高等学校学習指導要領

高等学校学習指導要領

...3 1-1...3 1-1...6 1-3...16 2....17...21 3-1...21 3-2...21 3-2...22 3-3...23 3-4...24...25 4-1....25 4-2...27 4-3...28 4-4...33 4-5...36...37 5-1...

DT-870/5100 &DT-5042RFB ...3 1-1...3 1-1...6 1-3...16 2....17...21 3-1...21 3-2...21 3-2...22 3-3...23 3-4...24...25 4-1....25 4-2...27 4-3...28 4-4...33 4-5...36...37 5-1....39 5-2...40 5-3...43...49

Gmech08.dvi

51 5 5.1 5.1.1 P r P z θ P P P z e r e, z ) r, θ, ) 5.1 z r e θ,, z r, θ, = r sin θ cos = r sin θ sin 5.1) e θ e z = r cos θ r, θ, 5.1: 0 r

海生研ニュース

1 2 3 4 5 6 0.4% 58.4% 41.2% 10 65 69 12.0% 9 60 64 13.4% 11 70 12.6% 8 55 59 8.6% 0.1% 1 20 24 3.1% 7 50 54 9.3% 2 25 29 6.0% 3 30 34 7.6% 6 45 49 9.7% 4 35 39 8.5% 5 40 44 9.1% 11 70 11.2% 10 65 69 11.0%

-5 -

別冊　各分野における虐待事例と分析

スタイルシェルフ　〈クローク収納プラン〉

2

<31332D97708CEA89F090E02E6D6364>

1 2 http://www.japan-shop.jp/ 3 4 http://www.japan-shop.jp/ 5 6 http://www.japan-shop.jp/ 7 2,930mm 2,700 mm 2,950mm 2,930mm 2,950mm 2,700mm 2,930mm 2,950mm 2,700mm 8 http://www.japan-shop.jp/ 9 10 http://www.japan-shop.jp/

マイスタープロジェクト　推奨仕様

第18回海岸シンポジウム報告書

2011.6.25 2011.6.26 L1 2011.6.27 L2 2011.7.6 2011.12.7 2011.10-12 2011.9-10 2012.3.9 23 2012.4, 2013.8.30 2012.6.13 2013.9 2011.7-2011.12-2012.4 2011.12.27 2013.9 1m30 1 2 3 4 5 6 m 5.0m 2.0m -5.0m 1.0m

3

(718)

1 911 34/ 22 1012 2/ 20 69 3/ 22 69 1/ 22 69 3/ 22 69 1/ 22 68 3/ 22 68 1/ 3 8 D 0.0900.129mm 0.1300.179mm 0.1800.199mm 0.1000.139mm 0.1400.409mm 0.4101.199mm 0.0900.139mm 0.1400.269mm 0.2700.289mm

液晶ディスプレイ取説TD-E432/TD-E502/TD-E552/TD-E652/TD-E432D/TD-E502D

1 2 3 4 5 6 7 1 2 3 4 5 6 7 2 2 2 1 1 2 9 10 11 12 13 14 15 16 17 1 8 2 3 4 5 6 7 1 2 3 4 5 6 7 8 9 10 9 11 12 13 13 14 15 16 17 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 1 2 3 4 5 6 7 8 9 11 12

() () ()

1 1 36 223 42 14 92 4 3 2 1 4 3 4 3429 13536 5 6 7 8 9 2.4m/ (M) (M) (M) (M) (M) 6.67.3 6.57.2 6.97.6 7.27.8 8.4 5 6 5 6 5 5 74 1,239 0 30 21 ( ) 1,639 3,898 0 1,084 887 2 5 0 2 2 4 22 1 3 1 ( :) 426 1500

1 C 2 C 3 C 4 C 1 C 2 C 3 C

1 e N >. C 40 41 2 >. C 3 >.. C 26 >.. C .mm 4 C 106 e A 107 1 C 2 C 3 C 4 C 1 C 2 C 3 C 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124

<967B95D2955C8E F4390B32E6169>

(1519) () 1 ( ) () 1 ( ) - 1 - - 2 - (1531) (25) 5 25,000 (25) 5 30,000 25,000 174 3 323 174 3 323 (1532) () 2 () 2-3 - - 4 - (1533) () 1 (2267)204 () (1)(2) () 1 (2267)204 () (1)(2) (3) (3) 840,000 680,000

平成２４年財政投融資計画ＰＤＦ出後８／０１６‐０３０

24 23 28,707,866 2,317,737 26,390,129 29,289,794 2,899,665 24 23 19,084,525 21,036,598 1952,073 24 23 8,603,613 8,393,427 967,631 925,404 202,440 179,834 217,469 219,963 66,716 64,877 3,160,423 2,951,165

[mm] [mm] [mm] 70 60 50 40 30 20 10 1H 0 18 19 20 21 22 23 24 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 1 2 3 4 5 6 7 8 9 10 11 12 60 50 40 30 20 10 0 18 19 20 21 22 23 24 1 2 3 4

1

000-.\..

1 1 1 2 3 4 5 6 7 8 9 e e 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 10mm 150mm 60mm 25mm 40mm 30mm 25 26 27 1 28 29 30 31 32 e e e e e e 33 e 34 35 35 e e e e 36 37 38 38 e e 39 e 1 40 e 41 e 42 43

#A A A F, F d F P + F P = d P F, F y P F F x A.1 ( α, 0), (α, 0) α > 0) (x, y) (x + α) 2 + y 2, (x α) 2 + y 2 d (x + α)2 + y 2 + (x α) 2 + y 2 =

#A A A. F, F d F P + F P = d P F, F P F F A. α, 0, α, 0 α > 0, + α +, α + d + α + + α + = d d F, F 0 < α < d + α + = d α + + α + = d d α + + α + d α + = d 4 4d α + = d 4 8d + 6 http://mth.cs.kitmi-it.c.jp/

1 3 1.1.......................... 3 1............................... 3 1.3....................... 5 1.4.......................... 6 1.5........................ 7 8.1......................... 8..............................

Gmech08.dvi

145 13 13.1 13.1.1 0 m mg S 13.1 F 13.1 F /m S F F 13.1 F mg S F F mg 13.1: m d2 r 2 = F + F = 0 (13.1) 146 13 F = F (13.2) S S S S S P r S P r r = r 0 + r (13.3) r 0 S S m d2 r 2 = F (13.4) (13.3) d 2

C:/KENAR/0p1.dvi

2{3. 53 2{3 [ ] 4 2 1 2 10,15 m 10,10 m 2 2 54 2 III 1{I U 2.4 U r (2.16 F U F =, du dt du dr > 0 du dr < 0 O r 0 r 2.4: 1 m =1:00 10 kg 1:20 10 kgf 8:0 kgf g =9:8 m=s 2 (a) x N mg 2.5: N 2{3. 55 (b) x

() n C + n C + n C + + n C n n (3) n C + n C + n C 4 + n C + n C 3 + n C 5 + (5) (6 ) n C + nc + 3 nc n nc n (7 ) n C + nc + 3 nc n nc n (

3 n nc k+ k + 3 () n C r n C n r nc r C r + C r ( r n ) () n C + n C + n C + + n C n n (3) n C + n C + n C 4 + n C + n C 3 + n C 5 + (4) n C n n C + n C + n C + + n C n (5) k k n C k n C k (6) n C + nc

untitled

( ) c a sin b c b c a cos a c b c a tan b a b cos sin a c b c a ccos b csin (4) Ma k Mg a (Gal) g(98gal) (Gal) a max (K-E) kh Zck.85.6. 4 Ma g a k a g k D τ f c + σ tanφ σ 3 3 /A τ f3 S S τ A σ /A σ /A

A

A05-132 2010 2 11 1 1 3 1.1.......................................... 3 1.2..................................... 3 1.3..................................... 3 2 4 2.1............................... 4 2.2

Gmech08.dvi

63 6 6.1 6.1.1 v = v 0 =v 0x,v 0y, 0) t =0 x 0,y 0, 0) t x x 0 + v 0x t v x v 0x = y = y 0 + v 0y t, v = v y = v 0y 6.1) z 0 0 v z yv z zv y zv x xv z xv y yv x = 0 0 x 0 v 0y y 0 v 0x 6.) 6.) 6.1) 6.)

(1) D = [0, 1] [1, 2], (2x y)dxdy = D = = (2) D = [1, 2] [2, 3], (x 2 y + y 2 )dxdy = D = = (3) D = [0, 1] [ 1, 2], 1 {

7 4.., ], ], ydy, ], 3], y + y dy 3, ], ], + y + ydy 4, ], ], y ydy ydy y y ] 3 3 ] 3 y + y dy y + 3 y3 5 + 9 3 ] 3 + y + ydy 5 6 3 + 9 ] 3 73 6 y + y + y ] 3 + 3 + 3 3 + 3 + 3 ] 4 y y dy y ] 3 y3 83 3

untitled

58 59 60 61 62 63 64 65 12 20 2.45 3.0 30 50 13.24.7 5mm SS CSS MS HMS CS 66 CSS SS 2.45 3.0 50 30 2.0 2.0 F.2.5 JIS A 5001 1995 67 1 130mm 2 75m 3 75m75m 60 75m 68 69 PK1 PK2 PK3 PK4 MK1 MK2 MK3 MN1 25

表1-表4_No78_念校.indd

mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm Fs = tan + tan. sin(1.5) tan sin. cos Fs ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

取扱説明書 [N-03A]

235 1 d dt 2 1 i 236 1 p 2 1 ty 237 o p 238 1 i 2 1 i 2 1 u 239 1 p o p b d 1 2 3 0 w 240 241 242 o d p f g p b t w 0 q f g h j d 1 2 d b 5 4 6 o p f g p 1 2 3 4 5 6 7 243 244 1 2 1 q p 245 p 246 p p 1

12-7 12-7 12-7 12-7 12-8 12-10 12-10 12-10 12-11 12-12 12-12 12-14 12-15 12-17 12-18 10 12-19 12-20 12-20 12-21 12-22 12-22 12-23 12-25 12-26 12-26 12-29 12-30 12-30 12-31 12-33 12-34 12-3 12-35 12-36

untitled

39 40 41 45 47 54 57 39 () 40 () () S22 12,262 7,108 5,154 S23 12,753 7,331 5,422 S24 14,201 8,391 5,810 S25 16,311 9,820 6,491 S26 15,415 9,035 6,380 S27 15,776 9,171 6,605 S28 17,731 10,450 7,281 S29

A (1) = 4 A( 1, 4) 1 A 4 () = tan A(0, 0) π A π

4 4.1 4.1.1 A = f() = f() = a f (a) = f() (a, f(a)) = f() (a, f(a)) f(a) = f 0 (a)( a) 4.1 (4, ) = f() = f () = 1 = f (4) = 1 4 4 (4, ) = 1 ( 4) 4 = 1 4 + 1 17 18 4 4.1 A (1) = 4 A( 1, 4) 1 A 4 () = tan

1.1 ft t 2 ft = t 2 ft+ t = t+ t 2 1.1 d t 2 t + t 2 t 2 = lim t 0 t = lim t 0 = lim t 0 t 2 + 2t t + t 2 t 2 t + t 2 t 2t t + t 2 t 2t + t = lim t 0

A c 2008 by Kuniaki Nakamitsu 1 1.1 t 2 sin t, cos t t ft t t vt t xt t + t xt + t xt + t xt t vt = xt + t xt t t t vt xt + t xt vt = lim t 0 t lim t 0 t 0 vt = dxt ft dft dft ft + t ft = lim t 0 t 1.1

B line of mgnetic induction AB MN ds df (7.1) (7.3) (8.1) df = µ 0 ds, df = ds B = B ds 2π A B P P O s s Q PQ R QP AB θ 0 <θ<π

8 Biot-Svt Ampèe Biot-Svt 8.1 Biot-Svt 8.1.1 Ampèe B B B = µ 0 2π. (8.1) B N df B ds A M 8.1: Ampèe 107 108 8 0 B line of mgnetic induction 8.1 8.1 AB MN ds df (7.1) (7.3) (8.1) df = µ 0 ds, df = ds B

untitled

(a) (b) (c) (d) Wunderlich 2.5.1 = = =90 2 1 (hkl) {hkl} [hkl] L tan 2θ = r L nλ = 2dsinθ dhkl ( ) = 1 2 2 2 h k l + + a b c c l=2 l=1 l=0 Polanyi nλ = I sinφ I: B A a 110 B c 110 b b 110 µ a 110

2. 2 P M A 2 F = mmg AP AP 2 AP (G > : ) AP/ AP A P P j M j F = n j=1 mm j G AP j AP j 2 AP j 3 P ψ(p) j ψ(p j ) j (P j j ) A F = n j=1 mgψ(p j ) j AP

1. 1 213 1 6 1 3 1: ( ) 2: 3: SF 1 2 3 1: 3 2 A m 2. 2 P M A 2 F = mmg AP AP 2 AP (G > : ) AP/ AP A P P j M j F = n j=1 mm j G AP j AP j 2 AP j 3 P ψ(p) j ψ(p j ) j (P j j ) A F = n j=1 mgψ(p j ) j AP

c y /2 ddy = = 2π sin θ /2 dθd /2 [ ] 2π cos θ d = log 2 + a 2 d = log 2 + a 2 = log 2 + a a 2 d d + 2 = l

c 28. 2, y 2, θ = cos θ y = sin θ 2 3, y, 3, θ, ϕ = sin θ cos ϕ 3 y = sin θ sin ϕ 4 = cos θ 5.2 2 e, e y 2 e, e θ e = cos θ e sin θ e θ 6 e y = sin θ e + cos θ e θ 7.3 sgn sgn = = { = + > 2 < 8.4 a b 2

64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () m/s : : a) b) kg/m kg/m k

63 3 Section 3.1 g 3.1 3.1: : 64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () 3 9.8 m/s 2 3.2 3.2: : a) b) 5 15 4 1 1. 1 3 14. 1 3 kg/m 3 2 3.3 1 3 5.8 1 3 kg/m 3 3 2.65 1 3 kg/m 3 4 6 m 3.1. 65 5

A大扉・騒音振動.qxd

H21-30 H21-31 H21-32 H21-33 H21-34 H21-35 H21-36 H21-37 H21-38 H21-39 H21-40 H21-41 H21-42 n n S L N S L N L N S S S L L log I II I L I L log I I H21-43 L log L log I I I log log I I I log log I I I I

応力とひずみ.ppt

in yukawa@numse.nagoya-u.ac.jp 2 3 4 5 x 2 6 Continuum) 7 8 9 F F 10 F L L F L 1 L F L F L F 11 F L F F L F L L L 1 L 2 12 F L F! A A! S! = F S 13 F L L F F n = F " cos# F t = F " sin# S $ = S cos# S S

1 1 2 2 3 4 5 5 6 7 8 10 9 10 10 10 11 13 14 15 15 16 17 18 19 21 21 22 22 24 28 38 40 41 41 43 45 46 47 47 47 47 48 50 50 50 50 51 52 54 54 55 56 56 57 57 57 58 58 59 59 59 61 61 61 62 62 62 62 63 63

() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)

0. A A = 4 IC () det A () A () x + y + z = x y z X Y Z = A x y z ( 5) ( s5590) 0. a + b + c b c () a a + b + c c a b a + b + c 0 a b c () a 0 c b b c 0 a c b a 0 0. A A = 7 5 4 5 0 ( 5) ( s5590) () A ()

１３２０Ｍ／１６１３２０Ｍ

" # $ %! θθ v m g y v θ O v α x! O x y x α x y y " v # v sinα $ & v cosα ' v cosα v sinα ( v cosα % v sinα " g # gsinθ $ g sinθ ' g ( gsinθ ) g sinθ % gcosθ & g cosθ * gcosθ! g cosθ xy y L v g x xy L α

ADHD 25

untitled

9118 154 B-1 B-3 B- 5cm 3cm 5cm 3m18m5.4m.5m.66m1.3m 1.13m 1.134m 1.35m.665m 5 , 4 13 7 56 M 1586.1.18 7.77.9 599.5.8 7 1596.9.5 7.57.75 684.11.9 8.5 165..3 7.9 87.8.11 6.57. 166.6.16 7.57.6 856 6.6.5

f (x) x y f(x+dx) f(x) Df 関数 接線 x Dx x 1 x x y f f x (1) x x 0 f (x + x) f (x) f (2) f (x + x) f (x) + f = f (x) + f x (3) x f

208 3 28. f fd f Df 関数 接線 D f f 0 f f f 2 f f f f f 3 f lim f f df 0 d 4 f df d 3 f d f df d 5 d c 208 2 f f t t f df d 6 d t dt 7 f df df d d df dt lim f 0 t df d d dt d t 8 dt 9.2 f,, f 0 f 0 lim 0 lim

1. (8) (1) (x + y) + (x + y) = 0 () (x + y ) 5xy = 0 (3) (x y + 3y 3 ) (x 3 + xy ) = 0 (4) x tan y x y + x = 0 (5) x = y + x + y (6) = x + y 1 x y 3 (

1 1.1 (1) (1 + x) + (1 + y) = 0 () x + y = 0 (3) xy = x (4) x(y + 3) + y(y + 3) = 0 (5) (a + y ) = x ax a (6) x y 1 + y x 1 = 0 (7) cos x + sin x cos y = 0 (8) = tan y tan x (9) = (y 1) tan x (10) (1 +

Note.tex 2008/09/19( )

1 20 9 19 2 1 5 1.1........................ 5 1.2............................. 8 2 9 2.1............................. 9 2.2.............................. 10 3 13 3.1.............................. 13 3.2..................................

66 σ σ (8.1) σ = 0 0 σd = 0 (8.2) (8.2) (8.1) E ρ d = 0... d = 0 (8.3) d 1 NN K K 8.1 d σd σd M = σd = E 2 d (8.4) ρ 2 d = I M = EI ρ 1 ρ = M EI ρ EI

65 8. K 8 8 7 8 K 6 7 8 K 6 M Q σ (6.4) M O ρ dθ D N d N 1 P Q B C (1 + ε)d M N N h 2 h 1 ( ) B (+) M 8.1: σ = E ρ (E, 1/ρ ) (8.1) 66 σ σ (8.1) σ = 0 0 σd = 0 (8.2) (8.2) (8.1) E ρ d = 0... d = 0 (8.3)

... 1... 1... 2... 3... 5... 7... 7... 7... 8... 8... 12... 14... 14... 14... 16... 16... 16... 17... 17... 18... 18... 19... 20... 43... 43... 53... 55... 56... 56... 57 JFE M... 57... 59... 60... 61

1 θ i (1) A B θ ( ) A = B = sin 3θ = sin θ (A B sin 2 θ) ( ) 1 2 π 3 < = θ < = 2 π 3 Ax Bx3 = 1 2 θ = π sin θ (2) a b c θ sin 5θ = sin θ f(sin 2 θ) 2

θ i ) AB θ ) A = B = sin θ = sin θ A B sin θ) ) < = θ < = Ax Bx = θ = sin θ ) abc θ sin 5θ = sin θ fsin θ) fx) = ax bx c ) cos 5 i sin 5 ) 5 ) αβ α iβ) 5 α 4 β α β β 5 ) a = b = c = ) fx) = 0 x x = x =

10 117 5 1 121841 4 15 12 7 27 12 6 31856 8 21 1983-2 - 321899 12 21656 2 45 9 2 131816 4 91812 11 20 1887 461971 11 3 2 161703 11 13 98 3 16201700-3 - 2 35 6 7 8 9 12 13 12 481973 12 2 571982 161703 11

lim lim lim lim 0 0 d lim 5. d 0 d d d d d d 0 0 lim lim 0 d

lim 5. 0 A B 5-5- A B lim 0 A B A 5. 5- 0 5-5- 0 0 lim lim 0 0 0 lim lim 0 0 d lim 5. d 0 d d d d d d 0 0 lim lim 0 d 0 0 5- 5-3 0 5-3 5-3b 5-3c lim lim d 0 0 5-3b 5-3c lim lim lim d 0 0 0 3 3 3 3 3 3

ma22-9 u ( v w) = u v w sin θê = v w sin θ u cos φ = = 2.3 ( a b) ( c d) = ( a c)( b d) ( a d)( b c) ( a b) ( c d) = (a 2 b 3 a 3 b 2 )(c 2 d 3 c 3 d

A 2. x F (t) =f sin ωt x(0) = ẋ(0) = 0 ω θ sin θ θ 3! θ3 v = f mω cos ωt x = f mω (t sin ωt) ω t 0 = f ( cos ωt) mω x ma2-2 t ω x f (t mω ω (ωt ) 6 (ωt)3 = f 6m ωt3 2.2 u ( v w) = v ( w u) = w ( u v) ma22-9

１

10 2 1990 5 1993 6 16 11 24 18 35 1960 41 1966 19 2 11 14 30 1955 10 41 1966 12 16 45 40 35 2004 2004 2004 30 25 20 15 10 5 0 1950 1960 1970 1980 1990 2000 6 10 1 6 46 10 2223 2 6 10 6 10 1 6 7 8 1011

29 4 ... 1... 1... 1... 2... 3... 4.... 4... 4... 7... 8... 8... 8... 8...12...14...14...14...16...18...18...19...21... 42...42...42....42....46....49...51....51....51... 52...52...52...53 I. I. I. I.

0.45m1.00m 1.00m 1.00m 0.33m 0.33m 0.33m 0.45m 1.00m 2

24 11 10 24 12 10 30 1 0.45m1.00m 1.00m 1.00m 0.33m 0.33m 0.33m 0.45m 1.00m 2 23% 29% 71% 67% 6% 4% n=1525 n=1137 6% +6% -4% -2% 21% 30% 5% 35% 6% 6% 11% 40% 37% 36 172 166 371 213 226 177 54 382 704 216

1 Q A 82% 89% 88% 82% 88% 82%

10 44 1.2 5 4 5 3 6-1 - 1 2 3 4 5 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8 9 10 TEL TEL 1 2 TEL FAX TEL FAX TEL FAX 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 1 2 3 4 5 6 ( ) ( ) 2

競技スポーツの科学研究 ～ アトランタ五輪を終えて ～ 新潟大学・山崎 健

1997 3 1998 12 sin cos 1997 3 1998 12 1997 3 1998 12 1997 3 1998 12 4 1997 3 1998 12 1964!? 100m 94 100m 100mH 10 100m 1964 1997 3 1998 12 1996 100m 7 0.174 0.14 9 84 1988 200m 25m 1986 1997 3 1998 12

sekibun.dvi

a d = a + a+ (a ), e d = e, sin d = cos, (af() + bg())d = a d = log, cosd = sin, f()d + b g()d d 3 d d d d d d d ( + 3 + )d ( + )d ( 3 )d (e )d ( sin 3 cos)d g ()f (g())d = f(g()) e d e d ( )e d cos d

untitled

... 1... 29... 31... 65 ... 152... 160... 162 ... 169 ... 201 1 2 3 4 玢 5 6 7 8 9 10 11 12 13 14 15 16 17 23 9 28 26 31 18 19 - - T.P.+ 1 21 3 8 22 3 1 18 2 8 41 2 T.P.+m 20 21 22 23 24 25 26 27 28 29

K E N Z U 01 7 16 HP M. 1 1 4 1.1 3.......................... 4 1.................................... 4 1..1..................................... 4 1...................................... 5................................

() 2

1 () 2 2 4 3 6,500 4 5 2 6 A B A B A B A B - A B 7 8 A B A B A B 9 JR JR 10 11 6 5 12 17 6 13 14 B A A B A B A B 2 1 8 15 8 16 17 9 18 3 4 5 mm mm 19 2 20 3 6 7 11 12 13 14 18 4 3 2 1 21 3 12 13 14 16

取扱説明書[N906i]

237 1 dt 2 238 1 i 1 p 2 1 ty 239 240 o p 1 i 2 1 u 1 i 2 241 1 p v 1 d d o p 242 1 o o 1 o 2 p 243 1 o 2 p 1 o 2 3 4 244 q p 245 p p 246 p 1 i 1 u c 2 o c o 3 o 247 1 i 1 u 2 co 1 1 248 1 o o 1 t 1 t

3 m/sec 8.35 39.06 3.22 2.15 13.72 52.78 15.00 2.12 2.69 12.62 27.62 3 m/ 772 79 68 263 410 1,182 3 m/sec 3.87 0.63 8.00 3.12 1.38 12.50 12.50 2.00 2.50 1.00 5.50 5.50 m/ 105 122 20 247 247 3 m/sec 0.23

Ł\”ƒ1

第1章 微分方程式と近似解法

April 12, 2018 1 / 52 1.1 ( ) 2 / 52 1.2 1.1 1.1: 3 / 52 1.3 Poisson Poisson Poisson 1 d {2, 3} 4 / 52 1 1.3.1 1 u,b b(t,x) u(t,x) x=0 1.1: 1 a x=l 1.1 1 (0, t T ) (0, l) 1 a b : (0, t T ) (0, l) R, u

m 3 /s

サクラの木につく毛虫の観察

85 4

85 4 86 Copright c 005 Kumanekosha 4.1 ( ) ( t ) t, t 4.1.1 t Step! (Step 1) (, 0) (Step ) ±V t (, t) I Check! P P V t π 54 t = 0 + V (, t) π θ : = θ : π ) θ = π ± sin ± cos t = 0 (, 0) = sin π V + t +V

1 12 ( )150 ( ( ) ) x M x 0 1 M 2 5x 2 + 4x + 3 x 2 1 M x M 2 1 M x (x + 1) 2 (1) x 2 + x + 1 M (2) 1 3 M (3) x 4 +

( )5 ( ( ) ) 4 6 7 9 M M 5 + 4 + M + M M + ( + ) () + + M () M () 4 + + M a b y = a + b a > () a b () y V a () V a b V n f() = n k= k k () < f() = log( ) t dt log () n+ (i) dt t (n + ) (ii) < t dt n+ n

DocuPrint C5450 ユーザーズガイド

1 2 3 4 5 6 7 8 1 10 1 11 1 12 1 13 1 14 1 15 1 16 17 1 1 18 1 19 1 20 1 21 1 22 1 23 1 24 1 25 1 26 27 1 1 28 1 29 1 30 1 31 1 2 12 13 3 2 10 11 4 9 8 7 6 5 34 24 23 14 15 22 21 20 16 19 18 17 2 35

P P P P P P P P P P P P P

P P P P P P P P P P P P P 1 (1) (2) (3) (1) (2) (3) 1 ( ( ) ( ) ( ) 2 ( 0563-00-0000 ( 090-0000-0000 ) 052-00-0000 ( ) ( ) () 1 3 0563-00-0000 3 [] g g cc [] [] 4 5 1 DV 6 7 1 DV 8 9 10 11 12 SD 13 .....

68 JAXA-RR r v m Ó e ε 0 E = - Ó/ r f f 0 f 1 f = f 0 + f 1 x k f 1 = f k e ikx Ó = Ó k e ikx Ó k 3

67 1 Landau Damping and RF Current Drive Kazuya UEHARA* 1 Abstract The current drive due to the rf travelling wave has been available to sustain the plasma current of tokamaks aiming the stational operation.

, 3, 6 = 3, 3,,,, 3,, 9, 3, 9, 3, 3, 4, 43, 4, 3, 9, 6, 6,, 0 p, p, p 3,..., p n N = p p p 3 p n + N p n N p p p, p 3,..., p n p, p,..., p n N, 3,,,,

6,,3,4,, 3 4 8 6 6................................. 6.................................. , 3, 6 = 3, 3,,,, 3,, 9, 3, 9, 3, 3, 4, 43, 4, 3, 9, 6, 6,, 0 p, p, p 3,..., p n N = p p p 3 p n + N p n N p p p,

untitled

2

1 12123456789012345678901234 12123456789012345678901234 12123456789012345678901234 12123456789012345678901234 12123456789012345678901234 12123456789012345678901234 12123456789012345678901234 12123456789012345678901234

a a b a b c d e R c d e A a b e a b a b c d a b c d e f a M a b f d a M b a b a M b a M b M M M R M a M b M c a M a R b A a b b a CF a b c a b a M b a b M a M b c a A b a b M b a A b a M b C a M C a M

4. ϵ(ν, T ) = c 4 u(ν, T ) ϵ(ν, T ) T ν π4 Planck dx = 0 e x 1 15 U(T ) x 3 U(T ) = σt 4 Stefan-Boltzmann σ 2π5 k 4 15c 2 h 3 = W m 2 K 4 5.

A 1. Boltzmann Planck u(ν, T )dν = 8πh ν 3 c 3 kt 1 dν h 6.63 10 34 J s Planck k 1.38 10 23 J K 1 Boltzmann u(ν, T ) T ν e hν c = 3 10 8 m s 1 2. Planck λ = c/ν Rayleigh-Jeans u(ν, T )dν = 8πν2 kt dν c

untitled

4-1 4-2 3 X 4 2 2 3 Y 1 1 4 5 4-3 4-4 4-5 { P} K { U} = T { P} = [ L][ K][ L] { U} { P} K { U} = K = [ L][ D][ U] { p 0 } { p} = [ K]{ u} + { p } 0 T [ L] = [ U] 4-6 4-7 sin θ,cosθ 0 4-8 K = [ L][ D][

A 99% MS-Free Presentation

A 99% MS-Free Presentation 2 Galactic Dynamics (Binney & Tremaine 1987, 2008) Dynamics of Galaxies (Bertin 2000) Dynamical Evolution of Globular Clusters (Spitzer 1987) The Gravitational Million-Body Problem

( ) sin 1 x, cos 1 x, tan 1 x sin x, cos x, tan x, arcsin x, arccos x, arctan x. π 2 sin 1 x π 2, 0 cos 1 x π, π 2 < tan 1 x < π 2 1 (1) (

6 20 ( ) sin, cos, tan sin, cos, tan, arcsin, arccos, arctan. π 2 sin π 2, 0 cos π, π 2 < tan < π 2 () ( 2 2 lim 2 ( 2 ) ) 2 = 3 sin (2) lim 5 0 = 2 2 0 0 2 2 3 3 4 5 5 2 5 6 3 5 7 4 5 8 4 9 3 4 a 3 b