NEWS 2012 WINTER 134 No.
F=maF ma m af Contents
N, X
θ 1,θ 2 θ N 0θ i π/2 X i X 0 Θ i Θ 1 = 2θ 1 Θ 2 = 2(θ 1 θ 2) NX N X 0 Θ N N Θ N = 2{θ 1 θ 2θ 3 θ N } Θ N = 2π A 1A 2B 2B 1 mm 3 α α = π /m A 1A 2B 2 B 2 β A 1A 2 m A 1, A 2 B 2 B 2 B 2 R 1, R 2 R 1R 2 B 2 β π /4π /2m β π /2π /m B 2 R 0R 1 β β A 1A 2B
x = xσ (x) Δxx=x+Δx σ (x+δx) σ (x)+ (dσ/dx)δx x = x