Vol.57A (11 3 ) RC Consecutve falling-weight impact test of large-scale RC girders under specified total input-impact energy * ** *** **** ***** Norimitsu Kishi, Hisashi Konno, Satoru Yamaguchi, Hiroshi Mikami, Miho Tamaki * 5-8585 27-1 ** ( ) 62-862 1-3 *** 62-862 1-3 **** ( ) 27-132 518-1 ***** 5-8585 27-1 In order to establish a performance-based impact resistant design procedure for reinforced concrete structures, consecutive falling-weight impact loading tests were conducted under specified total input-impact energy. In this experiment, the girders have rectangular cross section of 1 m width and depth, and 8 m clear-span length. A 2, kg steel weight was used and total inputimpact energy was specified as 196 kj. Three kinds of falling height of weight were set: 3.33 m; 5 m; and m. From this study, following results were obtained: (1) maximum and residual deflections were almost constant values for each input-impact energy; (2) deflections after the final loading were almost the same among all girders; and (3) accumulated residual deflections were proportional to the accumulated input-impact energy and the damage of the girder for each limit state can be precisely evaluated by means of this relationship. Key Words : RC girder, consecutive impact loading, input-impact energy, maximum deflection, residual deflection, accumulated residual deflection : RC 1. 1),2) RC RC 3) RC 4) RC --
12mm D13@25 C L P P : R=R-1+R-2 : D-1 D-6 : D-1 D-2 D-3 D-4 D-5 D-6 9 4@125 =5 9 7 1, 5 R-1 D25 8, R-2 5 9, 16 68 1, 16 (mm) 1 RC RC 5) 6) 7) 8) RC RC 9) RC ) 11) RC 1 p t a/d P usc (kn) V usc (kn) α 42 4.71 6 1,369 2.28 2 (MPa) (GPa) ν c 29 26.2 16.3.3 3 σ y (MPa) E s (GPa) ν s D13 SD3 389 6.3 D25 SD3 6.3 2. RC 2.1 RC 1m 1m 8m 1 RC.42 %D25 7 5 % D25 4-16-
4 H(m) E(kJ) G1 3.33 3 196 G2 5. 2 196 G3 1 1 196 (a) 1 mm 1/2 D13 25 mm 1 α =2.28 12 mm P R D-1 mm D-2 D-6 1 RC P usc V usc 12) α = V usc /P usc > 1. 2 3 2.2 2, kg RC (b) 2 1 1m 97 cm 8 cm RC 2(a) 2(b) 5 mm 4 196 kj G1 3.33 m 3 G2 5m 2 G3 m m P R D i (i = 1 6) 1kHz 1, G -17-
1kHz 1,5 kn 9 Hz mm.1 ms.5 ms 3. 3.1 2 2(a) 25 ms 5ms H = m G3--1 12 MN G2 2 1 G1 3 3 G2 2(b) H = 5m m G2/3 H = 3.3mG1 ms 1 2(c) H = 5m G2-5- 2 D-1 G1/2,, G3--1 G3--1 3-18-
(MN) (MN) - - - - - (MN) (MN) - - - - - D-1 D-2 D-3 D-4 D-5 D-6 3-3 - 3 - (mm) (mm) 6 3-6 3 - (MN) G3--1 - -5 5 25 (ms) (a) (MN) 8 G3--1 6 G3--1 - -5 5 25 - - 3 5 (ms) (b) (mm) (ms) (c) 2 3.2 3 H = 3.33 m G1 1 2 3 H = 5m G2 H = 3.33 m G1 2-19-
1 2 3 1 2 3 (a) G1 (a) G1 (b) G2 (b) G2 G3--1 G3--1 (c) G3 (c) G3 3 4 H = 3.33 m 2 H = m G3 G1 G2 1 2 3.3 4 X E = 196 kj X 3.4 5-11-
13.5 (MN).5 7.5 (MN) 2.8 2.6 2.4 2.2 2. G3--1 G3--1 (a) (b) 5 (mm) 6 3 (mm) 6 3 (mm) 6 3 G3--1 G3--1 G3--1 (a) D-1 (b) D-2 (c) D-3 6 5 5 5 (mm) 3 (mm) 3 3 G3--1 G3--1 (mm) G3--1 (a) D-1 (b) D-2 (c) D-3 7-1111-
3.5 6, 7 D-1 D-3 ) 1 2 8 7 E = 196 kj,, G3--1 D-1/3 G1 G2 G3 D-2 E = 196 kj 3.6 9 D-1 D-3 RC 3),4) α def =.387E, α rs =.2E α def α rs mm/kj E kj 4) α rs = 4β/P usc (1) β =.288 lnr M +.965 (2) W : (kg) B : (kg) r M W/B β r M α rs r M =.4 P usc = 6 kn α rs =.216 (α def /α rs ) 1.8 3.7 D-1 D-3 9 4. RC RC 8m RC 2, kg 196 kj 3.33 m 5 m -1112-
5 5 5 (mm) 3 (mm) 3 (mm) 3 G3--1 G3--1 G3--1 (a) D-1 (b) D-2 (c) D-3 8 G3--1 G3--1 6 6 6 (mm) 3 (mm) 3 (mm) 3 65.3 98. 19 65.3 98. 19 65.3 98. 19 E (kj) E (kj) E (kj) (a) D-1 (b) D-2 (c) D-3 9 (mm) 6 3 G3--1 (mm) 6 3 65.3 98. 13.7 19 65.3 98. 13.7 19 65.3 98. 13.7 19 E (kj) E (kj) E (kj) (a) D-1 (b) D-2 (c) D-3 (mm) 6 3-1113-
m 3, 2, 1 1) 2) 3) 4) 5) 1) 52 7. 2) RC No. 647/I-51, pp. 177-19,. 3) RC Vol. 53A, pp. 1251-126, 7. 4) RC Vol. 54A, pp. 77-88, 8. 5) RC Vol. 55A, pp. 1366-13, 9. 6) Vol. 29, No. 3, pp. 739-744, 7. 7) Vol. 31, No. 2, pp. 799-84, 9. 8) Vol. 32, No. 2, pp. 7-7,. 9) RC Vol. 51A, pp. 1695-176, 5. ) RC Vol. 55A, pp. 1225-1238, 7. 11) RC Vol. 56A, pp. 1137-1148,. 12) 2 2. ( 9 16 ) -1114-