t θ, τ, α, β S(, 0 P sin(θ P θ S x cos(θ SP = θ P (cos(θ, sin(θ sin(θ P t tan(θ θ 0 cos(θ tan(θ = sin(θ cos(θ ( 0t tan(θ

Similar documents
1 (1) ( i ) 60 (ii) 75 (iii) 315 (2) π ( i ) (ii) π (iii) 7 12 π ( (3) r, AOB = θ 0 < θ < π ) OAB A 2 OB P ( AB ) < ( AP ) (4) 0 < θ < π 2 sin θ

高等学校学習指導要領

高等学校学習指導要領

4 4 θ X θ P θ 4. 0, 405 P 0 X 405 X P 4. () 60 () 45 () 40 (4) 765 (5) 40 B 60 0 P = 90, = ( ) = X

x () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x

70 : 20 : A B (20 ) (30 ) 50 1

<4D F736F F D B B83578B6594BB2D834A836F815B82D082C88C60202E646F63>

18 ( ) I II III A B C(100 ) 1, 2, 3, 5 I II A B (100 ) 1, 2, 3 I II A B (80 ) 6 8 I II III A B C(80 ) 1 n (1 + x) n (1) n C 1 + n C

高等学校学習指導要領解説 数学編

(2000 )

OABC OA OC 4, OB, AOB BOC COA 60 OA a OB b OC c () AB AC () ABC D OD ABC OD OA + p AB + q AC p q () OABC 4 f(x) + x ( ), () y f(x) P l 4 () y f(x) l P

A (1) = 4 A( 1, 4) 1 A 4 () = tan A(0, 0) π A π


, x R, f (x),, df dx : R R,, f : R R, f(x) ( ).,, f (a) d f dx (a), f (a) d3 f dx 3 (a),, f (n) (a) dn f dx n (a), f d f dx, f d3 f dx 3,, f (n) dn f


() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)

no35.dvi

2014 S hara/lectures/lectures-j.html r 1 S phone: ,

6 2 2 x y x y t P P = P t P = I P P P ( ) ( ) ,, ( ) ( ) cos θ sin θ cos θ sin θ, sin θ cos θ sin θ cos θ y x θ x θ P

f(x) = x (1) f (1) (2) f (2) f(x) x = a y y = f(x) f (a) y = f(x) A(a, f(a)) f(a + h) f(x) = A f(a) A x (3, 3) O a a + h x 1 f(x) x = a

高校生の就職への数学II


1

名古屋工業大の数学 2000 年 ~2015 年 大学入試数学動画解説サイト

4 4 4 a b c d a b A c d A a da ad bce O E O n A n O ad bc a d n A n O 5 {a n } S n a k n a n + k S n a a n+ S n n S n n log x x {xy } x, y x + y 7 fx

1 θ i (1) A B θ ( ) A = B = sin 3θ = sin θ (A B sin 2 θ) ( ) 1 2 π 3 < = θ < = 2 π 3 Ax Bx3 = 1 2 θ = π sin θ (2) a b c θ sin 5θ = sin θ f(sin 2 θ) 2

[ ] x f(x) F = f(x) F(x) f(x) f(x) f(x)dx A p.2/29

1 26 ( ) ( ) 1 4 I II III A B C (120 ) ( ) 1, 5 7 I II III A B C (120 ) 1 (1) 0 x π 0 y π 3 sin x sin y = 3, 3 cos x + cos y = 1 (2) a b c a +

C:/KENAR/0p1.dvi

#A A A F, F d F P + F P = d P F, F y P F F x A.1 ( α, 0), (α, 0) α > 0) (x, y) (x + α) 2 + y 2, (x α) 2 + y 2 d (x + α)2 + y 2 + (x α) 2 + y 2 =

D xy D (x, y) z = f(x, y) f D (2 ) (x, y, z) f R z = 1 x 2 y 2 {(x, y); x 2 +y 2 1} x 2 +y 2 +z 2 = 1 1 z (x, y) R 2 z = x 2 y

( ) 2.1. C. (1) x 4 dx = 1 5 x5 + C 1 (2) x dx = x 2 dx = x 1 + C = 1 2 x + C xdx (3) = x dx = 3 x C (4) (x + 1) 3 dx = (x 3 + 3x 2 + 3x +

pdf

lim lim lim lim 0 0 d lim 5. d 0 d d d d d d 0 0 lim lim 0 d

DE-resume

18 ( ) ( ) [ ] [ ) II III A B (120 ) 1, 2, 3, 5, 6 II III A B (120 ) ( ) 1, 2, 3, 7, 8 II III A B (120 ) ( [ ]) 1, 2, 3, 5, 7 II III A B (

1 1 sin cos P (primary) S (secondly) 2 P S A sin(ω2πt + α) A ω 1 ω α V T m T m 1 100Hz m 2 36km 500Hz. 36km 1

熊本県数学問題正解

(, ) (, ) S = 2 = [, ] ( ) 2 ( ) 2 2 ( ) 3 2 ( ) 4 2 ( ) k 2,,, k =, 2, 3, 4 S 4 S 4 = ( ) 2 + ( ) ( ) (

< 1 > (1) f 0 (a) =6a ; g 0 (a) =6a 2 (2) y = f(x) x = 1 f( 1) = 3 ( 1) 2 =3 ; f 0 ( 1) = 6 ( 1) = 6 ; ( 1; 3) 6 x =1 f(1) = 3 ; f 0 (1) = 6 ; (1; 3)

2009 IA 5 I 22, 23, 24, 25, 26, (1) Arcsin 1 ( 2 (4) Arccos 1 ) 2 3 (2) Arcsin( 1) (3) Arccos 2 (5) Arctan 1 (6) Arctan ( 3 ) 3 2. n (1) ta

春期講座 ~ 極限 1 1, 1 2, 1 3, 1 4,, 1 n, n n {a n } n a n α {a n } α {a n } α lim n an = α n a n α α {a n } {a n } {a n } 1. a n = 2 n {a n } 2, 4, 8, 16,

微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 初版 1 刷発行時のものです.


No2 4 y =sinx (5) y = p sin(2x +3) (6) y = 1 tan(3x 2) (7) y =cos 2 (4x +5) (8) y = cos x 1+sinx 5 (1) y =sinx cos x 6 f(x) = sin(sin x) f 0 (π) (2) y


i

1 29 ( ) I II III A B (120 ) 2 5 I II III A B (120 ) 1, 6 8 I II A B (120 ) 1, 6, 7 I II A B (100 ) 1 OAB A B OA = 2 OA OB = 3 OB A B 2 :

() n C + n C + n C + + n C n n (3) n C + n C + n C 4 + n C + n C 3 + n C 5 + (5) (6 ) n C + nc + 3 nc n nc n (7 ) n C + nc + 3 nc n nc n (


44 4 I (1) ( ) (10 15 ) ( 17 ) ( 3 1 ) (2)

生活設計レジメ

I II III 28 29

- II

(iii) 0 V, x V, x + 0 = x. 0. (iv) x V, y V, x + y = 0., y x, y = x. (v) 1x = x. (vii) (α + β)x = αx + βx. (viii) (αβ)x = α(βx)., V, C.,,., (1)

r d 2r d l d (a) (b) (c) 1: I(x,t) I(x+ x,t) I(0,t) I(l,t) V in V(x,t) V(x+ x,t) V(0,t) l V(l,t) 2: 0 x x+ x 3: V in 3 V in x V (x, t) I(x, t


function2.pdf

II Karel Švadlenka * [1] 1.1* 5 23 m d2 x dt 2 = cdx kx + mg dt. c, g, k, m 1.2* u = au + bv v = cu + dv v u a, b, c, d R

x A Aω ẋ ẋ 2 + ω 2 x 2 = ω 2 A 2. (ẋ, ωx) ζ ẋ + iωx ζ ζ dζ = ẍ + iωẋ = ẍ + iω(ζ iωx) dt dζ dt iωζ = ẍ + ω2 x (2.1) ζ ζ = Aωe iωt = Aω cos ωt + iaω sin

2010 II / y = e x y = log x = log e x 2. ( e x ) = e x 3. ( ) log x = 1 x 1.2 Warming Up 1 u = log a M a u = M a 0

1. (8) (1) (x + y) + (x + y) = 0 () (x + y ) 5xy = 0 (3) (x y + 3y 3 ) (x 3 + xy ) = 0 (4) x tan y x y + x = 0 (5) x = y + x + y (6) = x + y 1 x y 3 (

Acrobat Distiller, Job 128

II A A441 : October 02, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka )

: α α α f B - 3: Barle 4: α, β, Θ, θ α β θ Θ

, 3, 6 = 3, 3,,,, 3,, 9, 3, 9, 3, 3, 4, 43, 4, 3, 9, 6, 6,, 0 p, p, p 3,..., p n N = p p p 3 p n + N p n N p p p, p 3,..., p n p, p,..., p n N, 3,,,,


z f(z) f(z) x, y, u, v, r, θ r > 0 z = x + iy, f = u + iv C γ D f(z) f(z) D f(z) f(z) z, Rm z, z 1.1 z = x + iy = re iθ = r (cos θ + i sin θ) z = x iy

, 1 ( f n (x))dx d dx ( f n (x)) 1 f n (x)dx d dx f n(x) lim f n (x) = [, 1] x f n (x) = n x x 1 f n (x) = x f n (x) = x 1 x n n f n(x) = [, 1] f n (x

( ) sin 1 x, cos 1 x, tan 1 x sin x, cos x, tan x, arcsin x, arccos x, arctan x. π 2 sin 1 x π 2, 0 cos 1 x π, π 2 < tan 1 x < π 2 1 (1) (

A S- hara/lectures/lectures-j.html r A = A 5 : 5 = max{ A, } A A A A B A, B A A A %

1 8, : 8.1 1, 2 z = ax + by + c ax by + z c = a b +1 x y z c = 0, (0, 0, c), n = ( a, b, 1). f = n i=1 a ii x 2 i + i<j 2a ij x i x j = ( x, A x), f =


I y = f(x) a I a x I x = a + x 1 f(x) f(a) x a = f(a + x) f(a) x (11.1) x a x 0 f(x) f(a) f(a + x) f(a) lim = lim x a x a x 0 x (11.2) f(x) x

Chap11.dvi

1 1 3 ABCD ABD AC BD E E BD 1 : 2 (1) AB = AD =, AB AD = (2) AE = AB + (3) A F AD AE 2 = AF = AB + AD AF AE = t AC = t AE AC FC = t = (4) ABD ABCD 1 1

17 ( ) II III A B C(100 ) 1, 2, 6, 7 II A B (100 ) 2, 5, 6 II A B (80 ) 8 10 I II III A B C(80 ) 1 a 1 = 1 2 a n+1 = a n + 2n + 1 (n = 1,

( )

II ( ) (7/31) II ( [ (3.4)] Navier Stokes [ (6/29)] Navier Stokes 3 [ (6/19)] Re

III No (i) (ii) (iii) (iv) (v) (vi) x 2 3xy + 2 lim. (x,y) (1,0) x 2 + y 2 lim (x,y) (0,0) lim (x,y) (0,0) lim (x,y) (0,0) 5x 2 y x 2 + y 2. xy x2 + y

,. Black-Scholes u t t, x c u 0 t, x x u t t, x c u t, x x u t t, x + σ x u t, x + rx ut, x rux, t 0 x x,,.,. Step 3, 7,,, Step 6., Step 4,. Step 5,,.

29

2009 I 2 II III 14, 15, α β α β l 0 l l l l γ (1) γ = αβ (2) α β n n cos 2k n n π sin 2k n π k=1 k=1 3. a 0, a 1,..., a n α a

[] x < T f(x), x < T f(x), < x < f(x) f(x) f(x) f(x + nt ) = f(x) x < T, n =, 1,, 1, (1.3) f(x) T x 2 f(x) T 2T x 3 f(x), f() = f(t ), f(x), f() f(t )

入試の軌跡

9 5 ( α+ ) = (α + ) α (log ) = α d = α C d = log + C C 5. () d = 4 d = C = C = 3 + C 3 () d = d = C = C = 3 + C 3 =

r III... IV.. grad, div, rot. grad, div, rot 3., B grad, div, rot I, II ɛ-δ web page (

. p.1/15

A A p.1/16

. sinh x sinh x) = e x e x = ex e x = sinh x 3) y = cosh x, y = sinh x y = e x, y = e x 6 sinhx) coshx) 4 y-axis x-axis : y = cosh x, y = s

I 1

ii 3.,. 4. F. (), ,,. 8.,. 1. (75%) (25%) =7 20, =7 21 (. ). 1.,, (). 3.,. 1. ().,.,.,.,.,. () (12 )., (), 0. 2., 1., 0,.

f(x,y) (x,y) x (x,y), y (x,y) f(x,y) x y f x (x,y),f y (x,y) B p.1/14

2016.

第121回関東連合産科婦人科学会総会・学術集会 プログラム・抄録

v_-3_+2_1.eps

DVIOUT-講

.. p.2/5

) ] [ h m x + y + + V x) φ = Eφ 1) z E = i h t 13) x << 1) N n n= = N N + 1) 14) N n n= = N N + 1)N + 1) 6 15) N n 3 n= = 1 4 N N + 1) 16) N n 4

*3 i 9 (1,) i (i,) (1,) 9 (i,) i i 2 1 ( 1, ) (1,) 18 2 i, 2 i i r 3r + 4i 1 i 1 i *4 1 i 9 i 1 1 i i 3 9 +

Transcription:

4 5 ( 5 3 9 4 0 5 ( 4 6 7 7 ( 0 8 3 9 ( 8

t θ, τ, α, β S(, 0 P sin(θ P θ S x cos(θ SP = θ P (cos(θ, sin(θ sin(θ P t tan(θ θ 0 cos(θ tan(θ = sin(θ cos(θ ( 0t tan(θ

S θ > 0 θ < 0 ( P S(, 0 θ > 0 ( 60 θ < 0 ( 300 P ( ( P θ ± n (n : cos(θ + = cos(θ, sin(θ + = sin(θ θ ( θ 3

B(0, C(, 0 A(, 0 x D(0, A,B,C,D ( θ = 0,,, 3 D θ = ( ( cos A, C (cos(0, sin(0 = A (, 0 ( ( ( B= cos, sin (0, (cos(, sin( = C (, 0 ( ( ( 3 3 D= cos, sin (0,, sin ( D= (0, tan(0 = tan( = 0 B, D ( ( 3 tan, tan ( ( 3 cos = cos = 0 4

( ; cos (θ + sin (θ = + tan (θ = cos (θ ( cos (θ {cos(θ} cos (θ cos(θ =c, sin(θ =s s P(c, s c θ θ c x Q( c, s s R(c, s. (cos( θ, sin( θ R = (cos(θ, sin(θ tan( θ = sin(θ cos(θ = tan(θ. (cos(θ +, sin(θ + Q = ( cos(θ, sin(θ 5

tan(θ + = sin(θ cos(θ = tan(θ Q( s, c s c P(c, s s θ c x R(s, c ( 3. (cos θ + (, sin θ + Q= ( sin(θ, cos(θ ( ( 4. cos θ (, sin θ R= (sin(θ, cos(θ ( tan θ + ( = tan θ = tan(θ ; R(θ = cos(θ sin(θ sin(θ θ cos(θ 5 θ = 0 R(0 = cos(0 sin(0 sin(0 = 0 = E cos(0 0 θ = ( R = ( cos ( sin ( sin ( cos = 0 0 6

θ = R( = cos ( sin ( sin ( = 0 = E cos ( 0 θ = ( R = ( cos ( sin ( sin ( cos = 0 ( = R 0 R(θR(τ =R(τR(θ =R(θ + τ θ θ R( θ = cos( θ sin( θ R(θ sin( θ = cos(θ cos( θ sin(θ sin(θ cos(θ R(θR( θ =R( θr(θ =R(θ θ =R(0 = E R( θ = {R(θ} v = cos(θ 4 sin(θ R( v = 0 cos(θ = cos(θ 0 sin(θ sin(θ. 7

( R v = 3. 0 cos(θ = sin(θ 0 sin(θ cos(θ ( R 0 v = cos(θ = sin(θ 0 sin(θ cos(θ 4. cos(β R(α sin(β R(α cos(β = cos(α sin(β sin(α sin(α cos(β = cos(α cos(β sin(α sin(β cos(α sin(β sin(α cos(β + cos(α sin(β R(α cos(β = cos (α + β sin(β sin (α + β cos (α + β = cos(α cos(β sin(α sin(β sin (α + β = sin(α cos(β + cos(α sin(β tan(α + β = sin(α cos(β + cos(α sin(β cos(α cos(β sin(α sin(β = tan(α + tan(β tan(α tan(β 8

3 (60 cos ( A + 90 = sin( A x (60 = 360 = 80 ( = 57.30 r θ ; l = rθ ; S = r θ = lr = 80 ( 80 = ex. (i 45 = 45 80 = 4 (ii 0 = 0 80 = 3 9

(iii 3 4 = 3 80 4 = 35 (iv 5 = 80 5 = 36 [ ] A v v A t S x S (, 0 t A SA= t, SA= t A (cos(t, sin(t v v A ( v v = ( v x, v 3. = ( sin(t, cos(t (3. p.6 A (cos(t, sin(t ( sin(t, cos(t 4 0

x ( P ( x sin(θ θ P sin(θ θ x θ θ x + = = sin(θ. sin(θ + = sin(θ sin(θ + = sin(θ 3 θ = sin(θ P

3 θ = cos(θ ( 3. sin θ + = cos(θ ( ( sin θ = cos(θ = cos(θ = sin(θ θ 3 θ = sin(θ; = cos(θ; < θ <. tan(θ + = tan(θ

3 θ 3. (60 360. ( 3. 400( 3. 00 = 0 3

[ ] = sin(θ 3 θ = cos(θ 3 θ 3 sin(θ + = sin(θ cos(θ + = cos(θ tan(θ + = tan(θ θ = tan(θ [ ] x f(x f( x = f(x ; ; 4

k f(x = x k f(x = x k+ θ cos( θ = cos(θ ; sin( θ = sin(θ, tan( θ = tan(θ ; B A A θ θ B = cos(θ = sin(θ cos( θ = cos(θ A; (θ, cos(θ B; ( θ, cos(θ sin( θ = sin(θ A; (θ, sin(θ B; ( θ, sin(θ 5 ( ( 8 cos (α + β = cos(α cos(β sin(α sin(β sin (α + β = sin(α cos(β + cos(α sin(β 5

tan(α + β = tan(α + tan(β tan(α tan(β β α cos (α = cos (α sin (α sin (α = sin(α cos(α tan(α = sin (α + cos (α = tan(α tan (α cos (α = cos (α sin (α = cos (α = sin (α cos (α = + cos(α, sin (α = cos(α tan (α = cos(α + cos(α β β α + β α β cos (α β = cos (α + ( β = cos(α cos( β sin(α sin( β = cos(α cos(β + sin(α sin(β cos (α β = cos(α cos(β + sin(α sin(β sin (α β = sin(α cos(β cos(α sin(β tan(α β = tan(α tan(β + tan(α tan(β cos (α + β = cos(α cos(β sin(α sin(β cos (α β = cos(α cos(β + sin(α sin(β 6

cos (α + β + cos (α β = cos(α cos(β cos (α + β cos (α β = sin(α sin(β cos(α cos(β = {cos (α + β + cos (α β} sin(α sin(β = {cos (α + β cos (α β} sin (α + β = sin(α cos(β + cos(α sin(β sin (α β = sin(α cos(β cos(α sin(β sin (α + β + sin (α β = sin(α cos(β 3 sin(α cos(β = {sin (α + β + sin (α β} 3 cos (α + β + cos (α β = cos(α cos(β cos (α + β cos (α β = sin(α sin(β sin (α + β + sin (α β = sin(α cos(β α + β = θ, α β = τ α = θ + τ, β = θ τ ( ( θ + τ θ τ cos (θ + cos (τ = cos cos ( ( θ + τ θ τ cos (θ cos (τ = sin sin ( ( θ + τ θ τ sin (θ + sin (τ = sin cos 7

τ τ sin (θ + sin ( τ = ( θ τ sin ( θ + τ cos sin ( τ = sin (τ 4 ( ( θ + τ θ τ sin (θ sin (τ = cos sin C sin (α + S cos (α = C + S { C sin (α + S cos (α = C + S sin(α + β sin(β = S C + S, cos(β = C S sin (α + C + S C C + S } C + S cos (α tan(β = S C 6 sin(t P t S x cos(t SP = t P x = cos(t, = sin(t 8

{cos(t} cos(t + t cos(t = lim t 0 t {sin(t} sin(t + t sin(t = lim t 0 t x = lim t 0 t = lim t 0 t x, t t + t ( t + t x = cos(t + t cos(t = sin + t ( t + t sin ( = sin t + t ( t sin = sin(t + t sin(t = ( = cos t + t ( t sin u = t x t t = cos(t + t cos(t t = sin(t + t sin(t t ( t + t cos + t ( t + t sin t t t 0 u 0 sin( u u ( u 0 = sin(t + u sin( u u = cos (t + u sin( u u {cos(t} = sin(t, {sin(t} = cos(t sin(t ( u 0 cos(t ( u 0 ( ( { x + = sin(t + u sin( u } { + cos (t + u sin( u t t u u = { sin (t + u + cos (t + u } { } sin( u u { } sin( u = ( u 0 u } 9

( ( dx d + = { sin(t} + {cos(t} = dt dt ( ( ( ( x dx d + + ( t 0 t t dt dt sin(x = x x3 6 + x5 (8 0 x sin(x x ex. ( ( dx d 3 + = dt dt = sin(x = cos(x = sin(x {sin(x} = cos(x ( sin 80 x 80 = 360 ( = sin 80 x = ( 80 cos 80 x 0

{sin(x} = cos (x 7 x = sin( = sin (x x, sin ( Y r Y P r ( r x = Y ( r < Y < r 3 P ( I IV sin ( Y r = xp, sin ( Y r

cos (x x = cos( = cos (x x, 0 sin (x + cos (x = cos (x = sin (x x > 0 x = cos (x = sin (x x 0 sin (x, cos (x x = tan( = tan (x < x <, < < tan ( Y X

Y P x = X = Y s θ X x 3 P tan ( Y X = xp < tan ( Y X < = sin (x, = cos (x = x = sin (x x = cos (x x = tan (x = x 3

4 = tan (x x 4 8 (! x a + b x cos(t a = (x 0, 0 = (a cos(t, b sin(t + sin(t b = xx 0 a + 0 b = 4

Asteroid; x 3 + 3 = a 3 ( a cos 3 (t, a sin 3 (t x a cos(t + a sin(t = a 4 = a (a > 0 4x = ( a 4, a + a = tan(θ (x a 4 θ tan(θ = a a F(, 0 sin(x = x x3 6 + x5 0 cos(x = x + x4 4 + sin(x = cos(x = k=0 ( k x k+ (k +! ( k k=0 x k (k! 5

sin(x = ( 0 x! + ( x3 3! + ( x5 5! + cos(x = ( 0 x0 0! + ( x! + ( x4 4! + k! k 0! =, ( 0 = x 0 = < x < sin(x cos(x sin(x = x x3 3! + x5 5! + [ ] x! + cos(x = x! + x4 4! + + [ ] x! + [ ] + ( ( x n x n Casio 0 = x 0 6

ex. x = cos(x = 0.96595863 6 + ( 4 S D x! + x4 4! x6 6! = 0.96595857 0 ex. x = 4 0 cos(x x! + x4 4! x6 6! ex.3 x = 96 cos(x x! + x4 4! cos(x = 0.9994645875 x! = 0.9994645397 0 ex.4 x = 3 cos(x = 0.5 x! + x4 4! x6 6! = 0.4999645653 4, 5, x! + x4 4! x6 6! + x8 8! x0 0! + x! x = 0.5 7

cos(x = cos (x ( ( ex.5 cos = cos 6 ( ( cos = cos 3 6 3 c =ex. c = c c 3 = c = 0.499999997 ( ( c 3 = cos = 0.5 3 0 x = 96 c = x! + x4 4! c = c, c 3 = c, c 4 = c 3, c 5 = c 4 c 5 = 0.500000004 ( c = cos 96 c 5 = 0.5 ex.3 ex. cos 8

9 sin(θ θ cos(θ tan(θ θ (cos(0, sin(0 = (, 0 tan(0 = 0 ( ( ( ( cos, sin = (0, tan ; (cos(, sin( = (, 0 tan( = 0 ( ( cos (, sin ( = (0, tan ; ( ( ( cos, sin 6 6 ( ( ( cos, sin 4 4 ( ( ( cos, sin 3 3 ( 3 =, = = (, (, 3 ( tan 6 ( tan 4 ( tan 3 = 3 = = 3 cos (θ + sin (θ = + tan (θ = cos (θ. (cos( θ, sin( θ = (cos(θ, sin(θ. (cos(θ +, sin(θ + = ( cos(θ, sin(θ tan( θ = tan(θ, tan(θ + = tan(θ 9

( 3. (cos θ + (, sin θ + = ( sin(θ, cos(θ ( ( 4. cos θ (, sin θ = (sin(θ, cos(θ ( tan θ + ( = tan θ = tan(θ cos (α ± β = cos(α cos(β sin(α sin(β, ( tan(α ± β = sin (α ± β = sin(α cos(β ± cos(α sin(β tan(α ± tan(β tan(α tan(β cos (α = cos (α sin (α = cos (α = sin (α sin (α = sin(α cos(α, tan(α = tan(α tan (α cos (α = + cos(α, sin (α = cos(α tan (α = cos(α + cos(α cos(α cos(β = {cos (α + β + cos (α β} sin(α sin(β = {cos (α + β cos (α β} sin(α cos(β = {sin (α + β + sin (α β} α + β = θ, α β = τ α = θ + τ, β = θ τ cos (θ + cos (τ = ( θ + τ cos ( θ + τ cos (θ cos (τ = sin ( θ τ cos sin ( θ τ 30

sin (θ + sin (τ = sin (θ sin (τ = ( θ + τ sin ( θ + τ cos ( θ τ cos sin ( θ τ C sin (α + S cos (α = C + S sin(α + β tan(β = S C = 360 = 80 = 57.30 r θ ; l = rθ ; S = r θ = lr r r sin(θ θ r cos(θ a sin(a = R (R ; a = b cos(c + c cos(b a = b + c bc cos(a 3