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2 A B A.70g/cm 3 B.74g/cm 3 B C 70at% %A C B at% 80at% %B 350 C γ δ y=00 x-y ρ l S ρ C p k C p ρ C p T ρ l t l S S ξ S t = ( k T ) ξ ( ) S = ( k T) ( ) t y ξ S ξ / t S v T T / t = v T / y 00 x v S

3 dy dx = dy dt dt dx = ( ) -0/0.3v S -0.45mm/s v mm/s y=0m 0.5m x=0.5m y m A J A B C D 0μm Eμm F μm G H I J 3

4 d d E G l () AB x = x B W AB BC () x = x B T AB BC T AB T BC (3) () AB τ AB AB T AB I p (4) (3) x AB x σ AB AB σ σ τ max AB x σ AB AB τ AB σ σ 棒 AB x A l d x B d l 棒 BC x C x x A 棒 AB W x B W 棒 BC x C x 棒 AB 棒 BC T x A x B x C x 4

5 A B リングB A B a b a > b () B b a B t リングA t () A B E B A B B t t b (3) A E B E B A B t t b A (4) (3) () (9) l P e E I δ δ l O x y M M = ( ) y M M = () M () α =P / EI () AB y = (3) x = 0 (4) (5) x = l (6) A B y y = (7) (8) y e P cr P cr = (9) 5

6 a b b O y y F A ( p, q) q () q min q max () θ 0 θ π q (3) θ ( 0 θ π )q θ B ( x, y) O ξη φ θ (4) (3) y φ q θ (5) μ τ θ F y 出力変位 q -b η b O τ 駆動トルク A(p,q) -b φ B(x,y) a ξ θ 入力角変位 x 6

7 () m k () m k l g (3) ω a ω b ω a = k / m ω b = g / l ω / ω 0 () a b ω ω ω / ω ω ω (4) (3) ω ω ω / a a b ω 0 ω / ω b a b 7

8 U F D =6πμRU πμru 4πμRU R μ a u r = r u θ Γ = exp π r u z = az ar 4ν ()( (3)(r, θ, z) ) u r u θ u z a Γ Γ νν= =μ/ρ f ρ f z = 0 u z = 0 u θ r max ()) ()) (3)) r max =, (4) u = θ, max Γ π (5) s+=exp(s) s z = 0 r max ρ p F c = F D =, R= dz z = 0 A: B: z = 0 C: z = 0 8

9 - ρ ()u ()() p ρ ( ρu) + = 0 () t x u + u u = p t x ρ x () c = p ρ c () u u ( ) ρ + u = (3) t x ρ x γ p = Kρ K, γ c = ( ) (4) (4) c = ( ) t = 0 u = uo, c = co t = t u = u, c = c ()(3)(4) ()(3) (4)u c (( ) u + c) (( ) u + c) ( ) ( ) + ( u + c) = 0 (5) + ( u c) = 0 (6) t x t x (( ) u + c) (5)( )(6) t = 0 (5)(6) (5)(( ) u + c) u + c (( ) u + c) t x A B (6) t = 0 t = t ( x; u, c ) u u c c = o, = o u u, c c = = t A (5) t = 0 (6) ( x ; u, c ) ( ;, ) t = t u = u, c = c u, c 9 o o o B x u c x

10 Bi = h/ k h k (a) Bi (b) Bi >> (c) Bi << (d) Bi 300 E T E 球 ( 黒体 ) T σ h E E E 4σ E E (a) T = 4 (b) T = 4 (c) T = (d) T = (e) T = 4 σ 4 σ h 4σ h h 4σ T 3 T s (a)(b)(c)(d) 4 (e)(f)(g)(h) 0 s (a) (b) (c) (d) (e) (f) (g) (h) (i) (j) (k) (l) u h s T p v h c p c v R (m) du = Tds + pdv (n) du = Tds pdv (o) du = Tds + vdp (p) dh = Tds + pdv (q) dh = Tds pdv (r)dh = Tds vdp (s) dt dv (t) dt dv (u) dt dp ds = c + R ds = c R ds = c + R v v v T v T v T p (v) dt dv (w) dt dv (x) dt dp ds = c + R ds = c R ds = c + R p p p T v T v T p 0

11 η O η C T, P, V T, P, V γ η O γ V = V D [m] -83 [atm] atm 0-83[ºC] 83 0 [ºC] D [m] -83 L [J/kg] Nu=hD/k=+0.6Re / h [W/(m K)] D [m] k [W/(mK)]Re ν [m /s] U [m/s] [W] D, k,u, ν [kg/s] h, D, L t[m]k shell [W/(mK)] Q [W] T [K]T [K] R T t, k,q, D, T shell R = 4πk shell r r r : r :

12 P(s) = a, b, c as + bs + c () P(s) () a > 0 P(s) a, b, c (3) P(s) a = b = c = S(s) = C(s) = k k s + (i) k (ii) r(t) lime(t) t (4) (3) G(s) = T s + T s + ( T > T > 0) C(s) = kg(s) (i) G(s) (ii) r(t) lime(t) t

13 dx = Ax + Bu dt y = Cx x R n u R m y R p x = x x, x R r, x R n r d dt x x = A A 0 A x x + B 0 u y = [ C C ] x x () () u = [ F F ] x x + v v x (3) (4) u(t) x(0) = x 0 u(t) (5) 3

14 問題 7 ( 信号処処理 ) 問 () g(tt ) () x( n) ( n = 0,,, 3) N n = 0 X( m) = g( ( t) = exp( t ) X(m ) ( m = 0,,, 3) X(m) π ( n) exp( ( j nm) ( m = 0,, N j x, N ) N 問 x, x x, x μ σ, σ σ, > 0 z z = k x + ( k) x ( 0 k ) () z () z (3) z k (4) (3)k z (5) (4) z σ, σ (6) = z k σ σ 4 ( 次ページに続く )

15 問 3 A n σ σ A σ G( A, σ ) s s SN SN = 0 log 0 n G( A, σ ) σ A G( A, σ ) G( A, σ ) G( A, σ ) G( A, σ ) () SN () G( A, σ ) M 0 0 SN (3) SN (4) A 0 σ 0 A, A, A,σ, σ σ 3 3 (5) A = A = A σ > σ > σ > SN 5 ( 問題 7 終わり )

16 以下の問いに答えよ ただし, 回路は () (a)(b) I 0 Y V 0 0 Z0 Z 0 Y 0 V 0 I 0 (a) ( (b) () (a)(a)(b) I 0 Y0 I 0 Y 0 V i Z i (i = n) (a) (b) (3) (a)v L jπ / (4) V = Ve Z Z V ω R C F 6

17 SS ω V S R S N R L V V I I A C B D V I A = C B V D I AD BC 0 () - Z V V () VS - Z C D R S (3) N A C (4) N R 0 C 0 in I A B B C D out R L V ( ) t I A B B D Z Z A C B D (5) (4) - V V ω V V 7

1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2

1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2 2005 9/8-11 2 2.2 ( 2-5) γ ( ) γ cos θ 2πr πρhr 2 g h = 2γ cos θ ρgr (2.1) γ = ρgrh (2.2) 2 cos θ θ cos θ = 1 (2.2) γ = 1 ρgrh (2.) 2 2. p p ρgh p ( ) p p = p ρgh (2.) h p p = 2γ r 1 1 (Berry,1975) 2-6

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