7. 1 max max min f g h h(x) = max{f(x), g(x)} f g h l(x) l(x) = min{f(x), g(x)} f g 1 f g h(x) = max{f(x), g(x)} l(x) = min{f(x), g(x)} h(x) = 1 (f(x)

Similar documents
untitled

0 = m 2p 1 p = 1/2 p y = 1 m = 1 2 d ( + 1)2 d ( + 1) 2 = d d ( + 1)2 = = 2( + 1) 2 g() 2 f() f() = [g()] 2 = g()g() f f () = [g()g()]

生産者行動の理論(1)



CAT. No. 1102k 2011 E-3 B206-B243

レイアウト 1

P1.\..

10_11p01(Ł\”ƒ)

P1.\..

Q34Q35 2

スライド タイトルなし

パソコン接続マニュアル P-01F 日本語

第2章

10 4 2

産業組織論(企業経済論)

10月表紙BB.indd

ミクロ経済学Ⅰ




9 5 ( α+ ) = (α + ) α (log ) = α d = α C d = log + C C 5. () d = 4 d = C = C = 3 + C 3 () d = d = C = C = 3 + C 3 =

VISPO /表1-4

橡Taro9-生徒の活動.PDF

‡ç‡¢‡Ó‡Ü‡Á‡Õ04-08„”

AC-2

エンジョイ北スポーツ

TC316_A5_2面_web用PDF台紙.indd

untitled

PDF


p q p q p q p q p q p q p q p q p q x y p q t u r s p q p p q p q p q p p p q q p p p q P Q [] p, q P Q [] P Q P Q [ p q] P Q Q P [ q p] p q imply / m


F-09C

(1) 1 y = 2 = = b (2) 2 y = 2 = 2 = 2 + h B h h h< h 2 h

B 1 レヴィットミクロ経済学 ( 基礎編 ) 演習問題 ( 抜粋 ) の解答 第 2 章 2. a P C 5 I 10 Q D O 75 5P O P O 5P O 100 Q O D P O Q D O 価格 ( ドル ) 20 0 D 100 有機ニンジ

1

中期経営計画 「NEXTAGE‐05」説明会



31 gh gw

さくらの個別指導 ( さくら教育研究所 ) A a 1 a 2 a 3 a n {a n } a 1 a n n n 1 n n 0 a n = 1 n 1 n n O n {a n } n a n α {a n } α {a

2


untitled


Chap9.dvi

シンデレラ合宿


製品案内 価格表 2014/4/1


3.ごみの減量方法.PDF

<4D F736F F F696E74202D20837E834E838D2D91E6428FCD EF97708DC58FAC89BB96E291E E707074>

1 (utility) 1.1 x u(x) x i x j u(x i ) u(x j ) u (x) 0, u (x) 0 u (x) x u(x) (Marginal Utility) 1.2 Cobb-Daglas 2 x 1, x 2 u(x 1, x 2 ) max x 1,x 2 u(


学習の手順

Riemann-Stieltjes Poland S. Lojasiewicz [1] An introduction to the theory of real functions, John Wiley & Sons, Ltd., Chichester, 1988.,,,,. Riemann-S

0 (18) /12/13 (19) n Z (n Z ) 5 30 (5 30 ) (mod 5) (20) ( ) (12, 8) = 4

概況

untitled

untitled

untitled


5. F(, 0) = = 4 = 4 O = 4 =. ( = = 4 ) = 4 ( 4 ), 0 = 4 4 O 4 = 4. () = 8 () = 4

2009 IA I 22, 23, 24, 25, 26, a h f(x) x x a h

応用数学特論.dvi

6 2 2 x y x y t P P = P t P = I P P P ( ) ( ) ,, ( ) ( ) cos θ sin θ cos θ sin θ, sin θ cos θ sin θ cos θ y x θ x θ P

F8302D_1目次_ doc

経済情報処理のための Mathematica 課題 改訂新里 課題 1 微分次の関数を微分せよ 1 f(x)=x 3-2x+x/(x+1) 2 f(x)=(x+1)(x 2 +1)-1/(x 3 +1) 3 f(x)=(2x+3)(x 3-2)+(2x+3)/(x 2 +1) 課題

uPC2745TB,uPC2746TB DS

( ) ( ) 1729 (, 2016:17) = = (1) 1 1

1



untitled

66 σ σ (8.1) σ = 0 0 σd = 0 (8.2) (8.2) (8.1) E ρ d = 0... d = 0 (8.3) d 1 NN K K 8.1 d σd σd M = σd = E 2 d (8.4) ρ 2 d = I M = EI ρ 1 ρ = M EI ρ EI

Chapter9 9 LDPC sum-product LDPC 9.1 ( ) 9.2 c 1, c 2, {0, 1, } SUM, PROD : {0, 1, } {0, 1, } SUM(c 1, c 2,, c n ) := { c1 + + c n (c n0 (1 n

Products catalog

( )

[ ] Table

FinePix A900 / FinePix A820 / FinePix A610 / FinePix A800 使用説明書

Microsoft PowerPoint - 第8章.ppt [互換モード]

H01.eps

sekibun.dvi

110

FnePix S8000fd 使用説明書

corega UPS 250 取扱説明書


1990 IMO 1990/1/15 1:00-4:00 1 N N N 1, N 1 N 2, N 2 N 3 N 3 2 x x + 52 = 3 x x , A, B, C 3,, A B, C 2,,,, 7, A, B, C

2 log 3 9 log 0 0 a log log 3 9 y 3 y = = 9 y = 2 0 y = 0 a log 0 0 a = a 9 2 = 3 log 9 3 = 2 a 0 = a = a log a a = log a = 0 log a a =. l

a, b a bc c b a a b a a a a p > p p p 2, 3, 5, 7,, 3, 7, 9, 23, 29, 3, a > p a p [ ] a bp, b p p cq, c, q, < q < p a bp bcq q a <

) km 200 m ) ) ) ) ) ) ) kg kg ) 017 x y x 2 y 5x 5 y )

FinePix Z3 使用説明書

取扱説明書[L-03B](詳細版)

名古屋工業大の数学 2000 年 ~2015 年 大学入試数学動画解説サイト


untitled

= = = = = = 1, 000, 000, 000, = = 2 2 = = = = a,

FinePix S5700使用説明書

f (x) x y f(x+dx) f(x) Df 関数 接線 x Dx x 1 x x y f f x (1) x x 0 f (x + x) f (x) f (2) f (x + x) f (x) + f = f (x) + f x (3) x f

Transcription:

7. 1 ma ma min f g h h() = ma{f(), g()} f g h l() l() = min{f(), g()} f g 1 f g h() = ma{f(), g()} l() = min{f(), g()} h() = 1 (f() + g() + f() g() ) 2 1

1 l() = 1 (f() + g() f() g() ) 2 2 1 45 = 2 e 1 log 1: 2

3 1 = = ( ) 2: = = = = 0 { if 0 = if < 0 2 = 2, 0 = 0, 2 = 2 3

= 2 0 3: 1 2 1 0.5 2 = 2 0 4: f 1 1 1 1 1 4

= 0 5: 4 = 6 0 = 0 0 6: 1 2 3 5

= 3 0 7: 3 = 0 5 2 2 z = f(, ) z = 2 + 2 z = 0 0 = 2 + 2 (0, 0) z = 1 1 = 2 + 2 1 z = 2 2 = 2 + 2 2 z (, ) ( ) 3 1 2 (,, z) = ( 1 1 2, 2, 1) 1 6

z 2 1 1 1 ( 1 2, 1 2 ) 8: 3 1 2 6 ( ) a b f b a f()d sum s a b f() 2 7

z 1 ( 1 2, 1 2 ) 9: s 2 1 5 5 i=1 i 2 i a 1 b 5 f() i 2 1 i 7 1. ( n ) = n n 1 2. (kf) = kf (k ) 3. (f + g) () = f () + g () 8

z 1 ( 1 2, 1 2 ) 10: = 2 = 2 13 2 2 ( ) 2 ( n ) = n n 1 n 9

f a b 11: f() = 2 5 i=1 i2 4 1 5 2 12: 2 ( ) 2 13: 10

8 1 f : X Y X 8.1 2 ( 1, 1 ) ( 2, 2 ) l l ( 1, 1 ) ( 2, 2 ) 0 14: = = l l = 2 1 2 1 = 2 1 2 1 ( 1 ) + 1 2 3 11

(1) m = m( 1 ) + 1 ( 1, 1 ) (2) m = m + b b (3) ( 1, 1 ) = 2 1 ( 1 ) + 1 2 1 ( 2, 2 ) 8.2 f 0 f f 0 f f( 0 ) 0 15: f 0 f ( 0 ) 0 f ( 0 ) 0 f( 0 ) ( 0, f( 0 )) (1) f 0 = f ( 0 )( 0 ) + f( 0 ) f 0 = f ( 0 )( 0 ) + f( 0 ) 12

1 = 1 2 0 = 0 1 = 1 2 = 1 3 1 = 1 = 2 + 2 = 2 + 2 16 = 2 + 2 = 2 + 2 = 1 = 1 2 0 16: = 1 2 2 = 0 = 4 8.3 0 = 0 + f( 0 ) f() f ( 0 ) f( 0 ) 13

f() f( 0 ) + f ( 0 ) f ( 0 ) f( 0 ) 0 17: f ( 0 ) 0 f() f( 0 ) + f ( 0 ) 2 (1.03) 2 2 2 f() = 2 0 = 1 = 0.03 f () = 2 f() f( 0 ) + f ( 0 ) = 2 0 + 2 0 = 1 2 + 2 1 0.03 = 1.06 (1.03) 2 = 1.0609 14

3 2.01 2 13 (2.01) 2 0 f( 0 ) + f ( 0 )( 0 ) f() = 0 f() f( 0 ) + f ( 0 ) f ( 0 ) = f() f( 0 ) 0 9 f 0 0 (a, b) a < < 0 = f() f( 0 ), 0 < < b = f( 0 ) f() 16 2 f 0 f ( 0 ) > 0 = f 0 f ( 0 ) < 0 = f 0 0 18 15

= 3 = 3 = 2 f (0) = 0 f f (0) = 0 f f (0) = 0 f 18: f (0) = 0 = 0 f = 0 f = 0 f = 0 f 0 2 18 0 0 3 f I f () > 0 ( I) = f I f () < 0 ( I) = f I f () = 0 ( I) = f I 10 19 = 0 1 (local maimum) = 0 f 0 16

19: (a, b) f( 0 ) f() ( (a, b)) = 0 f 0 (a, b) f( 0 ) f() ( (a, b)) = 0 > < f 0 f 4 f 0 f ( 0 ) = 0 f ( 0 ) = 0 18 2 17

4 (1) = 3 3 (2) = 3 + 12 2 11 ( ) C V C 64 0 F C Q 20: (total cost) TC or C Q Q C(Q) (marginal cost) MC 1 (fied cost) FC (variable cost) VC (AC) (AVC) 20 18

3 Q C(Q) C(Q) = Q 2 + 10Q + 9 3 MC = C (Q) = (Q 2 + 10Q + 9) = 2Q + 10 F C = 9 V C = Q 2 + 10Q AC = C(Q) Q = Q + 10 + 9 Q AV C = V C Q = Q + 10 MC = dc dq = 2Q + 10 21 ( ) MC AC AV C 0 Q 21: 5 MC(3) = AC(3) 19

4 Q C(Q) C(Q) = Q 3 4Q 2 + 7Q + 64 4 MC = C (Q) = 3Q 2 8Q + 7 F C = 64 V C = Q 3 4Q 2 + 7Q AC = C(Q) Q = Q2 4Q + 7 + 64 Q AV C = V C Q = Q2 4Q + 7 20 6 π(q) = pq C(Q) (1) p Q π(q) 16 0 (1) 0 dπ(q) dq = (pq C(Q)) = p(q) C (Q) = p 1 MC(Q) = p MC(Q) dπ(q) dq = 0 p MC(Q) = 0 p = MC(Q) 20

1 = 5 p C(q) = q 2 /2 5 ( ) q 2 = 1 2 2 2q = q p q = p 7 Q C(Q) C(Q) = Q 2 + 10Q + 9 12 f,g f/g (f/g)() = f() g() g() 0 h h() = f() g() (2) 21

h (2) f() = g()h() f () = g ()h() + g()h () h () h () = f () g ()h() g() h() (2) ( ) f () g () f() h g() () = g() = f ()g() g ()f() [g()] 2 ( ) f () = f ()g() g ()f() g (g()) 2 g() 0 g = 1 g = 0 f 1 f ( ) f = f g g f g g 2 8 2 3 + 5 2 + 1 9 2 2 22

10 ( ) 11 a + b 13 21 dac dq = d dq ( ) C(Q) = C (Q) Q C(Q) (Q) Q = C (Q)Q C(Q) Q 2 Q 2 C (Q)Q C(Q) = 0 C (Q) = C(Q) Q MC(Q) = AC(Q) 14 f() = 1 g() ( ) 1 () = 1 g g() g() ( ) 1 () = g () g (g()) 2 23

( ) 1 = g g g 2 g() 0 6 1/ 6 (1/) = () 2 = 1/ 2 1/ = 1 1/ 2 = 2 12 1 3 + 3 2 13 15 2 1 0 1 2 2 = 1 2 1 = 1 0 = 1 2 n = 1 n (2 3 ) 2 = 2 3 2 3 = (2 2 2 ) (2 2 2 ) = 2 6 (2 3 ) 2 = 2 3 2 = 2 6 2 ( a ) b = a b 24

d d n = d ( ) 1 d n = n n 1 d d n nn 1 = ( n ) = = n n 1 (2n) = n n 1 2n 2 2n n k d d k = k k 1 n ( n ) = n n 1 (n Z) 14 1 6 15 ( : f()/g() f() 1/g() ) 16 1. 2. 3. 4. 5. 6. 25

n f() = n f () = n n 1 17 (1) 1/ (2) 1 2 (3) 2 16 (production function) 8 155Kg 155 2 = 0 8 9 22: 1 (marginal product of labor) MPL (marginal product) 1 26

7 L Y Y = F (L) = L (L R + ) 7 MP L = F (L) = d L dl = 1 2 L1/2 1 = L 1 2 2 = 1 2 L (diminishing returns) 8 9 10 5 170 165 155 = 5 = 10 0 8 9 10 23: L Y = F (L) = L p w π(l) = pf (L) wl (3) 27

L (3) L dπ(l) dl = (pf (L)) (wl) = p(f (L)) w(l) = pf (L) w (3) 0 pf (L) w = 0 F (L) = w p 1 1000 100 1000/100 = 10 1 10 2 = 24 F (L) Y Y = w p L + π p Y = L Y E Y = w p L + π p L L 24: 28

π L Y π = py wl Y Y = w p L + π p (4) w/p L (4) ulπ E 29