1. (8) (1) (x + y) + (x + y) = 0 () (x + y ) 5xy = 0 (3) (x y + 3y 3 ) (x 3 + xy ) = 0 (4) x tan y x y + x = 0 (5) x = y + x + y (6) = x + y 1 x y 3 (

Similar documents
II Karel Švadlenka * [1] 1.1* 5 23 m d2 x dt 2 = cdx kx + mg dt. c, g, k, m 1.2* u = au + bv v = cu + dv v u a, b, c, d R

() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)

(3) (2),,. ( 20) ( s200103) 0.7 x C,, x 2 + y 2 + ax = 0 a.. D,. D, y C, C (x, y) (y 0) C m. (2) D y = y(x) (x ± y 0), (x, y) D, m, m = 1., D. (x 2 y

x = a 1 f (a r, a + r) f(a) r a f f(a) 2 2. (a, b) 2 f (a, b) r f(a, b) r (a, b) f f(a, b)

1 1 x y = y(x) y, y,..., y (n) : n y F (x, y, y,..., y (n) ) = 0 n F (x, y, y ) = 0 1 y(x) y y = G(x, y) y, y y + p(x)y = q(x) 1 p(x) q(

(4) P θ P 3 P O O = θ OP = a n P n OP n = a n {a n } a = θ, a n = a n (n ) {a n } θ a n = ( ) n θ P n O = a a + a 3 + ( ) n a n a a + a 3 + ( ) n a n

x () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x

(1) D = [0, 1] [1, 2], (2x y)dxdy = D = = (2) D = [1, 2] [2, 3], (x 2 y + y 2 )dxdy = D = = (3) D = [0, 1] [ 1, 2], 1 {

1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0

D xy D (x, y) z = f(x, y) f D (2 ) (x, y, z) f R z = 1 x 2 y 2 {(x, y); x 2 +y 2 1} x 2 +y 2 +z 2 = 1 1 z (x, y) R 2 z = x 2 y

,. Black-Scholes u t t, x c u 0 t, x x u t t, x c u t, x x u t t, x + σ x u t, x + rx ut, x rux, t 0 x x,,.,. Step 3, 7,,, Step 6., Step 4,. Step 5,,.

2.2 h h l L h L = l cot h (1) (1) L l L l l = L tan h (2) (2) L l 2 l 3 h 2.3 a h a h (a, h)

II A A441 : October 02, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka )

x x x 2, A 4 2 Ax.4 A A A A λ λ 4 λ 2 A λe λ λ2 5λ + 6 0,...λ 2, λ 2 3 E 0 E 0 p p Ap λp λ 2 p 4 2 p p 2 p { 4p 2 2p p + 2 p, p 2 λ {

6 2 2 x y x y t P P = P t P = I P P P ( ) ( ) ,, ( ) ( ) cos θ sin θ cos θ sin θ, sin θ cos θ sin θ cos θ y x θ x θ P

<4D F736F F D B B83578B6594BB2D834A836F815B82D082C88C60202E646F63>

S I. dy fx x fx y fx + C 3 C dy fx 4 x, y dy v C xt y C v e kt k > xt yt gt [ v dt dt v e kt xt v e kt + C k x v + C C k xt v k 3 r r + dr e kt S dt d

A


S I. dy fx x fx y fx + C 3 C vt dy fx 4 x, y dy yt gt + Ct + C dt v e kt xt v e kt + C k x v k + C C xt v k 3 r r + dr e kt S Sr πr dt d v } dt k e kt

DVIOUT

ma22-9 u ( v w) = u v w sin θê = v w sin θ u cos φ = = 2.3 ( a b) ( c d) = ( a c)( b d) ( a d)( b c) ( a b) ( c d) = (a 2 b 3 a 3 b 2 )(c 2 d 3 c 3 d

mugensho.dvi

i

n Y 1 (x),..., Y n (x) 1 W (Y 1 (x),..., Y n (x)) 0 W (Y 1 (x),..., Y n (x)) = Y 1 (x)... Y n (x) Y 1(x)... Y n(x) (x)... Y n (n 1) (x) Y (n 1)

.3. (x, x = (, u = = 4 (, x x = 4 x, x 0 x = 0 x = 4 x.4. ( z + z = 8 z, z 0 (z, z = (0, 8, (,, (8, 0 3 (0, 8, (,, (8, 0 z = z 4 z (g f(x = g(

I ( ) 1 de Broglie 1 (de Broglie) p λ k h Planck ( Js) p = h λ = k (1) h 2π : Dirac k B Boltzmann ( J/K) T U = 3 2 k BT

() (, y) E(, y) () E(, y) (3) q ( ) () E(, y) = k q q (, y) () E(, y) = k r r (3).3 [.7 ] f y = f y () f(, y) = y () f(, y) = tan y y ( ) () f y = f y

9 5 ( α+ ) = (α + ) α (log ) = α d = α C d = log + C C 5. () d = 4 d = C = C = 3 + C 3 () d = d = C = C = 3 + C 3 =

.5 z = a + b + c n.6 = a sin t y = b cos t dy d a e e b e + e c e e e + e 3 s36 3 a + y = a, b > b 3 s363.7 y = + 3 y = + 3 s364.8 cos a 3 s365.9 y =,

dy + P (x)y = Q(x) (1) dx dy dx = P (x)y + Q(x) P (x), Q(x) dy y dx Q(x) 0 homogeneous dy dx = P (x)y 1 y dy = P (x) dx log y = P (x) dx + C y = C exp

y π π O π x 9 s94.5 y dy dx. y = x + 3 y = x logx + 9 s9.6 z z x, z y. z = xy + y 3 z = sinx y 9 s x dx π x cos xdx 9 s93.8 a, fx = e x ax,. a =

f : R R f(x, y) = x + y axy f = 0, x + y axy = 0 y 直線 x+y+a=0 に漸近し 原点で交叉する美しい形をしている x +y axy=0 X+Y+a=0 o x t x = at 1 + t, y = at (a > 0) 1 + t f(x, y

pdf

Gmech08.dvi

v_-3_+2_1.eps


DE-resume

4.6: 3 sin 5 sin θ θ t θ 2t θ 4t : sin ωt ω sin θ θ ωt sin ωt 1 ω ω [rad/sec] 1 [sec] ω[rad] [rad/sec] 5.3 ω [rad/sec] 5.7: 2t 4t sin 2t sin 4t

2.2 ( y = y(x ( (x 0, y 0 y (x 0 (y 0 = y(x 0 y = y(x ( y (x 0 = F (x 0, y(x 0 = F (x 0, y 0 (x 0, y 0 ( (x 0, y 0 F (x 0, y 0 xy (x, y (, F (x, y ( (

v er.1/ c /(21)

#A A A F, F d F P + F P = d P F, F y P F F x A.1 ( α, 0), (α, 0) α > 0) (x, y) (x + α) 2 + y 2, (x α) 2 + y 2 d (x + α)2 + y 2 + (x α) 2 + y 2 =

高等学校学習指導要領解説 数学編

LLG-R8.Nisus.pdf

t θ, τ, α, β S(, 0 P sin(θ P θ S x cos(θ SP = θ P (cos(θ, sin(θ sin(θ P t tan(θ θ 0 cos(θ tan(θ = sin(θ cos(θ ( 0t tan(θ

1. z dr er r sinθ dϕ eϕ r dθ eθ dr θ dr dθ r x 0 ϕ r sinθ dϕ r sinθ dϕ y dr dr er r dθ eθ r sinθ dϕ eϕ 2. (r, θ, φ) 2 dr 1 h r dr 1 e r h θ dθ 1 e θ h


7. y fx, z gy z gfx dz dx dz dy dy dx. g f a g bf a b fa 7., chain ule Ω, D R n, R m a Ω, f : Ω R m, g : D R l, fω D, b fa, f a g b g f a g f a g bf a

1W II K =25 A (1) office(a439) (2) A4 etc. 12:00-13:30 Cafe David 1 2 TA appointment Cafe D

18 ( ) I II III A B C(100 ) 1, 2, 3, 5 I II A B (100 ) 1, 2, 3 I II A B (80 ) 6 8 I II III A B C(80 ) 1 n (1 + x) n (1) n C 1 + n C

[ ] 0.1 lim x 0 e 3x 1 x IC ( 11) ( s114901) 0.2 (1) y = e 2x (x 2 + 1) (2) y = x/(x 2 + 1) 0.3 dx (1) 1 4x 2 (2) e x sin 2xdx (3) sin 2 xdx ( 11) ( s

1 I p2/30

5. [1 ] 1 [], u(x, t) t c u(x, t) x (5.3) ξ x + ct, η x ct (5.4),u(x, t) ξ, η u(ξ, η), ξ t,, ( u(ξ,η) ξ η u(x, t) t ) u(x, t) { ( u(ξ, η) c t ξ ξ { (

Gmech08.dvi

ax 2 + bx + c = n 8 (n ) a n x n + a n 1 x n a 1 x + a 0 = 0 ( a n, a n 1,, a 1, a 0 a n 0) n n ( ) ( ) ax 3 + bx 2 + cx + d = 0 4

40 6 y mx x, y 0, 0 x 0. x,y 0,0 y x + y x 0 mx x + mx m + m m 7 sin y x, x x sin y x x. x sin y x,y 0,0 x 0. 8 x r cos θ y r sin θ x, y 0, 0, r 0. x,

2011de.dvi

入試の軌跡

No2 4 y =sinx (5) y = p sin(2x +3) (6) y = 1 tan(3x 2) (7) y =cos 2 (4x +5) (8) y = cos x 1+sinx 5 (1) y =sinx cos x 6 f(x) = sin(sin x) f 0 (π) (2) y

Part y mx + n mt + n m 1 mt n + n t m 2 t + mn 0 t m 0 n 18 y n n a 7 3 ; x α α 1 7α +t t 3 4α + 3t t x α x α y mx + n

II 2 II

Part () () Γ Part ,

( ) ( )


II (10 4 ) 1. p (x, y) (a, b) ε(x, y; a, b) 0 f (x, y) f (a, b) A, B (6.5) y = b f (x, b) f (a, b) x a = A + ε(x, b; a, b) x a 2 x a 0 A = f x (

08-Note2-web

A (1) = 4 A( 1, 4) 1 A 4 () = tan A(0, 0) π A π

webkaitou.dvi


( ) sin 1 x, cos 1 x, tan 1 x sin x, cos x, tan x, arcsin x, arccos x, arctan x. π 2 sin 1 x π 2, 0 cos 1 x π, π 2 < tan 1 x < π 2 1 (1) (

熊本県数学問題正解

2009 I 2 II III 14, 15, α β α β l 0 l l l l γ (1) γ = αβ (2) α β n n cos 2k n n π sin 2k n π k=1 k=1 3. a 0, a 1,..., a n α a

.1 A cos 2π 3 sin 2π 3 sin 2π 3 cos 2π 3 T ra 2 deta T ra 2 deta T ra 2 deta a + d 2 ad bc a 2 + d 2 + ad + bc A 3 a b a 2 + bc ba + d c d ca + d bc +

c y /2 ddy = = 2π sin θ /2 dθd /2 [ ] 2π cos θ d = log 2 + a 2 d = log 2 + a 2 = log 2 + a a 2 d d + 2 = l

1.2 y + P (x)y + Q(x)y = 0 (1) y 1 (x), y 2 (x) y 1 (x), y 2 (x) (1) y(x) c 1, c 2 y(x) = c 1 y 1 (x) + c 2 y 2 (x) 3 y 1 (x) y 1 (x) e R P (x)dx y 2

No δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i x j δx j (5) δs 2

4 4 θ X θ P θ 4. 0, 405 P 0 X 405 X P 4. () 60 () 45 () 40 (4) 765 (5) 40 B 60 0 P = 90, = ( ) = X

1 8, : 8.1 1, 2 z = ax + by + c ax by + z c = a b +1 x y z c = 0, (0, 0, c), n = ( a, b, 1). f = n i=1 a ii x 2 i + i<j 2a ij x i x j = ( x, A x), f =

TOP URL 1

y = f(x) y = f( + h) f(), x = h dy dx f () f (derivtive) (differentition) (velocity) p(t) =(x(t),y(t),z(t)) ( dp dx dt = dt, dy dt, dz ) dt f () > f x

II No.01 [n/2] [1]H n (x) H n (x) = ( 1) r n! r!(n 2r)! (2x)n 2r. r=0 [2]H n (x) n,, H n ( x) = ( 1) n H n (x). [3] H n (x) = ( 1) n dn x2 e dx n e x2

応力とひずみ.ppt

70 : 20 : A B (20 ) (30 ) 50 1

1 (Berry,1975) 2-6 p (S πr 2 )p πr 2 p 2πRγ p p = 2γ R (2.5).1-1 : : : : ( ).2 α, β α, β () X S = X X α X β (.1) 1 2

I 1

( ) 2.1. C. (1) x 4 dx = 1 5 x5 + C 1 (2) x dx = x 2 dx = x 1 + C = 1 2 x + C xdx (3) = x dx = 3 x C (4) (x + 1) 3 dx = (x 3 + 3x 2 + 3x +

n ( (

N cos s s cos ψ e e e e 3 3 e e 3 e 3 e

() Remrk I = [0, ] [x i, x i ]. (x : ) f(x) = 0 (x : ) ξ i, (f) = f(ξ i )(x i x i ) = (x i x i ) = ξ i, (f) = f(ξ i )(x i x i ) = 0 (f) 0.

Untitled

0.6 A = ( 0 ),. () A. () x n+ = x n+ + x n (n ) {x n }, x, x., (x, x ) = (0, ) e, (x, x ) = (, 0) e, {x n }, T, e, e T A. (3) A n {x n }, (x, x ) = (,

, 3, 6 = 3, 3,,,, 3,, 9, 3, 9, 3, 3, 4, 43, 4, 3, 9, 6, 6,, 0 p, p, p 3,..., p n N = p p p 3 p n + N p n N p p p, p 3,..., p n p, p,..., p n N, 3,,,,

.1 z = e x +xy y z y 1 1 x 0 1 z x y α β γ z = αx + βy + γ (.1) ax + by + cz = d (.1') a, b, c, d x-y-z (a, b, c). x-y-z 3 (0,

1/1 lim f(x, y) (x,y) (a,b) ( ) ( ) lim limf(x, y) lim lim f(x, y) x a y b y b x a ( ) ( ) xy x lim lim lim lim x y x y x + y y x x + y x x lim x x 1

2009 IA 5 I 22, 23, 24, 25, 26, (1) Arcsin 1 ( 2 (4) Arccos 1 ) 2 3 (2) Arcsin( 1) (3) Arccos 2 (5) Arctan 1 (6) Arctan ( 3 ) 3 2. n (1) ta


z f(z) f(z) x, y, u, v, r, θ r > 0 z = x + iy, f = u + iv C γ D f(z) f(z) D f(z) f(z) z, Rm z, z 1.1 z = x + iy = re iθ = r (cos θ + i sin θ) z = x iy

f(x) = f(x ) + α(x)(x x ) α(x) x = x. x = f (y), x = f (y ) y = f f (y) = f f (y ) + α(f (y))(f (y) f (y )) f (y) = f (y ) + α(f (y)) (y y ) ( (2) ) f

( z = x 3 y + y ( z = cos(x y ( 8 ( s8.7 y = xe x ( 8 ( s83.8 ( ( + xdx ( cos 3 xdx t = sin x ( 8 ( s84 ( 8 ( s85. C : y = x + 4, l : y = x + a,

I-2 (100 ) (1) y(x) y dy dx y d2 y dx 2 (a) y + 2y 3y = 9e 2x (b) x 2 y 6y = 5x 4 (2) Bernoulli B n (n = 0, 1, 2,...) x e x 1 = n=0 B 0 B 1 B 2 (3) co

Transcription:

1 1.1 (1) (1 + x) + (1 + y) = 0 () x + y = 0 (3) xy = x (4) x(y + 3) + y(y + 3) = 0 (5) (a + y ) = x ax a (6) x y 1 + y x 1 = 0 (7) cos x + sin x cos y = 0 (8) = tan y tan x (9) = (y 1) tan x (10) (1 + x ) = 1 + y (11) x(y ) = y 1

1. (8) (1) (x + y) + (x + y) = 0 () (x + y ) 5xy = 0 (3) (x y + 3y 3 ) (x 3 + xy ) = 0 (4) x tan y x y + x = 0 (5) x = y + x + y (6) = x + y 1 x y 3 (7) 3x + y + (x + y) (8) = x + y 1 x + y = 0

1.3 (1)-(9), Bernoulli (10)-(1) (1) + y = x () x + y = x (3) + y x = 1 x (4) y = sin x (5) + y tan x = sec x (6) + y cos x = cos x sin x (7) x + y = x ln x (8) (1 + x ) + xy = x (9) (1 x ) + xy = 1 (10) x = xy + y (11) x + y + (x 1)y = 0 (1) = xy + x3 y 3 3

1.4 (1) (y + x) + x = 0 () (6x y + 1) + (y x 3) = 0 (3) x(x + y) + (x y ) = 0 (4) xy + (y x ) = 0 (5) y(x + y) + x(x + 3y) = 0 (6) (y xy) x = 0 (7) (xy cos x) + (x 1) = 0 (8) (tan y 3x ) + x sec y = 0 (9) (tan y x) + sec y = 0 (10) (x + ln y) + x y = 0 1.5 p = y (1) y = px p () y = px p + p (3) y = xp + a p (4) y = xp + p (5) y = x p + p (6) yp = x + p 3 (7) p 3 4xyp + 8y = 0 (8) p 3 + axp + x 3 = 0 (9) (a x )p 3 + bx(a x )p p bx = 0 (10) p + py cot x y = 0 4

1.6 (1) y + (x 1)(y ) 3 = 0 () xy + x(y ) y = 0 (3) (1 + x )y + 1 + (y ) = 0 (4) (xy y ) = (y ) + 1 (5) y y = e x (6) y = e y ( ) (7) yy + (y ) = 1 (8) yy (y ) + (y ) 3 = 0 (9) y (y ) 3 = 1 (10) y(y 1)y + (y ) = 0 (11) y y = 3(y ) (1) 5(y ) = 3y y.1 1. t N(t) λ(> 0) N(t). N(0) = N 0 3. λ T log = 0.6931 4. t = 1 N(t) N 0 99% log 100 = 4.605, log 99 = 4.595 5

. A, B A 1 B 1 3 C 1 A B (t = 0) A a B b C 0 b > a t C t.3 10 [ C] t T (t)[ C] dt dt = k(t 10) (k > 0; ) (1) t = 0 60 [ C] 10 55 [ C] 40 [ C] log = 0.6931, log 3 = 1.099, log 5 = 1.609, log 10 =.303.4 M OX T MT OX OT.5 (r, θ).6 E E = E 0 sin ωt () ω = πf E i R L i 6

e (R/L)t L sin ωtdt = R + L ω e(r/l)t sin(ωt φ), tan φ = Lω R (3).7 Clairaut.8 ( ) ax + by + c = f αx + βy + γ (4) a, b, c, α, β, γ.9 1. v m(v) m u v v. v = 0 M 0 dm dv = m V (V : ) (5) 7

3 3.1 (1) y 6y + 8y = 0 () y 10y + 5y = 0 (3) y + 8y + 5y = 0 (4) y y 6y = 6x 1 (5) y y + y = x (6) y y + y = 6x 6 (7) y y + y = x 4 + x 3 1 (8) y 6y + 9y = e 4x (9) y y 8y = e x (10) y + y 6y = e 3x (11) y 3y + y = cos x (1) y + y = cos x cos 3x (13) y y + y = e x sin x (14) y y + y = (x + 1)e 3x (15) y + y = sec x 3. (1) y y y + y = 0 () y + y y y = 0 (3) y 3y + 3y y = e x (4) y + y + y = 0 8

4 Q T (x) k d T + Q = 0 (6) k Q (3.49) (3.5) 1. (5) T (x) = C 3 x (C 3 ) C 3 (5). (5) 3. x = 0, h T 1 T (0) = T (h) = T 1 T (x) 9

5 (1) y = (y + y)e x, x = 0 y = 0 () y + (cos x) y = sin x cos x, x = 0 y = 0 (3) (x + ln y) + x = 0, x = 1 y = 1 y 6 (1) y x x 1 y + 1 x 1 y = x 1, y 1 = x, () y + y + y = e x y = e x 7 (1) () (3) (4) = x y, dt dt = 5x y, dt = 7x + y, dt dt = 5x y + et, = 4x 3y dt = x 3y dt = x 5y dt = x 3y + et 10

8 1.1 (1) (1 + x)(1 + y) = C () y = Ce 1 x (3) y = C x + 1 (4) xy(y + 3) = C (5) ax a y = C(a + y ax a ) (6) x 1 + y 1 = C, y = 1 (7) sec x + tan y = C (8) sin y cos x = C (9) y + 1 = +C(y 1) cos x (10) y x = C(1 + xy) (11) x y = Ce y 1.(1) x + xy + y = C () Cx = (x 4y ) 5 (3) y (x + y ) = Cx 6 ( y (4) x sin = C x) (5) x Cy = C ( ) y + 1 (6) tan 1 = ln (x ) x + (y + 1) + C (7) 3x + xy + y = 4x + C (8) y x 1 ln x + y 3 = C 11

1.3 (1) y = Ce x + x 1 () y = 1 3 x + C x (3) xy = C + x x4 4 (4) y = Ce x 1 (sin x + cos x) (5) y = sin x + C cos x (6) y = sin x 1 + Ce sin x (7) 4xy = C x + x ln x (8) C y = 1 + 1 + x (9) y = x + C 1 x (10) x y = C ln x, y = 0 (11) 1/y = x + C x + 1 (1) y (x 1 + Ce x ) + 1 = 0 1.4 (1) x + xy = C () 3x xy + y + x 3y = C (3) x 3 + 3x y y 3 = C (4) x + y = Cy (5) x y + xy 3 = C (6) y + x = Cx y (7) x y sin x y = C (8) x tan y x 3 = C (9) tan y = Ce x + x 1 (10) 1 3 x3 + x ln y = C 1

1.5 (1) y = Cx C, y = 1 4 x () y = Cx C + C, y = 1 8 x + 1 4 x 1 8 (3) y = Cx + a C, y = ± ax (4) x = 3 p + C p, y = 3 p + C p, p [ ( (5) x = ln p + ) ] p p + 1 + C p + 1, [ ( y = ln p + ) ] p 1 + 1 + C p + 1 + p, p (6) x = p + Cp p 1, y = + C p 1 + p, p (7) y = C(C x), y(4x 3 7y) = 0 (8) x = at 1 + t 3, y = a (1 + 4t 3 ) 6(1 + t 3 + C, p = tx, ) p (9) (y + bx + C)[x a sin(y + C)] = 0 (10) (y sin x) Cy + C = 0 13

1.6 (1) y = ln (x 1) ± (x 1) + C 1 + C () y = ln x + C 1 + C, y = C (3) y = 1 x + 1 (C 1 + 1 ) ln C 1 C 1 C 1 x + 1 + C, C 1 y = 1 x + C (4) y = C 1 C 6 x3 ± 1 + 1 x + C x + C 3, [ 13 (1 x ) 3/ + x sin 1 x + ] 1 x y = ± 1 + C 4 x + C 5 (5) y = C 1 e x + C x + C 3 x + C 4 e x (6) C1e y = cosh(c 1 x + C ) 1 C3e y = cos(c 3 x + C 4 ) + 1, y = ln x + C (7) y = x + C 1 x + C (8) x = y C 1 ln y + C, y = C (9) y = 1 (x C ) C 1 + (x C ) + C 1 ln (10) y ln y = C 1 x + C, y = C 1 (11) y = + C 3 C 1 x + C x C C1 + (1) y = C 1 x + C + C 3 x + C 4, y = C 5 x + C 6 x + C 7 (x C ) + 1 C 1 + C 3 3.1 (1) y = C 1 e 4x + C e x () y = (C 1 + C x)e 5x (3) y = e 4x (C 1 cos 3x + C sin 3x) (4) y = C 1 e 3x + C e x + x (5) y = (C 1 + C x)e x + x + (6) y = e x (C 1 cos x + C sin x) + 3x (7) y = e x (C 1 + C x) + x 4 + 10x 3 + 48x + 13x + 167 (8) y = (C 1 + C x)e 3x + e 4x 14

(9) y = C 1 e 4x + C e x 1 8 ex (10) y = C 1 e x + C e 3x 1 5 xe 3x (11) y = C 1 e x + C e x 3 10 sin x + 1 10 cos x (1) y = C 1 cos x + C sin x + 1 x sin x + 1 cos 3x 8 (13) y = e [(C x 1 1 ] x) cos x + C sin x (14) y = e x (C 1 + C x) + 1 8 e3x (x 4x + 5) (15) y = C 1 cos x + C sin x + x sin x + (cos x) ln cos x 3. (1) y = C 1 e x + C e x + C 3 e x () y = C 1 e x + C e x + C 3 e x (3) y = C 1 e x + C xe x + C 3 x e x + e x 3 (4) y = e x/ (C 1 cos x + C sin 3 x) + e x/ (C 3 cos 3 3 x + C 4 sin x) 5.(1) y = 0 () y = sin x 1 + e sin x (3) 1 3 x3 + x ln y = 1 3 6.(1) y = C 1 x + C e x (x + x + 1) () y = C 1 e x + C xe x + 1 x e x 7.(1) x = C 1 e t + C e t, y = C 1 e t + 4C e t () x = (C 1 + C t)e 4t, y = (C 1 + C + C t)e 4t (3) x = e 6t (C 1 cos t + C sin t), y = e 6t [(C 1 + C ) cos t + (C C 1 ) sin t] (4) x = (C 1 + C t)e 4t + 4 5 et 1 36 et, y = (C 1 + C + C t)e 4t + 1 5 et + 7 36 et 15