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1 ( )
2 ( )
3 180 2
4 180 3
5
6
7
8
9 ( )
10 ( ) 9
11 P18 A A 10
12 P18 A A : = A : A 11
13 P18 A A : = A : A 12
14 P18 A F E A : = A : EF E // A, F // E AF A E = F A : = F A : E = F A : F = A : 13
15 P18 ( ) A : = A : E A F 14
16 1 ( ) 2 15
17 2005 a a, b, c(> 0) a b c, a < b + c P23 16
18 A a 17
19 A E F G H b c a 18
20 E F G H b c I a 19
21 A J E F G H b c I a 20
22 A J G b G H c I a 21
23 A E J F b F c I a 22
24 K I 23
25 ( ) 24
26 2006 1) 2) 3)
27
28 27
29 ( ) 28
30 ( ) ( ) 29
31 ( )? 30
32 ( ) ( ) ( ) ) 31
33 A A A 30 A 40 A ) P4 A 32
34 A A = A = 30 A = 40 A =? E 33
35 2 30 A A = A = 30 A = 40 A =? 40 E 34
36 3 30 A A = A = 30 A = 40 A =? 40 35
37 3 30 A A = A = 30 A = 40 A =? 40 E 36
38 3 A A = A = 30 A = 40 A =? 40 F 40 E 37
39 3 A A = A = 30 A = 40 A =? 40 F 40 E 38
40 P S R Q 39
41 P S R Q 40
42 P S R Q 41
43 P S R Q 42
44 43
45 44
46 45
47 46
48 O PQRS 47
49 P S R Q O 48
50 (1) A 49
51 (1) A 50
52 (1) E A 51
53 A A 52
54 A A 53
55 (2) 54
56 (2) 55
57 (3) 56
58 (3) 57
59 (4) 58
60 (4) 59
61 ( ) ( ) P
62 1 A A = A, =, A // = E A E P19 61
63 1 A A = A, =, A // = E A E A A P19 62
64 1 A A = A, =, A // = E A E A A P19 63
65 1 A A = A, =, A // = E A E A A P19 64
66 1 A A = A, =, A // = E A E A A E = E 65
67 2 A A E A = A, =, A // = E P19 66
68 2 A A E A = A, =, A // = E P19 67
69 2 A A E A = A, =, A // = E P19 68
70 2 A 69
71 a a A 70
72 a a A 71
73 P a a A (P) A 72
74 A P a a A (P) AP 73
75 P A 74
76 P A 75
77 A A = A, =, F A E A // = E E = E P13 76
78 F O P G E A P13 77
79 P A P = P = 15 P AP P13 A 78
80 ( ) θ 8 θ 7 θ 6 θ 5 A θ 1 θ 2 θ 4 θ 3 θ 1 + θ 2 + θ 3 + θ 8 = 180 θ 2 + θ 3 + θ 4 + θ 5 = 180 θ 6 + θ 7 = θ 2 + θ 3 P14 sin θ 1 sin θ 3 sin θ 5 sin θ 7 = sin θ 2 sin θ 4 sin θ 6 sin θ 8 79
81 ( ) θ 1 θ 8 80
82 ( ) 180 n n = 8 n = 36(n ) 81
83 ( ) n = 18(10 ) 724 A ( ) 372 ( ) 152(A 100 ) (1 ) 48 (1 ) 48 E 24 ( 12 ) A, 300 P22 82
84 300 ( ) x A θ 1 θ 2 θ 4 θ 3 83
85 ➀ ➁ ➂ ➃ ➄ ➅ ( ) P17 84
86 ( ) A x d a b c ➀ 40, 30, 80, 20 ➁ 10, 10, 40, 110 ➂ 40, 60, 30, 70 ➃ 10, 20, 40, 40 ➄ 20, 30, 70,
87 20, 60, 50, 30 P20 86
88 A 40, 30, 80, 20 x
89 A 40, 30, 80, 20 x
90 A 40, 30, 80, 20 x A
91 A 40, 30, 80, 20 x A A
92 A x , 30, 80, 20 A A A A = 50 2 =
93 10, 10, 40,
94 = 10, 10, 40, 110 A x
95 A A A x
96 A N: A N A x 95
97 N, : N N A x 96
98 N = N = 60 = NA N A x 97
99 AO A N O x 98
100 40, 60, 30, 70 99
101 N x 40, 60, 30, 70 A A A M A N N N N A x =
102 10, 20, 40,
103 = 10, 20, 40, 40 A A E x A A A A E A A A = A x =
104 20, 30, 70,
105 = 20, 30, 70, 40 A x P9 104
106 = 20, 30, 70, 40 A x E 105
107 = 20, 30, 70, 40 A x P9 106
108 = 20, 30, 70, 40 A x P9 107
109 = 20, 30, 70, 40 O A P9 x A = 1 2 O O A 108
110 = 20, 30, 70, 40 A x P9 109
111 = 20, 30, 70, 40 A x A P9 110
112 = 20, 30, 70, 40 G E A F P9 x A E EG,AE 111
113 A 4 A = 2 A α 2α A A 36 (300 ) 112
114 10, 20, 100, 20 = 10, 30, 70,
115 = 10, 30, 70, 30 A x
116 = 10, 30, 70, 30 A x E F E = 2 FE = 2 E 115
117 = 10, 30, 70, E F A x E = 2 FE = 2 E EF 116
118 = 10, 30, 70, E F A x E = 2 FE = 2 E EF E AE A x =
119 = 10, 20, 100, 20 = 10, 30, 70, 30 A x
120 = 10, 20, 100, 20 = 10, 30, 70, 30 E A x
121 = 10, 20, 100, 20 = 10, 30, 70, 30 E A x 10, 30, 70, 30 AE 120
122 20, 60, 50, 30 langley 121
123 A 20, 60, 50, E x = 60 E = 50 E
124 A 20 20, 60, 50, 30 A EF F E x F 123
125 x 20, 60, 50, 30 A
126 20, 60, 50, 30 x A
127 20, 60, 50, 30 G x F A G A F E
128 20, 60, 50, 30 A G F x F A G F A,G AFG GF A E
129 A 20 20, 60, 50, 30 E x
130 A 20 20, 60, 50, 30 E x A A
131 A 20 20, 60, 50, 30 E x A A
132 A 20 20, 60, 50, 30 E x A
133 P3 132
134 133
h16ﾏｽﾀｰｾﾝﾀｰ報告書（神奈川県支部）
( / 36 16 /16 /16 /16 /100 [ ] % [ ] [ ] [ ] [ ][ ] 5 ➀ ➁ ➂ ➀ ➀ ➁ ➀ ➁ ➀ ➀ ➁ ➂ ➀ ➂ ➀ ➁ ➂ ➀ ➁ ➂ ➀ ➂ ➀ ➁ ➂ ➀ ➂ ➀ ➀ ➁ ➂ ➀ ➁ ➂ ➀ ➁ ➂ ➀ ➂ ➀ ➂ ➀ ➁ ➂ ➃ ➀ ➁ ➂ ➀ ➁ ➀
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OFISTAR S3100取扱説明書
2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 1 7 2 4 3 0 6 4 1 2 5 3 24 1 2 3 1 2 3 25 1 2 3 6 7 8 9 26 27 1 2 3 4 5 28 29 ABC 30 31 32 : : 33 1 8 2 1 3 1 2 3 4 34 1 2 35 1 1 36 1 2 3a 3b
資料32-2-2 深海掘削検討会報告書（平成24年3月 独立行政法人海洋研究開発機構 深海掘削検討会）
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マリモの育て方
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1 1 3 ABCD ABD AC BD E E BD 1 : 2 (1) AB = AD =, AB AD = (2) AE = AB + (3) A F AD AE 2 = AF = AB + AD AF AE = t AC = t AE AC FC = t = (4) ABD ABCD 1 1
ABCD ABD AC BD E E BD : () AB = AD =, AB AD = () AE = AB + () A F AD AE = AF = AB + AD AF AE = t AC = t AE AC FC = t = (4) ABD ABCD AB + AD AB + 7 9 AD AB + AD AB + 9 7 4 9 AD () AB sin π = AB = ABD AD
1180年、源頼朝は鎌倉に入り、政治の中心をこの地に置いた
35000261 38000474 35001585 35002646 2003 12 22 1 2 12 4 3 4 1300 4 1180 1577 13 [] 5 (32% (22%) (13%) (5%) (5%) (12%) (1%) (10%) 30 60 ()() () [] (51%) (18%) 11% (5%) (5%) (3%) (2%) (5%) 6 () [] (33%)
2 (1) a = ( 2, 2), b = (1, 2), c = (4, 4) c = l a + k b l, k (2) a = (3, 5) (1) (4, 4) = l( 2, 2) + k(1, 2), (4, 4) = ( 2l + k, 2l 2k) 2l + k = 4, 2l
ABCDEF a = AB, b = a b (1) AC (3) CD (2) AD (4) CE AF B C a A D b F E (1) AC = AB + BC = AB + AO = AB + ( AB + AF) = a + ( a + b) = 2 a + b (2) AD = 2 AO = 2( AB + AF) = 2( a + b) (3) CD = AF = b (4) CE
(1) 3 A B E e AE = e AB OE = OA + e AB = (1 35 e ) e OE z 1 1 e E xy e = 0 e = 5 OE = ( 2 0 0) E ( 2 0 0) (2) 3 E P Q k EQ = k EP E y 0
(1) 3 A B E e AE = e AB OE = OA + e AB = (1 35 e 0 1 15 ) e OE z 1 1 e E xy 5 1 1 5 e = 0 e = 5 OE = ( 2 0 0) E ( 2 0 0) (2) 3 E P Q k EQ = k EP E y 0 Q y P y k 2 M N M( 1 0 0) N(1 0 0) 4 P Q M N C EP
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平成20年5月 協会創立50年の歩み 海の安全と環境保全を目指して 友國八郎 海上保安庁 長官 岩崎貞二 日本船主協会 会長 前川弘幸 JF全国漁業協同組合連合会 代表理事会長 服部郁弘 日本船長協会 会長 森本靖之 日本船舶機関士協会 会長 大内博文 航海訓練所 練習船船長 竹本孝弘 第二管区海上保安本部長 梅田宜弘
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4 5 6 7 8 9 10 11 12 13 14 15 16 I II I I I I I I I 17 18 19 20 21 22 23 http://www.surugabank.co.jp/dream/ http://www.surugabank.co.jp/directone/ http://www.surugabank.co.jp/ebusinessdirect/ http://www.surugabank.co.jp/so-net/
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b n c n d n d n = f() d (n =, ±, ±, ) () πi ( a) n+ () () = a R a f() = a k Γ ( < k < R) Γ f() Γ ζ R ζ k a Γ f() = f(ζ) πi ζ dζ f(ζ) dζ (3) πi Γ ζ (3)
[ ] KENZOU 6 3 4 Origin 6//5) 3 a a f() = b n ( a) n c n + ( a) n n= n= = b + b ( a) + b ( a) + + c a + c ( a) + b n = f() πi ( a) n+ d, c n = f() d πi ( a) n+ () b n c n d n d n = f() d (n =, ±, ±, )
【資料１】平成２８年度予算案における子ども・子育て支援新制度の状況について
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lim lim lim lim 0 0 d lim 5. d 0 d d d d d d 0 0 lim lim 0 d
lim 5. 0 A B 5-5- A B lim 0 A B A 5. 5- 0 5-5- 0 0 lim lim 0 0 0 lim lim 0 0 d lim 5. d 0 d d d d d d 0 0 lim lim 0 d 0 0 5- 5-3 0 5-3 5-3b 5-3c lim lim d 0 0 5-3b 5-3c lim lim lim d 0 0 0 3 3 3 3 3 3
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E115_FAX_J.book
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6 2 2 x y x y t P P = P t P = I P P P ( ) ( ) ,, ( ) ( ) cos θ sin θ cos θ sin θ, sin θ cos θ sin θ cos θ y x θ x θ P
6 x x 6.1 t P P = P t P = I P P P 1 0 1 0,, 0 1 0 1 cos θ sin θ cos θ sin θ, sin θ cos θ sin θ cos θ x θ x θ P x P x, P ) = t P x)p ) = t x t P P ) = t x = x, ) 6.1) x = Figure 6.1 Px = x, P=, θ = θ P
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BD = a, EA = b, BH = a, BF = b 3 EF B, EOA, BOD EF B EOA BF : AO = BE : AE, b : = BE : b, AF = BF = b BE = bb. () EF = b AF = b b. (2) EF B BOD EF : B
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(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0
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1 (1) ( i ) 60 (ii) 75 (iii) 315 (2) π ( i ) (ii) π (iii) 7 12 π ( (3) r, AOB = θ 0 < θ < π ) OAB A 2 OB P ( AB ) < ( AP ) (4) 0 < θ < π 2 sin θ
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知能科学：ニューラルネットワーク
2 3 4 (Neural Network) (Deep Learning) (Deep Learning) ( x x = ax + b x x x ? x x x w σ b = σ(wx + b) x w b w b .2.8.6 σ(x) = + e x.4.2 -.2 - -5 5 x w x2 w2 σ x3 w3 b = σ(w x + w 2 x 2 + w 3 x 3 + b) x,
知能科学：ニューラルネットワーク
2 3 4 (Neural Network) (Deep Learning) (Deep Learning) ( x x = ax + b x x x ? x x x w σ b = σ(wx + b) x w b w b .2.8.6 σ(x) = + e x.4.2 -.2 - -5 5 x w x2 w2 σ x3 w3 b = σ(w x + w 2 x 2 + w 3 x 3 + b) x,
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6AF~60AF A - 6 7-8 9 - - 7 7-8 9-0 - - - 6 7-8 9 - - - 7 8 9-0 - - - 6 7 - - 6 7-8 9 60 6-6 6-68 69-7 6 00 600 000 0 00 000 00 60 AE6-SW AE00-SW AE-SW AE600-SW AE000-SWA AE000-SW AE0-SW AE00-SW AE000-SWA
1 3 1.1.......................... 3 1............................... 3 1.3....................... 5 1.4.......................... 6 1.5........................ 7 8.1......................... 8..............................
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Index ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap. ap.
子ども・子育て支援新制度について
30 Ⅺ Ⅻ 1 . 2 24 3 248 4 5 24 6 7 () ( 教育 保育施設 8 従前どおり 9 20 19. 10 ... 11 12 50 13 14 15 . 16 17 ( 18 () 19 A B ( C D ( ( 20 21 2586 2512 18 2672 22 . 23 3,618 807 592 64 5,08129 24 5,081 3,618 H28 (4,001)
G G 4 G G 1 c1 f 1 2 G G 3 4 123 1 G f123 4
8 1 15 2 G 3 f f A G f A 11 G G 2 G 1 2 f 2 A G C G G 4 G G 1 c1 f 1 2 G G 3 4 123 1 G f123 4 A G G 3 L f 1 G 2 1 3 4 2 G G G G f 1 12 g 2 G G f G g 3 G f 1 2 12 G G 1 1 G G 2 G 1 7 1 2 G 1 G 1 8 1 Gf
70 : 20 : A B (20 ) (30 ) 50 1
70 : 0 : A B (0 ) (30 ) 50 1 1 4 1.1................................................ 5 1. A............................................... 6 1.3 B............................................... 7 8.1 A...............................................
(1) PQ (2) () 2 PR = PR P : P = R : R (2) () = P = P R M = XM : = M : M (1) (2) = N = N X M 161 (1) (2) F F = F F F EF = F E
5 1 1 1.1 2 159 O O PQ RS OR P = PQ P O M MQ O (1) M P (2) P : P R : R () PR P 160 > M : = M : M X (1) N = N M // N X M (2) M 161 (1) E = 8 = 4 = = E = (2) : = 2 : = E = E F 5 F EF F E 5 1 159 (1) PQ (2)
chap1.dvi
1 1 007 1 e iθ = cos θ + isin θ 1) θ = π e iπ + 1 = 0 1 ) 3 11 f 0 r 1 1 ) k f k = 1 + r) k f 0 f k k = 01) f k+1 = 1 + r)f k ) f k+1 f k = rf k 3) 1 ) ) ) 1+r/)f 0 1 1 + r/) f 0 = 1 + r + r /4)f 0 1 f
I ( ) ( ) (1) C z = a ρ. f(z) dz = C = = (z a) n dz C n= p 2π (ρe iθ ) n ρie iθ dθ 0 n= p { 2πiA 1 n = 1 0 n 1 (2) C f(z) n.. n f(z)dz = 2πi Re
I ( ). ( ) () a ρ. f() d ( a) n d n p π (ρe iθ ) n ρie iθ dθ n p { πia n n () f() n.. n f()d πi es f( k ) k n n. f()d n k k f()d. n f()d πi esf( k ). k I ( ). ( ) () f() p g() f() g()( ) p. f(). f() A
さくらの個別指導 ( さくら教育研究所 ) A a 1 a 2 a 3 a n {a n } a 1 a n n n 1 n n 0 a n = 1 n 1 n n O n {a n } n a n α {a n } α {a
... A a a a 3 a n {a n } a a n n 3 n n n 0 a n = n n n O 3 4 5 6 n {a n } n a n α {a n } α {a n } α α {a n } a n n a n α a n = α n n 0 n = 0 3 4. ()..0.00 + (0.) n () 0. 0.0 0.00 ( 0.) n 0 0 c c c c c
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Microsoft Word - ニュース更新システム（サイト用）.docx
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0.6 A = ( 0 ),. () A. () x n+ = x n+ + x n (n ) {x n }, x, x., (x, x ) = (0, ) e, (x, x ) = (, 0) e, {x n }, T, e, e T A. (3) A n {x n }, (x, x ) = (,
[ ], IC 0. A, B, C (, 0, 0), (0,, 0), (,, ) () CA CB ACBD D () ACB θ cos θ (3) ABC (4) ABC ( 9) ( s090304) 0. 3, O(0, 0, 0), A(,, 3), B( 3,, ),. () AOB () AOB ( 8) ( s8066) 0.3 O xyz, P x Q, OP = P Q =
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23 3 (10) - 1 - - 2 - - 3 - - 4 - - 5 - - 6 - 11 12 13 14-7 - - 8 - 1 1 3 3-9 - - 10 - - 11 - - 12 - - 13 - N 3 N 3 N 3-14 - - 15 - ( ) - 16 - 2 3 11 KYTBM - 17 - - 18 - - 19 - - 20 - - 21 - - 22 - ➀
現代社会文化研究
No.37 2006 12 少年非行, 在日本呈上升趋势, 日趋严峻, 且向一般化 低龄化 现代型 非社会的非行转变 少年非行的预防和更生已经成为一个不可忽视的社会问题 为了正确分析少年非行, 找出其原因及预防和更生对策, 首先必须明确少年非行的概念以确定研究对象以及研究范围 关于少年非行的概念, 从不同的根据, 不同的角度出发, 内容会有所不同 本文从法理上对少年非行和非行少年及相关概念进行了界定,
1122 1015 1 Voices 11 11 1 1 1 1 1 1 7 3 4 3 4 3 4 1 1 1 1 1 e 1 f dd 1 d 1 1 1 1 de 1 f 1 d b b bb ef f bb 1 1 882-1111 882-1160 1 1 a 6 1 1 1 f 1 1 c 1 f 1 1 f 1 cf 1 bf 1 1 1 1 a 1 g 1 g 1 af g 1 11
Taro13-①表紙関係.jtd
39 03 04 05 -- -2- ?? A A D = A B C A2 HI H = DG BC B = A G = EF C E = A I = H F = AE -39- 2 3 0.8 n n n n n 0.8 n n 0.8 n 70 30 00 70 30 70 30 00 250 250 200 bn 400
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18 10 01 ( ) 1 2018 4 1.1 2018............................... 4 1.2 2018......................... 5 2 2017 7 2.1 2017............................... 7 2.2 2017......................... 8 3 2016 9 3.1 2016...............................
() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)
0. A A = 4 IC () det A () A () x + y + z = x y z X Y Z = A x y z ( 5) ( s5590) 0. a + b + c b c () a a + b + c c a b a + b + c 0 a b c () a 0 c b b c 0 a c b a 0 0. A A = 7 5 4 5 0 ( 5) ( s5590) () A ()
1 26 ( ) ( ) 1 4 I II III A B C (120 ) ( ) 1, 5 7 I II III A B C (120 ) 1 (1) 0 x π 0 y π 3 sin x sin y = 3, 3 cos x + cos y = 1 (2) a b c a +
6 ( ) 6 5 ( ) 4 I II III A B C ( ) ( ), 5 7 I II III A B C ( ) () x π y π sin x sin y =, cos x + cos y = () b c + b + c = + b + = b c c () 4 5 6 n ( ) ( ) ( ) n ( ) n m n + m = 555 n OAB P k m n k PO +
I y = f(x) a I a x I x = a + x 1 f(x) f(a) x a = f(a + x) f(a) x (11.1) x a x 0 f(x) f(a) f(a + x) f(a) lim = lim x a x a x 0 x (11.2) f(x) x
11 11.1 I y = a I a x I x = a + 1 f(a) x a = f(a +) f(a) (11.1) x a 0 f(a) f(a +) f(a) = x a x a 0 (11.) x = a a f (a) d df f(a) (a) I dx dx I I I f (x) d df dx dx (x) [a, b] x a ( 0) x a (a, b) () [a,
1 θ i (1) A B θ ( ) A = B = sin 3θ = sin θ (A B sin 2 θ) ( ) 1 2 π 3 < = θ < = 2 π 3 Ax Bx3 = 1 2 θ = π sin θ (2) a b c θ sin 5θ = sin θ f(sin 2 θ) 2
θ i ) AB θ ) A = B = sin θ = sin θ A B sin θ) ) < = θ < = Ax Bx = θ = sin θ ) abc θ sin 5θ = sin θ fsin θ) fx) = ax bx c ) cos 5 i sin 5 ) 5 ) αβ α iβ) 5 α 4 β α β β 5 ) a = b = c = ) fx) = 0 x x = x =
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A(6, 13) B(1, 1) 65 y C 2 A(2, 1) B( 3, 2) C 66 x + 2y 1 = 0 2 A(1, 1) B(3, 0) P 67 3 A(3, 3) B(1, 2) C(4, 0) (1) ABC G (2) 3 A B C P 6
1 1 1.1 64 A6, 1) B1, 1) 65 C A, 1) B, ) C 66 + 1 = 0 A1, 1) B, 0) P 67 A, ) B1, ) C4, 0) 1) ABC G ) A B C P 64 A 1, 1) B, ) AB AB = 1) + 1) A 1, 1) 1 B, ) 1 65 66 65 C0, k) 66 1 p, p) 1 1 A B AB A 67
