<4D F736F F D20362E325F96D491968CCE82CC97AC93AE90858EBF93C190AB E646F63>

Size: px
Start display at page:

Download "<4D F736F F D20362E325F96D491968CCE82CC97AC93AE90858EBF93C190AB E646F63>"

Transcription

1

2

3 m 5m m 5m.6m/s 4 (m) (m)

4 (m) / 7 () 995/5 7 5 () 995/8 7 8 () 995/ 7 () () (mg/l) () () (g/m 3 )

5 4 998 () () () 997 () (m) COD(mg/l) (mg/l) (mg/l)

6 N : a (5.m) (7.m) :3.4m :4.m () () :6.m b (m).7m

7

8 4 (m) (m)

9 (m) 3 4 : : : 3: 4: 8/8 5:446:35() 8/8 :44:5 () 8/8 :3() 8/9 :58() ( m ) m / a(mg/l)

10 (m) 4 (m) 4 6 (min) 6

11

12 行政(網走開発建設部)学識者6. 網走湖の水理 水質特性 () 解析技術 ) モデル検討の背景と目的網走湖では 水質障害となっている青潮 アオコを抑制するための対策手法を検討するため 流動予測 水質予測に関する各種シミュレーション解析を 行政 ( 網走開発建設部 ) 学識者の協同のもとに行っている 昭和 6 年に青潮が初めて確認されたことを受けて 青潮の発生機構を検討する調査検討が実施され 平成元年に青潮の発生条件を検討するための青潮モデルを構築した また 湖内は富栄養化状態にありアオコが毎年のように発生している現状を受けて 湖内の水質汚濁機構を把握する調査検討が実施され 水質保全対策による湖内水質の改善効果を検討するための水質予測モデルを平成 5 年に構築した ( 水理 水質を分けて計算 ) その後 網走湖における富栄養化状態は 流域からの栄養塩類の負荷 塩水層および淡水層の流動 栄養塩類の拡散 3 底泥溶出による栄養塩の供給 4 栄養塩類を使って増殖するプランクトンの消長などにより形成されていることから 水理 水質 生物に関わる要因が複雑に関係している状況をつのモデルで再現し アオコ発生を抑制するための水質保全対策の効果を検討することを目的とした網走湖生態系モデルを平成 3 年度に構築した 流動予測 水質予測 塩淡境界層の長期予測 塩淡境界層制御対策検討 青潮の発生条件検討 水質改善対策検討 塩淡境界層予測長期モデル 塩水遡上モデル 平面 次元レイヤーモデル 宗宮モデル改 平面 次元レベルモデル 水質予測ホ ックスモテ ル 青潮モデル 網走湖生態系モデル 長期界面変動予測 一般座標系による密度流シミュレーション アオコ発生シミュレーション 青潮発生シミュレーション 図 6..4 水質シミュレーションモデル選定の経緯とその考え方 ( 概要 ) 6-4

13

14 ( ) ( ) [ ] [ ] τ τ ζ x, x, H a a a y M x M A x H x H x gh wu wu u N y u M x t M = = ( ) ( ) [ ] [ ] τ τ ζ y, y, H a a a y N x N A y H y H y gh wv wv v N y v M x t N = = = = w y N x N t w w y N x M τ ( ) ( ) ( ) [ ] [ ] z z H z K z K y H y x H x K w w N y M x M t = ( ) ( ) ( ) [ ] [ ] z z H z C K z C K y C H y x C H x K wc wc C N y C M x C M t =

15 τ s τ τ b = γ a = γ = γ a b ( W U ) ( U U ) U KMAX U W U U KMAX U t g x, y,z u,v,w x, y,z M ζ H,N x, y,z ( z ) x, y C A K K γ γ H s a b H z - W,U

16 w z y x H C Q z T K z y T K y x T K x z T w y T v x T u t T = x K y K z K Q w C ( ) ( ) ), ( S d S T c T c c S T b T b T b T b b T S W = = b = c = b 4.7 = c = b = c = b = b = d T a T a T a T a T a a W = = a = a = a = a = a = a

17 µ m µ m Q J / m / hr Q S = S Q η z S = Qe Q Q Q η z Q = ( )Q β in Q = ( α) Q α β Q in

18 Q LR J / m / hr 4 QLR = εσt K ε T K σ 7 4 =.4 J / m / hr / K J / m / hr 5 6 Q LA =.937 σt ( R) T R J / m / hr Q LAC = (.7n ) Q LA n J / m / s QW = acw CHU ( Ta Ts ) U T a s C H C H (. ~.) 3 m / s < U 5m / s C H (. ~.3) 3 5 m / s < U < 3m / s J / m / s Q = ι C U ( q ϕq) E a p s C ϕ q p.6( e / p) q.378( e / p) 7.5t /(37.3 t ) e = ι.45 J / g Q Q = Q Q Q Q Q S ( LR LAC W E )

19 H, M,u, N,v x dir y dir w, τ

20

21 P = P P P3 dp / dt = G T G Z / P d P Q P Q P ( p z ) ( )/ V ( G p T Gz Z / P d ) P ( Q P Q P) / V ( G 3 T G Z / P3 d 3) P3 ( Q P3 Q P3) V dp / dt = dp3 / dt = p 3 z / dz dc ( α G T ) Z ( Q Z Q Z ) V dt = α / s z 3 / in dc on / dt = / dt = { ( G pi ηni i T ) β pi Pi} i=,3 { ζ n β pi ( as ) Gz Z} i=,3 β θ z in n ω exp 3 T Z Dc. n [ RV in UGin RN in { γ T γ DO} A] / V ( Q C Q C )/ V in indo { ( G pi ηni i T ) β pi Pi} i=,3 { ζ n β pi ( as ) Gz Z} i=,3 in β z θ n 3 T Z Dc. n [ RV on UGon RN on ω on exp{ γ ont γ ondodo} A] / V d ( Con β z Z ) ( Q C Q C )/ V on on in

22 ( ) { } ( ) { } [ { } ] ( ) V C Q C Q C d V A DO T RN UG RV D Z T Z G a Pi T i G dt dc ip ip ip ip ipdo ip ip ip ip ip p c p z i z s pi p i pi pi pi ip / / exp /. 3,3,3 = = = γ γ ω θ γ γ ζ γ η ( ) { } ( ) { } [ { } ] ( ) ( ) V C Q C Q Z C d V A DO T RN UG RV D Z T Z G a Pi T i G dt dc op op z op opdo op op op op op p c P z i z s pi p i pi Pi Pi op / / exp /. 3,3,3 = = = γ γ γ ω θ γ γ ζ γ η { } ( ) { } [ { } ] ( ) V C Q C Q V A DO T UG RV D Z G a Pi T i dt dc sc sc scdo sc sc sc sc c c i z s Pi c i Pi ci sc / / exp /.,3,3 = = = γ γ ω δ ζ δ η ( ) { } [ ] ( ) ( ) { } ( ) ( ) ( ) ( ) V C Q C Q Z C d V UG RV D Z T K Z G a Pi T i G dt dc pc pc z pc pc pc c c i c z i z s pi i c i pi ii ci pi pc / / / 3,3,3 = = = δ θ θ δ δ ζ ζ δ η η

23 ddo / dt = { γ pdo Gpi Pi} i=,3 { T γ pdo Pi} i=,3 T γ 3 C C SC PC BD A B B max zdo OSC OPC exp Z exp exp ( Howa DO) { β SC ( T TBOSC )} { β ( T T )} { β ( T T )} BD PC BDO BOPC M M COD BDCOD γ pdo γ zdo BOSC BOPC BDmax β SC β PC β BD TBOSC T BOPC T BD M COD M BDCOD

24 G p G p G p3 n T T G p = µ exp T f T f L / L C / C C C { } { ( )} { ( )} ( ) L in in in ip / ip n T T G p = µ exp T f T f L / L C / C C C { } { ( )} { ( )} ( ) L in in in ip / ip ip ip n3 T T G p3 = µ 3 exp T f 3 T f 3 L / L C / C C C { } { ( )} { ( )} ( ) L3 in in3 in ip / ip3 G z Gz = cg pp P /( pp P) D c. n D c. p c c D. ip D D D c. n c. p c. c = = = f f f n c p exp exp exp { ( T ) } ( C β P β Z ) n { ( T ) } ( C γ P γ Z ) { ( T ) } ( C δ P δ Z ) c p on op pc p p p z z z

25 / α as

26

27

28

29 5 (m 3 /s) (m) 4/8 /8 5/ 3/

30 dh f A f = Q fin Q fout Q finb dt A S dh dt S = Q sin Q sout Q 3 Q = a(g b) tanh (c c d) H Qfin :Q=QfinbQsin :Q=QfoutQsout hf Qfout B D h h A Q Qfin hf Qfout :Q=QfinbQsin :Q=QfoutQsout Qsout Qsout=Q (:) Q hs Qsout hs

31 Q sout Q out Q sout Q = r Q, Q = ( -r) Q, r = γ exp( CE h ) sout out fout out f

32 = v v A gh = c v v a,v a v a = g h = g h h v a Q = v A v A a f a s A

33 5 5 (a) (m 3 /s) 5 5 (b) (m 3 /s) (m) (m 3 /s).5 () 994 () ( (m 3 /s) (m) (m 3 /s).5 (m 3 /s) () 995 () ( (m)

34

35 m :45: 4.5m/s 7 9 ::4 7: :356:38 (m) :74: :383:3 m 5 mg/l 4 6 m/s ( ) (m) 5 5 m

36

37 N N N N 5.(cm/s) 5.(cm/s) 5.(cm/s) 5.(cm/s) (m) (m) (m) (m) (a).m (b) 4.m (c) 6.m (d) 8.m m (m) 5 5 (cm/s) (m) 4 5m 4: 3:5 :45 m (b) (a) (c) m (m) 5 5 () () 9:3 9:5 :3 :5 :39 :5 5 4: 5m (a) 5 (m) 4:47 5: :3 :5 :9 m (m) 5 b c (m)

38 N N N N 5.(cm/s) 5.(cm/s) 5.(cm/s) 5.(cm/s) (m) (m) (m) (m) (a).m (b) 4.m (c) 6.m (d) 8.m m (m) 5 5 (cm/s) 4 (m) 5m : : :5 :3 m (b) 5 (a) (c) m (m) 5 5 () () 9:44 :5 : 5 9:3 5m m (m) (a) 5 (m) 9:44 : :4 :8 :3 b c (m)

39 N N N N 5.(cm/s) 5.(cm/s) 5.(cm/s) 5.(cm/s) (m) (m) (m) (m) (a).m (b) 4.m (c) 6.m (d) 8.m (b) (a) (c) 5m m 5m m (m) 6:3 7: 7:3 5 (m) :4 :6 : 9:55 9:3 9:7 m (m) m (m) (m) 7:33 7:33 7:33 7:33 7:5 8: (cm/s) 5 b 5 (a) c (m)

40 N N N N.(cm/s).(cm/s).(cm/s).(cm/s) (m) (m) (m) (m) (a).m (b) 4.m (c) 5.5m (d) 8.m ( ) ( ) (cm/s) (m) 8 9 (m)

41

42

43 .8m/s (m) (m) m ( ) m 8 ( ) (cm/s)

44

45 () () () () (a) (b) () () (c) (d)

46 ( (997//89 9:) 8 9:) (/8 89:) 9:) ((/9 95:) 5:) ( ) 35 (cm) (cm) (cm) (a) (b)

47 L h h T i = n ghh n TL h h

48

49

50

51 (m) (m) (m) (m) (T.P.) (m) (h) (h) /4/8 4 8 : 996/4/9 4 : 996/4/ 4 : 996/4/8 4 8 : 996/4/9 4 : 996/4/ 4 : : : : 3: 4: 5: 6: 7: 8: 9: 3: 4: 5: 6: 7: 8: 9: (m/s) 996/4/ 4 996/4/ 4 (cm/s) : : : (m) (m) : : : 3: 4: 5: 6: 7: 8: 9: : 3: 4: 5: 6: 7: 8: 9: : : 996/4/ 4 996/4/ 4 (T.P.) (m) (.m) (5.m) (h) (h) /8/7 8 : 996/8/8 8 : 997/8/9 8 : 996/8/7 8 : 996/8/8 8 : 997/8/9 8 : : : 3: : : : 3: 4: 5: 6: : 3: : : : 3: 4: 5: 6: 7: 996/8/ /8/ /8/ /8/8 8 (m/s) (m/s) : : 3: : : : 3: 4: 5: 6: : 3: : : : 3: 4: 5: 6: 7: 996/8/ /8/ /8/ /8/8 8 (.m) (5.m) (T.P.) (m) (m) (m) (T.P.) (m)

52 (m ) (m ) (m) 3 4 : : : 3: 4:

53 (: ) (.5m) (.5m) () () 4 4 H(= ) (cm) ()

54 (m ) 5 5 (mg/l).5 (m) 5.5 (m) (m) (m) (m )

55 cm //5 m m cm/s m 5 5 m m 997//5 H9//5 5:46:3 cm/s m 997//5 H9//5 6:337: cm/s 5 5 m cm/s 5 5 m

56 (m ) 5 5 (mg/l) (m) 5.5 (m) 4 8 (m)

57 (m 3 /s) /9 8/7 (m) 4 8 (m)

58 (m 3 /s) / AB ()() A B

59 Power spectrum m 4m 5m 6m 7m 8m 9m T= T= 8 T ( ) (cm/s) () 5cm 3cm / : 4/3 : 4/5 : 4/7 : (h)

60 z (v) a h u h u L x u t u t ξ = g x h τ o ξ = g x η x ξ h t η h t u x u x = η = t

61 τ = C D av ξ ξ τ gh = t x t x gh = gh t x ξ x gh ξ = x τ x gh = gh x ξ x ξ =, = x x τ L ξ = x, gh η = ξ

62

63 ( ) ( ) [ ] [ ] x, x, M fn y M x M A x H x H x gh wu wu U N y U M y t M = = τ τ ζ α α α ( ) ( ) [ ] [ ] y, y, N fm y N x N A y H y H y gh wv wv V N y V M x t N = = τ τ ζ α α α w w y N x M = w y N x M t = ζ ( ) ( ) ( ) [ ] [ ] Z Z H z K z K y H y x H x K w w N y M x H t =

64 (m)

65 (m/s) W 6 8 (hour) 4: t t3 t4 t5 t t6 t7 N E S

66 m/s (m) (m/s)

67

68

69

70

71

72

73

74

75

76

77

78

79

80

Microsoft Word - 11問題表紙(選択).docx

Microsoft Word - 11問題表紙(選択).docx A B A.70g/cm 3 B.74g/cm 3 B C 70at% %A C B at% 80at% %B 350 C γ δ y=00 x-y ρ l S ρ C p k C p ρ C p T ρ l t l S S ξ S t = ( k T ) ξ ( ) S = ( k T) ( ) t y ξ S ξ / t S v T T / t = v T / y 00 x v S dy dx

More information

pdf

pdf http://www.ns.kogakuin.ac.jp/~ft13389/lecture/physics1a2b/ pdf I 1 1 1.1 ( ) 1. 30 m µm 2. 20 cm km 3. 10 m 2 cm 2 4. 5 cm 3 km 3 5. 1 6. 1 7. 1 1.2 ( ) 1. 1 m + 10 cm 2. 1 hr + 6400 sec 3. 3.0 10 5 kg

More information

64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () m/s : : a) b) kg/m kg/m k

64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () m/s : : a) b) kg/m kg/m k 63 3 Section 3.1 g 3.1 3.1: : 64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () 3 9.8 m/s 2 3.2 3.2: : a) b) 5 15 4 1 1. 1 3 14. 1 3 kg/m 3 2 3.3 1 3 5.8 1 3 kg/m 3 3 2.65 1 3 kg/m 3 4 6 m 3.1. 65 5

More information

医系の統計入門第 2 版 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 第 2 版 1 刷発行時のものです.

医系の統計入門第 2 版 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます.   このサンプルページの内容は, 第 2 版 1 刷発行時のものです. 医系の統計入門第 2 版 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. http://www.morikita.co.jp/books/mid/009192 このサンプルページの内容は, 第 2 版 1 刷発行時のものです. i 2 t 1. 2. 3 2 3. 6 4. 7 5. n 2 ν 6. 2 7. 2003 ii 2 2013 10 iii 1987

More information

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0 1 1 1.1 1.) T D = T = D = kn 1. 1.4) F W = F = W/ = kn/ = 15 kn 1. 1.9) R = W 1 + W = 6 + 5 = 11 N. 1.9) W b W 1 a = a = W /W 1 )b = 5/6) = 5 cm 1.4 AB AC P 1, P x, y x, y y x 1.4.) P sin 6 + P 1 sin 45

More information

1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2

1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2 2005 9/8-11 2 2.2 ( 2-5) γ ( ) γ cos θ 2πr πρhr 2 g h = 2γ cos θ ρgr (2.1) γ = ρgrh (2.2) 2 cos θ θ cos θ = 1 (2.2) γ = 1 ρgrh (2.) 2 2. p p ρgh p ( ) p p = p ρgh (2.) h p p = 2γ r 1 1 (Berry,1975) 2-6

More information

Note.tex 2008/09/19( )

Note.tex 2008/09/19( ) 1 20 9 19 2 1 5 1.1........................ 5 1.2............................. 8 2 9 2.1............................. 9 2.2.............................. 10 3 13 3.1.............................. 13 3.2..................................

More information

30

30 3 ............................................2 2...........................................2....................................2.2...................................2.3..............................

More information

Microsoft Word - 3.1_3.2章_0802.doc

Microsoft Word - 3.1_3.2章_0802.doc 3.1 湖沼に対する負荷の内訳 第 3 章湖沼水質に影響を及ぼす負荷の把握 湖沼水質に影響を与える負荷には 外部負荷 内部負荷及び直接負荷がある 最近の調査研究では面源負荷 ( 外部負荷の一部 ) の寄与がこれまでの見積もりより大きいことが指摘されている また これにより 湖沼の水質改善を推進するためには 流入負荷対策と合わせて これまで湖沼内に蓄積してきた底泥からの溶出負荷 ( 内部負荷の一部 )

More information

05Mar2001_tune.dvi

05Mar2001_tune.dvi 2001 3 5 COD 1 1.1 u d2 u + ku =0 (1) dt2 u = a exp(pt) (2) p = ± k (3) k>0k = ω 2 exp(±iωt) (4) k

More information

LLG-R8.Nisus.pdf

LLG-R8.Nisus.pdf d M d t = γ M H + α M d M d t M γ [ 1/ ( Oe sec) ] α γ γ = gµ B h g g µ B h / π γ g = γ = 1.76 10 [ 7 1/ ( Oe sec) ] α α = λ γ λ λ λ α γ α α H α = γ H ω ω H α α H K K H K / M 1 1 > 0 α 1 M > 0 γ α γ =

More information

I II III IV V

I II III IV V I II III IV V N/m 2 640 980 50 200 290 440 2m 50 4m 100 100 150 200 290 390 590 150 340 4m 6m 8m 100 170 250 µ = E FRVβ β N/mm 2 N/mm 2 1.1 F c t.1 3 1 1.1 1.1 2 2 2 2 F F b F s F c F t F b F s 3 3 3

More information

Z: Q: R: C: sin 6 5 ζ a, b

Z: Q: R: C: sin 6 5 ζ a, b Z: Q: R: C: 3 3 7 4 sin 6 5 ζ 9 6 6............................... 6............................... 6.3......................... 4 7 6 8 8 9 3 33 a, b a bc c b a a b 5 3 5 3 5 5 3 a a a a p > p p p, 3,

More information

NETES No.CG V

NETES No.CG V 1 2006 6 NETES No.CG-050001-V 2007 5 2 1 2 1 19 5 1 2 19 8 2 i 1 1 1.1 1 1.2 2 1.3 2 2 3 2.1 3 2.2 8 3 9 3.1 9 3.2 10 3.3 13 3.3.1 13 3.3.2 14 3.3.3 14 3.3.4 16 3.3.5 17 3.3.6 18 3.3.7 21 3.3.8 22 3.4

More information

D = [a, b] [c, d] D ij P ij (ξ ij, η ij ) f S(f,, {P ij }) S(f,, {P ij }) = = k m i=1 j=1 m n f(ξ ij, η ij )(x i x i 1 )(y j y j 1 ) = i=1 j

D = [a, b] [c, d] D ij P ij (ξ ij, η ij ) f S(f,, {P ij }) S(f,, {P ij }) = = k m i=1 j=1 m n f(ξ ij, η ij )(x i x i 1 )(y j y j 1 ) = i=1 j 6 6.. [, b] [, d] ij P ij ξ ij, η ij f Sf,, {P ij } Sf,, {P ij } k m i j m fξ ij, η ij i i j j i j i m i j k i i j j m i i j j k i i j j kb d {P ij } lim Sf,, {P ij} kb d f, k [, b] [, d] f, d kb d 6..

More information

untitled

untitled ( ) c a sin b c b c a cos a c b c a tan b a b cos sin a c b c a ccos b csin (4) Ma k Mg a (Gal) g(98gal) (Gal) a max (K-E) kh Zck.85.6. 4 Ma g a k a g k D τ f c + σ tanφ σ 3 3 /A τ f3 S S τ A σ /A σ /A

More information

支持力計算法.PDF

支持力計算法.PDF . (a) P P P P P P () P P P P (0) P P Hotω H P P δ ω H δ P P (a) ( ) () H P P n0(k P 4.7) (a)0 0 H n(k P 4.76) P P n0(k P 5.08) n0(k P.4) () 0 0 (0 ) n(k P 7.56) H P P n0(k P.7) n(k P.7) H P P n(k P 5.4)

More information

微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 初版 1 刷発行時のものです.

微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます.   このサンプルページの内容は, 初版 1 刷発行時のものです. 微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. ttp://www.morikita.co.jp/books/mid/00571 このサンプルページの内容は, 初版 1 刷発行時のものです. i ii 014 10 iii [note] 1 3 iv 4 5 3 6 4 x 0 sin x x 1 5 6 z = f(x, y) 1 y = f(x)

More information

63 3.2,.,.,. (2.6.38a), (2.6.38b), V + V V + Φ + fk V = 0 (3.2.1)., Φ = gh, f.,. (2.6.40), Φ + V Φ + Φ V = 0 (3.2.2). T = L/C (3.2.3), C. C V, T = L/V

63 3.2,.,.,. (2.6.38a), (2.6.38b), V + V V + Φ + fk V = 0 (3.2.1)., Φ = gh, f.,. (2.6.40), Φ + V Φ + Φ V = 0 (3.2.2). T = L/C (3.2.3), C. C V, T = L/V 62 3 3.1,,.,. J. Charney, 1948., Burger(1958) Phillips(1963),.,. L : ( 1/4) T : ( 1/4) V :,. v x u x V L, etc, u V T,,.,., ( )., 2.1.1. 63 3.2,.,.,. (2.6.38a), (2.6.38b), V + V V + Φ + fk V = 0 (3.2.1).,

More information

(Compton Scattering) Beaming 1 exp [i (k x ωt)] k λ k = 2π/λ ω = 2πν k = ω/c k x ωt ( ω ) k α c, k k x ωt η αβ k α x β diag( + ++) x β = (ct, x) O O x

(Compton Scattering) Beaming 1 exp [i (k x ωt)] k λ k = 2π/λ ω = 2πν k = ω/c k x ωt ( ω ) k α c, k k x ωt η αβ k α x β diag( + ++) x β = (ct, x) O O x Compton Scattering Beaming exp [i k x ωt] k λ k π/λ ω πν k ω/c k x ωt ω k α c, k k x ωt η αβ k α x β diag + ++ x β ct, x O O x O O v k α k α β, γ k γ k βk, k γ k + βk k γ k k, k γ k + βk 3 k k 4 k 3 k

More information

untitled

untitled PGF 17 6 1 11 1 12 1 2 21 2 22 2 23 3 1 3 1 3 2 3 3 3 4 3 5 4 6 4 2 4 1 4 2 4 3 4 4 4 5 5 3 5 1 5 2 5 5 5 5 4 5 1 5 2 5 3 6 5 6 1 6 2 6 6 6 24 7 1 7 1 7 2 7 3 7 4 8 2 8 1 8 2 8 3 9 4 9 5 9 6 9 3 9 1 9

More information

II ( ) (7/31) II ( [ (3.4)] Navier Stokes [ (6/29)] Navier Stokes 3 [ (6/19)] Re

II ( ) (7/31) II (  [ (3.4)] Navier Stokes [ (6/29)] Navier Stokes 3 [ (6/19)] Re II 29 7 29-7-27 ( ) (7/31) II (http://www.damp.tottori-u.ac.jp/~ooshida/edu/fluid/) [ (3.4)] Navier Stokes [ (6/29)] Navier Stokes 3 [ (6/19)] Reynolds [ (4.6), (45.8)] [ p.186] Navier Stokes I Euler Navier

More information

τ τ

τ τ 1 1 1.1 1.1.1 τ τ 2 1 1.1.2 1.1 1.1 µ ν M φ ν end ξ µ ν end ψ ψ = µ + ν end φ ν = 1 2 (µφ + ν end) ξ = ν (µ + ν end ) + 1 1.1 3 6.18 a b 1.2 a b 1.1.3 1.1.3.1 f R{A f } A f 1 B R{AB f 1 } COOH A OH B 1.3

More information

(yx4) 1887-1945 741936 50 1995 1 31 http://kenboushoten.web.fc.com/ OCR TeX 50 yx4 e-mail: yx4.aydx5@gmail.com i Jacobi 1751 1 3 Euler Fagnano 187 9 0 Abel iii 1 1...................................

More information

grad φ(p ) φ P grad φ(p ) p P p φ P p l t φ l t = 0 g (0) g (0) (31) grad φ(p ) p grad φ φ (P, φ(p )) xy (x, y) = (ξ(t), η(t)) ( )

grad φ(p ) φ P grad φ(p ) p P p φ P p l t φ l t = 0 g (0) g (0) (31) grad φ(p ) p grad φ φ (P, φ(p )) xy (x, y) = (ξ(t), η(t)) ( ) 2 9 2 5 2.2.3 grad φ(p ) φ P grad φ(p ) p P p φ P p l t φ l t = g () g () (3) grad φ(p ) p grad φ φ (P, φ(p )) y (, y) = (ξ(t), η(t)) ( ) ξ (t) (t) := η (t) grad f(ξ(t), η(t)) (t) g(t) := f(ξ(t), η(t))

More information

2016 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 1 16 2 1 () X O 3 (O1) X O, O (O2) O O (O3) O O O X (X, O) O X X (O1), (O2), (O3) (O2) (O3) n (O2) U 1,..., U n O U k O k=1 (O3) U λ O( λ Λ) λ Λ U λ O 0 X 0 (O2) n =

More information

量子力学 問題

量子力学 問題 3 : 203 : 0. H = 0 0 2 6 0 () = 6, 2 = 2, 3 = 3 3 H 6 2 3 ϵ,2,3 (2) ψ = (, 2, 3 ) ψ Hψ H (3) P i = i i P P 2 = P 2 P 3 = P 3 P = O, P 2 i = P i (4) P + P 2 + P 3 = E 3 (5) i ϵ ip i H 0 0 (6) R = 0 0 [H,

More information

Part () () Γ Part ,

Part () () Γ Part , Contents a 6 6 6 6 6 6 6 7 7. 8.. 8.. 8.3. 8 Part. 9. 9.. 9.. 3. 3.. 3.. 3 4. 5 4.. 5 4.. 9 4.3. 3 Part. 6 5. () 6 5.. () 7 5.. 9 5.3. Γ 3 6. 3 6.. 3 6.. 3 6.3. 33 Part 3. 34 7. 34 7.. 34 7.. 34 8. 35

More information

2 1 κ c(t) = (x(t), y(t)) ( ) det(c (t), c x (t)) = det (t) x (t) y (t) y = x (t)y (t) x (t)y (t), (t) c (t) = (x (t)) 2 + (y (t)) 2. c (t) =

2 1 κ c(t) = (x(t), y(t)) ( ) det(c (t), c x (t)) = det (t) x (t) y (t) y = x (t)y (t) x (t)y (t), (t) c (t) = (x (t)) 2 + (y (t)) 2. c (t) = 1 1 1.1 I R 1.1.1 c : I R 2 (i) c C (ii) t I c (t) (0, 0) c (t) c(i) c c(t) 1.1.2 (1) (2) (3) (1) r > 0 c : R R 2 : t (r cos t, r sin t) (2) C f : I R c : I R 2 : t (t, f(t)) (3) y = x c : R R 2 : t (t,

More information

( ) 2002 1 1 1 1.1....................................... 1 1.1.1................................. 1 1.1.2................................. 1 1.1.3................... 3 1.1.4......................................

More information

(5) 75 (a) (b) ( 1 ) v ( 1 ) E E 1 v (a) ( 1 ) x E E (b) (a) (b)

(5) 75 (a) (b) ( 1 ) v ( 1 ) E E 1 v (a) ( 1 ) x E E (b) (a) (b) (5) 74 Re, bondar laer (Prandtl) Re z ω z = x (5) 75 (a) (b) ( 1 ) v ( 1 ) E E 1 v (a) ( 1 ) x E E (b) (a) (b) (5) 76 l V x ) 1/ 1 ( 1 1 1 δ δ = x Re x p V x t V l l (1-1) 1/ 1 δ δ δ δ = x Re p V x t V

More information

( ) ( )

( ) ( ) 20 21 2 8 1 2 2 3 21 3 22 3 23 4 24 5 25 5 26 6 27 8 28 ( ) 9 3 10 31 10 32 ( ) 12 4 13 41 0 13 42 14 43 0 15 44 17 5 18 6 18 1 1 2 2 1 2 1 0 2 0 3 0 4 0 2 2 21 t (x(t) y(t)) 2 x(t) y(t) γ(t) (x(t) y(t))

More information

KENZOU

KENZOU KENZOU 2008 8 2 3 2 3 2 2 4 2 4............................................... 2 4.2............................... 3 4.2........................................... 4 4.3..............................

More information

基礎数学I

基礎数学I I & II ii ii........... 22................. 25 12............... 28.................. 28.................... 31............. 32.................. 34 3 1 9.................... 1....................... 1............

More information

,,,,., = (),, (1) (4) :,,,, (1),. (2),, =. (3),,. (4),,,,.. (1) (3), (4).,,., () : = , ( ) : = F 1 + F 2 + F 3 + ( ) : = i Fj j=1 2

,,,,., = (),, (1) (4) :,,,, (1),. (2),, =. (3),,. (4),,,,.. (1) (3), (4).,,., () : = , ( ) : = F 1 + F 2 + F 3 + ( ) : = i Fj j=1 2 6 2 6.1 2 2, 2 5.2 R 2, 2 (R 2, B, µ)., R 2,,., 1, 2, 3,., 1, 2, 3,,. () : = 1 + 2 + 3 + (6.1.1).,,, 1 ,,,,., = (),, (1) (4) :,,,, (1),. (2),, =. (3),,. (4),,,,.. (1) (3), (4).,,., () : = 1 + 2 + 3 +,

More information

Microsoft Word - 章末問題

Microsoft Word - 章末問題 1906 R n m 1 = =1 1 R R= 8h ICP s p s HeNeArXe 1 ns 1 1 1 1 1 17 NaCl 1.3 nm 10nm 3s CuAuAg NaCl CaF - - HeNeAr 1.7(b) 2 2 2d = a + a = 2a d = 2a 2 1 1 N = 8 + 6 = 4 8 2 4 4 2a 3 4 π N πr 3 3 4 ρ = = =

More information

A 2 3. m S m = {x R m+1 x = 1} U + k = {x S m x k > 0}, U k = {x S m x k < 0}, ϕ ± k (x) = (x 0,..., ˆx k,... x m ) 1. {(U ± k, ϕ± k ) 0 k m} S m 1.2.

A 2 3. m S m = {x R m+1 x = 1} U + k = {x S m x k > 0}, U k = {x S m x k < 0}, ϕ ± k (x) = (x 0,..., ˆx k,... x m ) 1. {(U ± k, ϕ± k ) 0 k m} S m 1.2. A A 1 A 5 A 6 1 2 3 4 5 6 7 1 1.1 1.1 (). Hausdorff M R m M M {U α } U α R m E α ϕ α : U α E α U α U β = ϕ α (ϕ β ϕβ (U α U β )) 1 : ϕ β (U α U β ) ϕ α (U α U β ) C M a m dim M a U α ϕ α {x i, 1 i m} {U,

More information

Γ Ec Γ V BIAS THBV3_0401JA THBV3_0402JAa THBV3_0402JAb 1000 800 600 400 50 % 25 % 200 100 80 60 40 20 10 8 6 4 10 % 2.5 % 0.5 % 0.25 % 2 1.0 0.8 0.6 0.4 0.2 0.1 200 300 400 500 600 700 800 1000 1200 14001600

More information

K E N Z U 2012 7 16 HP M. 1 1 4 1.1 3.......................... 4 1.2................................... 4 1.2.1..................................... 4 1.2.2.................................... 5................................

More information

φ 4 Minimal subtraction scheme 2-loop ε 2008 (University of Tokyo) (Atsuo Kuniba) version 21/Apr/ Formulas Γ( n + ɛ) = ( 1)n (1 n! ɛ + ψ(n + 1)

φ 4 Minimal subtraction scheme 2-loop ε 2008 (University of Tokyo) (Atsuo Kuniba) version 21/Apr/ Formulas Γ( n + ɛ) = ( 1)n (1 n! ɛ + ψ(n + 1) φ 4 Minimal subtraction scheme 2-loop ε 28 University of Tokyo Atsuo Kuniba version 2/Apr/28 Formulas Γ n + ɛ = n n! ɛ + ψn + + Oɛ n =,, 2, ψn + = + 2 + + γ, 2 n ψ = γ =.5772... Euler const, log + ax x

More information

Z: Q: R: C:

Z: Q: R: C: 0 Z: Q: R: C: 3 4 4 4................................ 4 4.................................. 7 5 3 5...................... 3 5......................... 40 5.3 snz) z)........................... 4 6 46 x

More information

1

1 GL (a) (b) Ph l P N P h l l Ph Ph Ph Ph l l l l P Ph l P N h l P l .9 αl B βlt D E. 5.5 L r..8 e g s e,e l l W l s l g W W s g l l W W e s g e s g r e l ( s ) l ( l s ) r e l ( s ) l ( l s ) e R e r

More information

18 I ( ) (1) I-1,I-2,I-3 (2) (3) I-1 ( ) (100 ) θ ϕ θ ϕ m m l l θ ϕ θ ϕ 2 g (1) (2) 0 (3) θ ϕ (4) (3) θ(t) = A 1 cos(ω 1 t + α 1 ) + A 2 cos(ω 2 t + α

18 I ( ) (1) I-1,I-2,I-3 (2) (3) I-1 ( ) (100 ) θ ϕ θ ϕ m m l l θ ϕ θ ϕ 2 g (1) (2) 0 (3) θ ϕ (4) (3) θ(t) = A 1 cos(ω 1 t + α 1 ) + A 2 cos(ω 2 t + α 18 I ( ) (1) I-1,I-2,I-3 (2) (3) I-1 ( ) (100 ) θ ϕ θ ϕ m m l l θ ϕ θ ϕ 2 g (1) (2) 0 (3) θ ϕ (4) (3) θ(t) = A 1 cos(ω 1 t + α 1 ) + A 2 cos(ω 2 t + α 2 ), ϕ(t) = B 1 cos(ω 1 t + α 1 ) + B 2 cos(ω 2 t

More information

2 1 x 2 x 2 = RT 3πηaN A t (1.2) R/N A N A N A = N A m n(z) = n exp ( ) m gz k B T (1.3) z n z = m = m ρgv k B = erg K 1 R =

2 1 x 2 x 2 = RT 3πηaN A t (1.2) R/N A N A N A = N A m n(z) = n exp ( ) m gz k B T (1.3) z n z = m = m ρgv k B = erg K 1 R = 1 1 1.1 1827 *1 195 *2 x 2 t x 2 = 2Dt D RT D = RT N A 1 6πaη (1.1) D N A a η 198 *3 ( a =.212µ) *1 Robert Brown (1773-1858. *2 Albert Einstein (1879-1955 *3 Jean Baptiste Perrin (187-1942 2 1 x 2 x 2

More information

The Physics of Atmospheres CAPTER :

The Physics of Atmospheres CAPTER : The Physics of Atmospheres CAPTER 4 1 4 2 41 : 2 42 14 43 17 44 25 45 27 46 3 47 31 48 32 49 34 41 35 411 36 maintex 23/11/28 The Physics of Atmospheres CAPTER 4 2 4 41 : 2 1 σ 2 (21) (22) k I = I exp(

More information

(e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ,µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) [ ] [ ] [ ] ν e ν µ ν τ e µ τ, e R,µ R,τ R (2.1a

(e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ,µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) [ ] [ ] [ ] ν e ν µ ν τ e µ τ, e R,µ R,τ R (2.1a 1 2 2.1 (e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ,µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) [ ] [ ] [ ] ν e ν µ ν τ e µ τ, e R,µ R,τ R (2.1a) L ( ) ) * 2) W Z 1/2 ( - ) d u + e + ν e 1 1 0 0

More information

( ) Note (e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ, µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) 3 * 2) [ ] [ ] [ ] ν e ν µ ν τ e

( ) Note (e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ, µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) 3 * 2) [ ] [ ] [ ] ν e ν µ ν τ e ( ) Note 3 19 12 13 8 8.1 (e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ, µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) 3 * 2) [ ] [ ] [ ] ν e ν µ ν τ e µ τ, e R, µ R, τ R (1a) L ( ) ) * 3) W Z 1/2 ( - )

More information

dvipsj.8449.dvi

dvipsj.8449.dvi 9 1 9 9.1 9 2 (1) 9.1 9.2 σ a = σ Y FS σ a : σ Y : σ b = M I c = M W FS : M : I : c : = σ b

More information

Untitled

Untitled II 14 14-7-8 8/4 II (http://www.damp.tottori-u.ac.jp/~ooshida/edu/fluid/) [ (3.4)] Navier Stokes [ 6/ ] Navier Stokes 3 [ ] Reynolds [ (4.6), (45.8)] [ p.186] Navier Stokes I 1 balance law t (ρv i )+ j

More information

II A A441 : October 02, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka )

II A A441 : October 02, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka ) II 214-1 : October 2, 214 Version : 1.1 Kawahira, Tomoki TA (Kondo, Hirotaka ) http://www.math.nagoya-u.ac.jp/~kawahira/courses/14w-biseki.html pdf 1 2 1 9 1 16 1 23 1 3 11 6 11 13 11 2 11 27 12 4 12 11

More information

( ) ,

( ) , II 2007 4 0. 0 1 0 2 ( ) 0 3 1 2 3 4, - 5 6 7 1 1 1 1 1) 2) 3) 4) ( ) () H 2.79 10 10 He 2.72 10 9 C 1.01 10 7 N 3.13 10 6 O 2.38 10 7 Ne 3.44 10 6 Mg 1.076 10 6 Si 1 10 6 S 5.15 10 5 Ar 1.01 10 5 Fe 9.00

More information

Untitled

Untitled http://www.ike-dyn.ritsumei.ac.jp/ hyoo/dynamics.html 1 (i) (ii) 2 (i) (ii) (*) [1] 2 1 3 1.1................................ 3 1.2..................................... 3 2 4 2.1....................................

More information

2 ID POS 1... 1 2... 2 2.1 ID POS... 2 2.2... 3 3... 5 3.1... 5 3.2... 6 3.2.1... 6 3.2.2... 7 3.3... 7 3.3.1... 7 3.3.2... 8 3.3.3... 8 3.4... 9 4... 11 4.1... 11 4.2... 15 4.3... 27 5... 35... 36...

More information

128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds = 0 (3.4) S 1, S 2 { B( r) n( r)}ds

128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds = 0 (3.4) S 1, S 2 { B( r) n( r)}ds 127 3 II 3.1 3.1.1 Φ(t) ϕ em = dφ dt (3.1) B( r) Φ = { B( r) n( r)}ds (3.2) S S n( r) Φ 128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds

More information

keisoku01.dvi

keisoku01.dvi 2.,, Mon, 2006, 401, SAGA, JAPAN Dept. of Mechanical Engineering, Saga Univ., JAPAN 4 Mon, 2006, 401, SAGA, JAPAN Dept. of Mechanical Engineering, Saga Univ., JAPAN 5 Mon, 2006, 401, SAGA, JAPAN Dept.

More information

, 1.,,,.,., (Lin, 1955).,.,.,.,. f, 2,. main.tex 2011/08/13( )

, 1.,,,.,., (Lin, 1955).,.,.,.,. f, 2,. main.tex 2011/08/13( ) 81 4 2 4.1, 1.,,,.,., (Lin, 1955).,.,.,.,. f, 2,. 82 4.2. ζ t + V (ζ + βy) = 0 (4.2.1), V = 0 (4.2.2). (4.2.1), (3.3.66) R 1 Φ / Z, Γ., F 1 ( 3.2 ). 7,., ( )., (4.2.1) 500 hpa., 500 hpa (4.2.1) 1949,.,

More information

I A A441 : April 21, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka ) Google

I A A441 : April 21, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka ) Google I4 - : April, 4 Version :. Kwhir, Tomoki TA (Kondo, Hirotk) Google http://www.mth.ngoy-u.c.jp/~kwhir/courses/4s-biseki.html pdf 4 4 4 4 8 e 5 5 9 etc. 5 6 6 6 9 n etc. 6 6 6 3 6 3 7 7 etc 7 4 7 7 8 5 59

More information

: , 2.0, 3.0, 2.0, (%) ( 2.

: , 2.0, 3.0, 2.0, (%) ( 2. 2017 1 2 1.1...................................... 2 1.2......................................... 4 1.3........................................... 10 1.4................................. 14 1.5..........................................

More information

dynamics-solution2.dvi

dynamics-solution2.dvi 1 1. (1) a + b = i +3i + k () a b =5i 5j +3k (3) a b =1 (4) a b = 7i j +1k. a = 14 l =/ 14, m=1/ 14, n=3/ 14 3. 4. 5. df (t) d [a(t)e(t)] =ti +9t j +4k, = d a(t) d[a(t)e(t)] e(t)+ da(t) d f (t) =i +18tj

More information

21 2 26 i 1 1 1.1............................ 1 1.2............................ 3 2 9 2.1................... 9 2.2.......... 9 2.3................... 11 2.4....................... 12 3 15 3.1..........

More information

n (1.6) i j=1 1 n a ij x j = b i (1.7) (1.7) (1.4) (1.5) (1.4) (1.7) u, v, w ε x, ε y, ε x, γ yz, γ zx, γ xy (1.8) ε x = u x ε y = v y ε z = w z γ yz

n (1.6) i j=1 1 n a ij x j = b i (1.7) (1.7) (1.4) (1.5) (1.4) (1.7) u, v, w ε x, ε y, ε x, γ yz, γ zx, γ xy (1.8) ε x = u x ε y = v y ε z = w z γ yz 1 2 (a 1, a 2, a n ) (b 1, b 2, b n ) A (1.1) A = a 1 b 1 + a 2 b 2 + + a n b n (1.1) n A = a i b i (1.2) i=1 n i 1 n i=1 a i b i n i=1 A = a i b i (1.3) (1.3) (1.3) (1.1) (ummation convention) a 11 x

More information

4 5.............................................. 5............................................ 6.............................................. 7......................................... 8.3.................................................4.........................................4..............................................4................................................4.3...............................................

More information

1990 IMO 1990/1/15 1:00-4:00 1 N N N 1, N 1 N 2, N 2 N 3 N 3 2 x x + 52 = 3 x x , A, B, C 3,, A B, C 2,,,, 7, A, B, C

1990 IMO 1990/1/15 1:00-4:00 1 N N N 1, N 1 N 2, N 2 N 3 N 3 2 x x + 52 = 3 x x , A, B, C 3,, A B, C 2,,,, 7, A, B, C 0 9 (1990 1999 ) 10 (2000 ) 1900 1994 1995 1999 2 SAT ACT 1 1990 IMO 1990/1/15 1:00-4:00 1 N 1990 9 N N 1, N 1 N 2, N 2 N 3 N 3 2 x 2 + 25x + 52 = 3 x 2 + 25x + 80 3 2, 3 0 4 A, B, C 3,, A B, C 2,,,, 7,

More information

2.1: n = N/V ( ) k F = ( 3π 2 N ) 1/3 = ( 3π 2 n ) 1/3 V (2.5) [ ] a = h2 2m k2 F h2 2ma (1 27 ) (1 8 ) erg, (2.6) /k B 1 11 / K

2.1: n = N/V ( ) k F = ( 3π 2 N ) 1/3 = ( 3π 2 n ) 1/3 V (2.5) [ ] a = h2 2m k2 F h2 2ma (1 27 ) (1 8 ) erg, (2.6) /k B 1 11 / K 2 2.1? [ ] L 1 ε(p) = 1 ( p 2 2m x + p 2 y + pz) 2 = h2 ( k 2 2m x + ky 2 + kz) 2 n x, n y, n z (2.1) (2.2) p = hk = h 2π L (n x, n y, n z ) (2.3) n k p 1 i (ε i ε i+1 )1 1 g = 2S + 1 2 1/2 g = 2 ( p F

More information

meiji_resume_1.PDF

meiji_resume_1.PDF β β β (q 1,q,..., q n ; p 1, p,..., p n ) H(q 1,q,..., q n ; p 1, p,..., p n ) Hψ = εψ ε k = k +1/ ε k = k(k 1) (x, y, z; p x, p y, p z ) (r; p r ), (θ; p θ ), (ϕ; p ϕ ) ε k = 1/ k p i dq i E total = E

More information

研修コーナー

研修コーナー l l l l l l l l l l l α α β l µ l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l

More information

I A A441 : April 15, 2013 Version : 1.1 I Kawahira, Tomoki TA (Shigehiro, Yoshida )

I A A441 : April 15, 2013 Version : 1.1 I   Kawahira, Tomoki TA (Shigehiro, Yoshida ) I013 00-1 : April 15, 013 Version : 1.1 I Kawahira, Tomoki TA (Shigehiro, Yoshida) http://www.math.nagoya-u.ac.jp/~kawahira/courses/13s-tenbou.html pdf * 4 15 4 5 13 e πi = 1 5 0 5 7 3 4 6 3 6 10 6 17

More information

n ξ n,i, i = 1,, n S n ξ n,i n 0 R 1,.. σ 1 σ i .10.14.15 0 1 0 1 1 3.14 3.18 3.19 3.14 3.14,. ii 1 1 1.1..................................... 1 1............................... 3 1.3.........................

More information

総研大恒星進化概要.dvi

総研大恒星進化概要.dvi The Structure and Evolution of Stars I. Basic Equations. M r r =4πr2 ρ () P r = GM rρ. r 2 (2) r: M r : P and ρ: G: M r Lagrange r = M r 4πr 2 rho ( ) P = GM r M r 4πr. 4 (2 ) s(ρ, P ) s(ρ, P ) r L r T

More information

6 2 T γ T B (6.4) (6.1) [( d nm + 3 ] 2 nt B )a 3 + nt B da 3 = 0 (6.9) na 3 = T B V 3/2 = T B V γ 1 = const. or T B a 2 = const. (6.10) H 2 = 8π kc2

6 2 T γ T B (6.4) (6.1) [( d nm + 3 ] 2 nt B )a 3 + nt B da 3 = 0 (6.9) na 3 = T B V 3/2 = T B V γ 1 = const. or T B a 2 = const. (6.10) H 2 = 8π kc2 1 6 6.1 (??) (P = ρ rad /3) ρ rad T 4 d(ρv ) + PdV = 0 (6.1) dρ rad ρ rad + 4 da a = 0 (6.2) dt T + da a = 0 T 1 a (6.3) ( ) n ρ m = n (m + 12 ) m v2 = n (m + 32 ) T, P = nt (6.4) (6.1) d [(nm + 32 ] )a

More information

Gmech08.dvi

Gmech08.dvi 51 5 5.1 5.1.1 P r P z θ P P P z e r e, z ) r, θ, ) 5.1 z r e θ,, z r, θ, = r sin θ cos = r sin θ sin 5.1) e θ e z = r cos θ r, θ, 5.1: 0 r

More information

Sgr.A 2 saida@daido-it.a.jp Sgr.A 1 3 1.1 2............................................. 3 1.2.............................. 4 2 1 6 2.1................................. 6 2.2...................................

More information

x () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x

x () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x [ ] IC. f(x) = e x () f(x) f (x) () lim f(x) lim f(x) x + x (3) lim f(x) lim f(x) x + x (4) y = f(x) ( ) ( s46). < a < () a () lim a log xdx a log xdx ( ) n (3) lim log k log n n n k=.3 z = log(x + y ),

More information

4 Mindlin -Reissner 4 δ T T T εσdω= δ ubdω+ δ utd Γ Ω Ω Γ T εσ (1.1) ε σ u b t 3 σ ε. u T T T = = = { σx σ y σ z τxy τ yz τzx} { εx εy εz γ xy γ yz γ

4 Mindlin -Reissner 4 δ T T T εσdω= δ ubdω+ δ utd Γ Ω Ω Γ T εσ (1.1) ε σ u b t 3 σ ε. u T T T = = = { σx σ y σ z τxy τ yz τzx} { εx εy εz γ xy γ yz γ Mindlin -Rissnr δ εσd δ ubd+ δ utd Γ Γ εσ (.) ε σ u b t σ ε. u { σ σ σ z τ τ z τz} { ε ε εz γ γ z γ z} { u u uz} { b b bz} b t { t t tz}. ε u u u u z u u u z u u z ε + + + (.) z z z (.) u u NU (.) N U

More information

2009 2 26 1 3 1.1.................................................. 3 1.2..................................................... 3 1.3...................................................... 3 1.4.....................................................

More information

2 Chapter 4 (f4a). 2. (f4cone) ( θ) () g M. 2. (f4b) T M L P a θ (f4eki) ρ H A a g. v ( ) 2. H(t) ( )

2 Chapter 4 (f4a). 2. (f4cone) ( θ) () g M. 2. (f4b) T M L P a θ (f4eki) ρ H A a g. v ( ) 2. H(t) ( ) http://astr-www.kj.yamagata-u.ac.jp/~shibata f4a f4b 2 f4cone f4eki f4end 4 f5meanfp f6coin () f6a f7a f7b f7d f8a f8b f9a f9b f9c f9kep f0a f0bt version feqmo fvec4 fvec fvec6 fvec2 fvec3 f3a (-D) f3b

More information

July 28, H H 0 H int = H H 0 H int = H int (x)d 3 x Schrödinger Picture Ψ(t) S =e iht Ψ H O S Heisenberg Picture Ψ H O H (t) =e iht O S e i

July 28, H H 0 H int = H H 0 H int = H int (x)d 3 x Schrödinger Picture Ψ(t) S =e iht Ψ H O S Heisenberg Picture Ψ H O H (t) =e iht O S e i July 8, 4. H H H int H H H int H int (x)d 3 x Schrödinger Picture Ψ(t) S e iht Ψ H O S Heisenberg Picture Ψ H O H (t) e iht O S e iht Interaction Picture Ψ(t) D e iht Ψ(t) S O D (t) e iht O S e ih t (Dirac

More information

( ) ) AGD 2) 7) 1

( ) ) AGD 2) 7) 1 ( 9 5 6 ) ) AGD ) 7) S. ψ (r, t) ψ(r, t) (r, t) Ĥ ψ(r, t) = e iĥt/ħ ψ(r, )e iĥt/ħ ˆn(r, t) = ψ (r, t)ψ(r, t) () : ψ(r, t)ψ (r, t) ψ (r, t)ψ(r, t) = δ(r r ) () ψ(r, t)ψ(r, t) ψ(r, t)ψ(r, t) = (3) ψ (r,

More information

淀川水系流域委員会第 71 回委員会 (H20.1 審議参考資料 1-2 河川管理者提供資料

淀川水系流域委員会第 71 回委員会 (H20.1 審議参考資料 1-2 河川管理者提供資料 淀川水系流域委員会第 71 回委員会 (H2.1 審議参考資料 1-2 河川管理者提供資料 -4- -5- -6- -7- -8- -9- -1- -11- 45 197 1 7 1967 19761977 7 69 H19.12.27 1-2-2P.93 34 1975 1977 1976 1967 1975 1-12- 1967 19761977 2-13- 別紙 -159-23-

More information

( ; ) C. H. Scholz, The Mechanics of Earthquakes and Faulting : - ( ) σ = σ t sin 2π(r a) λ dσ d(r a) =

( ; ) C. H. Scholz, The Mechanics of Earthquakes and Faulting : - ( ) σ = σ t sin 2π(r a) λ dσ d(r a) = 1 9 8 1 1 1 ; 1 11 16 C. H. Scholz, The Mechanics of Earthquakes and Faulting 1. 1.1 1.1.1 : - σ = σ t sin πr a λ dσ dr a = E a = π λ σ πr a t cos λ 1 r a/λ 1 cos 1 E: σ t = Eλ πa a λ E/π γ : λ/ 3 γ =

More information

4. ϵ(ν, T ) = c 4 u(ν, T ) ϵ(ν, T ) T ν π4 Planck dx = 0 e x 1 15 U(T ) x 3 U(T ) = σt 4 Stefan-Boltzmann σ 2π5 k 4 15c 2 h 3 = W m 2 K 4 5.

4. ϵ(ν, T ) = c 4 u(ν, T ) ϵ(ν, T ) T ν π4 Planck dx = 0 e x 1 15 U(T ) x 3 U(T ) = σt 4 Stefan-Boltzmann σ 2π5 k 4 15c 2 h 3 = W m 2 K 4 5. A 1. Boltzmann Planck u(ν, T )dν = 8πh ν 3 c 3 kt 1 dν h 6.63 10 34 J s Planck k 1.38 10 23 J K 1 Boltzmann u(ν, T ) T ν e hν c = 3 10 8 m s 1 2. Planck λ = c/ν Rayleigh-Jeans u(ν, T )dν = 8πν2 kt dν c

More information

f(x) = f(x ) + α(x)(x x ) α(x) x = x. x = f (y), x = f (y ) y = f f (y) = f f (y ) + α(f (y))(f (y) f (y )) f (y) = f (y ) + α(f (y)) (y y ) ( (2) ) f

f(x) = f(x ) + α(x)(x x ) α(x) x = x. x = f (y), x = f (y ) y = f f (y) = f f (y ) + α(f (y))(f (y) f (y )) f (y) = f (y ) + α(f (y)) (y y ) ( (2) ) f 22 A 3,4 No.3 () (2) (3) (4), (5) (6) (7) (8) () n x = (x,, x n ), = (,, n ), x = ( (x i i ) 2 ) /2 f(x) R n f(x) = f() + i α i (x ) i + o( x ) α,, α n g(x) = o( x )) lim x g(x) x = y = f() + i α i(x )

More information

201711grade1ouyou.pdf

201711grade1ouyou.pdf 2017 11 26 1 2 52 3 12 13 22 23 32 33 42 3 5 3 4 90 5 6 A 1 2 Web Web 3 4 1 2... 5 6 7 7 44 8 9 1 2 3 1 p p >2 2 A 1 2 0.6 0.4 0.52... (a) 0.6 0.4...... B 1 2 0.8-0.2 0.52..... (b) 0.6 0.52.... 1 A B 2

More information

t = h x z z = h z = t (x, z) (v x (x, z, t), v z (x, z, t)) ρ v x x + v z z = 0 (1) 2-2. (v x, v z ) φ(x, z, t) v x = φ x, v z

t = h x z z = h z = t (x, z) (v x (x, z, t), v z (x, z, t)) ρ v x x + v z z = 0 (1) 2-2. (v x, v z ) φ(x, z, t) v x = φ x, v z I 1 m 2 l k 2 x = 0 x 1 x 1 2 x 2 g x x 2 x 1 m k m 1-1. L x 1, x 2, ẋ 1, ẋ 2 ẋ 1 x = 0 1-2. 2 Q = x 1 + x 2 2 q = x 2 x 1 l L Q, q, Q, q M = 2m µ = m 2 1-3. Q q 1-4. 2 x 2 = h 1 x 1 t = 0 2 1 t x 1 (t)

More information

untitled

untitled V. 8 9 9 8.. SI 5 6 7 8 9. - - SI 6 6 6 6 6 6 6 SI -- l -- 6 -- -- 6 6 u 6cod5 6 h5 -oo ch 79 79 85 875 99 79 58 886 9 89 9 959 966 - - NM /6 Nucl Ml SI NM/6/685 85co /./ /h / /6/.6 / /.6 /h o NM o.85

More information

31 gh gw

31 gh gw 30 31 gh gw 32 33 1406 1421 640 0 (mm) (mm) MAX1513 MIN349 MIN280 MAX900 gh gw 34 gh gh gw gw gh gh gw gw gh gh gw gw 35 175 176 177 178 179 180 181 195 196 197 198 202 203 2 1 L L L2 L2 L2 L 2 2 1 L L

More information

untitled

untitled - k k k = y. k = ky. y du dx = ε ux ( ) ux ( ) = ax+ b x u() = ; u( ) = AE u() = b= u () = a= ; a= d x du ε x = = = dx dx N = σ da = E ε da = EA ε A x A x x - σ x σ x = Eε x N = EAε x = EA = N = EA k =

More information

液晶の物理1:連続体理論(弾性,粘性)

液晶の物理1:連続体理論(弾性,粘性) The Physics of Liquid Crystals P. G. de Gennes and J. Prost (Oxford University Press, 1993) Liquid crystals are beautiful and mysterious; I am fond of them for both reasons. My hope is that some readers

More information

TOP URL 1

TOP URL   1 TOP URL http://amonphys.web.fc.com/ 3.............................. 3.............................. 4.3 4................... 5.4........................ 6.5........................ 8.6...........................7

More information