国土技術政策総合研究所 研究資料
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1 ISSN TECHNICAL NOTE of National Institut for Land and Infrastructur Managmnt No. Marc 006 Rsarc on Groundwatr Modl Rport Rivr Dpartmnt National Institut for Land and Infrastructur Managmnt Ministry of Land, Infrastructur and Transport, Japan
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3 Tcnical Not of NILIM No. Marc 006 Rsarc on Groundwatr Modl Rport Nario Yasuda* Masaki Kawasaki** Masaiko Muras*** Yosuk Tomizawa**** Masazumi Amakata***** Synopsis Tis rport mad up contnts of rsarc on t groundwatr modl. Ky Words groundwatr, groundwatr managmnt, data bas, watr circulation ******* ******* ******* ******* ******* Had, Watr Managmnt and Dam Division, Rivr Dpartmnt, NILIM Snior Rsarcr, Watr Managmnt and Dam Division, Rivr Dpartmnt, NILIM Cif, Planning Division, Planning and Rsarc Administration Dpartmnt, NILIM Rsarcr, Watr Managmnt and Dam Division, Rivr Dpartmnt, NILIM Gust Rsarc Enginr, Watr Managmnt and Dam Division, Rivr Dpartmnt, NILIM
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11 DATA(.ctl) DSET rain.dat TITLE Rain Data St UNDEF XDEF 00 LINEAR YDEF LINEAR ZDEF LINEAR TDEF LINEAR JAN000DY VARS Data Points ENDVARS + DATA(:rain.dat) X,Y,Z,Tim,RainData
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23 SHER
24 ds dt imp = P D imp E imp
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26 ds dt ds dt U E = s D s = P E R I U s + P a ds dt g = R D g P a
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28 T + T K T R = 0 k r ( θ ) dt K 0 k r T + T K I kr( T I = 0 θ ) sdt K0I kr
29 k r kr k ( θ ) θ θ r = θ 0 θ r k K 0k r ( θ ) n = k K 0I k r ( θ ) = K 0 K 0I θ θ 0 θ r
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32 K i ij j q = S S t
33 i, j :,, K : ( L / T ) : ( L) S s : ( L ) Q : (/ T ) : ( L) t : ( T )
34 control volum v z + vz z z v y + v y y y v z v + v z y v y v z y yz v control volum v Istok v Taylor ρv +! ( ρv ) + ( ρv )( ) + ( ρv )( ) +!
35 ρv + ( ρv) sinksourc q ρv y z+ ρv z + ρv y y z ρv ρv + ρq y z = t ρv y ρvz y z+ ρvy + y z ρvz z y y + + z ( ρ S n) w y z Sw q q ρv ρv y ρvz ρq = ( ) y z t ρ Swn t ( ρ ) = 0 S w n ρv ρv y y ρv z z ρq = 0 Darcy Darcy v K v K v K =, y = y, z = z y z
36 v v v K K K K K K K K K y z y z y z y yy yz z zy zz = Ky=KyKyz=KzyKz=Kz v ( ) ρ ρ ρ ρ ρ ρ ρ ρ ρ ρ ρ K K y K z y K K y K z z K K y K z q t S n y z y yy yz z zy zz w = ( ρ ρ ρ K q t S n i ij j w = ) ), :, : (:,,,, z y j i = ρ ρ ρ K K K i ij j i ij ij i ij j = + ρ ρ K K i ij j i ij j = /t ( ) ( ) ( ) ( w w w w S t n t n S n t S n S t ) ρ ρ ρ ρ + + = ( ) n t
37 n z = t t ( ) ( z n ) = n σ α( ) ( σ : ) n = α t ( n) σ z t σ z t n = α t n ( n) Sw t ( ρ) z z p = t p t constant βρ = ρ p ρ p = ρβ t t ( n) α = n σ z
38 t ( S w ) Sw p = 0 t t = ρg t K i ij q = j p ρg = S S t t t [ α( n) + βn] = [ α( n) + βn] n t ( ) ( ) t, = H t, H b b Kij ni = V ( i, t) j
39 V n i i K c ( c : ( lakanc) ) = ( K : d : ) d K c ( H ) = 0 : [L] H : [L] K : [L/T] (, = ) = ( ) t 0 H0
40 K i ij j q = S ( ) ( ) t, = H t, b Kij ni = V ( i, t) j (, = ) = ( ) t 0 H0 S t yz = 0 Dupuit-Forcimr z
41 u w q s q s dz = k = k sin β k β β ds d sin β tan β = qs u w d d u = k d
42 K = ij q d 0 i j 0 K d ij i j i T ij T ij ( ) qd = Kij 0 ( ) Q j = S S d dz dt d SSdz dt d = qd S 0 0 = S d S t ( ) Q( ) = S( ) T + T y + T y y y + T yy Q = S y t K T
43 y S y N S = i= b S i Si S=s y =n or S=bSs q Q q Kij d ni = V ( i, t) 0 0 T ij j ( ) ni = j 0 V (, t) V Q Tij ( ) ni = Q( i, t) j i i T ij = S + Q j t
44 ( y) = α + β + γy, (, y ) = = α + β + γy (, y ) = = α + β + γy (, y ) = = α + β + γy α β, γ, α = y / D β = y / D y y y y
45 D / = γ = = F y y y D F C y y B y y A C y y B y y A C y y B y y A = = = = = = = = = ( ) ( ) ( ) ( ) ( ) D y C B A y C B A y C B A y /, = ( ) ( ) D C C C k y k v D B B B k k v f f y f f / / + + = = + + = = S S S Q Q Q W W W 0 = + + S S S Q Q Q S S S S S S S S S Q Q Q W Q Q Q W Q Q Q W = + = = + = = + =
46 S S S Q Q Q W W W ( ) m y y v v Q y S = ( ) m y y v v Q y S = ( ) m y y v v Q y S = ( ) ( ) ( [ ] ) ( ) ( ) ( [ ] ) ( ) ( ) ( [ ] C C B B C C B B C C B B D T W C C B B C C B B C C B B D T W C C B B C C B B C C B B D T W = = = ) ( ) ( ) D T C C B B E j i j i ij / + = = = j i ij i E W
47 i k y i y k ( i) k = n, (, i) i k W i W k k = n(, i) W k A, B, C i i i A i A k B i B k C i E ij C k = n(, i) l n(, i) k E ij E kl = ( k, l) A k = B k = C k = E kl = 0 W k = n l= E kl l Wk Q E ij = 0
48 Wk M = W k Q k ( ) = 0 k =,, LN M N = l= E kl l Q k = 0 N M l= = E kl l Q k = 0 ( k =, LN) N l= a kl. l Qk = 0 ( k =, LN) L,y,t N N N, T ij Q S i j t N ( ( y, t) ) L ( (, y, t) ) 0 L N WRM R L N ( (, y, t) ) W (, y) dr = 0 W W n n,,y n W W W N Galrkin
49 W = 0 dr W t S Q T n R N j N ij i W = 0 dr W t S QW W T R n N n n j N ij i N N = 0 j N i Tij = 0 i ij T dr T W dr W T dr W T R j N ij i n R n j N ij i R n j N ij i = Gauss dl n W T dr W T i L j N ij n R n j N ij i = = R L i n j N ij n j N ij dl n W T dr W T div Q n i ( )( ) = L R n R n N R j N ij i n i n j N ij dr W Q W dr t S dr T W dl n W T 0 N y N Q Q
50 [ ] = = i= N i n N y N n i N ij n dl Q W dl Q Q W dl n t T W L L L N 0 = = = = W dr t N S QW dr dl Q W dr N T W n R R M m m m n L i N i n R j M m m m ij i n R R ( ) ( ) ( ) ( ) ( ) ( ) = Elmnts Num R N R N dr y W t y L dr y W t y L.,,,,,, 0 = = = = n R R M m m m n L i N i n R j M m m m ij i n dr W t N S dr QW dl Q W dr N T W [ ] 0. = = = = = n R R M n m m n L i N i n R j M m m m ij i n Num Elmnts dr W t N S dr QW dl Q W dr N T W m [ ]{ } [ ] { } { } m m m nm m nm D Q dt d F A = +
51 [ Anm ] = [ Anm ] = Num. Elmnts = Num. Elmnts = R W i n T ij N m j dr { Q } = { Q } m = Num. Elmnts Num. Elmnts = m Wn N m = L i= { D } = { D } = m Num. Elmnts Num. Elmnts = R = QW m m dr [ Fnm ] = [ Fnm ] = Num. Elmnts Nujm. Elmnts = R = SN m W n dr Q i dl N WGalrkin T T T T = T l N l l T Q S S = S l N l l FNuman Lumpd Mass Mtod S
52 W=N NdR NNdR NNdR N dr b N z dr c N N dr bb N N z dr bc N z N j R i j R i i R i i R i i R i j i j R i j i j R i j = = = = = = = z dr cc i j R = 4 [ ] { } j i yy i j y j i y j i R j yy i j y i j y i j i ij c c T c b T b c T b b T dr y N T y W N T y W y N T W N T W A = = 4 [ ] = 4 b c b c b c b c b c b c b c b c b c T c b c b c b c b c b c b b c b c b c T c c c c c c c c c c c c c c c c c c T b b b b b b b b b b b b b b b b b b T A y y yy ij Ty=Ty [A] [ ] = 4 b c c b b c c b b c c b b c c b b c c b b c c b b c b c b c b c b c b c T c c c c c c c c c c c c c c c c c c T b b b b b b b b b b b b b b b b b b T A y yy ij
53 { Q } W N ( Q + Q ) j ( L( Q + Q ) = i j j yj dl = L j yj j { D } j = QWi dr R Q = [ F ] ij = SN jwi R dr = S lumpd matri [ ] F ij = 4 S = 4 S
54 d + } dt m [ Anm ]{ m} [ Fnm ] = { Q n } { D n d + } dt m [ A nm ]{ m} [ Fnm ] = { C n t = t k + k + [ F ] + ω[ A ] { } nm k + { } k k k k [ F ] ( ω )[ A ] { } + ( ω ){ C } + ω{ C } nm nm nm k + m m n n k+ k+ GWAP k+/ k+/ t t/ t = t k + [ ] / k + F + ω[ A ] / { } nm k + [ ] / k + / ( )[ ] / k k + F ω A { } + { C } nm nm nm k + m k+/ t k + / m k + / m k = k m k m = t + t k m t m k m k k k k ( k m m n )
55 k + / m k + m t = k k k ( + ) + m m k m = k m t k m k k k + k t k k m = m + ( k m m t )
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126 (8) (7) () () (4) () (5) (6) (7) (0) (5) (4) (6) () () () (0) (9) () () () () (9) () (8)
127 4,5 6 9 ()
128 () () () () () () () () () () () ()
129 E = 0.4D p 0 P t E p D0 Pt
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145 TECHNICAL NOTE of Marc TEL
1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2
2005 9/8-11 2 2.2 ( 2-5) γ ( ) γ cos θ 2πr πρhr 2 g h = 2γ cos θ ρgr (2.1) γ = ρgrh (2.2) 2 cos θ θ cos θ = 1 (2.2) γ = 1 ρgrh (2.) 2 2. p p ρgh p ( ) p p = p ρgh (2.) h p p = 2γ r 1 1 (Berry,1975) 2-6
応力とひずみ.ppt
in [email protected] 2 3 4 5 x 2 6 Continuum) 7 8 9 F F 10 F L L F L 1 L F L F L F 11 F L F F L F L L L 1 L 2 12 F L F! A A! S! = F S 13 F L L F F n = F " cos# F t = F " sin# S $ = S cos# S S
21 2 26 i 1 1 1.1............................ 1 1.2............................ 3 2 9 2.1................... 9 2.2.......... 9 2.3................... 11 2.4....................... 12 3 15 3.1..........
No δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i x j δx j (5) δs 2
No.2 1 2 2 δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i δx j (5) δs 2 = δx i δx i + 2 u i δx i δx j = δs 2 + 2s ij δx i δx j
変 位 変位とは 物体中のある点が変形後に 別の点に異動したときの位置の変化で あり ベクトル量である 変位には 物体の変形の他に剛体運動 剛体変位 が含まれている 剛体変位 P(x, y, z) 平行移動と回転 P! (x + u, y + v, z + w) Q(x + d x, y + dy,
変 位 変位とは 物体中のある点が変形後に 別の点に異動したときの位置の変化で あり ベクトル量である 変位には 物体の変形の他に剛体運動 剛体変位 が含まれている 剛体変位 P(x, y, z) 平行移動と回転 P! (x + u, y + v, z + w) Q(x + d x, y + dy, z + dz) Q! (x + d x + u + du, y + dy + v + dv, z +
Gmech08.dvi
51 5 5.1 5.1.1 P r P z θ P P P z e r e, z ) r, θ, ) 5.1 z r e θ,, z r, θ, = r sin θ cos = r sin θ sin 5.1) e θ e z = r cos θ r, θ, 5.1: 0 r
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液晶の物理1:連続体理論(弾性,粘性)
The Physics of Liquid Crystals P. G. de Gennes and J. Prost (Oxford University Press, 1993) Liquid crystals are beautiful and mysterious; I am fond of them for both reasons. My hope is that some readers
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LLG-R8.Nisus.pdf
d M d t = γ M H + α M d M d t M γ [ 1/ ( Oe sec) ] α γ γ = gµ B h g g µ B h / π γ g = γ = 1.76 10 [ 7 1/ ( Oe sec) ] α α = λ γ λ λ λ α γ α α H α = γ H ω ω H α α H K K H K / M 1 1 > 0 α 1 M > 0 γ α γ =
[Ver. 0.2] 1 2 3 4 5 6 7 1 1.1 1.2 1.3 1.4 1.5 1 1.1 1 1.2 1. (elasticity) 2. (plasticity) 3. (strength) 4. 5. (toughness) 6. 1 1.2 1. (elasticity) } 1 1.2 2. (plasticity), 1 1.2 3. (strength) a < b F
O1-1 O1-2 O1-3 O1-4 O1-5 O1-6
O1-1 O1-2 O1-3 O1-4 O1-5 O1-6 O1-7 O1-8 O1-9 O1-10 O1-11 O1-12 O1-13 O1-14 O1-15 O1-16 O1-17 O1-18 O1-19 O1-20 O1-21 O1-22 O1-23 O1-24 O1-25 O1-26 O1-27 O1-28 O1-29 O1-30 O1-31 O1-32 O1-33 O1-34 O1-35
II No.01 [n/2] [1]H n (x) H n (x) = ( 1) r n! r!(n 2r)! (2x)n 2r. r=0 [2]H n (x) n,, H n ( x) = ( 1) n H n (x). [3] H n (x) = ( 1) n dn x2 e dx n e x2
II No.1 [n/] [1]H n x) H n x) = 1) r n! r!n r)! x)n r r= []H n x) n,, H n x) = 1) n H n x) [3] H n x) = 1) n dn x e dx n e x [4] H n+1 x) = xh n x) nh n 1 x) ) d dx x H n x) = H n+1 x) d dx H nx) = nh
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[ ] 9 IC. dx = 3x 4y dt dy dt = x y u xt = expλt u yt λ u u t = u u u + u = xt yt 6 3. u = x, y, z = x + y + z u u 9 s9 grad u ux, y, z = c c : grad u = u x i + u y j + u k i, j, k z x, y, z grad u v =
v v = v 1 v 2 v 3 (1) R = (R ij ) (2) R (R 1 ) ij = R ji (3) 3 R ij R ik = δ jk (4) i=1 δ ij Kronecker δ ij = { 1 (i = j) 0 (i
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Gauss Gauss ɛ 0 E ds = Q (1) xy σ (x, y, z) (2) a ρ(x, y, z) = x 2 + y 2 (r, θ, φ) (1) xy A Gauss ɛ 0 E ds = ɛ 0 EA Q = ρa ɛ 0 EA = ρea E = (ρ/ɛ 0 )e
7 -a 7 -a February 4, 2007 1. 2. 3. 4. 1. 2. 3. 1 Gauss Gauss ɛ 0 E ds = Q (1) xy σ (x, y, z) (2) a ρ(x, y, z) = x 2 + y 2 (r, θ, φ) (1) xy A Gauss ɛ 0 E ds = ɛ 0 EA Q = ρa ɛ 0 EA = ρea E = (ρ/ɛ 0 )e z
k m m d2 x i dt 2 = f i = kx i (i = 1, 2, 3 or x, y, z) f i σ ij x i e ij = 2.1 Hooke s law and elastic constants (a) x i (2.1) k m σ A σ σ σ σ f i x
k m m d2 x i dt 2 = f i = kx i (i = 1, 2, 3 or x, y, z) f i ij x i e ij = 2.1 Hooke s law and elastic constants (a) x i (2.1) k m A f i x i B e e e e 0 e* e e (2.1) e (b) A e = 0 B = 0 (c) (2.1) (d) e
5 1.2, 2, d a V a = M (1.2.1), M, a,,,,, Ω, V a V, V a = V + Ω r. (1.2.2), r i 1, i 2, i 3, i 1, i 2, i 3, A 2, A = 3 A n i n = n=1 da = 3 = n=1 3 n=1
4 1 1.1 ( ) 5 1.2, 2, d a V a = M (1.2.1), M, a,,,,, Ω, V a V, V a = V + Ω r. (1.2.2), r i 1, i 2, i 3, i 1, i 2, i 3, A 2, A = 3 A n i n = n=1 da = 3 = n=1 3 n=1 da n i n da n i n + 3 A ni n n=1 3 n=1
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50 2 I SI MKSA r q r q F F = 1 qq 4πε 0 r r 2 r r r r (2.2 ε 0 = 1 c 2 µ 0 c = m/s q 2.1 r q' F r = 0 µ 0 = 4π 10 7 N/A 2 k = 1/(4πε 0 qq
49 2 I II 2.1 3 e e = 1.602 10 19 A s (2.1 50 2 I SI MKSA 2.1.1 r q r q F F = 1 qq 4πε 0 r r 2 r r r r (2.2 ε 0 = 1 c 2 µ 0 c = 3 10 8 m/s q 2.1 r q' F r = 0 µ 0 = 4π 10 7 N/A 2 k = 1/(4πε 0 qq F = k r
1. (8) (1) (x + y) + (x + y) = 0 () (x + y ) 5xy = 0 (3) (x y + 3y 3 ) (x 3 + xy ) = 0 (4) x tan y x y + x = 0 (5) x = y + x + y (6) = x + y 1 x y 3 (
1 1.1 (1) (1 + x) + (1 + y) = 0 () x + y = 0 (3) xy = x (4) x(y + 3) + y(y + 3) = 0 (5) (a + y ) = x ax a (6) x y 1 + y x 1 = 0 (7) cos x + sin x cos y = 0 (8) = tan y tan x (9) = (y 1) tan x (10) (1 +
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(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0
1 1 1.1 1.) T D = T = D = kn 1. 1.4) F W = F = W/ = kn/ = 15 kn 1. 1.9) R = W 1 + W = 6 + 5 = 11 N. 1.9) W b W 1 a = a = W /W 1 )b = 5/6) = 5 cm 1.4 AB AC P 1, P x, y x, y y x 1.4.) P sin 6 + P 1 sin 45
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5 5.. Maxwell Maxwell-Ampere E H D P J D roth = J+ = J+ E+ P ( ε P = σe+ εe + (5. ( NL P= ε χe+ P NL, J = σe (5. Faraday rot = µ H E (5. (5. (5. ( E ( roth rot rot = µ NL µσ E µε µ P E (5.4 = ( = grad
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最新耐震構造解析 ( 第 3 版 ) サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. http://www.morikita.co.jp/books/mid/052093 このサンプルページの内容は, 第 3 版 1 刷発行時のものです. i 3 10 3 2000 2007 26 8 2 SI SI 20 1996 2000 SI 15 3 ii 1 56 6
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微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 初版 1 刷発行時のものです.
微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. ttp://www.morikita.co.jp/books/mid/00571 このサンプルページの内容は, 初版 1 刷発行時のものです. i ii 014 10 iii [note] 1 3 iv 4 5 3 6 4 x 0 sin x x 1 5 6 z = f(x, y) 1 y = f(x)
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