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1

2 a) Dutsch-Jozsa b) Grovr s c) Shor s

3 3 PD I Mchal A. Nlsn and Isaac L. Chuang, Quantum Computaton and Quantum Inormaton, Cambrdg Unvrsty Prss

4 N N log N L [=(999)] NN N N+

5 d V (, y,z ) dt m y z () ( t ) U( t ) ( ) t t t t U( t ) I!! 3! 3 () U(t) UU * I t U ( t ) U( ) ( ) ( t ) U( t ) ( t ) ( 3t ) U( t ) ( t ) n U U U n n U'

6 z I> ( t) a( t) b( t) a( t ) b( t ) z I z I I> I Z = a A a a a A * a a * * a a * * t t t t U( t ) I!! 3! 3 UU * I

7 (NOT R U R U U R ) b( t ) a( t ) t b( ) t a( ) t ( U R U R U R U R k k R U X(I X ) I U U R R *

8 (controlld NOT) 3,,,,,,,,,,,, U CN U CN, U CN, U,. CN U CN a a a3 a4 UCN a a a3 a4 N n U CN * UCNUCN I

9 NOT b a,, a b AND c a b a a b b c b Controlld NOT NOT a b a b a A b a b a A b c XOR a b a b a b a b c B A B

10 X Z Y Paul matrcs adamard gat U R X Y Z y z sn cos, sn cos I

11 adamard gat y looks lk a squar-root o NOT gat, though s not a NOT gat. y y

12 y z sn cos cos sn sn cos X sn I cos R X cos sn sn cos Y sn I cos R Y y Z z Z sn I cos R, y, z

13 A NOT B A NOT A B A B AB A,B A,A B A B, A B,A B B,A B A B B B, A,,,,,,

14 a b c NOT NOTcontrolld controlld NOT a a, b b, a c b c c a b a b c c c a b a b c a b NOT NOT AND b c c b,c c a c b c c a b

15 NOT3 NOTcontrolld controlld NOT a a b b c c U CCN a a, b b, a c b c c c a b c CCN CCN

16 a a b b c c d= d

17 (U R ) (U CN ) UCN a a a3 a4 ( >, >, >, >) a,,,, 3 a a a 3 a 4

18 b a d y K y ) ( ), ( ) ( ~ b a y K y,, ), ( ) ( ), ( ) ( ~ N y K y * ) ( ~ ), ( ) ( N y K y ) ( ~ ) ( N y N y y U adamard gat y y y ) ( ) ( ) ( ~ y y y N y

19 n j R R n- R n. j j n j R n- R n-. j j n j n R. jn j n j n. j n R jk jk jk jk jk jk jk p k j jk j k R jk jk

20 j R R 3 j R j 3 R R Stp R( ) R( ) p Stp 3 R3( 3) R3( 3) Stp 4 Stp 5 R(3) Stp 6 3 Stp 7 hjk kjh Stp

21 Quantum algorthms Dutsch-Jozsa algorthm Grovr s algorthm Shor s algorthms

22 Dutsch-Jozsa algorthm ( ) :, U, y, y U y y () U,,, Walsh-adamard transorm

23 Dutsch-Jozsa algorthm n n U y y () n n,,,, n n

24 Dutsch-Jozsa algorthm Dutsch y ) ( y U 3 U 3 3 3

25 Dutsch-Jozsa algorthm n :,,,, constant : () s constant balancd : () s hal and hal Msson : Judg whthr () s constant or balancd. n n U y y () 3 n n, n n 3 n z z n z

26 Eampl: n= n n (,,,) (,,,) ) ( or (,,,) ) ( (,,,) ) ( y ) ( y U n Gt () s constant. 3

27 Grovr s algorthm () N= n N- N N n n G G G G n n N Phas n

28 Grovr s algorthm () G n n Phas n ()= n P n n n I I I k k k k k k <>

29 Grovr s algorthm (3) 4 n n=

30 5=35 5, 53, 54 m n n N Fn m mod N Fn n mod5 N=5, m=

31 Fn n mod5 N=5, m= F = 5 F = 5 F = 5 4 r= F 3 = 3 5 F 4 = 4 5 F 5 = 5 5 F 6 = r m r m F 7 = 7 5

32 Fn n mod5 N=5, m= F = 5 F = 5 F = 5 F 3 = 3 5 F 4 = 4 5 F 5 = 5 5 F 6 = 6 5 F 7 = 7 5 r= r m r m N=5 r

33 F n n (mod 5) F F F F 3 4 F 4 F 5 F 6 4 F 7 X (n) Fn n mod5 Y n (mod 5) 3 3

34 F n n (mod 5) F F F F 3 4 F 4 F 5 F 6 4 F 7 X (n) Fn n mod5 Y n (mod 5) XY 3 3,

35 F n mod5 X(n) n Y n (mod 5) 3 3 n (mod 5) r=4

36 Shor s algorthm () : X 3()r= , :,Y X ()r 7 7, ',k k

37 Shor s algorthm () ()r=()=()=(4)=(6) ()=(3)=(5)=(7) ' ,,,, ' X4

38 Shor s algorthm (3) kk=, n r, n r, 3 n r, (r-) n r n=3k=,4r= kk=, n r, n r, 3 n r, (r-) n rr 7r= 7 =Xk=, 6, 3, 4, k 7 7 4,4,,,, k 5 k k r=5%

39 ()=k, k=,,, N-k y U U y, U y N, p( N),, y,,..., N k () k ( ) N k ( ) k N N U k k N=, k= U k ( ) ( k ), U k bk, bk, bk, N N N=6, k=4, g ( ) 4. g k 4

40 .. 3. # S N # #3 #4 #5 #6

41 n

42 ono

43 (n) n T t s T () t s

44 T? t s. (Kz) 7 K

45 QED NMR :, STM,...

46 * Vandrsypn APL Vandrsypn PRL Vandrsypn Natur actorng 5 Chuang Natur 9 Dlt NEC Vandrsypn PRL 99

140 120 100 80 60 40 20 0 115 107 102 99 95 97 95 97 98 100 64 72 37 60 50 53 50 36 32 18 H18 H19 H20 H21 H22 H23 H24 H25 H26 H27 1 100 () 80 60 40 20 0 1 19 16 10 11 6 8 9 5 10 35 76 83 73 68 46 44 H11

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7 27 7.1........................................ 27 7.2.......................................... 28 1 ( a 3 = 3 = 3 a a > 0(a a a a < 0(a a a -1 1 6 26 11 5 1 ( 2 2 2 3 5 3.1...................................... 5 3.2....................................... 5 3.3....................................... 6 3.4....................................... 7

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x, y x 3 y xy 3 x 2 y + xy 2 x 3 + y 3 = x 3 y xy 3 x 2 y + xy 2 x 3 + y 3 = 15 xy (x y) (x + y) xy (x y) (x y) ( x 2 + xy + y 2) = 15 (x y) x, y x 3 y xy 3 x 2 y + xy 2 x 3 + y 3 = 15 1 1977 x 3 y xy 3 x 2 y + xy 2 x 3 + y 3 = 15 xy (x y) (x + y) xy (x y) (x y) ( x 2 + xy + y 2) = 15 (x y) ( x 2 y + xy 2 x 2 2xy y 2) = 15 (x y) (x + y) (xy

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