é éτ Γ ζ ä



Similar documents
é éτ Γ ζ ä

(ANAGISAWA Daichi) (NISHINARI Katsuhiro) 1 1 Helbing Social Force Model [1] Social Force Social Force [2][3] [3] 1

PL2N.K*1k[o=] SMd"kZlR &2gX})X&fJ 27 / 2 n 25 5W 2o`N?3R,PL*+DS>*K.lF$kOGN"/i9?js".lNZj".lNi$U?$`"b)YhGN[o=]rtM7_el<7gsGrO7?# 1 O8aK


九州大学学術情報リポジトリ Kyushu University Institutional Repository ソリトンの二次元相互作用について 及川, 正行九州大学応用力学研究所 辻, 英一九州大学応用力学研究所 Oikawa, Masayuki Research Institute for A

<8CA48B8694EF8E E E816991E C5816A5F8DC58F4994C52E706466>

平成16年度標準技術集


untitled

演題

’¸’_Ł\”ƒ1-4fiñŒÊ


NOW-PDFŠp

vv#46jp

渦 輪 を 用 いた 渦 のつなぎ 換 え 実 験 横 浜 国 立 大 学 工 学 府 松 村 直 樹 (MATSUMURA Naoki) 横 浜 国 立 大 学 工 学 研 究 院 渡 辺 慎 介 (WATANABE Shinsuke) 同 じ 方 向 に 進 む 二 つの 渦 輪 の 相 互 作

No.26AO-S2 Reports of RIAM Symposium No.26AO-S2 State of arts and perspectives of nonlinear wave science Proceedings of a symposium held at Chikushi C

all.pdf

shinkenmi-183-p1-20

Japan Arts Fund

163 KdV KP Lax pair L, B L L L 1/2 W 1 LW = ( / x W t 1, t 2, t 3, ψ t n ψ/ t n = B nψ (KdV B n = L n/2 KP B n = L n KdV KP Lax W Lax τ KP L ψ τ τ Cha



プログラム 3日目:11月16日(日曜日)

0428_HP用.pdf

2 252

2 266

00_SRC News No.75.qxd

歴史におけるアイデンティティの諸相 : 課題と方法

セゾン保険_PDF用.indd

CD納品用.indd

独身女性の生命保険加入実態

平成16年度標準技術集 電子ペーパー及びフレキシブルディスプレイ

B1 B2 N

2016 Institute of Statistical Research


独身男性の生命保険加入実態

kikin2_web.pdf

No.18SP1-4 Reports of RIAM Symposium No.18SP1-4 Study on features and generation mechanisms of freak waves II Proceedings of a symposium held at Resea

mr0511_01fix.indd

広報さかき2006年11月号-18p.indd


bangumi1411



untitled

LabFabChemicals2014_Apr_ pdf

保証月報04.indd

untitled

untitled


TRUTH2012w_01-11_0118

é é ô

untitled

橡07第1章1_H160203_.PDF

tnbp59-17_Web:プO1/ky079888509610003201


総務省「平成20年度 地域力創造事例集」

「北米音楽進出ハンドブック」(抜粋)

02

1

日経テレコン料金表(2016年4月)

B

73 p p.152


Microsoft Word - 田中亮太郎.doc

_Print

122011pp

p

スラヴ_00A巻頭部分

Microsoft Word - 映画『東京裁判』を観て.doc

9

() L () 20 1

戦後の補欠選挙

2

A p A p. 224, p B pp p. 3.

308 ( ) p.121

広報かみす 平成28年6月15日号

.



2 74



untitled

untitled


untitled

さぬきの安全2016-cs5-出力.indd

看護学科案内'16/表紙

TK747取扱説明書


149 (Newell [5]) Newell [5], [1], [1], [11] Li,Ryu, and Song [2], [11] Li,Ryu, and Song [2], [1] 1) 2) ( ) ( ) 3) T : 2 a : 3 a 1 :

住宅(本文、図表)

CERI NEWS

CHUO UNIVERSITY 3

2

C79 A11 A12 A13 A19 B11 B12 B13 B14 B15 B19 B21 B22 B23 B24 B25 C11 C12 C19 C21 C31 C32 C33 C34 C35 C36 C37 C39 C41 C51 C52 C53 C54 C55 C61 ( ) C62 C6

大 気 海 洋 研 究 所 創 立 50 年 を 迎 えて

九大広報第61号

2 Bulletin

Transcription:

é éτ Γ ζ ä

é

é

éτ Γ ζ ä \\ é

\

No.16ME-S1 Reports of RIAM Symposium No.16ME-S1 Physics and Mathematical Structures of Nonlinear Waves Proceedings of a symposium held at Chikushi Campus, Kyushu Universiy, Kasuga, Fukuoka, Japan, November 15-17, 2004 Article No. 9 HIROTA RyogoTAKAHASHI Daisuke Received February 23, 2005 Research Institute for Applied Mechanics Kyushu University April, 2005

(Ryogo Hirota), (Daisuke Takahashi) 1 u m+1 1 n+1 u m n = δ(u m+1 n u m n+1) a) b) implicit KdV, KP explicit 1. 2. 3. 4. m, n 1 u m+1 1 n+1 u m n = δ(u m+1 n u m n+1) 1

δ BBB (Back ultradiscretized Box and Ball system) Satoshi Tujimoto and Ryogo Hirota, Ultradiscrete KdV Equations, J. Phys. Soc.Jpn. 67(1998) pp.1809-1810 Discrete KdV equation 1 1 u m+1 n u m n = δ(u m+1 n 1 u m n+1) m + n n BBB 1 u m+1 1 n+1 u m n = δ(u m+1 n u m n+1) u m n = f n m+1 fn+1 m fn m f m+1 n+1 fn+1 m+1 fn m 1 δfn m+1 f m 1 n+1 c 0 f m n+1f m n = 0 c 0 c 0 = 1 δ f m n f m n g(n), g(n) n Discrete KdV m + n n n m f(m, n) = 1 + e ξ 1 + e ξ 2 + a 12 e ξ 1+ξ 2, e ξ j = r j p n j q m j, q j = 1 δp j, for j = 1, 2, p j δ a 12 = (p 1 p 2 ) 2 (p 1 p 2 1) 2 p j q j p j = 1 + δq j q j + δ, a 12 = (q 1 q 2 ) 2 (q 1 q 2 1) 2. 2

U m n U m n = F m+1 n + F m n+1 F m n F m+1 n+1, F m n = max(0, Ξ 1, Ξ 1, A 12 + Ξ 1 + Ξ 2 ), Ξ j = P j n Q j m c j, for j = 1, 2. P j = max(q j, 1) max(0, Q j 1), A 12 = Q 1 Q 2 Q 1 + Q 2. P = max(q, 1) max(0, Q 1) Q 1 = 2, Q 2 = 1 {0,0,1,1,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0} {0,0,0,0,1,1,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0} {0,0,0,0,0,0,1,1,0,0,0,1,0,0,0,0,0,0,0,0,0} {0,0,0,0,0,0,0,0,1,1,0,0,1,0,0,0,0,0,0,0,0} {0,0,0,0,0,0,0,0,0,0,1,1,0,1,0,0,0,0,0,0,0} {0,0,0,0,0,0,0,0,0,0,0,0,1,0,1,1,0,0,0,0,0} {0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,1,1,0,0,0} Q 1 := 5/2, Q 2 := 1 1/2 3

{0,0,1/2,1,1,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0} {0,0,0,0,0,1,1,1/2,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0} {0,0,0,0,0,0,0,1/2,1,1,0,0,0,1,0,0,0,0,0,0,0,0,0} {0,0,0,0,0,0,0,0,0,0,1,1,1/2,0,1,0,0,0,0,0,0,0,0} {0,0,0,0,0,0,0,0,0,0,0,0,1/2,1,0,1,1,0,0,0,0,0,0} {0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,1,1,1/2,0,0,0} {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,1/2,1,1,0} BBB u m+1 n = x n, u m n+1 + 1 δu m n = a n, 1 δ = b j BBB x j = a j b j+1 x j+1, for j = 0, 1, 2,. (x j+n = x j, j = 0, 1, ) x j BBB u m+1 j = u m j u m j 1 + N 1 k 1 { k s=1 δ(u m j s) 2 }u m j k 1 u m j + N 1 k 1 { k s=1 δ(u m j+1 s) 2 }u m j k or u m+1 n = 1 δu m n+1 ( 10) 4

{0,0,0,0,1,0,0,0,1,1} {1,1,0,0,0,1,0,0,0,0} {0,0,1,1,0,0,1,0,0,0} {0,0,0,0,1,1,0,1,0,0} {0,0,0,0,0,0,1,0,1,1} {1,1,0,0,0,0,0,1,0,0} {0,0,1,1,0,0,0,0,1,0} {0,0,0,0,1,1,0,0,0,1} {1,0,0,0,0,0,1,1,0,0} 4 6 {1,0,0,1,1,1,0,0,0,0} {0,1,0,0,0,0,1,1,1,0} {1,0,1,1,0,0,0,0,0,1} {0,1,0,0,1,1,1,0,0,0} {0,0,1,0,0,0,0,1,1,1} {1,1,0,1,1,0,0,0,0,0} {0,0,1,0,0,1,1,1,0,0} {1,0,0,1,0,0,0,0,1,1} {0,1,1,0,1,1,0,0,0,0} {0,0,0,1,0,0,1,1,1,0} 7 3 {1,1,1,0,0,1,1,0,1,1} {1,0,0,1,1,1,0,1,1,1} {0,1,1,1,1,0,1,1,1,0} {1,1,1,1,0,1,1,0,0,1} {1,1,1,0,1,0,0,1,1,1} {1,0,0,1,0,1,1,1,1,1} {0,1,1,0,1,1,1,1,1,0} {1,1,0,1,1,1,1,0,0,1} {1,0,1,1,1,0,0,1,1,1} {0,1,1,0,0,1,1,1,1,1} {1,0,1,1,1,1,1,1,1,1} {0,1,1,1,1,1,1,1,1,1} {1,1,1,1,1,1,1,1,1,0} {1,1,1,1,1,1,1,1,0,1} {1,1,1,1,1,1,1,0,1,1} {1,1,1,1,1,1,0,1,1,1} {1,1,1,1,1,0,1,1,1,1} {1,1,1,1,0,1,1,1,1,1} {1,1,1,0,1,1,1,1,1,1} 5

( 10) ( 12) (-1) (-2) {0,0,1,1,0,0,0,-1,0,0,1,0,0,0,0} {0,0,0,0,1,1,0,0,-1,0,0,1,0,0,0} {0,0,0,0,0,0,1,1,0,-1,0,0,1,0,0} {0,0,0,0,0,0,0,0,1,1,-1,0,0,1,0} {0,0,0,0,0,0,0,0,0,0,2,-1,0,0,1} {1,0,0,0,0,0,0,0,0,0,-1,2,0,0,0} {0,1,0,0,0,0,0,0,0,0,0,-1,1,1,0} {1,0,1,0,0,0,0,0,0,0,0,0,-1,0,1} {0,1,0,1,1,0,0,0,0,0,0,0,0,-1,0} {0,0,1,1,0,0,-2,0,0,1,0,0} {0,0,0,0,1,1,0,-2,0,0,1,0} {0,0,0,0,0,0,1,1,-2,0,0,1} {1,0,0,0,0,0,0,0,2,-2,0,0} {0,1,0,0,0,0,0,0,-1,3,-2,0} {0,0,1,0,0,0,0,0,0,-2,3,-1} {0,0,0,1,0,0,0,0,0,0,-2,2} {1,1,0,0,1,0,0,0,0,0,0,-2} {-2,0,1,1,0,1,0,0,0,0,0,0} 1. 1 u m+1 1 n+1 u m n = δ(u m+1 n u m n+1) 2. 3. Yes,! 6