C: PC H19 A5 2.BUN Ohm s law
|
|
|
- たみえ つくとの
- 4 years ago
- Views:
Transcription
1 C: PC H19 A5 2.BUN Ohm s law
2 3 3.1 Cu 1 carrier v I 1 sec 1A 1 S v v 1s 1A= 1C 1sec 17. S 1 S N v 1 v N v 1sec 1m 3 n N = n S v /s 19
3 n 9 N 1 S 1 e I = e N = Snev A (16) j = = (17) j = I S = nev (18) 2. 1 mm 2 1 A v v = I Sne = 1C/sec m /m C = m/sec 0.07mm/sec 3. 1 A e = C I = QC tsec = A 9 n 1m 3 = n /m 3 63 Cu 29 1mol=63g= Avogadro 1 1 = 8.9 g/cm 3. 1 mol =. 63/8.9 =.. 7 cm 3 1 m 3 = 10 6 cm 3 n = 1m = = m 3 20
4 4. Bohr 1 n = 1 A 1 e 2 2 mv2 = k e r h 2 r = 4π 2 me 2 n 2 k e h = J secm = kg k e = Nm 2 /C 2 e = C 5. v 0.07 mm 3.2 Ohm s law Cu 1 Cu + m e E F = ee α + mα = ee 21
5 τ v = 0 τ v = 0 τ v = v max v e max = F + S E = α τ = ee l m τ 18. v v 0 v max v = 0 + v max 2 = 1 2 e m Eτ v max v max 2 19 µ eτ 2m 0 t τ τ v = µe µ mobility 16 I = neµse l V E E = V l = 22
6 V I = eµn S l V eµn l/s I V R l eµns R (19) I = V R (20) 20 Ohm s law l S ρ 19 ρ 1 eµn ρ (21) R = ρ l S (22) 22 ρ R l S ρ ρ M.K.S. 1m 2 1cm 2 23
7 σ ρ Ωcm NaCl ρ 10 6 Ω cm Ni Cr 2 1cm 1cm 1cm 1cm mm 1m R = ρ l S = Ω cm. = Ω. =. 0.1 Ω cm 3.14 ( cm) 2 S = πr Ohm s law V = RI I = V R R = V I (23) 1V=1 1A VoltOhmAmpare 5 24
8 R V M k m kvmv VnVpV I ma AnApA 10 9 =G 10 6 =M 10 3 =k 10 3 =m 10 6 = 10 9 =n =p =a =f 5. 25
9 4 4.1 R 1 R 2 V I R 1 R 2 V 1 V 2 A R I V B A V I R 1 R 2 V 1 V 2 V V 1 R 1 R 2 V 2 B a b a b V 1 = R 1 I V 2 = R 2 I I I = V (24) V 1 = R 1 V V 2 = R 2 V (25) V 2 V 1 V 2 26
10 R 1 R 2 V I I 2 R 1 R 2 I 1 I 2 R 1 R 2 V R 1 R 2 I V = R 1 I 1 V = R 2 I 2 I 1 I 2 2 I 1 I 2 = R 2 R 1 V R 1 R R 1 R R 1 R 2 24 R 1 R 2 24 I I = V = V R (26) R = 1 2 R 1 R 2 R = R 1 R 2 R n 24 V I = + + R n V I R 1 R 2 V 1 V
11 1 R 1 R 2 R n R = + + R n 4.4 R 1 R R 1 R 2 I V I 1 I 2 I 1 I 2 V R 1 R 2 I 25. I = I 1 + I 2 = V + V ( 1 = V + 1 ) R 1 R 2 R 1 R 2 1 R 1 R 2 1 R I = V 1 R R 1 R 2 R 1 R = 1 R R 2 (27) R = = R 1 R 2 R 1 R 2 (28) 28
12 R 1 R 2 27 R 1 R 2 28 R = R 1R = 2 2 (29) =2/ =12/ =10/ R R 1 R 2 28 R 3 R = R 1 R 2 R 3 = R 1 R 2 + R 3 R 1 R 2 R 3 R 1 R 2 + R 2 R 3 + R 3 R 1 (30) 29
13 2 n n n 1 n R = R 1 R 2 R n n (R 1 R 2 R n /R i ) i=1 (31) R 1 R n 27. n R = = = 24 = r x 30
14 R R = rx r + x x x = rr (32) r R x x = rr r R = 2 2 x = kΩ (33) R = 990Ω 1kΩ x = = = 99.0 kω 99.0 kω 100 kω R = 1 k 100 k 1 k k = Ω k = kω 100 kω 8. r r A 1 r r 1/A r Ar r p ( r r p = = r ) 1.=. r A r Ar r + Ar = A ( 1 1 ) A 31
15 Ω Ω r p = = = Ω. r p = 100(1 0.1) = 90 Ω 1% 10 Ω 1000 Ω r 10% r 10 =1% 5% r 20 =0.025% 1% r 100 =0.01% 32
16 4.7 2 R 1 R 2 R R = R 1 //R 2 // R 1 //R 2 = R 1R 2 (34) // R = R 1 //R 2 //R 3 // //R n R R 1 R 2 R 3 R n 1 R 1 R 2 R 3 R n n 10. AB R R 1 A // R 2 R 3 R = //R 3 B = R 3 R 2 + R 3 33
17 11. AB R 1 A R 3 R // R 2 R 4 R 5 R 6 R = //R 3 + R 4 //R 5 //R 6 ( ) R 4 R 5 R 6 = // R 3 + R 4 R 5 + R 5 R 6 + R 6 R 4 ) R 4 R 5 R 6 R 2 (R 3 + R 4 R 5 + R 5 R 6 + R 6 R 4 = R 1 + ( ) R 4 R 5 R 6 R 2 + R 3 + R 4 R 5 + R 5 R 6 + R 6 R 4 B = R 1 + R 4 R 5 R 6 R 2 R 3 + R 2 R 4 R 5 + R 5 R 6 + R 6 R 4 R 4 R 5 R 6 R 2 + R 3 + R 4 R 5 + R 5 R 6 + R 6 R 4 = R 3 R 4 R 5 + R 5 R 6 + R 6 R 4 + R 2 R 4 R 5 R 6 R 2 + R 3 R 4 R 5 + R 5 R 6 + R 6 R 4 + R 4 R 5 R 6 34
64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () m/s : : a) b) kg/m kg/m k
63 3 Section 3.1 g 3.1 3.1: : 64 3 g=9.85 m/s 2 g=9.791 m/s 2 36, km ( ) 1 () 2 () 3 9.8 m/s 2 3.2 3.2: : a) b) 5 15 4 1 1. 1 3 14. 1 3 kg/m 3 2 3.3 1 3 5.8 1 3 kg/m 3 3 2.65 1 3 kg/m 3 4 6 m 3.1. 65 5
LLG-R8.Nisus.pdf
d M d t = γ M H + α M d M d t M γ [ 1/ ( Oe sec) ] α γ γ = gµ B h g g µ B h / π γ g = γ = 1.76 10 [ 7 1/ ( Oe sec) ] α α = λ γ λ λ λ α γ α α H α = γ H ω ω H α α H K K H K / M 1 1 > 0 α 1 M > 0 γ α γ =
II (No.2) 2 4,.. (1) (cm) (2) (cm) , (
II (No.1) 1 x 1, x 2,..., x µ = 1 V = 1 k=1 x k (x k µ) 2 k=1 σ = V. V = σ 2 = 1 x 2 k µ 2 k=1 1 µ, V σ. (1) 4, 7, 3, 1, 9, 6 (2) 14, 17, 13, 11, 19, 16 (3) 12, 21, 9, 3, 27, 18 (4) 27.2, 29.3, 29.1, 26.0,
4‐E ) キュリー温度を利用した消磁：熱消磁
( ) () x C x = T T c T T c 4D ) ) Fe Ni Fe Fe Ni (Fe Fe Fe Fe Fe 462 Fe76 Ni36 4E ) ) (Fe) 463 4F ) ) ( ) Fe HeNe 17 Fe Fe Fe HeNe 464 Ni Ni Ni HeNe 465 466 (2) Al PtO 2 (liq) 467 4G ) Al 468 Al ( 468
µµ InGaAs/GaAs PIN InGaAs PbS/PbSe InSb InAs/InSb MCT (HgCdTe)
1001 µµ 1.... 2 2.... 7 3.... 9 4. InGaAs/GaAs PIN... 10 5. InGaAs... 17 6. PbS/PbSe... 18 7. InSb... 22 8. InAs/InSb... 23 9. MCT (HgCdTe)... 25 10.... 28 11.... 29 12. (Si)... 30 13.... 33 14.... 37
1. 4cm 16 cm 4cm 20cm 18 cm L λ(x)=ax [kg/m] A x 4cm A 4cm 12 cm h h Y 0 a G 0.38h a b x r(x) x y = 1 h 0.38h G b h X x r(x) 1 S(x) = πr(x) 2 a,b, h,π
![1. 4cm 16 cm 4cm 20cm 18 cm L λ(x)=ax [kg/m] A x 4cm A 4cm 12 cm h h Y 0 a G 0.38h a b x r(x) x y = 1 h 0.38h G b h X x r(x) 1 S(x) = πr(x) 2 a,b, h,π](/thumbs/101/149329485.jpg "1. 4cm 16 cm 4cm 20cm 18 cm L λ(x)=ax [kg/m] A x 4cm A 4cm 12 cm h h Y 0 a G 0.38h a b x r(x) x y = 1 h 0.38h G b h X x r(x) 1 S(x) = πr(x) 2 a,b, h,π")
. 4cm 6 cm 4cm cm 8 cm λ()=a [kg/m] A 4cm A 4cm cm h h Y a G.38h a b () y = h.38h G b h X () S() = π() a,b, h,π V = ρ M = ρv G = M h S() 3 d a,b, h 4 G = 5 h a b a b = 6 ω() s v m θ() m v () θ() ω() dθ()
Gauss Gauss ɛ 0 E ds = Q (1) xy σ (x, y, z) (2) a ρ(x, y, z) = x 2 + y 2 (r, θ, φ) (1) xy A Gauss ɛ 0 E ds = ɛ 0 EA Q = ρa ɛ 0 EA = ρea E = (ρ/ɛ 0 )e
7 -a 7 -a February 4, 2007 1. 2. 3. 4. 1. 2. 3. 1 Gauss Gauss ɛ 0 E ds = Q (1) xy σ (x, y, z) (2) a ρ(x, y, z) = x 2 + y 2 (r, θ, φ) (1) xy A Gauss ɛ 0 E ds = ɛ 0 EA Q = ρa ɛ 0 EA = ρea E = (ρ/ɛ 0 )e z
修士論文
SAW 14 2 M3622 i 1 1 1-1 1 1-2 2 1-3 2 2 3 2-1 3 2-2 5 2-3 7 2-3-1 7 2-3-2 2-3-3 SAW 12 3 13 3-1 13 3-2 14 4 SAW 19 4-1 19 4-2 21 4-2-1 21 4-2-2 22 4-3 24 4-4 35 5 SAW 36 5-1 Wedge 36 5-1-1 SAW 36 5-1-2
V(x) m e V 0 cos x π x π V(x) = x < π, x > π V 0 (i) x = 0 (V(x) V 0 (1 x 2 /2)) n n d 2 f dξ 2ξ d f 2 dξ + 2n f = 0 H n (ξ) (ii) H
199 1 1 199 1 1. Vx) m e V cos x π x π Vx) = x < π, x > π V i) x = Vx) V 1 x /)) n n d f dξ ξ d f dξ + n f = H n ξ) ii) H n ξ) = 1) n expξ ) dn dξ n exp ξ )) H n ξ)h m ξ) exp ξ )dξ = π n n!δ n,m x = Vx)
untitled
9118 154 B-1 B-3 B- 5cm 3cm 5cm 3m18m5.4m.5m.66m1.3m 1.13m 1.134m 1.35m.665m 5 , 4 13 7 56 M 1586.1.18 7.77.9 599.5.8 7 1596.9.5 7.57.75 684.11.9 8.5 165..3 7.9 87.8.11 6.57. 166.6.16 7.57.6 856 6.6.5
128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds = 0 (3.4) S 1, S 2 { B( r) n( r)}ds
127 3 II 3.1 3.1.1 Φ(t) ϕ em = dφ dt (3.1) B( r) Φ = { B( r) n( r)}ds (3.2) S S n( r) Φ 128 3 II S 1, S 2 Φ 1, Φ 2 Φ 1 = { B( r) n( r)}ds S 1 Φ 2 = { B( r) n( r)}ds (3.3) S 2 S S 1 +S 2 { B( r) n( r)}ds
[Ver. 0.2] 1 2 3 4 5 6 7 1 1.1 1.2 1.3 1.4 1.5 1 1.1 1 1.2 1. (elasticity) 2. (plasticity) 3. (strength) 4. 5. (toughness) 6. 1 1.2 1. (elasticity) } 1 1.2 2. (plasticity), 1 1.2 3. (strength) a < b F
後期化学_01_濃度
2011 ( ) 1 4 1 100 g g % * 1 100 g 1 g 1 % * 2 (1 g)/(100 g) = 0.01 = 1 % 100 g 100 g 99 g 100 g 1 g 1 % 2.5 g 50 g (2.5 g)/(50 g) = 0.050 = 5.0 % 100 ml g 1 %(w/w) wt% % %(w/v) % / 2 % SI 2 / % 100 ml
0.45m1.00m 1.00m 1.00m 0.33m 0.33m 0.33m 0.45m 1.00m 2
24 11 10 24 12 10 30 1 0.45m1.00m 1.00m 1.00m 0.33m 0.33m 0.33m 0.45m 1.00m 2 23% 29% 71% 67% 6% 4% n=1525 n=1137 6% +6% -4% -2% 21% 30% 5% 35% 6% 6% 11% 40% 37% 36 172 166 371 213 226 177 54 382 704 216
,.,, 1. LED, 1450nm 1450nm 2mm 2mm LED 1mm 1mm
25 SpO 2 2014 3 19 10-3A257 ,.,, 1. LED, 1450nm 1450nm 2mm 2mm LED 1mm 1mm 1 1 1.1................................. 1 1.2................................. 1 2 2 2.1............................... 2 2.2..............................
10 117 5 1 121841 4 15 12 7 27 12 6 31856 8 21 1983-2 - 321899 12 21656 2 45 9 2 131816 4 91812 11 20 1887 461971 11 3 2 161703 11 13 98 3 16201700-3 - 2 35 6 7 8 9 12 13 12 481973 12 2 571982 161703 11
ma22-9 u ( v w) = u v w sin θê = v w sin θ u cos φ = = 2.3 ( a b) ( c d) = ( a c)( b d) ( a d)( b c) ( a b) ( c d) = (a 2 b 3 a 3 b 2 )(c 2 d 3 c 3 d
A 2. x F (t) =f sin ωt x(0) = ẋ(0) = 0 ω θ sin θ θ 3! θ3 v = f mω cos ωt x = f mω (t sin ωt) ω t 0 = f ( cos ωt) mω x ma2-2 t ω x f (t mω ω (ωt ) 6 (ωt)3 = f 6m ωt3 2.2 u ( v w) = v ( w u) = w ( u v) ma22-9
180 140 22
21 180 140 22 23 25 50 1 3 350 140 500cm 600 140 24 25 26 27 28 29 30 31 1/12 8.3 1/15 6.7 10 1/8 12.5 1/20 140 90 75 150 60 150 10 30 15 35 2,000 30 32 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 % 100 50 33.3
<82D282A982C1746F95F18D908F57967B95B E696E6464>
1 2 (90cm 70cm 2015) 3 (68cm 28cm 30cm 12kg 2015) (77.5 109.5cm 2015) 4 (22cm 50cm 50cm 4.6kg 2015) (45cm 62.5cm 2015) (47.4cm 62.5cm 2014) 5 (28.5cm 23.5cm) (45cm 62cm 2015) (97cm 107cm 2015) 6 7 8 9
6 12 10661 93100 227213202 222208197 85kg cm 20 64.521 106856142 2 1 4 3 9767 100 35 cm 7747 208198 90kg 23 5828 10661 93100 cm 227213202 10639 61 64.521 85kg 78kg 70kg 61 100 197204.5 cm 15 61
23 1 Section ( ) ( ) ( 46 ) , 238( 235,238 U) 232( 232 Th) 40( 40 K, % ) (Rn) (Ra). 7( 7 Be) 14( 14 C) 22( 22 Na) (1 ) (2 ) 1 µ 2 4
23 1 Section 1.1 1 ( ) ( ) ( 46 ) 2 3 235, 238( 235,238 U) 232( 232 Th) 40( 40 K, 0.0118% ) (Rn) (Ra). 7( 7 Be) 14( 14 C) 22( 22 Na) (1 ) (2 ) 1 µ 2 4 2 ( )2 4( 4 He) 12 3 16 12 56( 56 Fe) 4 56( 56 Ni)
10 44 1.2 5 4 5 3 6-1 - 1 2 3 4 5 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8 9 10 TEL TEL 1 2 TEL FAX TEL FAX TEL FAX 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 1 2 3 4 5 6 ( ) ( ) 2
6 2 T γ T B (6.4) (6.1) [( d nm + 3 ] 2 nt B )a 3 + nt B da 3 = 0 (6.9) na 3 = T B V 3/2 = T B V γ 1 = const. or T B a 2 = const. (6.10) H 2 = 8π kc2
![6 2 T γ T B (6.4) (6.1) [( d nm + 3 ] 2 nt B )a 3 + nt B da 3 = 0 (6.9) na 3 = T B V 3/2 = T B V γ 1 = const. or T B a 2 = const. (6.10) H 2 = 8π kc2](/thumbs/92/109118076.jpg "6 2 T γ T B (6.4) (6.1) [( d nm + 3 ] 2 nt B )a 3 + nt B da 3 = 0 (6.9) na 3 = T B V 3/2 = T B V γ 1 = const. or T B a 2 = const. (6.10) H 2 = 8π kc2")
1 6 6.1 (??) (P = ρ rad /3) ρ rad T 4 d(ρv ) + PdV = 0 (6.1) dρ rad ρ rad + 4 da a = 0 (6.2) dt T + da a = 0 T 1 a (6.3) ( ) n ρ m = n (m + 12 ) m v2 = n (m + 32 ) T, P = nt (6.4) (6.1) d [(nm + 32 ] )a
A = A x x + A y y + A, B = B x x + B y y + B, C = C x x + C y y + C..6 x y A B C = A x x + A y y + A B x B y B C x C y C { B = A x x + A y y + A y B B
9 7 A = A x x + A y y + A, B = B x x + B y y + B, C = C x x + C y y + C..6 x y A B C = A x x + A y y + A B x B y B C x C y C { B = A x x + A y y + A y B B x x B } B C y C y + x B y C x C C x C y B = A
(1) 1.1
1 1 1.1 1.1.1 1.1 ( ) ( ) ( ) { ( ) ( ) { ( ) ( ) { ( ) ( ) { ( ) ( ) { ( ) ( ) ( ) ( ) ( ) 2 1 1.1.2 (1) 1.1 1.1 3 (2) 1.2 4 1 (3) 1.3 ( ) ( ) (4) 1.1 5 (5) ( ) 1.4 6 1 (6) 1.5 (7) ( ) (8) 1.1 7 1.1.3
36 th IChO : - 3 ( ) , G O O D L U C K final 1
36 th ICh - - 5 - - : - 3 ( ) - 169 - -, - - - - - - - G D L U C K final 1 1 1.01 2 e 4.00 3 Li 6.94 4 Be 9.01 5 B 10.81 6 C 12.01 7 N 14.01 8 16.00 9 F 19.00 10 Ne 20.18 11 Na 22.99 12 Mg 24.31 Periodic
緑化計画作成の手引き 26年4月版
http://www.city.shibuya.tokyo.jp/env/en_eventact/midori_ryokka.html 10 11 12 13 14 15 16 17 18 19 P10 P10 1 P12 2635 Fax (1) 47 03-5388-3554 http://www2.kankyo.metro.tokyo.jp/sizen/sinseisyo/e2/tebiki.htm
untitled
( ) c a sin b c b c a cos a c b c a tan b a b cos sin a c b c a ccos b csin (4) Ma k Mg a (Gal) g(98gal) (Gal) a max (K-E) kh Zck.85.6. 4 Ma g a k a g k D τ f c + σ tanφ σ 3 3 /A τ f3 S S τ A σ /A σ /A
1
GL (a) (b) Ph l P N P h l l Ph Ph Ph Ph l l l l P Ph l P N h l P l .9 αl B βlt D E. 5.5 L r..8 e g s e,e l l W l s l g W W s g l l W W e s g e s g r e l ( s ) l ( l s ) r e l ( s ) l ( l s ) e R e r
TOP URL 1
TOP URL http://amonphys.web.fc.com/ 1 19 3 19.1................... 3 19.............................. 4 19.3............................... 6 19.4.............................. 8 19.5.............................
58 5 5.2 1933 (Proctor) (JIS A 1210) ( 2.5 kg 4.5 kg ) (2.5 kg 30 cm 4.5 kg 45 cm) 5.3 5 5.1 ρ d w ρ d max w opt 5.1
57 5 5.1 2 2.1 ( ) ( ) 58 5 5.2 1933 (Proctor) (JIS A 1210) ( 2.5 kg 4.5 kg ) (2.5 kg 30 cm 4.5 kg 45 cm) 5.3 5 5.1 ρ d w ρ d max w opt 5.1 5.3 59 5.1 v a = 0 % S r = 100 % 5.3 5.1 5 5.1 5.4 2 2 5.2 3
0.1 I I : 0.2 I
1, 14 12 4 1 : 1 436 (445-6585), E-mail : sxiida@sci.toyama-u.ac.jp 0.1 I I 1. 2. 3. + 10 11 4. 12 1: 0.2 I + 0.3 2 1 109 1 14 3,4 0.6 ( 10 10, 2 11 10, 12/6( ) 3 12 4, 4 14 4 ) 0.6.1 I 1. 2. 3. 0.4 (1)
8 300 mm 2.50 m/s L/s ( ) 1.13 kg/m MPa 240 C 5.00mm 120 kpa ( ) kg/s c p = 1.02kJ/kgK, R = 287J/kgK kPa, 17.0 C 118 C 870m 3 R = 287J
26 1 22 10 1 2 3 4 5 6 30.0 cm 1.59 kg 110kPa, 42.1 C, 18.0m/s 107kPa c p =1.02kJ/kgK 278J/kgK 30.0 C, 250kPa (c p = 1.02kJ/kgK, R = 287J/kgK) 18.0 C m/s 16.9 C 320kPa 270 m/s C c p = 1.02kJ/kgK, R = 292J/kgK
(Blackbody Radiation) (Stefan-Boltzmann s Law) (Wien s Displacement Law)
( ) ( ) 2002.11 1 1 1.1 (Blackbody Radiation).............................. 1 1.2 (Stefan-Boltzmann s Law)................ 1 1.3 (Wien s Displacement Law)....................... 2 1.4 (Kirchhoff s Law)...........................
(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0
1 1 1.1 1.) T D = T = D = kn 1. 1.4) F W = F = W/ = kn/ = 15 kn 1. 1.9) R = W 1 + W = 6 + 5 = 11 N. 1.9) W b W 1 a = a = W /W 1 )b = 5/6) = 5 cm 1.4 AB AC P 1, P x, y x, y y x 1.4.) P sin 6 + P 1 sin 45
(e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ,µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) [ ] [ ] [ ] ν e ν µ ν τ e µ τ, e R,µ R,τ R (2.1a
![(e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ,µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) [ ] [ ] [ ] ν e ν µ ν τ e µ τ, e R,µ R,τ R (2.1a](/thumbs/100/144882653.jpg "(e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ,µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) [ ] [ ] [ ] ν e ν µ ν τ e µ τ, e R,µ R,τ R (2.1a")
1 2 2.1 (e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ,µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) [ ] [ ] [ ] ν e ν µ ν τ e µ τ, e R,µ R,τ R (2.1a) L ( ) ) * 2) W Z 1/2 ( - ) d u + e + ν e 1 1 0 0
K 1 mk(
R&D ATN K 1 mk(0.01 0.05 = ( ) (ITS-90)-59.3467 961.78 (T.J.Seebeck) A(+ T 1 I T 0 B - T 1 T 0 E (Thermoelectromotive force) AB =d E(AB) /dt=a+bt----------------- E(AB) T1 = = + + E( AB) α AB a b ( T0
The Physics of Atmospheres CAPTER :
The Physics of Atmospheres CAPTER 4 1 4 2 41 : 2 42 14 43 17 44 25 45 27 46 3 47 31 48 32 49 34 41 35 411 36 maintex 23/11/28 The Physics of Atmospheres CAPTER 4 2 4 41 : 2 1 σ 2 (21) (22) k I = I exp(
1 1 1 1-1 1 1-9 1-3 1-1 13-17 -3 6-4 6 3 3-1 35 3-37 3-3 38 4 4-1 39 4- Fe C TEM 41 4-3 C TEM 44 4-4 Fe TEM 46 4-5 5 4-6 5 5 51 6 5 1 1-1 1991 1,1 multiwall nanotube 1993 singlewall nanotube ( 1,) sp 7.4eV
[ ] [ ] [ ] [ ] [ ] [ ] ADC
![[ ] [ ] [ ] [ ] [ ] [ ] ADC](/thumbs/91/107208011.jpg "[ ] [ ] [ ] [ ] [ ] [ ] ADC")
[ ] [ ] [ ] [ ] [ ] [ ] ADC BS1 m1 PMT m2 BS2 PMT1 PMT ADC PMT2 α PMT α α = n ω n n Pn TMath::Poisson(x,[0]) 0.35 0.3 0.25 0.2 0.15 λ 1.5 ω n 2 = ( α 2 ) n n! e α 2 α 2 = λ = λn n! e λ Poisson Pn 0.1
B 1 B.1.......................... 1 B.1.1................. 1 B.1.2................. 2 B.2........................... 5 B.2.1.......................... 5 B.2.2.................. 6 B.2.3..................
Bethe-Bloch Bethe-Bloch (stopping range) Bethe-Bloch FNAL (Fermi National Accelerator Laboratory) - (SciBooNE ) SciBooNE Bethe-Bloch FNAL - (SciBooNE
21 2 27 Bethe-Bloch Bethe-Bloch (stopping range) Bethe-Bloch FNAL (Fermi National Accelerator Laboratory) - (SciBooNE ) SciBooNE Bethe-Bloch FNAL - (SciBooNE ) Bethe-Bloch 1 0.1..............................
07.報文_及川ら-二校目.indd
8 01 01 4 4 1 5 16 18 6 006 H 18 4 011 H 6 4 1 5 1 5 007 H 19 5 009 1 5 006 007 009 011 9 10 4 000 H 1 4 5 004 H 16 4 004 009 H 1 5 4 4 5 1 4 006 011 1 1 4m 5m 10m 007 1 7 009 009 1 5 10 1 000kg 10a 006
http://www.ns.kogakuin.ac.jp/~ft13389/lecture/physics1a2b/ pdf I 1 1 1.1 ( ) 1. 30 m µm 2. 20 cm km 3. 10 m 2 cm 2 4. 5 cm 3 km 3 5. 1 6. 1 7. 1 1.2 ( ) 1. 1 m + 10 cm 2. 1 hr + 6400 sec 3. 3.0 10 5 kg
( ) Note (e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ, µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) 3 * 2) [ ] [ ] [ ] ν e ν µ ν τ e
![( ) Note (e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ, µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) 3 * 2) [ ] [ ] [ ] ν e ν µ ν τ e](/thumbs/98/136160482.jpg "( ) Note (e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ, µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) 3 * 2) [ ] [ ] [ ] ν e ν µ ν τ e")
( ) Note 3 19 12 13 8 8.1 (e ) (µ ) (τ ) ( (ν e,e ) e- (ν µ, µ ) µ- (ν τ,τ ) τ- ) ( ) ( ) (SU(2) ) (W +,Z 0,W ) * 1) 3 * 2) [ ] [ ] [ ] ν e ν µ ν τ e µ τ, e R, µ R, τ R (1a) L ( ) ) * 3) W Z 1/2 ( - )
1 I 1.1 ± e = = - = C C MKSA [m], [Kg] [s] [A] 1C 1A 1 MKSA 1C 1C +q q +q q 1
![1 I 1.1 ± e = = - = C C MKSA [m], [Kg] [s] [A] 1C 1A 1 MKSA 1C 1C +q q +q q 1](/thumbs/94/121802164.jpg "1 I 1.1 ± e = = - = C C MKSA [m], [Kg] [s] [A] 1C 1A 1 MKSA 1C 1C +q q +q q 1")
1 I 1.1 ± e = = - =1.602 10 19 C C MKA [m], [Kg] [s] [A] 1C 1A 1 MKA 1C 1C +q q +q q 1 1.1 r 1,2 q 1, q 2 r 12 2 q 1, q 2 2 F 12 = k q 1q 2 r 12 2 (1.1) k 2 k 2 ( r 1 r 2 ) ( r 2 r 1 ) q 1 q 2 (q 1 q 2
006 11 8 0 3 1 5 1.1..................... 5 1......................... 6 1.3.................... 6 1.4.................. 8 1.5................... 8 1.6................... 10 1.6.1......................
( ) ,
II 2007 4 0. 0 1 0 2 ( ) 0 3 1 2 3 4, - 5 6 7 1 1 1 1 1) 2) 3) 4) ( ) () H 2.79 10 10 He 2.72 10 9 C 1.01 10 7 N 3.13 10 6 O 2.38 10 7 Ne 3.44 10 6 Mg 1.076 10 6 Si 1 10 6 S 5.15 10 5 Ar 1.01 10 5 Fe 9.00
) a + b = i + 6 b c = 6i j ) a = 0 b = c = 0 ) â = i + j 0 ˆb = 4) a b = b c = j + ) cos α = cos β = 6) a ˆb = b ĉ = 0 7) a b = 6i j b c = i + 6j + 8)
4 4 ) a + b = i + 6 b c = 6i j ) a = 0 b = c = 0 ) â = i + j 0 ˆb = 4) a b = b c = j + ) cos α = cos β = 6) a ˆb = b ĉ = 0 7) a b = 6i j b c = i + 6j + 8) a b a b = 6i j 4 b c b c 9) a b = 4 a b) c = 7
EPSON LP-8900ユーザーズガイド
3 4 5 6 7 8 abc ade w p s 9 10 s s 11 p 12 p 13 14 p s 15 p s A B 16 w 17 C p 18 D E F 19 p w G H 20 A B 21 C s p D 22 E s p w 23 w w s 24 p w s 25 w 26 p p 27 w p s 28 w p 29 w p s 30 p s 31 A s B 32
平成１２年度
1 1-1 (1) 150[ml] 500[ml/] Cerebral Ventricle Brain 1-1 2 ( ) 1-1 1-2 0.20.5[mm] 13 14[mm] 1-2 3 ( ) (2) 4 2-1 (cerebral ventricle) (peritoneum) R O p O Cerebral Ventricle Valve Brain R o R i P i Peritoneum
. ev=,604k m 3 Debye ɛ 0 kt e λ D = n e n e Ze 4 ln Λ ν ei = 5.6π / ɛ 0 m/ e kt e /3 ν ei v e H + +e H ev Saha x x = 3/ πme kt g i g e n
003...............................3 Debye................. 3.4................ 3 3 3 3. Larmor Cyclotron... 3 3................ 4 3.3.......... 4 3.3............ 4 3.3...... 4 3.3.3............ 5 3.4.........
( ) 2002 1 1 1 1.1....................................... 1 1.1.1................................. 1 1.1.2................................. 1 1.1.3................... 3 1.1.4......................................
H22応用物理化学演習1_濃度.ppt
1 2 4/12 4/19 4/27 5/10 5/17 5/24 5/31 (20 ) (20 ) (10 ) (50 ) 3 (mole fraction) X = (mol) (mol) i n 1, n 2,, n x N i X i = n i = n i n 1 + n 2 + + n x N 4 (molarity, M) 1 dm 3 ( L) (mol) (mol/l) = 1 L
研修コーナー
l l l l l l l l l l l α α β l µ l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l l
講義ノート 物性研究 電子版 Vol.3 No.1, (2013 年 T c µ T c Kammerlingh Onnes 77K ρ 5.8µΩcm 4.2K ρ 10 4 µωcm σ 77K ρ 4.2K σ σ = ne 2 τ/m τ 77K
2 2 T c µ T c 1 1.1 1911 Kammerlingh Onnes 77K ρ 5.8µΩcm 4.2K ρ 1 4 µωcm σ 77K ρ 4.2K σ σ = ne 2 τ/m τ 77K τ 4.2K σ 58 213 email:takada@issp.u-tokyo.ac.jp 1933 Meissner Ochsenfeld λ = 1 5 cm B = χ B =
Microsoft Word - 11問題表紙（選択）.docx
A B A.70g/cm 3 B.74g/cm 3 B C 70at% %A C B at% 80at% %B 350 C γ δ y=00 x-y ρ l S ρ C p k C p ρ C p T ρ l t l S S ξ S t = ( k T ) ξ ( ) S = ( k T) ( ) t y ξ S ξ / t S v T T / t = v T / y 00 x v S dy dx
g g/cm3 g / cm3 g g g g/cm3 cm2 kv QMI_10.dvi
... black body radiation black body black body radiation Gustav Kirchhoff 859 895 W. Wien O.R. Lummer cavity radiation ν ν +dν f T (ν) f T (ν)dν = 8πν2 c 3 kt dν (Rayleigh Jeans) (.) f T (ν) spectral energy
Note.tex 2008/09/19( )
1 20 9 19 2 1 5 1.1........................ 5 1.2............................. 8 2 9 2.1............................. 9 2.2.............................. 10 3 13 3.1.............................. 13 3.2..................................
untitled
- k k k = y. k = ky. y du dx = ε ux ( ) ux ( ) = ax+ b x u() = ; u( ) = AE u() = b= u () = a= ; a= d x du ε x = = = dx dx N = σ da = E ε da = EA ε A x A x x - σ x σ x = Eε x N = EAε x = EA = N = EA k =
Microsoft Word - 章末問題
1906 R n m 1 = =1 1 R R= 8h ICP s p s HeNeArXe 1 ns 1 1 1 1 1 17 NaCl 1.3 nm 10nm 3s CuAuAg NaCl CaF - - HeNeAr 1.7(b) 2 2 2d = a + a = 2a d = 2a 2 1 1 N = 8 + 6 = 4 8 2 4 4 2a 3 4 π N πr 3 3 4 ρ = = =
医系の統計入門第 2 版 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 第 2 版 1 刷発行時のものです.
医系の統計入門第 2 版 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. http://www.morikita.co.jp/books/mid/009192 このサンプルページの内容は, 第 2 版 1 刷発行時のものです. i 2 t 1. 2. 3 2 3. 6 4. 7 5. n 2 ν 6. 2 7. 2003 ii 2 2013 10 iii 1987
1: 3.3 1/8000 1/ m m/s v = 2kT/m = 2RT/M k R 8.31 J/(K mole) M 18 g 1 5 a v t πa 2 vt kg (
1905 1 1.1 0.05 mm 1 µm 2 1 1 2004 21 2004 7 21 2005 web 2 [1, 2] 1 1: 3.3 1/8000 1/30 3 10 10 m 3 500 m/s 4 1 10 19 5 6 7 1.2 3 4 v = 2kT/m = 2RT/M k R 8.31 J/(K mole) M 18 g 1 5 a v t πa 2 vt 6 6 10
( ) e + e ( ) ( ) e + e () ( ) e e Τ ( ) e e ( ) ( ) () () ( ) ( ) ( ) ( )
n n (n) (n) (n) (n) n n ( n) n n n n n en1, en ( n) nen1 + nen nen1, nen ( ) e + e ( ) ( ) e + e () ( ) e e Τ ( ) e e ( ) ( ) () () ( ) ( ) ( ) ( ) ( n) Τ n n n ( n) n + n ( n) (n) n + n n n n n n n n
30
3 ............................................2 2...........................................2....................................2.2...................................2.3..............................
5 H Boltzmann Einstein Brown 5.1 Onsager [ ] Tr Tr Tr = dγ (5.1) A(p, q) Â 0 = Tr Âe βĥ0 Tr e βĥ0 = dγ e βh 0(p,q) A(p, q) dγ e βh 0(p,q) (5.2) e βĥ0
![5 H Boltzmann Einstein Brown 5.1 Onsager [ ] Tr Tr Tr = dγ (5.1) A(p, q) Â 0 = Tr Âe βĥ0 Tr e βĥ0 = dγ e βh 0(p,q) A(p, q) dγ e βh 0(p,q) (5.2) e βĥ0](/thumbs/99/141438380.jpg "5 H Boltzmann Einstein Brown 5.1 Onsager [ ] Tr Tr Tr = dγ (5.1) A(p, q) Â 0 = Tr Âe βĥ0 Tr e βĥ0 = dγ e βh 0(p,q) A(p, q) dγ e βh 0(p,q) (5.2) e βĥ0")
5 H Boltzmann Einstein Brown 5.1 Onsager [ ] Tr Tr Tr = dγ (5.1) A(p, q) Â = Tr Âe βĥ Tr e βĥ = dγ e βh (p,q) A(p, q) dγ e βh (p,q) (5.2) e βĥ A(p, q) p q Â(t) = Tr Â(t)e βĥ Tr e βĥ = dγ() e βĥ(p(),q())
m dv = mg + kv2 dt m dv dt = mg k v v m dv dt = mg + kv2 α = mg k v = α 1 e rt 1 + e rt m dv dt = mg + kv2 dv mg + kv 2 = dt m dv α 2 + v 2 = k m dt d
m v = mg + kv m v = mg k v v m v = mg + kv α = mg k v = α e rt + e rt m v = mg + kv v mg + kv = m v α + v = k m v (v α (v + α = k m ˆ ( v α ˆ αk v = m v + α ln v α v + α = αk m t + C v α v + α = e αk m
NETES No.CG V
1 2006 6 NETES No.CG-050001-V 2007 5 2 1 2 1 19 5 1 2 19 8 2 i 1 1 1.1 1 1.2 2 1.3 2 2 3 2.1 3 2.2 8 3 9 3.1 9 3.2 10 3.3 13 3.3.1 13 3.3.2 14 3.3.3 14 3.3.4 16 3.3.5 17 3.3.6 18 3.3.7 21 3.3.8 22 3.4
I 1
I 1 1 1.1 1. 3 m = 3 1 7 µm. cm = 1 4 km 3. 1 m = 1 1 5 cm 4. 5 cm 3 = 5 1 15 km 3 5. 1 = 36 6. 1 = 8.64 1 4 7. 1 = 3.15 1 7 1 =3 1 7 1 3 π 1. 1. 1 m + 1 cm = 1.1 m. 1 hr + 64 sec = 1 4 sec 3. 3. 1 5 kg
devicemondai
c 2019 i 3 (1) q V I T ε 0 k h c n p (2) T 300 K (3) A ii c 2019 i 1 1 2 13 3 30 4 53 5 78 6 89 7 101 8 112 9 116 A 131 B 132 c 2019 1 1 300 K 1.1 1.5 V 1.1 qv = 1.60 10 19 C 1.5 V = 2.4 10 19 J (1.1)
untitled
71 7 3,000 1 MeV t = 1 MeV = c 1 MeV c 200 MeV fm 1 MeV 3.0 10 8 10 15 fm/s 0.67 10 21 s (1) 1fm t = 1fm c 1fm 3.0 10 8 10 15 fm/s 0.33 10 23 s (2) 10 22 s 7.1 ( ) a + b + B(+X +...) (3) a b B( X,...)
II
II 28 5 31 3 I 5 1 7 1.1.......................... 7 1.1.1 ( )................ 7 1.1.2........................ 12 1.1.3................... 13 1.1.4 ( )................. 14 1.1.5................... 15
2 Chapter 4 (f4a). 2. (f4cone) ( θ) () g M. 2. (f4b) T M L P a θ (f4eki) ρ H A a g. v ( ) 2. H(t) ( )
http://astr-www.kj.yamagata-u.ac.jp/~shibata f4a f4b 2 f4cone f4eki f4end 4 f5meanfp f6coin () f6a f7a f7b f7d f8a f8b f9a f9b f9c f9kep f0a f0bt version feqmo fvec4 fvec fvec6 fvec2 fvec3 f3a (-D) f3b
<4D F736F F D B B BB2D834A836F815B82D082C88C60202D B2E646F63>
例題で学ぶはじめての塑性力学 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. http://www.morikita.co.jp/books/mid/066721 このサンプルページの内容は, 初版 1 刷発行当時のものです. http://www.morikita.co.jp/support/ 03 3817 5670 FAX 03 3815 8199 i 1
P F ext 1: F ext P F ext (Count Rumford, ) H 2 O H 2 O 2 F ext F ext N 2 O 2 2
1 1 2 2 2 1 1 P F ext 1: F ext P F ext (Count Rumford, 1753 1814) 0 100 H 2 O H 2 O 2 F ext F ext N 2 O 2 2 P F S F = P S (1) ( 1 ) F ext x W ext W ext = F ext x (2) F ext P S W ext = P S x (3) S x V V
(1) (kn/m 3 )
1 1 1.1 1.1.1 (1) 1.1 1.2 1.1 (kn/m 3 ) 77 71 24.5 23 21 8.0 22.5 2 1 1.2 N/m 2 2 m 3 m 2000 2200 2500 3000 (2) 1 A B B 1.3 1.5 1.1 T cm 1.1 3 1.3 L m L 4 L > 4 1.0 L 32 + 7 8 1.2 T 4 1 2 5.0 kn/m 2 3.
2001 1 1 30 98% ()2003 7 26 10km 600 ()2003 9 26 8.0 1952 2003 1 1 30 60% 1200 600 0-600 -1200 0 20 40 60 80 100 120 1200 600 0-600 -1200 0 20 40 60 8
15 15 26 26 26-1 -1 1978 1952 2003 2003/9/26 04:50 M:8.0 D:42km 6 ()2003 5 26 1952 1952/3/4 10:22 2003/5/26 18:24 M:8.2 D:54km M:7.1 D:72km 5 6 2003/ /26 7:13 D M:6.4 D:12km 6 1978 1978 1978/6/12 17:14
untitled
8- My + Cy + Ky = f () t 8. C f () t ( t) = Ψq( t) () t = Ψq () t () t = Ψq () t = ( q q ) ; = [ ] y y y q Ψ φ φ φ = ( ϕ, ϕ, ϕ,3 ) 8. ψ Ψ MΨq + Ψ CΨq + Ψ KΨq = Ψ f ( t) Ψ MΨ = I; Ψ CΨ = C; Ψ KΨ = Λ; q
１３２０Ｍ／１６１３２０Ｍ
" # $ %! θθ v m g y v θ O v α x! O x y x α x y y " v # v sinα $ & v cosα ' v cosα v sinα ( v cosα % v sinα " g # gsinθ $ g sinθ ' g ( gsinθ ) g sinθ % gcosθ & g cosθ * gcosθ! g cosθ xy y L v g x xy L α
無印良品 2012 自転車 カタログ
26 897895321,000 140cm 76.0cm 16.0kg H LED 3 263 897896025,000 140cm 76.0cm 16.5kg H 3 LED 20 8978984 8978977 19,800 134cm 73.0cm 15.0kg LED 2620 2620 8486656550 5536207483 14512372,100 8279999840 26 77342561,417
2009 2 26 1 3 1.1.................................................. 3 1.2..................................................... 3 1.3...................................................... 3 1.4.....................................................
B
B07557 0 0 (AGN) AGN AGN X X AGN AGN Geant4 AGN X X X (AGN) AGN AGN X AGN. AGN AGN Seyfert Seyfert Seyfert AGN 94 Carl Seyfert Seyfert Seyfert z < 0. Seyfert I II I 000 km/s 00 km/s II AGN (BLR) (NLR)
thesis.dvi
3 17 03SA210A 2005 3 1 introduction 1 1.1 Positronium............ 1 1.2 Positronium....................... 4 1.2.1 moderation....................... 5 1.2.2..................... 6 1.2.3...................
untitled
1 17 () BAC9ABC6ACB3 1 tan 6 = 3, cos 6 = AB=1 BC=2, AC= 3 2 A BC D 2 BDBD=BA 1 2 ABD BADBDA ABC6 BAD = (18 6 ) / 2 = 6 θ = 18 BAD = 12 () AD AD=BADCAD9 ABD ACD A 1 1 1 1 dsinαsinα = d 3 sin β 3 sin β
m(ẍ + γẋ + ω 0 x) = ee (2.118) e iωt P(ω) = χ(ω)e = ex = e2 E(ω) m ω0 2 ω2 iωγ (2.119) Z N ϵ(ω) ϵ 0 = 1 + Ne2 m j f j ω 2 j ω2 iωγ j (2.120)
2.6 2.6.1 mẍ + γẋ + ω 0 x) = ee 2.118) e iωt Pω) = χω)e = ex = e2 Eω) m ω0 2 ω2 iωγ 2.119) Z N ϵω) ϵ 0 = 1 + Ne2 m j f j ω 2 j ω2 iωγ j 2.120) Z ω ω j γ j f j f j f j sum j f j = Z 2.120 ω ω j, γ ϵω) ϵ
12-7 12-7 12-7 12-7 12-8 12-10 12-10 12-10 12-11 12-12 12-12 12-14 12-15 12-17 12-18 10 12-19 12-20 12-20 12-21 12-22 12-22 12-23 12-25 12-26 12-26 12-29 12-30 12-30 12-31 12-33 12-34 12-3 12-35 12-36
vol5-honma (LSR: Local Standard of Rest) 2.1 LSR R 0 LSR Θ 0 (Galactic Constant) 1985 (IAU: International Astronomical Union) R 0 =8.5
2.2 1 2.2 2.2.1 (LSR: Local Standard of Rest) 2.1 LSR R 0 LSR Θ 0 (Galactic Constant) 1985 (IAU: International Astronomical Union) R 0 =8.5 kpc, Θ 0 = 220 km s 1. (2.1) R 0 7kpc 8kpc Θ 0 180 km s 1 270
1 B () Ver 2014 0 2014/10 2015/1 http://www-cr.scphys.kyoto-u.ac.jp/member/tsuru/lecture/... 1. ( ) 2. 3. 3 1 7 1.1..................................................... 7 1.2.............................................
BIT -2-
2004.3.31 10 11 12-1- BIT -2- -3-256 258 932 524 585 -4- -5- A B A B AB A B A B C AB A B AB AB AB AB -6- -7- A B -8- -9- -10- mm -11- fax -12- -13- -14- -15- s58.10.1 1255 4.2 30.10-16- -17- -18- -19-6.12.10
Part () () Γ Part ,
Contents a 6 6 6 6 6 6 6 7 7. 8.. 8.. 8.3. 8 Part. 9. 9.. 9.. 3. 3.. 3.. 3 4. 5 4.. 5 4.. 9 4.3. 3 Part. 6 5. () 6 5.. () 7 5.. 9 5.3. Γ 3 6. 3 6.. 3 6.. 3 6.3. 33 Part 3. 34 7. 34 7.. 34 7.. 34 8. 35
