廃棄物処理施設生活環境影響調査指針

Similar documents
Gmech08.dvi

知能科学:ニューラルネットワーク

知能科学:ニューラルネットワーク

植物工場の事例集.indd

64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () m/s : : a) b) kg/m kg/m k

1. z dr er r sinθ dϕ eϕ r dθ eθ dr θ dr dθ r x 0 ϕ r sinθ dϕ r sinθ dϕ y dr dr er r dθ eθ r sinθ dϕ eϕ 2. (r, θ, φ) 2 dr 1 h r dr 1 e r h θ dθ 1 e θ h

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0

プログラム

Gmech08.dvi

LLG-R8.Nisus.pdf

() (, y) E(, y) () E(, y) (3) q ( ) () E(, y) = k q q (, y) () E(, y) = k r r (3).3 [.7 ] f y = f y () f(, y) = y () f(, y) = tan y y ( ) () f y = f y

II ( ) (7/31) II ( [ (3.4)] Navier Stokes [ (6/29)] Navier Stokes 3 [ (6/19)] Re

1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2

#A A A F, F d F P + F P = d P F, F y P F F x A.1 ( α, 0), (α, 0) α > 0) (x, y) (x + α) 2 + y 2, (x α) 2 + y 2 d (x + α)2 + y 2 + (x α) 2 + y 2 =


Untitled

Part () () Γ Part ,

Gmech08.dvi

1 I 1.1 ± e = = - = C C MKSA [m], [Kg] [s] [A] 1C 1A 1 MKSA 1C 1C +q q +q q 1


TOP URL 1


Microsoft Word - 11問題表紙(選択).docx

85 4

untitled

(Compton Scattering) Beaming 1 exp [i (k x ωt)] k λ k = 2π/λ ω = 2πν k = ω/c k x ωt ( ω ) k α c, k k x ωt η αβ k α x β diag( + ++) x β = (ct, x) O O x

untitled

( ) ,

Taro13-芦北(改).jtd

Taro13-宇城(改).jtd

大型トランス等に係る現場解体作業について(抜油及び付属品取外し作業)

pdf

.5 z = a + b + c n.6 = a sin t y = b cos t dy d a e e b e + e c e e e + e 3 s36 3 a + y = a, b > b 3 s363.7 y = + 3 y = + 3 s364.8 cos a 3 s365.9 y =,

SFGÇÃÉXÉyÉNÉgÉãå`.pdf

/02/18

lim lim lim lim 0 0 d lim 5. d 0 d d d d d d 0 0 lim lim 0 d

II Karel Švadlenka * [1] 1.1* 5 23 m d2 x dt 2 = cdx kx + mg dt. c, g, k, m 1.2* u = au + bv v = cu + dv v u a, b, c, d R

ii 3.,. 4. F. (), ,,. 8.,. 1. (75%) (25%) =7 20, =7 21 (. ). 1.,, (). 3.,. 1. ().,.,.,.,.,. () (12 )., (), 0. 2., 1., 0,.

77

r d 2r d l d (a) (b) (c) 1: I(x,t) I(x+ x,t) I(0,t) I(l,t) V in V(x,t) V(x+ x,t) V(0,t) l V(l,t) 2: 0 x x+ x 3: V in 3 V in x V (x, t) I(x, t

8 300 mm 2.50 m/s L/s ( ) 1.13 kg/m MPa 240 C 5.00mm 120 kpa ( ) kg/s c p = 1.02kJ/kgK, R = 287J/kgK kPa, 17.0 C 118 C 870m 3 R = 287J

Note.tex 2008/09/19( )

m dv = mg + kv2 dt m dv dt = mg k v v m dv dt = mg + kv2 α = mg k v = α 1 e rt 1 + e rt m dv dt = mg + kv2 dv mg + kv 2 = dt m dv α 2 + v 2 = k m dt d

KENZOU


.2 ρ dv dt = ρk grad p + 3 η grad (divv) + η 2 v.3 divh = 0, rote + c H t = 0 dive = ρ, H = 0, E = ρ, roth c E t = c ρv E + H c t = 0 H c E t = c ρv T

B

No δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i x j δx j (5) δs 2

1. (8) (1) (x + y) + (x + y) = 0 () (x + y ) 5xy = 0 (3) (x y + 3y 3 ) (x 3 + xy ) = 0 (4) x tan y x y + x = 0 (5) x = y + x + y (6) = x + y 1 x y 3 (

高等学校学習指導要領

高等学校学習指導要領

A (1) = 4 A( 1, 4) 1 A 4 () = tan A(0, 0) π A π

ma22-9 u ( v w) = u v w sin θê = v w sin θ u cos φ = = 2.3 ( a b) ( c d) = ( a c)( b d) ( a d)( b c) ( a b) ( c d) = (a 2 b 3 a 3 b 2 )(c 2 d 3 c 3 d

τ τ

5 1.2, 2, d a V a = M (1.2.1), M, a,,,,, Ω, V a V, V a = V + Ω r. (1.2.2), r i 1, i 2, i 3, i 1, i 2, i 3, A 2, A = 3 A n i n = n=1 da = 3 = n=1 3 n=1

untitled

P F ext 1: F ext P F ext (Count Rumford, ) H 2 O H 2 O 2 F ext F ext N 2 O 2 2

<4D F736F F D E AC28BAB82CC8CBB8BB CE394BC816A81698ECA905E82C882B5816A>

09_organal2

() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)

振動と波動

grad φ(p ) φ P grad φ(p ) p P p φ P p l t φ l t = 0 g (0) g (0) (31) grad φ(p ) p grad φ φ (P, φ(p )) xy (x, y) = (ξ(t), η(t)) ( )

c y /2 ddy = = 2π sin θ /2 dθd /2 [ ] 2π cos θ d = log 2 + a 2 d = log 2 + a 2 = log 2 + a a 2 d d + 2 = l

放射線専門医認定試験(2009・20回)/HOHS‐05(基礎二次)

プログラム


70 : 20 : A B (20 ) (30 ) 50 1

36 3 D f(z) D z f(z) z Taylor z D C f(z) z C C f (z) C f(z) f (z) f(z) D C D D z C C 3.: f(z) 3. f (z) f 2 (z) D D D D D f (z) f 2 (z) D D f (z) f 2 (

第3章

Gauss Gauss ɛ 0 E ds = Q (1) xy σ (x, y, z) (2) a ρ(x, y, z) = x 2 + y 2 (r, θ, φ) (1) xy A Gauss ɛ 0 E ds = ɛ 0 EA Q = ρa ɛ 0 EA = ρea E = (ρ/ɛ 0 )e

Taro13-第2章まとめ(最終).PDF

Erased_PDF.pdf

ω 0 m(ẍ + γẋ + ω0x) 2 = ee (2.118) e iωt x = e 1 m ω0 2 E(ω). (2.119) ω2 iωγ Z N P(ω) = χ(ω)e = exzn (2.120) ϵ = ϵ 0 (1 + χ) ϵ(ω) ϵ 0 = 1 +


Z: Q: R: C: 3. Green Cauchy

液晶の物理1:連続体理論(弾性,粘性)

(1) θ a = 5(cm) θ c = 4(cm) b = 3(cm) (2) ABC A A BC AD 10cm BC B D C 99 (1) A B 10m O AOB 37 sin 37 = cos 37 = tan 37

I 1

I ( ) 2019

sec13.dvi

untitled

4. ϵ(ν, T ) = c 4 u(ν, T ) ϵ(ν, T ) T ν π4 Planck dx = 0 e x 1 15 U(T ) x 3 U(T ) = σt 4 Stefan-Boltzmann σ 2π5 k 4 15c 2 h 3 = W m 2 K 4 5.

PDF

(3) (2),,. ( 20) ( s200103) 0.7 x C,, x 2 + y 2 + ax = 0 a.. D,. D, y C, C (x, y) (y 0) C m. (2) D y = y(x) (x ± y 0), (x, y) D, m, m = 1., D. (x 2 y

untitled

m(ẍ + γẋ + ω 0 x) = ee (2.118) e iωt P(ω) = χ(ω)e = ex = e2 E(ω) m ω0 2 ω2 iωγ (2.119) Z N ϵ(ω) ϵ 0 = 1 + Ne2 m j f j ω 2 j ω2 iωγ j (2.120)


W u = u(x, t) u tt = a 2 u xx, a > 0 (1) D := {(x, t) : 0 x l, t 0} u (0, t) = 0, u (l, t) = 0, t 0 (2)

1 1 sin cos P (primary) S (secondly) 2 P S A sin(ω2πt + α) A ω 1 ω α V T m T m 1 100Hz m 2 36km 500Hz. 36km 1

untitled

2011de.dvi

V(x) m e V 0 cos x π x π V(x) = x < π, x > π V 0 (i) x = 0 (V(x) V 0 (1 x 2 /2)) n n d 2 f dξ 2ξ d f 2 dξ + 2n f = 0 H n (ξ) (ii) H

The Physics of Atmospheres CAPTER :

% %

05Mar2001_tune.dvi

2 Chapter 4 (f4a). 2. (f4cone) ( θ) () g M. 2. (f4b) T M L P a θ (f4eki) ρ H A a g. v ( ) 2. H(t) ( )

II No.01 [n/2] [1]H n (x) H n (x) = ( 1) r n! r!(n 2r)! (2x)n 2r. r=0 [2]H n (x) n,, H n ( x) = ( 1) n H n (x). [3] H n (x) = ( 1) n dn x2 e dx n e x2

, 3, 6 = 3, 3,,,, 3,, 9, 3, 9, 3, 3, 4, 43, 4, 3, 9, 6, 6,, 0 p, p, p 3,..., p n N = p p p 3 p n + N p n N p p p, p 3,..., p n p, p,..., p n N, 3,,,,

s = 1.15 (s = 1.07), R = 0.786, R = 0.679, DW =.03 5 Y = 0.3 (0.095) (.708) X, R = 0.786, R = 0.679, s = 1.07, DW =.03, t û Y = 0.3 (3.163) + 0

TOP URL 1

Transcription:

- - 0.04ppm 0.1ppm 10ppm 0ppm 0.10mg/m 3 0.0 mg/m 3 0.06ppm 0.04ppm 0.06ppm 0.003 mg/m 3 0. mg/m 3 0. mg/m 3 0.15 mg/m 3 - -1

- 0.6pg-TEQ/m 3 53 3 1 0.10.ppm 0.0ppm 5 6 16 136 0.0ppm 7 15 7 31 0.04g-Hg/m 3 -- - 10 e :m 3 N : e:m -

- l l l -3

- - g/m N H10.6 H10.7 H1.4 0.04 0.08 0.08 0.15 0.15 0.5 1-4

50ppm 1 - - 5 1 1 1 0 1 m 3 / 7 3 kl/ 0.80 1.0 0 1 m 3 / 0 1 m 3 / 0.80 1.0 5 3 1 1 1 1 0 1 m 3 / 7 3 kl/ 7 3 kl/ -5

0.80 1.0 1 0.3 0.7 0 1 m 3 / 0 1 m 3 / 0 1 m 3 / 0.80 1.0 1 700mg m N 430ppm 1 - - H1.1.15 H1.1.15 1,000kg 5ng-TEQ/m 3 10ng-TEQ/m 3 1,000kg 4,000kg 1ng-TEQ/m 3 5ng-TEQ/m 3 1 4,000kg 0.1ng-TEQ/m 3 1ng-TEQ/m 3 00kg/h 1-6

10 /L - 6 ( 13 93 1 -: - -7

- - - -8

Q C = π (π /8)Rσ z U exp (z H e ) σ z + exp (z + H ) e σ z 106 C ppm mg/m 3 R m z m Qm 3 N/s kg/s Um/s H e m Q C = π 3/ γ 1 R + (α / γ ) (H e z) + 1 R + (α / γ ) (H e + z) 106 R m (CONCAWE )(Briggs ) He = H0 + H Hem H0m Hm H=0.175 Q H 1/ U -3/4 Q H cal/s U m/s Q H = Q C p T 0=1.9310 3 g/m 3 Q m 3 N/s C p =0.4cal/K g T15 θ ( ) 1 3 8 4 H = 14. Q d H dz QH cal / s dθ / m dz dθ = dt + Γd dz dz dt / m dz Γd = 0. 0098 / m -9

1 Q C = πσ y σ z U exp y σ y exp (z H e ) σ z + exp (z + H e) σ z 106 C ppm mg/m 3 x m y X m z m Qm 3 N/s kg/s Um/s ) H e m y m z m 3 1 60 t t 60 1/5 r t σ y = σ yp t p t min t p = 3 min σ y tm σ yp m r1 51 ( z He + nl) ( z + He + nl) Q 3 = C = exp + exp π u σ y σz n 3 σ σ Q C = /3 π σ y σz ( z He + nl) ( z + He + nl) 3 = exp + exp n 3 σ σ n 3-10

Q C = π σ yf u Lf yf yfyc0.47he f f 1.1(He+0.5zc) yczc L H x = u ρa Cp f 0 4κ x u a p f 0 / g/ 3 cal/kg cal/mks /1.5.5 m m/s m/s m -11

Ministry of Economy, Trade and Industry-Low rise Industrial Source dispersion MODEL ; METI-LIS -1

- C( x, y, z) = Q y exp exp u σ y σ z σ y + exp ( z + H) ( z H) σ z σ z π l Q t = V w 1 3600 1 1000 ( N E ) i= 1 it i Q t : (m1/ms( mg/ms)) E i : (g/km) -15 N it : ( /h) V w : (m1/g( mg/g)) 01 53ml/g -13

1000mg/g g mg 0. 83 σ z = σ Z 0 + 0. 31 L 0.81 σ y = W + 0.46 L / σ W / C ( x, y, z) l = Q l m 1 exp 1 exp t0 + t0 ( π ) 3 / α γ l m 1 x + y + α ( z H) = γ 1 x + y ( z + H) m = + α γ y W t 0 = α -14

JEA Q C(x,z) = L (Usinθ ) A 0.5 x exp B zp s x W(x : y 1,y ) L S = α exp 0.89 U sinθ L G = γ exp.45 Usinθ W(x : y 1,y ) = 1 erf G y x erf G y 1 x ω erf (ω ) = π e η dη 0-15

Q C(y,z) = L (Ucosθ ) A 0.5 y + G z W(y : x L 1,x ) A = 3.9exp.8 Ucosθ L G 1 = γ exp 1.61 U cosθ y + G z y + G z W(y : x 1,x ) = erf G 1 erf G 1 x 1 x ϖ erf (ω ) = π e η dη 0 π A QL C( x, y) = W s ( x + Gz ) ( x : y, y ) 1 1 W ( x : y1, y ) = tan π A = 0.76 exp(.76l) s = 0.38 exp(1.9l) 5.5exp( 4.3L) G = 5.5exp( 77.6L) 1 y x + Gz L 0 L < 0 tan 1 x y 1 + Gz NO -16

-17

1/ 4 3 / 8 He Ho + 1.4 Q ( dθ / dz) = H 1/ 3/ 4 He = Ho + 0.175 Q H u Q 1930.4Qv(Tg-15)/3600cal/s HoQvTg (1) d /dz 0.01 u m/s (1/ αz) (1/ αz) αz He Xm = y z α + α αz Q / 3600 αy + αz 9 Cm = exp 10 ( αy+αz) π u γy γz Xm αz Cw = Cm Fw / 100-18

Q / 3600 1 9 C = 10 3 / (π) α γ R He + α γ Cc = C Fc / 100 Cn = Cw + Cc -19

-- METI-LIS METI-LIS - - (198) - () - (1959) -0

- METI-LIS 1,000 1,000 A 100 10 A B C D E F G 100 10 B C D E F G 1 100 1,000 10,000 100,000 1 100 1,000 10,000 100,000 - -1

- -

-3

1 0.0ppm 1 5ppm 1 0.04ppm 0.04ppm 0.06ppm 1 1 0.04ppm 1 0.10ppm 1 1 0.0ppm 0.015mg/m 3 1 1 0.075mg/m 3 1 1 0.04ppm 1 0.1ppm 1 1 0.04ppm 1 1 0.04ppm0.06ppm 1 0.10mg/m 3 1 0.0mg/m 3 1 1 10ppm 1 8 0ppm 1 0.06ppm 10t/km / 0t/km / 1 1 0.04ppm 1 0.10mg/m 3 1 0.0mg/m 3 1 0.06ppm 3 g/m 3 0.017ppm 0.00ppm -4

- 100 0.113-0.007 - - () () 0km/h 0.118.08 0.007 0.107 30 0.097 1.67 0.006 0.086 40 0.077 1.35 0.005 0.071 45 0.070 1.3 0.005 0.065 50 0.064 1.15 0.004 0.060 60 0.057 1.09 0.004 0.054 70 0.059 1.16 0.003 0.053 80 0.068 1.39 0.004 0.056 90 0.086 1.75 0.005 0.063 110 0.148-0.009 - ) -0.900.00578 0.0000439 0.61-7.1 0.0895 0.000735 3.93-0.1380.0004560.00000317 0.018 0.03180.00310 0.00007 0.158 g/km ( ) km/h 0 110km/h 0 90km/h -5