[1.1] r 1 =10e j(ωt+π/4), r 2 =5e j(ωt+π/3), r 3 =3e j(ωt+π/6) ~r = ~r 1 + ~r 2 + ~r 3 = re j(ωt+φ) =(10e π 4 j +5e π 3 j +3e π 6 j )e jωt

Similar documents
() (, y) E(, y) () E(, y) (3) q ( ) () E(, y) = k q q (, y) () E(, y) = k r r (3).3 [.7 ] f y = f y () f(, y) = y () f(, y) = tan y y ( ) () f y = f y

S I. dy fx x fx y fx + C 3 C dy fx 4 x, y dy v C xt y C v e kt k > xt yt gt [ v dt dt v e kt xt v e kt + C k x v + C C k xt v k 3 r r + dr e kt S dt d

Note.tex 2008/09/19( )

S I. dy fx x fx y fx + C 3 C vt dy fx 4 x, y dy yt gt + Ct + C dt v e kt xt v e kt + C k x v k + C C xt v k 3 r r + dr e kt S Sr πr dt d v } dt k e kt

x A Aω ẋ ẋ 2 + ω 2 x 2 = ω 2 A 2. (ẋ, ωx) ζ ẋ + iωx ζ ζ dζ = ẍ + iωẋ = ẍ + iω(ζ iωx) dt dζ dt iωζ = ẍ + ω2 x (2.1) ζ ζ = Aωe iωt = Aω cos ωt + iaω sin

64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () m/s : : a) b) kg/m kg/m k

1. 4cm 16 cm 4cm 20cm 18 cm L λ(x)=ax [kg/m] A x 4cm A 4cm 12 cm h h Y 0 a G 0.38h a b x r(x) x y = 1 h 0.38h G b h X x r(x) 1 S(x) = πr(x) 2 a,b, h,π

2011de.dvi

x () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x


m dv = mg + kv2 dt m dv dt = mg k v v m dv dt = mg + kv2 α = mg k v = α 1 e rt 1 + e rt m dv dt = mg + kv2 dv mg + kv 2 = dt m dv α 2 + v 2 = k m dt d


< 1 > (1) f 0 (a) =6a ; g 0 (a) =6a 2 (2) y = f(x) x = 1 f( 1) = 3 ( 1) 2 =3 ; f 0 ( 1) = 6 ( 1) = 6 ; ( 1; 3) 6 x =1 f(1) = 3 ; f 0 (1) = 6 ; (1; 3)



TOP URL 1

1 yousuke.itoh/lecture-notes.html [0, π) f(x) = x π 2. [0, π) f(x) = x 2π 3. [0, π) f(x) = x 2π 1.2. Euler α

K E N Z OU

1 1 sin cos P (primary) S (secondly) 2 P S A sin(ω2πt + α) A ω 1 ω α V T m T m 1 100Hz m 2 36km 500Hz. 36km 1

M3 x y f(x, y) (= x) (= y) x + y f(x, y) = x + y + *. f(x, y) π y f(x, y) x f(x + x, y) f(x, y) lim x x () f(x,y) x 3 -

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0

) a + b = i + 6 b c = 6i j ) a = 0 b = c = 0 ) â = i + j 0 ˆb = 4) a b = b c = j + ) cos α = cos β = 6) a ˆb = b ĉ = 0 7) a b = 6i j b c = i + 6j + 8)

sec13.dvi

(3) (2),,. ( 20) ( s200103) 0.7 x C,, x 2 + y 2 + ax = 0 a.. D,. D, y C, C (x, y) (y 0) C m. (2) D y = y(x) (x ± y 0), (x, y) D, m, m = 1., D. (x 2 y

2012 IA 8 I p.3, 2 p.19, 3 p.19, 4 p.22, 5 p.27, 6 p.27, 7 p

II No.01 [n/2] [1]H n (x) H n (x) = ( 1) r n! r!(n 2r)! (2x)n 2r. r=0 [2]H n (x) n,, H n ( x) = ( 1) n H n (x). [3] H n (x) = ( 1) n dn x2 e dx n e x2

No δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i x j δx j (5) δs 2

( ) 2.1. C. (1) x 4 dx = 1 5 x5 + C 1 (2) x dx = x 2 dx = x 1 + C = 1 2 x + C xdx (3) = x dx = 3 x C (4) (x + 1) 3 dx = (x 3 + 3x 2 + 3x +

Gmech08.dvi



1 variation 1.1 imension unit L m M kg T s Q C QT 1 A = C s 1 MKSA F = ma N N = kg m s 1.1 J E = 1 mv W = F x J = kg m s 1 = N m 1.

9 5 ( α+ ) = (α + ) α (log ) = α d = α C d = log + C C 5. () d = 4 d = C = C = 3 + C 3 () d = d = C = C = 3 + C 3 =


dynamics-solution2.dvi

18 I ( ) (1) I-1,I-2,I-3 (2) (3) I-1 ( ) (100 ) θ ϕ θ ϕ m m l l θ ϕ θ ϕ 2 g (1) (2) 0 (3) θ ϕ (4) (3) θ(t) = A 1 cos(ω 1 t + α 1 ) + A 2 cos(ω 2 t + α

Holton semigeostrophic semigeostrophic,.., Φ(x, y, z, t) = (p p 0 )/ρ 0, Θ = θ θ 0,,., p 0 (z), θ 0 (z).,,,, Du Dt fv + Φ x Dv Φ + fu +

08-Note2-web

main.dvi

1 [ 1] (1) MKS? (2) MKS? [ 2] (1) (42.195k) k 2 (2) (3) k/hr [ 3] t = 0 10 ( 1 velocity [/s] 8 4 O

II Karel Švadlenka * [1] 1.1* 5 23 m d2 x dt 2 = cdx kx + mg dt. c, g, k, m 1.2* u = au + bv v = cu + dv v u a, b, c, d R

Z[i] Z[i] π 4,1 (x) π 4,3 (x) 1 x (x ) 2 log x π m,a (x) 1 x ϕ(m) log x 1.1 ( ). π(x) x (a, m) = 1 π m,a (x) x modm a 1 π m,a (x) 1 ϕ(m) π(x)

9 2 1 f(x, y) = xy sin x cos y x y cos y y x sin x d (x, y) = y cos y (x sin x) = y cos y(sin x + x cos x) x dx d (x, y) = x sin x (y cos y) = x sin x

66 σ σ (8.1) σ = 0 0 σd = 0 (8.2) (8.2) (8.1) E ρ d = 0... d = 0 (8.3) d 1 NN K K 8.1 d σd σd M = σd = E 2 d (8.4) ρ 2 d = I M = EI ρ 1 ρ = M EI ρ EI

2009 IA 5 I 22, 23, 24, 25, 26, (1) Arcsin 1 ( 2 (4) Arccos 1 ) 2 3 (2) Arcsin( 1) (3) Arccos 2 (5) Arctan 1 (6) Arctan ( 3 ) 3 2. n (1) ta

, 3, 6 = 3, 3,,,, 3,, 9, 3, 9, 3, 3, 4, 43, 4, 3, 9, 6, 6,, 0 p, p, p 3,..., p n N = p p p 3 p n + N p n N p p p, p 3,..., p n p, p,..., p n N, 3,,,,

8 300 mm 2.50 m/s L/s ( ) 1.13 kg/m MPa 240 C 5.00mm 120 kpa ( ) kg/s c p = 1.02kJ/kgK, R = 287J/kgK kPa, 17.0 C 118 C 870m 3 R = 287J

2000年度『数学展望 I』講義録

2009 IA I 22, 23, 24, 25, 26, a h f(x) x x a h

1 1.1 [ 1] velocity [/s] 8 4 (1) MKS? (2) MKS? 1.2 [ 2] (1) (42.195k) k 2 (2) (3) k/hr [ 3] t = 0


(2000 )

DVIOUT-講


DVIOUT-HYOU

振動と波動

4 4 4 a b c d a b A c d A a da ad bce O E O n A n O ad bc a d n A n O 5 {a n } S n a k n a n + k S n a a n+ S n n S n n log x x {xy } x, y x + y 7 fx

() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)

(1) (2) (3) (4) HB B ( ) (5) (6) (7) 40 (8) (9) (10)

keisoku01.dvi

1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0

数学演習:微分方程式

#A A A F, F d F P + F P = d P F, F y P F F x A.1 ( α, 0), (α, 0) α > 0) (x, y) (x + α) 2 + y 2, (x α) 2 + y 2 d (x + α)2 + y 2 + (x α) 2 + y 2 =

微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 初版 1 刷発行時のものです.

f(x) = x (1) f (1) (2) f (2) f(x) x = a y y = f(x) f (a) y = f(x) A(a, f(a)) f(a + h) f(x) = A f(a) A x (3, 3) O a a + h x 1 f(x) x = a

() n C + n C + n C + + n C n n (3) n C + n C + n C 4 + n C + n C 3 + n C 5 + (5) (6 ) n C + nc + 3 nc n nc n (7 ) n C + nc + 3 nc n nc n (

sekibun.dvi

I-2 (100 ) (1) y(x) y dy dx y d2 y dx 2 (a) y + 2y 3y = 9e 2x (b) x 2 y 6y = 5x 4 (2) Bernoulli B n (n = 0, 1, 2,...) x e x 1 = n=0 B 0 B 1 B 2 (3) co

6kg 1.1m 1.m.1m.1 l λ ϵ λ l + λ l l l dl dl + dλ ϵ dλ dl dl + dλ dl dl 3 1. JIS 1 6kg 1% 66kg 1 13 σ a1 σ m σ a1 σ m σ m σ a1 f f σ a1 σ a1 σ m f 4

pdf

LCR e ix LC AM m k x m x x > 0 x < 0 F x > 0 x < 0 F = k x (k > 0) k x = x(t)

untitled

数学の基礎訓練I

I 1

( ) sin 1 x, cos 1 x, tan 1 x sin x, cos x, tan x, arcsin x, arccos x, arctan x. π 2 sin 1 x π 2, 0 cos 1 x π, π 2 < tan 1 x < π 2 1 (1) (

構造と連続体の力学基礎

I ( ) 1 de Broglie 1 (de Broglie) p λ k h Planck ( Js) p = h λ = k (1) h 2π : Dirac k B Boltzmann ( J/K) T U = 3 2 k BT

ω 0 m(ẍ + γẋ + ω0x) 2 = ee (2.118) e iωt x = e 1 m ω0 2 E(ω). (2.119) ω2 iωγ Z N P(ω) = χ(ω)e = exzn (2.120) ϵ = ϵ 0 (1 + χ) ϵ(ω) ϵ 0 = 1 +

main.dvi


x i [, b], (i 0, 1, 2,, n),, [, b], [, b] [x 0, x 1 ] [x 1, x 2 ] [x n 1, x n ] ( 2 ). x 0 x 1 x 2 x 3 x n 1 x n b 2: [, b].,, (1) x 0, x 1, x 2,, x n

2012 September 21, 2012, Rev.2.2

I

I A A441 : April 21, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka ) Google

f(x) = f(x ) + α(x)(x x ) α(x) x = x. x = f (y), x = f (y ) y = f f (y) = f f (y ) + α(f (y))(f (y) f (y )) f (y) = f (y ) + α(f (y)) (y y ) ( (2) ) f

II (10 4 ) 1. p (x, y) (a, b) ε(x, y; a, b) 0 f (x, y) f (a, b) A, B (6.5) y = b f (x, b) f (a, b) x a = A + ε(x, b; a, b) x a 2 x a 0 A = f x (


meiji_resume_1.PDF

x,, z v = (, b, c) v v 2 + b 2 + c 2 x,, z 1 i = (1, 0, 0), j = (0, 1, 0), k = (0, 0, 1) v 1 = ( 1, b 1, c 1 ), v 2 = ( 2, b 2, c 2 ) v

D:/BOOK/MAIN/MAIN.DVI

C:/KENAR/0p1.dvi

i

.5 z = a + b + c n.6 = a sin t y = b cos t dy d a e e b e + e c e e e + e 3 s36 3 a + y = a, b > b 3 s363.7 y = + 3 y = + 3 s364.8 cos a 3 s365.9 y =,

高等学校学習指導要領解説 数学編

1. (8) (1) (x + y) + (x + y) = 0 () (x + y ) 5xy = 0 (3) (x y + 3y 3 ) (x 3 + xy ) = 0 (4) x tan y x y + x = 0 (5) x = y + x + y (6) = x + y 1 x y 3 (



[] x < T f(x), x < T f(x), < x < f(x) f(x) f(x) f(x + nt ) = f(x) x < T, n =, 1,, 1, (1.3) f(x) T x 2 f(x) T 2T x 3 f(x), f() = f(t ), f(x), f() f(t )

基礎数学I

A (1) = 4 A( 1, 4) 1 A 4 () = tan A(0, 0) π A π

Transcription:

3.4.7 [.] =e j(t+/4), =5e j(t+/3), 3 =3e j(t+/6) ~ = ~ + ~ + ~ 3 = e j(t+φ) =(e 4 j +5e 3 j +3e 6 j )e jt = e jφ e jt cos φ =cos 4 +5cos 3 +3cos 6 =.69 sin φ =sin 4 +5sin 3 +3sin 6 =.9 =.69 +.9 =7.74 [.] φ =tan (.9/.69) = 46.67 [.85 ad] x =4cos(t/6+/4),x =5cos(t/5+/3) ~x = ~x + ~x =4cos( 6 t + 4 )+5cos( 5 t + 3 ) (.5) ½ ³ ~x = cos 6 + t ³ 5 + 4 + ¾ µ t 3 + Ψ = cos 6 + 7 4 + Ψ (.4) = 4 +5 +4 5 cos n³ 6 t + 5 4 o ³ = 4 + 4 cos 3 3 t + [.3] Ψ = 4 5 µ 4+5 tan t 6 = µ t 4 9 tan 6 + 4

θ : f(θ) = A θ θ 3 : f(θ) =A A θ 3 θ : f(θ) =A θ 4A a n = b n = T Z T f(t)sinntdt = Z A t sin ntdt + Z 3 + A sin ntdt Z 3 µ A Z 3 A t sin ntdt t 4A sin ntdt Z t sin ntdt = t cos nt + Z n n cos ntdt = t cos nt + [sin nt] n n b n = 4A µ sin n n 3n sin b = 8A,b =,b 3 = 8A 9,b 4 =,b 5 = 8A 5,... a = T Z T f(t)dt = Z A tdt + Z 3 Adt Z 3 A tdt + Z 3 µ A t 4A dt = f(t) = 8A sin t (/3 )sin3t +(/5 )sin5t...

[.4] θ : f(θ) = A θ θ : f(θ) = A θ A a n = a b n = A Z = A + A t sin ntdt + A Z n o ½ n cos n + A t sin ntdt A cos n + n Z sin ntdt ¾ cos n n ½ ¾ cos n cos n = A cos n = A n n n n ( )n f(t) = A [sin t (/) sin t +(/3) sin 3t... ] [.5] θ : f(θ) = A θ a n = Z A t cos ntdt = A = A ( t sin nt n + cos nt n ½ + ¾ cos n = n n ) a = Z A tdt = At 4 3 = A 8 µ 4 = A

b n = Z A t sin ntdt = A = A A ( t cos nt n = A ½ + ¾ cos n n sin nt n = A n f(t) = a + X b n sin nt n= µsin t + sin t + 3 sin 3t... ) 4

[.] f = k m =3.Hz 5g f = k m +5 =.5Hz m +5 m = 3..5 m =7.83kg k =365.3N/m =3.7kN/m [.] ρ d 4 x g mẍ + 4 d ρgx = n = d ρg 4m ad/s [.3] mb θ = k(aθ) a mb θ + ka θ = n = a b k m ad/s 5

[.4] m x y mẍ + k (x y) = ³ a k ya = k (x y)l l k a y = k l (x y) y = k l k a + k l x x µ k l mẍ + k x = k a + k l mẍ + k k a k a + k l x = s k k a n = (k a + k l )m ad/s [.5] α x cos α -5 mẍ +(kx cos α)cosα = mẍ + kx cos α = k n = m cos α ad/s [.6] 6

ml θ = k(aθ) a +(mg sin θ) l ml θ + ka θ mgθl = ka mgl n = ad/s ml [.7] µ a x a mg µ a + x a mg mẍ = µ a x + x mg µa a a mg ẍ + µg a x = µg n = ad/s () a [.8] m e e sin t (M + m + m e )ẍ + kx = m e e sin t x = C sin t (M + m + m e )C sin t + kc sin t = m e e sin t C = m e e k (M + m + m e ) x = m e e sin t k (M + m + m e ) m e e 4 ẍ = sin t k (M + m + m e ) m e e 4 k (M + m + m e ) g 3.35 4 5 (9) 9.8 () 7

=36.4ad/s [.9] m =kg,c =Ns/m,k =kn/m ζ = δ = c mk = =.58 ζ ζ =.58.58 =.5 [.] T = n = km n T = n mẍ + csẋ + kx = ẍ +ζ n ẋ + nx = ζ T T = n = ζ ζ = n = cs mk c = mk(n )/ns(n s/m) [.] θ ml θ + cb θ + ka θ = n = a l km ζ = cb al mk d = n ζ = a km c b 4 l 4mkl a = 4mkl a ml c b 4 8

[.] mẍ + cẋ + kx = f sin t k = n m =() = 98.7kN/m X = F /k ζ ζ = F kx =.68 c =ζ mk =.68 98.7 3 =47.3Ns/m [.3] mẍ + c(ẋ ẏ)+kx = y = Y sin t mẍ + cẋ + kx = cy cos t ẍ +ζ n ẋ + x = ζ n Y cos t x = C cos t + D sin t cos t, sin t C(n )+Dζ n = ζ n Y Cζ n + D(n ) = D = C = (ζ n ) Y (n ) +(ζ n ) ζ n (n )Y (n ) +(ζ n ) x = ζ n Y ( n ) +(ζ n ) sin(tφ) [.4] µ φ =tan ζn n 9

/ ζ ζ = log ζ (log ) = () +(log) =.539 ζ =.73 c = ζ mk =.73 = 4.6Ns/m k n = m = =3.6ad/s =ad/s F =N (.7) X = = X st ( (/n ) ) +(ζ(/ n )) / =.6m =.cm ( (/3.6) ) +(.73(/3.6)) [.5] K = Gd4,G: 3l J θ + c θ + Kθ = T sin t K Gd n = J = 4 c, ζ = 3l JK = c Gd 4 /3l (.7) Θ = T /K ( (/n ) ) +(ζ(/ n )) T /K = T /(Jn) [.6] (.93)

.5 f(t) = F F µsin t + sin t + 3 sin 3t... F x = F = Xst k f i = F sin it i x i = (X st /i)sin(it φ i ) { (i/n ) } + {ζ(i/ n )}, φ i =tan ζ(i/ n ) (i/ n ) [.7] x(t) = X st X i x i k n = m = =4.4ad/s 5 ζ = c mk = 5 =.4 F = kn = = 6.83ad/s = 4.443 n (.9) F T = F +{ζ(/n )} { (/n ) } + {ζ(/ n )} = 637 8.78 [.8] =8536.4N =8.54kN mẍ + k(x Y sin t) = ẍ + nx = ny sin t (.6) x = v = Y x = (/ n ) [sin t (/ n)sin n t] q Y =5 m, =4 =.566ad/s, n = t =8.65ad/s 3 x =5.6(sin 8.65t.65 sin.566t)cm

[.9] ẍ + ẋ + x = e t, t = >x=, ẋ = (4, ) s X(s) sx() ẋ() + sx(s) x() + X(S) = X(s) = (s + s +)X(s) = (s )(s + s +) + s s s + s + µ µ x(t) = L + L s s + s + s + s + = 3 L s s + 3 (s + ) + 3 (s + 4 ) + 3 + L (s + 4 ) + 3 4 à =! e t e t 3 cos 3 t t 3 e sin t + e t 3 sin 3 t à = 3 et e t 3 cos t! 3 3sin t [.] () () s +3 s +s +5 = (s +)+ (s +) +4 = e t (cos t +sint) s + (s )(s +s +) a s + bs + c s +s + = a(s +s +)+(bs + c)(s ) (s )(s +s +) a = 3 5, b = 3 5, c = 4 5 3 5 s 3(s +)+ 5 (s +) + = 3 5 et 3 5 cos t 5 sin t