CVMに基づくNi-Al合金の
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1 CV N-A (-' by T.Koyama
2 ennard-jones fcc α, β, γ, δ β α γ δ = or α, β. γ, δ α β γ ( αβγ w = = k k k ( αβγ w = ( αβγ ( αβγ w = w = ( αβγ w = ( αβγ w = ( αβγ w = ( αβγ w = ( αβγ w =
3 ( βγδ w = = k k k ( αγδ w = = k k k ( αβδ w = = k w k wk = wk wk wk wk ( ( αβγ ( βγδ ( αγδ ( αβδ ( ( αβ α β y = = k, ( αβ y = ( αβ y = ( αβ y = ( αβ y = ( βγ y = = k, k k k k ( γδ y = = k k k k k ( αδ y = =, ( αγ y = = k k, k k k k ( βδ y = =, y y = y y y y y y 6 ( ( αβ ( βγ ( γδ ( αδ ( αγ ( βδ (
4 ( α x α = = k,, ( α x = ( α x = ( β x = = k,, ( γ x = = k, k k k k k k k k ( δ x = =, k x x = x x x x ( ( α ( β ( γ ( δ (3 8- e ( r= e 8 r r r H G r K J ( e r r E E = ω e ( r y = ω( e y e y e y e y ( y 3
5 E = ω e ( r y ( αβ ( βγ ( γδ ( αδ ( αγ ( βδ = ω e ( r( y y y y y y ( ( e ( r y e ( r y e ( r y = ω ( ( e ( r y e ( r y e ( r y αβ αβ ( αβ αβ αβ ( αβ ( ( e ( r y ek ( r y k ek ( r yk k, k, = ω ( ( e ( r y e ( r y e ( r y αβ βγ ( γδ αδ αγ ( βδ k k, k,, e ( r( e ( r( k k k k k k, = ω ek ( r( k k k k e ( r( e ( r( e ( r( k,, k, k k k k k, e ( r ek ( r ek ( r k, k,, k, = ω e ( r e ( r e ( r k, k, k,,, k, e ( r ek ( r ek ( r, k, = ω e ( r e ( r e ( r k = ω { e ( r e ( r e ( r e ( r e ( r e ( r = ω e ( r k k k ( e = e ek e ek e ek (6 (3 x
6 ( α ( α ( β ( β ( γ ( γ ( δ ( δ x x = ( x x x x x x x x N N = k k k k k k,, k,, k,, k,,,,, k, k = p p p = ( p p p p = p k k p k (7 p =, p = p = p p p p (8 k CV S = k ( ( αβ ( βγ ( γδ ( y ( y ( y ( αδ ( αγ ( βδ ( y ( y ( y ( α ( β ( γ ( δ x ( x ( x ( x ( m S T r U V W (9 x ( = xnx x ( (9 ( = ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( αβ ( αβ ( αβ ( αβ ( αβ ( y = ( y ( y ( y ( y = ( ( ( (
7 ( ( ( x ( α = x ( α x ( α = ( ( (9 x ( = n x = n x x ( S S T ( αβ ( βγ ( γδ n( y n( y n( y n( ( αδ ( αγ ( βδ = k n( y n( y n( y ( α ( β ( γ ( δ mn( x n( x n( x n( x r αβ βγ γδ αδ αγ βδ α = k n( n( y y y y y y n( x x ( ( ( ( ( ( ( ( β ( γ ( δ x x U V W ( G = v µ( x x ( ((9( ( αβ ( βγ ( γδ ( y ( y ( y ( ( αδ ( αγ ( βδ y ( y ( y ( = ω e ( r kt ( α ( β ( γ ( δ mx ( x ( x ( x ( r S T U V W (3 λ g g G λ = v µ ( x x λ (3(7 6
8 g v µ ( x x λ = ω e ( r kt ( v µ p λ S T ( αβ ( βγ ( γδ ( y ( y ( y m r ( αδ ( αγ ( βδ ( y ( y ( y ( α ( β ( γ ( δ x ( x ( x ( x ( U V W ( g = g = ω e ( r ( αβ ( βγ ( γδ ( αδ ( αγ ( βδ ( α ( β ( γ ( δ kt n( n( y y y y y y n( x x x x µ p λ = d c h 8 / h / αβ λ ω e r µ p y y ( d exp exp kt kt kt c ( αβ ( βγ ( γδ ( αδ ( αγ ( βδ n( n( y y y y y y ω e ( r kt µ p α β γ δ ( ( ( ( n( x x x x λ = ( αβ ( βγ ( γδ ( αδ ( αγ ( βδ / ω 8 kt e r n( n y y y y y y ( ( α ( β ( γ ( δ / n x x x x d c µ λ 8kT p kt ( α ( β ( γ ( δ x x x x = λ ω µ n αβ βγ γδ αδ αγ βδ y y y y y y kt kt e ( r 8kT p ( ( ( ( ( ( = exp H G η exp 8 ω e ( r µ p exp kt 8kT d ( ( βγ y y y y y y y y y y ( γδ ( αδ ( αγ ( βδ x x x x ( αβ ( βγ ( γδ ( αδ ( αγ ( βδ c x x x x ( α ( β ( γ ( δ h ( α ( β ( γ ( δ 8 / / h 8 / / = ( (6 7
9 = η exp H G λ kt λ λ = = η exp H G exp kt kt λ = ktn = η H G η (7 g g v = λ g g = v λ = v k Tn = (7 η (8 g v = g = ω v e ( r v e ( r v = ω = (9 fcc fcc v r ( r 3 3 dr = v r = v 3r dr = dv = dv 3r (6 8
10 de dr d = ( dr e e e e e e k k k ( de ( r = e dr 7 H G K J 3 r r r r 8 8 e r r r r = 8 8 r e r r r = ( {( 9 r r r r H G 9 de ( r de de de de de k k dek dr = S dv H G dr K J H G dr K J H G dr K J H G dr K J H G dr K J H G dr K J T V W H G K J dv 8 e ( r {( r r ek ( rk {( rk r e ( r {( r r = 9 r e ( r {( r r e ( r {( r r e ( r {( r r 3r 8 = 3r k k k e ( r {( r r e ( r {( r r e ( r {( r r k k k e ( r {( r r e ( r {( r r e ( r {( r r k k k k k k U H G r r k k k (9 H G K J e ( r v 8 3r = ω e ( r {( r r ek ( rk {( rk r e ( r {( r r e ( r {( r r e ( r {( r r e ( r {( r r k k k k k k e ( r {( r r ek ( rk {( rk r e ( r {( r r e ( r {( r r e ( r {( r r e ( r {( r r k k k k k k 9 r r e ( r e k ( r k e ( r = e ω = ω 9 = r ω ( r e ( r e ( r k k k k e ( r e ( r e ( r e ( r e ( r e ( r k k k k k k 9 r r e ( r e ( r e ( r e ( r e ( r e ( r ω k k k k k k ( ( ( ( ( ( e r ek rk e r ek rk e r ek rk = ( e, r ( r = r * = 9
11 r = S T e ( r e ( r e ( r e ( r e ( r e ( r k k k k k k e ( r e ( r e ( r e ( r e ( r e ( r k k k k k k U V W / ( T e, r ω x r * :( :(N αβγδ β, γ, δ = = = = = = = = αβγδ αβγδ αβγδ αβγδ αβγδ αβγδ αβγδ αβγδ αβγδ αβγδ αβγδ αβγδ αβγδ αβγδ αβγδ αβγδ
第86回日本感染症学会総会学術集会後抄録(I)
κ κ κ κ κ κ μ μ β β β γ α α β β γ α β α α α γ α β β γ μ β β μ μ α ββ β β β β β β β β β β β β β β β β β β γ β μ μ μ μμ μ μ μ μ β β μ μ μ μ μ μ μ μ μ μ μ μ μ μ β
四変数基本対称式の解放
The second-thought of the Galois-style way to solve a quartic equation Oomori, Yasuhiro in Himeji City, Japan Jan.6, 013 Abstract v ρ (v) Step1.5 l 3 1 6. l 3 7. Step - V v - 3 8. Step1.3 - - groupe groupe
F = 0 F α, β F = t 2 + at + b (t α)(t β) = t 2 (α + β)t + αβ G : α + β = a, αβ = b F = 0 F (t) = 0 t α, β G t F = 0 α, β G. α β a b α β α β a b (α β)
19 7 12 1 t F := t 2 + at + b D := a 2 4b F = 0 a, b 1.1 F = 0 α, β α β a, b /stlasadisc.tex, cusp.tex, toileta.eps, toiletb.eps, fromatob.tex 1 F = 0 F α, β F = t 2 + at + b (t α)(t β) = t 2 (α + β)t
y = x x R = 0. 9, R = σ $ = y x w = x y x x w = x y α ε = + β + x x x y α ε = + β + γ x + x x x x' = / x y' = y/ x y' =
y x = α + β + ε =,, ε V( ε) = E( ε ) = σ α $ $ β w ( 0) σ = w σ σ y α x ε = + β + w w w w ε / w ( w y x α β ) = α$ $ W = yw βwxw $β = W ( W) ( W)( W) w x x w x x y y = = x W y W x y x y xw = y W = w w
研修コーナー
l l l l l l l l l l l α α β l µ l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l
1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2
2005 9/8-11 2 2.2 ( 2-5) γ ( ) γ cos θ 2πr πρhr 2 g h = 2γ cos θ ρgr (2.1) γ = ρgrh (2.2) 2 cos θ θ cos θ = 1 (2.2) γ = 1 ρgrh (2.) 2 2. p p ρgh p ( ) p p = p ρgh (2.) h p p = 2γ r 1 1 (Berry,1975) 2-6
n 2 + π2 6 x [10 n x] x = lim n 10 n n 10 k x 1.1. a 1, a 2,, a n, (a n ) n=1 {a n } n=1 1.2 ( ). {a n } n=1 Q ε > 0 N N m, n N a m
1 1 1 + 1 4 + + 1 n 2 + π2 6 x [10 n x] x = lim n 10 n n 10 k x 1.1. a 1, a 2,, a n, (a n ) n=1 {a n } n=1 1.2 ( ). {a n } n=1 Q ε > 0 N N m, n N a m a n < ε 1 1. ε = 10 1 N m, n N a m a n < ε = 10 1 N
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δ!!! μ μ μ γ UBE3A Ube3a Ube3a δ !!!! α α α α α α α α α α μ μ α β α β β !!!!!!!! μ! Suncus murinus μ Ω! π μ Ω in vivo! μ μ μ!!! ! in situ! in vivo δ δ !!!!!!!!!! ! in vivo Orexin-Arch Orexin-Arch !!
四変数基本対称式の解放
Solving the simultaneous equation of the symmetric tetravariate polynomials and The roots of a quartic equation Oomori, Yasuhiro in Himeji City, Japan Dec.1, 2011 Abstract 1. S 4 2. 1. {α, β, γ, δ} (1)
O1-1 O1-2 O1-3 O1-4 O1-5 O1-6
O1-1 O1-2 O1-3 O1-4 O1-5 O1-6 O1-7 O1-8 O1-9 O1-10 O1-11 O1-12 O1-13 O1-14 O1-15 O1-16 O1-17 O1-18 O1-19 O1-20 O1-21 O1-22 O1-23 O1-24 O1-25 O1-26 O1-27 O1-28 O1-29 O1-30 O1-31 O1-32 O1-33 O1-34 O1-35
n (1.6) i j=1 1 n a ij x j = b i (1.7) (1.7) (1.4) (1.5) (1.4) (1.7) u, v, w ε x, ε y, ε x, γ yz, γ zx, γ xy (1.8) ε x = u x ε y = v y ε z = w z γ yz
1 2 (a 1, a 2, a n ) (b 1, b 2, b n ) A (1.1) A = a 1 b 1 + a 2 b 2 + + a n b n (1.1) n A = a i b i (1.2) i=1 n i 1 n i=1 a i b i n i=1 A = a i b i (1.3) (1.3) (1.3) (1.1) (ummation convention) a 11 x
1 911 9001030 9:00 A B C D E F G H I J K L M 1A0900 1B0900 1C0900 1D0900 1E0900 1F0900 1G0900 1H0900 1I0900 1J0900 1K0900 1L0900 1M0900 9:15 1A0915 1B0915 1C0915 1D0915 1E0915 1F0915 1G0915 1H0915 1I0915
> > <., vs. > x 2 x y = ax 2 + bx + c y = 0 2 ax 2 + bx + c = 0 y = 0 x ( x ) y = ax 2 + bx + c D = b 2 4ac (1) D > 0 x (2) D = 0 x (3
13 2 13.0 2 ( ) ( ) 2 13.1 ( ) ax 2 + bx + c > 0 ( a, b, c ) ( ) 275 > > 2 2 13.3 x 2 x y = ax 2 + bx + c y = 0 2 ax 2 + bx + c = 0 y = 0 x ( x ) y = ax 2 + bx + c D = b 2 4ac (1) D >
さくらの個別指導 ( さくら教育研究所 ) 1 φ = φ 1 : φ [ ] a [ ] 1 a : b a b b(a + b) b a 2 a 2 = b(a + b). b 2 ( a b ) 2 = a b a/b X 2 X 1 = 0 a/b > 0 2 a
φ + 5 2 φ : φ [ ] a [ ] a : b a b b(a + b) b a 2 a 2 b(a + b). b 2 ( a b ) 2 a b + a/b X 2 X 0 a/b > 0 2 a b + 5 2 φ φ : 2 5 5 [ ] [ ] x x x : x : x x : x x : x x 2 x 2 x 0 x ± 5 2 x x φ : φ 2 : φ ( )
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3 3 5 5 5 3 3 7 5 33 5 33 9 5 8 > e > f U f U u u > u ue u e u ue u ue u e u e u u e u u e u N cos s s cos ψ e e e e 3 3 e e 3 e 3 e 3 > A A > A E A f A A f A [ ] f A A e > > A e[ ] > f A E A < < f ; >
(Compton Scattering) Beaming 1 exp [i (k x ωt)] k λ k = 2π/λ ω = 2πν k = ω/c k x ωt ( ω ) k α c, k k x ωt η αβ k α x β diag( + ++) x β = (ct, x) O O x
Compton Scattering Beaming exp [i k x ωt] k λ k π/λ ω πν k ω/c k x ωt ω k α c, k k x ωt η αβ k α x β diag + ++ x β ct, x O O x O O v k α k α β, γ k γ k βk, k γ k + βk k γ k k, k γ k + βk 3 k k 4 k 3 k
2 1 1 α = a + bi(a, b R) α (conjugate) α = a bi α (absolute value) α = a 2 + b 2 α (norm) N(α) = a 2 + b 2 = αα = α 2 α (spure) (trace) 1 1. a R aα =
1 1 α = a + bi(a, b R) α (conjugate) α = a bi α (absolute value) α = a + b α (norm) N(α) = a + b = αα = α α (spure) (trace) 1 1. a R aα = aα. α = α 3. α + β = α + β 4. αβ = αβ 5. β 0 6. α = α ( ) α = α
1. 2 P 2 (x, y) 2 x y (0, 0) R 2 = {(x, y) x, y R} x, y R P = (x, y) O = (0, 0) OP ( ) OP x x, y y ( ) x v = y ( ) x 2 1 v = P = (x, y) y ( x y ) 2 (x
. P (, (0, 0 R {(,, R}, R P (, O (0, 0 OP OP, v v P (, ( (, (, { R, R} v (, (, (,, z 3 w z R 3,, z R z n R n.,..., n R n n w, t w ( z z Ke Words:. A P 3 0 B P 0 a. A P b B P 3. A π/90 B a + b c π/ 3. +
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.2 ρ dv dt = ρk grad p + 3 η grad (divv) + η 2 v.3 divh = 0, rote + c H t = 0 dive = ρ, H = 0, E = ρ, roth c E t = c ρv E + H c t = 0 H c E t = c ρv T
NHK 204 2 0 203 2 24 ( ) 7 00 7 50 203 2 25 ( ) 7 00 7 50 203 2 26 ( ) 7 00 7 50 203 2 27 ( ) 7 00 7 50 I. ( ν R n 2 ) m 2 n m, R = e 2 8πε 0 hca B =.09737 0 7 m ( ν = ) λ a B = 4πε 0ħ 2 m e e 2 = 5.2977
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O x y z O ( O ) O (O ) 3 x y z O O x v t = t = 0 ( 1 ) O t = 0 c t r = ct P (x, y, z) r 2 = x 2 + y 2 + z 2 (t, x, y, z) (ct) 2 x 2 y 2 z 2 = 0
9 O y O ( O ) O (O ) 3 y O O v t = t = 0 ( ) O t = 0 t r = t P (, y, ) r = + y + (t,, y, ) (t) y = 0 () ( )O O t (t ) y = 0 () (t) y = (t ) y = 0 (3) O O v O O v O O O y y O O v P(, y,, t) t (, y,, t )
ax 2 + bx + c = n 8 (n ) a n x n + a n 1 x n a 1 x + a 0 = 0 ( a n, a n 1,, a 1, a 0 a n 0) n n ( ) ( ) ax 3 + bx 2 + cx + d = 0 4
20 20.0 ( ) 8 y = ax 2 + bx + c 443 ax 2 + bx + c = 0 20.1 20.1.1 n 8 (n ) a n x n + a n 1 x n 1 + + a 1 x + a 0 = 0 ( a n, a n 1,, a 1, a 0 a n 0) n n ( ) ( ) ax 3 + bx 2 + cx + d = 0 444 ( a, b, c, d
1 (Contents) (1) Beginning of the Universe, Dark Energy and Dark Matter Noboru NAKANISHI 2 2. Problem of Heat Exchanger (1) Kenji
8 4 2018 6 2018 6 7 1 (Contents) 1. 2 2. (1) 22 3. 31 1. Beginning of the Universe, Dark Energy and Dark Matter Noboru NAKANISHI 2 2. Problem of Heat Exchanger (1) Kenji SETO 22 3. Editorial Comments Tadashi
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W u = u(x, t) u tt = a 2 u xx, a > 0 (1) D := {(x, t) : 0 x l, t 0} u (0, t) = 0, u (l, t) = 0, t 0 (2)
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量子力学 問題
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5 5.1 E 1, E 2 N 1, N 2 E tot N tot E tot = E 1 + E 2, N tot = N 1 + N 2 S 1 (E 1, N 1 ), S 2 (E 2, N 2 ) E 1, E 2 S tot = S 1 + S 2 2 S 1 E 1 = S 2 E
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nm (T = K, p = kP a (1atm( )), 1bar = 10 5 P a = atm) 1 ( ) m / m
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.1, θ, ϕ d = A, t dt + B, t dtd + C, t d + D, t dθ +in θdϕ.1.1 t { = f1,t t = f,t { D, t = B, t =.1. t A, tdt e φ,t dt, C, td e λ,t d.1.3,t, t d = e φ,t dt + e λ,t d + dθ +in θdϕ.1.4 { = f1,t t = f,t {
m(ẍ + γẋ + ω 0 x) = ee (2.118) e iωt P(ω) = χ(ω)e = ex = e2 E(ω) m ω0 2 ω2 iωγ (2.119) Z N ϵ(ω) ϵ 0 = 1 + Ne2 m j f j ω 2 j ω2 iωγ j (2.120)
2.6 2.6.1 mẍ + γẋ + ω 0 x) = ee 2.118) e iωt Pω) = χω)e = ex = e2 Eω) m ω0 2 ω2 iωγ 2.119) Z N ϵω) ϵ 0 = 1 + Ne2 m j f j ω 2 j ω2 iωγ j 2.120) Z ω ω j γ j f j f j f j sum j f j = Z 2.120 ω ω j, γ ϵω) ϵ
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NMRの信号がはじめて観測されてから47年になる。その後、NMRは1960年前半までPhys. Rev.等の物理学誌上を賑わせた。1960年代後半、物理学者の間では”NMRはもう死んだ”とささやかれたということであるが(1)、しかし、これほど発展した構造、物性の
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