1 I p2/30

Similar documents
1 1 x y = y(x) y, y,..., y (n) : n y F (x, y, y,..., y (n) ) = 0 n F (x, y, y ) = 0 1 y(x) y y = G(x, y) y, y y + p(x)y = q(x) 1 p(x) q(

[ ] 0.1 lim x 0 e 3x 1 x IC ( 11) ( s114901) 0.2 (1) y = e 2x (x 2 + 1) (2) y = x/(x 2 + 1) 0.3 dx (1) 1 4x 2 (2) e x sin 2xdx (3) sin 2 xdx ( 11) ( s

(4) P θ P 3 P O O = θ OP = a n P n OP n = a n {a n } a = θ, a n = a n (n ) {a n } θ a n = ( ) n θ P n O = a a + a 3 + ( ) n a n a a + a 3 + ( ) n a n

Chap9.dvi

1. (8) (1) (x + y) + (x + y) = 0 () (x + y ) 5xy = 0 (3) (x y + 3y 3 ) (x 3 + xy ) = 0 (4) x tan y x y + x = 0 (5) x = y + x + y (6) = x + y 1 x y 3 (

高等学校学習指導要領

高等学校学習指導要領

r III... IV.. grad, div, rot. grad, div, rot 3., B grad, div, rot I, II ɛ-δ web page (

Untitled

さくらの個別指導 ( さくら教育研究所 ) A AB A B A B A AB AB AB B

1 12 ( )150 ( ( ) ) x M x 0 1 M 2 5x 2 + 4x + 3 x 2 1 M x M 2 1 M x (x + 1) 2 (1) x 2 + x + 1 M (2) 1 3 M (3) x 4 +

f(x) = x (1) f (1) (2) f (2) f(x) x = a y y = f(x) f (a) y = f(x) A(a, f(a)) f(a + h) f(x) = A f(a) A x (3, 3) O a a + h x 1 f(x) x = a

brother.\..2.ai


1 2 1 No p. 111 p , 4, 2, f (x, y) = x2 y x 4 + y. 2 (1) y = mx (x, y) (0, 0) f (x, y). m. (2) y = ax 2 (x, y) (0, 0) f (x,

, x R, f (x),, df dx : R R,, f : R R, f(x) ( ).,, f (a) d f dx (a), f (a) d3 f dx 3 (a),, f (n) (a) dn f dx n (a), f d f dx, f d3 f dx 3,, f (n) dn f

no35.dvi

I II

.5 z = a + b + c n.6 = a sin t y = b cos t dy d a e e b e + e c e e e + e 3 s36 3 a + y = a, b > b 3 s363.7 y = + 3 y = + 3 s364.8 cos a 3 s365.9 y =,

r 1 m A r/m i) t ii) m i) t B(t; m) ( B(t; m) = A 1 + r ) mt m ii) B(t; m) ( B(t; m) = A 1 + r ) mt m { ( = A 1 + r ) m } rt r m n = m r m n B

(3) (2),,. ( 20) ( s200103) 0.7 x C,, x 2 + y 2 + ax = 0 a.. D,. D, y C, C (x, y) (y 0) C m. (2) D y = y(x) (x ± y 0), (x, y) D, m, m = 1., D. (x 2 y

( )

1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0

0 = m 2p 1 p = 1/2 p y = 1 m = 1 2 d ( + 1)2 d ( + 1) 2 = d d ( + 1)2 = = 2( + 1) 2 g() 2 f() f() = [g()] 2 = g()g() f f () = [g()g()]

さくらの個別指導 ( さくら教育研究所 ) A a 1 a 2 a 3 a n {a n } a 1 a n n n 1 n n 0 a n = 1 n 1 n n O n {a n } n a n α {a n } α {a

1 (1) ( i ) 60 (ii) 75 (iii) 315 (2) π ( i ) (ii) π (iii) 7 12 π ( (3) r, AOB = θ 0 < θ < π ) OAB A 2 OB P ( AB ) < ( AP ) (4) 0 < θ < π 2 sin θ

() (, y) E(, y) () E(, y) (3) q ( ) () E(, y) = k q q (, y) () E(, y) = k r r (3).3 [.7 ] f y = f y () f(, y) = y () f(, y) = tan y y ( ) () f y = f y


II III I ~ 2 ~

中堅中小企業向け秘密保持マニュアル


PR映画-1

- 2 -


1 (1) (2)

( ) sin 1 x, cos 1 x, tan 1 x sin x, cos x, tan x, arcsin x, arccos x, arctan x. π 2 sin 1 x π 2, 0 cos 1 x π, π 2 < tan 1 x < π 2 1 (1) (

(1) 3 A B E e AE = e AB OE = OA + e AB = (1 35 e ) e OE z 1 1 e E xy e = 0 e = 5 OE = ( 2 0 0) E ( 2 0 0) (2) 3 E P Q k EQ = k EP E y 0

9 5 ( α+ ) = (α + ) α (log ) = α d = α C d = log + C C 5. () d = 4 d = C = C = 3 + C 3 () d = d = C = C = 3 + C 3 =

「産業上利用することができる発明」の審査の運用指針(案)

dy + P (x)y = Q(x) (1) dx dy dx = P (x)y + Q(x) P (x), Q(x) dy y dx Q(x) 0 homogeneous dy dx = P (x)y 1 y dy = P (x) dx log y = P (x) dx + C y = C exp

A

x x x 2, A 4 2 Ax.4 A A A A λ λ 4 λ 2 A λe λ λ2 5λ + 6 0,...λ 2, λ 2 3 E 0 E 0 p p Ap λp λ 2 p 4 2 p p 2 p { 4p 2 2p p + 2 p, p 2 λ {

grad φ(p ) φ P grad φ(p ) p P p φ P p l t φ l t = 0 g (0) g (0) (31) grad φ(p ) p grad φ φ (P, φ(p )) xy (x, y) = (ξ(t), η(t)) ( )

= M + M + M + M M + =.,. f = < ρ, > ρ ρ. ρ f. = ρ = = ± = log 4 = = = ± f = k k ρ. k


DVIOUT

di-problem.dvi

<4D F736F F D B B83578B6594BB2D834A836F815B82D082C88C60202E646F63>

Chap10.dvi

ac b 0 r = r a 0 b 0 y 0 cy 0 ac b 0 f(, y) = a + by + cy ac b = 0 1 ac b = 0 z = f(, y) f(, y) 1 a, b, c 0 a 0 f(, y) = a ( ( + b ) ) a y ac b + a y

I No. sin cos sine, cosine : trigonometric function π : π =.4 : n =, ±, ±, sin + nπ = sin cos + nπ = cos sin = sin : cos = cos :. sin. sin. sin + π si

III 1 (X, d) d U d X (X, d). 1. (X, d).. (i) d(x, y) d(z, y) d(x, z) (ii) d(x, y) d(z, w) d(x, z) + d(y, w) 2. (X, d). F X.. (1), X F, (2) F 1, F 2 F

. p.1/15

A A p.1/16

<4D F736F F D B B83578B6594BB2D834A836F815B82D082C88C60202E646F63>

webkaitou.dvi

1 I

5 1.2, 2, d a V a = M (1.2.1), M, a,,,,, Ω, V a V, V a = V + Ω r. (1.2.2), r i 1, i 2, i 3, i 1, i 2, i 3, A 2, A = 3 A n i n = n=1 da = 3 = n=1 3 n=1

( ) x y f(x, y) = ax

S I. dy fx x fx y fx + C 3 C vt dy fx 4 x, y dy yt gt + Ct + C dt v e kt xt v e kt + C k x v k + C C xt v k 3 r r + dr e kt S Sr πr dt d v } dt k e kt

橡早川ゼミ卒業論文 棟安.PDF

[ ] x f(x) F = f(x) F(x) f(x) f(x) f(x)dx A p.2/29

6 2 2 x y x y t P P = P t P = I P P P ( ) ( ) ,, ( ) ( ) cos θ sin θ cos θ sin θ, sin θ cos θ sin θ cos θ y x θ x θ P

18 ( ) ( ) [ ] [ ) II III A B (120 ) 1, 2, 3, 5, 6 II III A B (120 ) ( ) 1, 2, 3, 7, 8 II III A B (120 ) ( [ ]) 1, 2, 3, 5, 7 II III A B (

高校生の就職への数学II

S I. dy fx x fx y fx + C 3 C dy fx 4 x, y dy v C xt y C v e kt k > xt yt gt [ v dt dt v e kt xt v e kt + C k x v + C C k xt v k 3 r r + dr e kt S dt d

sekibun.dvi

1 (1) (2) 2


A(6, 13) B(1, 1) 65 y C 2 A(2, 1) B( 3, 2) C 66 x + 2y 1 = 0 2 A(1, 1) B(3, 0) P 67 3 A(3, 3) B(1, 2) C(4, 0) (1) ABC G (2) 3 A B C P 6

n Y 1 (x),..., Y n (x) 1 W (Y 1 (x),..., Y n (x)) 0 W (Y 1 (x),..., Y n (x)) = Y 1 (x)... Y n (x) Y 1(x)... Y n(x) (x)... Y n (n 1) (x) Y (n 1)

f (x) x y f(x+dx) f(x) Df 関数 接線 x Dx x 1 x x y f f x (1) x x 0 f (x + x) f (x) f (2) f (x + x) f (x) + f = f (x) + f x (3) x f

表1-表4_No78_念校.indd


: α α α f B - 3: Barle 4: α, β, Θ, θ α β θ Θ

1. z dr er r sinθ dϕ eϕ r dθ eθ dr θ dr dθ r x 0 ϕ r sinθ dϕ r sinθ dϕ y dr dr er r dθ eθ r sinθ dϕ eϕ 2. (r, θ, φ) 2 dr 1 h r dr 1 e r h θ dθ 1 e θ h

t θ, τ, α, β S(, 0 P sin(θ P θ S x cos(θ SP = θ P (cos(θ, sin(θ sin(θ P t tan(θ θ 0 cos(θ tan(θ = sin(θ cos(θ ( 0t tan(θ

C:/KENAR/0p1.dvi

() n C + n C + n C + + n C n n (3) n C + n C + n C 4 + n C + n C 3 + n C 5 + (5) (6 ) n C + nc + 3 nc n nc n (7 ) n C + nc + 3 nc n nc n (

2009 I 2 II III 14, 15, α β α β l 0 l l l l γ (1) γ = αβ (2) α β n n cos 2k n n π sin 2k n π k=1 k=1 3. a 0, a 1,..., a n α a

a (a + ), a + a > (a + ), a + 4 a < a 4 a,,, y y = + a y = + a, y = a y = ( + a) ( x) + ( a) x, x y,y a y y y ( + a : a ) ( a : a > ) y = (a + ) y = a

sin cos No. sine, cosine : trigonometric function π : π = 3.4 : n = 0, ±, ±, sin + nπ = sin cos + nπ = cos : parity sin = sin : odd cos = cos : even.

x = a 1 f (a r, a + r) f(a) r a f f(a) 2 2. (a, b) 2 f (a, b) r f(a, b) r (a, b) f f(a, b)

(, Goo Ishikawa, Go-o Ishikawa) ( ) 1

I No. sin cos sine, cosine : trigonometric function π : π =.4 : n = 0, ±, ±, sin + nπ = sin cos + nπ = cos : parity sin = sin : odd cos = cos : even.

( ) 2.1. C. (1) x 4 dx = 1 5 x5 + C 1 (2) x dx = x 2 dx = x 1 + C = 1 2 x + C xdx (3) = x dx = 3 x C (4) (x + 1) 3 dx = (x 3 + 3x 2 + 3x +

I, II 1, 2 ɛ-δ 100 A = A 4 : 6 = max{ A, } A A 10

1 1.1 [ ]., D R m, f : D R n C -. f p D (df) p : (df) p : R m R n f(p + vt) f(p) : v lim. t 0 t, (df) p., R m {x 1,..., x m }, (df) p (x i ) =

熊本県数学問題正解

CALCULUS II (Hiroshi SUZUKI ) f(x, y) A(a, b) 1. P (x, y) A(a, b) A(a, b) f(x, y) c f(x, y) A(a, b) c f(x, y) c f(x, y) c (x a, y b)

EP7000取扱説明書

みどり野43号-P01

応力とひずみ.ppt

.1 z = e x +xy y z y 1 1 x 0 1 z x y α β γ z = αx + βy + γ (.1) ax + by + cz = d (.1') a, b, c, d x-y-z (a, b, c). x-y-z 3 (0,

,.,. 2, R 2, ( )., I R. c : I R 2, : (1) c C -, (2) t I, c (t) (0, 0). c(i). c (t)., c(t) = (x(t), y(t)) c (t) = (x (t), y (t)) : (1)

分科会(OHP_プログラム.PDF


2010 II / y = e x y = log x = log e x 2. ( e x ) = e x 3. ( ) log x = 1 x 1.2 Warming Up 1 u = log a M a u = M a 0

P F ext 1: F ext P F ext (Count Rumford, ) H 2 O H 2 O 2 F ext F ext N 2 O 2 2


Transcription:

I I p1/30

1 I p2/30

1 ( ) I p3/30

1 ( ), y = y() d = f() g(y) ( g(y) = f()d) (1) I p4/30

1 ( ), y = y() d = f() g(y) ( g(y) = f()d) (1) g(y) = f()d I p4/30

1 ( ), y = y() d = f() g(y) ( g(y) = f()d) (1) g(y) = f()d G(y) = g(y) (g(y), y = y() (1) I p4/30

1 ( ), y = y() d = f() g(y) ( g(y) = f()d) (1) g(y) = f()d G(y) = g(y) (g(y), y = y() (1), d d {G(y())} = dg d = g(y()) () = f() d I p4/30

1 ( ), y = y() d = f() g(y) ( g(y) = f()d) (1) g(y) = f()d G(y) = g(y) (g(y), y = y() (1), d d {G(y())} = dg d = g(y()) () = f() d G(y) = f()d g(y) = f()d I p4/30

1 ( ) [ ] y = 1 + 2 «y I p5/30

1 ( ) [ ] y = 1 + 2 «y [ ] y = 1 + 2 «d I p5/30

1 ( ) [ ] y = 1 + 2 «y [ ] y = 1 + 2 «d log y = + 2log + c (c ) I p5/30

1 ( ) [ ] y = 1 + 2 «y [ ] y = 1 + 2 «d log y = + 2log + c (c ) y = e c 2 e, ±e c = C I p5/30

1 ( ) [ ] y = 1 + 2 «y [ ] y = 1 + 2 «d log y = + 2log + c (c ) y = e c 2 e, ±e c = C y = C 2 e (C 0 ) I p5/30

1 ( ) [ ] y = 1 + 2 «y [ ] y = 1 + 2 «d log y = + 2log + c (c ) y = e c 2 e, ±e c = C y = C 2 e (C 0 ) y 0 (y 0), C = 0 I p5/30

1 ( ) [ ] y = 1 + 2 «y [ ] y = 1 + 2 «d log y = + 2log + c (c ) y = e c 2 e, ±e c = C y = C 2 e (C 0 ) y 0 (y 0), C = 0 y = C 2 e (C ) I p5/30

1 ( ) [ ] 2 y = ( 1)y I p6/30

1 ( ) [ ] 2 y = ( 1)y 1 [ ] y = 1 «2 d I p6/30

1 ( ) [ ] 2 y = ( 1)y 1 [ ] y = 1 «2 d 1, y = 1 «2 d y = Ce 1 (C 0) I p6/30

1 ( ) [ ] 2 y = ( 1)y 1 [ ] y = 1 «2 d 1, y = 1 «2 d y = Ce 1 (C 0) y 0, C = 0 I p6/30

1 ( ) [ ] 2 y = ( 1)y 1 [ ] y = 1 «2 d 1, y = 1 «2 d y = Ce 1 (C 0) y 0, C = 0 y = Ce 1 (C ) I p6/30

2 I p7/30

2 (u = y ), y = y() d = f y (2) I p8/30

2 (u = y ), y = y() d = f y (2), u() = y() y() = u(), I p8/30

2 (u = y ), y = y() d = f y (2), u() = y() y() = u(),, d = du d + u I p8/30

2 (u = y ), y = y() d = f y (2), u() = y() y() = u(),, d = du d + u du d + u = f(u) du d = f(u) u u I p8/30

2 (u = y ), y = y() d = f y (2), u() = y() y() = u(),, d = du d + u du d + u = f(u) du d = f(u) u u u = u() y() = u() I p8/30

2 (u = y ) [ ] 2yy = 2 + y 2 I p9/30

2 (u = y ) [ ] 2yy = 2 + y 2 [ ] d = 2 + y 2 2y = 1 + ` y 2 ` y 2 I p9/30

2 (u = y ) [ ] 2yy = 2 + y 2 [ ] d = 2 + y 2 2y = 1 + ` y 2 ` y u() = y() y() = u(), d = du d + u 2 I p9/30

2 (u = y ) [ ] 2yy = 2 + y 2 [ ] d = 2 + y 2 2y = 1 + ` y 2 ` y u() = y() y() = u(), d = du d + u du d + u = 1 + u2 du 2u d = 1 u2 2u u 2 I p9/30

2 (u = y ) [ ] 2yy = 2 + y 2 [ ] d = 2 + y 2 2y = 1 + ` y 2 ` y u() = y() y() = u(), d = du d + u du d + u = 1 + u2 du 2u d = 1 u2 2u u 2u d u 2 1 du = log u 2 1 = log + c (c ) 2 I p9/30

2 (u = y ) [ ] 2yy = 2 + y 2 [ ] d = 2 + y 2 2y = 1 + ` y 2 ` y u() = y() y() = u(), d = du d + u du d + u = 1 + u2 du 2u d = 1 u2 2u u 2u d u 2 1 du = log u 2 1 = log + c (c ) (u 2 1) = C (C 0 ) 2 I p9/30

2 (u = y ) [ ] 2yy = 2 + y 2 [ ] d = 2 + y 2 2y = 1 + ` y 2 ` y u() = y() y() = u(), d = du d + u du d + u = 1 + u2 du 2u d = 1 u2 2u u 2u d u 2 1 du = log u 2 1 = log + c (c ) (u 2 1) = C (C 0 ) u() = y y2 2 = C 2 I p9/30

2 (u = y ) [ ] 2yy = 2 + y 2 [ ] d = 2 + y 2 2y = 1 + ` y 2 ` y u() = y() y() = u(), d = du d + u du d + u = 1 + u2 du 2u d = 1 u2 2u u 2u d u 2 1 du = log u 2 1 = log + c (c ) (u 2 1) = C (C 0 ) u() = y y2 2 = C y = ±, C = 0 2 I p9/30

2 (u = y ) [ ] 2yy = 2 + y 2 [ ] d = 2 + y 2 2y = 1 + ` y 2 ` y u() = y() y() = u(), d = du d + u du d + u = 1 + u2 du 2u d = 1 u2 2u u 2u d u 2 1 du = log u 2 1 = log + c (c ) (u 2 1) = C (C 0 ) u() = y y2 2 = C y = ±, C = 0 y 2 2 = C 2 (C ) I p9/30

2 (u = y ) [ ] ( 2y)y = 2 y I p10/30

2 (u = y ) [ ] ( 2y)y = 2 y [ ] d = 2 y 2y = 2 ` y 1 2 ` y I p10/30

2 (u = y ) [ ] ( 2y)y = 2 y [ ] d = 2 y 2y = 2 ` y 1 2 ` y u() = y() y() = u(), d = du d + u I p10/30

2 (u = y ) [ ] ( 2y)y = 2 y [ ] d = 2 y 2y = 2 ` y 1 2 ` y u() = y() y() = u(), d = du d + u du d + u = 2 u du u + u2 = 21 1 2u d (1 2u) u I p10/30

2 (u = y ) [ ] ( 2y)y = 2 y [ ] d = 2 y 2y = 2 ` y 1 2 ` y u() = y() y() = u(), d = du d + u du d + u = 2 u du u + u2 = 21 1 2u d (1 2u) u 1 2u d 1 u + u 2 du = 2 log 1 u + u 2 = 2 log + c (c ) I p10/30

2 (u = y ) [ ] ( 2y)y = 2 y [ ] d = 2 y 2y = 2 ` y 1 2 ` y u() = y() y() = u(), d = du d + u du d + u = 2 u du u + u2 = 21 1 2u d (1 2u) u 1 2u d 1 u + u 2 du = 2 log 1 u + u 2 = 2 log + c (c ) (u 2 u + 1) 2 = C (C 0 ) I p10/30

2 (u = y ) [ ] ( 2y)y = 2 y [ ] d = 2 y 2y = 2 ` y 1 2 ` y u() = y() y() = u(), d = du d + u du d + u = 2 u du u + u2 = 21 1 2u d (1 2u) u 1 2u d 1 u + u 2 du = 2 log 1 u + u 2 = 2 log + c (c ) (u 2 u + 1) 2 = C (C 0 ) u() = y 2 y + y 2 = C I p10/30

2 (u = y ) [ ] ( 2y)y = 2 y [ ] d = 2 y 2y = 2 ` y 1 2 ` y u() = y() y() = u(), d = du d + u du d + u = 2 u du u + u2 = 21 1 2u d (1 2u) u 1 2u d 1 u + u 2 du = 2 log 1 u + u 2 = 2 log + c (c ) (u 2 u + 1) 2 = C (C 0 ) u() = y 2 y + y 2 = C 2 y + y 2 = 0, C = 0 I p10/30

2 (u = y ) [ ] ( 2y)y = 2 y [ ] d = 2 y 2y = 2 ` y 1 2 ` y u() = y() y() = u(), d = du d + u du d + u = 2 u du u + u2 = 21 1 2u d (1 2u) u 1 2u d 1 u + u 2 du = 2 log 1 u + u 2 = 2 log + c (c ) (u 2 u + 1) 2 = C (C 0 ) u() = y 2 y + y 2 = C 2 y + y 2 = 0, C = 0 2 y + y 2 = C (C ) I p10/30

3 I p11/30

3 y y = y(), d = f(), I p12/30

3 y y = y(), d = f(), (, y) M(, y) + N(, y) d = 0 M(, y)d, + N(, y) = 0 I p12/30

3 y y = y(), d = f(), (, y) M(, y) + N(, y) d = 0 M(, y)d, + N(, y) = 0 M(, y)d + N(, y) = 0 (3) I p12/30

3 y y = y(), d = f(), (, y) M(, y) + N(, y) d = 0 M(, y)d, + N(, y) = 0 M(, y)d + N(, y) = 0 (3), y u(, y), M(, y) = u u, N(, y) = y, u(, y) = C (3) I p12/30

3 y y = y(), d = f(), (, y) M(, y) + N(, y) d = 0 M(, y)d, + N(, y) = 0 M(, y)d + N(, y) = 0 (3), y u(, y), M(, y) = u u, N(, y) = y, u(, y) = C (3) u(, y) = C, u(, y()) = C y I p12/30

3 y y = y(), d = f(), (, y) M(, y) + N(, y) d = 0 M(, y)d, + N(, y) = 0 M(, y)d + N(, y) = 0 (3), y u(, y), M(, y) = u u, N(, y) = y, u(, y) = C (3) u(, y) = C, u(, y()) = C y u(, y()) = C, I p12/30

3 y y = y(), d = f(), (, y) M(, y) + N(, y) d = 0 M(, y)d, + N(, y) = 0 M(, y)d + N(, y) = 0 (3), y u(, y), M(, y) = u u, N(, y) = y, u(, y) = C (3) u(, y) = C, u(, y()) = C y u u(, y()) = C, + u = M(, y) + N(, y) y d d = 0 I p12/30

3 y y = y(), d = f(), (, y) M(, y) + N(, y) d = 0 M(, y)d, + N(, y) = 0 M(, y)d + N(, y) = 0 (3), y u(, y), M(, y) = u u, N(, y) = y, u(, y) = C (3) u(, y) = C, u(, y()) = C y u u(, y()) = C, + u = M(, y) + N(, y) y d d = 0 u(, y) = C y, u((y), y) = C y I p12/30

3 y y = y(), d = f(), (, y) M(, y) + N(, y) d = 0 M(, y)d, + N(, y) = 0 M(, y)d + N(, y) = 0 (3), y u(, y), M(, y) = u u, N(, y) = y, u(, y) = C (3) u(, y) = C, u(, y()) = C y u u(, y()) = C, + u = M(, y) + N(, y) y d d = 0 u(, y) = C y, u((y), y) = C y u((y), y) = C y, I p12/30

3 y y = y(), d = f(), (, y) M(, y) + N(, y) d = 0 M(, y)d, + N(, y) = 0 M(, y)d + N(, y) = 0 (3), y u(, y), M(, y) = u u, N(, y) = y, u(, y) = C (3) u(, y) = C, u(, y()) = C y u u(, y()) = C, + u = M(, y) + N(, y) y d d = 0 u(, y) = C y, u((y), y) = C y u d u((y), y) = C y, + u y = M(, y)d + N(, y) = 0 I p12/30

3 y y = y(), d = f(), (, y) M(, y) + N(, y) d = 0 M(, y)d, + N(, y) = 0 M(, y)d + N(, y) = 0 (3), y u(, y), M(, y) = u u, N(, y) = y, u(, y) = C (3) u(, y) = C, u(, y()) = C y u u(, y()) = C, + u = M(, y) + N(, y) y d d = 0 u(, y) = C y, u((y), y) = C y u d u((y), y) = C y, + u y, u(, y) = C (3) = M(, y)d + N(, y) = 0 I p12/30

3 [ ] M(, y) = u u, N(, y) = y, M(, y) y = 2 u N(, y), y = 2 u y, I p13/30

3 [ ] M(, y) = u u, N(, y) = y, M(, y) y = 2 u N(, y), y M(, y) N(, y) = y (u ) = 2 u y, ( ) I p13/30

3 [ ] M(, y) = u u, N(, y) = y, M(, y) y = 2 u N(, y), y = 2 u y, M(, y) N(, y) = ( ) y (u ) ( ), (3) I p13/30

3 [ ] M(, y) = u u, N(, y) = y, M(, y) y = 2 u N(, y), y = 2 u y, M(, y) N(, y) = ( ) y (u ) ( ), (3) [u ] I p13/30

3 [ ] M(, y) = u u, N(, y) = y, M(, y) y = 2 u N(, y), y = 2 u y, M(, y) N(, y) = ( ) y (u ) ( ), (3) [u ] u = M(, y) u(, y) = M(, y)d + k(y), (k(y) y ) I p13/30

3 [ ] M(, y) = u u, N(, y) = y, M(, y) y = 2 u N(, y), y = 2 u y, M(, y) N(, y) = ( ) y (u ) ( ), (3) [u ] u = M(, y) u(, y) = M(, y)d + k(y), (k(y) y ) y u y = y Md + dk k(y) u(, y) = N(, y) I p13/30

3 [ ] M(, y) = u u, N(, y) = y, M(, y) y = 2 u N(, y), y = 2 u y, M(, y) N(, y) = ( ) y (u ) ( ), (3) [u ] u = M(, y) u(, y) = M(, y)d + k(y), y u y = y Md + dk k(y) u(, y) [ ] u(, y) = (k(y) y ) = N(, y) N(, y) + l(), u = M(, y) l() I p13/30

3 [ ] 2sin 3yd + 3 2 cos 3y = 0 I p14/30

3 [ ] 2sin 3yd + 3 2 cos 3y = 0 [ ] y (2 sin3y) = 6 cos3y = (32 cos3y) I p14/30

3 [ ] 2sin 3yd + 3 2 cos 3y = 0 [ ] (2 sin3y) = 6 cos3y = y (32 cos3y) u(, y) = 2 sin3y d + k(y) = 2 sin 3y + k(y) I p14/30

3 [ ] 2sin 3yd + 3 2 cos 3y = 0 [ ] (2 sin3y) = 6 cos3y = y (32 cos3y) u(, y) = 2 sin3y d + k(y) = 2 sin 3y + k(y) y `2 sin3y + k(y) = 3 2 cos3y + dk y = 32 cos3y I p14/30

3 [ ] 2sin 3yd + 3 2 cos 3y = 0 [ ] (2 sin3y) = 6 cos3y = y (32 cos3y) u(, y) = 2 sin3y d + k(y) = 2 sin 3y + k(y) y `2 sin3y + k(y) = 3 2 cos3y + dk y = 32 cos3y dk = 0 I p14/30

3 [ ] 2sin 3yd + 3 2 cos 3y = 0 [ ] (2 sin3y) = 6 cos3y = y (32 cos3y) u(, y) = 2 sin3y d + k(y) = 2 sin 3y + k(y) y `2 sin3y + k(y) = 3 2 cos3y + dk y = 32 cos3y dk = 0 k = C ( ) I p14/30

3 [ ] 2sin 3yd + 3 2 cos 3y = 0 [ ] (2 sin3y) = 6 cos3y = y (32 cos3y) u(, y) = 2 sin3y d + k(y) = 2 sin 3y + k(y) y `2 sin3y + k(y) = 3 2 cos3y + dk y = 32 cos3y dk = 0 k = C ( ) 2 sin3y = C I p14/30

3 [ ] 2 + y 2 = C I p15/30

3 [ ] [ ] 2 + y 2 = C u(, y) = 2 + y 2 I p15/30

3 [ ] 2 + y 2 = C [ ] u(, y) = 2 + y 2 u u d + = 2d + 2y y I p15/30

3 [ ] 2 + y 2 = C [ ] u(, y) = 2 + y 2 u u d + = 2d + 2y y 2d + 2y = 0 ( 2 d + y = 0 ) I p15/30

3 [ ] 2 + y 2 = C [ ] u(, y) = 2 + y 2 u u d + = 2d + 2y y 2d + 2y = 0 ( 2 d + y = 0 ) [ ] yd + = 0 I p15/30

3 [ ] 2 + y 2 = C [ ] u(, y) = 2 + y 2 u u d + = 2d + 2y y 2d + 2y = 0 ( 2 d + y = 0 ) [ ] yd + = 0 [ ] y (y) = 1 = (), I p15/30

3 [ ] 2 + y 2 = C [ ] u(, y) = 2 + y 2 u u d + = 2d + 2y y 2d + 2y = 0 ( 2 d + y = 0 ) [ ] yd + = 0 [ ] y (y) = 1 = (), u(, y) = y d + k(y) = y + k(y) I p15/30

3 [ ] 2 + y 2 = C [ ] u(, y) = 2 + y 2 u u d + = 2d + 2y y 2d + 2y = 0 ( 2 d + y = 0 ) [ ] yd + = 0 [ ] y (y) = 1 = (), u(, y) = y d + k(y) = y + k(y) y dk (y + k(y)) = + y = I p15/30

3 [ ] 2 + y 2 = C [ ] u(, y) = 2 + y 2 u u d + = 2d + 2y y 2d + 2y = 0 ( 2 d + y = 0 ) [ ] yd + = 0 [ ] y (y) = 1 = (), u(, y) = y d + k(y) = y + k(y) y dk = 0 y (y + k(y)) = + dk = I p15/30

3 [ ] 2 + y 2 = C [ ] u(, y) = 2 + y 2 u u d + = 2d + 2y y 2d + 2y = 0 ( 2 d + y = 0 ) [ ] yd + = 0 [ ] y (y) = 1 = (), u(, y) = y d + k(y) = y + k(y) y y dk = 0 k = C ( ) (y + k(y)) = + dk = I p15/30

3 [ ] 2 + y 2 = C [ ] u(, y) = 2 + y 2 u u d + = 2d + 2y y 2d + 2y = 0 ( 2 d + y = 0 ) [ ] yd + = 0 [ ] y (y) = 1 = (), u(, y) = y d + k(y) = y + k(y) y (y + k(y)) = + dk = y dk = 0 k = C ( ) y = C I p15/30

4 I p16/30

4 P(, y)d + Q(, y) = 0, F(, y), F(, y)p(, y)d + F(, y)q(, y) = 0 I p17/30

4 P(, y)d + Q(, y) = 0, F(, y), F(, y)p(, y)d + F(, y)q(, y) = 0 F(, y), I p17/30

4 P(, y)d + Q(, y) = 0, F(, y), F(, y)p(, y)d + F(, y)q(, y) = 0 F(, y), [ ] ( ) ( ) I p17/30

4 P(, y)d + Q(, y) = 0, F(, y), F(, y)p(, y)d + F(, y)q(, y) = 0 F(, y), [ ] ( ) ( ) [ ] F(, y) = 1 2 yd + = 0, I p17/30

4 P(, y)d + Q(, y) = 0, F(, y), F(, y)p(, y)d + F(, y)q(, y) = 0 F(, y), [ ] ( ) ( ) [ ] F(, y) = 1 2 yd + = 0, [ ] F(, y) y 2 d + 1 = 0, I p17/30

4 P(, y)d + Q(, y) = 0, F(, y), F(, y)p(, y)d + F(, y)q(, y) = 0 F(, y), [ ] ( ) ( ) [ ] F(, y) = 1 2 yd + = 0, [ ] F(, y) y 2 d + 1 = 0 y, = C I p17/30

4 [ ] F(, y) = 1 2 +y 2 yd + = 0, I p18/30

4 [ ] F(, y) = 1 2 +y 2 yd + = 0, [ ] F(, y), y 2 + y 2 d + 2 + y 2 = 0 I p18/30

4 [ ] F(, y) = 1 2 +y 2 yd + = 0, [ ] F(, y), y y 2 + y 2 y 2 + y 2 d + «= y2 2 ( 2 + y 2 ) 2 = 2 + y 2 = 0 2 + y 2 «I p18/30

4 [ ] F(, y) = 1 2 +y 2 yd + = 0, [ ] F(, y), y y 2 + y 2 y u(, y) = 2 d + k(y) + y2 y 2 + y 2 d + «= y2 2 ( 2 + y 2 ) 2 = 2 + y 2 = 0 2 + y 2 «I p18/30

4 [ ] F(, y) = 1 2 +y 2 yd + = 0, [ ] F(, y) y 2 + y 2 d + 2 + y 2 = 0, y «y 2 + y 2 = y2 2 ( 2 + y 2 ) 2 = «2 + y 2 y u(, y) = 2 + y 2 d + k(y) = 1 1 y 2 d + k(y) 1 + y I p18/30

4 [ ] F(, y) = 1 2 +y 2 yd + = 0, [ ] F(, y) y 2 + y 2 d + 2 + y 2 = 0, y «y 2 + y 2 = y2 2 ( 2 + y 2 ) 2 = «2 + y 2 y u(, y) = 2 + y 2 d + k(y) = 1 1 y 2 d + k(y) = tan 1 1 + y + k(y) y I p18/30

4 [ ] F(, y) = 1 2 +y 2 yd + = 0, [ ] F(, y) y 2 + y 2 d + 2 + y 2 = 0, y «y 2 + y 2 = y2 2 ( 2 + y 2 ) 2 = «2 + y 2 y u(, y) = 2 + y 2 d + k(y) = 1 1 y 2 d + k(y) = tan 1 1 + y + k(y) y y tan 1 y «y + k(y) = 1 1 + y 2 y 2 + dk = 2 + y 2 I p18/30

4 [ ] F(, y) = 1 2 +y 2 yd + = 0, [ ] F(, y) y 2 + y 2 d + 2 + y 2 = 0, y «y 2 + y 2 = y2 2 ( 2 + y 2 ) 2 = «2 + y 2 y u(, y) = 2 + y 2 d + k(y) = 1 1 y 2 d + k(y) = tan 1 1 + y + k(y) y y tan 1 y «y + k(y) = dk = 0 1 1 + y 2 y 2 + dk = 2 + y 2 I p18/30

4 [ ] F(, y) = 1 2 +y 2 yd + = 0, [ ] F(, y) y 2 + y 2 d + 2 + y 2 = 0, y «y 2 + y 2 = y2 2 ( 2 + y 2 ) 2 = «2 + y 2 y u(, y) = 2 + y 2 d + k(y) = 1 1 y 2 d + k(y) = tan 1 1 + y + k(y) y y tan 1 y «y + k(y) = dk = 0 k = C ( ) 1 1 + y 2 y 2 + dk = 2 + y 2 I p18/30

4 [ ] F(, y) = 1 2 +y 2 yd + = 0, [ ] F(, y) y 2 + y 2 d + 2 + y 2 = 0, y «y 2 + y 2 = y2 2 ( 2 + y 2 ) 2 = «2 + y 2 y u(, y) = 2 + y 2 d + k(y) = 1 1 y 2 d + k(y) = tan 1 1 + y + k(y) y y tan 1 y «y + k(y) = 1 1 + y 2 y 2 + dk = dk = 0 k = C ( ) tan 1 y = C 2 + y 2 I p18/30

4 [ ], F I p19/30

4 [ ], F (i) F = F() ( ), F = F(y) (y ) I p19/30

4 [ ], F (i) F = F() ( ), F = F(y) (y ) (ii) F = m y n I p19/30

4 [ ], F (i) F = F() ( ), F = F(y) (y ) (ii) F = m y n (iii) F = F( + y), F = F( y), F = F(y) I p19/30

4 [ ], F (i) F = F() ( ), F = F(y) (y ) (ii) F = m y n (iii) F = F( + y), F = F( y), F = F(y) [ ] (y + y 2 )d + ( 2 y) = 0, I p19/30

4 [ ], F (i) F = F() ( ), F = F(y) (y ) (ii) F = m y n (iii) F = F( + y), F = F( y), F = F(y) [ ] (y + y 2 )d + ( 2 y) = 0, [ ] y (y + y2 ) = + 2y 2 y = (2 y), I p19/30

4 [ ], F (i) F = F() ( ), F = F(y) (y ) (ii) F = m y n (iii) F = F( + y), F = F( y), F = F(y) [ ] (y + y 2 )d + ( 2 y) = 0, [ ] y (y + y2 ) = + 2y 2 y = (2 y), F(, y) = m y n, I p19/30

4 [ ], F (i) F = F() ( ), F = F(y) (y ) (ii) F = m y n (iii) F = F( + y), F = F( y), F = F(y) [ ] (y + y 2 )d + ( 2 y) = 0, [ ] y (y + y2 ) = + 2y 2 y = (2 y), F(, y) = m y n, y (m+1 y n+1 + m y n+2 ) = (m+2 y n m+1 y n+1 ) I p19/30

4 [ ], F (i) F = F() ( ), F = F(y) (y ) (ii) F = m y n (iii) F = F( + y), F = F( y), F = F(y) [ ] (y + y 2 )d + ( 2 y) = 0, [ ] y (y + y2 ) = + 2y 2 y = (2 y), F(, y) = m y n, y (m+1 y n+1 + m y n+2 ) = (m+2 y n m+1 y n+1 ) m = 2, n = 1 I p19/30

4 [ ], F (i) F = F() ( ), F = F(y) (y ) (ii) F = m y n (iii) F = F( + y), F = F( y), F = F(y) [ ] (y + y 2 )d + ( 2 y) = 0, [ ] y (y + y2 ) = + 2y 2 y = (2 y), F(, y) = m y n, y (m+1 y n+1 + m y n+2 ) = (m+2 y n m+1 y n+1 ) m = 2, n = 1 F(, y) = 1 2 y 1 + y «1 2 d + y 1 «= 0 I p19/30

4 [ ], F (i) F = F() ( ), F = F(y) (y ) (ii) F = m y n (iii) F = F( + y), F = F( y), F = F(y) [ ] (y + y 2 )d + ( 2 y) = 0, [ ] y (y + y2 ) = + 2y 2 y = (2 y), F(, y) = m y n, y (m+1 y n+1 + m y n+2 ) = (m+2 y n m+1 y n+1 ) m = 2, n = 1 F(, y) = 1 2 y 1 + y «1 2 d + y 1 «= 0, y = Ce y (C 0) I p19/30

4 [ ] (4 2 y 3 2y)d + (3 3 y 2 ) = 0 F = F(), I p20/30

4 [ ] (4 2 y 3 2y)d + (3 3 y 2 ) = 0 F = F(), [ ] y (42 y 3 2y) = 12 2 y 2 2 9 2 y 2 1 = (33 y 2 ), I p20/30

4 [ ] (4 2 y 3 2y)d + (3 3 y 2 ) = 0 F = F(), [ ] y (42 y 3 2y) = 12 2 y 2 2 9 2 y 2 1 = (33 y 2 ), F = F(), I p20/30

4 [ ] (4 2 y 3 2y)d + (3 3 y 2 ) = 0 F = F(), [ ] y (42 y 3 2y) = 12 2 y 2 2 9 2 y 2 1 = (33 y 2 ), F = F(), F(4 2 y 3 2y) = F(12 2 y 2 2) = F (3 3 y 2 ) + F(9 2 y 2 1) = F(3 3 y 2 ) y I p20/30

4 [ ] (4 2 y 3 2y)d + (3 3 y 2 ) = 0 F = F(), [ ] y (42 y 3 2y) = 12 2 y 2 2 9 2 y 2 1 = (33 y 2 ), F = F(), F(4 2 y 3 2y) = F(12 2 y 2 2) = F (3 3 y 2 ) + F(9 2 y 2 1) = F(3 3 y 2 ) y df d = 1 F I p20/30

4 [ ] (4 2 y 3 2y)d + (3 3 y 2 ) = 0 F = F(), [ ] y (42 y 3 2y) = 12 2 y 2 2 9 2 y 2 1 = (33 y 2 ), F = F(), F(4 2 y 3 2y) = F(12 2 y 2 2) = F (3 3 y 2 ) + F(9 2 y 2 1) = F(3 3 y 2 ) y df d = 1 F df F = d I p20/30

4 [ ] (4 2 y 3 2y)d + (3 3 y 2 ) = 0 F = F(), [ ] y (42 y 3 2y) = 12 2 y 2 2 9 2 y 2 1 = (33 y 2 ), F = F(), F(4 2 y 3 2y) = F(12 2 y 2 2) = F (3 3 y 2 ) + F(9 2 y 2 1) = F(3 3 y 2 ) y df d = 1 df d F F = F() = (4 3 y 3 2y)d + (3 4 y 2 2 ) = 0 I p20/30

4 [ ] (4 2 y 3 2y)d + (3 3 y 2 ) = 0 F = F(), [ ] y (42 y 3 2y) = 12 2 y 2 2 9 2 y 2 1 = (33 y 2 ), F = F(), F(4 2 y 3 2y) = F(12 2 y 2 2) = F (3 3 y 2 ) + F(9 2 y 2 1) = F(3 3 y 2 ) y df d = 1 df d F F = F() = (4 3 y 3 2y)d + (3 4 y 2 2 ) = 0, 4 y 3 2 y = C I p20/30

5 ( ) I p21/30

5 ( ), y = y() + p()y = q() (4) d I p22/30

5 ( ), y = y() + p()y = q() (4) d, d + p()y = 0 ( ) I p22/30

5 ( ), y = y() + p()y = q() (4) d, d + p()y = 0 ( ), (4) I p22/30

5 ( ), y = y() + p()y = q() (4) d, d + p()y = 0 ( ), (4) ( ) y = p()d y = C ep{ p()d} (C ) I p22/30

5 ( ), y = y() + p()y = q() (4) d, d + p()y = 0 ( ), (4) ( ) y = p()d y = C ep{ p()d}, C = C() (4) (C ) I p22/30

5 ( ), y = y() + p()y = q() (4) d, d + p()y = 0 ( ), (4) ( ) y = p()d y = C ep{ p()d} (C ), C = C() (4) dc + p()y = d d ep{ p()d} Cp() ep{ p()d} + p()c ep{ p()d} I p22/30

5 ( ), y = y() + p()y = q() (4) d, d + p()y = 0 ( ), (4) ( ) y = p()d y = C ep{ p()d} (C ), C = C() (4) dc + p()y = d d ep{ p()d} Cp() ep{ p()d} + p()c ep{ p()d} I p22/30

5 ( ), y = y() + p()y = q() (4) d, d + p()y = 0 ( ), (4) ( ) y = p()d y = C ep{ p()d} (C ), C = C() (4) dc + p()y = d d ep{ p()d} Cp() ep{ p()d} + p()c ep{ p()d} = dc d ep{ p()d} = q() I p22/30

5 ( ), y = y() + p()y = q() (4) d, d + p()y = 0 ( ), (4) ( ) y = p()d y = C ep{ p()d} (C ), C = C() (4) dc + p()y = d d ep{ p()d} Cp() ep{ p()d} + p()c ep{ p()d} = dc d ep{ p()d} = q() dc = q() ep{ p()d} d I p22/30

5 ( ), y = y() + p()y = q() (4) d, d + p()y = 0 ( ), (4) ( ) y = p()d y = C ep{ p()d} (C ), C = C() (4) dc + p()y = d d ep{ p()d} Cp() ep{ p()d} + p()c ep{ p()d} = dc d ep{ p()d} = q() dc = q() ep{ p()d} C() = q() ep{ p()d}d, d I p22/30

5 ( ), y = y() + p()y = q() (4) d, d + p()y = 0 ( ), (4) ( ) y = p()d y = C ep{ p()d} (C ), C = C() (4) dc + p()y = d d ep{ p()d} Cp() ep{ p()d} + p()c ep{ p()d} = dc d ep{ p()d} = q() dc = q() ep{ p()d} C() = q() ep{ p()d}d, (4) d «y = q() ep{ p()d}d ep{ p()d} I p22/30

5 ( ) [ ] y + 2 2 + 1 y = 4 (5) I p23/30

5 ( ) [ ] y + 2 2 + 1 y = 4 (5) [ ] d + 2 2 + 1 y = 0 I p23/30

5 ( ) [ ] y + 2 2 + 1 y = 4 (5) [ ] d + 2 2 + 1 y = 0 log y = log( 2 + 1) + c y = C 2 + 1 I p23/30

5 ( ) [ ] y + 2 2 + 1 y = 4 (5) [ ] d + 2 2 + 1 y = 0 log y = log( 2 + 1) + c y = C 2 + 1 y = C() 2 + 1 (5) I p23/30

5 ( ) [ ] y + 2 2 + 1 y = 4 (5) [ ] d + 2 2 + 1 y = 0 log y = log( 2 + 1) + c y = C 2 + 1 y = C() 2 + 1 (5) C 2 + 1 = 4 ie C = 4( 2 + 1) I p23/30

5 ( ) [ ] y + 2 2 + 1 y = 4 (5) [ ] d + 2 2 + 1 y = 0 log y = log( 2 + 1) + c y = C 2 + 1 y = C() 2 + 1 (5) C 2 + 1 = 4 ie C = 4( 2 + 1) C() = 4 + 2 2 + c (c ) I p23/30

5 ( ) [ ] y + 2 2 + 1 y = 4 (5) [ ] d + 2 2 + 1 y = 0 log y = log( 2 + 1) + c y = C 2 + 1 y = C() 2 + 1 (5) C 2 + 1 = 4 ie C = 4( 2 + 1) C() = 4 + 2 2 + c (c ) y = 4 + 2 2 + c 2 + 1 (c ) I p23/30

5 ( ) [ ] y 1 y = cos (6) I p24/30

5 ( ) [ ] y 1 y = cos (6) [ ] d 1 y = 0 I p24/30

5 ( ) [ ] y 1 y = cos (6) [ ] d 1 y = 0 log y = log + c y = C I p24/30

5 ( ) [ ] y 1 y = cos (6) [ ] d 1 y = 0 log y = log + c y = C y = C() (6) I p24/30

5 ( ) [ ] y 1 y = cos (6) [ ] d 1 y = 0 log y = log + c y = C y = C() (6) C = cos ie C = cos I p24/30

5 ( ) [ ] y 1 y = cos (6) [ ] d 1 y = 0 log y = log + c y = C y = C() (6) C = cos ie C = cos C() = sin + c (c ) I p24/30

5 ( ) [ ] y 1 y = cos (6) [ ] d 1 y = 0 log y = log + c y = C y = C() (6) C = cos ie C = cos C() = sin + c (c ) y = sin + c (c ) I p24/30

6 I p25/30

6 [ ] I p26/30

6 [ ] y = f(a + by + c) u = a + by + c I p26/30

6 [ ] y = f(a + by + c) u = a + by + c [ ] y = ( + y) 2 I p26/30

6 [ ] y = f(a + by + c) u = a + by + c [ ] y = ( + y) 2 [ ] y = tan( + c) (c ) I p26/30

6 [ ] I p27/30

6 [ ] y = y + f(y ) I p27/30

6 [ ] y = y + f(y ), p = y y = p + f(p) y = p + p + f (p)p ( + f (p))p = 0 I p27/30

6 [ ] y = y + f(y ), p = y y = p + f(p) y = p + p + f (p)p ( + f (p))p = 0 p = 0, p = C ( ) I p27/30

6 [ ] y = y + f(y ), p = y y = p + f(p) y = p + p + f (p)p ( + f (p))p = 0 p = 0, p = C ( ) y = C + f(c) ( ) I p27/30

6 [ ] y = y + f(y ), p = y y = p + f(p) y = p + p + f (p)p ( + f (p))p = 0 p = 0, p = C ( ) y = C + f(c) ( ) + f (p) = 0, p I p27/30

6 [ ] y = y + f(y ), p = y y = p + f(p) y = p + p + f (p)p ( + f (p))p = 0 p = 0, p = C ( ) y = C + f(c) ( ) + f (p) = 0, p = f (p) y = p + f(p) ( ) I p27/30

6 [ ] y = y + f(y ), p = y y = p + f(p) y = p + p + f (p)p ( + f (p))p = 0 p = 0, p = C ( ) y = C + f(c) ( ) + f (p) = 0, p [ ] = f (p) y = p + f(p) ( ) y = y + 1 2 (y ) 2 I p27/30

6 [ ] y = y + f(y ), p = y y = p + f(p) y = p + p + f (p)p ( + f (p))p = 0 p = 0, p = C ( ) y = C + f(c) ( ) + f (p) = 0, p [ ] = f (p) y = p + f(p) ( ) y = y + 1 2 (y ) 2 [ ] y = C + 1 2 C2 y = 1 2 2 I p27/30

6 [ ] I p28/30

6 [ ] y + p()y = q()y α (α 0,1) u = y (1 α), (1 α)y α (1 α)y α y + (1 α)p()y (1 α) = (1 α)q(), : I p28/30

6 [ ] y + p()y = q()y α (α 0,1) u = y (1 α), (1 α)y α (1 α)y α y + (1 α)p()y (1 α) = (1 α)q(), : u + (1 α)p()u = (1 α)q() I p28/30

6 [ ] y + p()y = q()y α (α 0,1) u = y (1 α), (1 α)y α (1 α)y α y + (1 α)p()y (1 α) = (1 α)q(), : u + (1 α)p()u = (1 α)q() [ ] y + y = 4( + 1) y I p28/30

6 [ ] y + p()y = q()y α (α 0,1) u = y (1 α), (1 α)y α (1 α)y α y + (1 α)p()y (1 α) = (1 α)q(), : [ ] y + y = u + (1 α)p()u = (1 α)q() 4( + 1) y [ ] y 2 = ce 2 + 4 2 (c ) I p28/30

6 [ ] I p29/30

6 [ ] y = p()y 2 + q()y + r() I p29/30

6 [ ] y = p()y 2 + q()y + r() y = y 1 () y = y 1 () + 1 u I p29/30

6 [ ] y = p()y 2 + q()y + r() y = y 1 () y = y 1 () + 1 u y 1() u u 2 = p() y 1 () + 1 «2 + q() y 1 () + 1 «+ r() u u I p29/30

6 [ ] y = p()y 2 + q()y + r() y = y 1 () y = y 1 () + 1 u y 1() u u 2 = p() y 1 () + 1 «2 + q() y 1 () + 1 «+ r() u u u 2 y 1()u 2 u = p()(y 1 ()u + 1) 2 + q() `y 1 ()u 2 + u + r()u 2 I p29/30

6 [ ] y = p()y 2 + q()y + r() y = y 1 () y = y 1 () + 1 u y 1() u u 2 = p() y 1 () + 1 «2 + q() y 1 () + 1 «+ r() u u u 2 y 1()u 2 u = p()(y 1 ()u + 1) 2 + q() `y 1 ()u 2 + u + r()u 2 u u + (2p()y 1 () + q()) u = p() I p29/30

6 [ ] y = p()y 2 + q()y + r() y = y 1 () y = y 1 () + 1 u y 1() u u 2 = p() y 1 () + 1 «2 + q() y 1 () + 1 «+ r() u u u 2 y 1()u 2 u = p()(y 1 ()u + 1) 2 + q() `y 1 ()u 2 + u + r()u 2 u u + (2p()y 1 () + q()) u = p() u y = y 1 () + 1 u() I p29/30

6 [ ] y = p()y 2 + q()y + r() y = y 1 () y = y 1 () + 1 u y 1() u u 2 = p() y 1 () + 1 «2 + q() y 1 () + 1 «+ r() u u u 2 y 1()u 2 u = p()(y 1 ()u + 1) 2 + q() `y 1 ()u 2 + u + r()u 2 u u + (2p()y 1 () + q()) u = p() u y = y 1 () + 1 u() [ ] y = y 2 (2 1)y + 1 I p29/30

6 [ ] y = p()y 2 + q()y + r() y = y 1 () y = y 1 () + 1 u y 1() u u 2 = p() y 1 () + 1 «2 + q() y 1 () + 1 «+ r() u u u 2 y 1()u 2 u = p()(y 1 ()u + 1) 2 + q() `y 1 ()u 2 + u + r()u 2 u u + (2p()y 1 () + q()) u = p() u y = y 1 () + 1 u() [ ] y = y 2 (2 1)y + 1 [ ] y = 1 y = 1 + 1 1 + Ce (C ) I p29/30

6 [ ] I p30/30

6 [ ] y, F(, y, y ) = 0, y = p p I p30/30

6 [ ] y, F(, y, y ) = 0, y = p p [ ] y + y = 0 I p30/30

6 [ ] y, F(, y, y ) = 0, y = p p [ ] y + y = 0 [ ] y = C 1 log + C 2 (C 1, C 2 ) I p30/30

6 [ ] y, F(, y, y ) = 0, y = p p [ ] y + y = 0 [ ] y = C 1 log + C 2 (C 1, C 2 ) y, F(y, y, y ) = 0, y = p y = dp p, y p I p30/30

6 [ ] y, F(, y, y ) = 0, y = p p [ ] y + y = 0 [ ] y = C 1 log + C 2 (C 1, C 2 ) y, F(y, y, y ) = 0, y = p y = dp p, y p [ ] y + (y ) 2 = 0 I p30/30

6 [ ] y, F(, y, y ) = 0, y = p p [ ] y + y = 0 [ ] y = C 1 log + C 2 (C 1, C 2 ) y, F(y, y, y ) = 0, y = p y = dp p, y p [ ] y + (y ) 2 = 0 [ ] y = log(c 1 + C 2 ) (C 1, C 2 ) I p30/30