Chap10.dvi

Similar documents
( ) sin 1 x, cos 1 x, tan 1 x sin x, cos x, tan x, arcsin x, arccos x, arctan x. π 2 sin 1 x π 2, 0 cos 1 x π, π 2 < tan 1 x < π 2 1 (1) (

, x R, f (x),, df dx : R R,, f : R R, f(x) ( ).,, f (a) d f dx (a), f (a) d3 f dx 3 (a),, f (n) (a) dn f dx n (a), f d f dx, f d3 f dx 3,, f (n) dn f

高等学校学習指導要領

高等学校学習指導要領

.5 z = a + b + c n.6 = a sin t y = b cos t dy d a e e b e + e c e e e + e 3 s36 3 a + y = a, b > b 3 s363.7 y = + 3 y = + 3 s364.8 cos a 3 s365.9 y =,

[ ] 0.1 lim x 0 e 3x 1 x IC ( 11) ( s114901) 0.2 (1) y = e 2x (x 2 + 1) (2) y = x/(x 2 + 1) 0.3 dx (1) 1 4x 2 (2) e x sin 2xdx (3) sin 2 xdx ( 11) ( s

() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)

1 2 1 No p. 111 p , 4, 2, f (x, y) = x2 y x 4 + y. 2 (1) y = mx (x, y) (0, 0) f (x, y). m. (2) y = ax 2 (x, y) (0, 0) f (x,

18 ( ) I II III A B C(100 ) 1, 2, 3, 5 I II A B (100 ) 1, 2, 3 I II A B (80 ) 6 8 I II III A B C(80 ) 1 n (1 + x) n (1) n C 1 + n C

x () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x

Chap9.dvi

(1) (2) (3) (4) HB B ( ) (5) (6) (7) 40 (8) (9) (10)

2009 I 2 II III 14, 15, α β α β l 0 l l l l γ (1) γ = αβ (2) α β n n cos 2k n n π sin 2k n π k=1 k=1 3. a 0, a 1,..., a n α a

i


Wide Scanner TWAIN Source ユーザーズガイド

di-problem.dvi

( ) 2.1. C. (1) x 4 dx = 1 5 x5 + C 1 (2) x dx = x 2 dx = x 1 + C = 1 2 x + C xdx (3) = x dx = 3 x C (4) (x + 1) 3 dx = (x 3 + 3x 2 + 3x +

4 4 4 a b c d a b A c d A a da ad bce O E O n A n O ad bc a d n A n O 5 {a n } S n a k n a n + k S n a a n+ S n n S n n log x x {xy } x, y x + y 7 fx

2.2 h h l L h L = l cot h (1) (1) L l L l l = L tan h (2) (2) L l 2 l 3 h 2.3 a h a h (a, h)

= M + M + M + M M + =.,. f = < ρ, > ρ ρ. ρ f. = ρ = = ± = log 4 = = = ± f = k k ρ. k

A (1) = 4 A( 1, 4) 1 A 4 () = tan A(0, 0) π A π


「産業上利用することができる発明」の審査の運用指針(案)

高等学校学習指導要領解説 数学編

III No (i) (ii) (iii) (iv) (v) (vi) x 2 3xy + 2 lim. (x,y) (1,0) x 2 + y 2 lim (x,y) (0,0) lim (x,y) (0,0) lim (x,y) (0,0) 5x 2 y x 2 + y 2. xy x2 + y




I, II 1, 2 ɛ-δ 100 A = A 4 : 6 = max{ A, } A A 10


.3. (x, x = (, u = = 4 (, x x = 4 x, x 0 x = 0 x = 4 x.4. ( z + z = 8 z, z 0 (z, z = (0, 8, (,, (8, 0 3 (0, 8, (,, (8, 0 z = z 4 z (g f(x = g(

. p.1/15

A A p.1/16

a n a n ( ) (1) a m a n = a m+n (2) (a m ) n = a mn (3) (ab) n = a n b n (4) a m a n = a m n ( m > n ) m n 4 ( ) 552

D xy D (x, y) z = f(x, y) f D (2 ) (x, y, z) f R z = 1 x 2 y 2 {(x, y); x 2 +y 2 1} x 2 +y 2 +z 2 = 1 1 z (x, y) R 2 z = x 2 y

grad φ(p ) φ P grad φ(p ) p P p φ P p l t φ l t = 0 g (0) g (0) (31) grad φ(p ) p grad φ φ (P, φ(p )) xy (x, y) = (ξ(t), η(t)) ( )

1 8, : 8.1 1, 2 z = ax + by + c ax by + z c = a b +1 x y z c = 0, (0, 0, c), n = ( a, b, 1). f = n i=1 a ii x 2 i + i<j 2a ij x i x j = ( x, A x), f =

2009 IA 5 I 22, 23, 24, 25, 26, (1) Arcsin 1 ( 2 (4) Arccos 1 ) 2 3 (2) Arcsin( 1) (3) Arccos 2 (5) Arctan 1 (6) Arctan ( 3 ) 3 2. n (1) ta

c y /2 ddy = = 2π sin θ /2 dθd /2 [ ] 2π cos θ d = log 2 + a 2 d = log 2 + a 2 = log 2 + a a 2 d d + 2 = l

S I. dy fx x fx y fx + C 3 C vt dy fx 4 x, y dy yt gt + Ct + C dt v e kt xt v e kt + C k x v k + C C xt v k 3 r r + dr e kt S Sr πr dt d v } dt k e kt

function2.pdf

178 5 I 1 ( ) ( ) ( ) ( ) (1) ( 2 )

I No. sin cos sine, cosine : trigonometric function π : π =.4 : n =, ±, ±, sin + nπ = sin cos + nπ = cos sin = sin : cos = cos :. sin. sin. sin + π si

44 4 I (1) ( ) (10 15 ) ( 17 ) ( 3 1 ) (2)

生活設計レジメ

I II III 28 29


29


sin cos No. sine, cosine : trigonometric function π : π = 3.4 : n = 0, ±, ±, sin + nπ = sin cos + nπ = cos : parity sin = sin : odd cos = cos : even.

(1) 3 A B E e AE = e AB OE = OA + e AB = (1 35 e ) e OE z 1 1 e E xy e = 0 e = 5 OE = ( 2 0 0) E ( 2 0 0) (2) 3 E P Q k EQ = k EP E y 0

I No. sin cos sine, cosine : trigonometric function π : π =.4 : n = 0, ±, ±, sin + nπ = sin cos + nπ = cos : parity sin = sin : odd cos = cos : even.

1 1 x y = y(x) y, y,..., y (n) : n y F (x, y, y,..., y (n) ) = 0 n F (x, y, y ) = 0 1 y(x) y y = G(x, y) y, y y + p(x)y = q(x) 1 p(x) q(

高校生の就職への数学II

70 : 20 : A B (20 ) (30 ) 50 1

ad bc A A A = ad bc ( d ) b c a n A n A n A A det A A ( ) a b A = c d det A = ad bc σ {,,,, n} {,,, } {,,, } {,,, } ( ) σ = σ() = σ() = n sign σ sign(

.....Z...^.[ \..

入試の軌跡

さくらの個別指導 ( さくら教育研究所 ) A a 1 a 2 a 3 a n {a n } a 1 a n n n 1 n n 0 a n = 1 n 1 n n O n {a n } n a n α {a n } α {a

c 2009 i

ii

Z: Q: R: C: sin 6 5 ζ a, b

untitled

i

AccessflÌfl—−ÇŠš1

1 12 ( )150 ( ( ) ) x M x 0 1 M 2 5x 2 + 4x + 3 x 2 1 M x M 2 1 M x (x + 1) 2 (1) x 2 + x + 1 M (2) 1 3 M (3) x 4 +

6. Euler x

1 I 1.1 ± e = = - = C C MKSA [m], [Kg] [s] [A] 1C 1A 1 MKSA 1C 1C +q q +q q 1

no35.dvi

2

S I. dy fx x fx y fx + C 3 C dy fx 4 x, y dy v C xt y C v e kt k > xt yt gt [ v dt dt v e kt xt v e kt + C k x v + C C k xt v k 3 r r + dr e kt S dt d

18 ( ) ( ) [ ] [ ) II III A B (120 ) 1, 2, 3, 5, 6 II III A B (120 ) ( ) 1, 2, 3, 7, 8 II III A B (120 ) ( [ ]) 1, 2, 3, 5, 7 II III A B (

1

meiji_resume_1.PDF

II A A441 : October 02, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka )

1 1. x 1 (1) x 2 + 2x + 5 dx d dx (x2 + 2x + 5) = 2(x + 1) x 1 x 2 + 2x + 5 = x + 1 x 2 + 2x x 2 + 2x + 5 y = x 2 + 2x + 5 dy = 2(x + 1)dx x + 1

M41 JP Manual.indd


A(6, 13) B(1, 1) 65 y C 2 A(2, 1) B( 3, 2) C 66 x + 2y 1 = 0 2 A(1, 1) B(3, 0) P 67 3 A(3, 3) B(1, 2) C(4, 0) (1) ABC G (2) 3 A B C P 6

chap1.dvi

50 2 I SI MKSA r q r q F F = 1 qq 4πε 0 r r 2 r r r r (2.2 ε 0 = 1 c 2 µ 0 c = m/s q 2.1 r q' F r = 0 µ 0 = 4π 10 7 N/A 2 k = 1/(4πε 0 qq

1 29 ( ) I II III A B (120 ) 2 5 I II III A B (120 ) 1, 6 8 I II A B (120 ) 1, 6, 7 I II A B (100 ) 1 OAB A B OA = 2 OA OB = 3 OB A B 2 :

, 3, 6 = 3, 3,,,, 3,, 9, 3, 9, 3, 3, 4, 43, 4, 3, 9, 6, 6,, 0 p, p, p 3,..., p n N = p p p 3 p n + N p n N p p p, p 3,..., p n p, p,..., p n N, 3,,,,

さくらの個別指導 ( さくら教育研究所 ) a a n n A m n 1 a m a n = a m+n 2 (a m ) n = a mn 3 (ab) n = a n b n a n n = = 3 2, = 3 2+

i


(iii) 0 V, x V, x + 0 = x. 0. (iv) x V, y V, x + y = 0., y x, y = x. (v) 1x = x. (vii) (α + β)x = αx + βx. (viii) (αβ)x = α(βx)., V, C.,,., (1)

(ii) (iii) z a = z a =2 z a =6 sin z z a dz. cosh z z a dz. e z dz. (, a b > 6.) (z a)(z b) 52.. (a) dz, ( a = /6.), (b) z =6 az (c) z a =2 53. f n (z

86 7 I ( 13 ) II ( )

熊本県数学問題正解

Part () () Γ Part ,

2014 S hara/lectures/lectures-j.html r 1 S phone: ,

入門ガイド

DE-resume

17 ( ) II III A B C(100 ) 1, 2, 6, 7 II A B (100 ) 2, 5, 6 II A B (80 ) 8 10 I II III A B C(80 ) 1 a 1 = 1 2 a n+1 = a n + 2n + 1 (n = 1,

zz + 3i(z z) + 5 = 0 + i z + i = z 2i z z z y zz + 3i (z z) + 5 = 0 (z 3i) (z + 3i) = 9 5 = 4 z 3i = 2 (3i) zz i (z z) + 1 = a 2 {

i

DVIOUT

<4D F736F F F696E74202D C835B B E B8CDD8AB B83685D>

Transcription:

=0. f = 2 +3 { 2 +3 0 2 f = 1 =0 { sin 0 3 f = 1 =0 2 sin 1 0 4 f = 0 =0 { 1 0 5 f = 0 =0 f 3 2 lim = lim 0 0 0 =0 =0. f 0 = 0. 2 =0. 3 4 f 1 lim 0 0 = lim 0 sin 2 cos 1 = lim 0 2 sin = lim =0 0 2 =0. f 0 = 0. f 0 lim 0 0 1 = lim sin 0 sin1/ 0. =0. f 0 = 0. 5 =0. 1

=0. sin 1 0 f = 0 =0 1 + sin 1 0 2 f = 0 =0 3 f = 3 + 4 f 0 lim 0 0 1 = lim sin 0, =0. 2 =0. 3 f 0 lim = lim + 2 0 0 0 + 2 + 2, 0. =0, f 0 = 0.. 1+ + 2 2 logtan 1 3 arcsin 4 5 1 a 2 2 2 + a 2 arcsin a y = 1 + + 2 1/2 1+2 = 2 1+ + 2 2 y tan sec 2 = = tan tan = 2 sin 2 2

3 y 1 1 = 1 2 1 = 1 2 2 1 4 y =, log y = log. y /y = log +1. y = ylog +1= log +1 5 y = 1 2 a 2 2 a2 + 1 1 2 a2 = a 1 /a 2 a 2 log + 2 1 2 log 3 cos + sin 2 4 e 1+2 5 arctansec + tan 1+ 2 1 + 2 1 = 1 2 1 2 y = log log y = log log. y /y = log log + 1/. y = log log log + 1 log log 3 y = 2cos + sin sin + cos 4 y = e 1+2 2 5 y 1 = 1 + sec + tan sec tan + 2 sec2 = 1 2 n, =0. e +1 2 cos 2 3 1 + 3 log1 + 3

y = e +1, y n = ee y = e + e + e2 2 + e3 6 + e4 24 + 2 y = cos 2 = 1 2 cos 2 + 1 2, yn =2 n 1 cos 2 + nπ 2 y =1+ 2 + 4 4 + 3 y =1+ 3 log1 +, y = 31 + 2 log1 + + 1 + 2, y = 61 + log1 + + 51 +, y = 6 log1 + + 11, y n = 6 1n n 4! 1 + n 3 n 4 y = + 52 2 + 113 6 + 4 4 + =0. arctan 2 sin 3 3 e sin y = arctan 1 + 2 y n+2 +2n +1y n+1 + nn +1y n =0. y0 = 0, y 0 = 1, y 0 = y 4 0 = 0, y 0 = 2. 2 y = sin 3 = 3 4 sin 1 sin 3. 4 y n = 3 4 sin + nπ 2 y = 3 3 3n 4 sin 3 + nπ 2 y = 3 + 4

3 y = e sin. y n =2 n/2 e sin + nπ 4 y = + 2 + 3 6 + R, φ = dist, Z T = n=0 φ10 n 10 n R,. R, 0 φ10 n 1 2 n=0 φ10 n 10 n R. φ φ10 n R., T R. φ φ10 n + 1 = φ10 n, T. 0 <1 T. [0, 1 =0.a 1 a 2 a n 0 a n 9 0.a 1 a 2 a n 99 0.a 1 a 2 a n + 100.. φ10 n = { 0.an+1 a n+2 a n+1 4 1 0.a n+1 a n+2 a n+1 5 { 10 m a m =4, 9 h m = 10 m a m 4, 9 + h m =0.a 1 a 2 a ma m+1, a m = 5 { am 1 a m =4, 9 a m +1 a m 4, 9

a m a m =10 m h m φ10 n + h m φ10 n 0 n m = 10 n m a m a m =10 n h m n < m, a n+1 4 10 n m a m a m= 10 n h m n < m, a n+1 5 m 1 T + h m T = ± 10n m 1 h m = ±1 h m 10 n h m n=0 m. m h m 0, m 1 ±1 T 0 <1. n=0 n=0 R f = b k cos a k π, a, b R, b < 1, ab < 1 k=0 R C 1. n b < 1 f n = b k cos a k π R f k=0. f R. n ab < 1 f n = πab k sin a k π R k=0 g = πab k sin a k π k=0. f =g f R C 1. f = 3 2 1 i vi. 6

i, f f. ii f =0, f. iii f =0, f. iv f. v f. vi f. i R \{ 1, 1}. f f f = 4 3 2 2 1 2, f = 23 +6 2 1 3 ii f =0 = 3, 0, 3. f 3 < 0 = 3 f 3 = 3 3 2 f 0 = 0, =0 f0 = 0 f 3 > 0 = 3 f 3 = 3 3 2 iii f iv < 1 f < 0 1 <<0 f > 0 0 <<1 f < 0 lim 1 0 lim 1 0 1 < f > 0 =0 f 0 = 0 3 2 1 3 =, lim 1+0 2 1 =, f = + 2 1, lim ± lim 1+0 y = f. 3 = =1, 2 1 3 = = 1, 2 1 =0 y =, 2 1 7

v f y y y vi f.., f, f = 2 e, R 2 f = log, 0, f 2 = e 2 f = 1 log,, >0 < arctan <. 1+2 f = arctan, f, > 0 1+2 f 2 2 = > 0. f0 = 0, f 1 + 2 2, >0 f > 0. g = arctan, g, >0 g = 2 > 0. g0 = 0, g, >0 1+2 g > 0. 0 <<π/2 2 π < sin. 8

f = sin 2 π, f, f cos sin = 2. g = cos sin g, 0<<π/2 g = sin <0. g0 = 0, g 0 <<π/2 g < 0. 0 <<π/2 fπ/2 = 0, f, f > 0. y 2 f = 0, 0. y 2 +y 2, y 0, 0 0, y =0, 0 2 fh, 0 f0, 0 0 0 f 0, 0 = lim = lim =0 h 0 h h 0 h f0,k f0, 0 0 0 f y 0, 0 = lim = lim =0 k 0 k k 0 k fh, 0 f0, 0 h f 0, 0 = lim = lim h 0 h h 0 h =0 f0,k f0, 0 f y 0, 0 = lim k 0 k k = lim k 0 k =0. sin y y sin 1, y 0, 0 2 f = 2 +y 2 0, y =0, 0 9

2 f 0, 0 = lim h 0 fh, 0 f0, 0 h f y 0, 0 = lim k 0 f0,k f0, 0 k = lim h 0 sin h h =1 = lim k 0 sin k k = 1 f 0, 0 = lim h 0 fh, 0 f0, 0 h f y 0, 0 = 0. h 0 sin 1 = lim 0 h h 0 h =0. sin5 + e y 2 e 2 +y 2 logy y 3 arctan 4 y y f = 5 cos5 + e y, f y = e y cos5 + e y 2 f = 2 logy+ 1 e 2 +y 2 f y = 3 f = y 2 + y 2, f y = 2y logy+ 1 y 2 + y 2 e 2 +y 2 4 f = y y y + log y, f y = y y y + log. a + by c + dy 2 log y 3 e a sin by + cos by 10

4 arcsin log y ad bc f = c + dy, f ad bcy 2 = c + dy 2 2 f = 1 log y, f y = log ylog y 2 3 f = ae a sin by + cos by, f y = be cos by sin by log y 4 f = 1 log y, f 2 y = y 1 log y 2. e log1 + y 2 1 2 y 2 f0, 0 = 0, f 0, 0 = 0, f y 0, 0 = 1, f 0, 0 = 0, f y 0, 0 = 1, f yy 0, 0 = 1 e log1 + y =y + 1 2 2y y2 + 2 f0, 0 = 1, f 0, 0 = 0, f y 0, 0 = 0, f 0, 0 = 1, f y 0, 0 = 0, f yy 0, 0 = 1 1 2 y 2 =1 1 2 2 + y 2 +. e a cos by 2 + 1 sin y f0, 0 = 1, f 0, 0 = a, f y 0, 0 = 0, f 0, 0 = a 2, f y 0, 0 = 11

0, f yy 0, 0 = b 2 e a cos by =1+ 1 2 a2 2 b 2 y 2 2 f0, 0 = 0, f 0, 0 = 0, f y 0, 0 = 1, f 0, 0 = 0, f y 0, 0 = 1/2, f yy 0, 0 = 0 + 1 sin y = y + 1 2 y R 2 f, y = 4 + y 4 2 2 +4y 2y 2. f f, y =43 + y, f y f y, y =4y3 y +, f = f y =0, y = 2, 2,, y = 2, 2,, y =0, 0. f 2 f 2, y = 432 1, f yy 2 f y 2, y = 43y2 1 f y 2 f, y =4, y f f, y Hf, y f f y f y f yy = y 2 f, y =4 y 43 2 1 4 4 43y 2 1. 2, 2, 2, 2, 0, 0 f 12

2, 2, 2, 2 det Hf 2, 2 = 384 > 0, f 2, 2 = 20 > 0 det Hf 2, 2 = 384 > 0, f 2, 2 = 20 > 0 det Hf0, 0 = 0. f, y ± 2, 2, f± 2, 2 = 8. f0, 0 = 0 = y 0 f, =2 4 > 0 =0, 0 y < 2 f0, y=y 2 y 2 2 < 0. 0, 0 f, y f0, 0 = 0 f0, 0 = 0. R 2 f, y = 3 + y 3 2 + y y 2. f =3 2 2 + y, f y =3y 2 2y +, f = f y =0, y =0, 0,, y =. f, y Hf, y = 1 3, 1 3 6 2 1 1 6y 2 1 0, 0 3, 1 f 3 det Hf0, 0 = 3 > 0, f 0, 0 = 2 < 0 13

f0, 0 = 0. f det Hf 1 3, 1 = 1 < 0 3 1 3, 1 = 1 3 27. 2 2 +2y +3y 2 =1 2 0,y 0 2 + y 2,. F, y, λ = 2 + y 2 λ2 2 +2y +3y 2 1 F =2 λ4+2y, F y =2y λ2+6y, F λ = 2 2 +2y +3y 2 1, F = F y = F λ =0 0,y 0. F + yf y, F λ =0 2 0 + y2 0 = λ F = F y =0 λ 2 1 2 0 +y2 0 0 + y 0 =0 0 +3 1 2 0 +y2 0 y 0 =0. 0,y 0 0, 0 2 1 1 2 0 +y2 0 1 3 1 2 0 +y2 0. 1 2 0 + y0 2 2 1 1 3 =0 14

.. 5+ 5 2 0 + y0 2 = 10 4l,., y, z +y +z = l, S =2y+yz+z. F, y, z, λ=2y + yz + z λ + y + z l, F = F y = F z = F λ =0 λ = 4 l. 3 = y = z = l 3.. 15