MOSFET HiSIM HiSIM2 1

Size: px
Start display at page:

Download "MOSFET HiSIM HiSIM2 1"

Transcription

1 MOSFET HiSIM HiSIM2 1

2 p/n Junction Shockley - - on-quasi-static Y- HiSIM2 2

3 Wilson E f E c E g E v Bandgap: E g Fermi Level: E f HiSIM2 3

4 a Si 1s 2s 2p 3s 3p HiSIM2 4

5 Fermi-Dirac Distribution Density-of of-state 1 f(e) D g(e) Carrier Concentration [ ] D p Ev E f E f n i 1- f ( E) g( E) ( ) ( ) D g E f Ec n E E n= N N f E E c : effective density of state N v : E n i =1.4x10 10 /cm 3 n = c p= N E Ec E E v top v bottom exp exp ( ) ( ) g E f E de ( ) ( ) p = g E f E de Ec -E kt fn E -E fp kt D (1- ) D v HiSIM2 5

6 p n Si Si Si Si Si Si Si -q Si Si Si B Si +q Si Si Si Si Si Si Si Si Si Si p + Si Si Si Si +q -q n i =1.4x10 10 /cm 3 Ev E f Ec E Ev E f Ec E Ev E f Ec E HiSIM2 6

7 Fermi n= n p= n c - fn cexp E E N c kt - fp v vexp E E N v kt = n i exp(-q(φ fn -φ i )/kt) = n i exp(-q(φ i -φ fp )/kt) E c E fn E=-qφ N c N v exp(e g /kt)=n i 2 E i E fp pn=n 2 i E v HiSIM2 7

8 p/n p/n Junction Equilibrium Condition - +q - +q - +q - +q + -q + -q + -q + -q - +q - +q - +q - +q + -q + -q + -q + -q - +q - +q - +q - +q + -q + -q + -q + -q - +q - +q q - +q q - +q - - / q + -q q + -q q + -q - + : N A : N D depletion region) HiSIM2 8

9 Fermi E fp p-type qx qφ f p n-type qφ f n E 0 E E c fn E v p/n E fp E c E fn E v Depletion Region - - ε E c E E f i E v HiSIM2 9

10 Poisson (x) E(x)=-dφ/dx ε ε ε ε ε HiSIM2 10

11 HiSIM2 11

12 HiSIM2 12

13 MOSFET Vg SOURCE v d Metal Electrode Oxide z SOURCE GATE DRAIN y n + Tox r j n+ x Channel L P-Type w Vb HiSIM2 13

14 HiSIM2 14

15 MOSFET Meyer Model J. E. Meyer, RCA Rev., vol. 32, p. 42, C. T. Sah, IEEE TED, ED11, 324, HiSIM2 15

16 MOSFET V gs V ds E y E x I qnv q: n: v V gs V ds HiSIM2 16

17 Vgs Semiconductor Surface E C E g ( φ > ) S qφ S 0 qφ qφ B E i E F E V Insulator p-type Semiconductor x HiSIM2 17

18 E F V <0 p -type E C E i E F E V V 0 E F V >0 n -type E C E F E i E V V >0 E F E C E i E F E V E F V < E E C E F i E V V >0 E F E C E i E F E V E F V < E C E E F i E V HiSIM2 18

19 HiSIM2 19

20 ( x ) Poisson :φ s 2 d φ ρ = 2 dx ε S ρ ( x) = q( N D N A + p n) N D N A = np0 pp0 p n = p exp ( βφ) n exp ( βφ) p0 Gradual Channel p0 x 2 φ = q ( ) ( ) ε p exp βφ 1 n exp βφ 1 2 p0 p0 x S φ/ x q φ ( ) ( ) d = ε p exp φ 1 n exp 1 d 0 x x 0 p0 p0 E 2 S φ φ β βφ φ 2 qp β 2kT n p0 = ( β q exp φ) + βφ+1 + p0 ( βφ) βφ 2ε p exp 1 E S si p0 ε = E ε = Q S : E ox ox s s HiSIM2 20

21 MOS HiSIM2 21

22 φ S Q b =sqrt(βφ s ) Q i =function(φ s ) charge-sheet HiSIM2 22

23 HiSIM2 23

24 V gs V ds E y E x I qnv q: n: v V gs V ds HiSIM2 24

25 d I = φ ds Wµ qn dy Ids dy = Wµ qndφ φ y = φ + V y ( ) ( ) 0 (y) Gauss Eoxε ox = ESiε Si = QS Vgs Vfb φ ( xy) = 0) ε T ox = Q Q ox n b ( ) 2 ( ) Q n = qn= Vgs Vfb φ0 V y Cox + εsiqnsub φ0 + V y L I dy = Wµ ds V ds 0 0 Q dv n W 1 I = µ C ( Vgs V ) V V L 2 2 ds ox th ds ds φ 0 =2Φ B ; V th = 2Φ + B 2E qn 2Φ C Si sub B ox HiSIM2 25

26 I ds V th V ds HiSIM2 26

27 HiSIM2 27

28 MOS φ f : (0 V ds ) φ s? V gs HiSIM2 28

29 φ φ φ SL : Gradual-Channel HiSIM2tut028 29

30 (y) ( ) ( ) ( ) dlnn y 1 dn y = dy n y dy ( ) ( ) I dφ y dn y ds s + n( y) β = W qµ dy dy eff L 0 ( ) I = I y dy ds ( ) ( ) C V y Q qn y ox G φs = B + ds HiSIM2 30

31 HiSIM2 32

32 HiSIM2 33

33 φ φ 2Φ B φ SL : Gradual-Channel HiSIM2tut028 34

34 - - HiSIM2 35

35 HiSIM2 36

36 Gradual-Channel φ φ HiSIM2 37

37 Channel-Length Modulation HiSIM2 38

38 HiSIM2 39

39 HiSIM2 40

40 Drift : : : HiSIM2 41

41 I x (t)=i x (V(t))+dQ x /dt HiSIM2 42

42 HiSIM2 43

43 HiSIM2 44

44 tut041 HiSIM2 45

45 tut042 HiSIM2 46

46 HiSIM2105 tut051 HiSIM2 47

47 IdVd gds NMOS Large HiSIM2 Measurement IdVg_low IdVg_low gm_low gm2_low gm3_low IdVg_high IdVg_high gm_high gm2_high gm3_high HiSIM2 48

48 L gate =40nm HiSIM2 49

49 HiSIM2 50

50 s SPICE ) HiSIM2 51

51 Donald O. Pederson You don t get any credit for doing 95 percent of the job. SPICE: Simulation Program with Integrated Circuit Emphasis HiSIM2 52

52 Circuit Simulator : Finding a set of for SPICE I ( I, I, I,... I ) s n V = ( V, V, V,... V ) s n by fulfilling the kirchhof law. m m+1 m V =V - I m g g V = - I + g V m I m m+1 m m m m+1 V m V Newton s Method HiSIM2 53

53 2 (V 2 ) I 21 Device1 1 (V 1 ) I 11 I 12 I I I 22 Device2 I 42 I 1 =I 11 +I 12 +I 13 I 2 =I 21 +I 22 I 3 =I 31 +I 13 3 (V 3 ) Device3 I 33 I 43 m m m m m m I11 I11 I 11 I11 I11 I V1 V2 V3 m+1 m V1 V2 V 3 V 1 +I m 11 V 1 m m m m I21 I21 I m m 21 m+1 m I21 I 21 I m V 2 = - +I V2 V1 V2 V3 V m+1 m 1 V2 V3 m m m m V 3 +I31 I31 I31 I m m m V I31 I31 I V1 V2 V 3 V1 V2 V 3 HiSIM2 54

untitled

untitled MOSFET 17 1 MOSFET.1 MOS.1.1 MOS.1. MOS.1.3 MOS 4.1.4 8.1.5 9. MOSFET..1 1.. 13..3 18..4 18..5 0..6 1.3 MOSFET.3.1.3. Poon & Yau 3.3.3 LDD MOSFET 5 3.1 3.1.1 6 3.1. 6 3. p MOSFET 3..1 8 3.. 31 3..3 36

More information

untitled

untitled /Si FET /Si FET Improvement of tunnel FET performance using narrow bandgap semiconductor silicide Improvement /Si hetero-structure of tunnel FET performance source electrode using narrow bandgap semiconductor

More information

スライド 1

スライド 1 Matsuura Laboratory SiC SiC 13 2004 10 21 22 H-SiC ( C-SiC HOY Matsuura Laboratory n E C E D ( E F E T Matsuura Laboratory Matsuura Laboratory DLTS Osaka Electro-Communication University Unoped n 3C-SiC

More information

13 2 9

13 2 9 13 9 1 1.1 MOS ASIC 1.1..3.4.5.6.7 3 p 3.1 p 3. 4 MOS 4.1 MOS 4. p MOS 4.3 5 CMOS NAND NOR 5.1 5. CMOS 5.3 CMOS NAND 5.4 CMOS NOR 5.5 .1.1 伝導帯 E C 禁制帯 E g E g E v 価電子帯 図.1 半導体のエネルギー帯. 5 4 伝導帯 E C 伝導電子

More information

PowerPoint プレゼンテーション

PowerPoint プレゼンテーション Drain Voltage (mv) 4 2 0-2 -4 0.0 0.2 0.4 0.6 0.8 1.0 Gate Voltage (V) Vds [V] 0.2 0.1 0.0-0.1-0.2-10 -8-6 -4-2 0 Vgs [V] 10 1000 1000 1000 1000 (LSI) Fe Catalyst Fe Catalyst Carbon nanotube 1~2 nm

More information

Acrobat Distiller, Job 2

Acrobat Distiller, Job 2 2 3 4 5 Eg φm s M f 2 qv ( q qφ ) = qφ qχ + + qφ 0 0 = 6 p p ( Ei E f ) kt = n e i Q SC = qn W A n p ( E f Ei ) kt = n e i 7 8 2 d φ( x) qn = A 2 dx ε ε 0 s φ qn s 2ε ε A ( x) = ( x W ) 2 0 E s A 2 EOX

More information

U.C. Berkeley SPICE Simulation Program with Integrated Circuit Emphasis 1) SPICE SPICE netli

U.C. Berkeley SPICE Simulation Program with Integrated Circuit Emphasis 1) SPICE SPICE netli 1 -- 7 7 2008 12 7-1 7-2 c 2011 1/(12) 1 -- 7 -- 7 7--1 2008 12 1960 1970 1972 U.C. Berkeley SPICE Simulation Program with Integrated Circuit Emphasis 1) SPICE SPICE 7--1--1 7 1 7 1 1 netlist SPICE 2)

More information

PowerPoint Presentation

PowerPoint Presentation 半導体電子工学 II 神戸大学工学部 電気電子工学科 12/08/'10 半導体電子工学 Ⅱ 1 全体の内容 日付内容 ( 予定 ) 備考 1 10 月 6 日半導体電子工学 I の基礎 ( 復習 ) 11/24/'10 2 10 月 13 日 pn 接合ダイオード (1) 3 10 月 20 日 4 10 月 27 日 5 11 月 10 日 pn 接合ダイオード (2) pn 接合ダイオード (3)

More information

jse2000.dvi

jse2000.dvi pn 1 2 1 1947 1 (800MHz) (12GHz) (CPUDSP ) 1: MOS (MOSFET) CCD MOSFET MES (MESFET) (HBT) (HEMT) GTO MOSFET (IGBT) (SIT) pn { 3 3 3 pn 2 pn pn 1 2 sirafuji@dj.kit.ac.jp yoshimot@dj.kit.ac.jp 1 3 3.1 III

More information

untitled

untitled Tokyo Institute of Technology high-k/ In.53 Ga.47 As MOS - Defect Analysis of high-k/in.53 G a.47 As MOS Capacitor using capacitance voltage method,,, Darius Zade,,, Parhat Ahmet,,,,,, ~InGaAs high-k ~

More information

devicemondai

devicemondai c 2019 i 3 (1) q V I T ε 0 k h c n p (2) T 300 K (3) A ii c 2019 i 1 1 2 13 3 30 4 53 5 78 6 89 7 101 8 112 9 116 A 131 B 132 c 2019 1 1 300 K 1.1 1.5 V 1.1 qv = 1.60 10 19 C 1.5 V = 2.4 10 19 J (1.1)

More information

橡Taro11-卒業論文.PDF

橡Taro11-卒業論文.PDF Recombination Generation Lifetime 13 9 1. 3. 4.1. 4.. 9 3. Recombination Lifetime 17 3.1. 17 3.. 19 3.3. 4. 1 4.1. Si 1 4.1.1. 1 4.1.. 4.. TEG 3 5. Recombination Lifetime 4 5.1 Si 4 5.. TEG 6 6. Pulse

More information

( ) : 1997

( ) : 1997 ( ) 2008 2 17 : 1997 CMOS FET AD-DA All Rights Reserved (c) Yoichi OKABE 2000-present. [ HTML ] [ PDF ] [ ] [ Web ] [ ] [ HTML ] [ PDF ] 1 1 4 1.1..................................... 4 1.2..................................

More information

untitled

untitled 20101221JST (SiC - Buried Gate Static Induction Transistor: SiC-BGSIT) SOURCE GATE N source layer p + n p + n p + n p+ n drift layer n + substrate DRAIN SiC-BGSIT (mωcm 2 ) 200 100 40 10 4 1 Si limit

More information

MOSFET 6-2 CMOS 6-2 TTL Transistor Transistor Logic ECL Emitter Coupled Logic I2L Integrated

MOSFET 6-2 CMOS 6-2 TTL Transistor Transistor Logic ECL Emitter Coupled Logic I2L Integrated 1 -- 7 6 2011 11 1 6-1 MOSFET 6-2 CMOS 6-2 TTL Transistor Transistor Logic ECL Emitter Coupled Logic I2L Integrated Injection Logic 6-3 CMOS CMOS NAND NOR CMOS 6-4 6-5 6-1 6-2 CMOS 6-3 6-4 6-5 c 2011 1/(33)

More information

120 9 I I 1 I 2 I 1 I 2 ( a) ( b) ( c ) I I 2 I 1 I ( d) ( e) ( f ) 9.1: Ampère (c) (d) (e) S I 1 I 2 B ds = µ 0 ( I 1 I 2 ) I 1 I 2 B ds =0. I 1 I 2

120 9 I I 1 I 2 I 1 I 2 ( a) ( b) ( c ) I I 2 I 1 I ( d) ( e) ( f ) 9.1: Ampère (c) (d) (e) S I 1 I 2 B ds = µ 0 ( I 1 I 2 ) I 1 I 2 B ds =0. I 1 I 2 9 E B 9.1 9.1.1 Ampère Ampère Ampère s law B S µ 0 B ds = µ 0 j ds (9.1) S rot B = µ 0 j (9.2) S Ampère Biot-Savart oulomb Gauss Ampère rot B 0 Ampère µ 0 9.1 (a) (b) I B ds = µ 0 I. I 1 I 2 B ds = µ 0

More information

18 2 F 12 r 2 r 1 (3) Coulomb km Coulomb M = kg F G = ( ) ( ) ( ) 2 = [N]. Coulomb

18 2 F 12 r 2 r 1 (3) Coulomb km Coulomb M = kg F G = ( ) ( ) ( ) 2 = [N]. Coulomb r 1 r 2 r 1 r 2 2 Coulomb Gauss Coulomb 2.1 Coulomb 1 2 r 1 r 2 1 2 F 12 2 1 F 21 F 12 = F 21 = 1 4πε 0 1 2 r 1 r 2 2 r 1 r 2 r 1 r 2 (2.1) Coulomb ε 0 = 107 4πc 2 =8.854 187 817 10 12 C 2 N 1 m 2 (2.2)

More information

Microsoft PowerPoint - semi_ppt07.ppt

Microsoft PowerPoint - semi_ppt07.ppt 半導体工学第 9 回目 / OKM 1 MOSFET の動作原理 しきい電圧 (V( TH) と制御 E 型と D 型 0 次近似によるドレイン電流解析 半導体工学第 9 回目 / OKM 2 電子のエネルギーバンド図での考察 金属 (M) 酸化膜 (O) シリコン (S) 熱平衡でフラットバンド 伝導帯 E c 電子エネルギ シリコンと金属の仕事関数が等しい 界面を含む酸化膜中に余分な電荷がない

More information

Microsoft PowerPoint - semi_ppt07.ppt [互換モード]

Microsoft PowerPoint - semi_ppt07.ppt [互換モード] 1 MOSFETの動作原理 しきい電圧 (V TH ) と制御 E 型とD 型 0 次近似によるドレイン電流解析 2 電子のエネルギーバンド図での考察 理想 MOS 構造の仮定 : シリコンと金属の仕事関数が等しい 界面を含む酸化膜中に余分な電荷がない 金属 (M) 酸化膜 (O) シリコン (S) 電子エ金属 酸化膜 シリコン (M) (O) (S) フラットバンド ネルギー熱平衡で 伝導帯 E

More information

note2.dvi

note2.dvi 8 216614 2.4 Joh Bardee, William Shockley, Walter Brattai. 1948 Bell William Shockley BrattaiBardee Shockley 1947 (12/16 23)Shockley BrattaiBardee (Trasistor, TrasferResistor ) Shockley 1/23 1 [2] 2.4.1

More information

MOS FET c /(17)

MOS FET c /(17) 1 -- 7 1 2008 9 MOS FT 1-1 1-2 1-3 1-4 c 2011 1/(17) 1 -- 7 -- 1 1--1 2008 9 1 1 1 1(a) VVS: Voltage ontrolled Voltage Source v in µ µ µ 1 µ 1 vin 1 + - v in 2 2 1 1 (a) VVS( ) (b) S( ) i in i in 2 2 1

More information

IA

IA IA 31 4 11 1 1 4 1.1 Planck.............................. 4 1. Bohr.................................... 5 1.3..................................... 6 8.1................................... 8....................................

More information

30

30 3 ............................................2 2...........................................2....................................2.2...................................2.3..............................

More information

i

i 009 I 1 8 5 i 0 1 0.1..................................... 1 0.................................................. 1 0.3................................. 0.4........................................... 3

More information

5 5.1 E 1, E 2 N 1, N 2 E tot N tot E tot = E 1 + E 2, N tot = N 1 + N 2 S 1 (E 1, N 1 ), S 2 (E 2, N 2 ) E 1, E 2 S tot = S 1 + S 2 2 S 1 E 1 = S 2 E

5 5.1 E 1, E 2 N 1, N 2 E tot N tot E tot = E 1 + E 2, N tot = N 1 + N 2 S 1 (E 1, N 1 ), S 2 (E 2, N 2 ) E 1, E 2 S tot = S 1 + S 2 2 S 1 E 1 = S 2 E 5 5.1 E 1, E 2 N 1, N 2 E tot N tot E tot = E 1 + E 2, N tot = N 1 + N 2 S 1 (E 1, N 1 ), S 2 (E 2, N 2 ) E 1, E 2 S tot = S 1 + S 2 2 S 1 E 1 = S 2 E 2, S 1 N 1 = S 2 N 2 2 (chemical potential) µ S N

More information

Microsoft PowerPoint - 4.1I-V特性.pptx

Microsoft PowerPoint - 4.1I-V特性.pptx 4.1 I-V 特性 MOSFET 特性とモデル 1 物理レベルの設計 第 3 章までに システム~ トランジスタレベルまでの設計の概要を学んだが 製造するためには さらに物理的パラメータ ( 寸法など ) が必要 物理的パラメータの決定には トランジスタの特性を理解する必要がある ゲート内の配線の太さ = 最小加工寸法 物理的パラメータの例 電源配線の太さ = 電源ラインに接続されるゲート数 (

More information

untitled

untitled SPring-8 RFgun JASRI/SPring-8 6..7 Contents.. 3.. 5. 6. 7. 8. . 3 cavity γ E A = er 3 πε γ vb r B = v E c r c A B A ( ) F = e E + v B A A A A B dp e( v B+ E) = = m d dt dt ( γ v) dv e ( ) dt v B E v E

More information

B1 Ver ( ), SPICE.,,,,. * : student : jikken. [ ] ( TarouOsaka). (, ) 1 SPICE ( SPICE. *1 OrCAD

B1 Ver ( ), SPICE.,,,,. * : student : jikken. [ ] ( TarouOsaka). (, ) 1 SPICE ( SPICE. *1 OrCAD B1 er. 3.05 (2019.03.27), SPICE.,,,,. * 1 1. 1. 1 1.. 2. : student : jikken. [ ] ( TarouOsaka). (, ) 1 SPICE ( SPICE. *1 OrCAD https://www.orcad.com/jp/resources/orcad-downloads.. 1 2. SPICE 1. SPICE Windows

More information

Bethe-Bloch Bethe-Bloch (stopping range) Bethe-Bloch FNAL (Fermi National Accelerator Laboratory) - (SciBooNE ) SciBooNE Bethe-Bloch FNAL - (SciBooNE

Bethe-Bloch Bethe-Bloch (stopping range) Bethe-Bloch FNAL (Fermi National Accelerator Laboratory) - (SciBooNE ) SciBooNE Bethe-Bloch FNAL - (SciBooNE 21 2 27 Bethe-Bloch Bethe-Bloch (stopping range) Bethe-Bloch FNAL (Fermi National Accelerator Laboratory) - (SciBooNE ) SciBooNE Bethe-Bloch FNAL - (SciBooNE ) Bethe-Bloch 1 0.1..............................

More information

V(x) m e V 0 cos x π x π V(x) = x < π, x > π V 0 (i) x = 0 (V(x) V 0 (1 x 2 /2)) n n d 2 f dξ 2ξ d f 2 dξ + 2n f = 0 H n (ξ) (ii) H

V(x) m e V 0 cos x π x π V(x) = x < π, x > π V 0 (i) x = 0 (V(x) V 0 (1 x 2 /2)) n n d 2 f dξ 2ξ d f 2 dξ + 2n f = 0 H n (ξ) (ii) H 199 1 1 199 1 1. Vx) m e V cos x π x π Vx) = x < π, x > π V i) x = Vx) V 1 x /)) n n d f dξ ξ d f dξ + n f = H n ξ) ii) H n ξ) = 1) n expξ ) dn dξ n exp ξ )) H n ξ)h m ξ) exp ξ )dξ = π n n!δ n,m x = Vx)

More information

Part () () Γ Part ,

Part () () Γ Part , Contents a 6 6 6 6 6 6 6 7 7. 8.. 8.. 8.3. 8 Part. 9. 9.. 9.. 3. 3.. 3.. 3 4. 5 4.. 5 4.. 9 4.3. 3 Part. 6 5. () 6 5.. () 7 5.. 9 5.3. Γ 3 6. 3 6.. 3 6.. 3 6.3. 33 Part 3. 34 7. 34 7.. 34 7.. 34 8. 35

More information

A B P (A B) = P (A)P (B) (3) A B A B P (B A) A B A B P (A B) = P (B A)P (A) (4) P (B A) = P (A B) P (A) (5) P (A B) P (B A) P (A B) A B P

A B P (A B) = P (A)P (B) (3) A B A B P (B A) A B A B P (A B) = P (B A)P (A) (4) P (B A) = P (A B) P (A) (5) P (A B) P (B A) P (A B) A B P 1 1.1 (population) (sample) (event) (trial) Ω () 1 1 Ω 1.2 P 1. A A P (A) 0 1 0 P (A) 1 (1) 2. P 1 P 0 1 6 1 1 6 0 3. A B P (A B) = P (A) + P (B) (2) A B A B A 1 B 2 A B 1 2 1 2 1 1 2 2 3 1.3 A B P (A

More information

3-2 PET ( : CYRIC ) ( 0 ) (3-1 ) PET PET [min] 11 C 13 N 15 O 18 F 68 Ga [MeV] [mm] [MeV]

3-2 PET ( : CYRIC ) ( 0 ) (3-1 ) PET PET [min] 11 C 13 N 15 O 18 F 68 Ga [MeV] [mm] [MeV] 3 PET 3-1 PET 3-1-1 PET PET 1-1 X CT MRI(Magnetic Resonance Imaging) X CT MRI PET 3-1 PET [1] H1 D2 11 C-doxepin 11 C-raclopride PET H1 D2 3-2 PET 0 0 H1 D2 3-1 PET 3-2 PET ( : CYRIC ) ( 0 ) 3-1-2 (3-1

More information

(4.15a) Hurwitz (4.15a) {a j } (s ) {a j } n n Hurwitz a n 1 a n 3 a n 5 a n a n 2 a n 4 a n 1 a n 3 H = a n a n 2. (4.16)..... a Hurwitz H i H i i H

(4.15a) Hurwitz (4.15a) {a j } (s ) {a j } n n Hurwitz a n 1 a n 3 a n 5 a n a n 2 a n 4 a n 1 a n 3 H = a n a n 2. (4.16)..... a Hurwitz H i H i i H 6 ( ) 218 1 28 4.2.6 4.1 u(t) w(t) K w(t) = Ku(t τ) (4.1) τ Ξ(iω) = exp[ α(ω) iβ(ω)] (4.11) (4.1) exp[ α(ω) iβ(ω)] = K exp( iωτ) (4.12) α(ω) = ln(k), β(ω) = ωτ (4.13) dϕ/dω f T 4.3 ( ) OP-amp Nyquist Hurwitz

More information

総研大恒星進化概要.dvi

総研大恒星進化概要.dvi The Structure and Evolution of Stars I. Basic Equations. M r r =4πr2 ρ () P r = GM rρ. r 2 (2) r: M r : P and ρ: G: M r Lagrange r = M r 4πr 2 rho ( ) P = GM r M r 4πr. 4 (2 ) s(ρ, P ) s(ρ, P ) r L r T

More information

電子回路I_4.ppt

電子回路I_4.ppt 電子回路 Ⅰ 第 4 回 電子回路 Ⅰ 5 1 講義内容 1. 半導体素子 ( ダイオードとトランジスタ ) 2. 基本回路 3. 増幅回路 電界効果トランジスタ (FET) 基本構造 基本動作動作原理 静特性 電子回路 Ⅰ 5 2 半導体素子 ( ダイオードとトランジスタ ) ダイオード (2 端子素子 ) トランジスタ (3 端子素子 ) バイポーラトランジスタ (Biolar) 電界効果トランジスタ

More information

I-2 (100 ) (1) y(x) y dy dx y d2 y dx 2 (a) y + 2y 3y = 9e 2x (b) x 2 y 6y = 5x 4 (2) Bernoulli B n (n = 0, 1, 2,...) x e x 1 = n=0 B 0 B 1 B 2 (3) co

I-2 (100 ) (1) y(x) y dy dx y d2 y dx 2 (a) y + 2y 3y = 9e 2x (b) x 2 y 6y = 5x 4 (2) Bernoulli B n (n = 0, 1, 2,...) x e x 1 = n=0 B 0 B 1 B 2 (3) co 16 I ( ) (1) I-1 I-2 I-3 (2) I-1 ( ) (100 ) 2l x x = 0 y t y(x, t) y(±l, t) = 0 m T g y(x, t) l y(x, t) c = 2 y(x, t) c 2 2 y(x, t) = g (A) t 2 x 2 T/m (1) y 0 (x) y 0 (x) = g c 2 (l2 x 2 ) (B) (2) (1)

More information

2 0.1 Introduction NMR 70% 1/2

2 0.1 Introduction NMR 70% 1/2 Y. Kondo 2010 1 22 2 0.1 Introduction NMR 70% 1/2 3 0.1 Introduction......................... 2 1 7 1.1.................... 7 1.2............................ 11 1.3................... 12 1.4..........................

More information

Mott散乱によるParity対称性の破れを検証

Mott散乱によるParity対称性の破れを検証 Mott Parity P2 Mott target Mott Parity Parity Γ = 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 t P P ),,, ( 3 2 1 0 1 γ γ γ γ γ γ ν ν µ µ = = Γ 1 : : : Γ P P P P x x P ν ν µ µ vector axial vector ν ν µ µ γ γ Γ ν γ

More information

2.1: n = N/V ( ) k F = ( 3π 2 N ) 1/3 = ( 3π 2 n ) 1/3 V (2.5) [ ] a = h2 2m k2 F h2 2ma (1 27 ) (1 8 ) erg, (2.6) /k B 1 11 / K

2.1: n = N/V ( ) k F = ( 3π 2 N ) 1/3 = ( 3π 2 n ) 1/3 V (2.5) [ ] a = h2 2m k2 F h2 2ma (1 27 ) (1 8 ) erg, (2.6) /k B 1 11 / K 2 2.1? [ ] L 1 ε(p) = 1 ( p 2 2m x + p 2 y + pz) 2 = h2 ( k 2 2m x + ky 2 + kz) 2 n x, n y, n z (2.1) (2.2) p = hk = h 2π L (n x, n y, n z ) (2.3) n k p 1 i (ε i ε i+1 )1 1 g = 2S + 1 2 1/2 g = 2 ( p F

More information

positron 1930 Dirac 1933 Anderson m 22Na(hl=2.6years), 58Co(hl=71days), 64Cu(hl=12hour) 68Ge(hl=288days) MeV : thermalization m psec 100

positron 1930 Dirac 1933 Anderson m 22Na(hl=2.6years), 58Co(hl=71days), 64Cu(hl=12hour) 68Ge(hl=288days) MeV : thermalization m psec 100 positron 1930 Dirac 1933 Anderson m 22Na(hl=2.6years), 58Co(hl=71days), 64Cu(hl=12hour) 68Ge(hl=288days) 0.5 1.5MeV : thermalization 10 100 m psec 100psec nsec E total = 2mc 2 + E e + + E e Ee+ Ee-c mc

More information

入試の軌跡

入試の軌跡 4 y O x 4 Typed by L A TEX ε ) ) ) 6 4 ) 4 75 ) http://kumamoto.s.xrea.com/plan/.. PDF) Ctrl +L) Ctrl +) Ctrl + Ctrl + ) ) Alt + ) Alt + ) ESC. http://kumamoto.s.xrea.com/nyusi/kumadai kiseki ri i.pdf

More information

PowerPoint Presentation

PowerPoint Presentation 半導体電子工学 II 神戸大学工学部電気電子工学科 小川真人 09/01/21 半導体電子工学 II 日付内容 ( 予定 ) 備考 1 10 月 1 日半導体電子工学 I の基礎 ( 復習 ) 2 10 月 8 日半導体電子工学 I の基礎 ( 復習 ) 3 10 月 15 日 pn 接合ダイオード (1) 4 10 月 22 日 pn 接合ダイオード (2) 5 10 月 29 日 pn 接合ダイオード

More information

. ev=,604k m 3 Debye ɛ 0 kt e λ D = n e n e Ze 4 ln Λ ν ei = 5.6π / ɛ 0 m/ e kt e /3 ν ei v e H + +e H ev Saha x x = 3/ πme kt g i g e n

. ev=,604k m 3 Debye ɛ 0 kt e λ D = n e n e Ze 4 ln Λ ν ei = 5.6π / ɛ 0 m/ e kt e /3 ν ei v e H + +e H ev Saha x x = 3/ πme kt g i g e n 003...............................3 Debye................. 3.4................ 3 3 3 3. Larmor Cyclotron... 3 3................ 4 3.3.......... 4 3.3............ 4 3.3...... 4 3.3.3............ 5 3.4.........

More information

2 2 MATHEMATICS.PDF 200-2-0 3 2 (p n ), ( ) 7 3 4 6 5 20 6 GL 2 (Z) SL 2 (Z) 27 7 29 8 SL 2 (Z) 35 9 2 40 0 2 46 48 2 2 5 3 2 2 58 4 2 6 5 2 65 6 2 67 7 2 69 2 , a 0 + a + a 2 +... b b 2 b 3 () + b n a

More information

E 1/2 3/ () +3/2 +3/ () +1/2 +1/ / E [1] B (3.2) F E 4.1 y x E = (E x,, ) j y 4.1 E int = (, E y, ) j y = (Hall ef

E 1/2 3/ () +3/2 +3/ () +1/2 +1/ / E [1] B (3.2) F E 4.1 y x E = (E x,, ) j y 4.1 E int = (, E y, ) j y = (Hall ef 4 213 5 8 4.1.1 () f A exp( E/k B ) f E = A [ k B exp E ] = f k B k B = f (2 E /3n). 1 k B /2 σ = e 2 τ(e)d(e) 2E 3nf 3m 2 E de = ne2 τ E m (4.1) E E τ E = τe E = / τ(e)e 3/2 f de E 3/2 f de (4.2) f (3.2)

More information

QMI_10.dvi

QMI_10.dvi ... black body radiation black body black body radiation Gustav Kirchhoff 859 895 W. Wien O.R. Lummer cavity radiation ν ν +dν f T (ν) f T (ν)dν = 8πν2 c 3 kt dν (Rayleigh Jeans) (.) f T (ν) spectral energy

More information

pdf

pdf http://www.ns.kogakuin.ac.jp/~ft13389/lecture/physics1a2b/ pdf I 1 1 1.1 ( ) 1. 30 m µm 2. 20 cm km 3. 10 m 2 cm 2 4. 5 cm 3 km 3 5. 1 6. 1 7. 1 1.2 ( ) 1. 1 m + 10 cm 2. 1 hr + 6400 sec 3. 3.0 10 5 kg

More information

1 B () Ver 2014 0 2014/10 2015/1 http://www-cr.scphys.kyoto-u.ac.jp/member/tsuru/lecture/... 1. ( ) 2. 3. 3 1 7 1.1..................................................... 7 1.2.............................................

More information

C el = 3 2 Nk B (2.14) c el = 3k B C el = 3 2 Nk B

C el = 3 2 Nk B (2.14) c el = 3k B C el = 3 2 Nk B I ino@hiroshima-u.ac.jp 217 11 14 4 4.1 2 2.4 C el = 3 2 Nk B (2.14) c el = 3k B 2 3 3.15 C el = 3 2 Nk B 3.15 39 2 1925 (Wolfgang Pauli) (Pauli exclusion principle) T E = p2 2m p T N 4 Pauli Sommerfeld

More information

[ ] (Ising model) 2 i S i S i = 1 (up spin : ) = 1 (down spin : ) (4.38) s z = ±1 4 H 0 = J zn/2 i,j S i S j (4.39) i, j z 5 2 z = 4 z = 6 3

[ ] (Ising model) 2 i S i S i = 1 (up spin : ) = 1 (down spin : ) (4.38) s z = ±1 4 H 0 = J zn/2 i,j S i S j (4.39) i, j z 5 2 z = 4 z = 6 3 4.2 4.2.1 [ ] (Ising model) 2 i S i S i = 1 (up spin : ) = 1 (down spin : ) (4.38) s z = ±1 4 H 0 = J zn/2 S i S j (4.39) i, j z 5 2 z = 4 z = 6 3 z = 6 z = 8 zn/2 1 2 N i z nearest neighbors of i j=1

More information

I ( ) 1 de Broglie 1 (de Broglie) p λ k h Planck ( Js) p = h λ = k (1) h 2π : Dirac k B Boltzmann ( J/K) T U = 3 2 k BT

I ( ) 1 de Broglie 1 (de Broglie) p λ k h Planck ( Js) p = h λ = k (1) h 2π : Dirac k B Boltzmann ( J/K) T U = 3 2 k BT I (008 4 0 de Broglie (de Broglie p λ k h Planck ( 6.63 0 34 Js p = h λ = k ( h π : Dirac k B Boltzmann (.38 0 3 J/K T U = 3 k BT ( = λ m k B T h m = 0.067m 0 m 0 = 9. 0 3 kg GaAs( a T = 300 K 3 fg 07345

More information

VLSI工学

VLSI工学 2008//5/ () 2008//5/ () 2 () http://ssc.pe.titech.ac.jp 2008//5/ () 3!! A (WCDMA/GSM) DD DoCoMo 905iP905i 2008//5/ () 4 minisd P900i SemiConsult SDRAM, MPEG4 UIMIrDA LCD/ AF ADC/DAC IC CCD C-CPUA-CPU DSPSRAM

More information

0201

0201 2018 10 17 2019 9 19 SI J cal 1mL 1ºC 1999 cal nutrition facts label calories cal kcal 1 cal = 4.184 J heat capacity 1 K 1 J K 1 mol molar heat capacity J K mol (specific heat specific heat capacity) 1

More information

II 2 II

II 2 II II 2 II 2005 yugami@cc.utsunomiya-u.ac.jp 2005 4 1 1 2 5 2.1.................................... 5 2.2................................. 6 2.3............................. 6 2.4.................................

More information

A 2 3. m S m = {x R m+1 x = 1} U + k = {x S m x k > 0}, U k = {x S m x k < 0}, ϕ ± k (x) = (x 0,..., ˆx k,... x m ) 1. {(U ± k, ϕ± k ) 0 k m} S m 1.2.

A 2 3. m S m = {x R m+1 x = 1} U + k = {x S m x k > 0}, U k = {x S m x k < 0}, ϕ ± k (x) = (x 0,..., ˆx k,... x m ) 1. {(U ± k, ϕ± k ) 0 k m} S m 1.2. A A 1 A 5 A 6 1 2 3 4 5 6 7 1 1.1 1.1 (). Hausdorff M R m M M {U α } U α R m E α ϕ α : U α E α U α U β = ϕ α (ϕ β ϕβ (U α U β )) 1 : ϕ β (U α U β ) ϕ α (U α U β ) C M a m dim M a U α ϕ α {x i, 1 i m} {U,

More information

() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)

() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi) 0. A A = 4 IC () det A () A () x + y + z = x y z X Y Z = A x y z ( 5) ( s5590) 0. a + b + c b c () a a + b + c c a b a + b + c 0 a b c () a 0 c b b c 0 a c b a 0 0. A A = 7 5 4 5 0 ( 5) ( s5590) () A ()

More information

PowerPoint Presentation

PowerPoint Presentation 2010 KEK (Japan) (Japan) (Japan) Cheoun, Myun -ki Soongsil (Korea) Ryu,, Chung-Yoe Soongsil (Korea) 1. S.Reddy, M.Prakash and J.M. Lattimer, P.R.D58 #013009 (1998) Magnetar : ~ 10 15 G ~ 10 17 19 G (?)

More information

untitled

untitled 4/6 S. Hara@ [.ppt] On Road 4/9 4/6 4/ 5/7 4 Scott 5/4 5 Off Road 5/ 5/8 6 7 S. Hara@ [.ppt] ... 4. [] S. Hara@ [.ppt] : 4 ε s ε a ε b Anti-bonding orbital bonding orbital Anion Cation ε c ε a ε a ε b

More information

f(x) = f(x ) + α(x)(x x ) α(x) x = x. x = f (y), x = f (y ) y = f f (y) = f f (y ) + α(f (y))(f (y) f (y )) f (y) = f (y ) + α(f (y)) (y y ) ( (2) ) f

f(x) = f(x ) + α(x)(x x ) α(x) x = x. x = f (y), x = f (y ) y = f f (y) = f f (y ) + α(f (y))(f (y) f (y )) f (y) = f (y ) + α(f (y)) (y y ) ( (2) ) f 22 A 3,4 No.3 () (2) (3) (4), (5) (6) (7) (8) () n x = (x,, x n ), = (,, n ), x = ( (x i i ) 2 ) /2 f(x) R n f(x) = f() + i α i (x ) i + o( x ) α,, α n g(x) = o( x )) lim x g(x) x = y = f() + i α i(x )

More information

..3. Ω, Ω F, P Ω, F, P ). ) F a) A, A,..., A i,... F A i F. b) A F A c F c) Ω F. ) A F A P A),. a) 0 P A) b) P Ω) c) [ ] A, A,..., A i,... F i j A i A

..3. Ω, Ω F, P Ω, F, P ). ) F a) A, A,..., A i,... F A i F. b) A F A c F c) Ω F. ) A F A P A),. a) 0 P A) b) P Ω) c) [ ] A, A,..., A i,... F i j A i A .. Laplace ). A... i),. ω i i ). {ω,..., ω } Ω,. ii) Ω. Ω. A ) r, A P A) P A) r... ).. Ω {,, 3, 4, 5, 6}. i i 6). A {, 4, 6} P A) P A) 3 6. ).. i, j i, j) ) Ω {i, j) i 6, j 6}., 36. A. A {i, j) i j }.

More information

arma dvi

arma dvi ARMA 007/05/0 Rev.0 007/05/ Rev.0 007/07/7 3. : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : 3. : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : : 3.3 : : : :

More information

2 3 v v S i i L L S i i E i v L E i v 3. L urren (A) approx. 60% E = V = 0 Ω L = 00 mh urren (A) app

2 3 v v S i i L L S i i E i v L E i v 3. L urren (A) approx. 60% E = V = 0 Ω L = 00 mh urren (A) app 3 ON ON L * 3. v() = i() (3.) 3.2 L 3. L = 0 S i() = i () = i L () v () L v L () = 0 L v () = i(), (3.4) v L () = L d i(). (3.5) d v () + v L () = E, (3.6) i () = i L () = i(). (3.7) L d i() + i() = E.

More information

Maxwell

Maxwell I 2018 12 13 0 4 1 6 1.1............................ 6 1.2 Maxwell......................... 8 1.3.......................... 9 1.4..................... 11 1.5..................... 12 2 13 2.1...................

More information

B line of mgnetic induction AB MN ds df (7.1) (7.3) (8.1) df = µ 0 ds, df = ds B = B ds 2π A B P P O s s Q PQ R QP AB θ 0 <θ<π

B line of mgnetic induction AB MN ds df (7.1) (7.3) (8.1) df = µ 0 ds, df = ds B = B ds 2π A B P P O s s Q PQ R QP AB θ 0 <θ<π 8 Biot-Svt Ampèe Biot-Svt 8.1 Biot-Svt 8.1.1 Ampèe B B B = µ 0 2π. (8.1) B N df B ds A M 8.1: Ampèe 107 108 8 0 B line of mgnetic induction 8.1 8.1 AB MN ds df (7.1) (7.3) (8.1) df = µ 0 ds, df = ds B

More information

Microsoft Word - 章末問題

Microsoft Word - 章末問題 1906 R n m 1 = =1 1 R R= 8h ICP s p s HeNeArXe 1 ns 1 1 1 1 1 17 NaCl 1.3 nm 10nm 3s CuAuAg NaCl CaF - - HeNeAr 1.7(b) 2 2 2d = a + a = 2a d = 2a 2 1 1 N = 8 + 6 = 4 8 2 4 4 2a 3 4 π N πr 3 3 4 ρ = = =

More information

4. ϵ(ν, T ) = c 4 u(ν, T ) ϵ(ν, T ) T ν π4 Planck dx = 0 e x 1 15 U(T ) x 3 U(T ) = σt 4 Stefan-Boltzmann σ 2π5 k 4 15c 2 h 3 = W m 2 K 4 5.

4. ϵ(ν, T ) = c 4 u(ν, T ) ϵ(ν, T ) T ν π4 Planck dx = 0 e x 1 15 U(T ) x 3 U(T ) = σt 4 Stefan-Boltzmann σ 2π5 k 4 15c 2 h 3 = W m 2 K 4 5. A 1. Boltzmann Planck u(ν, T )dν = 8πh ν 3 c 3 kt 1 dν h 6.63 10 34 J s Planck k 1.38 10 23 J K 1 Boltzmann u(ν, T ) T ν e hν c = 3 10 8 m s 1 2. Planck λ = c/ν Rayleigh-Jeans u(ν, T )dν = 8πν2 kt dν c

More information

50 2 I SI MKSA r q r q F F = 1 qq 4πε 0 r r 2 r r r r (2.2 ε 0 = 1 c 2 µ 0 c = m/s q 2.1 r q' F r = 0 µ 0 = 4π 10 7 N/A 2 k = 1/(4πε 0 qq

50 2 I SI MKSA r q r q F F = 1 qq 4πε 0 r r 2 r r r r (2.2 ε 0 = 1 c 2 µ 0 c = m/s q 2.1 r q' F r = 0 µ 0 = 4π 10 7 N/A 2 k = 1/(4πε 0 qq 49 2 I II 2.1 3 e e = 1.602 10 19 A s (2.1 50 2 I SI MKSA 2.1.1 r q r q F F = 1 qq 4πε 0 r r 2 r r r r (2.2 ε 0 = 1 c 2 µ 0 c = 3 10 8 m/s q 2.1 r q' F r = 0 µ 0 = 4π 10 7 N/A 2 k = 1/(4πε 0 qq F = k r

More information

Radiation from moving charges#1 Liénard-Wiechert potential Yuji Chinone 1 Maxwell Maxwell MKS E (x, t) + B (x, t) t = 0 (1) B (x, t) = 0 (2) B (x, t)

Radiation from moving charges#1 Liénard-Wiechert potential Yuji Chinone 1 Maxwell Maxwell MKS E (x, t) + B (x, t) t = 0 (1) B (x, t) = 0 (2) B (x, t) Radiation from moving harges# Liénard-Wiehert potential Yuji Chinone Maxwell Maxwell MKS E x, t + B x, t = B x, t = B x, t E x, t = µ j x, t 3 E x, t = ε ρ x, t 4 ε µ ε µ = E B ρ j A x, t φ x, t A x, t

More information

all.dvi

all.dvi I 1 Density Matrix 1.1 ( (Observable) Ô :ensemble ensemble average) Ô en =Tr ˆρ en Ô ˆρ en Tr  n, n =, 1,, Tr  = n n  n Tr  I w j j ( j =, 1,, ) ˆρ en j w j j ˆρ en = j w j j j Ô en = j w j j Ô j emsemble

More information

18 I ( ) (1) I-1,I-2,I-3 (2) (3) I-1 ( ) (100 ) θ ϕ θ ϕ m m l l θ ϕ θ ϕ 2 g (1) (2) 0 (3) θ ϕ (4) (3) θ(t) = A 1 cos(ω 1 t + α 1 ) + A 2 cos(ω 2 t + α

18 I ( ) (1) I-1,I-2,I-3 (2) (3) I-1 ( ) (100 ) θ ϕ θ ϕ m m l l θ ϕ θ ϕ 2 g (1) (2) 0 (3) θ ϕ (4) (3) θ(t) = A 1 cos(ω 1 t + α 1 ) + A 2 cos(ω 2 t + α 18 I ( ) (1) I-1,I-2,I-3 (2) (3) I-1 ( ) (100 ) θ ϕ θ ϕ m m l l θ ϕ θ ϕ 2 g (1) (2) 0 (3) θ ϕ (4) (3) θ(t) = A 1 cos(ω 1 t + α 1 ) + A 2 cos(ω 2 t + α 2 ), ϕ(t) = B 1 cos(ω 1 t + α 1 ) + B 2 cos(ω 2 t

More information

Untitled

Untitled II 14 14-7-8 8/4 II (http://www.damp.tottori-u.ac.jp/~ooshida/edu/fluid/) [ (3.4)] Navier Stokes [ 6/ ] Navier Stokes 3 [ ] Reynolds [ (4.6), (45.8)] [ p.186] Navier Stokes I 1 balance law t (ρv i )+ j

More information

Outline I. Introduction: II. Pr 2 Ir 2 O 7 Like-charge attraction III.

Outline I. Introduction: II. Pr 2 Ir 2 O 7 Like-charge attraction III. Masafumi Udagawa Dept. of Physics, Gakushuin University Mar. 8, 16 @ in Gakushuin University Reference M. U., L. D. C. Jaubert, C. Castelnovo and R. Moessner, arxiv:1603.02872 Outline I. Introduction:

More information

66 σ σ (8.1) σ = 0 0 σd = 0 (8.2) (8.2) (8.1) E ρ d = 0... d = 0 (8.3) d 1 NN K K 8.1 d σd σd M = σd = E 2 d (8.4) ρ 2 d = I M = EI ρ 1 ρ = M EI ρ EI

66 σ σ (8.1) σ = 0 0 σd = 0 (8.2) (8.2) (8.1) E ρ d = 0... d = 0 (8.3) d 1 NN K K 8.1 d σd σd M = σd = E 2 d (8.4) ρ 2 d = I M = EI ρ 1 ρ = M EI ρ EI 65 8. K 8 8 7 8 K 6 7 8 K 6 M Q σ (6.4) M O ρ dθ D N d N 1 P Q B C (1 + ε)d M N N h 2 h 1 ( ) B (+) M 8.1: σ = E ρ (E, 1/ρ ) (8.1) 66 σ σ (8.1) σ = 0 0 σd = 0 (8.2) (8.2) (8.1) E ρ d = 0... d = 0 (8.3)

More information

Donald Carl J. Choi, β ( )

Donald Carl J. Choi, β ( ) :: α β γ 200612296 20 10 17 1 3 2 α 3 2.1................................... 3 2.2................................... 4 2.3....................................... 6 2.4.......................................

More information

46 4 E E E E E 0 0 E E = E E E = ) E =0 2) φ = 3) ρ =0 1) 0 2) E φ E = grad φ E =0 P P φ = E ds 0

46 4 E E E E E 0 0 E E = E E E = ) E =0 2) φ = 3) ρ =0 1) 0 2) E φ E = grad φ E =0 P P φ = E ds 0 4 4.1 conductor E E E 4.1: 45 46 4 E E E E E 0 0 E E = E E E =0 4.1.1 1) E =0 2) φ = 3) ρ =0 1) 0 2) E φ E = grad φ E =0 P P φ = E ds 0 4.1 47 0 0 3) ε 0 div E = ρ E =0 ρ =0 0 0 a Q Q/4πa 2 ) r E r 0 Gauss

More information

IBIS Quality Framework IBIS モデル品質向上のための枠組み

IBIS Quality Framework IBIS モデル品質向上のための枠組み Quality Framework モデル品質向上のための枠組み EDA 標準 WG 1 目次 - 目次 - 1. 活動の背景 2. Quality Framework 3. ウェブサイトのご紹介 4. Frameworkの活用方法 2 目次 - 目次 - 1. 活動の背景 2. Quality Framework 3. ウェブサイトのご紹介 4. Frameworkの活用方法 3 1. 活動の背景

More information

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0 1 1 1.1 1.) T D = T = D = kn 1. 1.4) F W = F = W/ = kn/ = 15 kn 1. 1.9) R = W 1 + W = 6 + 5 = 11 N. 1.9) W b W 1 a = a = W /W 1 )b = 5/6) = 5 cm 1.4 AB AC P 1, P x, y x, y y x 1.4.) P sin 6 + P 1 sin 45

More information

= π2 6, ( ) = π 4, ( ). 1 ( ( 5) ) ( 9 1 ( ( ) ) (

= π2 6, ( ) = π 4, ( ). 1 ( ( 5) ) ( 9 1 ( ( ) ) ( + + 3 + 4 +... π 6, ( ) 3 + 5 7 +... π 4, ( ). ( 3 + ( 5) + 7 + ) ( 9 ( ( + 3) 5 + ) ( 7 + 9 + + 3 ) +... log( + ), ) +... π. ) ( 3 + 5 e x dx π.......................................................................

More information

ii 3.,. 4. F. (), ,,. 8.,. 1. (75%) (25%) =7 20, =7 21 (. ). 1.,, (). 3.,. 1. ().,.,.,.,.,. () (12 )., (), 0. 2., 1., 0,.

ii 3.,. 4. F. (), ,,. 8.,. 1. (75%) (25%) =7 20, =7 21 (. ). 1.,, (). 3.,. 1. ().,.,.,.,.,. () (12 )., (), 0. 2., 1., 0,. 24(2012) (1 C106) 4 11 (2 C206) 4 12 http://www.math.is.tohoku.ac.jp/~obata,.,,,.. 1. 2. 3. 4. 5. 6. 7.,,. 1., 2007 (). 2. P. G. Hoel, 1995. 3... 1... 2.,,. ii 3.,. 4. F. (),.. 5... 6.. 7.,,. 8.,. 1. (75%)

More information

untitled

untitled 1 17 () BAC9ABC6ACB3 1 tan 6 = 3, cos 6 = AB=1 BC=2, AC= 3 2 A BC D 2 BDBD=BA 1 2 ABD BADBDA ABC6 BAD = (18 6 ) / 2 = 6 θ = 18 BAD = 12 () AD AD=BADCAD9 ABD ACD A 1 1 1 1 dsinαsinα = d 3 sin β 3 sin β

More information

() n C + n C + n C + + n C n n (3) n C + n C + n C 4 + n C + n C 3 + n C 5 + (5) (6 ) n C + nc + 3 nc n nc n (7 ) n C + nc + 3 nc n nc n (

() n C + n C + n C + + n C n n (3) n C + n C + n C 4 + n C + n C 3 + n C 5 + (5) (6 ) n C + nc + 3 nc n nc n (7 ) n C + nc + 3 nc n nc n ( 3 n nc k+ k + 3 () n C r n C n r nc r C r + C r ( r n ) () n C + n C + n C + + n C n n (3) n C + n C + n C 4 + n C + n C 3 + n C 5 + (4) n C n n C + n C + n C + + n C n (5) k k n C k n C k (6) n C + nc

More information

スライド 1

スライド 1 情報デバイス特論演習設計ルール 実際に集積回路の設計を体験する 想定プロセス : μm CMOS 電源電圧 : 5V 本設計ルールは P. E. Allen and D. R. Holberg, CMOS Analog Circuit Design, Second Edition, 2002, Oxford University Press 及び VDEC( 東京大学大規模集積回路教育センタ ) を参考に教育用として作成したものであり

More information

I II

I II I II I I 8 I I 5 I 5 9 I 6 6 I 7 7 I 8 87 I 9 96 I 7 I 8 I 9 I 7 I 95 I 5 I 6 II 7 6 II 8 II 9 59 II 67 II 76 II II 9 II 8 II 5 8 II 6 58 II 7 6 II 8 8 I.., < b, b, c, k, m. k + m + c + c b + k + m log

More information

S I. dy fx x fx y fx + C 3 C dy fx 4 x, y dy v C xt y C v e kt k > xt yt gt [ v dt dt v e kt xt v e kt + C k x v + C C k xt v k 3 r r + dr e kt S dt d

S I. dy fx x fx y fx + C 3 C dy fx 4 x, y dy v C xt y C v e kt k > xt yt gt [ v dt dt v e kt xt v e kt + C k x v + C C k xt v k 3 r r + dr e kt S dt d S I.. http://ayapin.film.s.dendai.ac.jp/~matuda /TeX/lecture.html PDF PS.................................... 3.3.................... 9.4................5.............. 3 5. Laplace................. 5....

More information

.. ( )T p T = p p = T () T x T N P (X < x T ) N = ( T ) N (2) ) N ( P (X x T ) N = T (3) T N P T N P 0

.. ( )T p T = p p = T () T x T N P (X < x T ) N = ( T ) N (2) ) N ( P (X x T ) N = T (3) T N P T N P 0 20 5 8..................................................2.....................................3 L.....................................4................................. 2 2. 3 2. (N ).........................................

More information

( ) ,

( ) , II 2007 4 0. 0 1 0 2 ( ) 0 3 1 2 3 4, - 5 6 7 1 1 1 1 1) 2) 3) 4) ( ) () H 2.79 10 10 He 2.72 10 9 C 1.01 10 7 N 3.13 10 6 O 2.38 10 7 Ne 3.44 10 6 Mg 1.076 10 6 Si 1 10 6 S 5.15 10 5 Ar 1.01 10 5 Fe 9.00

More information

untitled

untitled 1 4 4 6 8 10 30 13 14 16 16 17 18 19 19 96 21 23 24 3 27 27 4 27 128 24 4 1 50 by ( 30 30 200 30 30 24 4 TOP 10 2012 8 22 3 1 7 1,000 100 30 26 3 140 21 60 98 88,000 96 3 5 29 300 21 21 11 21

More information

B 1 B.1.......................... 1 B.1.1................. 1 B.1.2................. 2 B.2........................... 5 B.2.1.......................... 5 B.2.2.................. 6 B.2.3..................

More information

25 7 18 1 1 1.1 v.s............................. 1 1.1.1.................................. 1 1.1.2................................. 1 1.1.3.................................. 3 1.2................... 3

More information

70 5. (isolated system) ( ) E N (closed system) N T (open system) (homogeneous) (heterogeneous) (phase) (phase boundary) (grain) (grain boundary) 5. 1

70 5. (isolated system) ( ) E N (closed system) N T (open system) (homogeneous) (heterogeneous) (phase) (phase boundary) (grain) (grain boundary) 5. 1 5 0 1 2 3 (Carnot) (Clausius) 2 5. 1 ( ) ( ) ( ) ( ) 5. 1. 1 (system) 1) 70 5. (isolated system) ( ) E N (closed system) N T (open system) (homogeneous) (heterogeneous) (phase) (phase boundary) (grain)

More information

P F ext 1: F ext P F ext (Count Rumford, ) H 2 O H 2 O 2 F ext F ext N 2 O 2 2

P F ext 1: F ext P F ext (Count Rumford, ) H 2 O H 2 O 2 F ext F ext N 2 O 2 2 1 1 2 2 2 1 1 P F ext 1: F ext P F ext (Count Rumford, 1753 1814) 0 100 H 2 O H 2 O 2 F ext F ext N 2 O 2 2 P F S F = P S (1) ( 1 ) F ext x W ext W ext = F ext x (2) F ext P S W ext = P S x (3) S x V V

More information

untitled

untitled 2 : n =1, 2,, 10000 0.5125 0.51 0.5075 0.505 0.5025 0.5 0.4975 0.495 0 2000 4000 6000 8000 10000 2 weak law of large numbers 1. X 1,X 2,,X n 2. µ = E(X i ),i=1, 2,,n 3. σi 2 = V (X i ) σ 2,i=1, 2,,n ɛ>0

More information

1 2 2 (Dielecrics) Maxwell ( ) D H

1 2 2 (Dielecrics) Maxwell ( ) D H 2003.02.13 1 2 2 (Dielecrics) 4 2.1... 4 2.2... 5 2.3... 6 2.4... 6 3 Maxwell ( ) 9 3.1... 9 3.2 D H... 11 3.3... 13 4 14 4.1... 14 4.2... 14 4.3... 17 4.4... 19 5 22 6 THz 24 6.1... 24 6.2... 25 7 26

More information

中央大学セミナー.ppt

中央大学セミナー.ppt String Gas Cosmology References Brandenberger & Vafa, Superstrings in the early universe, Nucl.Phys.B316(1988) 391. Tseytlin & Vafa, Elements of string cosmology, Nucl.Phys.B372 (1992) 443. Brandenberger,

More information