censoring) (5.3.5) i t λ() t 28
37 Pr( t Ti < t+ t t Ti) λ() t = lim t 0 t (5.3.6) dlog S( t) / dt i T i t St () St () = Pr( t< T i ) (5.3.7) Ft () = 1 St () f () t f () t = ds() t / dt dlog S( t) ds( t) / dt f( t) λ() t = = = (5.3.8) dt S() t S() t f () t = λ() t S() t Λ() t t () t λ( u) du Λ = (5.3.9) 0 St ( ) = exp( Λ ( t)) (5.3.10) v( < t) (Truncation) v Sv () St ()/ Sv ( ), f () t / S( v) f () t / S( v) f() t λ() t = = St ()/ Sv ( ) St () (5.3.11) i T % i f ( T% i) = λ( T% i)exp{ Λ( T% i)} (5.3.12) c i D i = 1Ti = T% i T i f ( T) = λ( T)exp{ Λ ( T)} (5.3.13) i i i D i = 0 T i = c i c i ST ( ) = exp{ Λ ( T)} (5.3.14) i D i = 1 D i = 0 i i = 1, L, N i D l = λ( T) i exp{ Λ( T)} (5.3.15) i i i i 29
38 N N Di L= λ( Ti) exp{ Λ( Ti)} (5.3.16) i= 1 λ() t St () u τ MRL( u) Mean Residual Life MRL( u) = E( τ u u < τ ) (5.3.17) τ u τ τ u u ( t u) f( t) dt u E( τ u u< τ) = (5.3.18) Su ( ) f () t = ds() t / dt [ t ust] ( St ( )) ( t u) f( t) dt = ( t u) [ ds( t) / dt] dt (5.3.19) u u = ( ) ( ) u dt ( t ust ) () ( t ust ) () Stdt () u t t= u u = + (5.3.20) = Stdt () (5.3.21) u t St () u () u MRL( u) = Stdt (5.3.22) Su ( ) t t λ() t t St () 30
39 ρ > 0, t 0 t λ() t ρ t St () exp ( ρt) t λ() t θ θ, ρ > 0,t ρ t t St () ρ θ t θ κ, ρ > 0, t 0 t λ() t ρ exp( κ t) t St () ρ exp 1 exp t κ { ( κ )} 31
40 κ, ρ > 0, t 0 t λ() t κρt 1+ ρt κ 1 κ t St () 1 1+ ρt κ 32
41 κ, ρ > 0, t 0 t λ() t t St () κρ 1 t κ exp ( ρt κ ) T Weibull( ρ, κ) ρ > κ > 0 t 0 λ() t ρκ 1 = t κ (5.3.23) κ > 1 κ = 1 κ < 1 33
42 Λ () t = ρt κ (5.3.24) St ( ) = exp{ Λ ( t)} = exp{ ρt κ } (5.3.25) T κ q q/ κ q ET [ ] = ρ Γ (1 + q/ κ) ET = ρ Γ + / κ (5.3.26) 1/ κ [ ] (1 1 ) Var[ T ] = ρ Γ (1 + 2 / κ) Γ (1 + 1 / κ) (5.3.27) 2/ κ 2 c > 0 T Weibull( ρ, κ ) ct Weibull( ρc κ, κ) T c Weibull( ρ, κ/ c) M Weibull( ρ, κ ) min{ T, L, T M } Weibull( M ρ, κ ) (minimum 1 stable) N 1 D κ i κ L= ρκti ρt i i= 1 exp{ } (5.3.28) N i= 1 log L Dilog( ) Di( 1) logti T κ = ρκ + κ ρ i (5.3.29) κ ρ 34
43 ( 8 t 3.98 ) St ( ) = exp (25%-quantile) (75%-quantile) Su ( ) = exp{ ρu κ } κ exp{ ρt } dt u MRL( u) = (5.3.30) κ exp{ ρu } κ IMRL ( u, ρκ, ) = exp{ ρt } dtκ > 0 y = ρt κ 1 κ dt = t dy/ ( ρκ ) ρ > 0, κ > 0 t y( = ρt κ ) t 1 κ 1 1 / κ 1 / κ 1 u 1 κ (,, ) exp{ } t IMRL u ρκ = y dy (5.3.31) κ ρu ρκ = ρ y 11 / κ (,, ) ρ exp{ } 1/ κ 1 IMRL u ρκ = y y dy κ ρκ (5.3.32) ρu Γ ( ν, z) 1 ( z) exp{ w} w ν ν dw ( ν 0 z 0) z Γ, =, >, > (5.3.33) (,, ) ρ 1 IMRL u ρκ = Γ, u (5.3.34) 1/ κ κ ρ κ κ 35
44 MRL( u) = ρ 1 / 1 κ κ Γ, ρu κ κ κ exp( ρu ) (5.3.35) u = 0 1/ κ ρ 1 0 Γ, / 1 κ κ κ ρ 1 MRL(0) = = Γ, 0 (5.3.36) exp(0) κ κ MRL(0) u 36
45 Y i n Y i µ i µ i > 0 x i k xi = ( xi 1,..., x ik) x i Y i y exp( µ ) i i µ i Pr( Yi = yi µ i) = µ i > 0, yi = 0,1, 2,... (5.4.1) y! i i µ i k µ = exp( x β ) (5.4.2) i β k i 37
46 [ ] =, [ ] E y x µ i i i Var y x = µ (5.4.3) i i i n n y exp( µ ) i i µ i L = (5.4.4) y! i= 1 n µ i y i n n y exp( µ ) i i µ i log L = log i= 1 yi! n i [ µ i yilog( µ i) log( yi!) ] [ exp( x iβ) yix iβ log( yi!) ] (5.4.5) = + = + i= 1 i= 1 n β ˆβ [ ] ˆ E y x = exp( x β ), i = 1,..., n (5.4.6) i i i [ x ] E y i x ij i = ˆ β exp( x ˆ β), i= 1,..., n; j = 1,..., k j i (5.4.7) 38
47 (5.4.6) j x ij 39
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49 1) , 1998, 20035, 4, 45, 4, 5 4, 4, OK 5, 4, 3, 2, 1 2) 3) i(i=1,,k) S={1,,K} t (t)=i t+1 RC (t+1)=j Pr ob [ ( t + 1) = j( t) = i] = (5.5.1) ij π11 π1k Π = M O M (5.5.2) 0 π KK K j = 1 π = 1 ij RC ς f ς ) F ς ) i i RC i y i+1 λ i ( y i ) y i i ( i i F ~ ( ) i y i i ( i i 41
50 f ( ~ ) i yi yi λ i( yi ) yi = (5.5.3) Fi ( yi) λ i ( y i ) y i i [ y i, y i + y i ] i+1 RC y i θi > 0( i = 1,, K) λ i( yi ) = θi (5.5.4) RC i y F ~ ( ) i i y i ~ F ( y ) = exp( y ) (5.5.5) i i θ i i τ A i y A i y A ~ z ( 0) i F ( y + z ζ y ) ~ F ( y + z ζ y ) i A i i i A i A i i A = Pr ob{ ζ y + z ζ y } (5.5.6) i A i i F ~ ( ) A i y i ~ Fi ( ya + zi) exp{ θ i( ya + zi)} ~ = = exp( θ izi) (5.5.7) Fi ( ya) exp{ θ i ya} y A i y i ω Pr ob[ ( y ) i ( y ) = i] = exp( Z) B ω A θ = (5.5.8) i = y Z B A + Z Pr ob[ ω( y ) = iω( y ) i] B A = π ii π ii θ i Z y A, yb 2) y A y B i j π π = Pr ob[ h( y ) = j h( y ) i] ij B A = ii j m = K = i m= i θ θ θ k 1 j 1 m θm exp( θ kz) θ θ k m= k m+ 1 k (5.5.9) 42
51 K 1 π ik = 1 π ij (5.5.10) j = i π ik
52 5.5.4 H0n =0 n H1n0 t- 1 t t-t t->t n A n305% t )
53 ) 4.62%
54 t
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56 t- 48
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58 CLEN
59 CWID
60 HIRW
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70 y = 0.020x R² = y = 0.002x R² = 9E mm mm 62
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72 812mm 0.7mm 1mm 2mm
73 good good 65
74 66
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87 good BIC good good BIC good
88 good BIC good good BIC good
89 good BIC good good BIC good BIC BIC BIC
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92 yi y% i =, i= 1,..., n Median( y,..., y ) 1 YDAN 0.12 n
93 YDEP LEVEL µ Dan i Dan µ = exp( β + x β ), i= 1,..., n i L 0 i 1 x L i β 0 β 1 85
94 β 0 β 1 exp( ) = 8.20 µ Pit i µ = exp( β + x β + x β ), i= 1,..., n Pit L Dan i 0 i 1 i 2 x Dan i β 2 x L i β 0 β 1 β 0 β 1 β 2 exp( ) =
95 m -8m -5m -3m -2.5m -1.7m -1m 0m 1.1m 1.8m 1m 1m m -8m -5m -3m -2.5m -1.7m -1m 0m 1.1m 1.8m 6(24mm^2) 20 (80mm^2 ) 87
96 24mm^ mm^2-1m mm^2 88
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123 LCC LCC LCC LCC 1 115
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