A

Similar documents
1 8, : 8.1 1, 2 z = ax + by + c ax by + z c = a b +1 x y z c = 0, (0, 0, c), n = ( a, b, 1). f = n i=1 a ii x 2 i + i<j 2a ij x i x j = ( x, A x), f =

x () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x

,. Black-Scholes u t t, x c u 0 t, x x u t t, x c u t, x x u t t, x + σ x u t, x + rx ut, x rux, t 0 x x,,.,. Step 3, 7,,, Step 6., Step 4,. Step 5,,.

(3) (2),,. ( 20) ( s200103) 0.7 x C,, x 2 + y 2 + ax = 0 a.. D,. D, y C, C (x, y) (y 0) C m. (2) D y = y(x) (x ± y 0), (x, y) D, m, m = 1., D. (x 2 y

II A A441 : October 02, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka )

y π π O π x 9 s94.5 y dy dx. y = x + 3 y = x logx + 9 s9.6 z z x, z y. z = xy + y 3 z = sinx y 9 s x dx π x cos xdx 9 s93.8 a, fx = e x ax,. a =



1. (8) (1) (x + y) + (x + y) = 0 () (x + y ) 5xy = 0 (3) (x y + 3y 3 ) (x 3 + xy ) = 0 (4) x tan y x y + x = 0 (5) x = y + x + y (6) = x + y 1 x y 3 (

変 位 変位とは 物体中のある点が変形後に 別の点に異動したときの位置の変化で あり ベクトル量である 変位には 物体の変形の他に剛体運動 剛体変位 が含まれている 剛体変位 P(x, y, z) 平行移動と回転 P! (x + u, y + v, z + w) Q(x + d x, y + dy,

() x + y + y + x dy dx = 0 () dy + xy = x dx y + x y ( 5) ( s55906) 0.7. (). 5 (). ( 6) ( s6590) 0.8 m n. 0.9 n n A. ( 6) ( s6590) f A (λ) = det(a λi)

.1 z = e x +xy y z y 1 1 x 0 1 z x y α β γ z = αx + βy + γ (.1) ax + by + cz = d (.1') a, b, c, d x-y-z (a, b, c). x-y-z 3 (0,

Part () () Γ Part ,

18 ( ) I II III A B C(100 ) 1, 2, 3, 5 I II A B (100 ) 1, 2, 3 I II A B (80 ) 6 8 I II III A B C(80 ) 1 n (1 + x) n (1) n C 1 + n C


W u = u(x, t) u tt = a 2 u xx, a > 0 (1) D := {(x, t) : 0 x l, t 0} u (0, t) = 0, u (l, t) = 0, t 0 (2)



II (10 4 ) 1. p (x, y) (a, b) ε(x, y; a, b) 0 f (x, y) f (a, b) A, B (6.5) y = b f (x, b) f (a, b) x a = A + ε(x, b; a, b) x a 2 x a 0 A = f x (

I, II 1, A = A 4 : 6 = max{ A, } A A 10 10%

1/1 lim f(x, y) (x,y) (a,b) ( ) ( ) lim limf(x, y) lim lim f(x, y) x a y b y b x a ( ) ( ) xy x lim lim lim lim x y x y x + y y x x + y x x lim x x 1


DVIOUT

ax 2 + bx + c = n 8 (n ) a n x n + a n 1 x n a 1 x + a 0 = 0 ( a n, a n 1,, a 1, a 0 a n 0) n n ( ) ( ) ax 3 + bx 2 + cx + d = 0 4

i

simx simxdx, cosxdx, sixdx 6.3 px m m + pxfxdx = pxf x p xf xdx = pxf x p xf x + p xf xdx 7.4 a m.5 fx simxdx 8 fx fx simxdx = πb m 9 a fxdx = πa a =

f(x,y) (x,y) x (x,y), y (x,y) f(x,y) x y f x (x,y),f y (x,y) B p.1/14

v er.1/ c /(21)

x = a 1 f (a r, a + r) f(a) r a f f(a) 2 2. (a, b) 2 f (a, b) r f(a, b) r (a, b) f f(a, b)

i

1 1.1 ( ). z = a + bi, a, b R 0 a, b 0 a 2 + b 2 0 z = a + bi = ( ) a 2 + b 2 a a 2 + b + b 2 a 2 + b i 2 r = a 2 + b 2 θ cos θ = a a 2 + b 2, sin θ =

No δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i x j δx j (5) δs 2

さくらの個別指導 ( さくら教育研究所 ) 1 φ = φ 1 : φ [ ] a [ ] 1 a : b a b b(a + b) b a 2 a 2 = b(a + b). b 2 ( a b ) 2 = a b a/b X 2 X 1 = 0 a/b > 0 2 a

) ] [ h m x + y + + V x) φ = Eφ 1) z E = i h t 13) x << 1) N n n= = N N + 1) 14) N n n= = N N + 1)N + 1) 6 15) N n 3 n= = 1 4 N N + 1) 16) N n 4

i 18 2H 2 + O 2 2H 2 + ( ) 3K

.3. (x, x = (, u = = 4 (, x x = 4 x, x 0 x = 0 x = 4 x.4. ( z + z = 8 z, z 0 (z, z = (0, 8, (,, (8, 0 3 (0, 8, (,, (8, 0 z = z 4 z (g f(x = g(


40 6 y mx x, y 0, 0 x 0. x,y 0,0 y x + y x 0 mx x + mx m + m m 7 sin y x, x x sin y x x. x sin y x,y 0,0 x 0. 8 x r cos θ y r sin θ x, y 0, 0, r 0. x,

, x R, f (x),, df dx : R R,, f : R R, f(x) ( ).,, f (a) d f dx (a), f (a) d3 f dx 3 (a),, f (n) (a) dn f dx n (a), f d f dx, f d3 f dx 3,, f (n) dn f


(iii) 0 V, x V, x + 0 = x. 0. (iv) x V, y V, x + y = 0., y x, y = x. (v) 1x = x. (vii) (α + β)x = αx + βx. (viii) (αβ)x = α(βx)., V, C.,,., (1)


°ÌÁê¿ô³ØII

Untitled

2009 IA 5 I 22, 23, 24, 25, 26, (1) Arcsin 1 ( 2 (4) Arccos 1 ) 2 3 (2) Arcsin( 1) (3) Arccos 2 (5) Arctan 1 (6) Arctan ( 3 ) 3 2. n (1) ta

5.. z = f(x, y) y y = b f x x g(x) f(x, b) g x ( ) A = lim h 0 g(a + h) g(a) h g(x) a A = g (a) = f x (a, b)

x (x, ) x y (, y) iy x y z = x + iy (x, y) (r, θ) r = x + y, θ = tan ( y ), π < θ π x r = z, θ = arg z z = x + iy = r cos θ + ir sin θ = r(cos θ + i s

(1) (2) (3) (4) HB B ( ) (5) (6) (7) 40 (8) (9) (10)

D xy D (x, y) z = f(x, y) f D (2 ) (x, y, z) f R z = 1 x 2 y 2 {(x, y); x 2 +y 2 1} x 2 +y 2 +z 2 = 1 1 z (x, y) R 2 z = x 2 y

II 2 II

No2 4 y =sinx (5) y = p sin(2x +3) (6) y = 1 tan(3x 2) (7) y =cos 2 (4x +5) (8) y = cos x 1+sinx 5 (1) y =sinx cos x 6 f(x) = sin(sin x) f 0 (π) (2) y

応力とひずみ.ppt

7. y fx, z gy z gfx dz dx dz dy dy dx. g f a g bf a b fa 7., chain ule Ω, D R n, R m a Ω, f : Ω R m, g : D R l, fω D, b fa, f a g b g f a g f a g bf a

( )/2 hara/lectures/lectures-j.html 2, {H} {T } S = {H, T } {(H, H), (H, T )} {(H, T ), (T, T )} {(H, H), (T, T )} {1

2

pdf

ii 3.,. 4. F. (), ,,. 8.,. 1. (75%) (25%) =7 20, =7 21 (. ). 1.,, (). 3.,. 1. ().,.,.,.,.,. () (12 )., (), 0. 2., 1., 0,.

() Remrk I = [0, ] [x i, x i ]. (x : ) f(x) = 0 (x : ) ξ i, (f) = f(ξ i )(x i x i ) = (x i x i ) = ξ i, (f) = f(ξ i )(x i x i ) = 0 (f) 0.

73

1990 IMO 1990/1/15 1:00-4:00 1 N N N 1, N 1 N 2, N 2 N 3 N 3 2 x x + 52 = 3 x x , A, B, C 3,, A B, C 2,,,, 7, A, B, C

II No.01 [n/2] [1]H n (x) H n (x) = ( 1) r n! r!(n 2r)! (2x)n 2r. r=0 [2]H n (x) n,, H n ( x) = ( 1) n H n (x). [3] H n (x) = ( 1) n dn x2 e dx n e x2

1.2 y + P (x)y + Q(x)y = 0 (1) y 1 (x), y 2 (x) y 1 (x), y 2 (x) (1) y(x) c 1, c 2 y(x) = c 1 y 1 (x) + c 2 y 2 (x) 3 y 1 (x) y 1 (x) e R P (x)dx y 2


CALCULUS II (Hiroshi SUZUKI ) f(x, y) A(a, b) 1. P (x, y) A(a, b) A(a, b) f(x, y) c f(x, y) A(a, b) c f(x, y) c f(x, y) c (x a, y b)



Gmech08.dvi

微分積分 サンプルページ この本の定価 判型などは, 以下の URL からご覧いただけます. このサンプルページの内容は, 初版 1 刷発行時のものです.

2S III IV K A4 12:00-13:30 Cafe David 1 2 TA 1 appointment Cafe David K2-2S04-00 : C

I A A441 : April 15, 2013 Version : 1.1 I Kawahira, Tomoki TA (Shigehiro, Yoshida )

2.2 ( y = y(x ( (x 0, y 0 y (x 0 (y 0 = y(x 0 y = y(x ( y (x 0 = F (x 0, y(x 0 = F (x 0, y 0 (x 0, y 0 ( (x 0, y 0 F (x 0, y 0 xy (x, y (, F (x, y ( (

III 1 (X, d) d U d X (X, d). 1. (X, d).. (i) d(x, y) d(z, y) d(x, z) (ii) d(x, y) d(z, w) d(x, z) + d(y, w) 2. (X, d). F X.. (1), X F, (2) F 1, F 2 F

(4) P θ P 3 P O O = θ OP = a n P n OP n = a n {a n } a = θ, a n = a n (n ) {a n } θ a n = ( ) n θ P n O = a a + a 3 + ( ) n a n a a + a 3 + ( ) n a n

I, II 1, 2 ɛ-δ 100 A = A 4 : 6 = max{ A, } A A 10

9. 05 L x P(x) P(0) P(x) u(x) u(x) (0 < = x < = L) P(x) E(x) A(x) P(L) f ( d EA du ) = 0 (9.) dx dx u(0) = 0 (9.2) E(L)A(L) du (L) = f (9.3) dx (9.) P

Chap11.dvi

(2 X Poisso P (λ ϕ X (t = E[e itx ] = k= itk λk e k! e λ = (e it λ k e λ = e eitλ e λ = e λ(eit 1. k! k= 6.7 X N(, 1 ϕ X (t = e 1 2 t2 : Cauchy ϕ X (t

II 2 3.,, A(B + C) = AB + AC, (A + B)C = AC + BC. 4. m m A, m m B,, m m B, AB = BA, A,, I. 5. m m A, m n B, AB = B, A I E, 4 4 I, J, K

, 1 ( f n (x))dx d dx ( f n (x)) 1 f n (x)dx d dx f n(x) lim f n (x) = [, 1] x f n (x) = n x x 1 f n (x) = x f n (x) = x 1 x n n f n(x) = [, 1] f n (x

newmain.dvi

2011de.dvi

ma22-9 u ( v w) = u v w sin θê = v w sin θ u cos φ = = 2.3 ( a b) ( c d) = ( a c)( b d) ( a d)( b c) ( a b) ( c d) = (a 2 b 3 a 3 b 2 )(c 2 d 3 c 3 d

B ver B

Gmech08.dvi

³ÎΨÏÀ

I A A441 : April 21, 2014 Version : Kawahira, Tomoki TA (Kondo, Hirotaka ) Google

S I. dy fx x fx y fx + C 3 C vt dy fx 4 x, y dy yt gt + Ct + C dt v e kt xt v e kt + C k x v k + C C xt v k 3 r r + dr e kt S Sr πr dt d v } dt k e kt


S I. dy fx x fx y fx + C 3 C dy fx 4 x, y dy v C xt y C v e kt k > xt yt gt [ v dt dt v e kt xt v e kt + C k x v + C C k xt v k 3 r r + dr e kt S dt d

III No (i) (ii) (iii) (iv) (v) (vi) x 2 3xy + 2 lim. (x,y) (1,0) x 2 + y 2 lim (x,y) (0,0) lim (x,y) (0,0) lim (x,y) (0,0) 5x 2 y x 2 + y 2. xy x2 + y

1. 1 BASIC PC BASIC BASIC BASIC Fortran WS PC (1.3) 1 + x 1 x = x = (1.1) 1 + x = (1.2) 1 + x 1 = (1.

6.1 (P (P (P (P (P (P (, P (, P.

[ ] 0.1 lim x 0 e 3x 1 x IC ( 11) ( s114901) 0.2 (1) y = e 2x (x 2 + 1) (2) y = x/(x 2 + 1) 0.3 dx (1) 1 4x 2 (2) e x sin 2xdx (3) sin 2 xdx ( 11) ( s

n Y 1 (x),..., Y n (x) 1 W (Y 1 (x),..., Y n (x)) 0 W (Y 1 (x),..., Y n (x)) = Y 1 (x)... Y n (x) Y 1(x)... Y n(x) (x)... Y n (n 1) (x) Y (n 1)

r 1 m A r/m i) t ii) m i) t B(t; m) ( B(t; m) = A 1 + r ) mt m ii) B(t; m) ( B(t; m) = A 1 + r ) mt m { ( = A 1 + r ) m } rt r m n = m r m n B

2000年度『数学展望 I』講義録

all.dvi

Z: Q: R: C:

6kg 1.1m 1.m.1m.1 l λ ϵ λ l + λ l l l dl dl + dλ ϵ dλ dl dl + dλ dl dl 3 1. JIS 1 6kg 1% 66kg 1 13 σ a1 σ m σ a1 σ m σ m σ a1 f f σ a1 σ a1 σ m f 4

mugensho.dvi

Transcription:

A 2563 15 4 21

1 3 1.1................................................ 3 1.2............................................. 3 2 3 2.1......................................... 3 2.2............................................ 4 2.3........................................... 4 3 4 3.1.................................................. 4 3.2....................................... 5 3.3............................................. 5 3.4.............................................. 6 3.5................................................ 7 3.6............................................ 9 3.7...................................... 15 4 16 4.1......................................... 16 4.2................................................. 16 4.3........................................ 19 4.4........................................ 21 5 23 6 23 7 25 2

1 1.1 1 1.2 1 2 3 4 2 2.1 x a c = a x a 2 1 c = a x 2 c R = e x = a x x c R f(x) =e x f n (x) c(x) f(x) =1+ x 1! + x2 2! + x3 +, <x< 3! f n (x) =1+ x 1! + x2 2! + x3 xn + + 3! n! c(x) f n (x) f(x) = xn+1 (n +1)! xn+2 (n +2)! f(x) x a f(x) f(a) 3

2.2 a =1.23456,b =1.23421 x, y a b =.35 =.35 1 3 6 2 a, b.5 1 5 /1.234 <.41 1 5 a b e R e R = (x y) (a b) a b (x a) (y b) a b 1 5 =.29 1 1.35 1 3 a,b 2.3 2 a = 123456.78,b =.12345678,c =.12345678 8 a + b = 123456.79 a + c = 123456.78 = a a b c 3 3.1 n +1 x,x 1,,x n f(x) f(x ),f(x 1 ),,f(x n ) n g(x) g(x j )=f j = f(x j ) (j =, 1,,n) (3.1) g(x) f(x) g(x) g(x i )=c + c 1 x i + c 2 x i + + c n x n i = f(x i ), g(x i ) x j (j =, 1,,n) x f(x) g(x) f(x) g(x) 4

1 n L n,k (x),k =, 1,,n g(x) L n,k (x) L n,k (x) = g(x) = n c k L n,k (x) (3.2) k= {, x = xj,j k 1, x = x k (3.3) g(x i )=c i i =, 1,,n c i = f(x i ),i=, 1,,n g(x) L i,k (x) = n i=,i k x x i x k k i (3.4) (3.3) (3.2) 1 3.2 x = x k 1 d y f(x k 1 ) x k 1 h x k, (h = x k x k 1 ) f(x k )=f(x k 1 )+(x k x k 1 )f (x k 1 )+ (x k x k 1 ) 2 f (x k x k 1 )+ (3.5) 2 (3.5) 3 f(x k )=f(x k 1 )+(x k x k 1 )f (x k 1 ) (3.6) f(x) = x 3.6 x k (3.6) f(x k )= x k = x k 1 f(x k 1) f (x k 1 ) (3.7) x k x k 1 x - 2 3.3 f(x) [a, b] b a f(x)dx (3.8) 5

[a, b] f(x) a b n x i (i =, 1, 2,,n) f(x i ) h (3.9) b a f(x)dx h(f(x 1 )+f(x 2 )+ + f(x n )), h(f(x )+f(x 1 )+ + f(x n 1 )), (h =(b a)/n) (3.9) [a, b] m x j [x j 1,x j ] (3.1) (3.1) b a b a f(x)dx = m j=1 xj x j 1 f(x)dx m j=1 h 2 (f j 1 + f j ) (3.1) f(x)dx h 2 (f + f m )+h(f 1 + f 2 +...+ f m 1 ), (h =(b a)/m) (3.11) 3 3.4 1 1 (3.12) dy dx = f(x, y), y(x )=y (3.12) y(x) =y y(x) Y j y(x) y(x j )=y(x j 1 )+hφ(x j 1,y(x j 1 ); h) (3.13) φ F (3.13) Y j = Y j 1 + hf (x j 1,Y j 1 ; h) (3.14) Y j (3.14) Y j F (x, y(x); h) f(x, y) φ y = f(x, y) y(x) h y(x + h) = y(x)+hy (x)+ h2 2! y (x)+ + hp p! y(p) (x)+ hp+1 (p +1)! y(p+1) (x + θh) = y(x)+hf(x, y(x)) + h2 d hp d p 1 f(x, y(x)) + + f(x, y(x)) 2! dx (p)! dxp 1 + hp+1 d p f(x + θh, y(x + θh)), <θ<1 (3.15) (p +1)! dxp 6

(3.15) φ(x, y(x); h) = f(x, y(x)) + h d 2! dx F + hp d p F (x, y(x); h) = f(x, y(x)) + h d 2! dx (3.16) (3.17) f(x, y(x)) + + hp 1 p! d p 1 f(x, y(x)) dxp 1 f(x + θh, y(x + θh)) (3.16) (p +1)! dxp f(x, y(x)) + + hp 1 p! d p 1 f(x, y(x)) (3.17) dxp 1 F (x, y(x); h) φ(x, y(x); h) = O(h p ) (3.18) (3.18) (3.14) p p =1 (3.14) p =1 (3.17) F (x, y(x); h) =f(x, y(x)) (3.19) (3.14) (3.19) Y = y Y j = Y j 1 + hf(x j 1,Y j 1 ) x j = x j 1 + h (j =1, 2,,n) 3.5 p (3.14) p =2 p =2 (3.19) F (x, y(x); h) =f(x, y(x)) + h d f(x, y(x)) (3.2) 2! dx y(x) (3.12) f(x, y(x)) x = f x (x, y(x)) + f y (x, y(x))y (x) = f x (x, y(x)) + f(x, y(x))f y (x, y(x)) (3.21) f x (x, y(x)) = f x f y (x, y(x)) = f 7

(3.2) (3.21) F (x, y(x); h) =f(x, y(x)) + h(f x(x, y(x)) + f(x, y(x))f y (x, y(x))) 2 (3.23) (3.22) F (x, y(x); h) =αf(x, y(x)) + βf(x + γh,y + γhf(x, y(x))) (3.23) (3.22) 2 (3.24) f(x + γh,y + γhf(x, y(x))) = f(x, y(x)) + γhf x (x, y(x)) + γhf(x, y(x))f y (x, y(x)) + O(h 2 ) (3.24) (3.23) F (x, y(x); h) = αf(x, y(x)) + β{f(x, y(x)) + γhf x (x, y(x)) + γhf(x, y(x))f y (x, y(x)) + O(h 2 )} = (α + β)f(x, y(x)) + βγh{f x (x, y(x)) + f(x, y(x))f y (x, y(x))} + O(h 2 ) (3.25) F = F (x, y(x); h), f = f(x, y(x)), f x = f x (x, y(x)), f y = f y (x, y(x)) (3.22) (3.25) F = f + h(f x + ff y )/2 (3.26) F = (α + β)f + βγh(f x + ff y )+O(h 2 ) (3.27) α + β =1,βγ =1/2 β λ (3.23) F (x, y(x); h) =(1 λ)f(x, y(x)) + λf(x + h 2λ,y+ h f(x, y(x))) (3.28) 2λ (3.17) (3.18) (3.19) (3.27) (3.28) F (x, y(x); h) φ(x, y(x); h) = O(h 2 ) (3.28) F (3.14) Y j = Y j 1 + hf (x j 1,Y j 1 ; h) 2 λ =1/2 (3.29) F (x, y(x); h) = 1 (f(x, y(x)) + f(x + h, y + hf(x, y(x))) (3.29) 2 Y j = y(x j ) (3.14) (3.25) Y j = Y j 1 + h(f(x j 1,Y j 1 )+f(x j 1 + h, Y j 1 + hf(x j 1,Y j 1 ))/2 (3.3) y j (j =1, 2,,n) Y = y k 1 = hf(x j 1,Y j 1 ) k 2 = hf(x j 1 + h, Y j 1 + k 1 ) Y j = Y j 1 + 1 2 (k 1 + k 2 ) x j = x j 1 + h 8

3.6 p p =4 k 1 = f(x, Y ) (3.31) k 2 = f(x + αh, Y + βk 1 ) (3.32) k 3 = f(x + α 1 h, Y +(β 1 k 1 + γ 1 k 2 )h) (3.33) k 4 = f(x + α 2 h, Y +(β 2 k 1 + γ 2 k 2 + δ 2 k 3 )h) (3.34) (3.35) (3.15) y = f(x, y(x)) y,y y = df dx = ( y = d2 f dx 2 = x + f ( x + f ) f = f x + ff y (3.36) ) (f x + ff y )=f xx + f x f y + ff xy + ff yx + ff 2 y + f 2 f yy (3.37) D = x + f f = f(x,y ) [ ] x = x,y = y y,y,y y = f y = [f x + ff y ] =[Df] y = [f xx +2ff xy + f 2 f yy + f y (f x + ff y )] =[D 2 f + f y Df] (3.16) x = x φ(x,y(x ); h) = [f + h h2 Df + 2! 3! (D2 + f y D)f ] + h3 4! (D3 + f y D 2 + fy 2 D +3D2 f y )f +O(h 5 ) (3.38) D l = l k= ( ) l k f l k l x k l k (3.16) p =4 f(x + u, y + v) = l= ( 1 u l! x + v ) l f(x, y) D l 1 = ( ) l l α k (βf ) l k l k x k l k k= 9

D 1 = α x + βf hd 1 = αh x + βhf D 11 k 1 = f(x,y )=f (3.39) k 2 = f(x + αh, y + βf h) [ = f + D 11 f + D2 11 f + D3 11 f + D4 11 f ] + 2! 3! 4! [ ] = f + hd 1 f + h2 2! D2 1 f + h3 3! D3 1 f + h4 4! D4 1 f + (3.4) D l 2 = ( ) l l α k k 1{(β 1 + γ 1 )f } l k l x k l k k= D 2 = α 1 x +(β 1 + γ 1 )f hd 2 = α 1 h x +(β 1 + γ 1 )hf α 1 h x +(β 1k 1 + γ 1 k 2 )h = hd 2 +(β 1 k 1 + γ 1 k 2 β 1 k 1 γ 1 k 1 )h = hd 2 +(k 2 f )γ 1 h [ = hd 2 + γ 1 h 2 D 1 f + h ] 2! D2 1 f + h2 3! D3 1 f + D 21 k 3 = = = f[x + α 1 h, y +(β 1 k 1 + γ 1 k 2 )h] [ f + D 21 f + D2 21 f + D3 21 f + D4 21 f ] + 2! 3! 4! [ [ ] f + {hd 2 + γ 1 h 2 D 1 f + h2 2! D2 1f + h2 3! D3 1f + + 1 [ {h 2 D 22 +2hD 2 γ 1 h 2 D 1 f + h ] 2! 2! D2 1f + } f 1

= + γ1h [D 2 4 1 f + h ] 2 2 } 2! D2 1f + 2 + 1 {h 3 D 32 3! +3h2 D 22 γ 1h [D 2 1 f + h2 ] 2! D2 1 f + [f + hd 2 f + h2 2! D2 2f + h3 3! D3 2f + + γ 1 h 2 + { f y D 1 f + h 2! f yd1f 2 + hd 1 fd 2 f y + h2 3! f yd1 3 f + h2 2! D2 1 fd 2f y + h2 2! γ 1f yy (D 1 f) 2 }] + h2 2! D 1fD2 2 f y + } ] f + (3.41) D l 3 = ( ) l l α k k 2{(β 2 + γ 2 + δ 2 )f } l k l x k l k k= D 3 = α 2 x +(β 2 + γ 2 + δ 2 )f hd 3 = α 2 h x +(β 2 + γ 2 + δ 2 )hf α 2 h x +(β 2k 1 + γ 2 k 2 + δ 2 k 3 )h = hd 3 +(β 2 k 1 + γ 2 k 2 + δ 2 k 3 β 2 f γ 2 f δ 2 f )h = hd 3 +[γ 2 (k 2 f )+δ 2 (k 3 f )]h [ { = hd 3 + h 2 γ 2 D 1 f + h } 2! D2 1f + h2 3! D3 1f + +2δ 2 γ 1 hf y D 1 f)+ h2 3! D3 1 f + h2 2! γ 1f y D 2 1 f + h2 γ 1 D 1 fd 2 f y + }] D 31 k 4 = = [ f + D 31 f + D2 31 f + D3 31 f + D4 31 f ] + 2! 3! 4! [f + hd 3 f + h 2 f y {γ 2 (D 1 f + h ) 2 D21f + h2 3! D3 1f + ( + δ 2 D 2 f + hγ 1 f y D 1 f + h 2 D2 2 f + h2 )} 3! D3 2 ff y + 2 γ 1f y D1 2 f + h2 γ 1 D1 2 fd 2f y + h2 + 1 ) {h 2 D 23 2! f h2 +2h3 h2 D 3 f y (γ 2 (D 1 f + D21 f + 3! D3 2 f + ( + δ 2 D 2 f + hγ 1 f y D 1 f + h 2 D2 2 f + ))+h 4 f yy (γ2 2 (D 1f) 2 +2γ 2 δ 2 D 1 fd 2 f 11

= } + δ2(d 2 2 f) 2 + ) + 1 3! {h3 D3f 3 +3h 4 D3f 2 y (γ 2 D 1 f + δ 2 D 2 f + )+ } + 1 4! {h4 D3 4 f + }+ ] [f + hd 3 f + h2 2! D2 3f + h3 3! D3 3f + + h 2 (γ 2 D 2 f)f y + h 3 (γ 2 D 1 f + δ 2 D 2 f y )D 3 f y + h3 2 (γ 2D 2 1 f + δ 2D 2 2 f +2γ 1δ 2 f y D 1 f)f y ] (3.42) (3.14) 1 Y j = Y j 1 + hf (x j 1,Y j 1 ; h) = Y j 1 + h(c 1 k 1 + c 2 k 2 + c 3 k 3 + c 4 k 4 ) (3.43) (3.39) (3.4) (3.41) (3.42) (3.38) hf : c 1 + c 2 + c 3 + c 4 =1 h 2 Df : c 2 D 1 f + C 3 D 2 f + c 4 D 3 f = Df 2! h 3 D 2 f : c 2 D1 2 f + c 3D2 2 f + c 4D3 2 f = 2! 3! D2 f h 3 f y Df : c 3 γ 1 D 1 f + c 4 (γ 2 D 1 f + δ 2 D 2 f)= 1 3! Df h 4 D 3 f : (3.44) c 2 D1 3 f + c 3D2 3 f + c 4D3 3 f = 3! 4! D3 f h 4 f y D 2 f : c 3 γ 1 D1 2 f + c 4(γ 2 D1 2 f + δ 2D2 2 f)= 2 4! D2 f h 4 DfDf y : c 3 γ 1 D 1 fd 2 f y + c 4 (γ 2 D 1 f + δ 2 D 2 f)d 3 f y = 3 4! DfDf y h 4 fy 2 Df : c 4 γ 1 δ 2 D 1 f = 1 4! Df D, D s (s =1, 2, 3) f D s/d l l f(s, l =1, 2, 3) D 1 f = α f f +β x D 1f = f x +f f D 2 f Df D 3 f Df α = β (3.45) { α1 = β 1 + γ 1 α 2 = β 2 + γ 2 + δ 2 (3.46) 12

D 1 f = αdf D 2 f = α 1 Df D 3 f = α 2 Df (3.47) (3.47) (3.44) 1 8 c 1 + c 2 + c 3 + c 4 = 1 (a) c 2 α + c 3 α 1 + c 4 α 2 = 1/2 (b) c 2 α 2 + c 3 α 2 1 + c 4 α 2 2 = 1/3 (c) c 2 α 3 + c 3 α 3 1 + c 4 α 3 2 = 1/4 (d) c 3 αγ 1 + c 4 (αγ 2 +(α 1 δ 2 ) = 1/6 (e) c 3 α 2 γ 1 + c 4 (α 2 γ 2 +(α 2 1 δ 2) = 1/12 (f) c 3 αα 1 γ 1 + c 4 (αγ 2 +(α 1 δ 2 )α 2 = 1/8 (g) c 4 αγ 1 δ 2 = 1/24 (h) (e) (f) c 3 (h) c 4 C 4 (α 1 α)α 1 δ 2 = 1 12 α 6 (α 1 α)α 1 δ 2 224αγ 1 δ 2 = 1 12 α 6 2αγ 1(2α 1) = α 1 (α α 1 ) (i) (3.48) (e) (f) c 4 (i) γ c 3 αγ 1 (α 2 α 1 )= α 2 6 1 8 c 3 (α 2 α 1 ) α 1(α α 1 ) 2(α 1) = α 2 6 1 8 ( α2 c 3 α 1 (α 2 α 1 )(α α 1 )=(2α 1) 3 1 ) 4 (b) αα 2 (α + α 1 ) (c)+(d) c 3 α 1 (α 2 α 1 )(α α 1 )= 1 2 αα 2 1 3 (α + α 2)+ 1 4 (j) (k) (j) (k) (h) α ( α2 (2α 1) 3 1 ) = 1 4 2 αα 2 1 3 (α + α 2)+ 1 4 α(α 2 1) =, α 2 = 13

(a) (b) (c) c 1,c 2,c 3,c 4 c 1 = 6αα 1 2(α + α 1 )+1 12αα 2α 1 1 c 2 = 12α(α 1 α)(1 α) 1 2α c 3 = 12α 1 (α 1 α)(1 α 1 ) c 4 = 6αα 1 4(α + α 1 )+3 12(1 α)(1 α 1 ) (a) (b) (c) (d) γ 1 γ 2 δ 1 α, α 1 (3.45) (3.46) β = α, β 1 = α 1 γ 1 (α, α 1 )β 2 = α 2 γ 2 (α, α 1 ) δ 2 (α, α 1 ) α = α 1 = 1 (a) (b) (c) 2 (d) 1 1 1 1 1 1/2 1/2 1 1/2 1/4 1/4 1 1/3 1/8 1/8 1 1/4 c 1,c 2,c 4 c 3 1 1/6 1 1 2/3 1 1/6 C 1 = 1 6 C 2 = 2 3 C 3 C 3 = 1 6 (3.49) (3.45) (3.46) (3.49) (e) (f) (g) γ 1 = 1 6c 3 γ 2 =1 3c 3 δ 2 =3c 3 β = α = 1 2 β 1 = α 1 γ 1 = 1 2 1 6c 3 β 2 = α 2 γ 2 γ 2 = (3.5) c 3 =1/3 c 1 =1/6,c 2 =1/3,c 3 =1/3,c 4 =1/6,γ 1 =1/2,γ 2 =,δ 2 =1,β 1 =,β 2 = Y = y j (j =1, 2,,n) k 1 = hf(x j 1,Y j 1 ) k 2 = hf(x j 1 + h/2,y j 1 + k 1 /2) 14

k 3 = hf(x j 1 + h/2,y j 1 + k 2 /2) k 4 = hf(x j 1 + h, Y j 1 + k 3 ) Y j = Y j 1 + 1 6 (k 1 +2k 2 +2k 3 + k 4 ) x j = x j 1 + h 4 3.7 m y 1 (x),...,y m (x) y = dy j dx = f j(x, y 1,...,y m ), y j (x )=y j, (j =1, 2,,m) y 1. y m, y = y 1. y m f 1 (x, y 1,,y m ), f(x, y) =. f m (x, y 1,,y m ) dy dx = f(x, y) y(x )=y (3.51) 2 j(j =1, 2,,n) dy dx = f 1(x, y, z) (3.52) dz dx = f 2(x, y, z) (3.53) y(x )=y, z(x )=z Y = y,z = z, k 1 = hf 1 (x j 1,Y j 1,Z j 1 ) m 1 = hf 2 (x j 1,Y j 1,Z j 1 ) k 2 = hf 1 (x j 1 + h/2,y j 1 + k 1 /2,Z j 1 + m 1 /2) m 2 = hf 2 (x j 1 + h/2,y j 1 + k 1 /2,Z j 1 + m 1 /2) k 3 = hf 1 (x j 1 + h/2,y j 1 + k 2 /2,Z j 1 + m 2 /2) 15

m 3 = hf 2 (x j 1 + h/2,y j 1 + k 2 /2,Z j 1 + m 2 /2) k 4 = hf 1 (x j 1 + h, Y j 1 + k 3,Z j 1 + m 3 ) m 4 = hf 2 (x j 1 + h, Y j 1 + k 3,Z j 1 + m 3 ) Y j = Y j 1 + 1 6 (k 1 +2k 2 +2k 3 + k 4 ) Z j = Z j 1 + 1 6 (m 1 +2m 2 +2m 3 + m 4 ) x j = x j 1 + h 5 4 4.1 x 1,x 2,,x n u u 1 F (x 1,x 2,,x n,u, u,, 2 u 2 u,, )= x 1 x 1 x 2 2 2 x, y u(x, y) x 2 1 a(x, y) 2 u x 2 +2b(x, y) 2 u x + c(x, u y) 2 + d(x, y) u 2 x + e(x, y) u + f(x, y)u = g(x, y) a, b, c, d, e, f, g b 2 ac > b 2 ac < b 2 ac = 4.2 1 x x i 1 <x i <x i+1 (x i+1 x i = x i x i 1 = x) y = y(x) 3 (x i 1,y i 1 ), (x i,y i ), (x i+1,y i+1 ) (x i,y i ) tan θ x θ tan θ = dy dx = lim y x x = lim y i+1 y i x x x tan θ =(y i+1 y i )/ x dy/dx dy dx = y i+1 y i x 16

dy dx = y i y i 1 x tan θ =(y i+1 y i 1 )/(2 x) dy dx = y i+1 y i 1 2 x u = u(x, y) x a, y b x i = m y j = n (x, y) (i, j) u u(x, y) u ij u i 1,j,u i,j 1 x i, y j u/ x, u/ u x = u i+1,j u i,j x i (4.1) u = u i,j+1 u i,j y j (4.2) u x = u i,j u i 1,j x i 1 (4.3) u = u i,j u i,j 1 y j 1 (4.4) u x = u i+1,j u i 1,j x i 1 + x i (4.5) u = u i,j+1 u i,j 1 y i 1 + y j (4.6) 2 2 u/ x 2 u x = x ( ) u = ( u/) i+1,j ( u/) i 1,j x i 1 + x i ( u/) i+1,j i +1 u ( u/) i 1,j i 1 ( ) u = u i 1,j+1 u i 1,j 1 i 1,j y j 1 + y j ( ) u = u i+1,j+1 u i+1,j 1 i+1,j y j 1 + y j 17

2 u x = u i+1,j+1 u i+1,j 1 u i 1,j+1 + u i 1,j 1 ( x i 1 + x i )( y i 1 + y i ) (4.7) 2 u/ x 2 u x = u i+1,j+1 u i+1,j 1 u i 1,j+1 + u i 1,j 1 ( x i 1 + x i )( y i 1 + y i ) (4.8) 2 u x = 2 u x (4.9) 2 u/ x 2 2 u/ 2 u/ x u/ 2 u x 2 = x ( ) u = ( u/ x) i+1,j ( u/ x) i,j x x i ( u/ x) i+1,j ( u/ x) i,j ( ) u = u ( ) i+1,j u i,j u, = u i,j u i 1,j x i+1,j x i x i,j x i 1 2 ( u x 2 = ui+1,j u i,j x i u )/ i,j u i 1,j x i (4.1) x i 1 y 2 u 2 = ( ui,j+1 u i,j y j u i,j u i,j 1 y j 1 ) / y j (4.11) x i 1 = x i = h y j 1 = j i = k h k 2 u x = 1 2h (u i+1,j u i 1,j ) (4.12) u = 1 2k (u i,j+1 u i,j 1 ) (4.13) 2 u x = 1 4hk (u i+1,j+1 u i+1,j 1 u i 1,j+1 + u i 1,j 1 ) (4.14) 2 u x 2 = 1 h 2 (u i+1,j 2u i,j u i 1,j ) (4.15) 2 u 2 = 1 k 2 (u i,j+1 2u i,j u i,j 1 ) (4.16) 18

2 u(x + h, y) u(x h, y) (4.17) ( u/ x) u(x + h, y) = u(x, y)+h u x + h2 2 u 2! u(x h, y) = u(x, y) h u x + h2 2! u u(x + h, y) u(x, y) = x h u(x + h, y) =u i+1,j,u(x, y) =u i,j u x = u i+1,j u i,j h x 2 + h3 3 u + 3! x3 (4.17) 2 u x 2 h3 3 u + 3! x3 (4.18) h 2 u 2! x 2 h2 3 u 3! x 3 + h (4.18) u x = u i,j u i 1,j h O(h) (4.19) O(h) (4.2) O(h) (4.17) (4.18) ( u/ x) u x u(x + h, y) u(x h, y) = 2h = u i+1,j u i 1,j 2h h2 3 u 3! x 3 O(h 2 ) (4.21) h 2 (4.17) (4.18) ( u/ x) 2 u x 2 = u(x + h, y) 2u(x, y)+u(x h, y) h 2 h2 4 u 12 x 4 = u i+1,j 2u i,j + u i 1,j h 2 O(h 2 ) (4.22) 2 u/ x 2 h 2 4.3 3 u t = c2 2 u x 2 (4.23) u(x, ) = f(x), x L u(,t)=p(t),u(l, t) =q(t), t 19

c (4.23) (4.13) (4.15) u(x, t + k) u(x, t) k 2 u(x + h, t) 2u(x, t)+u(x h, t) = c h 2 λ = kc 2 /h 2 u(x, t + k) =λu(x + h, t)+(1 2λ)u(x, t)+λu(x h, t) (4.24) u(x + h, t),u(x, t),u(x h, t) 3 u(x, t + k) (4.13) (4.15) {u t (x, t) c 2 u xx (x, t)} {c 2 /(λh 2 )}{u(x, t + k) λu(x + h, t) (1 2λ)u(x, t) λu(x h, t)} = O(h 2 ) u (4.23) k = λh 2 /c 2 u(x, t + k) =λu(x + h, t)+(1 2λ)u(x, t)+λu(x h, t)+o(h 4 ) O(h 4 ) [,L] N h = L/N, k = λh 2 /c 2 x m = mh (m =, 1,,N),t n = nk (n =, 1, ) { x L, t } (x m,t n ) u(x m,t n ) U m,n (4.23) (4.24) U m,n+1 = λu m 1,n +(1 2λ)U m,n + λu m+1,n (n =, 1, ; m =1, 2,,N 1) (4.25) { Um, = u(x m, ) = f(x m ) (m =, 1,,N) U,n = u(,t n )=p(t n ), U n,m = u(l, t n )=q(t n ) (n =, 1, ) (4.26) U m, = f(x m ) (m =, 1,,N) U,n = p(t n ),U N,n = q(t n ) (n =, 1, ) n (n =, 1, 2, ) U m,n+1 = λu m 1,n +(1 2λ)U m,n + λu m+1,n (m =1, 2,,N 1) λ λ λ 4.1 λ = kc 2 /h 2 λ 1/2 U m,n h u(x m,t n ) x 6 2

4.4 3 2 2 u x 2 + 2 u =; x a, y b (4.27) 2 u(, y)=p(y) u(x, ) = v(x), u(a, y) =q(y),u(x, b) =w(x) (4.28) p, q, v, w x a, y b h, k i =, 1,,m, j =, 1,,n f(x, y) =f i,j (4.15) (4.16) (4.27) u i,j 1 h 2 (u i+1,j 2u i,j + u i 1,j )+ 1 k 2 (u i,j+1 2u i,j + u i,j 1 )= u i,j = 1 2(h 2 + k 2 ) {k2 (u i+1,j + u i 1,j )+h 2 (u i,j+1 + u i,j 1 )} (4.29) u p(y) q(y) v(x) w(x) u i,j i =1, 2,,m 1; j =1, 2,,n 1 u i,j = (4.29) u u (1) i,j u(1) i,j (4.29) u(2) i,j k k +1 ε (u i,j (k+1) u (k) (k+1) i,j )/u i,j ε; (4.3) i =1, 2,,m 1; j =1, 2,,n 1 u (k+1) i,j u i,j m 1 i=1 n 1 j=1 u i,j (k+1) (k) u i,j / m 1 n 1 i=1 j=1 u i,j (k+1) ε (4.31) (4.31) (4.29) u (4.29) { } (k+1) 1 u i,j = 2(h 2 + k 2 k 2 (u (k) i+1,j + u (k+1) i 1,j )+h 2 (u (k) i,j+1 + u (k+1) i,j 1 ) (4.32) ) (4.32) - (4.32) u (k) i,j u (k) i,j [ { } ] u (k+1) i,j = u (k) 1 i,j + 2(h 2 + k 2 k 2 (u (k) i+1,j + u (k+1) i 1,j )+h 2 (u (k) i,j+1 + u (k+1) (k) i,j 1 ) u i,j (4.33) ) (4.33) [ ] u i,j (k) 1 u i,j (k+1) u i,j (k) u i,j (k+1) u i,j (k) =[ ] [ ] u i,j (k+1) u i,j (k) 21

[ ] [ ] ω [ u (k+1) i,j = u (k) i,j + ω 1 2(h 2 + k 2 ) { } ] k 2 (u (k) i+1,j + u (k+1) i 1,j )+h 2 (u (k) i,j+1 + u (k+1) (k) i,j 1 ) u i,j (4.34) ω (4.34) SOR ω ω i =, 1, 2,,m; j =, 1, 2,,n h = k ω = 2, µ =cos π 1+ 1 (µ/2) 2 m +cosπ n (4.35) 7 22

5 1 6 23

[1] 21 [2] 1998 [3] 1999 [4] 21 [5] 1993 [6] PAD,PASCAL,C 1999 [7] 3 1998 [8] 1997 [9] 1999 [1] C 1989 [11] Samuel P.Harbison,Guy L.Steele Jr., C 1992 [12] C 1993 [13] W.H.Press,B.P.Flannery,S.A.Teukolsky,W.T.Vetterling Numerical Recipes in C[ ] 1993 [14] 1997 [15] 1993 [16] - C 1992 [17] C 1998 [18] 199 [19] - C/C ++ 1997 24

7 =1= =2= =3= =4= =5= - =6= =7=