Microsoft Word - 表紙.docx

Similar documents
6.1 (P (P (P (P (P (P (, P (, P.

6.1 (P (P (P (P (P (P (, P (, P.101

..3. Ω, Ω F, P Ω, F, P ). ) F a) A, A,..., A i,... F A i F. b) A F A c F c) Ω F. ) A F A P A),. a) 0 P A) b) P Ω) c) [ ] A, A,..., A i,... F i j A i A

微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 初版 1 刷発行時のものです.

x () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x

solutionJIS.dvi

renshumondai-kaito.dvi

A B P (A B) = P (A)P (B) (3) A B A B P (B A) A B A B P (A B) = P (B A)P (A) (4) P (B A) = P (A B) P (A) (5) P (A B) P (B A) P (A B) A B P

ii 3.,. 4. F. ( ), ,,. 8.,. 1. (75% ) (25% ) =7 24, =7 25, =7 26 (. ). 1.,, ( ). 3.,...,.,.,.,.,. ( ) (1 2 )., ( ), 0., 1., 0,.

ii 3.,. 4. F. (), ,,. 8.,. 1. (75%) (25%) =7 20, =7 21 (. ). 1.,, (). 3.,. 1. ().,.,.,.,.,. () (12 )., (), 0. 2., 1., 0,.

Part () () Γ Part ,

統計学のポイント整理

( )/2 hara/lectures/lectures-j.html 2, {H} {T } S = {H, T } {(H, H), (H, T )} {(H, T ), (T, T )} {(H, H), (T, T )} {1

.3. (x, x = (, u = = 4 (, x x = 4 x, x 0 x = 0 x = 4 x.4. ( z + z = 8 z, z 0 (z, z = (0, 8, (,, (8, 0 3 (0, 8, (,, (8, 0 z = z 4 z (g f(x = g(

,. Black-Scholes u t t, x c u 0 t, x x u t t, x c u t, x x u t t, x + σ x u t, x + rx ut, x rux, t 0 x x,,.,. Step 3, 7,,, Step 6., Step 4,. Step 5,,.

1/1 lim f(x, y) (x,y) (a,b) ( ) ( ) lim limf(x, y) lim lim f(x, y) x a y b y b x a ( ) ( ) xy x lim lim lim lim x y x y x + y y x x + y x x lim x x 1

ii 3.,. 4. F. (), ,,. 8.,. 1. (75% ) (25% ) =9 7, =9 8 (. ). 1.,, (). 3.,. 1. ( ).,.,.,.,.,. ( ) (1 2 )., ( ), 0. 2., 1., 0,.

body.dvi

chap9.dvi

II A A441 : October 02, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka )

Morse ( ) 2014

all.dvi

n Y 1 (x),..., Y n (x) 1 W (Y 1 (x),..., Y n (x)) 0 W (Y 1 (x),..., Y n (x)) = Y 1 (x)... Y n (x) Y 1(x)... Y n(x) (x)... Y n (n 1) (x) Y (n 1)

2011de.dvi


No δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i x j δx j (5) δs 2

L P y P y + ɛ, ɛ y P y I P y,, y P y + I P y, 3 ŷ β 0 β y β 0 β y β β 0, β y x x, x,, x, y y, y,, y x x y y x x, y y, x x y y {}}{,,, / / L P / / y, P

notekiso1_09.dvi

応用数学III-4.ppt

v er.1/ c /(21)

f(x) = f(x ) + α(x)(x x ) α(x) x = x. x = f (y), x = f (y ) y = f f (y) = f f (y ) + α(f (y))(f (y) f (y )) f (y) = f (y ) + α(f (y)) (y y ) ( (2) ) f

1.2 y + P (x)y + Q(x)y = 0 (1) y 1 (x), y 2 (x) y 1 (x), y 2 (x) (1) y(x) c 1, c 2 y(x) = c 1 y 1 (x) + c 2 y 2 (x) 3 y 1 (x) y 1 (x) e R P (x)dx y 2

II (10 4 ) 1. p (x, y) (a, b) ε(x, y; a, b) 0 f (x, y) f (a, b) A, B (6.5) y = b f (x, b) f (a, b) x a = A + ε(x, b; a, b) x a 2 x a 0 A = f x (

M3 x y f(x, y) (= x) (= y) x + y f(x, y) = x + y + *. f(x, y) π y f(x, y) x f(x + x, y) f(x, y) lim x x () f(x,y) x 3 -

9. 05 L x P(x) P(0) P(x) u(x) u(x) (0 < = x < = L) P(x) E(x) A(x) P(L) f ( d EA du ) = 0 (9.) dx dx u(0) = 0 (9.2) E(L)A(L) du (L) = f (9.3) dx (9.) P

meiji_resume_1.PDF

i

populatio sample II, B II? [1] I. [2] 1 [3] David J. Had [4] 2 [5] 3 2

DVIOUT

R R 16 ( 3 )

医系の統計入門第 2 版 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 第 2 版 1 刷発行時のものです.

chap10.dvi


() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)

III ϵ-n ϵ-n lim n a n = α n a n α 1 lim a n = 0 1 n a k n n k= ϵ-n 1.1


() Remrk I = [0, ] [x i, x i ]. (x : ) f(x) = 0 (x : ) ξ i, (f) = f(ξ i )(x i x i ) = (x i x i ) = ξ i, (f) = f(ξ i )(x i x i ) = 0 (f) 0.

(2 X Poisso P (λ ϕ X (t = E[e itx ] = k= itk λk e k! e λ = (e it λ k e λ = e eitλ e λ = e λ(eit 1. k! k= 6.7 X N(, 1 ϕ X (t = e 1 2 t2 : Cauchy ϕ X (t

II 2 II

ax 2 + bx + c = n 8 (n ) a n x n + a n 1 x n a 1 x + a 0 = 0 ( a n, a n 1,, a 1, a 0 a n 0) n n ( ) ( ) ax 3 + bx 2 + cx + d = 0 4

8.1 Fubini 8.2 Fubini 9 (0%) 10 (50%) Carathéodory 10.3 Fubini 1 Introduction 1 (1) (2) {f n (x)} n=1 [a, b] K > 0 n, x f n (x) K < ( ) x [a

ad bc A A A = ad bc ( d ) b c a n A n A n A A det A A ( ) a b A = c d det A = ad bc σ {,,,, n} {,,, } {,,, } {,,, } ( ) σ = σ() = σ() = n sign σ sign(

x (x, ) x y (, y) iy x y z = x + iy (x, y) (r, θ) r = x + y, θ = tan ( y ), π < θ π x r = z, θ = arg z z = x + iy = r cos θ + ir sin θ = r(cos θ + i s

l µ l µ l 0 (1, x r, y r, z r ) 1 r (1, x r, y r, z r ) l µ g µν η µν 2ml µ l ν 1 2m r 2mx r 2 2my r 2 2mz r 2 2mx r 2 1 2mx2 2mxy 2mxz 2my r 2mz 2 r

n=1 1 n 2 = π = π f(z) f(z) 2 f(z) = u(z) + iv(z) *1 f (z) u(x, y), v(x, y) f(z) f (z) = f/ x u x = v y, u y = v x

mugensho.dvi

I, II 1, A = A 4 : 6 = max{ A, } A A 10 10%

st.dvi

24 I ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x

1 (1) () (3) I 0 3 I I d θ = L () dt θ L L θ I d θ = L = κθ (3) dt κ T I T = π κ (4) T I κ κ κ L l a θ L r δr δl L θ ϕ ϕ = rθ (5) l

tokei01.dvi

, 1 ( f n (x))dx d dx ( f n (x)) 1 f n (x)dx d dx f n(x) lim f n (x) = [, 1] x f n (x) = n x x 1 f n (x) = x f n (x) = x 1 x n n f n(x) = [, 1] f n (x

i

A

,,,,., = (),, (1) (4) :,,,, (1),. (2),, =. (3),,. (4),,,,.. (1) (3), (4).,,., () : = , ( ) : = F 1 + F 2 + F 3 + ( ) : = i Fj j=1 2

(, ) (, ) S = 2 = [, ] ( ) 2 ( ) 2 2 ( ) 3 2 ( ) 4 2 ( ) k 2,,, k =, 2, 3, 4 S 4 S 4 = ( ) 2 + ( ) ( ) (

r 1 m A r/m i) t ii) m i) t B(t; m) ( B(t; m) = A 1 + r ) mt m ii) B(t; m) ( B(t; m) = A 1 + r ) mt m { ( = A 1 + r ) m } rt r m n = m r m n B

= π2 6, ( ) = π 4, ( ). 1 ( ( 5) ) ( 9 1 ( ( ) ) (

1

³ÎΨÏÀ

y π π O π x 9 s94.5 y dy dx. y = x + 3 y = x logx + 9 s9.6 z z x, z y. z = xy + y 3 z = sinx y 9 s x dx π x cos xdx 9 s93.8 a, fx = e x ax,. a =

1 8, : 8.1 1, 2 z = ax + by + c ax by + z c = a b +1 x y z c = 0, (0, 0, c), n = ( a, b, 1). f = n i=1 a ii x 2 i + i<j 2a ij x i x j = ( x, A x), f =

ii

2 7 V 7 {fx fx 3 } 8 P 3 {fx fx 3 } 9 V 9 {fx fx f x 2fx } V {fx fx f x 2fx + } V {{a n } {a n } a n+2 a n+ + a n n } 2 V 2 {{a n } {a n } a n+2 a n+

waseda2010a-jukaiki1-main.dvi

第10章 アイソパラメトリック要素

untitled

newmain.dvi



II 2 3.,, A(B + C) = AB + AC, (A + B)C = AC + BC. 4. m m A, m m B,, m m B, AB = BA, A,, I. 5. m m A, m n B, AB = B, A I E, 4 4 I, J, K

ii p ϕ x, t = C ϕ xe i ħ E t +C ϕ xe i ħ E t ψ x,t ψ x,t p79 やは時間変化しないことに注意 振動 粒子はだいたい このあたりにいる 粒子はだいたい このあたりにいる p35 D.3 Aψ Cϕdx = aψ ψ C Aϕ dx

N cos s s cos ψ e e e e 3 3 e e 3 e 3 e


Acrobat Distiller, Job 128

1 Introduction 1 (1) (2) (3) () {f n (x)} n=1 [a, b] K > 0 n, x f n (x) K < ( ) x [a, b] lim f n (x) f(x) (1) f(x)? (2) () f(x)? b lim a f n (x)dx = b

18 ( ) I II III A B C(100 ) 1, 2, 3, 5 I II A B (100 ) 1, 2, 3 I II A B (80 ) 6 8 I II III A B C(80 ) 1 n (1 + x) n (1) n C 1 + n C

日本内科学会雑誌第102巻第4号

II

sec13.dvi

: , 2.0, 3.0, 2.0, (%) ( 2.

18 I ( ) (1) I-1,I-2,I-3 (2) (3) I-1 ( ) (100 ) θ ϕ θ ϕ m m l l θ ϕ θ ϕ 2 g (1) (2) 0 (3) θ ϕ (4) (3) θ(t) = A 1 cos(ω 1 t + α 1 ) + A 2 cos(ω 2 t + α

[ ] =. =3.5 3 =.3 =. =0.30 : (f i ) u i u i f i u i f i


分散分析・2次元正規分布

( z = x 3 y + y ( z = cos(x y ( 8 ( s8.7 y = xe x ( 8 ( s83.8 ( ( + xdx ( cos 3 xdx t = sin x ( 8 ( s84 ( 8 ( s85. C : y = x + 4, l : y = x + a,

‚åŁÎ“·„´Šš‡ðŠp‡¢‡½‹âfi`fiI…A…‰…S…−…Y…•‡ÌMarkovŸA“½fiI›ð’Í

1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0

I L01( Wed) : Time-stamp: Wed 07:38 JST hig e, ( ) L01 I(2017) 1 / 19

熊本県数学問題正解

Transcription:

黒住英司 [ 著 ] サピエンティア 計量経済学 訂正および練習問題解答 (206/2/2 版 ) 訂正 練習問題解答 3

.69, 3.8 4 (X i X)U i i i (X i μ x )U i ( X μx ) U i. i E [ ] (X i μ x )U i i E[(X i μ x )]E[U i ]0. i V [ ] (X i μ x )U i i 2 i j E [(X i μ x )(X j μ x )U i U j ] 2 E [ (X i μ x ) 2] E [ Ui 2 ] i σ2 xσ 2 P ( ε) ε 2 V [ ( ) 2] ε 2 σ 2 xσ 2 0 0 2 3.3(i) ( X μx ) i U i 0 0 2.7(iii) i (X i X)U i i (X i X) 2 0 σ 2 x a 0.92, 4(d) ( ) ˆV i b 2 Ŵ i + Êi ( ) ˆV i b Ŵ i + Êi.0 (5-2) ( ) +0.X i ( ) +0.X i 4

.24 2 ( ) ( ) 0.25, 3 ( ) (6-2) 9.36, 6 ( )σi 2 X2 i ( )σ2 i cx i.4, 8. ( ) 4.3(iv) ( ) 4.3(v).49, 8.3.2 ( ) 2 W i (8-0) Y i αw i + βx i + U i Ỹ ˆφ 2 Y, W ˆφ 2, Xi ˆφ 2 X, i 2,, Ỹ i Y i ˆφY i, Wi ˆφ, Xi X i ˆφX i i,, Ỹi W i X i ˆα ˆβ.66, (9 27) ( ) β 2i ( ) β 2.7, 2 ( ) ( ) 2

( 3 4 ) 0.55 0.57 0.97 2 (-3) (X i X) 2 i (X i X)(X i X) i X i (X i X) X i X i (X i X). i (X i X) i 3 (-4) (Y i Ȳ )2 i (Y i Ȳ )(Y i Ȳ ) i Y i (Y i Ȳ ) Ȳ i Y i (Y i Ȳ ). i (Y i Ȳ ) i 4 (-3) (-4) (X i X)(Y i Ȳ ) X i (Y i Ȳ ) X (Y i Ȳ ) i i i X i (Y i Ȳ ). i (X i X)(Y i Ȳ ) (X i X)Y i (X i X)Ȳ 3 i (X i X)Y i. i i i

(X i X)(Y i Ȳ ) X i Y i X Y i X i Ȳ + i i i i i X i Y i XȲ XȲ + XȲ i X i Y i XȲ. i XȲ 5 (-) (-7) 6(a) S(β) (Y i βx i ) 2 ds(β) 2 X i (Y i βx i )0. dβ β 2 i i b i X iy i i X2 i (b) (a) b Û i i (Y i bx i ) i Y i i i X iy i i X2 i 0 X i Û i X i (Y i bx i ) i i X i Y i i i X iy i i X2 i i X i Xi 2 0. 2 0 2 2 3 Ŷ i bx i X iy i X i i X2 i i 4 i i

Ȳ 3 4 2 Ŷ i Û i b i X i Û i 0 2 3 5 b X i X iy i i X2 i i X i Ȳ (c) 4 TSS ESS + RSS R 2 i 2 (a) (i) A {, 2, 3, 4}, A c {5, 6} P (A) 2 3, P(Ac ) 3 P (A)+P (A c ). B {4, 5, 6}, B c {, 2, 3} P (B) 2, P(Bc ) 2 P (B)+P (B c ). (ii) A B (iii) A B {, 2, 3, 4, 5, 6} P (A B) P (A)+P (B) P (A B) 2 3 + 2 6. (b) A B {4} P (A B) /6 /2 3. (c) P (A B) /6 P (A B) /3 P (B)P (A B) 2 3 6. 5

P (B A) /4 2 F (x) F (x) P (A)P (B A) 2 3 4 6. x 0 : x a f(t)dt x a b a : a<x b : x>b a + b 2 (a b)2,. 2 3 X Y ( ) X Y f X (x) f Y (y) f X,Y (x, y) (i) E[a] (ii) E[aX + b] (iii) E[X + Y ] a af X (x)dx a (ax + b)f X (x)dx xf X (x)dx + b (x + y)f X,Y (x, y)dxdy ( ) x f X,Y (x, y)dy xf X (x)dx + E[X]+E[Y ]. (iv) E[cg(X)+dh(Y )] c c +d yf Y (y)dy. f(x)dx a. f X (x)dx ae[x]+b. dx + y ( ) f X,Y (x, y)dx dy (cg(x)+dh(y))f X,Y (x, y)dxdy ( ) g(x) f X,Y (x, y)dy dx ( ) h(y) f X,Y (x, y)dx dy g(x)f X (x)dx + d ce[g(x)] + de[h(y )]. 6 h(y)f Y (y)dy

(v) V [ax + b] {(ax + b) E[aX + b]} 2 f X (x)dx {a(x E[X])} 2 f X (x)dx a 2 (x E[X]) 2 f X (x)dx a 2 V [X]. (vi) V [X] (x E[X]) 2 f X (x)dx ( x 2 2xE[X]+(E[X]) 2) f X (x)dx E[X 2 ] 2E[X]E[X]+(E[X]) 2 E[X 2 ] (E[X]) 2. 45 ( a a 2 a 3 a 4 a 5 ) 5 E[ X] E[X] i μ μ. i V [ X] E [ ( X μ) 2] { } 2 E (X i μ) 2 i i j E[(X i μ)(x j μ)]. i j E[(X i μ)(x j μ)] σ 2 i j E[(X i μ)(x j μ)] 0 V [ X] 2 i σ 2 σ2. 6(a) 2.5 X 2 X +3 X 2 2μ +3μ 2. μ X 2 μ 2 2.7 7

(b) 2.6 ( σ X μ ) ( σ X 2 μ 2 ) 2 d σ N(0,σ 2 ) N(0, ), d σ 2 N(0,σ 2 2) N(0, ). X i X 2i 2.9 2 ( ) 2 ( ) 2 ( σ X μ ) + ( σ X d 2 μ 2 ) χ 2 2. 2 7 2.575 2.325(Excel 2.5758 2.3263) 3 3.. 256 (3-3) V [a] E[(a α) 2 ] X 2 V [b]+e[ū 2 ] 2 XE[(b β)ū]. E[Ū 2 ] σ2, [ E[(b β)ū] E i (X i X)U i i (X i X) 2 i (X i X)σ 2 i (X 0. i X) 2 V [a] σ 2 X2 i (X i X) 2 + σ2 ] U i i σ 2 i X2 i i (X i X) 2. Cov(a, b) E [{ (b β) X + Ū} (b β) ] XE[(b β) 2 ]+E[(b β)ū] σ 2 X i (X +0. i X) 2 8

3 (3-6) (3-7) (3-8) 4 a Ȳ b X Y i X i (X i X)Y i i (X i X) 2 i i c i Y i, c i X(Xi X) i (X i X) 2. 5 a i c i Y i a E[a ] α c i E[Y i ] i c i E[α + βx i + U i ] i c i + β i c i X i α a c i, c i X i 0 i i i a c i (α + βx i + U i )α + i V [a ]σ 2 i c 2 i. 2 a c i, c i X i 0 i i c i U i i V [a] σ 2 c 2 i i 9

(3-22) i c i(c i c i)0 i c 2 i {c i +(c i c i )} 2 i 6 X b V [a ] σ 2 i c 2 i σ 2 c 2 i + σ 2 i c 2 i + i (c i c i ) 2 i (c i c i ) 2 i σ 2 c 2 i V [a]. i μ x Ū β 56 (3-3) a α (b β) X + Ū 0 3.8 α (β β)μ x +0α. 4 2 (4-6) (4-6) β,,β K b,,b K 2 K 2 2 3 4 Ŷi b + b 2 X 2i + + bkx Ki 2 5 3 X ki 2(a)R 2 0.8 R 2 0.796 (b) t 7 2,.25 0, 0.0456, 0.22 (c) t 0.25.96 (d) 0.5 ± 0.4.96 [.284, 0.284] 3 [ 0.29, 0.097] [0.064, 0.42] [0.594, 0.960] [.47, 0.62] 0

4 (a) (4-6) b b 2 X i (Y i b X i b 2 X 2i ) 0 i X 2i (Y i b X i b 2 X 2i ) 0 i (b) b S 22S Y S 2 S 2Y S S 22 S 2 2, b 2 S S 2Y S 2 S Y S S 22 S 2 2 (c) b Y 2 S 2Y, b 2 S 2. S 22 S 22 (d) ˆV i Y i b Y 2 X 2i Ŵi X i b 2 X 2i i b Ŵi ˆV i i Ŵ i 2 (S 22S Y S 2 S 2Y )/S 22 (S S 22 S 2 2 )/S 22 S 22S Y S 2 S 2Y S S 22 S 2 2 b. 5 (4-2) X i X 2i S Y β S + β 2 S 2 + S U, S 2Y β S 2 + β 2 S 22 + S 2U b b β + S 22S U S 2 S 2U S S 22 S 2 2 X X 2 U E[b X,X 2 ]β + S 22E[S U ] S 2 E[S 2U ] S S 22 S 2 2 β. E[b ]E[E[b X,X 2 ]] β b β + S 22 S U S 2 S 2U S S 22 ( S 2) 2 β + lim S 22 0 lim S 2 0 lim S S 22 lim( S 2) β. 2

5 (5-8) 0.95 9.5 4. 2.20, 0.95 (5-9) 9.5 0.23 2.9 0.23 4. 0.94 (5-20) 0.05 4. 2.45 0.05 9.5.06 2 7 3 i j D ji (j, 2, 3, 4) Y i α D i + α 2 D 2i + α 3 D 3i + α 4 D 4i + βx i + U i. 4 i D i Y i α + δ c D i + βx i + δ X D i X i + U i δ X 0 t 5 (5-2) 0.5.9.32 (5-22) 2 2+2 0.7 +2 0.7 2 + 2/0.3 6.67 ( s0 s 2 0.7s )/( s0 2 0.7s )0.7/0.3 2.33 6 b Ȳ b 2 X 2 (5-5) Ȳ β + β 2 X2 + β 3 X3 + Ū 5.5.2 E[b ]β β 3 i (X 2i X 2 )(X 3i X 3 ) i (X 2i X 2 ) 2 X2 + β 3 X3, b β β 3 σ 23 σ 22 μ 2x + β 3 μ 3x. 7 (5-23) AIC 0.49 BIC 0.56 (5-24) AIC 0.2 BIC 0.23 (5-24) 8(a)g(Y i )logy i (b) g(y i ) Y i 2

6 (a)h 0 : β 2 β 3 0 H : β 2 β 3 0 (b) 2 (c) Y i β + β 4 X 4i + U i (d) F.857 3.37 W 3.74 5.99 2(a)H 0 : β 2 β 3 β 4 0 H : β 2 β 3 β 4 0 (b) 3 (c) Y i β + U i (d) F.98 2.98 W 5.943 7.85 3 suw 8.86 5 6.45 5 7 (a)e[a] E[Ȳ ] E[b] X (α + β X + E[Ū]) β X α. (b) 3 2, V [a] X 2 V [b]+e[ū 2 ] 2 XE[(b β)ū] X 2 i (X i X) 2 σi 2 { i (X i X) i 2 } 2 + σ2 i 2 2 X i (X i X)σ i 2 i (X i X) 2. 2(a) Y i,x i,x 2 i,x3 i Ûi 2 Û 2 i,x i,x 2 i X 3 i,x4 i,x5 i,x6 i R2 3 R 2 χ 2 6 (b) χ 2 6 5 2.59 3 Y i /X i /Xi 8 (a)e[a] E[Ȳ ] E[b] X (α + β X + E[Ū]) β X α. 3

(b) 3 2, V [a] X 2 V [b]+e[ū 2 ] 2 XE[(b β)ū] X 2 i j (X i X)(X j X)σ ij { i (X i X) i j 2 } 2 + σ ij 2 2 X i j (X i X)σ ij i (X i X) 2. 2 3 (8-) 4 χ 2 0 5 8.3 5 3 0 4 6 Y i (X i ) X 2i,X 3i Ûi 2 Ûi Ûi ˆφ 3 i Ỹ ˆφ 2 Y 9 X ˆφ 2 X 2 ˆφ 2 X 2 X 3 ˆφ 2 X 3 i 2,, Ỹ i Y i ˆφY i X i ˆφ X 2i X 2i ˆφX 2i X 3i X 3i ˆφX 3i i, 2,, Ỹi X i X 2i X 3i ˆβ ˆβ 2 ˆβ 3 a α + Ū (b β) X α γ xuμ x. σ 2 x 4

2 b 2 i (X 2i X 2 )(Y i Ȳ ) i (X 2i X 2 ) 2 i β 2 + β (X 2i X 2 )(X 3i X 3 ) 3 i (X 2i X + 2 ) 2 β 2 + β 3 σ 3x ρ 2,3 σ 2x. i (X 2i X 2 )(U i Ū) i (X 2i X 2 ) 2 3 b,iv β + Ū (b 2,IV β 2 ) X 2 (b K,IV β K ) X K β +0 (β 2 β 2 )μ 2x (β K β K )μ Kx β. 43 0 (8-3) i 2,, i.i.d.(0,σ 2 ε) i φ 2 φ 2 Y α φ 2 + β φ 2 X + φ 2 U V [ φ 2 U ]σε 2 φ 2 2 φ ˆφ 2 3 Cov(Y i,y i h ) σ 2 ( + θ 2 + θ2 2 ) : h 0 σ 2 (θ + θ θ 2 ) : h σ 2 θ 2 : h 2 0 : h 3 5

4 Y i Y + U 2 + + U i E[Yi 2]Y 2 + σ2 (i ) [ ] 5 (0-9) E i2 Y 2 i ( )Y 2 + σ 2 ( 2)( ). 2 Y i φ Y i + + φ Y i + + φ Y i + φ Y i + + φ Y i + U i φ Y i + +(φ + φ )Y i + +( φ )ΔY i + + U i 2 3 2 3 3 3 ( ) 2 TSS R 2 SSR/TSS( RSS ) 3 Y it X it U it t Ȳt i Y it X t i X it Ūt i U it Ȳ t α + β X t + γz t + Ūt (Y it Ȳt) β(x it X t )+(U it Ūt) 2 4(a) σu 2 (b) (c) 0 2 6

2 3 42 5 7