平成18年度弁理士試験本試験問題とその傾向

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1 CBA CBA CBA CBA CBA CBA Vol. No.

2 CBA CBA CBA CBA a b a bm m swkmsms kgm NmPa WWmK σ x σ y τ xy θ σ θ τ θ m b t p A-A' σ τ A-A' θ B-B' σ τ B-B' A-A' B-B' B-B' pσ σ B-B' pτ τ l x x I E Vol. No.

3 w x xl/ 3 pl 48EI t xy uv x y p ρ μ h u U y yh v xy p xy x u dp u y U dx μ h y dp U μ h dx m m p Pa ρ kg/m xy u duct [m/s] u out [m/s] p duct [Pa] p [Pa] u out [m/s] y ρ kg/m u ou t[m/s] y Y[N] L T L T H Q L Q H φl Q L φ φ QL QH φ T L T H T L T H TL φ = T H T L η c η c φ Vol. No.

4 φ ΔT L ΔT H T L ΔT L T L ' T H ' φ T L ' T H 'φ'φ φ 'T L T H ΔT L ΔT H T ΔT + T ΔT L H H L φ φ' = φφ ' φφ' p h p-h p-h ad Q T p V C V C P R dq TpVC V d X T T = d p p X κ ρ g hhdh dh hhdh p p pdpdp = ρ g dh = Y dh T R g M Y m/s J/mol/K m l θ θl & θ l & u u t) = f θ ( t) f & θ ( t) f l( t) f l& ( ) ( t 3 4 a x = θ,θ, l, l& b c f f f f ( ) T f a b u a x & = Ax + bu x & = ( A bf ) x f Abf d d t a d d Abf e f Vol. No.

= Y dh T R g M Y m/s J/mol/K m l θ θl & θ l & u u t) = f θ ( t) f & θ ( t) f l( t) f l& ( ) ( t 3 4 a x

5 a f u & θ u & θ b m m & l = mg sinθ A sinθ θ ii f g Gs Cs GsCs Gsab ab Gs a b Gs Cs K L M σ l xy L 3 L FΔt Δt T R α T RR αtt R Ω α Ω/Ω/ ImA δ mw G R V R W R R V R R R W R R R Vol. No.

6 R V R W R W m A B A B m A B C D C T V D T V mv V V A/D A/D V V / ( + δ ) + δ δ λ A C B C C AC BC AC BC AC a AB a << a C m m m m n a θ Vol. No.

7 bm wm tm pm P V P IA vm/s qcia I v EVm μm Vs vμe P RΩR μ v v sat v R v sat v z B x y z P N P a p n np p n n a V V V V a C F b Am tm εfm b X C b Y C X C Y X b Z C X C Z X Z X V b X Y Z a Vol. No.

8 b a b C V ε Q Q Q Q Q Q μ I II sinωt BB sinωt a V R R AB R L R L b V VR R R V R L P R L P c Vse jt I θ ω V s VRkLmHCμF a b c a I E IC I E I s expβv BE I C αi E β qktqkt I s α b R L V out V in Z Z cv out V in d V out V in V in αri s a b c d Vol. No.

9 CO EV R fhz T on T off T sw vv ia v V i leak A v Ei leak ER P max W T on T off f T SW T on T off BASETX FastEthenetIEEEu MAC MAC Mbps TCP IP TCP Mbps MIMOMultipleInputMultipleOutput WEPWiedEquivalentPivacy A e B B e A e A A A A A A A A A A A A A B A A A A B A B B B B B B B B B B B B A B B B B A B B a b A e B B e A C C e A A A A A A A A A A A A A B A A A A B A B B B B B B B B B B B B A B B B B A B B C C C C C C C C C C C C C C C C C C C C a b Vol. No.

e A A A A A A A A A A A A A B A A A A B A B B B B B B B B B B B B A B B B B A B B a b A e B B e A C C e A A A A A

10 A A i c c B A B C B A B VLIWVeyLongInstuctionWod MPIMessagePassingInteface DMADiectMemoyAccess u v uv n n n m Vol. No.

11 m n O A ABCDEFG A XML Wiki Ca Mg HCO Ca Mg moll ph moll e A A e B B AB T PAPB PAPB iiii i G A B A B ii C D D H iii E E RMulliken E F A F i G A B ii H D CH CH CH CH CH C FiedelCafts AC ae ab Vol. No.

12 cd esp IC AE ATP dimethylpopanol npentanol RCOSR'RCOOR' SO SO ppbv ph ph ph Vol. No.

13 A A B ELISA A A A ELISA A D A C IP C IP D D D mrna mrna N C Vol. No.

14 COPICOPII DNA DNA DNA DNA DNA RNA DNA DNA RNA DNA DNA DNA DNA DNA cdna C C A B C B C C Vol. No.

15 A A B A C C C A C C X Y Y X X X X X A Y A A X B X X Y A X X Y X X X Y A B A A A A A Vol. No.

16 A A A A a Vol. No.

17 b c a A A b A A A A A A c A A A d A Vol. No.

18 A A X A Y Y Y Y X A A B B B B a A a X A a B X A B A Vol. No.

19 A X A A A A A A B A B A A A A A A Vol. No.

20 A A A A H H H H H PCT HHH H H Vol. No.

21 A B B A B C A B C γ B γ α α β α β C Vol. No.

22 B A A A B B A B A A B C Vol. No.

23 A A A A B B A Vol. No.

24 B C C B C x x y B x y A A A A B B A B HHH H H Vol. No.

25 CBA CBA CBA CBA CBA CBA CBA CBA CBA CBA Vol. No.

26 CBA CBA CBA CBA CBA CBA CBA Vol. No.

27 a Baon Baona Baon Baon Baon Baon a a Baon Baon a Baon Baon Baon Baon Baon Baon Baon Baon Aa A aa Vol. No.

28 A OCEANS OCEANS OCEANS OCEANS OCEANS OCEANS OCEANS OCEANS OCEANS CBA CBA CBA CBA CBA CBA CBA CBA CBA Vol. No.

29 CBA HHHH H Vol. No.

30 Vol. No.

31 A A nm A BSA T B PTEN K A E BLAST N C GST MBP Vol. No.

32 abcd ef u θ & θ θ && θ & θ = + u l & l & l l& ( ) T b = θ m & l = mgθ & θ = & θ, l & = l & & θ θ && θ & θ = + l & l g u & l l& si s f g ( A bf ) 3 s + f 4 s + f s + f s = f s 3 f 4 = s + gf s 4 + gf 3 = ( s ( i) )( s ( + i) )( s ( 3 i) )( s ( 3 + i) ) 4 3 s + s + 39s + 7s + 5 = f ( f f f ) ( ) f = f = 3 4 = a ( s ( ± ) = b X = G( U CX ) X ( s) G( s) = = U ( s) + G( s) C( s) s + 4s + K a = 4 >, a = K > H = a = 4 > a H = = 4K > a K K l G L L Ml Ml = lσ ( l) dl = dl = ML G L 3 l G = L 3 dm I G I 3 8 (/ 3) L = dm = σ ( + L) d = ML G ( / 3) L Δt F e z 3 LFΔt FΔt = L L FΔt e = e z z 4 3 v v G F e y Mv Mv = Fdt = FΔt ( ) e G y v G FΔt = e y M F Δt Mv G = M ω ω G I ω I ω = ( F dt = FΔt G G G ) LFΔt ω = G ( ) ML 3FΔt e = e z z 8 ML 3F Δt Mω G = ML v FΔt 3FΔt v = v + ω = + G G M ML L = 3 Vol. No.

33 A B C C AC BC BCAC = a = + a = a a + a a a + a a AC k m = kλ a AC AC AC AC θ φ φ ψ θ ψ φ θ θ ψ θ ψ φ φ sinθ = nsinθ θ = θ + φ φ = φ θ = θ θ θ = nθ φ = φ = θ θ = n θ = n θ. 5 ( ) ( ) ( ) θ = FET wtv pq I = wtvqp VIR V be be b R = = = = I wtvqp wtqpμe wtqpμ V be R = = I wtv qp sat F = q( vi Bi ) = qvbi x z y Y Y Y E y Y F = q( E i vbi ) = y y y E = vb y V y I IB V = we = wvb = wb = y y wtqp tqp V y A C = ε t C Y C X C Y C X C Z C Vol. No.

34 X C z P N Y X P X S E ε E nds ρdv = s v E Q 4πε E = Q ( < ) E = Q ( > ) E = 4πε V Q V = E d = 4πε Q d = 4πε Q Q ( < ) E = Q ( < < ) E = 4πε Q + Q ( > ) E = 4πε V Q + Q V = E d = 4πε Q + Q d = 4πε V = Q + Q = Q V E d d d 4πε 4πε Q + Q Q Q = + 4 πε 4πε 4πε Q Q = 4πε V V = 4 = πε Q = Q Q Q dl i l i i z I dh dh I i i Idl l = dl = i z 4π 4π H I I H = dh = π i = i z z c 4π B Iμ B = μ H = i z e d e = B i ds dt z S d = ( π B sinωt) dt = π ωb cosωt Mbitss μs bitsμsbitμs bitsμsbitμs bitsμsbitμs μsμs μsμs μs bitsμsmbitss TCP IP TCP TCP bitsμsmbps Vol. No.

24.15章.微分方程式

24.15章.微分方程式 m d y dt = F m d y = mg dt V y = dy dt d y dt = d dy dt dt = dv y dt dv y dt = g dv y dt = g dt dt dv y = g dt V y ( t) = gt + C V y ( ) = V y ( ) = C = V y t ( ) = gt V y ( t) = dy dt = gt dy = g t dt