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19 7 ( ) 2019.4.20 1 1.1 (data structure ( (dynamic data structure 1 malloc C free C (garbage collection GC C GC(conservative GC 2 1.2 data next p 3 5 7 9 p 3 5 7 9 p 3 5 7 9 1 1: (single linked list 1 (node (cell (C 1 (static data structure 2 conservative GC 1

( NULL( stdlib.h 0 2 ( )3 1.0 ( NULL node new plist p p = p->next; p p NULL // slistdemo1.c --- single-linked list demonstration #include <stdio.h> #include <stdlib.h> struct node { double data; struct node *next; ; typedef struct node *nodep; nodep node_new(double d, nodep n) { nodep p = (nodep)malloc(sizeof(struct node)); p->data = d; p->next = n; return p; void plist(nodep p) { while(p!= NULL) { printf(" %g", p->data); p = p->next; printf("\n"); nodep mklist(int n, char *a[]) { nodep p = NULL; for(int i = n-1; i >= 0; --i) { p = node_new(atof(a[i]), p); return p; int main(int argc, char *argv[]) { nodep p = mklist(argc-1, argv+1); plist(p); p->next->next = p->next->next->next; plist(p); p->next->next = node_new(1.0, p->next->next); plist(p); return 0; ( mklist p NULL p = node new(, p); main argv 1 ( argc-1 2 ( )2 ( )3 plist %./a.out 3 5 7 9 2

3 5 7 9 3 5 9 3 5 1 9 mklist plist void plist(nodep p) { if(p == NULL) { printf("\n"); return; printf(" %g", p->data); plist(p->next); nodep mklist(int n, char *a[]) { if(n == 0) { return NULL; return node_new(atof(*a), mklist(n-1, a+1)); plist NULL mklist 0 NULL 1 a. ( 1 b. ( 2 c. 2 3 ( d. 2 ( 1 2 3 1 1 2 2 3 3 e. 1.3 : ( 1 e (enter ( a (append add (add d (delete p (print q (quit %./a.out > e 1 2 3 > a 4 5 6 > p 3

1 2 3 4 5 6 > add 1 1 1 1 4 1 > p 2 3 4 5 5 6 > d 2 2 ( 0 ) > p 2 3 5 5 6 > q % plist (include // listeditor.c --- single-linked list editor #include <stdio.h> #include <stdlib.h> #include <string.h> #include <stdbool.h> struct node { double data; struct node *next; ; typedef struct node *nodep; nodep node_new(double d, nodep n) { nodep p = (nodep)malloc(sizeof(struct node)); p->data = d; p->next = n; return p; nodep mklist(int n, char *a[]) { if(n == 0) { return NULL; return node_new(atof(*a), mklist(n-1, a+1)); void plist(nodep p) { if(p == NULL) { printf("\n"); return; printf(" %g", p->data); plist(p->next); nconc p q p next q void nconc(nodep p, nodep q) { while(p!= NULL && p->next!= NULL) { p = p->next; if(p!= NULL) { p->next = q; 1 void delnode(nodep p, int n) { while(--n > 0 && p!= NULL) { p = p->next; if(p!= NULL && p->next!= NULL) { p->next = p->next->next; 4

2 NULL null 2 nodep addlist(nodep x, nodep y) { if(x == NULL) { return y; if(y == NULL) { return x; return node_new(x->data+y->data, addlist(x->next, y->next)); getl 1 getchar 1 1 ( ++ 0 false true bool getl(char s[], int lim) { int c, i = 0; for(c = getchar(); c!= EOF && c!= \n ; c = getchar()) { s[i++] = c; if(i+1 >= lim) { break; s[i] = \0 ; return c!= EOF; parse 1 ( 1 1 int parse(char *a[], char *s) { int i, k = 0, len = strlen(s); for(i = 0; i < len; ++i) { if(s[i] == ) { s[i] = \0 ; if(s[i]!= \0 && (i == 0 s[i-1] == \0 )) { a[k++] = s+i; return k; main 1 1 q e mklist a list nconc add addlist list d dellist p plist int main(int argc, char *argv[]) { 5

char buf[200], *cmd[20]; nodep list = NULL; while(true) { printf("> "); if(!getl(buf, 200)) { break; int k = parse(cmd, buf); if(k > 0 && strcmp(cmd[0], "q") == 0) { break; else if(k > 0 && strcmp(cmd[0], "e") == 0) { // enter list list = mklist(k-1, cmd+1); else if(k > 0 && strcmp(cmd[0], "a") == 0) { // append list nconc(list, mklist(k-1, cmd+1)); else if(k > 1 && strcmp(cmd[0], "add") == 0) { // add list list = addlist(list, mklist(k-1, cmd+1)); else if(k > 1 && strcmp(cmd[0], "d") == 0) { // delete item delnode(list, atoi(cmd[1])); else { plist(list); return 0; 2 ( a. b. c. ( d. ( e. (1 f. 3 p p head p p head 2: ( 3 1 (head 3 ( 2 / / 6

2 2.1 1 ( 1 2.2 3 top push next top (top NULL pop top next push(1) push(2) top top top pop 1 2 1 1 pop 2 3: istack.h 3 // istack.h --- int type stack interface #include <stdbool.h> struct istack; typedef struct istack *istackp; istackp istack_new(int size); // allocate new stack bool istack_isempty(istackp p); // test if the stack is empty void istack_push(istackp p, int v); // push a value int istack_pop(istackp p); // pop a value and return it int istack_top(istackp p); // peek the topmost value 1 size(? 7

size size size 4 size 2.3 top last 2 ( (head 4 ( top last last next last top next next top last enq(1) top last enq(2) top last enq(3) 1 1 2 top last top last 1 2 3 2 3 deq 1 4: ( ) iqueue.h isfull // iqueue.h --- int type queue interface #include <stdbool.h> struct iqueue; typedef struct iqueue *iqueuep; iqueuep iqueue_new(int size); bool iqueue_isempty(iqueuep p); bool iqueue_isfull(iqueuep p); void iqueue_enq(iqueuep p, int v); int iqueue_deq(iqueuep p); 5 ( size isfull (#3 6 ( size isfull (#4 8

7 ( last ( last 1 size isfull last enq 1 enq 2 enq 3 deq 1 1 1 2 1 2 3 enq 4 deq 2 deq 3 deq 4 2 3 2 3 4 3 4 4 7A 1 6 1 ( 23:59 1. sol CED /home3/staff/ka002689/prog19upload 7a 2. ( @@@ 3. 1 4. ( ( 5. Q1. Q2. Q3. ( 7B 1 6 ( 7A ( 2 23:69 1. sol CED /home3/staff/ka002689/prog19upload 7b 2. ( @@@ 3. 1 ( ( 4. 2 5. Q1. Q2. Q3. ( 9

3 : gdb? printf (debugger ( ( gdb gdb gcc gcc gcc -g % gcc8 -g % gdb8 a.out gcc...... (gdb) gdb gdb ( 1 bt 2 break (b) 3 b b b : ( run (r)./a.out 1 2 gdb r 1 2 r quit (q) gdb r gdb ( bus error backtreace (bt) list (l) print (p) p i p a[i] p q->data continue (c) next (n) 1 1 (p step (s) next 10

// factdemo.c --- two fact function for gdb exercise. #include <stdio.h> #include <stdlib.h> int fact1(int n) { int i, r = 1; for(i = 1; i <= n; ++i) { r *= i; return r; int fact2(int n) { if(n <= 0) { return 1; int r = fact2(n-1); return n * r; int main(int argc, char *argv[]) { int n = atoi(argv[1]); printf("fact1(%d) == %d\n", n, fact1(n)); printf("fact2(%d) == %d\n", n, fact2(n)); return 0; c ( % gcc8 -g factdemo.c % gdb a.out Copyright (C) 2018... Reading symbols from a.out...done. (gdb) break fact1 fact1 Breakpoint 1 at 0x40056d: file factdemo.c, line 5. (gdb) break fact2 fact2 Breakpoint 2 at 0x4005a3: file factdemo.c, line 12. (gdb) r 5 Starting program: /home3/staff/ka002689/a.out 5 Breakpoint 1, fact1 (n=5) at factdemo.c:5 5 int i, r = 1; 6 for(i = 1; i <= n; ++i) { 7 r *= i; 6 for(i = 1; i <= n; ++i) { 11

7 r *= i; 6 for(i = 1; i <= n; ++i) { 7 r *= i; (gdb) p r r $1 = 2 (gdb) p i i $2 = 3 (gdb) c fact1(5) == 120 Breakpoint 2, fact2 (n=5) at factdemo.c:12 12 if(n <= 0) { return 1; (gdb) c Breakpoint 2, fact2 (n=4) at factdemo.c:12 12 if(n <= 0) { return 1; (gdb) c Breakpoint 2, fact2 (n=3) at factdemo.c:12 12 if(n <= 0) { return 1; (gdb) c Breakpoint 2, fact2 (n=2) at factdemo.c:12 12 if(n <= 0) { return 1; (gdb) c Breakpoint 2, fact2 (n=1) at factdemo.c:12 12 if(n <= 0) { return 1; (gdb) c Breakpoint 2, fact2 (n=0) at factdemo.c:12 12 if(n <= 0) { return 1; (gdb) bt #0 fact2 (n=0) at factdemo.c:12 #1 0x00000000004005bd in fact2 (n=1) at factdemo.c:13 #2 0x00000000004005bd in fact2 (n=2) at factdemo.c:13 #3 0x00000000004005bd in fact2 (n=3) at factdemo.c:13 #4 0x00000000004005bd in fact2 (n=4) at factdemo.c:13 #5 0x00000000004005bd in fact2 (n=5) at factdemo.c:13 #6 0x0000000000400618 in main (argc=3, argv=0x7fffffffd7f8) at factdemo.c:19 15 14 return n * r; 12

(gdb) p r r $3 = 1 (gdb) p n n $4 = 1 15 14 return n * r; 15 14 return n * r; (gdb) p r r $5 = 2 (gdb) p n n $6 = 3 (gdb) c fact2(5) == 120 [Inferior 1 (process 44205) exited normally] (gdb) q 13