多数アンカー式補強土壁工法

Size: px
Start display at page:

Download "多数アンカー式補強土壁工法"

Transcription

1

2

3

4 1. (SN ) SS400 ( ) SN400 SM490A ( ) SN490 JIS G 3136:SN JIS G 3136:SN 1) SN (SNR ) (JIS G ) SN SNR490B 1 1SNR490B 2. SN490 SM490A 2) SNR490B SM490 3) 2SNR490B [N/mm 2 ] [N/mm 2 ]

5 3. (a) (SNR490B ) 16mm18mm20mm22mm25mm (b) (SNR490B) M18M20M22M24M27 (c) M18M20M22M24M27 (d) M18M20M22M24M27 (e) (f) M18M20M22M24M27 (g) 3 3 JIS G 3138 SNR490B JIS H 8641 HDZ55 JIS G 3138 SNR490B JIS H 8641 HDZ55 JIS G 3475 STKN400WBSTKN490B JIS H 8641 HDZ55 JIS G 4051 S45C JIS H 8641 HDZ55 JIS G 3101 SS400 JIS H 8641 HDZ55 JIS G 3101 SS400 JIS H 8641 HDZ55 JIS B 1180 JIS B g JIS H 8641 HDZ55 7H JIS H 8641 HDZ55 S45C 2

6 (1) (mm) (2) 2 5 (mm) (mm) (mm) (mm)

7 4 6 (mm) (mm) 18M22 M M27 M (3) 5 7 (mm) (mm) (kn)

8 (4) 6 M18 M20 M22 M24 M L(mm) (M18 ) 80 (M20 ) 80 (M22 ) 80 (M24 ) 80 (M27 ) 90 (5) M18 7 5

9 9 (mm) (mm) (kg) (td) (mm) (HBC) (mm) (td) (mm) M M M M M

10 (6) 2 2 T (mm) (mm) (mm) (mm) 4.5D D D

11 12 (mm) (mm) (mm) (mm) 4.5S S S M M ) (SN ):() ) )

12 SNR490B C kn/m kn/m kn/m kn/m kn/m C kn/m 9

13 H m N H0 m 1m WwukN/m Hk m H1m BG m BL m kn/m kn/m kh kn/m CkN/m m Df DfB bc c c m mkn/m 10

14 FsFs FsFs FsFs FsFs 11

15 12 kn/ mm mm mm mm M M M M M M M M M M M M M M M M M M M M M M T M M T M M M T M M T M M M M M T M M M M M T M

16 3. 1 K cos sin( δ ) sin cos cosδ KA 3 3 / 2 A ( ) cossin cot sec( ) tan( ) sin 3 H m 4 BGmBLm kn/m z kn/m z m BG m 13

17 5 1 HH ( zh ) i K K kn/m KA kn/m z m H m q kn/m 2 i { } ( i) ( i ) (kn/m ) (kn/m ) (kn/m ) 14

18 i kn/m zi m zi m 3 hi i i hi cos H i Li hii kn/ ihi kn/m Hii m Liii m ii kn/ zi i m i Pi Hi Li Phi Ti i (kn/m cos ) (kn/) (kn/) (kn/) 15

19 SNR490B i Ti (kn/) M M M M M M M M M M M M M M M M M M M M SS400 i Ti (kn/) 16 M M M M M M M M M M M M M M M M M M M M

20 Lri m Lr ii m Lr i m m A i h L L ril r i Lr Lr i i Lri Li qpi = KA (Hpi + zi +Hk) + KAqi i kn/ m KA 3 kn/ m H i m zi i m Hk =0.500 i kn/ m 17

21 i zi H i i kn/ m i kn/ m 1 ui C Nc i N i Q ui kn/ m q i kn/ m C kn/ m Nc Nq 2 T i ui i F u Tai i kn/ Q ui kn/ m i m 18

22 A i i m FPu i bi A i (m ) i kn/m Q ui kn/m 2 ai kn/ 3 Ti TaiOK Tia kn/ Tai kn/ i m Li m Li i m 19

23 i bi Li Li i ai kn/ kn/ 1 B m 0 m kn/ m c kn/ m W kn/ m kn/ m Ls m W m P PH P Pcos kn/ m PV P Psin kn/ m 20

24 { C Ls cos W sin( )} cos( ) W2 Ls 2 C B V Fs H ( Wr) C B Fsa Fsa Fsa V kn/m H kn/m B m C kn/m Wr kn/m WrW W kn/m 21

25 1 k C' N' c k ' Df N' ' B N' kn/m u r Qu kn/m k kdfb Df m B m kn/m C kn/m N c N q N r tan H V V VPVWr kn/m H HPH kn/m 2 Qu kn/m Qa kn/m QaQuFkN/m Qu kn/m V QakN/m B 22

26 F V kn/m B m 1 v i sin Hi kn/m Pvi kn/m Pi kn/m u uhi m i zi Pi (kn/m ) sin Hi vi kn/ m 2 VB V B w c v kn/m kn/m w kn/m 23

27 WwWwuHkN/m wu m kn/m uh m c kn/m c cbchc kn/m c kn/m c m c m v kn /m 3 ub kb C' N' c kb ' DfBN' ' c N' r kn/m QuB kn/m kb kabdfbbc DfB DfBDfhc m c m c m C kn/m kn/m tan N c N q N r 4 V B B QBa kn/m bc QBu kn/m QBa kn/m 24

28 QBaQuBF kn/m QuB kn/m F VB kn/m bc m d B m d m M V M knm/m V knm/m TPi ri = Hi L i K P KP u T i = Min ( Ti Ri ) ri kn/m 25

29 T i kn/ ti kn/ uhi m Li m Tai i kn/ FS SS zi m i zi Hi Li Tai ri T i ri kn/ kn/ kn/ kn/ m 2 1 Fs = ( ) Rc l W costan R W sin Fs R m i kn/m i m W i kn/m i 26

30 i 2 Fsmin Fsa MRMT knm /m MD X X Y 1 Y R k h A + tan K E A -<0 sin(-)=0 A KA kh 2 1 HH i K kn/m K ( zh ) K E E 27

31 kn/m z m H m q kn/m 2 i { } ( i) ( i ) i kn/m zi m zi m (kn/m ) (kn/m ) 3) (kn/m ) hi i cos H i Li hii kn/ 28

32 ihi kn/m Hii m Liii m 4) WhiW wu kh H i Li Whi kn/ Hi m Li m Wwu kn/m kh 5) TiP hiw hi Ti kn/ Phi kn/ Whi kn/ i i Pi (kn/m ) cos Hi Li (kn/) Phi (kn/) Whi (kn/) Ti (kn/) 29

33 SNR490B i Ti () M M M M M M M M M M M M M M M M M M M M SS400 i Ti () M M M M M M M M M M M M M M M M M M M M 30

34 i L ril r Lri m Lr i i m Lr i m m AE h i L r i L Lr i Lri Li 1 i K ( Hi zi) K i i kn/ m KAE 3 kn/ m H i m zi i m i kn/ m

35 ui C Nc i N i Q ui kn/ m i zi H i i kn/ m i kn/ m q i kn/ m C kn/ m Nc [ ] Nq [ ] 2 Tai i kn/ Q ui kn/ m i T i ui i F u m A i i m FPu 3 Ti Tai OK 32

36 33 Tia kn/ Tai kn/ i bi Li Li i kn/ i kn/

37 1 2 C B V Fs H C B ( Wr) Fsa khw Fsa Fsa V kn/m H kn/m B m C kn/m Wr kn/m 1 k C' N' c k ' Df N' ' B N' kn/m u r 34

38 Qu kn/m k kdfb Df m B m kn/m C kn/m N c N q N r tan H V V VPVWr kn/m H kn/m HPH kn/m 2 V QakN/m B Qu kn/m Qa kn/m QaQuFkN/m Qu kn/m F V kn/m B m 35

39 1 v i sin Hi kn/m Pvi kn/m Pi kn/m u uhi m i zi Pi (kn/m ) sin Hi vi kn/ m v= 2 V B w c v kn/m VB kn/m w kn/m WwWwuHkN/m wu m kn/m u 36

40 H m c kn/m c cbchc kn/m c kn/m c m c m v kn /m 3 ub kb C' N' c kb ' DfBN' ' c N' r kn/m QuB kn/m kb kabdfbbc DfB DfBDfhcm c m c m C kn/m kn/m tan N c N q N r 4 QBu kn/m QBa kn/m QBaQuBFkN/m V B B QBakN/m bc 37

41 QuB kn/m F VB kn/m bc m d B m d m M V TPi ri = Hi L i K P ri kn/m T i kn/ ti kn/ uhi m 38

42 Li m Tai i kn/ FS SS i zi Hi Li Tai ri T i ri kn/ kn/ kn/ kn/ m 2 1 Fs = R { c l ( W cos kh Wsin ) tan } ( RWsin kh Wy ) Fs R m i kn/m i m W i kn/m i i kh 39

43 yg m 2 Fsmin Fsa MRMT knm /m MD X X Y Y R 40

Microsoft Word - 部材規格追記 doc

Microsoft Word - 部材規格追記 doc 3 14 10 18 7 20 10 SS SN 21 3 24 4 ... 1... 5... 13 f ck=40n/mm 2 P d1 =60kN/ f ck=40n/mm 2 P d2 =100kN/ f ck=40n/mm 2 P d3 =150kN/ UAUBUC TATBTC DADBDC 115mm 75mm 115mm 75mm 160mm 120mm D13 6.0% l l l

More information

1.500 m X Y m m m m m m m m m m m m N/ N/ ( ) qa N/ N/ 2 2

1.500 m X Y m m m m m m m m m m m m N/ N/ ( ) qa N/ N/ 2 2 1.500 m X Y 0.200 m 0.200 m 0.200 m 0.200 m 0.200 m 0.000 m 1.200 m m 0.150 m 0.150 m m m 2 24.5 N/ 3 18.0 N/ 3 30.0 0.60 ( ) qa 50.79 N/ 2 0.0 N/ 2 20.000 20.000 15.000 15.000 X(m) Y(m) (kn/m 2 ) 10.000

More information

... 1... 1... 2... 3... 5... 7... 7... 7... 8... 8... 12... 14... 14... 14... 16... 16... 16... 17... 17... 18... 18... 19... 20... 43... 43... 53... 55... 56... 56... 57 JFE M... 57... 59... 60... 61

More information

29 4 ... 1... 1... 1... 2... 3... 4.... 4... 4... 7... 8... 8... 8... 8...12...14...14...14...16...18...18...19...21... 42...42...42....42....46....49...51....51....51... 52...52...52...53 I. I. I. I.

More information

16 6 12 1 16 6 23 23 11 16 START 1 Out Ok 1,2 Ok END Out 3 1 1/ H24.2 2 1 L2-1 L2-2 H14.3 3 H9.10 PHC SC 19 1 24 3 18N/mm 2 24N/mm 2 30N/mm 2 25 10 13 12 13 12 11 11 11 11 19 7 25 10 24N 8cm 25(20)mm 45

More information

(1)基礎の設計に関する基本事項

(1)基礎の設計に関する基本事項 (1) qa 50kN/m 2 qa 13 1113 1 (2) (3) (2) 50 qa 100kN/m 2 13 1113 1 (3) qa 100kN/m 2 qa 120kN/m 2 (1) qa 300kN/m 2 qa 13 1113 1 (2) (2) qa 300 kn/m 2 qa 1000kN/m 2 38 3 50 30 3 /10m 42 1 13 1113 5 6 30

More information

untitled

untitled 9118 154 B-1 B-3 B- 5cm 3cm 5cm 3m18m5.4m.5m.66m1.3m 1.13m 1.134m 1.35m.665m 5 , 4 13 7 56 M 1586.1.18 7.77.9 599.5.8 7 1596.9.5 7.57.75 684.11.9 8.5 165..3 7.9 87.8.11 6.57. 166.6.16 7.57.6 856 6.6.5

More information

untitled

untitled .m 5m :.45.4m.m 3.m.6m (N/mm ).8.6 σ.4 h.m. h.68m h(m) b.35m θ4..5.5.5 -. σ ta.n/mm c 3kN/m 3 w 9.8kN/m 3 -.4 ck 6N/mm -.6 σ -.8 3 () :. 4 5 3.75m :. 7.m :. 874mm 4 865mm mm/ :. 7.m 4.m 4.m 6 7 4. 3.5

More information

NETES No.CG V

NETES No.CG V 1 2006 6 NETES No.CG-050001-V 2007 5 2 1 2 1 19 5 1 2 19 8 2 i 1 1 1.1 1 1.2 2 1.3 2 2 3 2.1 3 2.2 8 3 9 3.1 9 3.2 10 3.3 13 3.3.1 13 3.3.2 14 3.3.3 14 3.3.4 16 3.3.5 17 3.3.6 18 3.3.7 21 3.3.8 22 3.4

More information

untitled

untitled 33 30 1 1955 1-1 1-1 -1- - D.J.Varnes Crown Main ScrapTop Head Transverse CrackMinor Scrap LongitudinalFault Zone Surface of Rupture Foot Transverse RidgeTip ToeRight Flank 1-1 -- ph RpH -3- -5-4- -5-

More information

3.300 m m m m m m 0 m m m 0 m 0 m m m he m T m 1.50 m N/ N

3.300 m m m m m m 0 m m m 0 m 0 m m m he m T m 1.50 m N/ N 3.300 m 0.500 m 0.300 m 0.300 m 0.300 m 0.500 m 0 m 1.000 m 2.000 m 0 m 0 m 0.300 m 0.300 m -0.200 he 0.400 m T 0.200 m 1.50 m 0.16 2 24.5 N/ 3 18.0 N/ 3 28.0 18.7 18.7 14.0 14.0 X(m) 1.000 2.000 20 Y(m)

More information

(1) (kn/m 3 )

(1) (kn/m 3 ) 1 1 1.1 1.1.1 (1) 1.1 1.2 1.1 (kn/m 3 ) 77 71 24.5 23 21 8.0 22.5 2 1 1.2 N/m 2 2 m 3 m 2000 2200 2500 3000 (2) 1 A B B 1.3 1.5 1.1 T cm 1.1 3 1.3 L m L 4 L > 4 1.0 L 32 + 7 8 1.2 T 4 1 2 5.0 kn/m 2 3.

More information

(1) 1.1

(1) 1.1 1 1 1.1 1.1.1 1.1 ( ) ( ) ( ) { ( ) ( ) { ( ) ( ) { ( ) ( ) { ( ) ( ) { ( ) ( ) ( ) ( ) ( ) 2 1 1.1.2 (1) 1.1 1.1 3 (2) 1.2 4 1 (3) 1.3 ( ) ( ) (4) 1.1 5 (5) ( ) 1.4 6 1 (6) 1.5 (7) ( ) (8) 1.1 7 1.1.3

More information

untitled

untitled 0 ( L CONTENTS 0 . sin(-x-sinx, (-x(x, sin(90-xx,(90-xsinx sin(80-xsinx,(80-x-x ( sin{90-(ωφ}(ωφ. :n :m.0 m.0 n tn. 0 n.0 tn ω m :n.0n tn n.0 tn.0 m c ω sinω c ω c tnω ecω sin ω ω sin c ω c ω tn c tn ω

More information

[Ver. 0.2] 1 2 3 4 5 6 7 1 1.1 1.2 1.3 1.4 1.5 1 1.1 1 1.2 1. (elasticity) 2. (plasticity) 3. (strength) 4. 5. (toughness) 6. 1 1.2 1. (elasticity) } 1 1.2 2. (plasticity), 1 1.2 3. (strength) a < b F

More information

2.2 h h l L h L = l cot h (1) (1) L l L l l = L tan h (2) (2) L l 2 l 3 h 2.3 a h a h (a, h)

2.2 h h l L h L = l cot h (1) (1) L l L l l = L tan h (2) (2) L l 2 l 3 h 2.3 a h a h (a, h) 1 16 10 5 1 2 2.1 a a a 1 1 1 2.2 h h l L h L = l cot h (1) (1) L l L l l = L tan h (2) (2) L l 2 l 3 h 2.3 a h a h (a, h) 4 2 3 4 2 5 2.4 x y (x,y) l a x = l cot h cos a, (3) y = l cot h sin a (4) h a

More information

Q & A Q A p

Q & A Q A p Q & A 2004.12 1 Q1. 12 2 A1. 11 3 p.1 1.1 2 Q2. A2. < > [ ] 10 5 15 (p.138) (p.150) (p.176) (p.167 ) 3 1. 4 1.6 1.6.1 (2) (p.6) Q3. 5 1 1:1.0 12 2 1:0.6 1:1.0 1:1.0 1:0.6 1:0.6 1:0.6 1:1.0 1:0.6 ( ) 1:1.0

More information

表1-表4_No78_念校.indd

表1-表4_No78_念校.indd mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm Fs = tan + tan. sin(1.5) tan sin. cos Fs ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

More information

untitled

untitled PGF 17 6 1 11 1 12 1 2 21 2 22 2 23 3 1 3 1 3 2 3 3 3 4 3 5 4 6 4 2 4 1 4 2 4 3 4 4 4 5 5 3 5 1 5 2 5 5 5 5 4 5 1 5 2 5 3 6 5 6 1 6 2 6 6 6 24 7 1 7 1 7 2 7 3 7 4 8 2 8 1 8 2 8 3 9 4 9 5 9 6 9 3 9 1 9

More information

untitled

untitled - k k k = y. k = ky. y du dx = ε ux ( ) ux ( ) = ax+ b x u() = ; u( ) = AE u() = b= u () = a= ; a= d x du ε x = = = dx dx N = σ da = E ε da = EA ε A x A x x - σ x σ x = Eε x N = EAε x = EA = N = EA k =

More information

...............y.\....07..

...............y.\....07.. 150 11.512.0 11.812.0 12.013.0 12.514.0 1 a c d e 1 3 a 1m b 6 20 30cm day a b a b 6 6 151 6 S 5m 11.511.8 G 515m 11.812.0 SG 10m 11.812.0 10m 11.511.8 1020m 11.812.0 SF 5m 11.511.8 510m 11.812.0 V 5m

More information

Taro13-学習ノート表紙.PDF

Taro13-学習ノート表紙.PDF 10 11 12 13 13 14 15 18 22 27 30 32 A B C -1- -2- 1 2 A BC -3- -4- A B C -5- A B C -6- A B C -7- -8- 1-1 1-6 1-2 6-1 1-5 1-3 2-1 6-6 6-2 1-4 2-6 2-2 6-5 6-3 2-5 2-3 6-4 2-4 5-1 3-1 5-6 5-2 3-6 3-2 5-5

More information

Taro11-aマニュアル.jtd

Taro11-aマニュアル.jtd L A m ton m kn t t kn t kn t m m kn ton ton m m m kn/ CK CK = N/mm ca sa a cm kn/ kn/ kn/ kn/ kn/ kn/ kn/ - - kn/m WL % /m - - A c sin cos kn/m kn/m kn/m / - / A A H V H A cos V A sin - - = N/mm P P m

More information

1

1 GL (a) (b) Ph l P N P h l l Ph Ph Ph Ph l l l l P Ph l P N h l P l .9 αl B βlt D E. 5.5 L r..8 e g s e,e l l W l s l g W W s g l l W W e s g e s g r e l ( s ) l ( l s ) r e l ( s ) l ( l s ) e R e r

More information

http://www.ike-dyn.ritsumei.ac.jp/ hyoo/wave.html 1 1, 5 3 1.1 1..................................... 3 1.2 5.1................................... 4 1.3.......................... 5 1.4 5.2, 5.3....................

More information

1.... 1 1.1.... 1 1.2.... 1 1.3.... 1 1.3.1.... 1 2.... 3 2.1.... 3 2.2.... 5 3.... 5 3.1.... 5 3.2.... 6 3.2.1.... 6 3.2.2.... 7 3.2.3.... 8 3.2.4.... 8 3.2.5.... 8 3.2.6.... 8 3.3.... 9 3.3.1.... 9 3.3.2....

More information

untitled

untitled .. 3. 3 3. 3 4 3. 5 6 3 7 3.3 9 4. 9 0 6 3 7 0705 φ c d φ d., φ cd, φd. ) O x s + b l cos s s c l / q taφ / q taφ / c l / X + X E + C l w q B s E q q ul q q ul w w q q E E + E E + ul X X + (a) (b) (c)

More information

1 23G 2 1 2 3 4 5 6 7 3 a a b c a 4 1 18G 18G 6 6 3 30 34 2 23G 48 23G 1 25 45 5 20 145mm 20 26 0.6 1.000 0.7 1.000mm a b c a 20 b c 24 28 a c d 3 60 70 / a RC 5 15 b 1 3 c 0.5 1 4 6 5 a 5 1 b a b a d

More information

(2) 50% (3) FRP 2 (4) FRP FRP FRP FRP FRP FRP (1)

(2) 50% (3) FRP 2 (4) FRP FRP FRP FRP FRP FRP (1) FRP 1 12 15 + FRP (1) 8,00010,000cm 2 / g 49 (2) 50% (3) FRP 2 (4) FRP FRP FRP FRP FRP FRP (1) 12 15 3 50 C NM 255kgm 3 WC55%sa47%8cm 417kgm 3 C M FS 0 FS A A FS B B SS FS- FS- SS- 25 34 29 36 N/mm 2 45

More information

untitled

untitled ( ) c a sin b c b c a cos a c b c a tan b a b cos sin a c b c a ccos b csin (4) Ma k Mg a (Gal) g(98gal) (Gal) a max (K-E) kh Zck.85.6. 4 Ma g a k a g k D τ f c + σ tanφ σ 3 3 /A τ f3 S S τ A σ /A σ /A

More information

) ) (1)

) ) (1) 1-1 1) ) 3-1-1 1-1--1 1.1 1) ) (1) 1--1 1.1 1--1 3-1- () 1-- 1-- 1.1 3-1-3 1-- 1) -1 1--1 1--1 H3.0 3.0H10.0 1) 10.0 ) H 4) H3.0 3) 1) ) ) N0 kn / m 3) 4 H8.0 4) -9-5 (1) - -1 1-- 1-- ) - 3-1-4 () 1 4

More information

128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds = 0 (3.4) S 1, S 2 { B( r) n( r)}ds

128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds = 0 (3.4) S 1, S 2 { B( r) n( r)}ds 127 3 II 3.1 3.1.1 Φ(t) ϕ em = dφ dt (3.1) B( r) Φ = { B( r) n( r)}ds (3.2) S S n( r) Φ 128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds

More information

untitled

untitled 20 3 Copyright (2007) by P.W.R.I. All rights reserved. No part of this book may be reproduced by any means, nor transmitted, nor translated into a machine language without the written permission of the

More information

07.報文_及川ら-二校目.indd

07.報文_及川ら-二校目.indd 8 01 01 4 4 1 5 16 18 6 006 H 18 4 011 H 6 4 1 5 1 5 007 H 19 5 009 1 5 006 007 009 011 9 10 4 000 H 1 4 5 004 H 16 4 004 009 H 1 5 4 4 5 1 4 006 011 1 1 4m 5m 10m 007 1 7 009 009 1 5 10 1 000kg 10a 006

More information

he T N/ N/

he T N/ N/ 6.000 1.000 0.800 0.000 0.500 1.500 3.000 1.200 0.000 0.000 0.000 0.000 0.000-0.100 he 1.500 T 0.100 1.50 0.00 2 24.5 N/ 3 18.0 N/ 3 28.0 18.7 18.7 14.0 14.0 X() 20.000 Y() 0.000 (kn/2) 10.000 0.000 kn

More information

(1) θ a = 5(cm) θ c = 4(cm) b = 3(cm) (2) ABC A A BC AD 10cm BC B D C 99 (1) A B 10m O AOB 37 sin 37 = cos 37 = tan 37

(1) θ a = 5(cm) θ c = 4(cm) b = 3(cm) (2) ABC A A BC AD 10cm BC B D C 99 (1) A B 10m O AOB 37 sin 37 = cos 37 = tan 37 4. 98 () θ a = 5(cm) θ c = 4(cm) b = (cm) () D 0cm 0 60 D 99 () 0m O O 7 sin 7 = 0.60 cos 7 = 0.799 tan 7 = 0.754 () xkm km R km 00 () θ cos θ = sin θ = () θ sin θ = 4 tan θ = () 0 < x < 90 tan x = 4 sin

More information

3 9 3 100 2 10 30 12 1 1 2 2 4 3 9 1 250-1- 3 12 2 2 4 2 16 2-2- -3-8 2 6 10 30 11 30 11 2,500 9 2 2 10-4- 2005 2005 5 50-5- 3 30 FM 43 18 23 730 1700 17 11 3 FM 2 1800 30 3 400 1 1 28 3 4 18.1.28-6- 1

More information

4 4 θ X θ P θ 4. 0, 405 P 0 X 405 X P 4. () 60 () 45 () 40 (4) 765 (5) 40 B 60 0 P = 90, = ( ) = X

4 4 θ X θ P θ 4. 0, 405 P 0 X 405 X P 4. () 60 () 45 () 40 (4) 765 (5) 40 B 60 0 P = 90, = ( ) = X 4 4. 4.. 5 5 0 A P P P X X X X +45 45 0 45 60 70 X 60 X 0 P P 4 4 θ X θ P θ 4. 0, 405 P 0 X 405 X P 4. () 60 () 45 () 40 (4) 765 (5) 40 B 60 0 P 0 0 + 60 = 90, 0 + 60 = 750 0 + 60 ( ) = 0 90 750 0 90 0

More information

x A Aω ẋ ẋ 2 + ω 2 x 2 = ω 2 A 2. (ẋ, ωx) ζ ẋ + iωx ζ ζ dζ = ẍ + iωẋ = ẍ + iω(ζ iωx) dt dζ dt iωζ = ẍ + ω2 x (2.1) ζ ζ = Aωe iωt = Aω cos ωt + iaω sin

x A Aω ẋ ẋ 2 + ω 2 x 2 = ω 2 A 2. (ẋ, ωx) ζ ẋ + iωx ζ ζ dζ = ẍ + iωẋ = ẍ + iω(ζ iωx) dt dζ dt iωζ = ẍ + ω2 x (2.1) ζ ζ = Aωe iωt = Aω cos ωt + iaω sin 2 2.1 F (t) 2.1.1 mẍ + kx = F (t). m ẍ + ω 2 x = F (t)/m ω = k/m. 1 : (ẋ, x) x = A sin ωt, ẋ = Aω cos ωt 1 2-1 x A Aω ẋ ẋ 2 + ω 2 x 2 = ω 2 A 2. (ẋ, ωx) ζ ẋ + iωx ζ ζ dζ = ẍ + iωẋ = ẍ + iω(ζ iωx) dt dζ

More information

dynamics-solution2.dvi

dynamics-solution2.dvi 1 1. (1) a + b = i +3i + k () a b =5i 5j +3k (3) a b =1 (4) a b = 7i j +1k. a = 14 l =/ 14, m=1/ 14, n=3/ 14 3. 4. 5. df (t) d [a(t)e(t)] =ti +9t j +4k, = d a(t) d[a(t)e(t)] e(t)+ da(t) d f (t) =i +18tj

More information

 

  10 44 1.2 5 4 5 3 6-1 - 1 2 3 4 5 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8 9 10 TEL TEL 1 2 TEL FAX TEL FAX TEL FAX 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 1 2 3 4 5 6 ( ) ( ) 2

More information

案内(最終2).indd

案内(最終2).indd 1 2 3 4 5 6 7 8 9 Y01a K01a Q01a T01a N01a S01a Y02b - Y04b K02a Q02a T02a N02a S02a Y05b - Y07b K03a Q03a T03a N03a S03a A01r Y10a Y11a K04a K05a Q04a Q05a T04b - T06b T08a N04a N05a S04a S05a Y12b -

More information

a,, f. a e c a M V N W W c V R MN W e sin V e cos f a b a ba e b W c V e c e F af af F a a c a e be a f a F a b e f F f a b e F e ff a e F a b e e f b e f F F a R b e c e f F M N DD s n s n D s s nd s

More information

PowerPoint プレゼンテーション

PowerPoint プレゼンテーション 003.10.3 003.10.8 Y 1 0031016 B4(4 3 B4,1 M 0 C,Q 0. M,Q 1.- MQ 003/10/16 10/8 Girder BeamColumn Foundation SlabWall Girder BeamColumn Foundation SlabWall 1.-1 5mm 0 kn/m 3 0.05m=0.5 kn/m 60mm 18 kn/m

More information

c 2009 i

c 2009 i I 2009 c 2009 i 0 1 0.0................................... 1 0.1.............................. 3 0.2.............................. 5 1 7 1.1................................. 7 1.2..............................

More information

Mục lục Lời mở đầu 1 1 Ba loại tai nạn lao động thường xảy ra trong khi hàn 2 2 Những công việc nhiều tai nạn gây tử vong 2 3 Tai họa và các nghi vấn

Mục lục Lời mở đầu 1 1 Ba loại tai nạn lao động thường xảy ra trong khi hàn 2 2 Những công việc nhiều tai nạn gây tử vong 2 3 Tai họa và các nghi vấn Dành cho thực tập sinh kỹ năng Bước đầu tiên để thực tập sinh kỹ năng thực hiện công việc hàn an toàn Mục lục Lời mở đầu 1 1 Ba loại tai nạn lao động thường xảy ra trong khi hàn 2 2 Những công việc nhiều

More information

A(6, 13) B(1, 1) 65 y C 2 A(2, 1) B( 3, 2) C 66 x + 2y 1 = 0 2 A(1, 1) B(3, 0) P 67 3 A(3, 3) B(1, 2) C(4, 0) (1) ABC G (2) 3 A B C P 6

A(6, 13) B(1, 1) 65 y C 2 A(2, 1) B( 3, 2) C 66 x + 2y 1 = 0 2 A(1, 1) B(3, 0) P 67 3 A(3, 3) B(1, 2) C(4, 0) (1) ABC G (2) 3 A B C P 6 1 1 1.1 64 A6, 1) B1, 1) 65 C A, 1) B, ) C 66 + 1 = 0 A1, 1) B, 0) P 67 A, ) B1, ) C4, 0) 1) ABC G ) A B C P 64 A 1, 1) B, ) AB AB = 1) + 1) A 1, 1) 1 B, ) 1 65 66 65 C0, k) 66 1 p, p) 1 1 A B AB A 67

More information

Chap10.dvi

Chap10.dvi =0. f = 2 +3 { 2 +3 0 2 f = 1 =0 { sin 0 3 f = 1 =0 2 sin 1 0 4 f = 0 =0 { 1 0 5 f = 0 =0 f 3 2 lim = lim 0 0 0 =0 =0. f 0 = 0. 2 =0. 3 4 f 1 lim 0 0 = lim 0 sin 2 cos 1 = lim 0 2 sin = lim =0 0 2 =0.

More information

66 σ σ (8.1) σ = 0 0 σd = 0 (8.2) (8.2) (8.1) E ρ d = 0... d = 0 (8.3) d 1 NN K K 8.1 d σd σd M = σd = E 2 d (8.4) ρ 2 d = I M = EI ρ 1 ρ = M EI ρ EI

66 σ σ (8.1) σ = 0 0 σd = 0 (8.2) (8.2) (8.1) E ρ d = 0... d = 0 (8.3) d 1 NN K K 8.1 d σd σd M = σd = E 2 d (8.4) ρ 2 d = I M = EI ρ 1 ρ = M EI ρ EI 65 8. K 8 8 7 8 K 6 7 8 K 6 M Q σ (6.4) M O ρ dθ D N d N 1 P Q B C (1 + ε)d M N N h 2 h 1 ( ) B (+) M 8.1: σ = E ρ (E, 1/ρ ) (8.1) 66 σ σ (8.1) σ = 0 0 σd = 0 (8.2) (8.2) (8.1) E ρ d = 0... d = 0 (8.3)

More information

競技スポーツの科学研究 ~ アトランタ五輪を終えて ~ 新潟大学・山崎 健

競技スポーツの科学研究  ~ アトランタ五輪を終えて ~ 新潟大学・山崎  健 1997 3 1998 12 sin cos 1997 3 1998 12 1997 3 1998 12 1997 3 1998 12 4 1997 3 1998 12 1964!? 100m 94 100m 100mH 10 100m 1964 1997 3 1998 12 1996 100m 7 0.174 0.14 9 84 1988 200m 25m 1986 1997 3 1998 12

More information

案内最終.indd

案内最終.indd 1 2 3 4 5 6 IC IC R22 IC IC http://www.gifu-u.ac.jp/view.rbz?cd=393 JR JR JR JR JR 7 / JR IC km IC km IC IC km 8 F HPhttp://www.made.gifu-u.ac.jp/~vlbi/index.html 9 Q01a N01a X01a K01a S01a T01a Q02a N02a

More information

sikepuri.dvi

sikepuri.dvi 2009 2 2 2. 2.. F(s) G(s) H(s) G(s) F(s) H(s) F(s),G(s) H(s) : V (s) Z(s)I(s) I(s) Y (s)v (s) Z(s): Y (s): 2: ( ( V V 2 I I 2 ) ( ) ( Z Z 2 Z 2 Z 22 ) ( ) ( Y Y 2 Y 2 Y 22 ( ) ( ) Z Z 2 Y Y 2 : : Z 2 Z

More information

untitled

untitled ( ) l 1991 1) 4) 5),6) 7) 8) 31) 39) 46) : () + +θ (c) l h A - : θ A () (d) 1 ε=/l=θ/cot 1(d) 1 () =tn( ) h + 1 u F m N F m =Ntn N N N F m N F m =Ntn N S α S1 R α+ R = tn( ) = tn = tn( + ) R R d = d ()

More information

t θ, τ, α, β S(, 0 P sin(θ P θ S x cos(θ SP = θ P (cos(θ, sin(θ sin(θ P t tan(θ θ 0 cos(θ tan(θ = sin(θ cos(θ ( 0t tan(θ

t θ, τ, α, β S(, 0 P sin(θ P θ S x cos(θ SP = θ P (cos(θ, sin(θ sin(θ P t tan(θ θ 0 cos(θ tan(θ = sin(θ cos(θ ( 0t tan(θ 4 5 ( 5 3 9 4 0 5 ( 4 6 7 7 ( 0 8 3 9 ( 8 t θ, τ, α, β S(, 0 P sin(θ P θ S x cos(θ SP = θ P (cos(θ, sin(θ sin(θ P t tan(θ θ 0 cos(θ tan(θ = sin(θ cos(θ ( 0t tan(θ S θ > 0 θ < 0 ( P S(, 0 θ > 0 ( 60 θ

More information

3 MS- MS-TS ST ST 3 FF-TS MS-hi3 MS-TSST3 FF-TS3 MkNm ce ce 1 5 MS-hi15 3 MS-hi15 6 ce MS-hi3 35 MS-hi MS-hi3 MS-hi15

3 MS- MS-TS ST ST 3 FF-TS MS-hi3 MS-TSST3 FF-TS3 MkNm ce ce 1 5 MS-hi15 3 MS-hi15 6 ce MS-hi3 35 MS-hi MS-hi3 MS-hi15 I N F O R M T I O N MS- MS-TS ST FF-TS 3 3 MS- MS-TS ST ST 3 FF-TS MS-hi3 MS-TSST3 FF-TS3 MkNm 6 5 4 3 2 ce 35 4 1.2 ce 1 5 MS-hi15 3 MS-hi15 6 ce 7 2 1.8 MS-hi3 35 MS-hi3 7 -- MS-hi3 MS-hi15 5 1 15 2

More information

21 2 26 i 1 1 1.1............................ 1 1.2............................ 3 2 9 2.1................... 9 2.2.......... 9 2.3................... 11 2.4....................... 12 3 15 3.1..........

More information

15 DAMTS-DAM BF-DAMBF-TS-DAM MkNm DAM BF-DAM DAM15 TS-DAM15 BF-DAM15 BF-TS-DAM DAM BF-DAM DAM15 TS-DAM15 BF-DAM1

15 DAMTS-DAM BF-DAMBF-TS-DAM MkNm DAM BF-DAM DAM15 TS-DAM15 BF-DAM15 BF-TS-DAM DAM BF-DAM DAM15 TS-DAM15 BF-DAM1 DAMTS-DAM DAMTS-DAM BF-DAMBF-TS-DAM BF-DAMBF-TS-DAM 15 I N F O R M A T I O N 15 DAMTS-DAM BF-DAMBF-TS-DAM15 3. 2. 1.2 6. 345 345 MkNm 6 4 3 2 DAM BF-DAM DAM15 TS-DAM15 BF-DAM15 BF-TS-DAM15 2 3. DAM BF-DAM

More information

I y = f(x) a I a x I x = a + x 1 f(x) f(a) x a = f(a + x) f(a) x (11.1) x a x 0 f(x) f(a) f(a + x) f(a) lim = lim x a x a x 0 x (11.2) f(x) x

I y = f(x) a I a x I x = a + x 1 f(x) f(a) x a = f(a + x) f(a) x (11.1) x a x 0 f(x) f(a) f(a + x) f(a) lim = lim x a x a x 0 x (11.2) f(x) x 11 11.1 I y = a I a x I x = a + 1 f(a) x a = f(a +) f(a) (11.1) x a 0 f(a) f(a +) f(a) = x a x a 0 (11.) x = a a f (a) d df f(a) (a) I dx dx I I I f (x) d df dx dx (x) [a, b] x a ( 0) x a (a, b) () [a,

More information

kuikiso1-sample.xdw

kuikiso1-sample.xdw 計 算 法 -A 支 柱 基 礎 の 根 入 れ 長 計 算 ( 極 限 地 盤 反 力 法 による 最 小 根 入 れ 長 を 確 保 する) 柵 の 支 柱 基 礎 設 置 箇 所 : NO.12+15(L) 計 算 条 件 項 目 記 号 単 位 数 値 摘 要 水 平 力 H kn 9.126 作 用 荷 重 曲 げモーメント M kn m 4.563 支 柱 寸 法 支 柱 の 幅 ( 直

More information

64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () m/s : : a) b) kg/m kg/m k

64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () m/s : : a) b) kg/m kg/m k 63 3 Section 3.1 g 3.1 3.1: : 64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () 3 9.8 m/s 2 3.2 3.2: : a) b) 5 15 4 1 1. 1 3 14. 1 3 kg/m 3 2 3.3 1 3 5.8 1 3 kg/m 3 3 2.65 1 3 kg/m 3 4 6 m 3.1. 65 5

More information

1.. 1 ll a ii. 1i. i f 1 1 a. a. i. t. 1 fi fi. t i j fj i. j ;i 1. i. aa a

1.. 1 ll a ii. 1i. i f 1 1 a. a. i. t. 1 fi fi. t i j fj i. j ;i 1. i. aa a 1.. 1 ll a ii. 1i. i f 1 1 a. a. i. t. 1 fi fi. t i j fj i. j ;i 1. i. aa 1 111 0 0 0 0 a I E l21 1fi i L < i i;i1=t ii 111 1; ai i ti a t T ;,, l 1i.... E 11fi i 1t l l t2 1i i1 t Ea li )2 0 u 0 1f )2

More information

arctan 1 arctan arctan arctan π = = ( ) π = 4 = π = π = π = =

arctan 1 arctan arctan arctan π = = ( ) π = 4 = π = π = π = = arctan arctan arctan arctan 2 2000 π = 3 + 8 = 3.25 ( ) 2 8 650 π = 4 = 3.6049 9 550 π = 3 3 30 π = 3.622 264 π = 3.459 3 + 0 7 = 3.4085 < π < 3 + 7 = 3.4286 380 π = 3 + 77 250 = 3.46 5 3.45926 < π < 3.45927

More information

橡博論表紙.PDF

橡博論表紙.PDF Study on Retaining Wall Design For Circular Deep Shaft Undergoing Lateral Pressure During Construction 2003 3 Study on Retaining Wall Design For Circular Deep Shaft Undergoing Lateral Pressure During Construction

More information

50 2 I SI MKSA r q r q F F = 1 qq 4πε 0 r r 2 r r r r (2.2 ε 0 = 1 c 2 µ 0 c = m/s q 2.1 r q' F r = 0 µ 0 = 4π 10 7 N/A 2 k = 1/(4πε 0 qq

50 2 I SI MKSA r q r q F F = 1 qq 4πε 0 r r 2 r r r r (2.2 ε 0 = 1 c 2 µ 0 c = m/s q 2.1 r q' F r = 0 µ 0 = 4π 10 7 N/A 2 k = 1/(4πε 0 qq 49 2 I II 2.1 3 e e = 1.602 10 19 A s (2.1 50 2 I SI MKSA 2.1.1 r q r q F F = 1 qq 4πε 0 r r 2 r r r r (2.2 ε 0 = 1 c 2 µ 0 c = 3 10 8 m/s q 2.1 r q' F r = 0 µ 0 = 4π 10 7 N/A 2 k = 1/(4πε 0 qq F = k r

More information

土砂流入対策実施計画〔久著呂川〕

土砂流入対策実施計画〔久著呂川〕 22 52 12 3000 2500 2000 1500 (km 2 ) 1000 500 0 1947 1955 1977 1985 1989 1994 2000 22 30 52 60 6 12 2000 1947 2000 110 100 90 (km 2 ) 30 20 10 1947 2000 0 () ( 10 20 () 30 40 50 60 60 a b b

More information

4 2

4 2 1 ( 2 ( 1 3 4 2 3 ( 5 km 6 4 7 ( 564 ( khkv ( 5 8 36m 60m 130m 105m 226m S47 S55.2 S56.2 S55.3 (S55 (a (b ( V M H ( 6 6.6m 2.0m 2m 56 6.5m 9 3.1m 5.75m 2.5m 1.0m 5.0m 2.65m 10 7 48 5.0m 5.0m 8mm 16mm 25.50

More information

+ 1 ( ) I IA i i i 1 n m a 11 a 1j a 1m A = a i1 a ij a im a n1 a nj a nm.....

+   1 ( ) I IA i i i 1 n m a 11 a 1j a 1m A = a i1 a ij a im a n1 a nj a nm..... + http://krishnathphysaitama-uacjp/joe/matrix/matrixpdf 1 ( ) I IA i i i 1 n m a 11 a 1j a 1m A = a i1 a ij a im a n1 a nj a nm (1) n m () (n, m) ( ) n m B = ( ) 3 2 4 1 (2) 2 2 ( ) (2, 2) ( ) C = ( 46

More information

di-problem.dvi

di-problem.dvi III 005/06/6 by. : : : : : : : : : : : : : : : : : : : : :. : : : : : : : : : : : : : : : : : : : : : : : : : : 3 3. : : : : : : : : : : : : : : 4 4. : : : : : : : : : : : : : : : : : : : : : : 5 5. :

More information

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0 1 1 1.1 1.) T D = T = D = kn 1. 1.4) F W = F = W/ = kn/ = 15 kn 1. 1.9) R = W 1 + W = 6 + 5 = 11 N. 1.9) W b W 1 a = a = W /W 1 )b = 5/6) = 5 cm 1.4 AB AC P 1, P x, y x, y y x 1.4.) P sin 6 + P 1 sin 45

More information

1 I 1.1 ± e = = - = C C MKSA [m], [Kg] [s] [A] 1C 1A 1 MKSA 1C 1C +q q +q q 1

1 I 1.1 ± e = = - = C C MKSA [m], [Kg] [s] [A] 1C 1A 1 MKSA 1C 1C +q q +q q 1 1 I 1.1 ± e = = - =1.602 10 19 C C MKA [m], [Kg] [s] [A] 1C 1A 1 MKA 1C 1C +q q +q q 1 1.1 r 1,2 q 1, q 2 r 12 2 q 1, q 2 2 F 12 = k q 1q 2 r 12 2 (1.1) k 2 k 2 ( r 1 r 2 ) ( r 2 r 1 ) q 1 q 2 (q 1 q 2

More information

Microsoft Word - Œ{Ł¶.doc

Microsoft Word - Œ{Ł¶.doc 17 59.0% 41.0% 60.8% 76.0%71.9% 65.3% 17 2.6% 3.5% 25.9% 57.3% 16.7% 28.1% 52.2% 11.1% 2.6% =270 18 2 (=199) 1 17 71.0% 76.0% 44.2% 71.9% 36.2% 18.1% 65.3% 16.7% 34.1% 16.3% 47.1% 14.9% 13.8% 5.0% 3.6%

More information

Γ Ec Γ V BIAS THBV3_0401JA THBV3_0402JAa THBV3_0402JAb 1000 800 600 400 50 % 25 % 200 100 80 60 40 20 10 8 6 4 10 % 2.5 % 0.5 % 0.25 % 2 1.0 0.8 0.6 0.4 0.2 0.1 200 300 400 500 600 700 800 1000 1200 14001600

More information

W06_viet01

W06_viet01 Tiếng Việt 10 điểm cần thiết cho sự an toàn và vui tươi trong học tập tại trường cấp 1 đối với học sinh và phụ huynh người ngoại quốc. Hướng đến việc nhập học trường cấp 1 Hãy xác định lịch trình cho đến

More information

新:コミュ障レポート.pages

新:コミュ障レポート.pages 1. 18 3 1 1 2. 21 YouTube 1 1 21 1 300 1 3. 4 5 1 Y Y 4. 2 2 3 1 2 2 5 10 3 3 Y 1 Y Y 3 3 3 Y Y Y Y Y Y Y Y 5. 3 6. 1 IT 2 4 1 3 4 1 A B 100 C UI Facebook twitter 7. 900 15kg 1 1 1 2 3 15kg 1 21

More information

all.dvi

all.dvi 38 5 Cauchy.,,,,., σ.,, 3,,. 5.1 Cauchy (a) (b) (a) (b) 5.1: 5.1. Cauchy 39 F Q Newton F F F Q F Q 5.2: n n ds df n ( 5.1). df n n df(n) df n, t n. t n = df n (5.1) ds 40 5 Cauchy t l n mds df n 5.3: t

More information

< B38BD C78F6F97CD97E12D332E786477>

< B38BD C78F6F97CD97E12D332E786477> 無筋擁壁設計システム Ver4.2 適用基準 土地改良事業計画設計基準 設計 農道 (H7/3) 土地改良事業計画設計基準 設計 水路工 (H26/3) 日本道路協会 道路土工 擁壁工指針 (H24/7) 土木学会 大型ブロック積み擁壁設計 (H6/6) 宅地防災マニュアルの解説 第二次改訂版 (H9/2) 出力例 ブロック積み擁壁の計算書 ( 安定計算および部材断面計算 ) 開発 販売元 ( 株

More information

y.\..../3.05

y.\..../3.05 G GF S SF M C V O P t GOGV SOSV 70 71 CBR PI CBR qu 75mm 74m5 574m50 1574m50 74m5 574m15 1574m50 74m50 G2.075mm50 S74m2.0mm50 F74m50 Pt 5074m 50 G 502.0mm75mm 50 G 74m15 S 74m15 S 5074m2.0mm F 5074m 50

More information

- 1-128 - 2 -

- 1-128 - 2 - 127 - 1-128 - 2 - - 3-129 - 4 - 2-5 - 130-6 - - 7-131 - 8 - - 9-132 - 10 - 6041 3 () 1 ( ) () 6041 (1010) 1041 (192) 1941 () 2 (1) (2) (3) () 3 1 1 () 4 2 () 5 1 2 3 4 () 6 () 7-11 - 133-12 - 134 135 136

More information

FORES II [フォレスII]

FORES II [フォレスII] ORES Z7 M06 G699 MG59 M59 M49 M06 Z7 G699 1 JOIA ABS 02 231 1 2013-2014 40 -OPEN -LOK L L 1 1 L 735 A4BOX6 /653 2 601 A4BOX5 /525 257 40 2 OA 40 P252 1230 02 232 2 2013-2014 A B 9G-MP59 920RG-MP 59 106,6

More information

No ii

No ii 2005 6 1 2 200004 103/7-2000041037-1 3 4 5 JIS JIS X 0208, 1997 o È o http://www.pref.hiroshima.jp/soumu/bunsyo/monjokan/index.htm 200004 3 6 188030489521435 6119865 1220007 2 1659361903 3118983 16 381963

More information

genron-7

genron-7 F! Z F = * N s/m)! Z R i K # & = " % ) " $ ) ' F R i i K =! " )! +! N) ) R! " i)! i K )! F ) K F = R!, R >> ), R >> ) 3) K F = " i)!, ) >> R, >> ) )! 4) F i K K K =!, > ) ) ) ) F F! 1µ b a r ) V

More information

(1) (2) (1) (2) 2 3 {a n } a 2 + a 4 + a a n S n S n = n = S n

(1) (2) (1) (2) 2 3 {a n } a 2 + a 4 + a a n S n S n = n = S n . 99 () 0 0 0 () 0 00 0 350 300 () 5 0 () 3 {a n } a + a 4 + a 6 + + a 40 30 53 47 77 95 30 83 4 n S n S n = n = S n 303 9 k d 9 45 k =, d = 99 a d n a n d n a n = a + (n )d a n a n S n S n = n(a + a n

More information

A4東尾表紙2012 [更新済み]

A4東尾表紙2012 [更新済み] JPF-MP-003 JPF-MP-008 JWW-K-116 JWW-K-1 PVC JWW-K-116 JWW-K-1 PM 21 CIPM 199511PM 21 C f 1MpaG10Kf/cm 2 C JWW-K-116SGP-V,V JWW-K-1SGP-P,P 2.5MPaG f 1/2 3/4 1 1 1/4 1 1/2 2 2 1/2 3 4 16.0 18.5 21.0 22.9

More information

1. 4cm 16 cm 4cm 20cm 18 cm L λ(x)=ax [kg/m] A x 4cm A 4cm 12 cm h h Y 0 a G 0.38h a b x r(x) x y = 1 h 0.38h G b h X x r(x) 1 S(x) = πr(x) 2 a,b, h,π

1. 4cm 16 cm 4cm 20cm 18 cm L λ(x)=ax [kg/m] A x 4cm A 4cm 12 cm h h Y 0 a G 0.38h a b x r(x) x y = 1 h 0.38h G b h X x r(x) 1 S(x) = πr(x) 2 a,b, h,π . 4cm 6 cm 4cm cm 8 cm λ()=a [kg/m] A 4cm A 4cm cm h h Y a G.38h a b () y = h.38h G b h X () S() = π() a,b, h,π V = ρ M = ρv G = M h S() 3 d a,b, h 4 G = 5 h a b a b = 6 ω() s v m θ() m v () θ() ω() dθ()

More information

58 5 5.2 1933 (Proctor) (JIS A 1210) ( 2.5 kg 4.5 kg ) (2.5 kg 30 cm 4.5 kg 45 cm) 5.3 5 5.1 ρ d w ρ d max w opt 5.1

58 5 5.2 1933 (Proctor) (JIS A 1210) ( 2.5 kg 4.5 kg ) (2.5 kg 30 cm 4.5 kg 45 cm) 5.3 5 5.1 ρ d w ρ d max w opt 5.1 57 5 5.1 2 2.1 ( ) ( ) 58 5 5.2 1933 (Proctor) (JIS A 1210) ( 2.5 kg 4.5 kg ) (2.5 kg 30 cm 4.5 kg 45 cm) 5.3 5 5.1 ρ d w ρ d max w opt 5.1 5.3 59 5.1 v a = 0 % S r = 100 % 5.3 5.1 5 5.1 5.4 2 2 5.2 3

More information

(30 ) (30 )

(30 ) (30 ) 10.1.1 15 10 10 15 10 122 10.2.1 100 5 60 100 25 100 40 50 16 (30 ) 3540 25 (30 ) 35 14 35 27 27 27 120 123 10.2.2 F24F80 F100 320 400 800 800 1500 () 10.2.3 40 40 3.2 (3.0) 40 4.0 3.2 20 4.0 25 () 3.0m

More information

19 () -1- 11 12 17 18 6 ()( ) ( ) () () 17 7 ()( ) 18 () -2- 4610 21-3- ( 20 15 4 ) -4- () -5- () () () -6- ( ) -7- cm/s 5cm7.5cm 10cm. 1 ( qc) 400 200-8- 20 ( 46 300 ) 27 252 19 1 252 22 () 1.6.2()

More information

1- 擁壁断面の形状 寸法及び荷重の計算 ( 常時 ) フェンス荷重 1 kn/m 1,100 0 上載荷重 10 m kn/ 3, (1) 自重 地表面と水平面とのなす角度 α=0.00 壁背面と鉛直面とのなす角度 θ=.73 擁壁

1- 擁壁断面の形状 寸法及び荷重の計算 ( 常時 ) フェンス荷重 1 kn/m 1,100 0 上載荷重 10 m kn/ 3, (1) 自重 地表面と水平面とのなす角度 α=0.00 壁背面と鉛直面とのなす角度 θ=.73 擁壁 構造計算例鉄筋コンクリート造擁壁の構造計算例 1 常時 1-1 設計条件 (1) 擁壁の型式及び高さ型式 : 片持梁式鉄筋コンクリート造 L 型擁壁擁壁の高さ :H'=3.00m 擁壁の全高 :H =3.50m () 外力土圧の作用面は縦壁背面とする 上載荷重 : q=10kn/ mフェンス荷重 ( 水平力 ) : 1kN/ m (3) 背面土土質の種類 : 関東ローム土の単位体積重量 :γs=16.0/

More information

20169 3 4 5003 n=3,000 61.8% 38.2% n=3,000 20 7.3% 30 21.3% 40 34.8% 50 36.6% n=3,000 3.0% 2.0% 1.5% 12.1% 14.0% 41.4% 25.9% n=3,000 37.7% % 24.8% 28.8% 1.9% 3.1% 0.2% n=3,000 500 64.0% 500 1,000 31.3%

More information

平塚信用金庫の現況 2015

平塚信用金庫の現況 2015 2015 1 2 3 1 2 3 4 5 6 7 1 2 3 4 5 8 9 @ A B C D E F G H I J K HK L M N O P Q R T R T S T U V W 1 2 3 4 5 6 E F C J I O M N K L H 8 7 G D 0 A 6 9 5

More information

転がり軸受 総合カタログ

転がり軸受 総合カタログ K 4 21 AU L TDO TD 10500 mm 1 10220 mm 10130 mm 19 mm 19 mm 1075 mm 4 5 1 ZZ 2RU 2RS 2RK 2RD JIS 1512 ML JIS 1514-1 A60 A63 7-3 JIS 1520 A102 10-2 A102 10-3 A105 10-7 ZZ 2RU (a) 1) (b) (c) (d) 2) (e) (f)

More information

1

1 1 2 B 3 4 5 6 10 Ss 1.5 G 7 1G 1G 1G 1G 1G G 8 2 9 10 11 12 SSs Sd Ss LOCA AS Sd AS Sd 13 14 15 16 SsSd Ss Sd X Y X Y 1 IC16 2 IC16 SsSd Ss Sd X Y X Y 1 IC16 2 IC16 17 18 19 20 21 22 AB F 23 D 24 1.2~1.3

More information

1 [ 1] (1) MKS? (2) MKS? [ 2] (1) (42.195k) k 2 (2) (3) k/hr [ 3] t = 0 10 ( 1 velocity [/s] 8 4 O

1 [ 1] (1) MKS? (2) MKS? [ 2] (1) (42.195k) k 2 (2) (3) k/hr [ 3] t = 0 10 ( 1 velocity [/s] 8 4 O : 2014 4 10 1 2 2 3 2.1...................................... 3 2.2....................................... 4 2.3....................................... 4 2.4................................ 5 2.5 Free-Body

More information

f : R R f(x, y) = x + y axy f = 0, x + y axy = 0 y 直線 x+y+a=0 に漸近し 原点で交叉する美しい形をしている x +y axy=0 X+Y+a=0 o x t x = at 1 + t, y = at (a > 0) 1 + t f(x, y

f : R R f(x, y) = x + y axy f = 0, x + y axy = 0 y 直線 x+y+a=0 に漸近し 原点で交叉する美しい形をしている x +y axy=0 X+Y+a=0 o x t x = at 1 + t, y = at (a > 0) 1 + t f(x, y 017 8 10 f : R R f(x) = x n + x n 1 + 1, f(x) = sin 1, log x x n m :f : R n R m z = f(x, y) R R R R, R R R n R m R n R m R n R m f : R R f (x) = lim h 0 f(x + h) f(x) h f : R n R m m n M Jacobi( ) m n

More information