snkp-14-2/ky347084220200019175
|
|
- さやな ごちょう
- 5 years ago
- Views:
Transcription
1
2
3
4
5 β β
6 α
7 α
8
9
10
11
12 ββ
13
14
15
16
17 α
18
19
20
21
1 911 9001030 9:00 A B C D E F G H I J K L M 1A0900 1B0900 1C0900 1D0900 1E0900 1F0900 1G0900 1H0900 1I0900 1J0900 1K0900 1L0900 1M0900 9:15 1A0915 1B0915 1C0915 1D0915 1E0915 1F0915 1G0915 1H0915 1I0915
研修コーナー
l l l l l l l l l l l α α β l µ l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l
_0212_68<5A66><4EBA><79D1>_<6821><4E86><FF08><30C8><30F3><30DC><306A><3057><FF09>.pdf
平成20年5月 協会創立50年の歩み 海の安全と環境保全を目指して 友國八郎 海上保安庁 長官 岩崎貞二 日本船主協会 会長 前川弘幸 JF全国漁業協同組合連合会 代表理事会長 服部郁弘 日本船長協会 会長 森本靖之 日本船舶機関士協会 会長 大内博文 航海訓練所 練習船船長 竹本孝弘 第二管区海上保安本部長 梅田宜弘
第86回日本感染症学会総会学術集会後抄録(I)
κ κ κ κ κ κ μ μ β β β γ α α β β γ α β α α α γ α β β γ μ β β μ μ α ββ β β β β β β β β β β β β β β β β β β γ β μ μ μ μμ μ μ μ μ β β μ μ μ μ μ μ μ μ μ μ μ μ μ μ β
O1-1 O1-2 O1-3 O1-4 O1-5 O1-6
O1-1 O1-2 O1-3 O1-4 O1-5 O1-6 O1-7 O1-8 O1-9 O1-10 O1-11 O1-12 O1-13 O1-14 O1-15 O1-16 O1-17 O1-18 O1-19 O1-20 O1-21 O1-22 O1-23 O1-24 O1-25 O1-26 O1-27 O1-28 O1-29 O1-30 O1-31 O1-32 O1-33 O1-34 O1-35
( )
) ( ( ) 3 15m t / 1.9 3 m t / 0.64 3 m ( ) ( ) 3 15m 3 1.9m / t 0.64m 3 / t ) ( β1 β 2 β 3 y ( ) = αx1 X 2 X 3 ( ) ) ( ( ) 3 15m t / 1.9 3 m 3 90m t / 0.64 3 m ( ) : r : ) 30 ( 10 0.0164
> > <., vs. > x 2 x y = ax 2 + bx + c y = 0 2 ax 2 + bx + c = 0 y = 0 x ( x ) y = ax 2 + bx + c D = b 2 4ac (1) D > 0 x (2) D = 0 x (3
13 2 13.0 2 ( ) ( ) 2 13.1 ( ) ax 2 + bx + c > 0 ( a, b, c ) ( ) 275 > > 2 2 13.3 x 2 x y = ax 2 + bx + c y = 0 2 ax 2 + bx + c = 0 y = 0 x ( x ) y = ax 2 + bx + c D = b 2 4ac (1) D >
3/4/8:9 { } { } β β β α β α β β
α β : α β β α β α, [ ] [ ] V, [ ] α α β [ ] β 3/4/8:9 3/4/8:9 { } { } β β β α β α β β [] β [] β β β β α ( ( ( ( ( ( [ ] [ ] [ β ] [ α β β ] [ α ( β β ] [ α] [ ( β β ] [] α [ β β ] ( / α α [ β β ] [ ] 3
zsj2017 (Toyama) program.pdf
88 th Annual Meeting of the Zoological Society of Japan Abstracts 88 th Annual Meeting of the Zoological Society of Japan Abstracts 88 th Annual Meeting of the Zoological Society of Japan Abstracts 88
88 th Annual Meeting of the Zoological Society of Japan Abstracts 88 th Annual Meeting of the Zoological Society of Japan Abstracts 88 th Annual Meeting of the Zoological Society of Japan Abstracts 88
_170825_<52D5><7269><5B66><4F1A>_<6821><4E86><5F8C><4FEE><6B63>_<518A><5B50><4F53><FF08><5168><9801><FF09>.pdf
88 th Annual Meeting of the Zoological Society of Japan Abstracts 88 th Annual Meeting of the Zoological Society of Japan Abstracts 88 th Annual Meeting of the Zoological Society of Japan Abstracts 88
指数関数的進化企業に及ぼす弱い連携の影響 日産自動車, 富士フイルム, 川崎重工業のイノベーションの源泉 1 115 12 13 14 15 16 2 21 22 23 24 25 3 31 32 321 322 323 332 4 41 42 43 5-17 - 18 1 115 4 5 9 1 5 5 2 152045 2 3 12015 22015 1000111000 100111200 112
研修コーナー
l l l l l l l Department of Obstetrics and Gynecology, Fukui Medical University, Fukui l l l l l l µ l β β l α l µ µ l l l l Department of Obstetrics and Gynecology, Gifu University School of Medicine,
nsg04-28/ky208684356100043077
δ!!! μ μ μ γ UBE3A Ube3a Ube3a δ !!!! α α α α α α α α α α μ μ α β α β β !!!!!!!! μ! Suncus murinus μ Ω! π μ Ω in vivo! μ μ μ!!! ! in situ! in vivo δ δ !!!!!!!!!! ! in vivo Orexin-Arch Orexin-Arch !!
#A A A F, F d F P + F P = d P F, F y P F F x A.1 ( α, 0), (α, 0) α > 0) (x, y) (x + α) 2 + y 2, (x α) 2 + y 2 d (x + α)2 + y 2 + (x α) 2 + y 2 =
#A A A. F, F d F P + F P = d P F, F P F F A. α, 0, α, 0 α > 0, + α +, α + d + α + + α + = d d F, F 0 < α < d + α + = d α + + α + = d d α + + α + d α + = d 4 4d α + = d 4 8d + 6 http://mth.cs.kitmi-it.c.jp/
2 2 1?? 2 1 1, 2 1, 2 1, 2, 3,... 1, 2 1, 3? , 2 2, 3? k, l m, n k, l m, n kn > ml...? 2 m, n n m
2009 IA I 22, 23, 24, 25, 26, 27 4 21 1 1 2 1! 4, 5 1? 50 1 2 1 1 2 1 4 2 2 2 1?? 2 1 1, 2 1, 2 1, 2, 3,... 1, 2 1, 3? 2 1 3 1 2 1 1, 2 2, 3? 2 1 3 2 3 2 k, l m, n k, l m, n kn > ml...? 2 m, n n m 3 2
日本分子第5巻2号_15特別講演・シンポジウム.indd
25 JSMI Report JSMI Report 26 41 JSMI Report JSMI Report 42 JSMI Report 54 55 JSMI Report JSMI Report 56 57 JSMI Report JSMI Report 58 59 JSMI Report JSMI Report 60 61 JSMI Report β JSMI Report 62 63 JSMI
1 3 1.1.......................... 3 1............................... 3 1.3....................... 5 1.4.......................... 6 1.5........................ 7 8.1......................... 8..............................
ID POS F
01D8101011L 2005 3 ID POS 2 2 1 F 1... 1 2 ID POS... 2 3... 4 3.1...4 3.2...4 3.3...5 3.4 F...5 3.5...6 3.6 2...6 4... 8 4.1...8 4.2...8 4.3...8 4.4...9 4.5...10 5... 12 5.1...12 5.2...13 5.3...15 5.4...17
漸化式のすべてのパターンを解説しましたー高校数学の達人・河見賢司のサイト
https://www.hmg-gen.com/tuusin.html https://www.hmg-gen.com/tuusin1.html 1 2 OK 3 4 {a n } (1) a 1 = 1, a n+1 a n = 2 (2) a 1 = 3, a n+1 a n = 2n a n a n+1 a n = ( ) a n+1 a n = ( ) a n+1 a n {a n } 1,
NL09
Information September, 2005 1 2 Japanese Association for Molecular Target Therapy of Cancer News Letter No.9 September, 2005 3 2005 4 Japanese Association for Molecular Target Therapy of Cancer News Letter
09 II 09/12/ (3D ) f(, y) = 2 + y 2 3D- 1 f(0, 0) = 2 f(1, 0) = 3 f(0, 1) = 4 f(1, 1) = 5 f( 1, 2) = 6 f(0, 1) = z y (3D ) f(, y) = 2 + y
09 II 09/12/21 1 1 7 1.1 I 2D II 3D f() = 3 6 2 + 9 2 f(, y) = 2 2 + 2y + y 2 6 4y f(1) = 1 3 6 1 2 9 1 2 = 2 y = f() f(3, 2) = 2 3 2 + 2 3 2 + 2 2 6 3 4 2 = 8 z = f(, y) y 2 1 z 8 3 2 y 1 ( y ) 1 (0,
数学概論I
{a n } M >0 s.t. a n 5 M for n =1, 2,... lim n a n = α ε =1 N s.t. a n α < 1 for n > N. n > N a n 5 a n α + α < 1+ α. M := max{ a 1,..., a N, 1+ α } a n 5 M ( n) 1 α α 1+ α t a 1 a N+1 a N+2 a 2 1 a n
2 ID POS 1... 1 2... 2 2.1 ID POS... 2 2.2... 3 3... 5 3.1... 5 3.2... 6 3.2.1... 6 3.2.2... 7 3.3... 7 3.3.1... 7 3.3.2... 8 3.3.3... 8 3.4... 9 4... 11 4.1... 11 4.2... 15 4.3... 27 5... 35... 36...
春期講座 ~ 極限 1 1, 1 2, 1 3, 1 4,, 1 n, n n {a n } n a n α {a n } α {a n } α lim n an = α n a n α α {a n } {a n } {a n } 1. a n = 2 n {a n } 2, 4, 8, 16,
春期講座 ~ 極限 1 1, 1 2, 1 3, 1 4,, 1 n, n n {a n } n a n α {a n } α {a n } α lim an = α n a n α α {a n } {a n } {a n } 1. a n = 2 n {a n } 2, 4, 8, 16, 32, n a n {a n } {a n } 2. a n = 10n + 1 {a n } lim an
nsg02-13/ky045059301600033210
φ φ φ φ κ κ α α μ μ α α μ χ et al Neurosci. Res. Trpv J Physiol μ μ α α α β in vivo β β β β β β β β in vitro β γ μ δ μδ δ δ α θ α θ α In Biomechanics at Micro- and Nanoscale Levels, Volume I W W v W
202
202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 DS =+α log (Spread )+ β DSRate +γlend +δ DEx DS t Spread t 1 DSRate t Lend t DEx DS DEx Spread DS
住宅ローンのリスク管理
NSSOL & CPC 2008 (p.23) Credit Pricing Corp. @ Now Printing PD i 1 i 2 t = 1 α t Now Printing T i i i 1 1 2 2 n n T exp( βx ) βx = β x + β x + Lβ x x i DTI x i Now Printing Now Printing Now Printing
ax 2 + bx + c = n 8 (n ) a n x n + a n 1 x n a 1 x + a 0 = 0 ( a n, a n 1,, a 1, a 0 a n 0) n n ( ) ( ) ax 3 + bx 2 + cx + d = 0 4
20 20.0 ( ) 8 y = ax 2 + bx + c 443 ax 2 + bx + c = 0 20.1 20.1.1 n 8 (n ) a n x n + a n 1 x n 1 + + a 1 x + a 0 = 0 ( a n, a n 1,, a 1, a 0 a n 0) n n ( ) ( ) ax 3 + bx 2 + cx + d = 0 444 ( a, b, c, d
koji07-01.dvi
2007 I II III 1, 2, 3, 4, 5, 6, 7 5 10 19 (!) 1938 70 21? 1 1 2 1 2 2 1! 4, 5 1? 50 1 2 1 1 2 2 1?? 2 1 1, 2 1, 2 1, 2, 3,... 3 1, 2 1, 3? 2 1 3 1 2 1 1, 2 2, 3? 2 1 3 2 3 2 k,l m, n k,l m, n kn > ml...?
4 4 θ X θ P θ 4. 0, 405 P 0 X 405 X P 4. () 60 () 45 () 40 (4) 765 (5) 40 B 60 0 P = 90, = ( ) = X
4 4. 4.. 5 5 0 A P P P X X X X +45 45 0 45 60 70 X 60 X 0 P P 4 4 θ X θ P θ 4. 0, 405 P 0 X 405 X P 4. () 60 () 45 () 40 (4) 765 (5) 40 B 60 0 P 0 0 + 60 = 90, 0 + 60 = 750 0 + 60 ( ) = 0 90 750 0 90 0
6 2 2 x y x y t P P = P t P = I P P P ( ) ( ) ,, ( ) ( ) cos θ sin θ cos θ sin θ, sin θ cos θ sin θ cos θ y x θ x θ P
6 x x 6.1 t P P = P t P = I P P P 1 0 1 0,, 0 1 0 1 cos θ sin θ cos θ sin θ, sin θ cos θ sin θ cos θ x θ x θ P x P x, P ) = t P x)p ) = t x t P P ) = t x = x, ) 6.1) x = Figure 6.1 Px = x, P=, θ = θ P
2019 年 6 月 4 日演習問題 I α, β > 0, A > 0 を定数として Cobb-Douglas 型関数 Y = F (K, L) = AK α L β (5) と定義します. (1) F KK, F KL, F LK, F LL を求めましょう. (2) 第 1 象限のすべての点
09 年 6 月 4 日演習問題 I α, β > 0, A > 0 を定数として Cobb-Douglas 型関数 Y = F K, L) = AK α L β 5) と定義します. ) F KK, F KL, F LK, F LL を求めましょう. ) 第 象限のすべての点 K, L) R ++ に対して F KK K, L) < 0, かつ dethf )K, L) > 0 6) を満たす α,
jscr15-1Net.indd
Vol.15, No.1(2011) JSCR Newsletter JSCR Newsletter published by The Japanese Society of Carbohydrate Research β JSCR Newsletter Vol.15,No.1(2011) 1 2 JSCR Newsletter Vol. 15, No.1 (2011) β α β α JSCR Newsletter
.1 A cos 2π 3 sin 2π 3 sin 2π 3 cos 2π 3 T ra 2 deta T ra 2 deta T ra 2 deta a + d 2 ad bc a 2 + d 2 + ad + bc A 3 a b a 2 + bc ba + d c d ca + d bc +
.1 n.1 1 A T ra A A a b c d A 2 a b a b c d c d a 2 + bc ab + bd ac + cd bc + d 2 a 2 + bc ba + d ca + d bc + d 2 A a + d b c T ra A T ra A 2 A 2 A A 2 A 2 A n A A n cos 2π sin 2π n n A k sin 2π cos 2π
日歯雑誌(H28・8月号)別刷り/ポスターセッション とびら
α P. gingivalis P. gingivalis αsmatgf- VEGF-A α in vitro μ Porphyromonas gingivalis in vitro Porphyromonas gingivalis β β β JBiolChem. μ μ μ β Porphyromonas gingivalis in vitro μ α β α
1 12 *1 *2 (1991) (1992) (2002) (1991) (1992) (2002) 13 (1991) (1992) (2002) *1 (2003) *2 (1997) 1
2005 1 1991 1996 5 i 1 12 *1 *2 (1991) (1992) (2002) (1991) (1992) (2002) 13 (1991) (1992) (2002) *1 (2003) *2 (1997) 1 2 13 *3 *4 200 1 14 2 250m :64.3km 457mm :76.4km 200 1 548mm 16 9 12 589 13 8 50m
NMRの信号がはじめて観測されてから47年になる。その後、NMRは1960年前半までPhys. Rev.等の物理学誌上を賑わせた。1960年代後半、物理学者の間では”NMRはもう死んだ”とささやかれたということであるが(1)、しかし、これほど発展した構造、物性の
8. CW-NR Bloch[]Z (longitudinal relaxation timexy (transversal relaxation timebloembergen [] Bloch Bloembergen Bloch (3.. d d d x z = ( ω ω = ωz + ( ω ω x = ω ( z x (8..a (8..b (8..c = z = z θ = ω t (
85 4
85 4 86 Copright c 005 Kumanekosha 4.1 ( ) ( t ) t, t 4.1.1 t Step! (Step 1) (, 0) (Step ) ±V t (, t) I Check! P P V t π 54 t = 0 + V (, t) π θ : = θ : π ) θ = π ± sin ± cos t = 0 (, 0) = sin π V + t +V
α β *2 α α β β α = α 1 β = 1 β 2.2 α 0 β *3 2.3 * *2 *3 *4 (µ A ) (µ P ) (µ A > µ P ) 10 (µ A = µ P + 10) 15 (µ A = µ P +
Armitage 1 1.1 2 t *1 α β 1.2 µ x µ 2 2 2 α β 2.1 1 α β α ( ) β *1 t t 1 α β *2 α α β β α = α 1 β = 1 β 2.2 α 0 β 1 0 0 1 1 5 2.5 *3 2.3 *4 3 3.1 1 1 1 *2 *3 *4 (µ A ) (µ P ) (µ A > µ P ) 10 (µ A = µ P
( ) FAS87 FAS FAS87 v = 1 i 1 + i
( ) ( 7 6 ) ( ) 1 6 1 18 FAS87 FAS87 7 1 FAS87 v = 1 i 1 + i 10 14 6 6-1 - 7 73 2 N (m) N L m a N (m) L m a N m a (m) N 73 9 99 18 4-2 - 4 143 2 145 3 37 4 37 4 40 6 40 6 41 10 41 10 13 10 14 4 24 3 145
Microsoft Word - 4NMR2.doc
4 NMR 4.1 Zeeman 1, 13 C, 19 F, 31 P NMR 1 13 C 1/2 4.1 7%&'- 89:;'
1 (1) ( i ) 60 (ii) 75 (iii) 315 (2) π ( i ) (ii) π (iii) 7 12 π ( (3) r, AOB = θ 0 < θ < π ) OAB A 2 OB P ( AB ) < ( AP ) (4) 0 < θ < π 2 sin θ
1 (1) ( i ) 60 (ii) 75 (iii) 15 () ( i ) (ii) 4 (iii) 7 1 ( () r, AOB = θ 0 < θ < ) OAB A OB P ( AB ) < ( AP ) (4) 0 < θ < sin θ < θ < tan θ 0 x, 0 y (1) sin x = sin y (x, y) () cos x cos y (x, y) 1 c
N cos s s cos ψ e e e e 3 3 e e 3 e 3 e
3 3 5 5 5 3 3 7 5 33 5 33 9 5 8 > e > f U f U u u > u ue u e u ue u ue u e u e u u e u u e u N cos s s cos ψ e e e e 3 3 e e 3 e 3 e 3 > A A > A E A f A A f A [ ] f A A e > > A e[ ] > f A E A < < f ; >
y = x x R = 0. 9, R = σ $ = y x w = x y x x w = x y α ε = + β + x x x y α ε = + β + γ x + x x x x' = / x y' = y/ x y' =
y x = α + β + ε =,, ε V( ε) = E( ε ) = σ α $ $ β w ( 0) σ = w σ σ y α x ε = + β + w w w w ε / w ( w y x α β ) = α$ $ W = yw βwxw $β = W ( W) ( W)( W) w x x w x x y y = = x W y W x y x y xw = y W = w w
n 2 + π2 6 x [10 n x] x = lim n 10 n n 10 k x 1.1. a 1, a 2,, a n, (a n ) n=1 {a n } n=1 1.2 ( ). {a n } n=1 Q ε > 0 N N m, n N a m
1 1 1 + 1 4 + + 1 n 2 + π2 6 x [10 n x] x = lim n 10 n n 10 k x 1.1. a 1, a 2,, a n, (a n ) n=1 {a n } n=1 1.2 ( ). {a n } n=1 Q ε > 0 N N m, n N a m a n < ε 1 1. ε = 10 1 N m, n N a m a n < ε = 10 1 N
内科96巻3号★/NAI3‐1(第22回試験問題)
µ µ α µ µ µ µ µ µ β β α γ µ Enterococcus faecalis Escherichia coli Legionella pneumophila Pseudomonas aeruginosa Streptococcus viridans α β 正解表正解記号問題 No. 正解記号問題 No. e(4.5) 26 e 1 a(1.2) 27 a 2
dy = sin cos y cos () y () 1 y = sin 1 + c 1 e sin (3) y() () y() y( 0 ) = y 0 y 1 1. (1) d (1) y = f(, y) (4) i y y i+1 y i+1 = y( i + ) = y i
007 8 8 4 1 1.1 ( ) (partial differential equation) (ordinary differential equation) 1 dy = f(, y) (1) 1 1 y() (1) y() (, y) 1 dy = sin cos y cos () y () 1 y = sin 1 + c 1 e sin (3) 1 1 5 y() () y() y(
(1) 1 y = 2 = = b (2) 2 y = 2 = 2 = 2 + h B h h h< h 2 h
6 6.1 6.1.1 O y A y y = f() y = f() b f(b) B y f(b) f() = b f(b) f() f() = = b A f() b AB O b 6.1 2 y = 2 = 1 = 1 + h (1 + h) 2 1 2 (1 + h) 1 2h + h2 = h h(2 + h) = h = 2 + h y (1 + h) 2 1 2 O y = 2 1
振動工学に基礎
Ky Words. ω. ω.3 osω snω.4 ω snω ω osω.5 .6 ω osω snω.7 ω ω ( sn( ω φ.7 ( ω os( ω φ.8 ω ( ω sn( ω φ.9 ω anφ / ω ω φ ω T ω T s π T π. ω Hz ω. T π π rad/s π ω π T. T ω φ 6. 6. 4. 4... -... -. -4. -4. -6.
さくらの個別指導 ( さくら教育研究所 ) A a 1 a 2 a 3 a n {a n } a 1 a n n n 1 n n 0 a n = 1 n 1 n n O n {a n } n a n α {a n } α {a
... A a a a 3 a n {a n } a a n n 3 n n n 0 a n = n n n O 3 4 5 6 n {a n } n a n α {a n } α {a n } α α {a n } a n n a n α a n = α n n 0 n = 0 3 4. ()..0.00 + (0.) n () 0. 0.0 0.00 ( 0.) n 0 0 c c c c c
第10章 アイソパラメトリック要素
June 5, 2019 1 / 26 10.1 ( ) 2 / 26 10.2 8 2 3 4 3 4 6 10.1 4 2 3 4 3 (a) 4 (b) 2 3 (c) 2 4 10.1: 3 / 26 8.3 3 5.1 4 10.4 Gauss 10.1 Ω i 2 3 4 Ξ 3 4 6 Ξ ( ) Ξ 5.1 Gauss ˆx : Ξ Ω i ˆx h u 4 / 26 10.2.1
sekibun.dvi
a d = a + a+ (a ), e d = e, sin d = cos, (af() + bg())d = a d = log, cosd = sin, f()d + b g()d d 3 d d d d d d d ( + 3 + )d ( + )d ( 3 )d (e )d ( sin 3 cos)d g ()f (g())d = f(g()) e d e d ( )e d cos d
F = 0 F α, β F = t 2 + at + b (t α)(t β) = t 2 (α + β)t + αβ G : α + β = a, αβ = b F = 0 F (t) = 0 t α, β G t F = 0 α, β G. α β a b α β α β a b (α β)
19 7 12 1 t F := t 2 + at + b D := a 2 4b F = 0 a, b 1.1 F = 0 α, β α β a, b /stlasadisc.tex, cusp.tex, toileta.eps, toiletb.eps, fromatob.tex 1 F = 0 F α, β F = t 2 + at + b (t α)(t β) = t 2 (α + β)t
70 : 20 : A B (20 ) (30 ) 50 1
70 : 0 : A B (0 ) (30 ) 50 1 1 4 1.1................................................ 5 1. A............................................... 6 1.3 B............................................... 7 8.1 A...............................................
untitled
( ) l 1991 1) 4) 5),6) 7) 8) 31) 39) 46) : () + +θ (c) l h A - : θ A () (d) 1 ε=/l=θ/cot 1(d) 1 () =tn( ) h + 1 u F m N F m =Ntn N N N F m N F m =Ntn N S α S1 R α+ R = tn( ) = tn = tn( + ) R R d = d ()
O x y z O ( O ) O (O ) 3 x y z O O x v t = t = 0 ( 1 ) O t = 0 c t r = ct P (x, y, z) r 2 = x 2 + y 2 + z 2 (t, x, y, z) (ct) 2 x 2 y 2 z 2 = 0
9 O y O ( O ) O (O ) 3 y O O v t = t = 0 ( ) O t = 0 t r = t P (, y, ) r = + y + (t,, y, ) (t) y = 0 () ( )O O t (t ) y = 0 () (t) y = (t ) y = 0 (3) O O v O O v O O O y y O O v P(, y,, t) t (, y,, t )
10 : 3010 : 54 1F Annex 1! 1 15:3015 : 58 1F Annex 1
4 16 1 10:0010 : 24 1F Annex 1! 2 15:0015 : 24 1F Annex 1!! 10 : 3010 : 54 1F Annex 1! 1 15:3015 : 58 1F Annex 1 ! 2 10:0010 : 28 1F Annex 1 3 15:0015 : 28 1F Annex 1 4 10:3010 : 58 1F Annex 1 1 15:3015
総合薬学講座 生物統計の基礎
2013 10 22 ( ) 2013 10 22 1 / 40 p.682 1. 2. 3 2 t Mann Whitney U ). 4 χ 2. 5. 6 Dunnett Tukey. 7. 8 Kaplan Meier.. U. ( ) 2013 10 22 2 / 40 1 93 ( 20 ) 230. a t b c χ 2 d 1.0 +1.0 e, b ( ) e ( ) ( ) 2013
untitled
The 23rd Annual Meeting of the Japanese Association of Cardiac Rehabilitation! The 23rd Annual Meeting of the Japanese Association of Cardiac Rehabilitation The 23rd Annual Meeting of the Japanese Association
16
15 16 3-1 3-2 3-3 3-3-1 2 2-1 2 3-3-2 3 3-1 17 ) 3-3-3 115 115 8 10 3-2 3-2 1 1573 24 617 47 322 70 193 93 107 2 1441 25 600 48 313 71 192 94 106 3 884 26 592 49 262 72 189 95 98 4 883 27 571 50 304 73
授業研究第1日目
1 1 1 0. (sextant) ( ) 2 1. IB I AB I AI E H H E B GHE CIHE ( ) 2 2 I H A (0 ) ( ) 3 2 2 θ = α + γ β + γ = θ + α β + γ = ( α + γ ) + α β = 2 α + γ γ C H CIG ( ) 4 2. John Hadley 1731 5 ( (octant)) Captain