2 A B A B A A B Ea 1 51 Ea 1 A B A B B A B B A Ea 2 A B Ea 1 ( )k 1 Ea 1 Ea 2 Arrhenius 53 Ea R T k 1 = χe 1 Ea RT k 2 = χe 2 Ea RT 53 A B A B

Similar documents
36 th IChO : - 3 ( ) , G O O D L U C K final 1

03J_sources.key

(1) (2) (1) (2) 2 3 {a n } a 2 + a 4 + a a n S n S n = n = S n

2 Zn Zn + MnO 2 () 2 O 2 2 H2 O + O 2 O 2 MnO 2 2 KClO 3 2 KCl + 3 O 2 O 3 or 3 O 2 2 O 3 N 2 () NH 4 NO 2 2 O + N 2 ( ) MnO HCl Mn O + CaCl(ClO

H22環境地球化学4_化学平衡III_ ppt

IS(A3) 核データ表 ( 内部転換 オージェ電子 ) No.e1 By IsoShieldJP 番号 核種核種半減期エネルギー放出割合核種番号通番数値単位 (kev) (%) 核崩壊型 娘核種 MG H β-/ce K A

PowerPoint プレゼンテーション

物理化学I-第12回(13).ppt

untitled


さくらの個別指導 ( さくら教育研究所 ) A a 1 a 2 a 3 a n {a n } a 1 a n n n 1 n n 0 a n = 1 n 1 n n O n {a n } n a n α {a n } α {a

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0




F-08E

H1-H4

無印良品のスキンケア

untitled

春期講座 ~ 極限 1 1, 1 2, 1 3, 1 4,, 1 n, n n {a n } n a n α {a n } α {a n } α lim n an = α n a n α α {a n } {a n } {a n } 1. a n = 2 n {a n } 2, 4, 8, 16,


コロイド化学と界面化学

元素分析

食事編_表1_4_0508

Microsoft Word - 表紙資料2-4

London -van der Waals Coulomb Fe, Mn


PDF

46 4 E E E E E 0 0 E E = E E E = ) E =0 2) φ = 3) ρ =0 1) 0 2) E φ E = grad φ E =0 P P φ = E ds 0

1 発病のとき

yamato_2016_0915_色校_CS3.indd

さくらの個別指導 ( さくら教育研究所 ) 1 φ = φ 1 : φ [ ] a [ ] 1 a : b a b b(a + b) b a 2 a 2 = b(a + b). b 2 ( a b ) 2 = a b a/b X 2 X 1 = 0 a/b > 0 2 a

D = [a, b] [c, d] D ij P ij (ξ ij, η ij ) f S(f,, {P ij }) S(f,, {P ij }) = = k m i=1 j=1 m n f(ξ ij, η ij )(x i x i 1 )(y j y j 1 ) = i=1 j

FERRITES March 2014 Mn-Zn EPC

PROSTAGE[プロステージ]

加速度センサを用いた図形入力

II (Percolation) ( 3-4 ) 1. [ ],,,,,,,. 2. [ ],.. 3. [ ],. 4. [ ] [ ] G. Grimmett Percolation Springer-Verlag New-York [ ] 3

1 c H O. H C C O H. CH 3 COOH ( ). C 2 H 4 O 2. CH 2 O H [. CH2 CH 2 CH CH ]. CH 3 COOH 3 1 C H ( ) CH 3 CH 3 CH CH CH

宿泊産業活性化のための実証実験

P00(表紙)

PJZ012A081_A




RN201602_cs5_0122.indd

x, y x 3 y xy 3 x 2 y + xy 2 x 3 + y 3 = x 3 y xy 3 x 2 y + xy 2 x 3 + y 3 = 15 xy (x y) (x + y) xy (x y) (x y) ( x 2 + xy + y 2) = 15 (x y)

1/120 別表第 1(6 8 及び10 関係 ) 放射性物質の種類が明らかで かつ 一種類である場合の放射線業務従事者の呼吸する空気中の放射性物質の濃度限度等 添付 第一欄第二欄第三欄第四欄第五欄第六欄 放射性物質の種類 吸入摂取した 経口摂取した 放射線業 周辺監視 周辺監視 場合の実効線 場合

30


6 2 T γ T B (6.4) (6.1) [( d nm + 3 ] 2 nt B )a 3 + nt B da 3 = 0 (6.9) na 3 = T B V 3/2 = T B V γ 1 = const. or T B a 2 = const. (6.10) H 2 = 8π kc2

kcal/mol 83kcal/mol 2 63 kcal/mol 83 kcal/mol kcal/mol nm kcal/mol nm

m(ẍ + γẋ + ω 0 x) = ee (2.118) e iωt P(ω) = χ(ω)e = ex = e2 E(ω) m ω0 2 ω2 iωγ (2.119) Z N ϵ(ω) ϵ 0 = 1 + Ne2 m j f j ω 2 j ω2 iωγ j (2.120)


4 1 Ampère 4 2 Ampere 31

Part () () Γ Part ,

和RIM24_佐野氏.indd


名称未設定-2

CuSO POINT S 2 Ni Sn Hg Cu Ag Zn 2 Cu Cu Cu OH 2 Cu NH CuSO 4 5H 2O Ag Ag 2O Ag 2CrO4 Zn ZnS ZnO 2+ Fe Fe OH 2 Fe 3+ Fe OH 3 2 Cu Cu OH 2 Ag Ag

B [ 0.1 ] x > 0 x 6= 1 f(x) µ 1 1 xn 1 + sin sin x 1 x 1 f(x) := lim. n x n (1) lim inf f(x) (2) lim sup f(x) x 1 0 x 1 0 (

FORES II [フォレスII]

JAJP

ω 0 m(ẍ + γẋ + ω0x) 2 = ee (2.118) e iωt x = e 1 m ω0 2 E(ω). (2.119) ω2 iωγ Z N P(ω) = χ(ω)e = exzn (2.120) ϵ = ϵ 0 (1 + χ) ϵ(ω) ϵ 0 = 1 +

power.tex

L1-a.dvi

ii

さくらの個別指導 ( さくら教育研究所 ) A 2 P Q 3 R S T R S T P Q ( ) ( ) m n m n m n n n

微粒子合成化学・講義

微粒子合成化学・講義

II No.01 [n/2] [1]H n (x) H n (x) = ( 1) r n! r!(n 2r)! (2x)n 2r. r=0 [2]H n (x) n,, H n ( x) = ( 1) n H n (x). [3] H n (x) = ( 1) n dn x2 e dx n e x2

: Napoleon IOC : IOC? I = Imaginative O = Obsession C = Committee


nm (T = K, p = kP a (1atm( )), 1bar = 10 5 P a = atm) 1 ( ) m / m

[ ] 0.1 lim x 0 e 3x 1 x IC ( 11) ( s114901) 0.2 (1) y = e 2x (x 2 + 1) (2) y = x/(x 2 + 1) 0.3 dx (1) 1 4x 2 (2) e x sin 2xdx (3) sin 2 xdx ( 11) ( s

C el = 3 2 Nk B (2.14) c el = 3k B C el = 3 2 Nk B

3章 問題・略解

koji07-01.dvi

1 1 H Li Be Na M g B A l C S i N P O S F He N Cl A e K Ca S c T i V C Mn Fe Co Ni Cu Zn Ga Ge As Se B K Rb S Y Z Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb T e

4‐E ) キュリー温度を利用した消磁:熱消磁

Microsoft Word - 章末問題

23 1 Section ( ) ( ) ( 46 ) , 238( 235,238 U) 232( 232 Th) 40( 40 K, % ) (Rn) (Ra). 7( 7 Be) 14( 14 C) 22( 22 Na) (1 ) (2 ) 1 µ 2 4

() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)

高校生の就職への数学II

, 1 ( f n (x))dx d dx ( f n (x)) 1 f n (x)dx d dx f n(x) lim f n (x) = [, 1] x f n (x) = n x x 1 f n (x) = x f n (x) = x 1 x n n f n(x) = [, 1] f n (x

x = a 1 f (a r, a + r) f(a) r a f f(a) 2 2. (a, b) 2 f (a, b) r f(a, b) r (a, b) f f(a, b)



P KK-KKH.indd

CRA3689A

Microsoft Word - 00”ŒŁ\”ƒf.doc

42 3 u = (37) MeV/c 2 (3.4) [1] u amu m p m n [1] m H [2] m p = (4) MeV/c 2 = (13) u m n = (4) MeV/c 2 =

案内最終.indd


* n x 11,, x 1n N(µ 1, σ 2 ) x 21,, x 2n N(µ 2, σ 2 ) H 0 µ 1 = µ 2 (= µ ) H 1 µ 1 µ 2 H 0, H 1 *2 σ 2 σ 2 0, σ 2 1 *1 *2 H 0 H

(1) 3 A B E e AE = e AB OE = OA + e AB = (1 35 e ) e OE z 1 1 e E xy e = 0 e = 5 OE = ( 2 0 0) E ( 2 0 0) (2) 3 E P Q k EQ = k EP E y 0

newmain.dvi

2001 Mg-Zn-Y LPSO(Long Period Stacking Order) Mg,,,. LPSO ( ), Mg, Zn,Y. Mg Zn, Y fcc( ) L1 2. LPSO Mg,., Mg L1 2, Zn,Y,, Y.,, Zn, Y Mg. Zn,Y., 926, 1

00) î âûë¨ìx.pdf



Transcription:

5. A B B A B A B B A A B A B 2 A [A] B [B] 51 v = k[a][b] 51 A B 3 0 273.16 A B A B A B A A [A] 52 v= k[a] 52 A B 55

2 A B A B A A B Ea 1 51 Ea 1 A B A B B A B B A Ea 2 A B Ea 1 ( )k 1 Ea 1 Ea 2 Arrhenius 53 Ea 2 2 53 R T k 1 = χe 1 Ea RT k 2 = χe 2 Ea RT 53 A B A B A 53 52 A B 56

A B G 43 S 54 K 53 54 55 G = Ea 2 Ea 1 = TS Ea Ea RT G RT T S RT k2 K = = χe = χe = χe = χe k 1 2 1 54 S RT R 55 57

1 27 A B 53 G0 1kcal/mol 3:1 3kcal/mol 99.4 55 T 3 3 4 van der Waals 58

51 20 1 0.17 e 0.15 N 3 526000.00 Ne 0.98 3 2 119.31 N 2 2.37 2 4 15.36 2 4.47 S 3846.00 Ar 6.39 2 168.06 N 2 117.11 S 2 112800.00 51 Kr 28.80 Xe 72.97 59

2 3 2 1 3 3 l Br N 3 N 3 2 3 P 4 2 S 2 S 4 2 Na 36 47.5 88 63.5 37 21.5 9.6 7.7 15.8 19.8 K 34 65.2 31.6 112 71.5 52.5 24.9 159 107 Mg 2 54.5 96.5 42.1 26.2 a 2 74.5 143 56.39 0.17 4x10 3 0.17 2x10 2 0.208 Ba 2 35.7 104 9.2 3.89 2x10 3 2x10 2 Al 3 47.3 73 9x10 4 26.7 Fe 2 37.6 53.5 45.6 7x10 6 7x10 5 26.5 Fe 3 91.9 46.6 o 2 34.6 50 3x10 4 4x10 3 4x10 4 26.5 Ni 2 39.6 56.7 48.5 1x10 3 9x10 3 37.8 u 2 41.5 55.9 55.58 3x10 5 3x10 5 20.7 Zn 2 367 81.7 117.5 4x10 4 5x10-5 53.8 60

52 K Na Mg a Ba Fe Al 51 2.59 4.8 8.02 12.9 19.11 28.7 6.9 9.6 12.7 16.4 109 129 174 35.7 36 36.6 37.3 38.4 39.8 27.6 34 40 45.5 51.1 56.7 29.4 37.2 45.8 55.2 65.6 77.3 52.8 54.5 57.5 61 66 73 74.4 91.9 14.3 20.7 28.5 40 55 75.4 3 6 13.6 35.3 154 2.75 3.4 0.17 0.29 0.56 1.16 2.8 6.46 2.8 6.9 16.2 35.8 70.8 122.9 141.8 225.2 331.6 452.6 671.7 3.41 7.17 15.08 31.69 140 9.2 22.6 43.3 78.3 125 185 61

55 S T 53 0 100 2 100 20 Brønsted A A B B 54 1s 1s 2 A A B B 2 Lewis 2 62

A A A B A B 52 51 56 0 56 57 v=-k a [A]k b [ ][A - ] K A = k a = [ ][A - ] k b [A] [A] [ ]=K A [A - ] pk a =-log(k A ) 56 57 58 59 K A 55 57 58 59 pka 54 pka pka 5.20 4.75 0.3 pka B B 56 510 63

54 pka25 pka l l 7.00 S 4 S 4 5.20 N 3 N 3 1.40 S 4 S 4 2 1.92 3 P 4 P 4 2.12 3.75 6 5 6 5 4.19 3 3 4.75 3 3 6.37 S S 7.04 P 4 P 4 2 7.21 N N 9.10 3 B 3 B 3 9.14 6 5 6 5 9.89 3 3 2 10.25 S S 2 11.96 P 4 2 P 4 3 12.67 B 3 B 3 2 12.74 B 3 2 B 3 3 13.80 3 3 15.00 15.70 3 3 3 20.00 N 3 N 36.00 6 6 6 5 43.00 0 510 511 511 57 512 pka 55 pka 64

55 pka25 pka 4 6 N 4 5 N 2.9 3 1.7 NN 3 3 N 3 ( ) 2 ()N 3 5 6 N 4 2 3 ()N 3 5 4 N 4 N 3 2 NN 0.1 3 N 0.63 ( ) 2 ( )N 3 5 5 N 4 3 ( )N 3 5 3 N 4 N 3 ( ) 2 ( )N 3 ( ) 2 ( )N 3 6 5 N 3 3 N ( ) 4 ()N 3 510 511 512 pka 9.25 4.63 pka 2.13 2.3 2.35 4.12 4.31 6 5 N 4.63 N( ) 4 ( )N 3 5 6 N 5 5 N 5.25 3 5 N 2 5 5 N 4 N 4 5.05 3 4 N 2 6.95 5 4 N 4 8.96 N 3 9.25 ( 3 ) 3 N ( 3 ) 3 N 9.81 5 3 N 4 N 3 N( ) 4 ( )N 3 3 N 3 ( 3 ) 2 N 5 3 N 4 N 9.83 N( ) 4 ( )N 10.53 3 N 10.66 ( 3 ) 2 N 10.73 3 4 N 2 3 4 N 2 14.3 v=-k b [ ][B]k a [B ] K B = k a = [ ][B] k b [B ] [ [B ]=K ] B [B] 65

Brønsted A A B B (A) (B) B A 58 512 513 [B ][A - ] K = A [B][A] KB 513 55 pka 7.00 9.25 513 10 16.25 R R N X N X pka R=: X=l: R= 4.75 4.63 6 5 : X= 3 : 10 0.08 pka 15.7 56 pka 1.7 3 pk a :-1.7 514 2 pk a :15.7 66

N 4 pka 515 pka 3 516 2 A A K A B B K B 55 [ ][N 3 ] KN 4 10 = = -9.25 10-15.70 = 10 6.45 [ - ][N 4 ] K [ ][S - 4 ] K S 4 10 = = 5.20 10-15.70 = 10 20.90 [ - ][ S 4 ] K [ ][ S 4 ] K 3 [ 3 ][S - = = = 10-3.50 4 ] K 101.70 S 4 10 5.20 514 515 516 2 3 67

57 3 13 10 27 1 ( ) n ( ) n ( ) n 3 3 3 n=1216 3 3 3 3 3 2 3 2 2 2 3 2 3 3 3 68

2 2 2 2 2 69

2 58 2 16 18 5 17 15 17 70

m n n m n m Na m n n=15or17,m=31or33or35 Brønsted 2 pka pka pka pka<1 pka pka pka 56 56 pka 8 pka 4.9 pka pka p 518 pka 56 Na 3 71

1 p = pka 2 ( log 14) 3.75 Na 8.4 4.76 3 Na 8.9 4.87 3 Na 8.9 4.83 3 ( ) 2 Na 8.9 4.84 3 ( ) 3 Na 8.9 4.86 3 ( ) 4 Na 8.9 4.89 3 ( ) 5 Na 8.9 4.89 3 ( ) 6 Na 8.9 4.95 3 ( ) 7 Na 9.0 4.90 3 ( ) 8 Na 9.0 4.21 6 5 Na 8.6 9.99 6 5 Na 11.5 10.26 3 6 4 Na 11.6 0.70 6 5 S 3 Na 7.0 15.74 Na 13.0 15.54 3 Na 13.0 16.00 3 Na 13.0 14.16 Na 13.6 10.50 3 SNa 11.8 10.66 3 ( ) 3 SNa 11.8 7.80 6 5 SNa 10.4 72

R 1 R S 5 S R S S R 2 3 R 4 2 S R R R P 6 2 7 3 3 3 3 3 3 R N R R N R R N 3 N 2 9 10 2 11 2 12 8 R R R 13 14 15 16 R 17 18 19 R R R N 73

3 59 R 1218 pka0.70-3.00 Ka2.12 594 510 597 12 4 S 3 12 5 12 5 S Al 2 3 S 4 Na 12 5 4 4 S Na 74

5 911 12 1 1 511 n 5914 Ag 2 R Na R 13 Na R R 15 75

1950 PET (B) (A) 76

55 2 512 van t off A B 519 V b T R ΠV = n b RT 519 c b ρ b M b 520 Π = c b RT ρbrt = M b 520 2 512 3.6 77