laplace.dvi
|
|
- きゅういち こうい
- 5 years ago
- Views:
Transcription
1 Λ Λ 1
2 2 Ay = u 2 2 A 2 u " # a 11 a 12 A = ; u = a 21 a 22 " # u 1 u 2 y Ay = u (1) A (1) y = A 1 u y A 2 x i i i =1; 2 Ax 1 = 1 x 1 ; Ax 2 = 2 x 2 (2) x 1 x 2 =0 (3) (3) (2) x 1 x 2 x 1 x 1 =1; x 2 x 2 =1 (4) 2 2 (1) x 1 x 2 2 u x 1 x 2 1 u = U 1 x 1 + U 2 x 2 (5) U 1 U 2 u x 1 x 2 U 1 U 2 x 1 x 2 U 1 U 2 (5) U 1 = x 1 u; U 2 = x 2 u (6) x 1 u = x 1 (U 1 x 1 + U 2 x 2 ) = x 1 (U 1 x 1 )+x 1 (U 2 x 2 ) 2
3 u U 2 x 2 x 2 U 1 x 1 x 1 1: x 1 x 2 u U 1 U 2 (3) (4) x 1 u = U 1 (x 1 x 1 )+U 2 (x 1 x 2 ) = U 1 (6) U 1 U 2 y y x 1 x 2 Y 1 Y 2 y y = Y 1 x 1 + Y 2 x 2 (7) (1) y Y 1 Y 2 (5) (7) (1) A (Y 1 x 1 + Y 2 x 2 )=U 1 x 1 + U 2 x 2 (8) Y 1 Y 2 x 1 x 2 (8) A (Y 1 x 1 + Y 2 x 2 ) = Y 1 (Ax 1 )+Y 2 (Ax 2 ) = Y 1 ( 1 x 1 )+Y 2 ( 2 x 2 ) = ( 1 Y 1 ) x 1 +( 2 Y 2 ) x 2 (9) (8) (9) ( 1 Y 1 ) x 1 +( 2 Y 2 ) x 2 = U 1 x 1 + U 2 x 2 (10) 3
4 (1) (10) x 1 x 2 (10) 1 Y 1 = U 1 ; 2 Y 2 = U 2 (11) y y Y 1 = U 1 1 ; Y 2 = U 2 2 (11) y = U 1 1 x 1 + U 2 2 x 2 4
5 3 A 2 A 2 A (2) A 2 x 1 x 2 A 2 x 1 = A (Ax 1 ) = A ( 1 x 1 ) = 1 (Ax 1 ) = 2 1 x 1 A 2 x x 2 A A 2 A 2 A 2 y + Ay+ y = u (12) y A 2 y (7) A 2 (Y 1 x 1 + Y 2 x 2 )=( 2 1 Y 1) x 1 +( 2 2 Y 2) x 2 (13) (13) (12) (5) (7) ( 2 1 Y Y 1 + Y 1 ) x 1 +( 2 2 Y Y 2 + Y 2 ) x 2 = U 1 x 1 + U 2 x 2 (14) x 1 x 2 (14) Y 1 Y Y Y 1 + Y 1 = U Y Y 2 + Y 2 = U 2 Y 1 = U ; Y 2 = U (7) (12) y y = U x 1 + U x 2 A 2 2 n n (12) a 2 A 2 y + a 1 Ay+ a 0 y = b 0 u 5
6 y y = = b 0 U 1 b 0 U 2 b 0 U n a a x a 0 a a x 2 + ::: a 0 a a x n n 1 n + a 0 nx i=1 b 0 U i a a x i i 1 i + a 0 6
7 4 dy(t) = u(t) (15) y(t) t u(t) y(t) (15) d y(t) =u(t) (16) u(t) y(t) t u(t) t 1 t 2 ::: u(t 1 ) u(t 2 ) ::: 2 u(t) (16) d A y Ay y(t) (16) (1) d u(t) y(t) 3 d d d e j!t d ej!t = j! e j!t (17) e j!t d j! ej!t (17)!! e j!t u 6 - t 2: 7
8 y 6 - t d dy 6 - t u 6 - t 3:! e j!t U(j!) u(t) e j!t u(t) U(j!) u(t) = 1 1 U(j!) ej!t d! (18)! (18) (18) U(j!) (6) f (t) g(t) hf; gi hf; gi = 0 f (t) g(t) (19) f (t) f (t) (19) n (19) f (t) t hf; fi 0 n 2 8
9 (19) he j! 1t ;e j! 2t i =ffi(! 2! 1 ) (20) ffi( )! 1 6=! 2 ffi(! 2! 1 )=0 (20) e j! 1t e j! 2t U(j!) U(j!) = he j!t ;ui (21) = = e j!t u(t) (22) 0 u(t) e j!t (23) 0 (18) (23) (16) u(t) (16) y(t) (18) y(t) Y (j!) y(t) = 1 y(t) (18) (24) (16) d Z Y (j!) ej!t d! (24) = 1 1 Y (j!) ej!t d! d (Y (j!) ej!t ) d! = 1 1 Y (j!)(j! ej!t ) d! = 1 1 j! Y (j!) ej!t d! = 1 e j!t (25) (26) Y (j!) 1 U(j!) ej!t d! 1 U(j!) ej!t d! 1 U(j!) ej!t d! 1 U(j!) ej!t d! (25)! j! Y (j!)=u(j!) (26) Y (j!)= U(j!) (24) (27) Y (j!) y(t) j! (27) 9
10 5 d 2 2 n n 2 d 2 2 ej!t = d (j! ej!t ) = (j!) d ej!t = (j!) 2 e j!t e j!t (j!) 2 n n =2 n >2 d 2 y(t) 2 + dy(t) (28) d 2 + y(t) =u(t) (28) y(t) + d y(t) +y(t) =u(t) (29) 2 u(t) y(t) (24) d 2 y(t) = d = 1 = 1 Z 1 1 d 2 1 Y (j!) ej!t d! 2 (Y (j!) ej!t ) d! 1 (j!)2 Y (j!) e j!t d! (29) (18) (24) 1 1 ((j!)2 + j! +1)Y (j!) e j!t d! = 1 1 U(j!) ej!t d! (30) e j!t! (30) Y (j!) ((j!) 2 + j! +1)Y (j!)=u(j!) (31) Y (j!)= U(j!) (j!) 2 + j! +1 (32) 10
11 y(t) (29) d 2 a 2 y(t) +a d 2 1 y(t) +a d 0 y(t) =b 1 u(t) +b 0 u(t) (33) Y (j!) Y (j!)= b 1 (j!)+b 0 a 2 (j!) 2 + a 1 (j!)+a 0 U(j!) (34) d A ψ! ψ! e j!t ψ! j! ψ! ψ! 11
12 6 (23) u(t) t!1 t!1 u(t) lim u(t) =1 t!1 c>0 ^u(t) =u(t) e ct (35) lim ^u(t) =0 (36) t!1 u(t) =e t c =2 ^u(t) =e t e 2t = e t (36) (35) ^u(t) ^u(t) ^U (j!) ^u(t) = 1 1 ^U (j!) e j!t d! (37) u(t) =^u(t) e ct u(t) u(t) = ect 1 ^U (j!) e j!t d! (38) e ct u(t) = 1 = 1 1 ^U (j!) e ct e j!t d! 1 ^U (j!) e (c+j!) t d! (39) 12
13 e ct u(t) ^u(t) ^U (j!)! U(s) e ct 4: ^u(t) u(t) u(t) ^u(t) c>0 c>0 ^u(t) u(t) ^U(j!) (37) (18) (23) ^U(j!)= (35) ^U (j!) = = 0 ^u(t) e j!t (40) u(t) e ct e j!t 0 u(t) e (c+j!) t (41) 0 (39) (41) c + j! ^u(t) ^U(j!)= ^U(Im(c + j!)) j! c + j! ^U U c + j! s (39) u(t) = 1 j = 1 j 1 ^U (j!) e (c+j!) t jd! Z c+j1 c j1 U(s) est ds (42) (41) U(s) = u(t) e st (43) 0 13
14 (42) (43) 4 (39) (41) (42) (43) s c + j! (43) s (43) s c (38) c s = c j1 s = c + j! c c (42) (42) c 4 14
24 I ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x
24 I 1.1.. ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x 1 (t), x 2 (t),, x n (t)) ( ) ( ), γ : (i) x 1 (t),
More information5. [1 ] 1 [], u(x, t) t c u(x, t) x (5.3) ξ x + ct, η x ct (5.4),u(x, t) ξ, η u(ξ, η), ξ t,, ( u(ξ,η) ξ η u(x, t) t ) u(x, t) { ( u(ξ, η) c t ξ ξ { (
5 5.1 [ ] ) d f(t) + a d f(t) + bf(t) : f(t) 1 dt dt ) u(x, t) c u(x, t) : u(x, t) t x : ( ) ) 1 : y + ay, : y + ay + by : ( ) 1 ) : y + ay, : yy + ay 3 ( ): ( ) ) : y + ay, : y + ay b [],,, [ ] au xx
More informationuntitled
20010916 22;1017;23;20020108;15;20; 1 N = {1, 2, } Z + = {0, 1, 2, } Z = {0, ±1, ±2, } Q = { p p Z, q N} R = { lim a q n n a n Q, n N; sup a n < } R + = {x R x 0} n = {a + b 1 a, b R} u, v 1 R 2 2 R 3
More information.1 z = e x +xy y z y 1 1 x 0 1 z x y α β γ z = αx + βy + γ (.1) ax + by + cz = d (.1') a, b, c, d x-y-z (a, b, c). x-y-z 3 (0,
.1.1 Y K L Y = K 1 3 L 3 L K K (K + ) 1 1 3 L 3 K 3 L 3 K 0 (K + K) 1 3 L 3 K 1 3 L 3 lim K 0 K = L (K + K) 1 3 K 1 3 3 lim K 0 K = 1 3 K 3 L 3 z = f(x, y) x y z x-y-z.1 z = e x +xy y 3 x-y ( ) z 0 f(x,
More information20169 3 4 5003 n=3,000 61.8% 38.2% n=3,000 20 7.3% 30 21.3% 40 34.8% 50 36.6% n=3,000 3.0% 2.0% 1.5% 12.1% 14.0% 41.4% 25.9% n=3,000 37.7% % 24.8% 28.8% 1.9% 3.1% 0.2% n=3,000 500 64.0% 500 1,000 31.3%
More information1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0
1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0 0 < t < τ I II 0 No.2 2 C x y x y > 0 x 0 x > b a dx
More informationDecember 28, 2018
e-mail : kigami@i.kyoto-u.ac.jp December 28, 28 Contents 2............................. 3.2......................... 7.3..................... 9.4................ 4.5............. 2.6.... 22 2 36 2..........................
More informationNetcommunity SYSTEM X7000 IPコードレス電話機 取扱説明書
4 5 6 7 8 9 . 4 DS 0 4 5 4 4 4 5 5 6 7 8 9 0 4 5 6 7 8 9 4 5 6 4 0 4 4 4 4 5 6 7 8 9 40 4 4 4 4 44 45 4 6 7 5 46 47 4 5 6 48 49 50 5 4 5 4 5 6 5 5 6 4 54 4 5 6 7 55 5 6 4 56 4 5 6 57 4 5 6 7 58 4
More information.A. D.S
1999-1- .A. D.S 1996 2001 1999-2- -3- 1 p.16 17 18 19 2-4- 1-5- 1~2 1~2 2 5 1 34 2 10 3 2.6 2.85 3.05 2.9 2.9 3.16 4 7 9 9 17 9 25 10 3 10 8 10 17 10 18 10 22 11 29-6- 1 p.1-7- p.5-8- p.9 10 12 13-9- 2
More information2 1 κ c(t) = (x(t), y(t)) ( ) det(c (t), c x (t)) = det (t) x (t) y (t) y = x (t)y (t) x (t)y (t), (t) c (t) = (x (t)) 2 + (y (t)) 2. c (t) =
1 1 1.1 I R 1.1.1 c : I R 2 (i) c C (ii) t I c (t) (0, 0) c (t) c(i) c c(t) 1.1.2 (1) (2) (3) (1) r > 0 c : R R 2 : t (r cos t, r sin t) (2) C f : I R c : I R 2 : t (t, f(t)) (3) y = x c : R R 2 : t (t,
More information18 (1) US (2) US US US 90 (3) 2 8 1 18 108 2 2,000 3 6,000 4 33 2 17 5 2 3 1 2 8 6 7 7 2 2,000 8 1 8 19 9 10 2 2 7 11 2 12 28 1 2 11 7 1 1 1 1 1 1 3 2 3 33 2 1 3 2 3 2 16 2 8 3 28 8 3 5 13 1 14 15 1 2
More informationDVIOUT
A. A. A-- [ ] f(x) x = f 00 (x) f 0 () =0 f 00 () > 0= f(x) x = f 00 () < 0= f(x) x = A--2 [ ] f(x) D f 00 (x) > 0= y = f(x) f 00 (x) < 0= y = f(x) P (, f()) f 00 () =0 A--3 [ ] y = f(x) [, b] x = f (y)
More information数学概論I
{a n } M >0 s.t. a n 5 M for n =1, 2,... lim n a n = α ε =1 N s.t. a n α < 1 for n > N. n > N a n 5 a n α + α < 1+ α. M := max{ a 1,..., a N, 1+ α } a n 5 M ( n) 1 α α 1+ α t a 1 a N+1 a N+2 a 2 1 a n
More information1 8, : 8.1 1, 2 z = ax + by + c ax by + z c = a b +1 x y z c = 0, (0, 0, c), n = ( a, b, 1). f = n i=1 a ii x 2 i + i<j 2a ij x i x j = ( x, A x), f =
1 8, : 8.1 1, z = ax + by + c ax by + z c = a b +1 x y z c = 0, (0, 0, c), n = ( a, b, 1). f = a ii x i + i
More information() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)
0. A A = 4 IC () det A () A () x + y + z = x y z X Y Z = A x y z ( 5) ( s5590) 0. a + b + c b c () a a + b + c c a b a + b + c 0 a b c () a 0 c b b c 0 a c b a 0 0. A A = 7 5 4 5 0 ( 5) ( s5590) () A ()
More informationIA hara@math.kyushu-u.ac.jp Last updated: January,......................................................................................................................................................................................
More information弾性論(Chen)
Phase-field by T.Koyama Phase-field da da a( ) a + { } a d + d δ (-) δ (-) eigen a a a ε ε δ δ (-) da ε (-4) a d ε ε + δε ( ) (-5) δε d (-6) V u ul δεl + l (-7) eigen el ε ε ε (-8) σ el C ε el C { ε ε
More information『こみの株式会社』の実践
2003 . JA JA A JA 811 2005/8/11 1003 452 10 960 28 2005/8/11 1003 452 6 120 29 2005/8/11 2003 151 10 420 33 2005/8/11 2003 211 3 180 31 2005/8/11 2003 211 3 150 32 827 400 5 80 221 2005/6/25 900 3 300
More information15 7 26 1,276 3,800 1 16 15 1 2 3 4 2
1 15 7 26 1,276 3,800 1 16 15 1 2 3 4 2 JA 3 4 2 1 3 2001 1981 6 10% 10 30% 1 2 JA JA 2 4 JA 2 1 2 1 2 1 2 1 2 1 2 7 5 1 1 1 3 1 6 1 1 2 2 1 7 2 3 3 53 1 2000 30 8 250 53 435 20 35 3 1 8 2 4 3 2 2 232
More informationEX-word_Library_JA
JA 2 3 4 5 14 7 1 2 6 3 1 2 7 3 8 27 1 2 3 1 2 3 9 1 2 3 1 2 3 10 12 13 14 11 1 12 1 2 13 1 2 3 25 14 1 2 3 25 15 1 2 3 25 16 1 2 3 25 17 1 2 3 25 18 1 2 3 4 25 19 1 2 3 4 25 20 1 2 21 3 4 25 22 1 2 3
More information324.pdf
50 50 10 30 11 26 12 27 14 16 27 18 20 21 22 22 22 22 23 24 24 1 No.324 JA 2 85 69 20 12 81 18 12 22 93 10 31 3 50 50 30 30 50 22 27 27 10 16 14 52 10 62 15 64 25 24 50 4 25 23 27 5 10 11 25 6 11 49 10
More information( ) 2.1. C. (1) x 4 dx = 1 5 x5 + C 1 (2) x dx = x 2 dx = x 1 + C = 1 2 x + C xdx (3) = x dx = 3 x C (4) (x + 1) 3 dx = (x 3 + 3x 2 + 3x +
(.. C. ( d 5 5 + C ( d d + C + C d ( d + C ( ( + d ( + + + d + + + + C (5 9 + d + d tan + C cos (sin (6 sin d d log sin + C sin + (7 + + d ( + + + + d log( + + + C ( (8 d 7 6 d + 6 + C ( (9 ( d 6 + 8 d
More information,. Black-Scholes u t t, x c u 0 t, x x u t t, x c u t, x x u t t, x + σ x u t, x + rx ut, x rux, t 0 x x,,.,. Step 3, 7,,, Step 6., Step 4,. Step 5,,.
9 α ν β Ξ ξ Γ γ o δ Π π ε ρ ζ Σ σ η τ Θ θ Υ υ ι Φ φ κ χ Λ λ Ψ ψ µ Ω ω Def, Prop, Th, Lem, Note, Remark, Ex,, Proof, R, N, Q, C [a, b {x R : a x b} : a, b {x R : a < x < b} : [a, b {x R : a x < b} : a,
More informationNo δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i x j δx j (5) δs 2
No.2 1 2 2 δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i δx j (5) δs 2 = δx i δx i + 2 u i δx i δx j = δs 2 + 2s ij δx i δx j
More information214 March 31, 214, Rev.2.1 4........................ 4........................ 5............................. 7............................... 7 1 8 1.1............................... 8 1.2.......................
More informationTOP URL 1
TOP URL http://amonphys.web.fc.com/ 3.............................. 3.............................. 4.3 4................... 5.4........................ 6.5........................ 8.6...........................7
More information( ) sin 1 x, cos 1 x, tan 1 x sin x, cos x, tan x, arcsin x, arccos x, arctan x. π 2 sin 1 x π 2, 0 cos 1 x π, π 2 < tan 1 x < π 2 1 (1) (
6 20 ( ) sin, cos, tan sin, cos, tan, arcsin, arccos, arctan. π 2 sin π 2, 0 cos π, π 2 < tan < π 2 () ( 2 2 lim 2 ( 2 ) ) 2 = 3 sin (2) lim 5 0 = 2 2 0 0 2 2 3 3 4 5 5 2 5 6 3 5 7 4 5 8 4 9 3 4 a 3 b
More information微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 初版 1 刷発行時のものです.
微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. ttp://www.morikita.co.jp/books/mid/00571 このサンプルページの内容は, 初版 1 刷発行時のものです. i ii 014 10 iii [note] 1 3 iv 4 5 3 6 4 x 0 sin x x 1 5 6 z = f(x, y) 1 y = f(x)
More information20 4 20 i 1 1 1.1............................ 1 1.2............................ 4 2 11 2.1................... 11 2.2......................... 11 2.3....................... 19 3 25 3.1.............................
More informationf (x) f (x) f (x) f (x) f (x) 2 f (x) f (x) f (x) f (x) 2 n f (x) n f (n) (x) dn f f (x) dx n dn dx n D n f (x) n C n C f (x) x = a 1 f (x) x = a x >
5.1 1. x = a f (x) a x h f (a + h) f (a) h (5.1) h 0 f (x) x = a f +(a) f (a + h) f (a) = lim h +0 h (5.2) x h h 0 f (a) f (a + h) f (a) f (a h) f (a) = lim = lim h 0 h h 0 h (5.3) f (x) x = a f (a) =
More informationMicrosoft Word - 触ってみよう、Maximaに2.doc
i i e! ( x +1) 2 3 ( 2x + 3)! ( x + 1) 3 ( a + b) 5 2 2 2 2! 3! 5! 7 2 x! 3x! 1 = 0 ",! " >!!! # 2x + 4y = 30 "! x + y = 12 sin x lim x!0 x x n! # $ & 1 lim 1 + ('% " n 1 1 lim lim x!+0 x x"!0 x log x
More information( )
( ) ( 27) ( 28) ( ) 170ha 62 ょ - 1 - ( ) 50-2 - ( ) JA - 3 - ( ) - 4 - ( ) - 5 - ( ) - 6 - ( ) HP - 7 - ( ) - 8 - ( ) ( ) - 9 - ( ) - 10 - ( ) - 11 - ( ) - 12 - ( ) - 13 - ( ) - 14 - ( ) 9 15 16 2,000
More informationIntroduction to Numerical Analysis of Differential Equations Naoya Enomoto (Kyoto.univ.Dept.Science(math))
Introduction to Numerical Analysis of Differential Equations Naoya Enomoto (Kyoto.univ.Dept.Science(math)) 2001 1 e-mail:s00x0427@ip.media.kyoto-u.ac.jp 1 1 Van der Pol 1 1 2 2 Bergers 2 KdV 2 1 5 1.1........................................
More informationfa-problem.dvi
6//4 by. : : : : : : : : : : : : : : :. : : : : : : : : : : : : : : 3. : : : : : : : : : 4. : : : : : : : : : 3 5. : : : : : : : : : : : : : : : : : : : 3 6. : : : : : : : : : : : : 3 7. : : : : : : :
More information213 March 25, 213, Rev.1.5 4........................ 4........................ 6 1 8 1.1............................... 8 1.2....................... 9 2 14 2.1..................... 14 2.2............................
More information23 7 28 i i 1 1 1.1................................... 2 1.2............................... 3 1.2.1.................................... 3 1.2.2............................... 4 1.2.3 SI..............................
More information(3) (2),,. ( 20) ( s200103) 0.7 x C,, x 2 + y 2 + ax = 0 a.. D,. D, y C, C (x, y) (y 0) C m. (2) D y = y(x) (x ± y 0), (x, y) D, m, m = 1., D. (x 2 y
[ ] 7 0.1 2 2 + y = t sin t IC ( 9) ( s090101) 0.2 y = d2 y 2, y = x 3 y + y 2 = 0 (2) y + 2y 3y = e 2x 0.3 1 ( y ) = f x C u = y x ( 15) ( s150102) [ ] y/x du x = Cexp f(u) u (2) x y = xey/x ( 16) ( s160101)
More informationJacobson Prime Avoidance
2016 2017 2 22 1 1 3 2 4 2.1 Jacobson................. 4 2.2.................... 5 3 6 3.1 Prime Avoidance....................... 7 3.2............................. 8 3.3..............................
More informationmeiji_resume_1.PDF
β β β (q 1,q,..., q n ; p 1, p,..., p n ) H(q 1,q,..., q n ; p 1, p,..., p n ) Hψ = εψ ε k = k +1/ ε k = k(k 1) (x, y, z; p x, p y, p z ) (r; p r ), (θ; p θ ), (ϕ; p ϕ ) ε k = 1/ k p i dq i E total = E
More information2 0.1 Introduction NMR 70% 1/2
Y. Kondo 2010 1 22 2 0.1 Introduction NMR 70% 1/2 3 0.1 Introduction......................... 2 1 7 1.1.................... 7 1.2............................ 11 1.3................... 12 1.4..........................
More informationPart y mx + n mt + n m 1 mt n + n t m 2 t + mn 0 t m 0 n 18 y n n a 7 3 ; x α α 1 7α +t t 3 4α + 3t t x α x α y mx + n
Part2 47 Example 161 93 1 T a a 2 M 1 a 1 T a 2 a Point 1 T L L L T T L L T L L L T T L L T detm a 1 aa 2 a 1 2 + 1 > 0 11 T T x x M λ 12 y y x y λ 2 a + 1λ + a 2 2a + 2 0 13 D D a + 1 2 4a 2 2a + 2 a
More information構造と連続体の力学基礎
II 37 Wabash Avenue Bridge, Illinois 州 Winnipeg にある歩道橋 Esplanade Riel 橋6 6 斜張橋である必要は多分無いと思われる すぐ横に道路用桁橋有り しかも塔基部のレストランは 8 年には営業していなかった 9 9. 9.. () 97 [3] [5] k 9. m w(t) f (t) = f (t) + mg k w(t) Newton
More information曲面のパラメタ表示と接線ベクトル
L11(2011-07-06 Wed) :Time-stamp: 2011-07-06 Wed 13:08 JST hig 1,,. 2. http://hig3.net () (L11) 2011-07-06 Wed 1 / 18 ( ) 1 V = (xy2 ) x + (2y) y = y 2 + 2. 2 V = 4y., D V ds = 2 2 ( ) 4 x 2 4y dy dx =
More information(1) (2) (3) (4) HB B ( ) (5) (6) (7) 40 (8) (9) (10)
2017 12 9 4 1 30 4 10 3 1 30 3 30 2 1 30 2 50 1 1 30 2 10 (1) (2) (3) (4) HB B ( ) (5) (6) (7) 40 (8) (9) (10) (1) i 23 c 23 0 1 2 3 4 5 6 7 8 9 a b d e f g h i (2) 23 23 (3) 23 ( 23 ) 23 x 1 x 2 23 x
More informationarma dvi
ARMA 007/05/0 Rev.0 007/05/ Rev.0 007/07/7 3. : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : 3. : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : 3.3 : : : :
More informationgrad φ(p ) φ P grad φ(p ) p P p φ P p l t φ l t = 0 g (0) g (0) (31) grad φ(p ) p grad φ φ (P, φ(p )) xy (x, y) = (ξ(t), η(t)) ( )
2 9 2 5 2.2.3 grad φ(p ) φ P grad φ(p ) p P p φ P p l t φ l t = g () g () (3) grad φ(p ) p grad φ φ (P, φ(p )) y (, y) = (ξ(t), η(t)) ( ) ξ (t) (t) := η (t) grad f(ξ(t), η(t)) (t) g(t) := f(ξ(t), η(t))
More informationmugensho.dvi
1 1 f (t) lim t a f (t) = 0 f (t) t a 1.1 (1) lim(t 1) 2 = 0 t 1 (t 1) 2 t 1 (2) lim(t 1) 3 = 0 t 1 (t 1) 3 t 1 2 f (t), g(t) t a lim t a f (t) g(t) g(t) f (t) = o(g(t)) (t a) = 0 f (t) (t 1) 3 1.2 lim
More informationNote.tex 2008/09/19( )
1 20 9 19 2 1 5 1.1........................ 5 1.2............................. 8 2 9 2.1............................. 9 2.2.............................. 10 3 13 3.1.............................. 13 3.2..................................
More informationx () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x
[ ] IC. f(x) = e x () f(x) f (x) () lim f(x) lim f(x) x + x (3) lim f(x) lim f(x) x + x (4) y = f(x) ( ) ( s46). < a < () a () lim a log xdx a log xdx ( ) n (3) lim log k log n n n k=.3 z = log(x + y ),
More informationV 0 = + r pv (H) + qv (T ) = + r ps (H) + qs (T ) = S 0 X n+ (T ) = n S n+ (T ) + ( + r)(x n n S n ) = ( + r)x n + n (d r)s n = ( + r)v n + V n+(h) V
I (..2) (0 < d < + r < u) X 0, X X = 0 S + ( + r)(x 0 0 S 0 ) () X 0 = 0, P (X 0) =, P (X > 0) > 0 0 H, T () X 0 = 0, X (H) = 0 us 0 ( + r) 0 S 0 = 0 S 0 (u r) X (T ) = 0 ds 0 ( + r) 0 S 0 = 0 S 0 (d r)
More information211 kotaro@math.titech.ac.jp 1 R *1 n n R n *2 R n = {(x 1,..., x n ) x 1,..., x n R}. R R 2 R 3 R n R n R n D D R n *3 ) (x 1,..., x n ) f(x 1,..., x n ) f D *4 n 2 n = 1 ( ) 1 f D R n f : D R 1.1. (x,
More informationx ( ) x dx = ax
x ( ) x dx = ax 1 dx = a x log x = at + c x(t) = e at C (C = e c ) a > 0 t a < 0 t 0 (at + b ) h dx = lim x(t + h) x(t) h 0 h x(t + h) x(t) h x(t) t x(t + h) x(t) ax(t) h x(t + h) x(t) + ahx(t) 0, h, 2h,
More informationX線-m.dvi
X Λ 1 X 1 O Y Z X Z ν X O r Y ' P I('; r) =I e 4 m c 4 1 r sin ' (1.1) I X 1sec 1cm e = 4:8 1 1 e.s.u. m = :1 1 8 g c =3: 1 1 cm/sec X sin '! 1 ß Z ß Z sin 'd! = 1 ß ß 1 sin χ cos! d! = 1+cos χ (1.) e
More information2 G(k) e ikx = (ik) n x n n! n=0 (k ) ( ) X n = ( i) n n k n G(k) k=0 F (k) ln G(k) = ln e ikx n κ n F (k) = F (k) (ik) n n= n! κ n κ n = ( i) n n k n
. X {x, x 2, x 3,... x n } X X {, 2, 3, 4, 5, 6} X x i P i. 0 P i 2. n P i = 3. P (i ω) = i ω P i P 3 {x, x 2, x 3,... x n } ω P i = 6 X f(x) f(x) X n n f(x i )P i n x n i P i X n 2 G(k) e ikx = (ik) n
More informationsimx simxdx, cosxdx, sixdx 6.3 px m m + pxfxdx = pxf x p xf xdx = pxf x p xf x + p xf xdx 7.4 a m.5 fx simxdx 8 fx fx simxdx = πb m 9 a fxdx = πa a =
II 6 ishimori@phys.titech.ac.jp 6.. 5.4.. f Rx = f Lx = fx fx + lim = lim x x + x x f c = f x + x < c < x x x + lim x x fx fx x x = lim x x f c = f x x < c < x cosmx cosxdx = {cosm x + cosm + x} dx = [
More informationu = u(t, x 1,..., x d ) : R R d C λ i = 1 := x 2 1 x 2 d d Euclid Laplace Schrödinger N := {1, 2, 3,... } Z := {..., 3, 2, 1,, 1, 2, 3
2 2 1 5 5 Schrödinger i u t + u = λ u 2 u. u = u(t, x 1,..., x d ) : R R d C λ i = 1 := 2 + + 2 x 2 1 x 2 d d Euclid Laplace Schrödinger 3 1 1.1 N := {1, 2, 3,... } Z := {..., 3, 2, 1,, 1, 2, 3,... } Q
More information2 1 x 1.1: v mg x (t) = v(t) mv (t) = mg 0 x(0) = x 0 v(0) = v 0 x(t) = x 0 + v 0 t 1 2 gt2 v(t) = v 0 gt t x = x 0 + v2 0 2g v2 2g 1.1 (x, v) θ
1 1 1.1 (Isaac Newton, 1642 1727) 1. : 2. ( ) F = ma 3. ; F a 2 t x(t) v(t) = x (t) v (t) = x (t) F 3 3 3 3 3 3 6 1 2 6 12 1 3 1 2 m 2 1 x 1.1: v mg x (t) = v(t) mv (t) = mg 0 x(0) = x 0 v(0) = v 0 x(t)
More information.5 z = a + b + c n.6 = a sin t y = b cos t dy d a e e b e + e c e e e + e 3 s36 3 a + y = a, b > b 3 s363.7 y = + 3 y = + 3 s364.8 cos a 3 s365.9 y =,
[ ] IC. r, θ r, θ π, y y = 3 3 = r cos θ r sin θ D D = {, y ; y }, y D r, θ ep y yddy D D 9 s96. d y dt + 3dy + y = cos t dt t = y = e π + e π +. t = π y =.9 s6.3 d y d + dy d + y = y =, dy d = 3 a, b
More informationMY16_R8_DI_ indd
R8 Audi R8 Coupé Data Information Audi R8 Specifications mm 4,426 1,940 1,240 4,426 1,940 1,240 mm 2,650 2,650 : mm 1,638 1,638 : mm 1,599 1,599 kg 1,670 1,630 4WD 4WD cc 5,204 5,204 V 10 DOHC V 10 DOHC
More information, x R, f (x),, df dx : R R,, f : R R, f(x) ( ).,, f (a) d f dx (a), f (a) d3 f dx 3 (a),, f (n) (a) dn f dx n (a), f d f dx, f d3 f dx 3,, f (n) dn f
,,,,.,,,. R f : R R R a R, f(a + ) f(a) lim 0 (), df dx (a) f (a), f(x) x a, f (a), f(x) x a ( ). y f(a + ) y f(x) f(a+) f(a) f(a + ) f(a) f(a) x a 0 a a + x 0 a a + x y y f(x) 0 : 0, f(a+) f(a)., f(x)
More informationK E N Z OU
K E N Z OU 11 1 1 1.1..................................... 1.1.1............................ 1.1..................................................................................... 4 1.........................................
More informationac b 0 r = r a 0 b 0 y 0 cy 0 ac b 0 f(, y) = a + by + cy ac b = 0 1 ac b = 0 z = f(, y) f(, y) 1 a, b, c 0 a 0 f(, y) = a ( ( + b ) ) a y ac b + a y
01 4 17 1.. y f(, y) = a + by + cy + p + qy + r a, b, c 0 y b b 1 z = f(, y) z = a + by + cy z = p + qy + r (, y) z = p + qy + r 1 y = + + 1 y = y = + 1 6 + + 1 ( = + 1 ) + 7 4 16 y y y + = O O O y = y
More informationS I. dy fx x fx y fx + C 3 C vt dy fx 4 x, y dy yt gt + Ct + C dt v e kt xt v e kt + C k x v k + C C xt v k 3 r r + dr e kt S Sr πr dt d v } dt k e kt
S I. x yx y y, y,. F x, y, y, y,, y n http://ayapin.film.s.dendai.ac.jp/~matuda n /TeX/lecture.html PDF PS yx.................................... 3.3.................... 9.4................5..............
More information( ) ( )
20 21 2 8 1 2 2 3 21 3 22 3 23 4 24 5 25 5 26 6 27 8 28 ( ) 9 3 10 31 10 32 ( ) 12 4 13 41 0 13 42 14 43 0 15 44 17 5 18 6 18 1 1 2 2 1 2 1 0 2 0 3 0 4 0 2 2 21 t (x(t) y(t)) 2 x(t) y(t) γ(t) (x(t) y(t))
More information4.6: 3 sin 5 sin θ θ t θ 2t θ 4t : sin ωt ω sin θ θ ωt sin ωt 1 ω ω [rad/sec] 1 [sec] ω[rad] [rad/sec] 5.3 ω [rad/sec] 5.7: 2t 4t sin 2t sin 4t
1 1.1 sin 2π [rad] 3 ft 3 sin 2t π 4 3.1 2 1.1: sin θ 2.2 sin θ ft t t [sec] t sin 2t π 4 [rad] sin 3.1 3 sin θ θ t θ 2t π 4 3.2 3.1 3.4 3.4: 2.2: sin θ θ θ [rad] 2.3 0 [rad] 4 sin θ sin 2t π 4 sin 1 1
More informationt = h x z z = h z = t (x, z) (v x (x, z, t), v z (x, z, t)) ρ v x x + v z z = 0 (1) 2-2. (v x, v z ) φ(x, z, t) v x = φ x, v z
I 1 m 2 l k 2 x = 0 x 1 x 1 2 x 2 g x x 2 x 1 m k m 1-1. L x 1, x 2, ẋ 1, ẋ 2 ẋ 1 x = 0 1-2. 2 Q = x 1 + x 2 2 q = x 2 x 1 l L Q, q, Q, q M = 2m µ = m 2 1-3. Q q 1-4. 2 x 2 = h 1 x 1 t = 0 2 1 t x 1 (t)
More information(u(x)v(x)) = u (x)v(x) + u(x)v (x) ( ) u(x) = u (x)v(x) u(x)v (x) v(x) v(x) 2 y = g(t), t = f(x) y = g(f(x)) dy dx dy dx = dy dt dt dx., y, f, g y = f (g(x))g (x). ( (f(g(x)). ). [ ] y = e ax+b (a, b )
More information「国債の金利推定モデルに関する研究会」報告書
: LG 19 7 26 2 LG Quadratic Gaussian 1 30 30 3 4 2,,, E-mail: kijima@center.tmu.ac.jp, E-mail: tanaka-keiichi@tmu.ac.jp 1 L G 2 1 L G r L t),r G t) L r L t) G r G t) r L t) h G t) =r G t) r L t) r L t)
More information2 0 B B B B - B B - B - - B (1.0.6) 0 1 p /p p {0} (1.0.7) B m n ϕ : B ϕ(m) n ϕ 1 (n) = m /m B/n 1.1. (1.1.1) a a n > 0 x n a x r(a) a r(r(a)) = r(a)
1 0 1. 1.0. (1.0.1) - (1.0.2), B ϕ : B resp. B- M a m = ϕ(a) m (resp. m a = m ϕ(a)) resp. - M - B- resp. - M [ϕ] L - u : L M [ϕ] a x L u(a x) = ϕ(a) u(x) ϕ- L M (ϕ, u) u (, L) (B, M) - L (, L) (1.0.3)
More information( ) x y f(x, y) = ax
013 4 16 5 54 (03-5465-7040) nkiyono@mail.ecc.u-okyo.ac.jp hp://lecure.ecc.u-okyo.ac.jp/~nkiyono/inde.hml 1.. y f(, y) = a + by + cy + p + qy + r a, b, c 0 y b b 1 z = f(, y) z = a + by + cy z = p + qy
More informationII 2 II
II 2 II 2005 yugami@cc.utsunomiya-u.ac.jp 2005 4 1 1 2 5 2.1.................................... 5 2.2................................. 6 2.3............................. 6 2.4.................................
More information(1) 1 y = 2 = = b (2) 2 y = 2 = 2 = 2 + h B h h h< h 2 h
6 6.1 6.1.1 O y A y y = f() y = f() b f(b) B y f(b) f() = b f(b) f() f() = = b A f() b AB O b 6.1 2 y = 2 = 1 = 1 + h (1 + h) 2 1 2 (1 + h) 1 2h + h2 = h h(2 + h) = h = 2 + h y (1 + h) 2 1 2 O y = 2 1
More informationS I. dy fx x fx y fx + C 3 C dy fx 4 x, y dy v C xt y C v e kt k > xt yt gt [ v dt dt v e kt xt v e kt + C k x v + C C k xt v k 3 r r + dr e kt S dt d
S I.. http://ayapin.film.s.dendai.ac.jp/~matuda /TeX/lecture.html PDF PS.................................... 3.3.................... 9.4................5.............. 3 5. Laplace................. 5....
More informationdifgeo1.dvi
1 http://matlab0.hwe.oita-u.ac.jp/ matsuo/difgeo.pdf ver.1 8//001 1 1.1 a A. O 1 e 1 ; e ; e e 1 ; e ; e x 1 ;x ;x e 1 ; e ; e X x x x 1 ;x ;x X (x 1 ;x ;x ) 1 1 x x X e e 1 O e x x 1 x x = x 1 e 1 + x
More information2004 10 2004 1984 2 1986 4 20 60 1 3 1 1 1 13,300 2 2 2 3 1 2004 2009 2 1 1 2 1 1985 97JR JT NTT 2002 96 97 4 JR JT 97 3 JR 19 29 JT 2.4 2.5 JR JT NTT JR JT NTT 2 97 4 JR 20.09 JT 19.92 NTT 17.35 17.35
More informationdi-problem.dvi
III 005/06/6 by. : : : : : : : : : : : : : : : : : : : : :. : : : : : : : : : : : : : : : : : : : : : : : : : : 3 3. : : : : : : : : : : : : : : 4 4. : : : : : : : : : : : : : : : : : : : : : : 5 5. :
More information7. y fx, z gy z gfx dz dx dz dy dy dx. g f a g bf a b fa 7., chain ule Ω, D R n, R m a Ω, f : Ω R m, g : D R l, fω D, b fa, f a g b g f a g f a g bf a
9 203 6 7 WWW http://www.math.meiji.ac.jp/~mk/lectue/tahensuu-203/ 2 8 8 7. 7 7. y fx, z gy z gfx dz dx dz dy dy dx. g f a g bf a b fa 7., chain ule Ω, D R n, R m a Ω, f : Ω R m, g : D R l, fω D, b fa,
More information1 I 1.1 ± e = = - = C C MKSA [m], [Kg] [s] [A] 1C 1A 1 MKSA 1C 1C +q q +q q 1
1 I 1.1 ± e = = - =1.602 10 19 C C MKA [m], [Kg] [s] [A] 1C 1A 1 MKA 1C 1C +q q +q q 1 1.1 r 1,2 q 1, q 2 r 12 2 q 1, q 2 2 F 12 = k q 1q 2 r 12 2 (1.1) k 2 k 2 ( r 1 r 2 ) ( r 2 r 1 ) q 1 q 2 (q 1 q 2
More information数値計算:有限要素法
( ) 1 / 61 1 2 3 4 ( ) 2 / 61 ( ) 3 / 61 P(0) P(x) u(x) P(L) f P(0) P(x) P(L) ( ) 4 / 61 L P(x) E(x) A(x) x P(x) P(x) u(x) P(x) u(x) (0 x L) ( ) 5 / 61 u(x) 0 L x ( ) 6 / 61 P(0) P(L) f d dx ( EA du dx
More informationhttp://www.ns.kogakuin.ac.jp/~ft13389/lecture/physics1a2b/ pdf I 1 1 1.1 ( ) 1. 30 m µm 2. 20 cm km 3. 10 m 2 cm 2 4. 5 cm 3 km 3 5. 1 6. 1 7. 1 1.2 ( ) 1. 1 m + 10 cm 2. 1 hr + 6400 sec 3. 3.0 10 5 kg
More informationRadiation from moving charges#1 Liénard-Wiechert potential Yuji Chinone 1 Maxwell Maxwell MKS E (x, t) + B (x, t) t = 0 (1) B (x, t) = 0 (2) B (x, t)
Radiation from moving harges# Liénard-Wiehert potential Yuji Chinone Maxwell Maxwell MKS E x, t + B x, t = B x, t = B x, t E x, t = µ j x, t 3 E x, t = ε ρ x, t 4 ε µ ε µ = E B ρ j A x, t φ x, t A x, t
More information応力とひずみ.ppt
in yukawa@numse.nagoya-u.ac.jp 2 3 4 5 x 2 6 Continuum) 7 8 9 F F 10 F L L F L 1 L F L F L F 11 F L F F L F L L L 1 L 2 12 F L F! A A! S! = F S 13 F L L F F n = F " cos# F t = F " sin# S $ = S cos# S S
More informationDynkin Serre Weyl
Dynkin Naoya Enomoto 2003.3. paper Dynkin Introduction Dynkin Lie Lie paper 1 0 Introduction 3 I ( ) Lie Dynkin 4 1 ( ) Lie 4 1.1 Lie ( )................................ 4 1.2 Killing form...........................................
More information120 9 I I 1 I 2 I 1 I 2 ( a) ( b) ( c ) I I 2 I 1 I ( d) ( e) ( f ) 9.1: Ampère (c) (d) (e) S I 1 I 2 B ds = µ 0 ( I 1 I 2 ) I 1 I 2 B ds =0. I 1 I 2
9 E B 9.1 9.1.1 Ampère Ampère Ampère s law B S µ 0 B ds = µ 0 j ds (9.1) S rot B = µ 0 j (9.2) S Ampère Biot-Savart oulomb Gauss Ampère rot B 0 Ampère µ 0 9.1 (a) (b) I B ds = µ 0 I. I 1 I 2 B ds = µ 0
More information( )
7..-8..8.......................................................................... 4.................................... 3...................................... 3..3.................................. 4.3....................................
More information,.,. 2, R 2, ( )., I R. c : I R 2, : (1) c C -, (2) t I, c (t) (0, 0). c(i). c (t)., c(t) = (x(t), y(t)) c (t) = (x (t), y (t)) : (1)
( ) 1., : ;, ;, ; =. ( ).,.,,,., 2.,.,,.,.,,., y = f(x), f ( ).,,.,.,., U R m, F : U R n, M, f : M R p M, p,, R m,,, R m. 2009 A tamaru math.sci.hiroshima-u.ac.jp 1 ,.,. 2, R 2, ( ).,. 2.1 2.1. I R. c
More informationMY16_R8_DI_ indd
R8 Audi R8 Coupé Data Information Audi R8 Specifications R8 Coupé V10 5.2 FSI quattro R8 Coupé V10 plus 5.2 FSI quattro ABA-4SCSPF ABA-4SCSPD mm 4,425 1,940 1,240 4,425 1,940 1,240 mm 2,650 2,650 : mm
More information