lim lim lim lim 0 0 d lim 5. d 0 d d d d d d 0 0 lim lim 0 d

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1 lim 5. 0 A B 5-5- A B lim 0 A B A 5. 5-

2 lim lim lim lim 0 0 d lim 5. d 0 d d d d d d 0 0 lim lim 0 d

3 b 5-3c lim lim d b 5-3c lim lim lim d lim lim lim d d d d d n n n d 3 n 0,,, n 0 5-3

4 d / lo nturl ln lo 5.4 d lo 5.4b d 5-4

5 sin cos d 5.4c cos sin d 5.4d tn d cos 5.4 sin n n n α 0 α n α n / n n / 0 α 0 lim lim lim d 0 0 B 5.5 A

6 5-4 A B / 0 A 0 sin 4 cos θ cos θ sin θ sin θ / cos sin / θ cos sin / sin / sin / lim lim lim / lim sin 0 sin sin sin sin cos cos sin sin lim lim d 0 0 sin cos cos sin cos sin lim lim sin cos 0 0 cos cos cos sin cos cos cos cos sin sin cos lim lim d 0 0 cos cos sin sin cos sin lim lim cos sin 0 0 sin 5-6

7 lim lim d 0 0 d d 5sin 5cos d sin 5cos { } { } lim d 0 { } { } lim 0 ' d 5-7

8 3 3 d cos sin d 3 3 cos sin 5.6 d 5.6b d b 0 d d 3 3 d sin 3cos cos 3sin d d 5-8

9 lo 7 tn /3 3 n 8 i / 7 /3 i 8 i i cos n i 0 i n i i lim d 0 lim 0 { } { } lim d 5-9

10 [ ] [ ] d 3 3 sin 3 sin cos d lo lo d 3 sin 3 cos lo lo 5 sin 6 tn lo lo 5 sin cos sin cos 6 tn cos 5-0

11 5- cos cos sin cos sin lim lim lim lim d d 5.8 cos sin cos cos sin sin cos cos n 0 n n n n n n

12 sin cos sin cos tn cos tn n n sin 3 4 sin cos cos sin 5 sin cos cos sin sin 3 sin cos sin cos cos cos sin sin cos sin 4 cos cos sin cos 5 sin sin cos sin cos sin 5 sin 5-

13 z z z z z z z d z lim d 0 lim 0 z, z 0 0 z z lim, 0 dz d dz z z dz 5.9 d d dz 5-3

14 5 4 5 d d z 5 z dz 4 4 5z 5 d d dz z dz z z dz z d d dz lo d d d d d d d d d d lo lo d d lo lo d d d 5-4

15 d d lo d lo lo lo lo lo lo d lo lo lo lo lo lo lo lo lo d lo 5 3 sin cos 3 sin 4 5 sin tn sin 7 lo 8 lo cos sin 3sin cos 3cos sin sin cos 3 sin 4 cos 5 3 cos cos cos sin 5-5

16 . n n n. 3. lo 4. sin cos 5. cos sin 6. tn cos dz d z. z d dz

17 sin sin sin cos sin cos sin cos sin sin z sin z dz d cosz cos dz dz cos d dz cos 3 3 sin sin3 6 / 8 lo sin cos [ ] 3 sin cos 4 5-7

18 5-8 5 sin3 3cos lo / 8

9 5 ( α+ ) = (α + ) α (log ) = α d = α C d = log + C C 5. () d = 4 d = C = C = 3 + C 3 () d = d = C = C = 3 + C 3 =

9 5 ( α+ ) = (α + ) α (log ) = α d = α C d = log + C C 5. () d = 4 d = C = C = 3 + C 3 () d = d = C = C = 3 + C 3 = 5 5. 5.. A II f() f() F () f() F () = f() C (F () + C) = F () = f() F () + C f() F () G() f() G () = F () 39 G() = F () + C C f() F () f() F () + C C f() f() d f() f() C f() f() F () = f() f() f() d =

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zz + 3i(z z) + 5 = 0 + i z + i = z 2i z z z y zz + 3i (z z) + 5 = 0 (z 3i) (z + 3i) = 9 5 = 4 z 3i = 2 (3i) zz i (z z) + 1 = a 2 { 04 zz + iz z) + 5 = 0 + i z + i = z i z z z 970 0 y zz + i z z) + 5 = 0 z i) z + i) = 9 5 = 4 z i = i) zz i z z) + = a {zz + i z z) + 4} a ) zz + a + ) z z) + 4a = 0 4a a = 5 a = x i) i) : c Darumafactory

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