学習内容と日常生活との関連性の研究-第2部-第4章-1

Similar documents
() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)

() (, y) E(, y) () E(, y) (3) q ( ) () E(, y) = k q q (, y) () E(, y) = k r r (3).3 [.7 ] f y = f y () f(, y) = y () f(, y) = tan y y ( ) () f y = f y

S I. dy fx x fx y fx + C 3 C vt dy fx 4 x, y dy yt gt + Ct + C dt v e kt xt v e kt + C k x v k + C C xt v k 3 r r + dr e kt S Sr πr dt d v } dt k e kt

1. (8) (1) (x + y) + (x + y) = 0 () (x + y ) 5xy = 0 (3) (x y + 3y 3 ) (x 3 + xy ) = 0 (4) x tan y x y + x = 0 (5) x = y + x + y (6) = x + y 1 x y 3 (

S I. dy fx x fx y fx + C 3 C dy fx 4 x, y dy v C xt y C v e kt k > xt yt gt [ v dt dt v e kt xt v e kt + C k x v + C C k xt v k 3 r r + dr e kt S dt d

chap1.dvi

1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0

[ ] 0.1 lim x 0 e 3x 1 x IC ( 11) ( s114901) 0.2 (1) y = e 2x (x 2 + 1) (2) y = x/(x 2 + 1) 0.3 dx (1) 1 4x 2 (2) e x sin 2xdx (3) sin 2 xdx ( 11) ( s

TOP URL 1

振動と波動

x () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x


December 28, 2018

A (1) = 4 A( 1, 4) 1 A 4 () = tan A(0, 0) π A π

高等学校学習指導要領解説 数学編


4 4 θ X θ P θ 4. 0, 405 P 0 X 405 X P 4. () 60 () 45 () 40 (4) 765 (5) 40 B 60 0 P = 90, = ( ) = X

08-Note2-web

( ) 2.1. C. (1) x 4 dx = 1 5 x5 + C 1 (2) x dx = x 2 dx = x 1 + C = 1 2 x + C xdx (3) = x dx = 3 x C (4) (x + 1) 3 dx = (x 3 + 3x 2 + 3x +

W u = u(x, t) u tt = a 2 u xx, a > 0 (1) D := {(x, t) : 0 x l, t 0} u (0, t) = 0, u (l, t) = 0, t 0 (2)

(3) (2),,. ( 20) ( s200103) 0.7 x C,, x 2 + y 2 + ax = 0 a.. D,. D, y C, C (x, y) (y 0) C m. (2) D y = y(x) (x ± y 0), (x, y) D, m, m = 1., D. (x 2 y

1 1 sin cos P (primary) S (secondly) 2 P S A sin(ω2πt + α) A ω 1 ω α V T m T m 1 100Hz m 2 36km 500Hz. 36km 1

18 ( ) I II III A B C(100 ) 1, 2, 3, 5 I II A B (100 ) 1, 2, 3 I II A B (80 ) 6 8 I II III A B C(80 ) 1 n (1 + x) n (1) n C 1 + n C

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0

SO(2)

pdf

II K116 : January 14, ,. A = (a ij ) ij m n. ( ). B m n, C n l. A = max{ a ij }. ij A + B A + B, AC n A C (1) 1. m n (A k ) k=1,... m n A, A k k

入試の軌跡

DVIOUT

DE-resume

1 θ i (1) A B θ ( ) A = B = sin 3θ = sin θ (A B sin 2 θ) ( ) 1 2 π 3 < = θ < = 2 π 3 Ax Bx3 = 1 2 θ = π sin θ (2) a b c θ sin 5θ = sin θ f(sin 2 θ) 2

m(ẍ + γẋ + ω 0 x) = ee (2.118) e iωt P(ω) = χ(ω)e = ex = e2 E(ω) m ω0 2 ω2 iωγ (2.119) Z N ϵ(ω) ϵ 0 = 1 + Ne2 m j f j ω 2 j ω2 iωγ j (2.120)

II Karel Švadlenka * [1] 1.1* 5 23 m d2 x dt 2 = cdx kx + mg dt. c, g, k, m 1.2* u = au + bv v = cu + dv v u a, b, c, d R

( ) sin 1 x, cos 1 x, tan 1 x sin x, cos x, tan x, arcsin x, arccos x, arctan x. π 2 sin 1 x π 2, 0 cos 1 x π, π 2 < tan 1 x < π 2 1 (1) (

2 1 x 1.1: v mg x (t) = v(t) mv (t) = mg 0 x(0) = x 0 v(0) = v 0 x(t) = x 0 + v 0 t 1 2 gt2 v(t) = v 0 gt t x = x 0 + v2 0 2g v2 2g 1.1 (x, v) θ

Note.tex 2008/09/19( )

数学Ⅱ演習(足助・09夏)

LCR e ix LC AM m k x m x x > 0 x < 0 F x > 0 x < 0 F = k x (k > 0) k x = x(t)

function2.pdf

Part () () Γ Part ,

) a + b = i + 6 b c = 6i j ) a = 0 b = c = 0 ) â = i + j 0 ˆb = 4) a b = b c = j + ) cos α = cos β = 6) a ˆb = b ĉ = 0 7) a b = 6i j b c = i + 6j + 8)

,. Black-Scholes u t t, x c u 0 t, x x u t t, x c u t, x x u t t, x + σ x u t, x + rx ut, x rux, t 0 x x,,.,. Step 3, 7,,, Step 6., Step 4,. Step 5,,.

No2 4 y =sinx (5) y = p sin(2x +3) (6) y = 1 tan(3x 2) (7) y =cos 2 (4x +5) (8) y = cos x 1+sinx 5 (1) y =sinx cos x 6 f(x) = sin(sin x) f 0 (π) (2) y

I ( ) 1 de Broglie 1 (de Broglie) p λ k h Planck ( Js) p = h λ = k (1) h 2π : Dirac k B Boltzmann ( J/K) T U = 3 2 k BT

untitled

No δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i x j δx j (5) δs 2

( ) ,

85 4

.A.N.Z.X36..PDF

ω 0 m(ẍ + γẋ + ω0x) 2 = ee (2.118) e iωt x = e 1 m ω0 2 E(ω). (2.119) ω2 iωγ Z N P(ω) = χ(ω)e = exzn (2.120) ϵ = ϵ 0 (1 + χ) ϵ(ω) ϵ 0 = 1 +

熊本県数学問題正解

I

Microsoft Word - 触ってみよう、Maximaに2.doc


4.6: 3 sin 5 sin θ θ t θ 2t θ 4t : sin ωt ω sin θ θ ωt sin ωt 1 ω ω [rad/sec] 1 [sec] ω[rad] [rad/sec] 5.3 ω [rad/sec] 5.7: 2t 4t sin 2t sin 4t

高等学校学習指導要領

高等学校学習指導要領

x A Aω ẋ ẋ 2 + ω 2 x 2 = ω 2 A 2. (ẋ, ωx) ζ ẋ + iωx ζ ζ dζ = ẍ + iωẋ = ẍ + iω(ζ iωx) dt dζ dt iωζ = ẍ + ω2 x (2.1) ζ ζ = Aωe iωt = Aω cos ωt + iaω sin

9 5 ( α+ ) = (α + ) α (log ) = α d = α C d = log + C C 5. () d = 4 d = C = C = 3 + C 3 () d = d = C = C = 3 + C 3 =

A A = a 41 a 42 a 43 a 44 A (7) 1 (3) A = M 12 = = a 41 (8) a 41 a 43 a 44 (3) n n A, B a i AB = A B ii aa

f(x) = x (1) f (1) (2) f (2) f(x) x = a y y = f(x) f (a) y = f(x) A(a, f(a)) f(a + h) f(x) = A f(a) A x (3, 3) O a a + h x 1 f(x) x = a

振動工学に基礎

all.dvi

1 (1) ( i ) 60 (ii) 75 (iii) 315 (2) π ( i ) (ii) π (iii) 7 12 π ( (3) r, AOB = θ 0 < θ < π ) OAB A 2 OB P ( AB ) < ( AP ) (4) 0 < θ < π 2 sin θ


D xy D (x, y) z = f(x, y) f D (2 ) (x, y, z) f R z = 1 x 2 y 2 {(x, y); x 2 +y 2 1} x 2 +y 2 +z 2 = 1 1 z (x, y) R 2 z = x 2 y

, 3, 6 = 3, 3,,,, 3,, 9, 3, 9, 3, 3, 4, 43, 4, 3, 9, 6, 6,, 0 p, p, p 3,..., p n N = p p p 3 p n + N p n N p p p, p 3,..., p n p, p,..., p n N, 3,,,,

Gmech08.dvi

x = a 1 f (a r, a + r) f(a) r a f f(a) 2 2. (a, b) 2 f (a, b) r f(a, b) r (a, b) f f(a, b)

3. ( 1 ) Linear Congruential Generator:LCG 6) (Mersenne Twister:MT ), L 1 ( 2 ) 4 4 G (i,j) < G > < G 2 > < G > 2 g (ij) i= L j= N

数学の基礎訓練I

Gmech08.dvi

#A A A F, F d F P + F P = d P F, F y P F F x A.1 ( α, 0), (α, 0) α > 0) (x, y) (x + α) 2 + y 2, (x α) 2 + y 2 d (x + α)2 + y 2 + (x α) 2 + y 2 =

1 1 n 0, 1, 2,, n n 2 a, b a n b n a, b n a b (mod n) 1 1. n = (mod 10) 2. n = (mod 9) n II Z n := {0, 1, 2,, n 1} 1.

untitled

keisoku01.dvi

c y /2 ddy = = 2π sin θ /2 dθd /2 [ ] 2π cos θ d = log 2 + a 2 d = log 2 + a 2 = log 2 + a a 2 d d + 2 = l

30 (11/04 )

K 1 mk(

6 2 2 x y x y t P P = P t P = I P P P ( ) ( ) ,, ( ) ( ) cos θ sin θ cos θ sin θ, sin θ cos θ sin θ cos θ y x θ x θ P

n Y 1 (x),..., Y n (x) 1 W (Y 1 (x),..., Y n (x)) 0 W (Y 1 (x),..., Y n (x)) = Y 1 (x)... Y n (x) Y 1(x)... Y n(x) (x)... Y n (n 1) (x) Y (n 1)

18 ( ) ( ) [ ] [ ) II III A B (120 ) 1, 2, 3, 5, 6 II III A B (120 ) ( ) 1, 2, 3, 7, 8 II III A B (120 ) ( [ ]) 1, 2, 3, 5, 7 II III A B (

.5 z = a + b + c n.6 = a sin t y = b cos t dy d a e e b e + e c e e e + e 3 s36 3 a + y = a, b > b 3 s363.7 y = + 3 y = + 3 s364.8 cos a 3 s365.9 y =,

all.dvi

chap03.dvi


The Physics of Atmospheres CAPTER :

17 ( ) II III A B C(100 ) 1, 2, 6, 7 II A B (100 ) 2, 5, 6 II A B (80 ) 8 10 I II III A B C(80 ) 1 a 1 = 1 2 a n+1 = a n + 2n + 1 (n = 1,

ẍ = kx, (k > ) (.) x x(t) = A cos(ωt + α) (.). d/ = D. d dt x + k ( x = D + k ) ( ) ( ) k k x = D + i D i x =... ( ) k D + i x = or ( ) k D i x =.. k.

Chap10.dvi


1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2

i

() n C + n C + n C + + n C n n (3) n C + n C + n C 4 + n C + n C 3 + n C 5 + (5) (6 ) n C + nc + 3 nc n nc n (7 ) n C + nc + 3 nc n nc n (

arctan 1 arctan arctan arctan π = = ( ) π = 4 = π = π = π = =

i

2000年度『数学展望 I』講義録

main.dvi

高校生の就職への数学II

2011de.dvi

Transcription:

69

V A V + A V A 2A 2 http://www.jba-hp.jp/ http://www.kbn3.com/ http://www.usba.org/ 70

(1) (1996)35 7 pp.28-33 (2) (1994) 71

() 3 1 1 99 8 1 10 1 11.3 2.5 1 100 11.4 30.9 1 72

(1) http://www.stat.go.jp/data/zensho/1999/zuhyou/a906-6.xls http://tohoku.naro.affrc.go.jp/reigai/map/akita/aktycv.html (2) 73

meta- + PRD RT RT DJ boy tall girl dog cat book VT sees reads VI runs ADJ black difficult small ADV quickly skillfully ART a the PRD The boy sees a black dog. The cat runs quickly. A boy reads the difficult book skillfully. 74

2005Vol.75, No.1 (2005-4) pp.1-30 75

70 70 70 20 70 0.72 7010 10 70 10r0.1 a B = A( 1+ r) a a BA A 2 = (1 + r) a x 100r 2 (1 + x r = r) 100 1 x r 100 2 = {(1 + r) } a 1 r ( 1+ r) r e 2.71828 100 2 = e x 100 1000 7035 35 35 2000 76 x

2003pp.150154 2003pp.3035 2002pp.9091 77

( x, y) ( 0, c) A m/ θ x y t ( x, y) x = At cosθ, 1 2 1 g 2 sinθ 2 y = gt + At sinθ + c y = x + x + c = ax + bx + c t 2 2 2 ( Acosθ ) cosθ x y 2 ax + bx + c ( R, S) 2 R S = -ax + bx + c 1 ( b ± b 4 ( ) ) 2 + a c S 2a R 1 ( b b 4 ( ) ) 2 + a c S A 2 cos g 2 θ sinθ cosθ 2a sin θ 2g( c S) + A = 2 2 cos θ A cos θ + cosθ sinθ + g 2 2 2 + sin 2 2 2g( c S) θ + A R A θ c S 2 2 A cosθ 2sinθ A sin 2θ R = R A g g 18m, 30m, 50m, 60m, 70m, 90m () 78

1 2 2 b 2 b ax + bx + c = a( x ) + c + 2a 4a 2 2 2 b A sin θ tanθ c + = c + c+ R 4a 2g 4 A 50m / A θ 79

80

81

82

83

3 3 = 9 3 2 3 = 3 3 = 2 3 = 6 3, 2, 6, 4, 5, 1 p r r p 1 1mod p 5 S.K. K.W. a = 7 M = 2 31 1 5 X i = 7 X i 1 mod (2 31 1) 2 31 2 mod (2 31 1) IBM RANDU 1970 X i = 65539X i 1 mod 2 31 () 84

3 1 = 3 3 2 = 9 2mod7 3 3 = 2 3 = 6 3 4 = 6 3 = 18 4mod7 3 5 = 4 3 = 12 5mod7 3 6 = 5 3 = 15 1mod7 3, 2, 6, 4, 5, 1 5 S.K. K.W. a = 7 M = 2 31 1 5 X i = 7 X i 1 mod (2 31 1) IBM RANDU 1970 X i = 65539X i 1 mod 2 31 (1) S. K. Park and K. W. Miller, 1988, Random number generators: Good ones are hard to find, Communication of the ACM, Vol.31, pp.1192-1201 85

2 2 C 2 3 2 86

D 87

250150 150100 100012 1000 150x + 100y 1000 5 1 12 1 1 1 x + y 1 5 12 s y = 2x + 50 88

y 1 1 x + y = 1 5 12 150 x + 100y = 1000 x 89

30 7000 6000 7000+6000300000 7x+6300 30,15 k=30+15=45 90

91

() 92

93

1 2 1 2 2 1 2 x 5700 1 y = 2 94

14 14 5700 14 11400 95

96

JPEG cos 97

asin( ωt) asin( ωt) a ω φ t asin( ω t + φ) a' sin( ω t + φ' ) a' φ' asin( ωt + φ) a'sin( ωt + φ') = asin( ωt + φ) asin( ωt + φ') + ( a a')sin( ωt + φ') φ + φ' φ φ' = a cos( ωt + )sin( ) + ( a a')sin( ωt + φ') 2 2 φ = φ' a = a' φ = φ' a = a' 98

99

440Hz () 100

y = sin x y = 0.8x y = sin x+ sin 0.8x 1998 pp60-62 101

B L 2 3 80 L (1+ 2 + 2 + 2 + L+ 2 ) x 81 2 3 80 1 2 81 x = 1+ 2+ 2 + 2 + L+ 2 = = 2 1 1 2 81 log( x + 1) = log 2 = 81 log 2 = 81 0.3010 = 24.381 24 25 10 < x + 1< 10 12 10 10 24 102

103

3 5 f(x) 3 5 f(x) 3 5f(x) 3 5 yf(x) a a 0 f ( an ) 2an 5 a a n = + f ( a ) 3 3a n 2 n a 1 2 4 5 21 7 a2 = + = = = 1.75, a 3 12 12 4 a 4 = 2 3 503 5 2 294 503 3 2 294 2 3 = 1.709976428 3 = 7 5 4 7 3 4 2 2 = 503 294 = 1.710884 4 3 5 = 1. 709975947 a 5 a 6 104

105

106

107

108

109

14 N 12 C 14 N 12 C 14 C 12 CO2 14 CO2 CO 2 12 CO2 14 CO 14 C 14 C 2 12 C 14 C t y() t t t+ dt y() t kk ( > 0) y( t+ dt) y( t) = ky( t) dt dt dt 0 y () t = ky() t y = Ce kt t = 0 A y = Ae kt kt 1 t 0 e 0 = 1 2 4 2t o 14 C 1 4 110

1998 pp110-111 111

d dt N( t) α λ t 2 L = N( t) N( ) N t) = 1+ αt me ( 112

L N( t) = 1+ αt me L S t L N(t) L 1972 1985 1972 1977 1982 3 127,085,000 20 dn dt = b( 1 an( t)) N( t) dn dn adn ( 1 an ) N = bdt N + 1 an = bdt log N log(1 an) = bt C C bt log( 1 an ) / N = bt + C 1/ N a = e C bt bt N = 1/( a + e ) = L /(1 + me ) L = 1/ a, m 1 e a C = 113

2 2 = 4 (1)(3) = AB + AB AB A B A A B B Exclusive ORXOR () 114

(1) (2) (3) (4) (1) 0 1 1 0 (2) (4) (3) 0 0 1 1 1 0 1 0 A B A B (1) (2) A B A B (3) (4) (1)(1986)pp.127-144 115

13 2 495 5 1 a + b + c + d = 7 1 a, b, c, d 4 6! = (6 3)!3! 4 H 3 = 4 + 3 1C3 = 6C3 = 20 116

(2)(1985)JIS X 0501 117

1960 180 45 30 () 118

1 (1) 1993pp.161167 119

50% 6 1mm 100 188 138 50 51% 52% 30 29% 100 30 20%60% 120

(1) (2) (1) http://www.jma.go.jp/jma_hp/jma/index.html (2) http://www.tbs.co.jp/morita/ 121

/ 122

2005Vol.75, No.1 (2005-4) pp.1-30 123

124

A A A A A A A A 2005Vol.75, No.1 (2005-4) pp.1-30 125

126

127

128 Internet Explorer

HTML This is our Home Page! / / Here we can write any massage or information contents. / /HTML 2005Vol.75, No.1 (2005-4) pp.1-30 129

syntactic role 130

2005Vol.75, No.1 (2005-4) pp.1-30 131

HP Home Page D1,D2,D3,,Dn D1,D2,D3,,Dn K1,K2K13K 1,K2K3Kn1,Kn2Kn3 Di F F Di F Ki1,Ki2,Ki3, F Di Ki1,Ki2,Ki3, F Di Ki1,Ki2,Ki3, F F -1 K Di K F -1 Di, Dj, Dk, F -1 F -1 F F inverted file 132

D1 K1 K2 K D2 K1 K2 K D3 K1 K2 K3 Dn Kn1 Kn2 Kn K1 D1 D2 D K2 D1 D2 D K3 D1 D2 D3 Kn Dn1 Dn2 Dn F -1 HP1 HP6 HP1 HP1 HP HP6 HP2 HP HP HP HP HP HP HP HP5 HP1 HP HP HP HP HP 2005Vol.75, No.1 (2005-4) pp.1-30 133

134

135

raw data 111100555550003333333000022200000 run-length 136

or or or or or 0 or 0 or 0 or 0 or 0 or 0 or 0 or 0 or 2005Vol.75, No.1 (2005-4) pp.1-30 137

138

139

1 1 1 1 1 1 140

-1-1 1234 1 1-1 2 2-1 3 3-1 4 4-1 1 2 3 4 i i i i -1 i -1 i 2005Vol.75, No.1 (2005-4) pp.1-30 141

r= (%) =T ), S X S X ( 1+ r) S m m k X = (( ( T (1 + r) S)(1 + r) S)(1 + r) S) = T (1 + r) S(1 + r) m 1 k = 0 m k 1 (1 + r) S m m S m S(1 + r) = S = {(1 + r) 1} X = T ( 1+ r) {(1 + r) 1} 1 (1 + r) r r 1. S S = 2. m m= m 1 k = 0 X S X ( 1+ r) S Excel y, (1+r) S (1+r) S S () 142

(T) (T)(T)() (T)()(S) T(1+r)S T(1+r)SS T(1+r) 2 S(1+r)S m (T(1+r)S)(S) T(1+r) S() S *** T=, r=, S= Excel *** Excel A1 T B1 C1 S A2 A2 A3 A2 Excel A2 1 S A3 Excel A B C D =A1+B$1) C$1 =A2+B$1) C$1 =A+B$1) C$1 =A+B$1) C$1 =A+B$1) C$1 =A+B$1) C$1 18000000 15900000 13695000 11379750 8948738 6396174 143

38 12 12 12 38 1 144

2005Vol.75, No.1 (2005-4) pp.1-30 145