BD = a, EA = b, BH = a, BF = b 3 EF B, EOA, BOD EF B EOA BF : AO = BE : AE, b : = BE : b, AF = BF = b BE = bb. () EF = b AF = b b. (2) EF B BOD EF : B
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1 p q θ = 80 B E a H F b θ/2 O θ/2 D A B E
2 BD = a, EA = b, BH = a, BF = b 3 EF B, EOA, BOD EF B EOA BF : AO = BE : AE, b : = BE : b, AF = BF = b BE = bb. () EF = b AF = b b. (2) EF B BOD EF : BO = BE : DB, EF : = BE : a, BE = a EF. (3) (), (2), (3) bb = a(b b ), b = ab a + b. (4) 2 F BH, ABD BF : BA = BH : BD, b : BA = a : a BA = 2a 2(a ) 2 = ab, ab a = 2. (5) BB = 2a p = 2a EE = 2b q = 2b 2 AB = 2a p 2 = (2)(2a ) 2BF = 2b q 2 = (2)(2b ) (4), (5) p, q, p 2, q 2 q 2 = 4 (2) 2 p q (2) (p + q ) = 2p q, (6) p + q p 2 = 4 2 (2) p (4) q 2 = p q 2. (7) = 6 p 6 = 6, q 6 = 4 3 (6) q 2 = = 24(2 3). (7) p 2 = 6 24(2 3) =
3 = 2, < π < 3.253, = 24, < π < 3.596, = 48, < π < 3.460, = 96, 3.40 < π < 3.427, = 92, 3.44 < π < π E B G O θ D A G B E 6 a BB = a OAB 2 OA BD = ( ) 2 2 a = 4 a s 2 = (2)(a /4) = a /2 ( ABB ) = ( OAB ) 2 ( OBB ) 3
4 (5 OBGG B ) = ( OAB ) 2 + ( ABB ) = ( OAB ) 4 ( OBB ) ( ) < 4 ( OAB ) ( OBB ) = 2s 2 s, s 2 < ( ) < s 2 + (s 2 s ) p = a s 2 = p /2 2 p < ( ) < 2 p + 2 (p p /2 ) π π a 2 a OD = (a /2) 2, AD = OD AB = BD 2 + AD 2 = (a /2) 2 + ( (a /2) 2 ) 2 = 2 4 a 2. AB = a 2 a 2 = 2 4 a 2. (8) (8) = 6 a 6 = a 2 = 2 3 (8) a 24 = , a 48 = , a 96 = , a 92 = ,. 4
5 s 24 = = 3.326, s 48 = = 3.393, s 96 = = 3.40, s 92 = = 3.45, < π < < π < = = x = si θ π 2 θ π 2 θ = arcsi x x x = si θ π 2 θ π 2 θ arcsi x x = ta θ π 2 < θ < π 2 θ = arcta x < x < x = ta θ π 2 < θ < π 2 θ arcta x x = si θ dx dθ = cos θ = si 2 θ = x 2 d dθ arcsi x = dx dx = x 2 5 (9)
6 x = ta θ dx dθ = cos 2 θ = + ta2 θ = + x 2 d dθ arcta x = dx dx = (0) + x 2 x < + x 2 = x2 + x 4 x 6 + = ( ) x 2 (0) arcta x = C + x x3 3 + x5 5 x7 7 + = C + ( ) x x = 0 C = arcta 0 = 0 arcta x arcta x = x x3 3 + x5 5 x7 7 + = ( ) x () x < x = ta π = 4 arcta = π 4 () x = π 4 = = ( ) 2 + (2) ta x ta(α + β) = ta 2α = ta α + ta β ta α ta β 2 ta α ta 2 α α = arcta 5 ta 2α = 2 ta α ta 2 α =
7 ta 4α = 2 ta 2α ta 2 2α = β = 4α π 4 ta β = ta 4α + ta 4α = 239. β = arcta 239 π 4 = 4α β = 4 arcta 5 arcta 239. () (704 ) π 4 = 4 ( ) (2 + )5 ( ) (3) 2+ (2 + ) (2) = 4 π = arcta x arcsi x 2 a ( + x) a = a ( ) a x, ( ) a = a C = a(a ) (a + ),! ( ) ( ) a a = a a 0 a = /2 ( ) 2 = ( )( 3 2 ) ( ) (2 )(2 3) 3 = ( ),! 2! ( /2 ) ( /2 ) x x < ( + x) /2 + x = + (2 )(2 3) 3 ( ) x. 2! = x x 2 = + x 2 = (2 )(2 3) 3 x 2. 2! 7
8 (9) arcsi x = x + = (2 )(2 3) 3 x 2+ (4) 2 (2 + )! si π = 6 2 arcsi = π 2 6 (4) x = /2 π 6 = 2 + = (2 )(2 3) (2 + )! (5) = 3 π = 3.4 (5) π 6 (665 ) (2) (5) (739 ) 49 π 4 (83 ) α (α; ) = α(α + ) (α + ) (α; 0) = α, β, γ 0,, 2,... x < F (α, β, γ; x) = (α; )(β; ) x (6) (γ; )! F (α, β, γ; x) α, β, γ (α; ) ( ) α F (α, β, β; x) = x = x = ( + x) α,! xf (,, 2; x) =!! ( + )!! x+ = 8 + x+ = log( x),
9 ( xf 2,, 3 ) 2 ; x2 = 2 + ( ) x 2+ = arcta x. F (α, β, γ; x) = F (α, β +, γ + ; x) F (α, β, γ; x) = F (α +, β, γ + ; x) α(γ β) xf (α +, β +, γ + 2; x), (7) γ(γ + ) β(γ α) xf (α +, β +, γ + 2; x). (8) γ(γ + ) (7) F (α, β +, γ + ; x) F (α, β, γ; x) F (α, β +, γ + ; x) = α(γ β) γ(γ + ) x F (α, β +, γ + ; x) F (α +, β +, γ + 2; x) (8) (α, β, γ) (α, β +, γ + ) F (α +, β +, γ + 2; x) F (α, β +, γ + ; x) F (α +, β +, γ + 2; x) F (α, β, γ; x) F (α, β +, γ + ; x) = = (β + )(γ + α) (γ + )(γ + 2) x α(γ β) x γ(γ+) (β+)(γ+ α) x (γ+)(γ+2) F (α+,β+,γ+2;x) F (α+,β+2,γ+3;x) F (α+,β+,γ+2;x) F (α+,β+2,γ+3;x)... F (α, β, γ; x) F (α, β +, γ + ; x) = a x a 2 x... a 2ν x F (α+ν,β+ν,γ+2ν;x) F (α+ν,β+ν+,γ+2ν+;x). (α + )(γ + β) a 2 = (γ + 2 2)(γ + 2 ), a (β + )(γ + α) 2 = (γ + 2 )(γ + 2),. 9
10 α = γ =, β = 0 2 F (/2, 0, /2; x2 ) =, xf (/2,, 3/2; x 2 ) = arcta x x arcta x = + a x 2 a 2 x a 2ν x 2 F (ν+/2,ν,2ν+/2; x 2 ) F (ν+/2,ν+,2ν+3/2; x 2 ) (2 ) 2 a 2 = (4 3)(4 ), a (2) 2 2 = (4 )(4 + ),. a = 2 (2 )(2 + ), ν arcta x. arcta x = x x 2 3 (2x) (3x) (x) 2 (2 )(2+)... = x x 2 (2x) 2 (3x) (9) 2 + (x)2... 0
11 (9) x = arcta = π 4 π π = (20) {A }, {B } A = (2 + )A + 2 A 2, = 2, 3,..., A = 3, A 2 = 9, B = (2 + )B + 2 B 2, = 2, 3,..., B =, B 2 = 6. A B = = 5 π A B A /B / / / / A 2 /B 2 = / =
12 3 2 ( 96 ) ( 92 ) ( ) 737 ( ) 67 ( ) 674 ( ) ( ) ( ) 83 [],,, 999. [2],,,
1 1 3 ABCD ABD AC BD E E BD 1 : 2 (1) AB = AD =, AB AD = (2) AE = AB + (3) A F AD AE 2 = AF = AB + AD AF AE = t AC = t AE AC FC = t = (4) ABD ABCD 1 1
ABCD ABD AC BD E E BD : () AB = AD =, AB AD = () AE = AB + () A F AD AE = AF = AB + AD AF AE = t AC = t AE AC FC = t = (4) ABD ABCD AB + AD AB + 7 9 AD AB + AD AB + 9 7 4 9 AD () AB sin π = AB = ABD AD
第86回日本感染症学会総会学術集会後抄録（I）
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.1 A cos 2π 3 sin 2π 3 sin 2π 3 cos 2π 3 T ra 2 deta T ra 2 deta T ra 2 deta a + d 2 ad bc a 2 + d 2 + ad + bc A 3 a b a 2 + bc ba + d c d ca + d bc +
.1 n.1 1 A T ra A A a b c d A 2 a b a b c d c d a 2 + bc ab + bd ac + cd bc + d 2 a 2 + bc ba + d ca + d bc + d 2 A a + d b c T ra A T ra A 2 A 2 A A 2 A 2 A n A A n cos 2π sin 2π n n A k sin 2π cos 2π
取扱説明書 -詳細版- 液晶プロジェクター CP-AW3019WNJ
B A C D E F K I M L J H G N O Q P Y CB/PB CR/PR COMPONENT VIDEO OUT RS-232C LAN RS-232C LAN LAN BE EF 03 06 00 2A D3 01 00 00 60 00 00 BE EF 03 06 00 BA D2 01 00 00 60 01 00 BE EF 03 06 00 19 D3 02 00
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, 1. x 2 1 = (x 1)(x + 1) x 3 1 = (x 1)(x 2 + x + 1). a 2 b 2 = (a b)(a + b) a 3 b 3 = (a b)(a 2 + ab + b 2 ) 2 2, 2.. x a b b 2. b {( 2 a } b )2 1 =
x n 1 1.,,.,. 2..... 4 = 2 2 12 = 2 2 3 6 = 2 3 14 = 2 7 8 = 2 2 2 15 = 3 5 9 = 3 3 16 = 2 2 2 2 10 = 2 5 18 = 2 3 3 2, 3, 5, 7, 11, 13, 17, 19.,, 2,.,.,.,?.,,. 1 , 1. x 2 1 = (x 1)(x + 1) x 3 1 = (x 1)(x
HITACHI 液晶プロジェクター CP-AX3505J/CP-AW3005J 取扱説明書 -詳細版- 【技術情報編】
B A C E D 1 3 5 7 9 11 13 15 17 19 2 4 6 8 10 12 14 16 18 H G I F J M N L K Y CB/PB CR/PR COMPONENT VIDEO OUT RS-232C LAN RS-232C LAN LAN BE EF 03 06 00 2A D3 01 00 00 60 00 00 BE EF 03 06 00 BA D2 01
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(1) 3 A B E e AE = e AB OE = OA + e AB = (1 35 e ) e OE z 1 1 e E xy e = 0 e = 5 OE = ( 2 0 0) E ( 2 0 0) (2) 3 E P Q k EQ = k EP E y 0
(1) 3 A B E e AE = e AB OE = OA + e AB = (1 35 e 0 1 15 ) e OE z 1 1 e E xy 5 1 1 5 e = 0 e = 5 OE = ( 2 0 0) E ( 2 0 0) (2) 3 E P Q k EQ = k EP E y 0 Q y P y k 2 M N M( 1 0 0) N(1 0 0) 4 P Q M N C EP
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4 4 5 4 I II III A B C, 5 7 I II A B,, 8, 9 I II A B O A,, Bb, b, Cc, c, c b c b b c c c OA BC P BC OP BC P AP BC n f n x xn e x! e n! n f n x f n x f n x f k x k 4 e > f n x dx k k! fx sin x cos x tan
2 (1) a = ( 2, 2), b = (1, 2), c = (4, 4) c = l a + k b l, k (2) a = (3, 5) (1) (4, 4) = l( 2, 2) + k(1, 2), (4, 4) = ( 2l + k, 2l 2k) 2l + k = 4, 2l
ABCDEF a = AB, b = a b (1) AC (3) CD (2) AD (4) CE AF B C a A D b F E (1) AC = AB + BC = AB + AO = AB + ( AB + AF) = a + ( a + b) = 2 a + b (2) AD = 2 AO = 2( AB + AF) = 2( a + b) (3) CD = AF = b (4) CE
(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0
1 1 1.1 1.) T D = T = D = kn 1. 1.4) F W = F = W/ = kn/ = 15 kn 1. 1.9) R = W 1 + W = 6 + 5 = 11 N. 1.9) W b W 1 a = a = W /W 1 )b = 5/6) = 5 cm 1.4 AB AC P 1, P x, y x, y y x 1.4.) P sin 6 + P 1 sin 45
1 26 ( ) ( ) 1 4 I II III A B C (120 ) ( ) 1, 5 7 I II III A B C (120 ) 1 (1) 0 x π 0 y π 3 sin x sin y = 3, 3 cos x + cos y = 1 (2) a b c a +
6 ( ) 6 5 ( ) 4 I II III A B C ( ) ( ), 5 7 I II III A B C ( ) () x π y π sin x sin y =, cos x + cos y = () b c + b + c = + b + = b c c () 4 5 6 n ( ) ( ) ( ) n ( ) n m n + m = 555 n OAB P k m n k PO +
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HITACHI 液晶プロジェクター CP-EX301NJ/CP-EW301NJ 取扱説明書 -詳細版- 【技術情報編】 日本語
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2007 I II III 1, 2, 3, 4, 5, 6, 7 5 10 19 (!) 1938 70 21? 1 1 2 1 2 2 1! 4, 5 1? 50 1 2 1 1 2 2 1?? 2 1 1, 2 1, 2 1, 2, 3,... 3 1, 2 1, 3? 2 1 3 1 2 1 1, 2 2, 3? 2 1 3 2 3 2 k,l m, n k,l m, n kn > ml...?
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n 2 + π2 6 x [10 n x] x = lim n 10 n n 10 k x 1.1. a 1, a 2,, a n, (a n ) n=1 {a n } n=1 1.2 ( ). {a n } n=1 Q ε > 0 N N m, n N a m
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量子力学 問題
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() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)
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ORIGINAL TEXT I II A B 1 4 13 21 27 44 54 64 84 98 113 126 138 146 165 175 181 188 198 213 225 234 244 261 268 273 2 281 I II A B 292 3 I II A B c 1 1 (1) x 2 + 4xy + 4y 2 x 2y 2 (2) 8x 2 + 16xy + 6y 2
O1-1 O1-2 O1-3 O1-4 O1-5 O1-6
O1-1 O1-2 O1-3 O1-4 O1-5 O1-6 O1-7 O1-8 O1-9 O1-10 O1-11 O1-12 O1-13 O1-14 O1-15 O1-16 O1-17 O1-18 O1-19 O1-20 O1-21 O1-22 O1-23 O1-24 O1-25 O1-26 O1-27 O1-28 O1-29 O1-30 O1-31 O1-32 O1-33 O1-34 O1-35
極限
si θ = ) θ 0 θ cos θ θ 0 θ = ) P T θ H A, 0) θ, 0 < θ < π ) AP, P H A P T PH < AP < AT si θ < θ < ta θ si θ < θ < si θ cos θ θ cos θ < si θ θ < θ < 0 θ = h θ 0 cos θ =, θ 0 si θ θ =. θ 0 cos θ θ θ 0 cos
N cos s s cos ψ e e e e 3 3 e e 3 e 3 e
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漸化式のすべてのパターンを解説しましたー高校数学の達人・河見賢司のサイト
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