(a) (b) X Ag + + X AgX F < Cl < Br < I Li + + X LiX F > Cl > Br > I (a) (b) (c)

Size: px
Start display at page:

Download "(a) (b) X Ag + + X AgX F < Cl < Br < I Li + + X LiX F > Cl > Br > I (a) (b) (c)"

Transcription

1 ( 13 : : 00 )

2 (a) (b) X Ag + + X AgX F < Cl < Br < I Li + + X LiX F > Cl > Br > I (a) (b) (c)

3 (a) CH 3 -Br (b) (c),2,4- (d) CH 3 O-CH=CH-CH 2 (a) NH 2 CH 3 H 3 C NH 2 H CH 3 CH 3 NH 2 H 3 C CH 3 NH (b)

4 (a), (b) (a) 2H 2 (g) + O 2 (g) = 2H 2 O(l) H 298 K 1 atm O 2 1 mol 572 kj (g)(l) O 2 1 mol U R = 8.31 JK 1 mol 1 1 atm = Pa (b) T 1 mol V 1 V 2 R (a) (b) S (c) 20% 10 log 10 2 = (a) (b)

5 l C (a) I 0 I (b) l (a) (i) (ii) l (a) mol dm 3 1 dm 3 AgCl mol 2 dm 6 AgI mol 2 dm 6 Cl 35 Ag 108 I 127 (a) 1.0 mmol (b) (a) Ag + (c) AgCl AgI Ag +

6 +Ze e m e Ĥ = 2 Ze 4πε r 0 r ε 0 n, l, m r, θ, φ r θ φ r θ φ 2 2 Z e E1 = 8πε 0a0 2 4πε 0h a0 = 2 m e e 5 n E n = l n l

7 (a) -D- 20 C (b) 20 C (c)

8 ( 9 : : 30 ) 3

9 (a) H 3 PO 4 > H 2 PO 4 > HPO 2 4 (b) H 2 Se > H 2 S > H 2 O (c) HClO 4 > H 2 SO 4 > H 3 PO 4 > H 4 SiO 4 (a) fac-[co(gly) 3 ]gly = [Ni(CO) 4 ] [PtCl 3 (C 2 H 4 )] C 2 H 4 = [Fe(C 5 H 5 ) 2 ] C 5 H 5 = [Co(CN) 5 ] 3 (b) (1) (III) (2) [Co(NH 3 ) 6 ] 2+ [Co(NH 3 ) 6 ] 3+ (3) [MnO 4 ] Mn O Re 2 Cl 2 8 Re Cl Cl Cl Re Cl Cl Re Cl Cl 871 Cl

10 (a) (b) (a) CH 3 + Cl 2 hν CH 3 (b) + HI (c) + H 2 C CH 2 H 2 SO 4 (d) CH 3 CH 2 CH 2 CH 3 Cl + H 2 O (e) CH 3 2 CH 3 CO 2 C 2 H 5 NaOC 2 H 5 C 2 H 5 OH H 3 O +

11 P G (a) G P+ P P solid O D liquid gas A B (b) A, B C (c) (b) T P AB Tm T b T b+ T (d) (c) OA, OC, OD O dp/dt (e) P + P G (f) (Tm)(T b) Tm T b

12 i P i S k S = k p i ln p i i U i E i < E i > (a) U p i (b) <( E i U ) 2 > < E i 2 > U 2 (c) E W i p i S (d) V T N i E i Q Q ( T, V, N) = exp( E i kt ) i i p i U Q S A Q

13 Ag + + e = Ag Nernst E = E Ag Ag + ( 2.303RT F)log(1 a Ag+ ) a Ag+ E Ag/Ag+ F, T, R Faraday (a) NHE E Ag/Ag V 298K 0.799V (b) NHE( mol dm 3 )( mol dm 3 ) 298K 298K 2.303RT /F 0.060V (c) (d) E AgCl/Ag a Cl - ph = dc B / dph C B K a HA C a C b CB [H + ] CC = C a + C b K a K w

14 [OH ] + [A ] = C = C a + C b = K a = [A ] = K w = [H + ] C B C B = [H + ] dc B / d [H+] = dc B /dph = 2.3{K w / [H + ] + [H + ] K a C [H + ] / ([H + ] + K a ) 2 } (a)(e) (a) (b) (c) (d) (e)

15 m V(x)a, b V 0 x b 0 b < x < a V(x) = V 0 a x a 0 a < x < b x b (a) E V 0 0 < E < V 0 φ (x) k E, V 0, m h h ( = ) A, B, C, D 2π φ (x) = A exp(ikx) + B exp( ikx) (k > 0) φ (x) = C exp(kx) + D exp( kx) (k > 0) φ (x) = 0 (b) A, B, C, D E (c)

16 (a) Hückel MO MO (b) MO MO MO MO MO MO (c) MO (b) (d) Hückel MO E 1 = 2E 2,3 = E 4 = 2 MO

17 cm M ph = 4.61 M = 1 mol dm 3 ph = cm 3 4 M ph (a) ph 4.8 (b) (c) - H-Arg-Glu-Thr-Ile-Glu-Ser-Leu-Ser-Ser-Ser M - (d) - HPLC 8,5009,300 HPLC Edman 212

18 (e) H-Tyr-Pro-Phe(or Trp)-Phe-NH 2

19

物理化学I-第12回(13).ppt

物理化学I-第12回(13).ppt I- 12-1 11 11.1 2Mg(s) + O 2 (g) 2MgO(s) [Mg 2+ O 2 ] Zn(s) + Cu 2+ (aq) Zn 2+ (aq) + Cu(s) - 2Mg(s) 2Mg 2+ (s) + 4e +) O 2 (g) + 4e 2O 2 (s) 2Mg(s) + O 2 (g) 2MgO(s) Zn(s) Zn 2+ (aq) + 2e +) Cu 2+ (aq)

More information

2 Zn Zn + MnO 2 () 2 O 2 2 H2 O + O 2 O 2 MnO 2 2 KClO 3 2 KCl + 3 O 2 O 3 or 3 O 2 2 O 3 N 2 () NH 4 NO 2 2 O + N 2 ( ) MnO HCl Mn O + CaCl(ClO

2 Zn Zn + MnO 2 () 2 O 2 2 H2 O + O 2 O 2 MnO 2 2 KClO 3 2 KCl + 3 O 2 O 3 or 3 O 2 2 O 3 N 2 () NH 4 NO 2 2 O + N 2 ( ) MnO HCl Mn O + CaCl(ClO 1 [1]. Zn + 2 H + Zn 2+,. K Ca Na Mg Al Zn Fe Ni Sn Pb H Cu Hg Ag Pt Au H (H + ),,. [2] ( ) ( ) CO 2, S, SO 2, NH 3 () + () () + () FeS Fe S ( ) + ( ) ( ) + ( ) 2 NH 4 Cl + Ca(OH) 2 Ca O + 2 NH 3,.,,.,,.,.

More information

H22環境地球化学4_化学平衡III_ ppt

H22環境地球化学4_化学平衡III_ ppt 1 2 3 2009年度 環境地球化学 大河内 温度上昇による炭酸水の発泡 気泡 温度が高くなると 溶けきれなくなった 二酸化炭素が気泡として出てくる 4 2009年度 環境地球化学 圧力上昇による炭酸水の発泡 栓を開けると 瓶の中の圧力が急激に 小さくなるので 発泡する 大河内 5 CO 2 K H CO 2 H 2 O K H + 1 HCO 3- K 2 H + CO 3 2- (M) [CO

More information

コロイド化学と界面化学

コロイド化学と界面化学 x 25 1 kg 1 kg = 1 l mmol dm -3 ----- 1000 mg CO 2 -------------------------------------250 mg Li + --------------------------------1 mg Sr 2+ -------------------- 10

More information

1

1 I II II 1 dw = pd = 0 1 U = Q (4.10) 1K (heat capacity) (mole heat capacity) ( dq / d ) = ( du d C = / ) (4.11) du = C d U = C d (4.1) 1 1 du = dq + dw dw = pd dq = du + pd (4.13) p dq = d( U + p ) p (4.14)

More information

4 1 Ampère 4 2 Ampere 31

4 1 Ampère 4 2 Ampere 31 4. 2 2 Coulomb 2 2 2 ( ) electricity 2 30 4 1 Ampère 4 2 Ampere 31 NS 2 Fleming 4 3 B I r 4 1 0 1.257 10-2 Gm/A µ 0I B = 2πr 4 1 32 4 4 A A A A 4 4 10 9 1 2 12 13 14 4 1 16 4 1 CH 2 =CH 2 28.0313 28 2

More information

20_zairyou.pdf

20_zairyou.pdf 平 成 29 年 4 月 入 学 及 び 平 成 28 年 9 月 入 学 大 学 院 修 士 課 程 専 門 職 学 位 課 程 入 学 試 験 物 質 理 工 学 院 材 料 系 筆 答 専 門 試 験 科 目 想 定 問 題 平 成 28 年 1 月 東 京 工 業 大 学 出 題 される 分 野 問 題 数 等 本 想 定 問 題 の 内 容 は 実 際 の 試 験 問 題 とは 異 なる

More information

物理化学I-第11回(13).ppt

物理化学I-第11回(13).ppt I- 11-1 10 10.5 H 3 O + (aq) + OH (aq) + Na + (aq) + Cl (aq) Na + (aq) + Cl (aq) + 2H 2 O(l) - or - [A] V A = [B] V B 22 mol dm 3 equiv dm 3 - H 2 SO 4 (aq) + 2NaOH(aq) 2Na + (aq) + SO 4 2 (aq) + 2H 2

More information

タミフルインタビューフォーム

タミフルインタビューフォーム 2008 1 20 87625 IF 1998 9 75 3% 2 1 75mg 1 g 30mg Oseltamivir Phosphate 2000 12 12 2001 2 2 2001 2 2 2002 1 17 2002 4 26 2002 7 31 IF 2008 1 O H 2 N O H O CH 3 H 3 C N H H 3 PO 4 H H O H 3 C CH 3

More information

36 th IChO : - 3 ( ) , G O O D L U C K final 1

36 th IChO : - 3 ( ) , G O O D L U C K final 1 36 th ICh - - 5 - - : - 3 ( ) - 169 - -, - - - - - - - G D L U C K final 1 1 1.01 2 e 4.00 3 Li 6.94 4 Be 9.01 5 B 10.81 6 C 12.01 7 N 14.01 8 16.00 9 F 19.00 10 Ne 20.18 11 Na 22.99 12 Mg 24.31 Periodic

More information

熊本県数学問題正解

熊本県数学問題正解 00 y O x Typed by L A TEX ε ( ) (00 ) 5 4 4 ( ) http://www.ocn.ne.jp/ oboetene/plan/. ( ) (009 ) ( ).. http://www.ocn.ne.jp/ oboetene/plan/eng.html 8 i i..................................... ( )0... (

More information

近畿中国四国農業研究センター研究報告 第7号

近畿中国四国農業研究センター研究報告 第7号 230 C B A D E 50m 558 0 1km (mg L 1 ) T N NO 2 3 N NH 4 N 2.0 0 (a) 2001 1.5 6 20 21 5 1.0 0.5 0.0 2.0 1.5 1.0 0.5 0.0 14:00 17:00 (b) 2001 7 3 4 20:00 23:00 2:00 (h) 5:00 8:00 11:00 10 0 5 10 15

More information

Microsoft Word - 目次注意事項2.doc

Microsoft Word - 目次注意事項2.doc I II 2009 1. 2. 12 50 3. 1. 2. 3 ( 0.1g, 0.01g, 0.001g ) 3. 4. 1. 2. ()A4 3. 000005 19 5 11 () 19 5 15 () EDTA " # $ 1000 500 =... mol/l Web 1) p.159 2) 1987pp.14-15 3) 1989pp.58-60 4) http://www.chem.zenkyo.h.kyoto-u.ac.jp/operation/

More information

kcal/mol 83kcal/mol 2 63 kcal/mol 83 kcal/mol kcal/mol nm kcal/mol nm

kcal/mol 83kcal/mol 2 63 kcal/mol 83 kcal/mol kcal/mol nm kcal/mol nm 4. 2 3 2 E n 7 2 2 2 1 2 2 3 3 3 4 1(A) 2 2 2 4 1(B) 3 6 2 4 2 4 1 2 4 2 40 2 2 2 146 kcal/mol 83kcal/mol 2 63 kcal/mol 83 kcal/mol kcal/mol nm kcal/mol nm - 3 104 138-3 91 157-2 5 98 146-6 5 112 128-6

More information

追加演習問題

追加演習問題 v (.5 v x (.98 3R k R. v v x B M m M v x v y v z v 3 v x m v mol M v 3 U U R ****************** 500 kcal 60 kg (.3 0 m. mgh t w t (500 kcal (4.84 0 J kcal (4 h (60 min h (60 s min (60 kg (9.80 m s (60

More information

ab c d 6 12 1:25,000 28 3 2-1-3 18 2-1-10 25000 3120 10 14 15 16 7 2-1-4 1000ha 10100ha 110ha ha ha km 200ha 100m 0.3 ha 100m 1m 2-1-11 2-1-5 20cm 2-1-12 20cm 2003 1 05 12 2-1-13 1968 10 7 1968 7 1897

More information

I ( ) 1 de Broglie 1 (de Broglie) p λ k h Planck ( Js) p = h λ = k (1) h 2π : Dirac k B Boltzmann ( J/K) T U = 3 2 k BT

I ( ) 1 de Broglie 1 (de Broglie) p λ k h Planck ( Js) p = h λ = k (1) h 2π : Dirac k B Boltzmann ( J/K) T U = 3 2 k BT I (008 4 0 de Broglie (de Broglie p λ k h Planck ( 6.63 0 34 Js p = h λ = k ( h π : Dirac k B Boltzmann (.38 0 3 J/K T U = 3 k BT ( = λ m k B T h m = 0.067m 0 m 0 = 9. 0 3 kg GaAs( a T = 300 K 3 fg 07345

More information

( )

( ) 18 10 01 ( ) 1 2018 4 1.1 2018............................... 4 1.2 2018......................... 5 2 2017 7 2.1 2017............................... 7 2.2 2017......................... 8 3 2016 9 3.1 2016...............................

More information

09_organal2

09_organal2 4. (1) (a) I = 1/2 (I = 1/2) I 0 p ( ), n () I = 0 (p + n) I = (1/2, 3/2, 5/2 ) p ( ), n () I = (1, 2, 3 ) (b) (m) (I = 1/2) m = +1/2, 1/2 (I = 1/2) m = +1/2, 1/2 I m = +I, +(I 1), +(I 2) (I 1), I ( )

More information

1 2 3 6 10 < > 13 16 16 4 17 13 00 15 30 5

1 2 3 6 10 < > 13 16 16 4 17 13 00 15 30 5 2004 16 3 23 q 4 21 r 1 2 3 6 10 < > 13 16 16 4 17 13 00 15 30 5 13 2 2 16 4 4 17 3 16 3 1 16 3 2 905 1438 1201 1205 1210 70 1812 25 1635 1654 3 44 47 10 10 911.18-R 1193 34 1652 4 911.107-H 1159 1685

More information

(4) P θ P 3 P O O = θ OP = a n P n OP n = a n {a n } a = θ, a n = a n (n ) {a n } θ a n = ( ) n θ P n O = a a + a 3 + ( ) n a n a a + a 3 + ( ) n a n

(4) P θ P 3 P O O = θ OP = a n P n OP n = a n {a n } a = θ, a n = a n (n ) {a n } θ a n = ( ) n θ P n O = a a + a 3 + ( ) n a n a a + a 3 + ( ) n a n 3 () 3,,C = a, C = a, C = b, C = θ(0 < θ < π) cos θ = a + (a) b (a) = 5a b 4a b = 5a 4a cos θ b = a 5 4 cos θ a ( b > 0) C C l = a + a + a 5 4 cos θ = a(3 + 5 4 cos θ) C a l = 3 + 5 4 cos θ < cos θ < 4

More information

2001 Mg-Zn-Y LPSO(Long Period Stacking Order) Mg,,,. LPSO ( ), Mg, Zn,Y. Mg Zn, Y fcc( ) L1 2. LPSO Mg,., Mg L1 2, Zn,Y,, Y.,, Zn, Y Mg. Zn,Y., 926, 1

2001 Mg-Zn-Y LPSO(Long Period Stacking Order) Mg,,,. LPSO ( ), Mg, Zn,Y. Mg Zn, Y fcc( ) L1 2. LPSO Mg,., Mg L1 2, Zn,Y,, Y.,, Zn, Y Mg. Zn,Y., 926, 1 Mg-LPSO 2566 2016 3 2001 Mg-Zn-Y LPSO(Long Period Stacking Order) Mg,,,. LPSO ( ), Mg, Zn,Y. Mg Zn, Y fcc( ) L1 2. LPSO Mg,., Mg L1 2, Zn,Y,, Y.,, Zn, Y Mg. Zn,Y., 926, 1 1,.,,., 1 C 8, 2 A 9.., Zn,Y,.

More information

土壌の観察・実験テキスト −土壌を調べよう!−

土壌の観察・実験テキスト −土壌を調べよう!− ( ) 2006 7 20 i 21 1962 1969 1987 1992 2005 65 1972 1977 1997 1977 1998 1982 1998 2002 2004 2005 SPP 1999 ii 1 g cm m 6378km ( ) 4.2, 4.3 5.1 7.1 8.1 4.1 7.3, 7.4 7.1 1 2 7.1 8.2 2 5 6 1, 2 2.3 4.2, 4.3

More information

(1) θ a = 5(cm) θ c = 4(cm) b = 3(cm) (2) ABC A A BC AD 10cm BC B D C 99 (1) A B 10m O AOB 37 sin 37 = cos 37 = tan 37

(1) θ a = 5(cm) θ c = 4(cm) b = 3(cm) (2) ABC A A BC AD 10cm BC B D C 99 (1) A B 10m O AOB 37 sin 37 = cos 37 = tan 37 4. 98 () θ a = 5(cm) θ c = 4(cm) b = (cm) () D 0cm 0 60 D 99 () 0m O O 7 sin 7 = 0.60 cos 7 = 0.799 tan 7 = 0.754 () xkm km R km 00 () θ cos θ = sin θ = () θ sin θ = 4 tan θ = () 0 < x < 90 tan x = 4 sin

More information

02.O...r.A..

02.O...r.A.. 8 300ha k (m 3 / / ) (0 2 ) 0405 135 270 2 12 0540 162 351 12 24 0810 216 486 500kg 135 459 127 1987 (m 3 / / ) 0566 2266 5947 9 18kg 0057 0425 1019 18 45 0142 0566 1358 45 675 0198 0708 2038 675 945 0283

More information

温泉の化学 1

温泉の化学 1 H O 1,003 516 149 124 2,237 1974 90 110 1km 2,400 ( 100 Mg 200 (98 ) 43,665 mg 38,695 mg 19,000 mg 2000 2000 Na-Ca-Cl 806 1970 1989 10 1991 4 ph 1 981 10,000 1993... (^^; (SO_4^{2-}) " " 1973-1987 1970

More information

untitled

untitled Kw 1-12 1-13 Kw van t Hoff 0 0 0 H S d ln K H ln K = + = RT R d(1/ T ) R ln KW 1/T H 0 /R H 0 = 51.0 kj mol -1 HCl H + + Cl - H2O H + + OH - [] [H + ] [OH - ]=10-14 M 2 25 OH - x OH - [OH - ]=x [H + ]

More information

4 4 4 a b c d a b A c d A a da ad bce O E O n A n O ad bc a d n A n O 5 {a n } S n a k n a n + k S n a a n+ S n n S n n log x x {xy } x, y x + y 7 fx

4 4 4 a b c d a b A c d A a da ad bce O E O n A n O ad bc a d n A n O 5 {a n } S n a k n a n + k S n a a n+ S n n S n n log x x {xy } x, y x + y 7 fx 4 4 5 4 I II III A B C, 5 7 I II A B,, 8, 9 I II A B O A,, Bb, b, Cc, c, c b c b b c c c OA BC P BC OP BC P AP BC n f n x xn e x! e n! n f n x f n x f n x f k x k 4 e > f n x dx k k! fx sin x cos x tan

More information

untitled

untitled I 3 2 4 2. 4 2. 2 4 2. 3 4 2. 4 4 2. 5 4 2. 6 4 2. 7 5 2. 8 5 2. 9 5 3. 8 3. 8 3.2 8 3.3 0 3.4 0 3.5 4 3.6 6 3.7 7 3.8 Lagmur 22 3.9 Freudlch 26 3.0 29 3. 30 3.2 36 4. 37 4. 37 4.2 37 4.3 39 4.4 4 5. DNA

More information

20 15 14.6 15.3 14.9 15.7 16.0 15.7 13.4 14.5 13.7 14.2 10 10 13 16 19 22 1 70,000 60,000 50,000 40,000 30,000 20,000 10,000 0 2,500 59,862 56,384 2,000 42,662 44,211 40,639 37,323 1,500 33,408 34,472

More information

I? 3 1 3 1.1?................................. 3 1.2?............................... 3 1.3!................................... 3 2 4 2.1........................................ 4 2.2.......................................

More information

- 2 -

- 2 - - 2 - - 3 - (1) (2) (3) (1) - 4 - ~ - 5 - (2) - 6 - (1) (1) - 7 - - 8 - (i) (ii) (iii) (ii) (iii) (ii) 10 - 9 - (3) - 10 - (3) - 11 - - 12 - (1) - 13 - - 14 - (2) - 15 - - 16 - (3) - 17 - - 18 - (4) -

More information

2 1980 8 4 4 4 4 4 3 4 2 4 4 2 4 6 0 0 6 4 2 4 1 2 2 1 4 4 4 2 3 3 3 4 3 4 4 4 4 2 5 5 2 4 4 4 0 3 3 0 9 10 10 9 1 1

2 1980 8 4 4 4 4 4 3 4 2 4 4 2 4 6 0 0 6 4 2 4 1 2 2 1 4 4 4 2 3 3 3 4 3 4 4 4 4 2 5 5 2 4 4 4 0 3 3 0 9 10 10 9 1 1 1 1979 6 24 3 4 4 4 4 3 4 4 2 3 4 4 6 0 0 6 2 4 4 4 3 0 0 3 3 3 4 3 2 4 3? 4 3 4 3 4 4 4 4 3 3 4 4 4 4 2 1 1 2 15 4 4 15 0 1 2 1980 8 4 4 4 4 4 3 4 2 4 4 2 4 6 0 0 6 4 2 4 1 2 2 1 4 4 4 2 3 3 3 4 3 4 4

More information

1 (1) (2)

1 (1) (2) 1 2 (1) (2) (3) 3-78 - 1 (1) (2) - 79 - i) ii) iii) (3) (4) (5) (6) - 80 - (7) (8) (9) (10) 2 (1) (2) (3) (4) i) - 81 - ii) (a) (b) 3 (1) (2) - 82 - - 83 - - 84 - - 85 - - 86 - (1) (2) (3) (4) (5) (6)

More information

平成19年度

平成19年度 1 2 3 4 H 3 H CC N + 3 O H 3 C O CO CH 3 CH O CO O CH2 CH 3 P O O 5 H H H CHOH H H H N + CHOH CHOH N + CH CH COO- CHOH CH CHOH 6 1) 7 2 ) 8 3 ) 4 ) 9 10 11 12 13 14 15 16 17 18 19 20 A A 0 21 ) exp( )

More information

3章 問題・略解

3章 問題・略解 S S W R S O( l) O( ) c Jg g J Jg S R J 7. K.9 JK S W S R S JK S S R J 7. K.9JK 4 (a) -Tice 7.K T ice T N 77 K S R.9 JK 4. JK T T ice N.6JK S W S R S JK S S.6JK R (b) S R JK S.6 JK T T ice N 6 O( c) O(

More information

卓球の試合への興味度に関する確率論的分析

卓球の試合への興味度に関する確率論的分析 17 i 1 1 1.1..................................... 1 1.2....................................... 1 1.3..................................... 2 2 5 2.1................................ 5 2.2 (1).........................

More information

卒論 提出用ファイル.doc

卒論 提出用ファイル.doc 11 13 1LT99097W (i) (ii) 0. 0....1 1....3 1.1....3 1.2....4 2....7 2.1....7 2.2....8 2.2.1....8 2.2.2....9 2.2.3.... 10 2.3.... 12 3.... 15 Appendix... 17 1.... 17 2.... 19 3.... 20... 22 (1) a. b. c.

More information

表紙/151708H

表紙/151708H ! " # $ % & ' ( ) ! #! $! " % & " ' " # * + $ %, &! & ', '! " # $ (! " # $ )! " # $ !!$ "! " # $ #! " # $ $! " # $ %! " # $ ! " # " 1 $ 2 " $ % 3 & % ' ( 4 ( ) * ' + 5, -. 6 / 0 0 +, 1 -. 2 3 /! /!%!!

More information

1 26 ( ) ( ) 1 4 I II III A B C (120 ) ( ) 1, 5 7 I II III A B C (120 ) 1 (1) 0 x π 0 y π 3 sin x sin y = 3, 3 cos x + cos y = 1 (2) a b c a +

1 26 ( ) ( ) 1 4 I II III A B C (120 ) ( ) 1, 5 7 I II III A B C (120 ) 1 (1) 0 x π 0 y π 3 sin x sin y = 3, 3 cos x + cos y = 1 (2) a b c a + 6 ( ) 6 5 ( ) 4 I II III A B C ( ) ( ), 5 7 I II III A B C ( ) () x π y π sin x sin y =, cos x + cos y = () b c + b + c = + b + = b c c () 4 5 6 n ( ) ( ) ( ) n ( ) n m n + m = 555 n OAB P k m n k PO +

More information

「産業上利用することができる発明」の審査の運用指針(案)

「産業上利用することができる発明」の審査の運用指針(案) 1 1.... 2 1.1... 2 2.... 4 2.1... 4 3.... 6 4.... 6 1 1 29 1 29 1 1 1. 2 1 1.1 (1) (2) (3) 1 (4) 2 4 1 2 2 3 4 31 12 5 7 2.2 (5) ( a ) ( b ) 1 3 2 ( c ) (6) 2. 2.1 2.1 (1) 4 ( i ) ( ii ) ( iii ) ( iv)

More information

untitled

untitled 1 Physical Chemistry I (Basic Chemical Thermodynamics) [I] [II] [III] [IV] Introduction Energy(The First Law of Thermodynamics) Work Heat Capacity C p and C v Adiabatic Change Exact(=Perfect) Differential

More information

後期化学_04_酸塩基pH

後期化学_04_酸塩基pH 2011 ( ) ph H3O + H + H3O + HCl H3O + HCl + H2O H3O + + Cl HCl H + + Cl OH OH NaOH OH NaOH Na + + OH NH3 OH NH3 + H2O NH4 + + OH 1 H + OH H + H + * 1 NH3 HCl NH4Cl NH4Cl NH3 + Cl NH3 + HCl NH4 + + Cl.

More information

閨75, 縺5 [ ィ チ573, 縺 ィ ィ

閨75, 縺5 [ ィ チ573, 縺 ィ ィ 39ィ 8 998 3. 753 68, 7 86 タ7 9 9989769 438 縺48 縺55 3783645 タ5 縺473 タ7996495 ィ 59754 8554473 9 8984473 3553 7. 95457357, 4.3. 639745 5883597547 6755887 67996499 ィ 597545 4953473 9 857473 3553, 536583, 89573,

More information

1 1 H Li Be Na M g B A l C S i N P O S F He N Cl A e K Ca S c T i V C Mn Fe Co Ni Cu Zn Ga Ge As Se B K Rb S Y Z Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb T e

1 1 H Li Be Na M g B A l C S i N P O S F He N Cl A e K Ca S c T i V C Mn Fe Co Ni Cu Zn Ga Ge As Se B K Rb S Y Z Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb T e No. 1 1 1 H Li Be Na M g B A l C S i N P O S F He N Cl A e K Ca S c T i V C Mn Fe Co Ni Cu Zn Ga Ge As Se B K Rb S Y Z Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb T e I X e Cs Ba F Ra Hf Ta W Re Os I Rf Db Sg Bh

More information

29

29 9 .,,, 3 () C k k C k C + C + C + + C 8 + C 9 + C k C + C + C + C 3 + C 4 + C 5 + + 45 + + + 5 + + 9 + 4 + 4 + 5 4 C k k k ( + ) 4 C k k ( k) 3 n( ) n n n ( ) n ( ) n 3 ( ) 3 3 3 n 4 ( ) 4 4 4 ( ) n n

More information

CuSO POINT S 2 Ni Sn Hg Cu Ag Zn 2 Cu Cu Cu OH 2 Cu NH CuSO 4 5H 2O Ag Ag 2O Ag 2CrO4 Zn ZnS ZnO 2+ Fe Fe OH 2 Fe 3+ Fe OH 3 2 Cu Cu OH 2 Ag Ag

CuSO POINT S 2 Ni Sn Hg Cu Ag Zn 2 Cu Cu Cu OH 2 Cu NH CuSO 4 5H 2O Ag Ag 2O Ag 2CrO4 Zn ZnS ZnO 2+ Fe Fe OH 2 Fe 3+ Fe OH 3 2 Cu Cu OH 2 Ag Ag CuSO POINT S 2 Ni Sn Hg Cu Ag Zn 2 CuCu Cu OH 2 Cu NH 3 4 2 CuSO 4 5H 2O AgAg 2O Ag 2CrO4 ZnZnS ZnO 2+ Fe Fe OH 2 Fe 3+ Fe OH 3 2 Cu Cu OH 2 Ag Ag 2O Cl Cl AgCl PbCl 2 Ag Cl AgCl Pb 2 2Cl PbCl2 Cl Hg22

More information

Contents 1 1. ph ph ph 7 a) ph 9 b) 10 c) ph 11 a) 11 b) 12 c) ph 14 d) 15 ph a) 18 b) / 19 c)

Contents 1 1. ph ph ph 7 a) ph 9 b) 10 c) ph 11 a) 11 b) 12 c) ph 14 d) 15 ph a) 18 b) / 19 c) ph Theory Guide School experiments ph Natural science laws experience ph live ph learn easily Contents 1 1. ph 5 1.1. 5 1.2. ph 6 1.3. ph 7 a) ph 9 b) 10 c) 11 1.4. ph 11 a) 11 b) 12 c) ph 14 d) 15 ph

More information

入試の軌跡

入試の軌跡 4 y O x 4 Typed by L A TEX ε ) ) ) 6 4 ) 4 75 ) http://kumamoto.s.xrea.com/plan/.. PDF) Ctrl +L) Ctrl +) Ctrl + Ctrl + ) ) Alt + ) Alt + ) ESC. http://kumamoto.s.xrea.com/nyusi/kumadai kiseki ri i.pdf

More information

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0 1 1 1.1 1.) T D = T = D = kn 1. 1.4) F W = F = W/ = kn/ = 15 kn 1. 1.9) R = W 1 + W = 6 + 5 = 11 N. 1.9) W b W 1 a = a = W /W 1 )b = 5/6) = 5 cm 1.4 AB AC P 1, P x, y x, y y x 1.4.) P sin 6 + P 1 sin 45

More information

橡今後のワークスタイルの変化.PDF

橡今後のワークスタイルの変化.PDF E08-0224A 60 70 2 80 OA 1 90 1 90 SOHO SOHO small office SOHO SOHO SOHO SOHO SOHO SOHO SOHO SOHO small office Home Office SOHO SOHO SOHO SOHO SO small office HO home office OA SOHO SOHO

More information

[ ] (Verschieden Wissenschaft auf Pedologie fur Geologe) (Taqumi, TuZino) Julius 2007 I. 3 II. 3 II. 1 : : : : : : : : : : : : :

[ ] (Verschieden Wissenschaft auf Pedologie fur Geologe) (Taqumi, TuZino) Julius 2007 I. 3 II. 3 II. 1 : : : : : : : : : : : : : [ ] (Verschieden Wissenschaft auf Pedologie fur Geologe) 2008 1 8 (Taqumi, TuZino) 2008 1 8 10 Julius 2007 I. 3 II. 3 II. 1 : : : : : : : : : : : : : : : : : : : : : : : : : : : : 3 II. 2 : : : : : : :

More information

48 13 13 13 38 21 13 3 13 3.1 l l l l l l 4.1.1 5mm 0.5mm 5mm 10 500mL 500mL 500mL 20 1 200 / 4 5 6 3000G 20 G1118 R N 2 10-8 GG Rcm Nrpm 1μm 2 3000G 1 /1 4.1.2PCB PCB 5mm 0.5mm 5mm 10 500mL 500mL 500mL

More information

RAA-05(201604)MRA対応製品ver6

RAA-05(201604)MRA対応製品ver6 M R A 対 応 製 品 ISO/IEC 17025 ISO/IEC 17025は 試験所及び校正機関が特定の試験又は 校正を実施する能力があるものとして認定を 受けようとする場合の一般要求事項を規定した国際規格 国際相互承認 MRA Mutual Recognition Arrangement 相互承認協定 とは 試験 検査を実施する試験所 検査機関を認定する国際組織として ILAC 国際試験所認定協力機構

More information

911 Carrera Dr.Ing.h.c.F.Porsche AG 2 3 4 5 6 7 8 9 10 11 12 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 13 14 A 1 2 3 4 B 15 16 17 18 B B 19 A A 20 21 A B C 22 23 A A 24 25 A B C 26 27 28 H 29 M 1 30

More information

Microsoft PowerPoint - anachem2018PPT

Microsoft PowerPoint - anachem2018PPT 分析化学 II 分担 : 竹原, 恩田 講義分担竹原 :/( 水 ),( 金 ),9,6,/,9,6,( 木 ) 恩田 :/3( 金 ),/7,,,/,5,/,8 竹原の分担内容 クリスチャン分析化学 I 第 7 版, 第 ~5 章 電気分析化学 試験 ( 竹原 ): 中間試験 回 + 最終試験 回 http://www.scc.kyushuu.ac.jp/reac/index_j.html 電気化学的セルアノード

More information

a n a n ( ) (1) a m a n = a m+n (2) (a m ) n = a mn (3) (ab) n = a n b n (4) a m a n = a m n ( m > n ) m n 4 ( ) 552

a n a n ( ) (1) a m a n = a m+n (2) (a m ) n = a mn (3) (ab) n = a n b n (4) a m a n = a m n ( m > n ) m n 4 ( ) 552 3 3.0 a n a n ( ) () a m a n = a m+n () (a m ) n = a mn (3) (ab) n = a n b n (4) a m a n = a m n ( m > n ) m n 4 ( ) 55 3. (n ) a n n a n a n 3 4 = 8 8 3 ( 3) 4 = 8 3 8 ( ) ( ) 3 = 8 8 ( ) 3 n n 4 n n

More information

A B 5 C 9 3.4 7 mm, 89 mm 7/89 = 3.4. π 3 6 π 6 6 = 6 π > 6, π > 3 : π > 3

A B 5 C 9 3.4 7 mm, 89 mm 7/89 = 3.4. π 3 6 π 6 6 = 6 π > 6, π > 3 : π > 3 π 9 3 7 4. π 3................................................. 3.3........................ 3.4 π.................... 4.5..................... 4 7...................... 7..................... 9 3 3. p

More information

広域防災拠点検討会報告書030723表紙_0829_.PDF

広域防災拠点検討会報告書030723表紙_0829_.PDF 15 3 i 15 3 ii iii iv ( ) ( ) ( ) ... i...iii... 1.... 1.... 1..... 1..... 2.... 3... 5.... 5..... 5..... 5.... 6..... 6..... 6.... 7..... 7..... 8... 12... 13.... 13..... 13..... 16..... 16.... 17....

More information

活用ガイド (ソフトウェア編)

活用ガイド (ソフトウェア編) ii iii iv NEC Corporation 1998 v vi PA RT 1 vii PA RT 2 viii PA RT 3 PA RT 4 ix P A R T 1 2 3 1 4 5 1 1 2 1 2 3 4 6 1 2 3 4 5 7 1 6 7 8 1 9 1 10 1 2 3 4 5 6 7 8 9 10 11 11 1 12 12 1 13 1 1 14 2 3 4 5 1

More information

cm H.11.3 P.13 2 3-106-

cm H.11.3 P.13 2 3-106- H11.3 H.11.3 P.4-105- cm H.11.3 P.13 2 3-106- 2 H.11.3 P.47 H.11.3 P.27 i vl1 vl2-107- 3 h vl l1 l2 1 2 0 ii H.11.3 P.49 2 iii i 2 vl1 vl2-108- H.11.3 P.50 ii 2 H.11.3 P.52 cm -109- H.11.3 P.44 S S H.11.3

More information

03J_sources.key

03J_sources.key Radiation Detection & Measurement (1) (2) (3) (4)1 MeV ( ) 10 9 m 10 7 m 10 10 m < 10 18 m X 10 15 m 10 15 m ......... (isotope)...... (isotone)......... (isobar) 1 1 1 0 1 2 1 2 3 99.985% 0.015% ~0% E

More information

/02/18

/02/18 3 09/0/8 i III,,,, III,?,,,,,,,,,,,,,,,,,,,,?,?,,,,,,,,,,,,,,!!!,? 3,,,, ii,,,!,,,, OK! :!,,,, :!,,,,,, 3:!,, 4:!,,,, 5:!,,! 7:!,,,,, 8:!,! 9:!,,,,,,,,, ( ),, :, ( ), ( ), 6:!,,, :... : 3 ( )... iii,,

More information

CRA3689A

CRA3689A AVIC-DRZ90 AVIC-DRZ80 2 3 4 5 66 7 88 9 10 10 10 11 12 13 14 15 1 1 0 OPEN ANGLE REMOTE WIDE SET UP AVIC-DRZ90 SOURCE OFF AV CONTROL MIC 2 16 17 1 2 0 0 1 AVIC-DRZ90 2 3 4 OPEN ANGLE REMOTE SOURCE OFF

More information

I ( ) 2019

I ( ) 2019 I ( ) 2019 i 1 I,, III,, 1,,,, III,,,, (1 ) (,,, ), :...,, : NHK... NHK, (YouTube ),!!, manaba http://pen.envr.tsukuba.ac.jp/lec/physics/,, Richard Feynman Lectures on Physics Addison-Wesley,,,, x χ,

More information

第2章 有機物汚濁指標の概要と問題点

第2章 有機物汚濁指標の概要と問題点 3 COD Mn 3-1 3-1-1 OC 2 3 OC Oxygen Consumed 3-1 13 DO BOD OC 1 1970 OC KMnO 4 2 K 2 Cr 2 O 7 2 OC ph OC 50 OC JIS K0102 100 30 KMnO 4 3-1 COD 17 3-1 1973 1 KMnO 4 KMnO 4 COD Mn COD Mn COD COD Mn Cr COD

More information

13ィェィ 0002ィェィ 00ィヲ1 702ィョ ィーィ ィイ071 7ィ 06ィヲ02, ISSN

13ィェィ 0002ィェィ 00ィヲ1 702ィョ ィーィ ィイ071 7ィ 06ィヲ02, ISSN 13 13ィェィ 0002ィェィ 00ィヲ1 702ィョ050702 0709ィーィ ィイ071 7ィ 06ィヲ02, ISSN 1992-6138 1 70306070302071 70307090303 07030209020703 1 7 03000009070807 01090803010908071 7030709030503 0300060903031 709020705 ィヲ0302090803001

More information

... 3... 3... 3... 3... 4... 7... 10... 10... 11... 12... 12... 13... 14... 15... 18... 19... 20... 22... 22... 23 2

... 3... 3... 3... 3... 4... 7... 10... 10... 11... 12... 12... 13... 14... 15... 18... 19... 20... 22... 22... 23 2 1 ... 3... 3... 3... 3... 4... 7... 10... 10... 11... 12... 12... 13... 14... 15... 18... 19... 20... 22... 22... 23 2 3 4 5 6 7 8 9 Excel2007 10 Excel2007 11 12 13 - 14 15 16 17 18 19 20 21 22 Excel2007

More information

10 35 10 1 1 5 1 2 3 2 1 34 37.000 28,000 75 203 208 655 7,000 8,000 655 7 70 7 10 1 1,700 5,500 2 7 2 3 9 34 3 4,100 9 1,800 1 1 34 5,800 4,200 470 280 3400 32 1 5 97.8 7 3 34 65 1 40 70 1 2 9 3 3 1 6

More information

2_R_新技術説明会(佐々木)

2_R_新技術説明会(佐々木) % U: 6.58%, Np, Am:.5%, Pu:.% 5.8% Cs 6.5% Sr %.9%Mo 8.74% Tc.9% TODA C 8 H 7 C 8 H 7 N CH C CH N CH O C C 8 H 7 O N MIDOA C 8 H 7 DOODA NTA + HN(C 8 H 7 ) + H O DCC + SOCl + HN(C 8 H 7 ) + Cl TODA (TODA)

More information

A(6, 13) B(1, 1) 65 y C 2 A(2, 1) B( 3, 2) C 66 x + 2y 1 = 0 2 A(1, 1) B(3, 0) P 67 3 A(3, 3) B(1, 2) C(4, 0) (1) ABC G (2) 3 A B C P 6

A(6, 13) B(1, 1) 65 y C 2 A(2, 1) B( 3, 2) C 66 x + 2y 1 = 0 2 A(1, 1) B(3, 0) P 67 3 A(3, 3) B(1, 2) C(4, 0) (1) ABC G (2) 3 A B C P 6 1 1 1.1 64 A6, 1) B1, 1) 65 C A, 1) B, ) C 66 + 1 = 0 A1, 1) B, 0) P 67 A, ) B1, ) C4, 0) 1) ABC G ) A B C P 64 A 1, 1) B, ) AB AB = 1) + 1) A 1, 1) 1 B, ) 1 65 66 65 C0, k) 66 1 p, p) 1 1 A B AB A 67

More information

,,., (,, SiO 2, Si-N, ),,,,,.,.,,, (Schottky). [ ].,..,.,., 1 m µm 10., 10 5, [ ] (6N-103)..,.,. [ ] 1. (,, ) :,.,,.., (HF),.

,,., (,, SiO 2, Si-N, ),,,,,.,.,,, (Schottky). [ ].,..,.,., 1 m µm 10., 10 5, [ ] (6N-103)..,.,. [ ] 1. (,, ) :,.,,.., (HF),. 17 2 2.1,,., (,, SiO 2, Si-N, ),,,,,.,.,,, (Schottky). [ ].,..,.,., 1 m 3 0.1 µm 10., 10 5, 10 7. [ ] (6N-103)..,.,. [ ] 1. (,, ) :,.,,.., (HF),. 18 2,,.,,. 2.,,,.,,. 2.1. 19 2.1.1 1. 1, (Schottky),,,.

More information

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 5 2 5 24 () () () () () 1 1 150 50 50 1 1 ( 15,000 ) 150 ( 15,000 ) 100 50 50 1 1 ( 6,000 ) 150 ( 6,000 ) 100 50 50 1 1 150 1 1 150 100 0.25

More information

1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0

1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0 1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0 0 < t < τ I II 0 No.2 2 C x y x y > 0 x 0 x > b a dx

More information

NumRu::GPhys::EP Flux 2 2 NumRu::GPhys::EP Flux 3 2.................................. 3 2.2 EP............................. 4 2.3.....................

NumRu::GPhys::EP Flux 2 2 NumRu::GPhys::EP Flux 3 2.................................. 3 2.2 EP............................. 4 2.3..................... NumRu::GPhys::EP Flux 7 2 9 NumRu::GPhys::EP Flux 2 2 NumRu::GPhys::EP Flux 3 2.................................. 3 2.2 EP............................. 4 2.3................................. 5 2.4.............................

More information

CARC, AIST

CARC, AIST CARC, AIST 2005 4 14 1 3 2 3 2.1......................................... 3 2.2....................................... 3 2.3......................................... 4 2.4..........................................

More information

24.15章.微分方程式

24.15章.微分方程式 m d y dt = F m d y = mg dt V y = dy dt d y dt = d dy dt dt = dv y dt dv y dt = g dv y dt = g dt dt dv y = g dt V y ( t) = gt + C V y ( ) = V y ( ) = C = V y t ( ) = gt V y ( t) = dy dt = gt dy = g t dt

More information

1 4 2 4 3 5 4? 7 5 9 6 10 7 11 8 13 9 16 10 17 11 19 12 20 13 21 2

1 4 2 4 3 5 4? 7 5 9 6 10 7 11 8 13 9 16 10 17 11 19 12 20 13 21 2 78-2 (2002) p.172-193 1 1 4 2 4 3 5 4? 7 5 9 6 10 7 11 8 13 9 16 10 17 11 19 12 20 13 21 2 ( ) ( )? 3 1 N i p i log p i i p i log p i i N i q i N i p i log q i N i p i { ( log q i ) ( log p i ) } = N i

More information

1.3 (heat transfer with phase change) (phase change) (evaporation) (boiling) (condensation) (melting) (solidification) 1.4 (thermal radiation) 4 2. 1

1.3 (heat transfer with phase change) (phase change) (evaporation) (boiling) (condensation) (melting) (solidification) 1.4 (thermal radiation) 4 2. 1 CAE ( 6 ) 1 1. (heat transfer) 4 1.1 (heat conduction) 1.2 (convective heat transfer) (convection) (natural convection) (free convection) (forced convection) 1 1.3 (heat transfer with phase change) (phase

More information

I S /I SO 1.04 C T S D 0.38 I SO =0.70

I S /I SO 1.04 C T S D 0.38 I SO =0.70 I S /I SO 1.01 C T S D 0.63 I SO =0.75 U=1.25 I S /I SO 1.00 C T S D 0.63 I SO =0.75 U=1.25 I S /I SO 1.01 C T S D 0.77 I SO =0.75 U=1.25 I S /I SO 1.03 C TU S D 0.32 I S /I SO 1.08 C TU S D 0.66 I S /I

More information

税関分析25 年の進歩

税関分析25 年の進歩 25 1 25 40 27 25 27 32 25 CeEDTA 10) 11 1) Fe Al Zn EDTA 2) 12) n IR400 2N BT EDTA 14) e 15) 16) 17) 18) 3) Zn Cu 4) Mn 5) 6) 7) 8) 9 13) 2 24) X 56),57) 58) 25) 59) 60) X 61) X X 26) X 27),28),29) 62)

More information

GDP GDP 1 98% 2

GDP GDP 1 98% 2 2016 2016 4 6 [ ] 1 1.1 1.1.1 1. 2. 3. 2 1 4. 1 700-800 1 GDP GDP 1 98% 2 1.1.2 BOD Biochemical Oxygen Demand BOD COD Chemical Oxygen Demand COD DO DO PM2.5 eg.1 GDP CO 2 eg.2 Life Cycle Assessment 3 eg.

More information