64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () m/s : : a) b) kg/m kg/m k

Similar documents
Gmech08.dvi

8 300 mm 2.50 m/s L/s ( ) 1.13 kg/m MPa 240 C 5.00mm 120 kpa ( ) kg/s c p = 1.02kJ/kgK, R = 287J/kgK kPa, 17.0 C 118 C 870m 3 R = 287J

1. 4cm 16 cm 4cm 20cm 18 cm L λ(x)=ax [kg/m] A x 4cm A 4cm 12 cm h h Y 0 a G 0.38h a b x r(x) x y = 1 h 0.38h G b h X x r(x) 1 S(x) = πr(x) 2 a,b, h,π

LLG-R8.Nisus.pdf

untitled

Gmech08.dvi

Note.tex 2008/09/19( )

2. 2 P M A 2 F = mmg AP AP 2 AP (G > : ) AP/ AP A P P j M j F = n j=1 mm j G AP j AP j 2 AP j 3 P ψ(p) j ψ(p j ) j (P j j ) A F = n j=1 mgψ(p j ) j AP

II Karel Švadlenka * [1] 1.1* 5 23 m d2 x dt 2 = cdx kx + mg dt. c, g, k, m 1.2* u = au + bv v = cu + dv v u a, b, c, d R

pdf


(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0



ma22-9 u ( v w) = u v w sin θê = v w sin θ u cos φ = = 2.3 ( a b) ( c d) = ( a c)( b d) ( a d)( b c) ( a b) ( c d) = (a 2 b 3 a 3 b 2 )(c 2 d 3 c 3 d

2.2 h h l L h L = l cot h (1) (1) L l L l l = L tan h (2) (2) L l 2 l 3 h 2.3 a h a h (a, h)

無印良品 2012 自転車 カタログ

untitled

85 4

m dv = mg + kv2 dt m dv dt = mg k v v m dv dt = mg + kv2 α = mg k v = α 1 e rt 1 + e rt m dv dt = mg + kv2 dv mg + kv 2 = dt m dv α 2 + v 2 = k m dt d

sec13.dvi


1 I 1.1 ± e = = - = C C MKSA [m], [Kg] [s] [A] 1C 1A 1 MKSA 1C 1C +q q +q q 1

The Physics of Atmospheres CAPTER :

W u = u(x, t) u tt = a 2 u xx, a > 0 (1) D := {(x, t) : 0 x l, t 0} u (0, t) = 0, u (l, t) = 0, t 0 (2)

untitled

TOP URL 1

1 Q A 82% 89% 88% 82% 88% 82%

) km 200 m ) ) ) ) ) ) ) kg kg ) 017 x y x 2 y 5x 5 y )


V(x) m e V 0 cos x π x π V(x) = x < π, x > π V 0 (i) x = 0 (V(x) V 0 (1 x 2 /2)) n n d 2 f dξ 2ξ d f 2 dξ + 2n f = 0 H n (ξ) (ii) H

FS_handbook.indd

[1.1] r 1 =10e j(ωt+π/4), r 2 =5e j(ωt+π/3), r 3 =3e j(ωt+π/6) ~r = ~r 1 + ~r 2 + ~r 3 = re j(ωt+φ) =(10e π 4 j +5e π 3 j +3e π 6 j )e jωt

0.45m1.00m 1.00m 1.00m 0.33m 0.33m 0.33m 0.45m 1.00m 2


( ) e + e ( ) ( ) e + e () ( ) e e Τ ( ) e e ( ) ( ) () () ( ) ( ) ( ) ( )


秋植え花壇の楽しみ方

<82D282A982C1746F95F18D908F57967B95B E696E6464>


4. ϵ(ν, T ) = c 4 u(ν, T ) ϵ(ν, T ) T ν π4 Planck dx = 0 e x 1 15 U(T ) x 3 U(T ) = σt 4 Stefan-Boltzmann σ 2π5 k 4 15c 2 h 3 = W m 2 K 4 5.

nsg04-28/ky208684356100043077

TOP URL 1

1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2

6 2 2 x y x y t P P = P t P = I P P P ( ) ( ) ,, ( ) ( ) cos θ sin θ cos θ sin θ, sin θ cos θ sin θ cos θ y x θ x θ P

緑化計画作成の手引き 26年4月版

医系の統計入門第 2 版 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 第 2 版 1 刷発行時のものです.

NETES No.CG V

I-2 (100 ) (1) y(x) y dy dx y d2 y dx 2 (a) y + 2y 3y = 9e 2x (b) x 2 y 6y = 5x 4 (2) Bernoulli B n (n = 0, 1, 2,...) x e x 1 = n=0 B 0 B 1 B 2 (3) co

II ( ) (7/31) II ( [ (3.4)] Navier Stokes [ (6/29)] Navier Stokes 3 [ (6/19)] Re

0.1 I I : 0.2 I

重力方向に基づくコントローラの向き決定方法

Untitled

2 2 1?? 2 1 1, 2 1, 2 1, 2, 3,... 1, 2 1, 3? , 2 2, 3? k, l m, n k, l m, n kn > ml...? 2 m, n n m

[ ] 0.1 lim x 0 e 3x 1 x IC ( 11) ( s114901) 0.2 (1) y = e 2x (x 2 + 1) (2) y = x/(x 2 + 1) 0.3 dx (1) 1 4x 2 (2) e x sin 2xdx (3) sin 2 xdx ( 11) ( s

2 Chapter 4 (f4a). 2. (f4cone) ( θ) () g M. 2. (f4b) T M L P a θ (f4eki) ρ H A a g. v ( ) 2. H(t) ( )

.5 z = a + b + c n.6 = a sin t y = b cos t dy d a e e b e + e c e e e + e 3 s36 3 a + y = a, b > b 3 s363.7 y = + 3 y = + 3 s364.8 cos a 3 s365.9 y =,

量子力学 問題

A = A x x + A y y + A, B = B x x + B y y + B, C = C x x + C y y + C..6 x y A B C = A x x + A y y + A B x B y B C x C y C { B = A x x + A y y + A y B B

() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)

tnbp59-21_Web:P2/ky132379509610002944

(3) (2),,. ( 20) ( s200103) 0.7 x C,, x 2 + y 2 + ax = 0 a.. D,. D, y C, C (x, y) (y 0) C m. (2) D y = y(x) (x ± y 0), (x, y) D, m, m = 1., D. (x 2 y

untitled

50 2 I SI MKSA r q r q F F = 1 qq 4πε 0 r r 2 r r r r (2.2 ε 0 = 1 c 2 µ 0 c = m/s q 2.1 r q' F r = 0 µ 0 = 4π 10 7 N/A 2 k = 1/(4πε 0 qq

II (10 4 ) 1. p (x, y) (a, b) ε(x, y; a, b) 0 f (x, y) f (a, b) A, B (6.5) y = b f (x, b) f (a, b) x a = A + ε(x, b; a, b) x a 2 x a 0 A = f x (

, [g/cm 3 ] [m/s] 1 6 [kg m 2 s 1 ] ,58 1, ,56 1, , ,58 1,

微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 初版 1 刷発行時のものです.

S I. dy fx x fx y fx + C 3 C vt dy fx 4 x, y dy yt gt + Ct + C dt v e kt xt v e kt + C k x v k + C C xt v k 3 r r + dr e kt S Sr πr dt d v } dt k e kt

) a + b = i + 6 b c = 6i j ) a = 0 b = c = 0 ) â = i + j 0 ˆb = 4) a b = b c = j + ) cos α = cos β = 6) a ˆb = b ĉ = 0 7) a b = 6i j b c = i + 6j + 8)

128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds = 0 (3.4) S 1, S 2 { B( r) n( r)}ds


( ) sin 1 x, cos 1 x, tan 1 x sin x, cos x, tan x, arcsin x, arccos x, arctan x. π 2 sin 1 x π 2, 0 cos 1 x π, π 2 < tan 1 x < π 2 1 (1) (

koji07-01.dvi

07.報文_及川ら-二校目.indd

P F ext 1: F ext P F ext (Count Rumford, ) H 2 O H 2 O 2 F ext F ext N 2 O 2 2

Part () () Γ Part ,

66 σ σ (8.1) σ = 0 0 σd = 0 (8.2) (8.2) (8.1) E ρ d = 0... d = 0 (8.3) d 1 NN K K 8.1 d σd σd M = σd = E 2 d (8.4) ρ 2 d = I M = EI ρ 1 ρ = M EI ρ EI

Transcription:

63 3 Section 3.1 g 3.1 3.1: :

64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () 3 9.8 m/s 2 3.2 3.2: : a) b) 5 15 4 1 1. 1 3 14. 1 3 kg/m 3 2 3.3 1 3 5.8 1 3 kg/m 3 3 2.65 1 3 kg/m 3 4 6 m

3.1. 65 5 5 1 15 1 1-5 -5 1 5 5-5 1-5 5 5 1-5 5-5 -1-15 15 1 3.3: 1 5 m/s 2 5 6 7 3.3 5 1 6 2 7 3

66 3 l u B S 3.4 l S l l S l d C 2 C G 2 S 2 A 3.4 Section 3.2 3.4 S S A A 8 8 3.5.4

3.2. 67 S (S ) l S (l S ) l (= l S + l S ) T d (T u ) g α (2π) 2 g = [ Td 2 + T u 2 + T d 2 T 2 ]( u 1 1 2l 2(l S l S ) 8 α2 + O(α 4 ) ) (3.1) (l S ) (3.1) l S l S g = (2π)2 l T 2 ( 1 + 1 8 α2) (T = T d = T u ) (3.2) T l l 3.2.1 3.4 A, B, C-C l l θ(θ =.19 deg 1 ) T R ( C) l l = l (1 + (T R 15)θ) (3.3) 3.2.2

68 3 3.2.3 9 9. 9 9 9 9 3.5 3.2.4 ( 3.6) I I II 1 1 µsec ( 1 ) 99.9999 sec ( 3.5) 1 1 1/1 1 µsec 1/1 3.6 Section 3.3 T d = T u 1 2

3.3. 69 3. cm(±1 mm ) TA C C 77 cm 79 cm 81 cm 83 cm 85 cm

7 3 1 T d = T u A T d = T u C C 1. T d C C 77 cm 85 cm 2. T u C C 77 cm 85 cm 3. C C T d T u T d T u T d = T u T A 3.7 4. A 2 T d = T u B A C C 79 cm, 81 cm, 83 cm T d T u T d = T u 1. C C 79 cm, 81 cm, 83 cm 2. C C 79 cm, 81 cm, 83 cm 3. TA 4. T d, T u B 5. B

3.3. 71 d= (down) u= (up) C-C (cm) (sec) 1 d77. 1 2.468 2 2.471 C-C (cm) (sec) 3 2.469 1 u85. 1 2.976 4 2.47 2 2.971 5 2.467 3 2.974 2.469 : : : 2 d79. 1 2.56 2.974 2 2.545 2 u83. 1 1.52235 3 2.552 2 2.721 : : : 3 1.972 2.552 4 1.9722 3 d81. 1 1.79956 : : : 2 2.65 2.721 3 2.654 3 u81. 1 2.444 4 2.652 : : : : : : : 2.652 : : : l TA 2 cm =.1 sec 2.5 2.4 2.3 2.2 2.1 77. 79. 81. 83. 85. C-C cm 3.7

72 3 3 B B C C T d = T u A 1. C C 2. C C T d T u 3. T d T u T = T d T u 3 B T d T u AC C T d T u T 4, p. 1 1 2

3.3. 73 1. 1 2 3 2. 1 2 C C 77 79 81 83 85 cm T d T u 3. 2 B TA 4. A B Section 3.4 1 2 3 1 3

74 3 Section 3.4 3.4.1 1 1. T d = T u A B T d = T u CT d = T u T 5 2. C A B C A B B C C 77, 79, 81, 83, 85 cm T d T u 3. C 3.2 C T g( m/s 2 ) g 4 π = 3.1415 A.2 p. 271 4. l l g( ) g(+) A.3 A.4 p. 272 274 Section 3.5 g = 9.83 ±.2 m/s 2 (3.4) 9.81 m/s 2 9.85 m/s 2 5. C A B T A B - - A.4 p. 274

3.4. 75 3.4.2 2 m 38 15 37 Section 3.5 (g N ) 9.816 m/s 2 m Section 3.5 3 g 1. h = 67.8 m g 1 m 3.86 1 6 m/s 2 g f : g f = 3.86 1 6 h m g B = 2πGρh ρ = 2.65 1 3 kg/m 3 G = 6.672 1 11 m 3 kg 1 s 2 2. g N g f g B g = (g + g f g B ) g N (3.5) 3.4.3 3 1. 2-2 1-4 2-2 1-4 3.4 2. ρ = 2.65 1 3 kg/m 3 g ρ

76 3 Section 3.5 3.5.1 2 m m 3.5.2 (g N ) 1984 g N = 9.783267714( 1 +.193185138639 sin2 λ ) (3.6) 1.66943799913 sin 2 λ (λ 3.5.3 h g(= g g f ) g R g R 2 = g (R + h) 2 ( mg = G mm R, mg = G mm 2 (R + h) ) (3.7) 2 (m: M: G: g g g =g+3.86 1 6 h g f = 3.86 1 6 h

3.5. 77 ρ h ρ g B g B = 2πGρh (3.8) g g N g g = (g + 3.86 1 6 h 2πGρh) g N (3.9) g > g < 3.5.4 S S A A M I l S θ d 2 dt θ(t) = 2 ω2 sin θ(t) (3.1) ω 2 = Mgl S I + Ml 2 S (3.11) θ d 2 dt θ(t) = ( 1 2 ω2 θ(t) 6 θ(t)3 + O(θ 5 ) ) (3.12) α α 4 θ(t) = α ( sin ωt 1 192 α2 sin 3ωt + O(α 4 ) ) (3.13) ω = ω ( 1 1 16 α2 + O(α 4 ) ) (3.14) I + Ml 2 ( S 1 T d = 2π 1 + Mgl S 16 α2 O(α 4 ) ) (3.15)

78 3 I T d T u T u I + Ml 2 ( S 1 T u = 2π 1 + Mgl S 16 α2 O(α 4 ) ) (3.16) (3.15) (3.16) I (3.1) 3.5.5 (3.2) g = (2π)2 l T 2 ( 1 + 1 8 α2) (3.2) l T α g T α l 1-4 l α l l δl l + δl (3.2) g l δl l = 999.14 ±.2 mm.2 mm (3.3) 1 C 15 C 22 C +.19 (22 15) = 1.133 999.14 mm 999.27 mm ±.2 mm.2 1.133 m m

3.5. 79 3.5.6 h r 99.93 mm 1.7 mm 1 mm.7 mm 1 mm δh δr(> ) h h δh h + δh V π V = πr 2 h (3.17) V + V + = π(r + δr) 2 (h + δh) = π(r 2 h + 2rhδr + hδr 2 + r2 δh + 2rδrδh + δr2 δh ) (3.18) 2 V + = π(r 2 h + 2rhδr + r 2 δh) (3.19) π(2rhδr + r 2 δh) V V = π(r 2 h 2rhδr r 2 δh) (3.2) V V + V δv ±π(2rhδr + r 2 δh) δv 1 2πrhδr V r r δr 2 V h δh δv δv = V r V δr + δh (3.21) h X Y Z R(X, Y, Z, ) δx δy δz R δr δr = R X δx + R Y R δy + δz + (3.22) Z δr δr = R X δx + R Y δy + R Z δz + (3.23)

8 3 3.5.7 (3.2) 3 ± g A.3 A.4 68.3% 1/3