ARspec_decomp.dvi
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- しょうじ こしの
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1 February 8, 0 auto-regresive mode AR ) AR.. t N fx t);x t);x3 t); ;xn t)g Burg AR xt) a m xt m t)+fft) AR M Fina Prediction Error,FPE) FPEM) ^ff M +MN MN ^ff M P f) P f) ff t M a m e ißfm t AR [,,3]. AR Az ) a m z m 0 m m Ck t) F e kff t + e k t fg cos ßf k t) H sin ßf k t)g ) AR AR L. H. Zetterberg,Estimation of parameters for a inear difference equation wit appication to EEG anaysis",mat. Biosci.,5, ) ARMA AR
2 AR AR t fx t);x t);x3 t); ;xn t)g M AR xt) a xt t)+a xt t)+ + a M xt M t)+fft) a m xt m t)+fft); ) fa ; ;a M g fft) 0, ff P f) P f) A ) ff t ) M a m e ißfm t Az ) a m z m 3) P f) a m e ißf t m ff t ) ) a m e ißf t m ff t Az ) Az) 4) zexpißf t) z AR C) Ck t) Wiener-Kintcine Z t Ck t) t P f) e ißfk t df 5) Ck t) Z t t ff iß Z ff t P M a m e ißfm t eißfk t df z Az )Az) zk dz 6) e ißf t z m m Ck t) F e kff t + e k t fg cos ßf k t) H sin ßf k t)g 7)
3 Figure : a) C ) F e ff. b) a) 0) ) c) C ) e k t fg cos ßf k t) H sin ßf k t)g. d) c) ) ) 7) Wiener-Kintcine P f) t ' t k Z 0 Ck t)e ißfk t 8) Ck t) cosßfk t) dk 9). C k t) F e kff t Fig. a)) P f) Fig. b))., t! 0 F ff F ff +4ß f ; 0). C k t) e k t fg cos ßf k t) H sin ßf k t)g Fig. c)) ) P f) G +4ß f + f ) + +4ß f f ) ) ß f + f ) H +4ß f + f ) ß f f ) ; ) +4ß f f ) Fig. d))., t! 0 G f H G H 0 7) q R G + H Φ tan H G 3
4 G cos ßf k t) H sin ßf k t) R cosßf k t +Φ ) ) k 0 f 7) ) H > 0 H 0 f H < 0 f >0 P f) G +4ß f f ) + ß f f ) H 3) +4ß f f ) dp f)df 0) H > 0 H < 0 f Λ f + G ßH ψs + H G ψs f Λ f G + H ßH G!! ; 4) 3) H 60 4),5) AR AR 7) 7) ff,, f, F, G, H AR Az ) 3) ) 0 5) Az ) a z a z a M z M 0 6) 6) 7) 6) M fz ;z ; ;z M g m m m +m M 6) e ff t ; ; ; ;m ) 7) e t±ißf t ; ; ; ;m ) 0» f» 7) t t 7) 8) ff,, f 7) 7) 8) n z0) ff t n t f arg ß t n t arg ß t 8) 4
5 z) Az) d dz z M Φ Ψ ψ z M Az ) a m z!ψm m z) 7) F ff G ff Re H ff Im B ) 3 ff Re ff Im a m M m)z m! 9) AR AR 3. 3 AR t xt) :8xt ) :495xt )+0:45xt 3) + fft) AR 0) ) ) Az ) :8z +:495z 0:45z 3 0 3) z 3 z 3 :8z +:495z 0:45) 0 z 3 z 0:5)z :3z +0:845) 0 z 0:5; 0:65 ± 0:65i 0:5 7) ff t ) 0:5 e ff F 9) z) ff n 0:5 0: ) :8z +:495z 0:45z 3 )3 3:6z +:495z ) F ff 0:5) 5) :33463 ff 6) fft) ff ff, F 0) Fig. b)) 5
6 Figure : a) 3 AR xt) :8xt ) :495xt )+0:45xt 3) + fft) b) c) 0:65 ± 0:65i G, H ),) 0:994; arg ±0:78540 n z 0: ) f arg ß 6:895 + :337i 0:5 8) G :579 ff 9) H :4674 ff 30) ) Fig. c)) f Λ 5) f Λ 0:370 3) f 0:5 H G f 4 RQ3 AR M 7 FPE 7 AR AR 4. Tabe ) 0% Tabe Fig. 3 f Λ ß 8 6
7 Figure 3: a) RQ3 ) ). b) a) f f Λ Tabe : RQ3 I %power ff f F G H f Λ A xt) yt) yt) Z u)xt u) du 3) xt) P x f) yt) P y f) Z Af) ) e ißf d 33) i ) u) t P y f) Af) P x f) 34) yt) m 33),34) Af) m a m xt m t) 35) am) e ißfm t d 36) P y f) Af) P x f) 37) 7
8 t» f» t AR ) AR ) ) P x f) yt) xt) a m xt m t) fft) 38) xt) yt) 37) 36) Af) a m e ißfm t 39) 38) yt) P y f) fft) P y f) ff t 40) 38) P y f) P x f) M a m e ißfm t P x f) ff t P x f) ff t 4) M a m e ißfm t B AR AR 6) 7) Ck t) ff iß Z z Az )Az) zk dz 4) m m Ck t) F e kff t + e k t fg cos ßf k t) H sin ßf k t)g 43) AR ) ) Az ) a m z m 0 44) AR fz ;z ; ;z M g z m < ) 8
9 k 45) M 45) z k Ck t) ff iß z z m ) Az )Az) z z m ) zzm z z m ) Z z Az )Az) zk dz z k M ff z z m ) Az )Az) 45) zzm ψ z M ψ z k a m z m! Az) z k z M zz m a m z m! Az) zz m z m ) k+m z m z )z m z ) z m z m )z m z m+ ) z m z M ) Az m ) Az m ) Az) Az) z m ) k+m ρ d dz zm Az )ff zzm Mz M M z k z k z M a m M m)z M m ) a m M m)z m ) zz m zz m 45) Ck t) ff M Az) M z k a m M m)z m ) zz m ff M z m )z m ) k 46) z) 9) ). k» 0 z 0 9
10 44) 46) e ff t ; ; ; ;m ) 47) k e ff t k e ffk t 48) e t±ißf t ; ; ; ;m ) 49) k n + n + Re n Re Re n Re k + e k t n Re + i Im + i Im + i Im i Im 45) k Ck t) m ff m + e ffk t e t±ißf t k k e k t fcos ßf k t) ± i sin ßf k t)g o n ff e k t Re 43) o o o cos ßf k t) Im F ff e k t fcos ßf k t)+i sin ßf k t)g e k t fcos ßf k t) i sin ßf k t)g e k t fcos ßf k t)+i sin ßf k t)g G ff Re H ff Im e k t fcos ßf k t) i sin ßf k t)g o sin ßf k t) cos ßf k t) Im o sin ßf k t) 50) 0
11 References [],,977) [], ),,998) [3],,,007)
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x (x, ) x y (, y) iy x y z = x + iy (x, y) (r, θ) r = x + y, θ = tan ( y ), π < θ π x r = z, θ = arg z z = x + iy = r cos θ + ir sin θ = r(cos θ + i s
... x, y z = x + iy x z y z x = Rez, y = Imz z = x + iy x iy z z () z + z = (z + z )() z z = (z z )(3) z z = ( z z )(4)z z = z z = x + y z = x + iy ()Rez = (z + z), Imz = (z z) i () z z z + z z + z.. z
211 [email protected] 1 R *1 n n R n *2 R n = {(x 1,..., x n ) x 1,..., x n R}. R R 2 R 3 R n R n R n D D R n *3 ) (x 1,..., x n ) f(x 1,..., x n ) f D *4 n 2 n = 1 ( ) 1 f D R n f : D R 1.1. (x,
36 3 D f(z) D z f(z) z Taylor z D C f(z) z C C f (z) C f(z) f (z) f(z) D C D D z C C 3.: f(z) 3. f (z) f 2 (z) D D D D D f (z) f 2 (z) D D f (z) f 2 (
3 3. D f(z) D D D D D D D D f(z) D f (z) f (z) f(z) D (i) (ii) (iii) f(z) = ( ) n z n = z + z 2 z 3 + n= z < z < z > f (z) = e t(+z) dt Re z> Re z> [ ] f (z) = e t(+z) = (Rez> ) +z +z t= z < f(z) Taylor
II No.01 [n/2] [1]H n (x) H n (x) = ( 1) r n! r!(n 2r)! (2x)n 2r. r=0 [2]H n (x) n,, H n ( x) = ( 1) n H n (x). [3] H n (x) = ( 1) n dn x2 e dx n e x2
II No.1 [n/] [1]H n x) H n x) = 1) r n! r!n r)! x)n r r= []H n x) n,, H n x) = 1) n H n x) [3] H n x) = 1) n dn x e dx n e x [4] H n+1 x) = xh n x) nh n 1 x) ) d dx x H n x) = H n+1 x) d dx H nx) = nh
1 I 1.1 ± e = = - = C C MKSA [m], [Kg] [s] [A] 1C 1A 1 MKSA 1C 1C +q q +q q 1
1 I 1.1 ± e = = - =1.602 10 19 C C MKA [m], [Kg] [s] [A] 1C 1A 1 MKA 1C 1C +q q +q q 1 1.1 r 1,2 q 1, q 2 r 12 2 q 1, q 2 2 F 12 = k q 1q 2 r 12 2 (1.1) k 2 k 2 ( r 1 r 2 ) ( r 2 r 1 ) q 1 q 2 (q 1 q 2
重力方向に基づくコントローラの向き決定方法
( ) 2/Sep 09 1 ( ) ( ) 3 2 X w, Y w, Z w +X w = +Y w = +Z w = 1 X c, Y c, Z c X c, Y c, Z c X w, Y w, Z w Y c Z c X c 1: X c, Y c, Z c Kentaro [email protected] 1 M M v 0, v 1, v 2 v 0 v
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1. 1 A : l l : (1) l m (m 3) (2) m (3) n (n 3) (4) A 2 1 2 1 2 3 α, β γ α β + γ = 2 m l lm n nα nα = lm. α = lm n. m lm 2β 2β = lm β = lm 2. γ l 2. 3 4 P, Q R n = {(x 1, x 2,, x n ) ; x 1, x 2,, x n R}
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(Bessel) (Legendre).. (Hankel). (Laplace) V = (x, y, z) n (r, θ, ϕ) r n f n (θ, ϕ). f n (θ, ϕ) n f n (θ, ϕ) z = cos θ z θ ϕ n ν. P ν (z), Q ν (z) (Fou
(Bessel) (Legendre).. (Hankel). (Laplace) V = (x, y, z) n (r, θ, ϕ) r n f n (θ, ϕ). f n (θ, ϕ) n f n (θ, ϕ) z = cos θ z θ ϕ n ν. P ν (z), Q ν (z) (Fourier) (Fourier Bessel).. V ρ(x, y, z) V = 4πGρ G :.
1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0
1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0 0 < t < τ I II 0 No.2 2 C x y x y > 0 x 0 x > b a dx
(ii) (iii) z a = z a =2 z a =6 sin z z a dz. cosh z z a dz. e z dz. (, a b > 6.) (z a)(z b) 52.. (a) dz, ( a = /6.), (b) z =6 az (c) z a =2 53. f n (z
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I ( ) 1 de Broglie 1 (de Broglie) p λ k h Planck ( Js) p = h λ = k (1) h 2π : Dirac k B Boltzmann ( J/K) T U = 3 2 k BT
I (008 4 0 de Broglie (de Broglie p λ k h Planck ( 6.63 0 34 Js p = h λ = k ( h π : Dirac k B Boltzmann (.38 0 3 J/K T U = 3 k BT ( = λ m k B T h m = 0.067m 0 m 0 = 9. 0 3 kg GaAs( a T = 300 K 3 fg 07345
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r(t) t r(t) O v(t) = dr(t) dt a(t) = dv(t) dt = d2 r(t) dt 2 r(t), v(t), a(t) t dr(t) dt r(t) =(x(t),y(t),z(t)) = d 2 r(t) dt 2 = ( dx(t) dt ( d 2 x(t) dt 2, dy(t), dz(t) dt dt ), d2 y(t) dt 2, d2 z(t)
1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2
2005 9/8-11 2 2.2 ( 2-5) γ ( ) γ cos θ 2πr πρhr 2 g h = 2γ cos θ ρgr (2.1) γ = ρgrh (2.2) 2 cos θ θ cos θ = 1 (2.2) γ = 1 ρgrh (2.) 2 2. p p ρgh p ( ) p p = p ρgh (2.) h p p = 2γ r 1 1 (Berry,1975) 2-6
2000年度『数学展望 I』講義録
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β β β (q 1,q,..., q n ; p 1, p,..., p n ) H(q 1,q,..., q n ; p 1, p,..., p n ) Hψ = εψ ε k = k +1/ ε k = k(k 1) (x, y, z; p x, p y, p z ) (r; p r ), (θ; p θ ), (ϕ; p ϕ ) ε k = 1/ k p i dq i E total = E
z f(z) f(z) x, y, u, v, r, θ r > 0 z = x + iy, f = u + iv C γ D f(z) f(z) D f(z) f(z) z, Rm z, z 1.1 z = x + iy = re iθ = r (cos θ + i sin θ) z = x iy
z fz fz x, y, u, v, r, θ r > z = x + iy, f = u + iv γ D fz fz D fz fz z, Rm z, z. z = x + iy = re iθ = r cos θ + i sin θ z = x iy = re iθ = r cos θ i sin θ x = z + z = Re z, y = z z = Im z i r = z = z
grad φ(p ) φ P grad φ(p ) p P p φ P p l t φ l t = 0 g (0) g (0) (31) grad φ(p ) p grad φ φ (P, φ(p )) xy (x, y) = (ξ(t), η(t)) ( )
2 9 2 5 2.2.3 grad φ(p ) φ P grad φ(p ) p P p φ P p l t φ l t = g () g () (3) grad φ(p ) p grad φ φ (P, φ(p )) y (, y) = (ξ(t), η(t)) ( ) ξ (t) (t) := η (t) grad f(ξ(t), η(t)) (t) g(t) := f(ξ(t), η(t))
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I013 00-1 : April 15, 013 Version : 1.1 I Kawahira, Tomoki TA (Shigehiro, Yoshida) http://www.math.nagoya-u.ac.jp/~kawahira/courses/13s-tenbou.html pdf * 4 15 4 5 13 e πi = 1 5 0 5 7 3 4 6 3 6 10 6 17
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1. 1 BASIC PC BASIC BASIC BASIC Fortran WS PC (1.3) 1 + x 1 x = x = (1.1) 1 + x = (1.2) 1 + x 1 = (1.
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AI n Z f n : Z Z f n (k) = nk ( k Z) f n n 1.9 R R f : R R f 1 1 {a R f(a) = 0 R = {0 R 1.10 R R f : R R f 1 : R R 1.11 Z Z id Z 1.12 Q Q id
1 1.1 1.1 R R (1) R = 1 2 Z = 2 n Z (2) R 1.2 R C Z R 1.3 Z 2 = {(a, b) a Z, b Z Z 2 a, b, c, d Z (a, b) + (c, d) = (a + c, b + d), (a, b)(c, d) = (ac, bd) (1) Z 2 (2) Z 2? (3) Z 2 1.4 C Q[ 1] = {a + bi
Tips KENZOU PC no problem 2 1 w = f(z) z 1 w w z w = (z z 0 ) b b w = log (z z 0 ) z = z 0 2π 2 z = z 0 w = z 1/2 z = re iθ θ (z = 0) 0 2π 0
Tips KENZOU 28 7 6 P no problem 2 w = f(z) z w w z w = (z z ) b b w = log (z z ) z = z 2π 2 z = z w = z /2 z = re iθ θ (z = ) 2π 4π 2 θ θ 2π 4π z r re iθ re i2π = r re i4π = r w r re iθ/2 re iπ = r re
Z: Q: R: C: 3. Green Cauchy
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I = [a, b] R γ : I C γ(a) = γ(b) z C \ γ(i) 1(4) γ z winding number index Ind γ (z) = φ(b, z) φ(a, z) φ 1(1) (i)(ii) 1 1 c C \ {0} B(c; c ) L c z B(c;
21 1 http://www.ozawa.phys.waseda.ac.jp/index2.html ( ) 1. I = [a, b] R γ : I C γ γ(i) z 0 C \ γ(i) (1) ε > 0 φ : I B(z 0 ; ε) C (i) B(z 0 ; ε) γ(i) = (ii) (t, z) I B(z 0 ; ε) exp(φ(t, z)) = γ(t) z (2)
n=1 1 n 2 = π = π f(z) f(z) 2 f(z) = u(z) + iv(z) *1 f (z) u(x, y), v(x, y) f(z) f (z) = f/ x u x = v y, u y = v x
n= n 2 = π2 6 3 2 28 + 4 + 9 + = π2 6 2 f(z) f(z) 2 f(z) = u(z) + iv(z) * f (z) u(x, y), v(x, y) f(z) f (z) = f/ x u x = v y, u y = v x f x = i f y * u, v 3 3. 3 f(t) = u(t) + v(t) [, b] f(t)dt = u(t)dt
5 1.2, 2, d a V a = M (1.2.1), M, a,,,,, Ω, V a V, V a = V + Ω r. (1.2.2), r i 1, i 2, i 3, i 1, i 2, i 3, A 2, A = 3 A n i n = n=1 da = 3 = n=1 3 n=1
4 1 1.1 ( ) 5 1.2, 2, d a V a = M (1.2.1), M, a,,,,, Ω, V a V, V a = V + Ω r. (1.2.2), r i 1, i 2, i 3, i 1, i 2, i 3, A 2, A = 3 A n i n = n=1 da = 3 = n=1 3 n=1 da n i n da n i n + 3 A ni n n=1 3 n=1
X G P G (X) G BG [X, BG] S 2 2 2 S 2 2 S 2 = { (x 1, x 2, x 3 ) R 3 x 2 1 + x 2 2 + x 2 3 = 1 } R 3 S 2 S 2 v x S 2 x x v(x) T x S 2 T x S 2 S 2 x T x S 2 = { ξ R 3 x ξ } R 3 T x S 2 S 2 x x T x S 2
77
O r r r, F F r,r r = r r F = F (. ) r = r r 76 77 d r = F d r = F (. ) F + F = 0 d ( ) r + r = 0 (. 3) M = + MR = r + r (. 4) P G P MX = + MY = + MZ = z + z PG / PG = / M d R = 0 (. 5) 78 79 d r = F d
DVIOUT
A. A. A-- [ ] f(x) x = f 00 (x) f 0 () =0 f 00 () > 0= f(x) x = f 00 () < 0= f(x) x = A--2 [ ] f(x) D f 00 (x) > 0= y = f(x) f 00 (x) < 0= y = f(x) P (, f()) f 00 () =0 A--3 [ ] y = f(x) [, b] x = f (y)
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II 2 II
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Chap9.dvi
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5 5. 2 D xy D (x, y z = f(x, y f D (2 (x, y, z f R 2 5.. z = x 2 y 2 {(x, y; x 2 +y 2 } x 2 +y 2 +z 2 = z 5.2. (x, y R 2 z = x 2 y + 3 (2,,, (, 3,, 3 (,, 5.3 (. (3 ( (a, b, c A : (x, y, z P : (x, y, x
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数学Ⅱ演習(足助・09夏)
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II Karel Švadlenka 2018 5 26 * [1] 1.1* 5 23 m d2 x dt 2 = cdx kx + mg dt. c, g, k, m 1.2* 5 23 1 u = au + bv v = cu + dv v u a, b, c, d R 1.3 14 14 60% 1.4 5 23 a, b R a 2 4b < 0 λ 2 + aλ + b = 0 λ =
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[ ] IC. f(x) = e x () f(x) f (x) () lim f(x) lim f(x) x + x (3) lim f(x) lim f(x) x + x (4) y = f(x) ( ) ( s46). < a < () a () lim a log xdx a log xdx ( ) n (3) lim log k log n n n k=.3 z = log(x + y ),
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