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- きょういち こいまる
- 5 years ago
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1 iphone C xkozima@myu.ac.jp
2 C Hello, World!
3 Hello World hello.c! printf( Hello, World!\n );! os> ls! hello.c! os> cc hello.c o hello! os> ls! hello!!hello.c! os>./hello! Hello, World!! os>! os> ls! hello.c! os> cc hello.c! os> ls! a.out!!hello.c! os>./a.out! Hello, World!! os>!
4 Hello World hello.c! printf( Hello, World!\n );! Xcode Create a new Xcode Project Mac OS X / Application Command Line Tool Run Console
5 Hello World hello.c! printf( Hello, World!\n );! Windows Visual C++ (Express Edition C++
6 Hello World hello.c! printf( Hello, World!\n );! C main Koz koz _ printf
7
8 int keisan.c! int x;! int y;! int wa, sa;! x = 17;! y = 6;! wa = x + y;! sa = x y;! printf( wa: %d\n, wa);! printf( sa: %d\n, sa);! = ; %d \n
9 int ans_i;! float ans_f;! ans_i = 17 / 6;! printf( ans_i: %d\n, ans_i);! ans_f = 17 / 6;! printf( ans_f: %f\n, ans_f);! ans_f = 17.0 / 6.0;! printf( ans_f: %f\n, ans_f);! ans_i = 17.0 / 6.0;! printf( ans_i: %d\n, ans_i);! ans_f = (float) 17 / 6;! printf( ans_f: %f\n, ans_f);! keisan.c! float double / ans_i: 2 / ans_f: / ans_f: ans_i: 2 (float) %f
10 // 32bit: ! int score;! int income, outgo;! score = 80;! income = 15000; outgo = 17800;! //! float height, weight;! double kousoku;! height = 1.70; weight = 62.0;! kousoku = ;! // m/s! kousoku = e9;! // ! //! char c1, c2;! //! /* */!! c1 = A ;!!! //! c2 = 65;!!! // ASCII!
11 if else for, while
12 if / if else branch1.c! int n = 12;! if (n > 10)! (n > 10) printf( n is greater than 10\n );! if (n == 0)! == printf( n is zero\n );! if (n < 10)! printf( n is less than 10\n );! if (n % 2 == 0)! n % 2 2 printf( n is even number\n );! else! printf( n is odd number\n );! return 0;!
13 if / if else branch2.c! float height_m = 1.70;! float weight_kg = 62.0;! float bmi = weight_kg / (height_m *height_m);! if (height_m > 2.5) printf( Use [m] for height.\n );! printf( Your BMI is %f\n, bmi);! if (bmi >= 25.0)! printf( WARNING!\n );! else! printf( SAFE\n );! return 0;! { }
14 if else if else if else float height_m = 1.70;! float weight_kg = 62.0;! float bmi = weight_kg / (height_m *height_m);! branch3.c! printf( Your BMI is %f\n, bmi);! if (bmi >= 30.0)! printf( You are obese!\n );! else if (bmi >= 25.0)! printf( You are overweight.\n );! else if (bmi >= 18.5)! printf( You are normal.\n );! else! printf( You are underweight.\n );! return 0;!
15 for int k, acc = 0;! int n = 10;! for (k = 1; k <= n; k = k + 1)! acc = acc + k;! printf( %d = %d\n, n, acc);! return 0;! = 55 loop1.c! k = k + 1 k++ acc = acc + k acc += k for ( ; ; ) ; for ( ; ; ) { ; ;} / { }
16 while loop2.c! int k, acc = 0;! int n = 10;! k = 1;! while (k <= n) acc += k;! k++;! = 55 printf( %d = %d\n, n, acc);! while ( ) ; / { } while ( ) { ; ;}
17 branch4.c! int n = 10;! while (n) n 0 printf( %d\n, n);! if (n > 0) n--;! else n++;! printf( BANG!\n );! return 0;! (n > 0) n > 0 1 n <= 0 0
18
19 int sum (int n)! int k, acc = 0;! kansu1.c! y = f(x) sum(n) n for (k = 1; k <= n; k++)! acc += k;! return acc;! acc int ans;! main 20 sum ans ans = sum(20);! printf( = %d\n, ans);! main 0 OS
20 int sum (int n);! int ans;! ans = sum(20);! printf( = %d\n, ans);! int sum (int n)! int k, acc = 0;! for (k = 1; k <= n; k++)! acc += k;! return acc;! kansu2.c! { } sum int ans;! int sum(int n);! ans = sum(20);! printf(...);! int sum(int);
21 void bmi_check (float bmi)! if (bmi >= 25.0)! printf( You are fat.\n );! else if (bmi >= 18.5)! printf( You are normal.\n );! else! printf( You are thin.\n );! return;! float height_m = 1.70;! float weight_kg = 62.0;! float bmi = weight_kg / (height_m *height_m);! printf( Your BMI is %f\n, bmi);! bmi_check(bmi);! kansu3.c! void return; (return; main int
22 int RandomValue = 14992;! int random (void)! int tmp = RandomValue * ;! RandomValue = (tmp % ) / 10;! return RandomValue;! int i;! for (i = 0; i < 10; i++) int ran;! ran = random();! printf( random() = %d\n, ran);! kansu4.c! ran {} random() = 9056! random() = 9563! random() = 43684! random() = 40027! random() = 93911! random() = 20304! random() = 66553! random() = 79111! random() = 24264! random() = 33061!
23 int x = 123;! int square (int x)! x = x * x;! return x;! printf( before: x = %d\n, x);! int x = 0;! while (x < 8) { } printf( while : x = %d\n, x);! if (x % 2 == 0) int x, y;! x = square(12); y = square(15);! printf( if : x = %d\n, x);! x++;! printf( after : x = %d\n, x);! (int x) kansu4.c! before: x = 123! while : x = 0! if : x = 144! while : x = 1! while : x = 2! if : x = 144! while : x = 3! while : x = 4! if : x = 144! while : x = 5! while : x = 6! if : x = 144! while : x = 7! after : x = 8
24
25 int a[8];! a array1.c! a[0] = 123; a[1] = 234; a[2] = 345; a[3] = 456;! a[4] = 567; a[5] = 678; a[6] = 789; a[7] = 890;! int i, acc = 0;! for (i = 0; i < 8; i++) printf( a[%d] = %d\n, i, a[i]);! acc += a[i];! printf( mean = %f, (float) acc / 8);! acc
26 float array_mean (int x[8])! int i, acc = 0;! for (i = 0; i < 8; i++)! acc += x[i];! return (float) acc / 8;! int a[8];! x a a[0] = 123; a[1] = 234; a[2] = 345; a[3] = 456;! a[4] = 567; a[5] = 678; a[6] = 789; a[7] = 890;! float mean! mean = array_mean(a);! printf( mean = %f\n, mean);! array2.c! x. (int x[])
27 void array_init (int x[8])! x[0] = 123; x[1] = 234; x[2] = 345; x[3] = 456;! x[4] = 567; x[5] = 678; x[6] = 789; x[7] = 890;! int a[8];! array_init(a);! int i, acc = 0;! for (i = 0; i < 8; i++) printf( a[%d] = %d\n, i, a[i]);! acc += a[i];! printf( mean = %f\n, (float) acc / 8);! x a array3.c! x. (int x[])
28 char c;! array4.c! This is the letter A.! This is a string MYU.! This is also a string MYU c = A ;! printf( This is the letter %c.\n, c);! char s[4];! %c s[0] = M ; s[1] = Y ;! s[2] = U ; s[3] = \0 ;! printf( This is a string %s.\n, s);! printf( This is also a string %s.\n, MYU );! s! \0!
29 char s[4] = MYU ;! int i;! s array5.c! s MYU!! for (i = 0; i < 4; i++) if (s[i] == \0 )! if (s[i] == 0)! printf( s[%d] = end\n, i);! else! printf( s[%d] = %c \n, i, s[i]);! s[0] = 'M! s[1] = 'Y! s[2] = 'U! s[3] = end
30
31 int k;! int *p;! p! p = &k;! &k k! k = 123;! printf( k = %d, *p = %d\n, k, *p);! k = 234;! printf( k = %d, *p = %d\n, k, *p);! *p = 345;! printf( k = %d, *p = %d\n, k, *p);! pointer1.c! k p? k p *p p!! k = 123, *p = 123! k = 234, *p = 234! k = 345, *p = 345
32 pointer2.c! char *s;! s? s = Miyagi ;! int i = 0;! while (s[i]!= \0 ) printf( s[%d] = %c \n, i, s[i]);! i++;! printf( s[%d] = end\n, i);! s s[0] = M! s[1] = i! s[2] = y! s[3] = a! s[4] = g! s[5] = i! s[6] = end
33 void explode (char *str)! int i = 0;! while (str[i]!= \0 ) printf( str[%d] = %c \n, i, str[i]);! i++;! printf( str[%d] = end\n, i);! char *s;! s = Miyagi ;! explode(s);! s pointer3.c! str[0] = M! str[1] = i! str[2] = y! str[3] = a! str[4] = g! str[5] = i! str[6] = end
34 void explode (char *str)! while (*str!= \0 ) printf( char = %c \n, *str);! str++;! printf( str[%d] = end\n, i);! char *s;! s = Miyagi ;! explode(s);! s pointer4.c! while (*str) printf( char = %c\n, *str);! str++;! }! char = M! char = i! char = y! char = a! char = g! char = i! char = end
35 struct
36 struct gp_data float latitude;!!// ! float longitude;!!// ! float altitude;!!// [m]! };! void gp_print (struct gp_data *gp)! printf( latitude : %f\n, gp->latitude);! printf( longitude: %f\n, gp->longitude);! printf( altitude : %f\n, gp->altitude);! struct gp_data gp_myu;! gp_myu.latitude = ;! gp_myu.longitude = ;! gp_myu.altitude = 92.50;! gp_print(&gp_myu);! *gp! struct1.c! x->y! x! y! x.y! x! y! &gp_myu! gp_myu!
37 #include <math.h>! struct pos double x, y;! };! double distance (struct pos *p1, struct pos *p2)! float dx = p1->x - p2->x,! dy = p1->y - p2->y;! return sqrt(dx*dx + dy*dy);! double sqrt(double);! struct pos now, goal;! now.x = 1.23; now.y = 2.34;! goal.x = 3.45; goal.y = 4.56;! double d = distance(&now, &goal);! printf( distance = %f\n, d);! struct2.c! sqrt, sin! now, goal!
38 // Tobii! // 120! struct _TobiiGazeData // int timestamp_sec; // int timestamp_microsec; // // float x_gazepos_lefteye; // float y_gazepos_lefteye; // float x_camerapos_lefteye; // Tobii float y_camerapos_lefteye; // Tobii float diameter_pupil_lefteye; // float distance_lefteye; // long validity_lefteye; // 0=,1-3=,4= // float x_gazepos_righteye; // float y_gazepos_righteye; // float x_camerapos_righteye; // Tobii float y_camerapos_righteye; // Tobii float diameter_pupil_righteye; // float distance_righteye; // int validity_righteye; // 0=,1-3=,4= };!
39
40 void ango (char *str)! int i = 0;! while (str[i]!= \0 ) str[i] += 1;! i++;! char *s = Miyagi ;! printf( moto: %s\n, s);! ango(s);! printf( ango: %s\n, s);! s memory1.c!!!!
41 void ango (char *str)! int i = 0;! while (str[i]!= \0 ) str[i] += 1;! i++;!! Miyagi! char s[] = Miyagi ;! printf( moto: %s\n, s);! ango(s);! printf( ango: %s\n, s);! s memory2.c!! moto: Miyagi! ango: Njzbhj
42 #include <stdlib.h>! char s_data[5] = data ;! char *s_code = code ;! char s_stack[6] = stack ;! char *s_heap;! s_heap = malloc(5);! s_heap[0] = h ; s_heap[1] = e ;! s_heap[2] = a ; s_heap[3] = p ;! s_heap[4] = \0 ;! printf( %s, %s, %s, %s\n,! s_code, s_data, s_stack, s_heap );! memory3.c!! code!!! data!!! heap! malloc!! stack!!! code, data, stack, heap
43 char *s_code = code ;! printf( %s\n, s_code);! s_code[0] = C ;! printf( %s\n, s_code);!!!!!!! memory4.c!! code!!! data!!! heap! malloc!! stack!!!
44 char s_data[5] = data ;! void dosomething (void)!! s_data[0] = D ;!! printf( %s\n, s_data);! dosomething();! printf( %s\n, s_data);! data! Data memory5.c!! code!!! data!!! heap! malloc!! stack!!!
45 void fun1 (void)! char s_stack[6] = STACK ;! printf( fun1: %s\n, s_stack);! char s_stack[6] = stack ;! printf( main: %s\n, s_stack);! fun1();! printf( main: %s\n, s_stack);! (main)! s_stack[6]! (fun1)! s_stack[6]! (main)! (main)!! s_stack[6]!! s_stack[6]! memory6.c!! code!!! data!!! heap! malloc!! stack!!! main: stack! fun1: STACK! main: stack
46 fun1: stack! fun2: Stack! void fun2 (char *str)! fun1: Stack str[0] = S ;! printf( fun2: %s\n, str);! void fun1 (void)! char s_stack[6] = stack ;! printf( fun1: %s\n, s_stack);! fun2(s_stack);! printf( fun1: %s\n, s_stack);! fun1();! (main)!! (fun1)! s_stack[6]! (main)!! (fun2)! str! (fun1)! s_stack[6]! (main)! memory7.c!! code!!! data!!! heap! malloc!! stack!!!! (fun1)! s_stack[6]! (main)!!
47 char *funok (char *str)! str[0] = S ;! return str;!! (main)! s_st[],res! char *funng ()! char str[6] = STACK ;! return str;!!! (funng)! str[6]! char s_st[6] = stack ;! char *res;! res = funok(s_st); printf( %s\n, res);! res = funng(); printf( %s\n, res);! memory8.c! (main)! (main)!! s_st[],res!! s_st[],res! Stack! *error*!
48 malloc #include <stdlib.h>! char *func (void)! char *s_heap;!! s_heap = (char *) malloc(5);! s_heap[0] = h ; s_heap[1] = e ;! s_heap[2] = a ; s_heap[3] = p ;! s_heap[4] = \0 ;! printf( func: %s\n, s_heap);! return s_heap;!!! char *res;!! res = func();! printf( main: %s\n, res);! memory9.c!! code!!! data!!! heap! malloc!! stack!!! func: heap! main: heap
49 malloc // ex.! char *s;!! s = (char *) malloc(3);! s[0] = O ; s[0] = K ; s[0] = \0 ;! // ex.! int *a;!! a = (int *) malloc(sizeof(int) * 4);! a[0] = 14; a[1] = 15; a[2] = 92; a[3] = 65;! //! struct pos *p;!! p = (struct pos *) malloc(sizeof(struct pos));! p->x = 12.3; p->y = 23.4;! //! free(s);! free(a);! free(p);! malloc!
50 //! char sd[5] = data ;! void fun (void)! char *sc = code ;! char ss[6] = stack ;! char *sh = (char *) malloc(5);! //!!!!!!!!malloc free!! code!!! data!!! heap! malloc!! stack!!! (fun2)! str! (fun1)! s_stack[6]! (fun1)! s_stack[6]! (fun1)! s_stack[6]! (main)!! (main)!! (main)!! (main)!!
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1.ppt
/* * Program name: hello.c */ #include int main() { printf( hello, world\n ); return 0; /* * Program name: Hello.java */ import java.io.*; class Hello { public static void main(string[] arg)
A/B (2018/10/19) Ver kurino/2018/soft/soft.html A/B
A/B (2018/10/19) Ver. 1.0 kurino@math.cst.nihon-u.ac.jp http://edu-gw2.math.cst.nihon-u.ac.jp/ kurino/2018/soft/soft.html 2018 10 19 A/B 1 2018 10 19 2 1 1 1.1 OHP.................................... 1
超初心者用
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Informatics 2014
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Informatics 2015
C 計算機の歴史 新旧のソロバン バベッジの階差機関 19C前半 手回し計算機 19C後半 20C後半 スパコン 1960年代 ENIAC (1946) 大型汎用計算機 1950年代 1980年代 電卓 1964 パソコン 1970年代 現在のコンピュータ Input Output Device Central Processing Unit I/O CPU Memory OS (Operating
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ohp03.dvi
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導入基礎演習.ppt
Multi-paradigm Programming Functional Programming Scheme Haskell ML Scala X10 KL1 Prolog Declarative Lang. C Procedural Lang. Java C++ Python Object-oriented Programming / (root) bin home lib 08 09
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r03.dvi
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r08.dvi
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Taro-リストⅢ（公開版）.jtd
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kiso2-06.key
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c-all.dvi
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橡Pro PDF
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ohp08.dvi
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第 4 回基本データ構造 1 明星大学情報学科 2 3 年前期 アルゴリズムとデータ構造 Ⅰ 第 4 回 Page 1 配列 スタック キューとその操作 4-1. 配列とその操作 配列型 同じ型の変数を並べたもの 配列にする型は 基本型 配列型 構造体 ポインタいずれでもよい 要素の並べ方を 次元 という 1 次元配列 ( 直線状 ) 2 次元配列 ( 平面状 ) 3 次元配列 ( 立体状 ) a[5]
C による数値計算法入門 ( 第 2 版 ) 新装版 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 新装版 1 刷発行時のものです.
C による数値計算法入門 ( 第 2 版 ) 新装版 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. http://www.morikita.co.jp/books/mid/009383 このサンプルページの内容は, 新装版 1 刷発行時のものです. i 2 22 2 13 ( ) 2 (1) ANSI (2) 2 (3) Web http://www.morikita.co.jp/books/mid/009383
kiso2-03.key
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Informatics 2010.key
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PowerPoint Presentation
p.130 p.198 p.208 2 double weight[num]; double min, max; min = max = weight[0]; for( i= 1; i i < NUM; i++ ) ) if if ( weight[i] > max ) max = weight[i]: if if ( weight[i] < min ) min = weight[i]: weight
1 return main() { main main C 1 戻り値の型 関数名 引数 関数ブロックをあらわす中括弧 main() 関数の定義 int main(void){ printf("hello World!!\n"); return 0; 戻り値 1: main() 2.2 C main
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void hash1_init(int *array) int i; for (i = 0; i < HASHSIZE; i++) array[i] = EMPTY; /* i EMPTY */ void hash1_insert(int *array, int n) if (n < 0 n >=
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joho07-1.ppt
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問 2 ( 型変換 ) 次のプログラムを実行しても正しい結果が得られない 何が間違いかを指摘し 正しく修正せよ ただし int サイズが 2 バイト long サイズが 4 バイトの処理系での演算を仮定する #include <stdio.h> int main( void ) { int a =
問 1 配列の宣言整数型配列 data1 にデータが初期設定されている この配列 data1 のデータを下図のように 整数型配列 data2 に代入しなさい また data2 の内容を printf( "data2[0] = %d\n", data2[0] ); printf( "data2[5] = %d\n", data2[5] ); を用いて出力しなさい 実行結果 data2[0] = 76
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x h = (b a)/n [x i, x i+1 ] = [a+i h, a+ (i + 1) h] A(x i ) A(x i ) = h 2 {f(x i) + f(x i+1 ) = h {f(a + i h) + f(a + (i + 1) h), (2) 2 a b n A(x i )
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プログラミング方法論 II 第 14,15 回 ( 担当 : 鈴木伸夫 ) 問題 17. x 座標と y 座標をメンバに持つ構造体 Point を作成せよ 但し座標 は double 型とする typedef struct{ (a) x; (b) y; Point; 問題 18. 問題 17 の Point を用いて 2 点の座標を入力するとその 2 点間の距 離を表示するプログラムを作成せよ 平方根は
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Taro-リストⅠ（公開版）.jtd
0. 目次 1. 再帰的なデータ構造によるリストの表現 1. 1 リストの作成と表示 1. 1. 1 リストの先頭に追加する方法 1. 1. 2 リストの末尾に追加する方法 1. 1. 3 昇順を保存してリストに追加する方法 1. 2 問題 問題 1 問題 2-1 - 1. 再帰的なデータ構造によるリストの表現 リストは データの一部に次のデータの記憶場所を示す情報 ( ポインタという ) を持つ構造をいう
ex01.dvi
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kiso2-09.key
座席指定はありません 計算機基礎実習II 2018 のウェブページか 第9回 ら 以下の課題に自力で取り組んで下さい 計算機基礎実習II 第7回の復習課題(rev07) 第9回の基本課題(base09) 第8回試験の結果 中間試験に関するコメント コンパイルできない不完全なプログラムなど プログラミングに慣れていない あるいは複雑な問題は 要件 をバラして段階的にプログラムを作成する exam08-2.c
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P06.ppt
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