Relaxation scheme of Besse t t n = n t, u n = u(t n ) (n = 0, 1,,...)., t u(t) = F (u(t)) (1). (1), u n+1 u n t = F (u n ) u n+1 = u n + tf (u n )., t

Size: px
Start display at page:

Download "Relaxation scheme of Besse t t n = n t, u n = u(t n ) (n = 0, 1,,...)., t u(t) = F (u(t)) (1). (1), u n+1 u n t = F (u n ) u n+1 = u n + tf (u n )., t"

Transcription

1 RIMS relaxation sheme of Besse splitting method Scilab Scilab Google Scilab Scilab Mathieu Colin Mathieu Colin 1

2 Relaxation scheme of Besse t t n = n t, u n = u(t n ) (n = 0, 1,,...)., t u(t) = F (u(t)) (1). (1), u n+1 u n t = F (u n ) u n+1 = u n + tf (u n )., t = t n+1/ (1) u n+1 u n = F (u n+1/ ), u n+1/ = un+1 + u n t (Crank-Nicolson scheme). () u(t + h) u(t) h u(t ± h) = u(t) ± hu (t) + h u (t) + O(h 3 ) = u (t) + O(h),. () u(t + h) u(t h) h = u (t) + O(h ) u n+1 = u n+1/ u n, (3) u n+1/ tf (u n+1/ ) = u n (4). F, u n u n+1/, (4)., F F (u) = Au, (4) (I ta)u n+1/ = u n,, u n u n+1/, (3) u n+1.

3 , A, g t u = Au + g(u)u (5). Crank-Nicolson scheme,. u n+1 u n t = Au n+1/ + g(u n )u n+1/, u n+1/ = un+1 + u n (6), u n, (I ta tg(u n ))u n+1/ = u n, u n+1/. (6), g(u n ) t = t n g(u(t)), t = t n+1/. g(u) t = t n+1/, Crank-Nicolson scheme., (Relaxation scheme of Besse). ϕ, (5) { ϕ = g(u) (7) t u = Au + ϕu (8). (7) t = t n, (8) t = t n+1/ ϕ n+1/ + ϕ n 1/ = g(u n ), u n+1 u n = Au n+1/ + ϕ n+1/ u n+1/ t., ϕ 1/ = g(u 0 )., (ϕ n 1/, u n ) ϕ n+1/ = g(u n ) ϕ n 1/, (I ta tϕ n+1/ )u n+1/ = u n, ϕ n+1/ u n+1/. u n+1 = u n+1/ u n u n+1, (ϕ n+1/, u n+1 ). 3

4 Schrödinger i t u = xu + V (x)u g(u)u, 0 x < L, 0 < t T, u(t, 0) = u(t, L), 0 < t T, u(0, x) = u 0 (x), 0 x < L relaxation scheme of Besse., V (x), g(u) = c u p (c R, p > 0). [0, L) N. x = L/N. x j = j x (j = 0, 1,..., N 1). t, t n = n t (n = 0, 1,,...). u(t, x) u n = [u n 0, u n 1,..., u n ] T, u n j = u(t n, x j )., T. n, u n N. u = [u 0, u 1,..., u ] T, g(u) = [g(u 0 ), g(u 1 ),..., g(u )] T. Laplacian u(x ± h) = u(x) ± hu (x) + h u (x) ± h3 3! u(3) (x) + O(h 4 ) u(x + h) + u(x h) u(x) = u (x) + O(h ). h, x N D xx = 1 ( x) , A = D xx diag [V (x 0 ), V (x 1 ),..., V (x )]. 4

5 w n+1/ + w n 1/ = g(u n ), w 1/ = g(u 0 ) i un+1 u n t + Au n+1/ + w n+1/ u u+1/ = 0, u n+1/ = un+1 + u n., u n+1 u n = (u n+1/ u n ), W n+1/ = diag (w n+1/ ) w n+1/ = g(u n ) w n 1/, ( iin + ta + tw n+1/) u n+1/ = iu n., I N N., u n u n+1/. u n+1 = u n+1/ u n, u n+1. Scilab. N u, v, u, v = x u j v j, u = u, u 1/ j=0. {u n }, L., n = 0, 1,,..., u n = u 0.,,, []. []. [1] C. Besse, Schéma de relaxation pour l équation de Schrödinger non linéaire et les systèmes de Davey et Stewartson, C. R. Acad. Sci. Paris Sér. I Math. 36 (1998) [] C. Besse, A relaxation scheme for the nonlinear Schrödinger equation, SIAM J. Numer. Anal. 4 (004)

6 Solitary waves for nonlinear Schrödinger equations Schrödinger. i t u + xu + g(u)u = 0, (x, t) R g(u) = c 3 u p (p > 0, c 3 > 0) ω > 0, k R. u ω,k (t, x) = exp(ikx ik t) exp(iω t)φ ω (x kt), ( ) 1/p ω c3 φ ω (x) =, d 3 = d 3 cosh(pωx) p + 1 u ω,k (0, x) = (ω/d 3 ) 1/p exp(ikx){cosh(pωx)} 1/p. g(u) = c u p + c 3 u p (p > 0, c, c 3 R) ω > 0, k R φ ω (x) = (. u ω,k (t, x) = exp(ikx ik t) exp(iω t)φ ω (x kt), ω d + d + d 3ω cosh(pωx) u ω,k (0, x) = exp(ikx) ( ) 1/p, d = c p +, d c3 3 = p + 1 ω d + d + d 3ω cosh(pωx) ) 1/p. 1

7 05/5/11 09:54:03 C:/Documents and Settings/Administrator/My Documents/Kyoto053/B clear; // Nonlinear Schrodinger equation // iu_t+u_{xx}+c3 u ^{p}u=0, 0<x<L, 0<t<T // with periodic boundary conditions // Constants c3=0; p=1; L=10; N=56; T=10; NT=0; dt=10^(-3); ome1=4; k1=0; ome=3; k=-1; dx=*l/n; x=[0:n-1]'*dx; // Space variable Dxx=-*speye(N,N)+[spzeros(1,N);speye(N-1,N)]... +[spzeros(n,1),speye(n,n-1)]; Dxx(1,N)=1; Dxx(N,1)=1; Dxx=Dxx/dx/dx; // Second Derivative in x function y=g(u) // Nonlinear term y=c3*abs(u)^(*p) d3=sqrt(c3/(p+1)); // Solitary waves function y=f1(x) y=(ome1/d3)^(1/p)*exp(%i*k1*x).*(cosh(p*ome1*x))^(-1/p) function y=f(x) y=(ome/d3)^(1/p)*exp(%i*k*x).*(cosh(p*ome*x))^(-1/p) u0=f1(x-l+4)+f(x-l-4); // Initial data IA=*%i*speye(N,N)+dt*Dxx; timer(); // Relaxation scheme of Besse t=0; u=u0; w=g(u); for n=1:nt, while t<=n*t/nt, w=*g(u)-w; v=(ia+dt*sparse(diag(w)))\(*%i*u); u=*v-u; clear v; t=t+dt; end clf(); // Animation plot(x,real(u),'g'); plot(x,imag(u),'y'); plot(x,abs(u),'b'); plot(x,-abs(u),'b'); Mass(n)=sum(abs(u)^)*dx; Energy(n)=-real(u'*Dxx*u)*dx/-c3*sum(abs(u)^(*p+))*dx/(*p+); end Timer=timer() plot(x,abs(u0),'r'); xset("window",1) plot(mass); xset("window",) plot(energy); ErrorMass=max(Mass)-min(Mass) ErrorEnergy=max(Energy)-min(Energy) Page : 1

8 Splitting method for nonlinear Schrödinger equations, splitting method, t u = A(u) + B(u), u(0) = u 0 u(t) = S(t)u 0, t v = A(v) X(t) t w = B(w) Y (t). Z L (t) = Y (t)x(t), Z S (t) = Y (t/)x(t)y (t/)., T > 0, t > 0, n t T n N S(n t)u 0 Z L ( t) n u 0 C t, S(n t)u 0 Z S ( t) n u 0 C( t)., C T u 0. Z L Lie formula, Z S Strang formula., Y (t) Z S ( t) n = Y ( t/)z L ( t) n Y ( t/)., Schrödinger { i t u = (1) xu + V (x)u g(u)u (t, x) R u(0, x) = u 0 (x) x R., V (x), g, g(z) = g( z ) (z C). g(u) = c u p (c R, p > 0)., (1) { t v = i () xv (t, x) R v(0, x) = v 0 (x) x R (3). () {., (3) t w = i[g(w) V (x)]w (t, x) R w(0, x) = w 0 (x) x R v(t, x) = F 1 [e itξ Fv 0 ](x) w(t, x) = exp ( it{g(w 0 (x)) V (x)} ) w 0 (x) (4)., g, x R t w(t, x) = R(ww) = R{i[g(w(t, x)) V (x)] w(t, x) } = 0., (t, x) R w(t, x) = w 0 (x)., g(z) = g( z ), (t, x) R g(w(t, x)) = g(w 0 (x)), (4). Scilab. 1

9 [1] C. Besse, B. Bidégaray, and S. Descombes, Order estimates in time of splitting methods for nonlinear Schrödinger equation, SIAM J. Numer. Anal. 40 (00) [] H. Holden, K. H. Karlsen, K.-A. Lie, and N. H. Risebro, Splitting methods for partial differential equations with rough solutions, Analysis and MATLAB programs, EMS Series of Lectures in Mathematics, European Mathematical Society (EMS), Zürich, 010. [3] H. Holden, K. H. Karlsen, N. H. Risebro, and T. Tao, Operator splitting for the KdV equation, preprint, arxiv: [4] C. Lubich, On splitting methods for Schrödinger-Poisson and cubic nonlinear Schrödinger equations, Math. Comp. 77 (008)

10 Fourier f(x) L., k Z, ξ k = kπ/l, f(x) Fourier ˆf(ξ k ) = 1 L L 0 f(x)e iξ kx dx (1) f(x) =.. k= ˆf(ξ k )e iξ kx () N, [0, L) N. x = L/N. x j = j x, f j = f(x j ) (j Z)., f j+n = f j (j Z), f(x) N [f 0, f 1,..., f ]. (1) ˆf(ξ k ) 1 f(x j )e iξ kx j x = L ˆf k j=0. ˆf k = 1 N j=0 f j ω jk, ω = exp ( ) πi N., ω N = 1, ˆfk+N = ˆf k (k Z), ˆf(ξk ) N [ ˆf 0, ˆf 1,..., ˆf ] [ ˆf N/+1,..., ˆf 1, ˆf 0, ˆf 1,..., ˆf N/ ]., () N/ k= N/+1 ˆf k ω jk = ˆf k ω jk., j = 0, 1,..., N 1 ˆf k ω jk = 1 N l=0 f l ω (j l)k = 1 N l=0 f l ω (j l)k, j, l = 0, 1,..., N 1, j l N 1, l j, ω j l 1 ω (j l)k = 1 ω(j l)n 1 ω j l = 0. 1

11 , l = j, ω (j l)k = N, () f j = ˆf k ω jk = N/ k= N/+1 ˆf k ω jk (j Z)., (), f (x). N/ k= N/+1 f (x) = k= iξ k ˆf(ξk )e iξ kx N/ iξ k ˆfk ω jk = iξ k ˆfk ω jk + k=n/+1 iξ k N ˆfk ω jk Scilab, N u = [u 0, u 1,..., u ], v=fft(u) N v = [v 0, v 1,..., v ], v k = j=0 u j ω jk., N v = [v 0, v 1,..., v ], u=ifft(v) N u = [u 0, u 1,..., u ], u j = 1 N. fft ifft. v k ω jk xi = [ξ 0, ξ 1,..., ξ N/, ξ N/+1,..., ξ 1 ] = π [0, 1,..., N/, N/ + 1,..., 1] L, p( x )u(x) ifft(p(%i*xi).*fft(u))., u = [u(x 0 ), u(x 1 ),..., u(x )], %i, p(z) v = [v 0, v 1,..., v ], p(v) p(v) = [p(v 0 ), p(v 1 ),..., p(v )], v w, v. w. v. w = [v 0 w 0, v 1 w 1,..., v w ]

12 05/5/11 09:57:13 C:/Documents and Settings/Administrator/My Documents/Kyoto053/S clear; // Nonlinear Schrodinger equation // iu_t+u_{xx}+c_3 u ^{p}u=0, 0<x<L, 0<t<T // with periodic boundary conditions // Constants c3=0; p=1; L=10; N=56; T=10; NT=0; dt=10^(-4); ome1=4; k1=0; ome=3; k=-1; dx=*l/n; x=[0:n-1]*dx; // Space variable xi=[0:n/,-n/+1:-1]*%pi/l; // Fourier variable function y=g(u) // Nonlinear term y=c3*abs(u)^(*p) function v=dx(u) // Derivative in x v=ifft(%i*xi.*fft(u)) d3=sqrt(c3/(p+1)); // Solitary waves function y=f1(x) y=(ome1/d3)^(1/p)*exp(%i*k1*x).*(cosh(p*ome1*x))^(-1/p) function y=f(x) y=(ome/d3)^(1/p)*exp(%i*k*x).*(cosh(p*ome*x))^(-1/p) u0=f1(x-l+4)+f(x-l-4); // Initial data timer(); // Splitting method with Strang formula t=0; u=u0; for n=1:nt, u=exp(%i*dt/*g(u)).*u; while t<=n*t/nt, u=ifft(exp(-%i*dt*xi^).*fft(u)); u=exp(%i*dt*g(u)).*u; t=t+dt; end u=exp(-%i*dt/*g(u)).*u; clf(); // Animation plot(x,real(u),'g'); plot(x,imag(u),'y'); plot(x,abs(u),'b'); plot(x,-abs(u),'b'); Mass(n)=sum(abs(u)^)*dx; Energy(n)=sum(abs(Dx(u))^)*dx/-c3*sum(abs(u)^(*p+))*dx/(*p+); end Timer=timer() plot(x,abs(u0),'r'); xset("window",1) plot(mass); xset("window",) plot(energy); ErrorMass=max(Mass)-min(Mass) ErrorEnergy=max(Energy)-min(Energy) Page : 1

163 KdV KP Lax pair L, B L L L 1/2 W 1 LW = ( / x W t 1, t 2, t 3, ψ t n ψ/ t n = B nψ (KdV B n = L n/2 KP B n = L n KdV KP Lax W Lax τ KP L ψ τ τ Cha

163 KdV KP Lax pair L, B L L L 1/2 W 1 LW = ( / x W t 1, t 2, t 3, ψ t n ψ/ t n = B nψ (KdV B n = L n/2 KP B n = L n KdV KP Lax W Lax τ KP L ψ τ τ Cha 63 KdV KP Lax pair L, B L L L / W LW / x W t, t, t 3, ψ t n / B nψ KdV B n L n/ KP B n L n KdV KP Lax W Lax τ KP L ψ τ τ Chapter 7 An Introduction to the Sato Theory Masayui OIKAWA, Faculty of Engneering,

More information

I ( ) 1 de Broglie 1 (de Broglie) p λ k h Planck ( Js) p = h λ = k (1) h 2π : Dirac k B Boltzmann ( J/K) T U = 3 2 k BT

I ( ) 1 de Broglie 1 (de Broglie) p λ k h Planck ( Js) p = h λ = k (1) h 2π : Dirac k B Boltzmann ( J/K) T U = 3 2 k BT I (008 4 0 de Broglie (de Broglie p λ k h Planck ( 6.63 0 34 Js p = h λ = k ( h π : Dirac k B Boltzmann (.38 0 3 J/K T U = 3 k BT ( = λ m k B T h m = 0.067m 0 m 0 = 9. 0 3 kg GaAs( a T = 300 K 3 fg 07345

More information

Korteweg-de Vries

Korteweg-de Vries Korteweg-de Vries 2011 03 29 ,.,.,.,, Korteweg-de Vries,. 1 1 3 1.1 K-dV........................ 3 1.2.............................. 4 2 K-dV 5 2.1............................. 5 2.2..............................

More information

untitled

untitled 3 3. (stochastic differential equations) { dx(t) =f(t, X)dt + G(t, X)dW (t), t [,T], (3.) X( )=X X(t) : [,T] R d (d ) f(t, X) : [,T] R d R d (drift term) G(t, X) : [,T] R d R d m (diffusion term) W (t)

More information

( ) ( 40 )+( 60 ) Schrödinger 3. (a) (b) (c) yoshioka/education-09.html pdf 1

( ) ( 40 )+( 60 ) Schrödinger 3. (a) (b) (c)   yoshioka/education-09.html pdf 1 2009 1 ( ) ( 40 )+( 60 ) 1 1. 2. Schrödinger 3. (a) (b) (c) http://goofy.phys.nara-wu.ac.jp/ yoshioka/education-09.html pdf 1 1. ( photon) ν λ = c ν (c = 3.0 108 /m : ) ɛ = hν (1) p = hν/c = h/λ (2) h

More information

phs.dvi

phs.dvi 483F 3 6.........3... 6.4... 7 7.... 7.... 9.5 N (... 3.6 N (... 5.7... 5 3 6 3.... 6 3.... 7 3.3... 9 3.4... 3 4 7 4.... 7 4.... 9 4.3... 3 4.4... 34 4.4.... 34 4.4.... 35 4.5... 38 4.6... 39 5 4 5....

More information

u = u(t, x 1,..., x d ) : R R d C λ i = 1 := x 2 1 x 2 d d Euclid Laplace Schrödinger N := {1, 2, 3,... } Z := {..., 3, 2, 1,, 1, 2, 3

u = u(t, x 1,..., x d ) : R R d C λ i = 1 := x 2 1 x 2 d d Euclid Laplace Schrödinger N := {1, 2, 3,... } Z := {..., 3, 2, 1,, 1, 2, 3 2 2 1 5 5 Schrödinger i u t + u = λ u 2 u. u = u(t, x 1,..., x d ) : R R d C λ i = 1 := 2 + + 2 x 2 1 x 2 d d Euclid Laplace Schrödinger 3 1 1.1 N := {1, 2, 3,... } Z := {..., 3, 2, 1,, 1, 2, 3,... } Q

More information

p = mv p x > h/4π λ = h p m v Ψ 2 Ψ

p = mv p x > h/4π λ = h p m v Ψ 2 Ψ II p = mv p x > h/4π λ = h p m v Ψ 2 Ψ Ψ Ψ 2 0 x P'(x) m d 2 x = mω 2 x = kx = F(x) dt 2 x = cos(ωt + φ) mω 2 = k ω = m k v = dx = -ωsin(ωt + φ) dt = d 2 x dt 2 0 y v θ P(x,y) θ = ωt + φ ν = ω [Hz] 2π

More information

5. [1 ] 1 [], u(x, t) t c u(x, t) x (5.3) ξ x + ct, η x ct (5.4),u(x, t) ξ, η u(ξ, η), ξ t,, ( u(ξ,η) ξ η u(x, t) t ) u(x, t) { ( u(ξ, η) c t ξ ξ { (

5. [1 ] 1 [], u(x, t) t c u(x, t) x (5.3) ξ x + ct, η x ct (5.4),u(x, t) ξ, η u(ξ, η), ξ t,, ( u(ξ,η) ξ η u(x, t) t ) u(x, t) { ( u(ξ, η) c t ξ ξ { ( 5 5.1 [ ] ) d f(t) + a d f(t) + bf(t) : f(t) 1 dt dt ) u(x, t) c u(x, t) : u(x, t) t x : ( ) ) 1 : y + ay, : y + ay + by : ( ) 1 ) : y + ay, : yy + ay 3 ( ): ( ) ) : y + ay, : y + ay b [],,, [ ] au xx

More information

X G P G (X) G BG [X, BG] S 2 2 2 S 2 2 S 2 = { (x 1, x 2, x 3 ) R 3 x 2 1 + x 2 2 + x 2 3 = 1 } R 3 S 2 S 2 v x S 2 x x v(x) T x S 2 T x S 2 S 2 x T x S 2 = { ξ R 3 x ξ } R 3 T x S 2 S 2 x x T x S 2

More information

2015 I ( TA)

2015 I ( TA) 2015 I ( TA) Schrödinger PDE Python u(t, x) x t 2 u(x, t) = k u(t, x) t x2 k k = i h 2m Schrödinger h m 1 ψ(x, t) i h ( 1 ψ(x, t) = i h ) 2 ψ(x, t) t 2m x Cauchy x : x Fourier x x Fourier 2 u(x, t) = k

More information

²ÄÀÑʬΥ»¶ÈóÀþ·¿¥·¥å¥ì¡¼¥Ç¥£¥ó¥¬¡¼ÊýÄø¼°¤ÎÁ²¶á²òÀÏ Asymptotic analysis for the integrable discrete nonlinear Schrödinger equation

²ÄÀÑʬΥ»¶ÈóÀþ·¿¥·¥å¥ì¡¼¥Ç¥£¥ó¥¬¡¼ÊýÄø¼°¤ÎÁ²¶á²òÀÏ  Asymptotic analysis for the integrable discrete nonlinear Schrödinger equation Asymptotic analysis for the integrable discrete nonlinear Schrödinger equation ( ) ( ) 2016 12 17 1. Schrödinger focusing NLS iu t + u xx +2 u 2 u = 0 u(x, t) =2ηe 2iξx 4i(ξ2 η 2 )t+i(ψ 0 +π/2) sech(2ηx

More information

t, x (4) 3 u(t, x) + 6u(t, x) u(t, x) + u(t, x) = 0 t x x3 ( u x = u x (4) u t + 6uu x + u xxx = 0 ) ( ): ( ) (2) Riccati ( ) ( ) ( ) 2 (1) : f

t, x (4) 3 u(t, x) + 6u(t, x) u(t, x) + u(t, x) = 0 t x x3 ( u x = u x (4) u t + 6uu x + u xxx = 0 ) ( ): ( ) (2) Riccati ( ) ( ) ( ) 2 (1) : f : ( ) 2008 5 31 1 f(t) t (1) d 2 f(t) + f(t) = 0 dt2 f(t) = sin t f(t) = cos t (1) 1 (2) d dt f(t) + f(t)2 = 0 (1) (2) t (c ) (3) 2 2 u(t, x) c2 u(t, x) = 0 t2 x2 1 (1) (1) 1 t, x (4) 3 u(t, x) + 6u(t,

More information

December 28, 2018

December 28, 2018 e-mail : kigami@i.kyoto-u.ac.jp December 28, 28 Contents 2............................. 3.2......................... 7.3..................... 9.4................ 4.5............. 2.6.... 22 2 36 2..........................

More information

1 4 1 ( ) ( ) ( ) ( ) () 1 4 2

1 4 1 ( ) ( ) ( ) ( ) () 1 4 2 7 1995, 2017 7 21 1 2 2 3 3 4 4 6 (1).................................... 6 (2)..................................... 6 (3) t................. 9 5 11 (1)......................................... 11 (2)

More information

Feynman Encounter with Mathematics 52, [1] N. Kumano-go, Feynman path integrals as analysis on path space by time slicing approximation. Bull

Feynman Encounter with Mathematics 52, [1] N. Kumano-go, Feynman path integrals as analysis on path space by time slicing approximation. Bull Feynman Encounter with Mathematics 52, 200 9 [] N. Kumano-go, Feynman path integrals as analysis on path space by time slicing approximation. Bull. Sci. Math. vol. 28 (2004) 97 25. [2] D. Fujiwara and

More information

p12.dvi

p12.dvi 301 12 (2) : 1 (1) dx dt = f(x,t) ( (t 0,t 1,...,t N ) ) h k = t k+1 t k. h k k h. x(t k ) x k. : 2 (2) :1. step. 1 : explicit( ) : ξ k+1 = ξ k +h k Ψ(t k,ξ k,h k ) implicit( ) : ξ k+1 = ξ k +h k Ψ(t k,t

More information

: 1g99p038-8

: 1g99p038-8 16 17 : 1g99p038-8 1 3 1.1....................................... 4 1................................... 5 1.3.................................. 5 6.1..................................... 7....................................

More information

ohpr.dvi

ohpr.dvi 2003/12/04 TASK PAF A. Fukuyama et al., Comp. Phys. Rep. 4(1986) 137 A. Fukuyama et al., Nucl. Fusion 26(1986) 151 TASK/WM MHD ψ θ ϕ ψ θ e 1 = ψ, e 2 = θ, e 3 = ϕ ϕ E = E 1 e 1 + E 2 e 2 + E 3 e 3 J :

More information

1 Fourier Fourier Fourier Fourier Fourier Fourier Fourier Fourier Fourier analog digital Fourier Fourier Fourier Fourier Fourier Fourier Green Fourier

1 Fourier Fourier Fourier Fourier Fourier Fourier Fourier Fourier Fourier analog digital Fourier Fourier Fourier Fourier Fourier Fourier Green Fourier Fourier Fourier Fourier etc * 1 Fourier Fourier Fourier (DFT Fourier (FFT Heat Equation, Fourier Series, Fourier Transform, Discrete Fourier Transform, etc Yoshifumi TAKEDA 1 Abstract Suppose that u is

More information

main.dvi

main.dvi 4 DFT DFT Fast Fourier Transform: FFT 4.1 DFT IDFT X(k) = 1 n=0 x(n)e j2πkn (4.1) 1 x(n) = 1 X(k)e j2πkn (4.2) k=0 x(n) X(k) DFT 2 ( 1) 2 4 2 2(2 1) 2 O( 2 ) 4.2 FFT 4.2.1 radix2 FFT 1 (4.1) 86 4. X(0)

More information

構造と連続体の力学基礎

構造と連続体の力学基礎 II 37 Wabash Avenue Bridge, Illinois 州 Winnipeg にある歩道橋 Esplanade Riel 橋6 6 斜張橋である必要は多分無いと思われる すぐ横に道路用桁橋有り しかも塔基部のレストランは 8 年には営業していなかった 9 9. 9.. () 97 [3] [5] k 9. m w(t) f (t) = f (t) + mg k w(t) Newton

More information

4. ϵ(ν, T ) = c 4 u(ν, T ) ϵ(ν, T ) T ν π4 Planck dx = 0 e x 1 15 U(T ) x 3 U(T ) = σt 4 Stefan-Boltzmann σ 2π5 k 4 15c 2 h 3 = W m 2 K 4 5.

4. ϵ(ν, T ) = c 4 u(ν, T ) ϵ(ν, T ) T ν π4 Planck dx = 0 e x 1 15 U(T ) x 3 U(T ) = σt 4 Stefan-Boltzmann σ 2π5 k 4 15c 2 h 3 = W m 2 K 4 5. A 1. Boltzmann Planck u(ν, T )dν = 8πh ν 3 c 3 kt 1 dν h 6.63 10 34 J s Planck k 1.38 10 23 J K 1 Boltzmann u(ν, T ) T ν e hν c = 3 10 8 m s 1 2. Planck λ = c/ν Rayleigh-Jeans u(ν, T )dν = 8πν2 kt dν c

More information

9. 05 L x P(x) P(0) P(x) u(x) u(x) (0 < = x < = L) P(x) E(x) A(x) P(L) f ( d EA du ) = 0 (9.) dx dx u(0) = 0 (9.2) E(L)A(L) du (L) = f (9.3) dx (9.) P

9. 05 L x P(x) P(0) P(x) u(x) u(x) (0 < = x < = L) P(x) E(x) A(x) P(L) f ( d EA du ) = 0 (9.) dx dx u(0) = 0 (9.2) E(L)A(L) du (L) = f (9.3) dx (9.) P 9 (Finite Element Method; FEM) 9. 9. P(0) P(x) u(x) (a) P(L) f P(0) P(x) (b) 9. P(L) 9. 05 L x P(x) P(0) P(x) u(x) u(x) (0 < = x < = L) P(x) E(x) A(x) P(L) f ( d EA du ) = 0 (9.) dx dx u(0) = 0 (9.2) E(L)A(L)

More information

k m m d2 x i dt 2 = f i = kx i (i = 1, 2, 3 or x, y, z) f i σ ij x i e ij = 2.1 Hooke s law and elastic constants (a) x i (2.1) k m σ A σ σ σ σ f i x

k m m d2 x i dt 2 = f i = kx i (i = 1, 2, 3 or x, y, z) f i σ ij x i e ij = 2.1 Hooke s law and elastic constants (a) x i (2.1) k m σ A σ σ σ σ f i x k m m d2 x i dt 2 = f i = kx i (i = 1, 2, 3 or x, y, z) f i ij x i e ij = 2.1 Hooke s law and elastic constants (a) x i (2.1) k m A f i x i B e e e e 0 e* e e (2.1) e (b) A e = 0 B = 0 (c) (2.1) (d) e

More information

2 1 κ c(t) = (x(t), y(t)) ( ) det(c (t), c x (t)) = det (t) x (t) y (t) y = x (t)y (t) x (t)y (t), (t) c (t) = (x (t)) 2 + (y (t)) 2. c (t) =

2 1 κ c(t) = (x(t), y(t)) ( ) det(c (t), c x (t)) = det (t) x (t) y (t) y = x (t)y (t) x (t)y (t), (t) c (t) = (x (t)) 2 + (y (t)) 2. c (t) = 1 1 1.1 I R 1.1.1 c : I R 2 (i) c C (ii) t I c (t) (0, 0) c (t) c(i) c c(t) 1.1.2 (1) (2) (3) (1) r > 0 c : R R 2 : t (r cos t, r sin t) (2) C f : I R c : I R 2 : t (t, f(t)) (3) y = x c : R R 2 : t (t,

More information

Gelfand 3 L 2 () ix M : ϕ(x) ixϕ(x) M : σ(m) = i (λ M) λ (L 2 () ) ( 0 ) L 2 () ϕ, ψ L 2 () ((λ M) ϕ, ψ) ((λ M) ϕ, ψ) = λ ix ϕ(x)ψ(x)dx. λ /(λ ix) ϕ,

Gelfand 3 L 2 () ix M : ϕ(x) ixϕ(x) M : σ(m) = i (λ M) λ (L 2 () ) ( 0 ) L 2 () ϕ, ψ L 2 () ((λ M) ϕ, ψ) ((λ M) ϕ, ψ) = λ ix ϕ(x)ψ(x)dx. λ /(λ ix) ϕ, A spectral theory of linear operators on Gelfand triplets MI (Institute of Mathematics for Industry, Kyushu University) (Hayato CHIBA) chiba@imi.kyushu-u.ac.jp Dec 2, 20 du dt = Tu. (.) u X T X X T 0 X

More information

1 nakayama/print/ Def (Definition ) Thm (Theorem ) Prop (Proposition ) Lem (Lemma ) Cor (Corollary ) 1. (1) A, B (2) ABC

1   nakayama/print/ Def (Definition ) Thm (Theorem ) Prop (Proposition ) Lem (Lemma ) Cor (Corollary ) 1. (1) A, B (2) ABC 1 http://www.gem.aoyama.ac.jp/ nakayama/print/ Def (Definition ) Thm (Theorem ) Prop (Proposition ) Lem (Lemma ) Cor (Corollary ) 1. (1) A, B (2) ABC r 1 A B B C C A (1),(2),, (8) A, B, C A,B,C 2 1 ABC

More information

V(x) m e V 0 cos x π x π V(x) = x < π, x > π V 0 (i) x = 0 (V(x) V 0 (1 x 2 /2)) n n d 2 f dξ 2ξ d f 2 dξ + 2n f = 0 H n (ξ) (ii) H

V(x) m e V 0 cos x π x π V(x) = x < π, x > π V 0 (i) x = 0 (V(x) V 0 (1 x 2 /2)) n n d 2 f dξ 2ξ d f 2 dξ + 2n f = 0 H n (ξ) (ii) H 199 1 1 199 1 1. Vx) m e V cos x π x π Vx) = x < π, x > π V i) x = Vx) V 1 x /)) n n d f dξ ξ d f dξ + n f = H n ξ) ii) H n ξ) = 1) n expξ ) dn dξ n exp ξ )) H n ξ)h m ξ) exp ξ )dξ = π n n!δ n,m x = Vx)

More information

Euler Appendix cos, sin 2π t = 0 kx = 0, 2π x = 0 (wavelength)λ kλ = 2π, k = 2π/λ k (wavenumber) x = 0 ωt = 0, 2π t = 0 (period)t T = 2π/ω ω = 2πν (fr

Euler Appendix cos, sin 2π t = 0 kx = 0, 2π x = 0 (wavelength)λ kλ = 2π, k = 2π/λ k (wavenumber) x = 0 ωt = 0, 2π t = 0 (period)t T = 2π/ω ω = 2πν (fr This manuscript is modified on March 26, 2012 3 : 53 pm [1] 1 ( ) Figure 1: (longitudinal wave) (transverse wave). P 7km S 4km P S P S x t x u(x, t) t = t 0 = 0 f(x) f(x) = u(x, 0) v +x (Fig.2) ( ) δt

More information

n ξ n,i, i = 1,, n S n ξ n,i n 0 R 1,.. σ 1 σ i .10.14.15 0 1 0 1 1 3.14 3.18 3.19 3.14 3.14,. ii 1 1 1.1..................................... 1 1............................... 3 1.3.........................

More information

??

?? ( ) 2014 2014 1/119 = (ISS) ISS ISS ISS iss-clf iss-clf ISS = (ISS) FB 2014 2/119 = (ISS) ISS ISS ISS iss-clf iss-clf ISS R + : 0 K: γ: R + R + K γ γ(0) = 0 K : γ: R + R + K γ K γ(r) (r ) FB K K K K R

More information

QMI_09.dvi

QMI_09.dvi 25 3 19 Erwin Schrödinger 1925 3.1 3.1.1 3.1.2 σ τ 2 2 ux, t) = ux, t) 3.1) 2 x2 ux, t) σ τ 2 u/ 2 m p E E = p2 3.2) E ν ω E = hν = hω. 3.3) k p k = p h. 3.4) 26 3 hω = E = p2 = h2 k 2 ψkx ωt) ψ 3.5) h

More information

QMI_10.dvi

QMI_10.dvi 25 3 19 Erwin Schrödinger 1925 3.1 3.1.1 σ τ x u u x t ux, t) u 3.1 t x P ux, t) Q θ P Q Δx x + Δx Q P ux + Δx, t) Q θ P u+δu x u x σ τ P x) Q x+δx) P Q x 3.1: θ P θ Q P Q equation of motion P τ Q τ σδx

More information

takei.dvi

takei.dvi 0 Newton Leibniz ( ) α1 ( ) αn (1) a α1,...,α n (x) u(x) = f(x) x 1 x n α 1 + +α n m 1957 Hans Lewy Lewy 1970 1 1.1 Example 1.1. (2) d 2 u dx 2 Q(x)u = f(x), u(0) = a, 1 du (0) = b. dx Q(x), f(x) x = 0

More information

Design of highly accurate formulas for numerical integration in weighted Hardy spaces with the aid of potential theory 1 Ken ichiro Tanaka 1 Ω R m F I = F (t) dt (1.1) Ω m m 1 m = 1 1 Newton-Cotes Gauss

More information

211 kotaro@math.titech.ac.jp 1 R *1 n n R n *2 R n = {(x 1,..., x n ) x 1,..., x n R}. R R 2 R 3 R n R n R n D D R n *3 ) (x 1,..., x n ) f(x 1,..., x n ) f D *4 n 2 n = 1 ( ) 1 f D R n f : D R 1.1. (x,

More information

Grushin 2MA16039T

Grushin 2MA16039T Grushin 2MA1639T 3 2 2 R d Borel α i k (x, bi (x, 1 i d, 1 k N d N α R d b α = α(x := (αk(x i 1 i d, 1 k N b = b(x := (b i (x 1 i d X = (X t t x R d dx t = α(x t db t + b(x t dt ( 3 u t = Au + V u, u(,

More information

名称未設定

名称未設定 ! = ( u v w = u i u = u 1 u u 3 u = ( u 1 u = ( u v = u i! 11! 1! 13 % T = $! 1!! 3 ' =! ij #! 31! 3! 33 & 1 0 0%! ij = $ 0 1 0 ' # 0 0 1& # % 1! ijm = $ 1 & % 0 (i, j,m = (1,,3, (, 3,1, (3,1, (i, j,m

More information

II Karel Švadlenka * [1] 1.1* 5 23 m d2 x dt 2 = cdx kx + mg dt. c, g, k, m 1.2* u = au + bv v = cu + dv v u a, b, c, d R

II Karel Švadlenka * [1] 1.1* 5 23 m d2 x dt 2 = cdx kx + mg dt. c, g, k, m 1.2* u = au + bv v = cu + dv v u a, b, c, d R II Karel Švadlenka 2018 5 26 * [1] 1.1* 5 23 m d2 x dt 2 = cdx kx + mg dt. c, g, k, m 1.2* 5 23 1 u = au + bv v = cu + dv v u a, b, c, d R 1.3 14 14 60% 1.4 5 23 a, b R a 2 4b < 0 λ 2 + aλ + b = 0 λ =

More information

1 u t = au (finite difference) u t = au Von Neumann

1 u t = au (finite difference) u t = au Von Neumann 1 u t = au 3 1.1 (finite difference)............................. 3 1.2 u t = au.................................. 3 1.3 Von Neumann............... 5 1.4 Von Neumann............... 6 1.5............................

More information

30

30 3 ............................................2 2...........................................2....................................2.2...................................2.3..............................

More information

W u = u(x, t) u tt = a 2 u xx, a > 0 (1) D := {(x, t) : 0 x l, t 0} u (0, t) = 0, u (l, t) = 0, t 0 (2)

W u = u(x, t) u tt = a 2 u xx, a > 0 (1) D := {(x, t) : 0 x l, t 0} u (0, t) = 0, u (l, t) = 0, t 0 (2) 3 215 4 27 1 1 u u(x, t) u tt a 2 u xx, a > (1) D : {(x, t) : x, t } u (, t), u (, t), t (2) u(x, ) f(x), u(x, ) t 2, x (3) u(x, t) X(x)T (t) u (1) 1 T (t) a 2 T (t) X (x) X(x) α (2) T (t) αa 2 T (t) (4)

More information

II No.01 [n/2] [1]H n (x) H n (x) = ( 1) r n! r!(n 2r)! (2x)n 2r. r=0 [2]H n (x) n,, H n ( x) = ( 1) n H n (x). [3] H n (x) = ( 1) n dn x2 e dx n e x2

II No.01 [n/2] [1]H n (x) H n (x) = ( 1) r n! r!(n 2r)! (2x)n 2r. r=0 [2]H n (x) n,, H n ( x) = ( 1) n H n (x). [3] H n (x) = ( 1) n dn x2 e dx n e x2 II No.1 [n/] [1]H n x) H n x) = 1) r n! r!n r)! x)n r r= []H n x) n,, H n x) = 1) n H n x) [3] H n x) = 1) n dn x e dx n e x [4] H n+1 x) = xh n x) nh n 1 x) ) d dx x H n x) = H n+1 x) d dx H nx) = nh

More information

A 2 3. m S m = {x R m+1 x = 1} U + k = {x S m x k > 0}, U k = {x S m x k < 0}, ϕ ± k (x) = (x 0,..., ˆx k,... x m ) 1. {(U ± k, ϕ± k ) 0 k m} S m 1.2.

A 2 3. m S m = {x R m+1 x = 1} U + k = {x S m x k > 0}, U k = {x S m x k < 0}, ϕ ± k (x) = (x 0,..., ˆx k,... x m ) 1. {(U ± k, ϕ± k ) 0 k m} S m 1.2. A A 1 A 5 A 6 1 2 3 4 5 6 7 1 1.1 1.1 (). Hausdorff M R m M M {U α } U α R m E α ϕ α : U α E α U α U β = ϕ α (ϕ β ϕβ (U α U β )) 1 : ϕ β (U α U β ) ϕ α (U α U β ) C M a m dim M a U α ϕ α {x i, 1 i m} {U,

More information

2 G(k) e ikx = (ik) n x n n! n=0 (k ) ( ) X n = ( i) n n k n G(k) k=0 F (k) ln G(k) = ln e ikx n κ n F (k) = F (k) (ik) n n= n! κ n κ n = ( i) n n k n

2 G(k) e ikx = (ik) n x n n! n=0 (k ) ( ) X n = ( i) n n k n G(k) k=0 F (k) ln G(k) = ln e ikx n κ n F (k) = F (k) (ik) n n= n! κ n κ n = ( i) n n k n . X {x, x 2, x 3,... x n } X X {, 2, 3, 4, 5, 6} X x i P i. 0 P i 2. n P i = 3. P (i ω) = i ω P i P 3 {x, x 2, x 3,... x n } ω P i = 6 X f(x) f(x) X n n f(x i )P i n x n i P i X n 2 G(k) e ikx = (ik) n

More information

SFGÇÃÉXÉyÉNÉgÉãå`.pdf

SFGÇÃÉXÉyÉNÉgÉãå`.pdf SFG 1 SFG SFG I SFG (ω) χ SFG (ω). SFG χ χ SFG (ω) = χ NR e iϕ +. ω ω + iγ SFG φ = ±π/, χ φ = ±π 3 χ SFG χ SFG = χ NR + χ (ω ω ) + Γ + χ NR χ (ω ω ) (ω ω ) + Γ cosϕ χ NR χ Γ (ω ω ) + Γ sinϕ. 3 (θ) 180

More information

II 1 II 2012 II Gauss-Bonnet II

II 1 II 2012 II Gauss-Bonnet II II 1 II 212 II Gauss-Bonnet II 1 1 1.1......................................... 1 1.2............................................ 2 1.3.................................. 3 1.4.............................................

More information

{ 8. { CHAPTER 8. Å (sampling time) x[k] =x(kå) u(ú) t t + Å (u[k]) x[k + 1] =A d x[k] +B d u[k] (8:) (diãerence equation) A d =e AÅ ; B d = Z Å 0 e A

{ 8. { CHAPTER 8. Å (sampling time) x[k] =x(kå) u(ú) t t + Å (u[k]) x[k + 1] =A d x[k] +B d u[k] (8:) (diãerence equation) A d =e AÅ ; B d = Z Å 0 e A Chapter 8 ( _x = Ax +Bu; y = Cx) 8.1 8.1.1 x(t) =e At x(0) + _x =Ax +Bu (8:1) Z t 0 e A(tÄú) Bu(ú)dú u(t) x(0) t x(t) t =kå (k + 1)Å x(t) x[k + 1] =e AÅ x[k] + Z t+å t { 8.1 { e A(t+ÅÄú) Bu(ú)dú (8:) {

More information

Xray.dvi

Xray.dvi 1 X 1 X 1 1.1.............................. 1 1.2.................................. 3 1.3........................ 3 2 4 2.1.................................. 6 2.2 n ( )............. 6 3 7 3.1 ( ).....................

More information

QMII_10.dvi

QMII_10.dvi 65 1 1.1 1.1.1 1.1 H H () = E (), (1.1) H ν () = E ν () ν (). (1.) () () = δ, (1.3) μ () ν () = δ(μ ν). (1.4) E E ν () E () H 1.1: H α(t) = c (t) () + dνc ν (t) ν (), (1.5) H () () + dν ν () ν () = 1 (1.6)

More information

23 7 28 i i 1 1 1.1................................... 2 1.2............................... 3 1.2.1.................................... 3 1.2.2............................... 4 1.2.3 SI..............................

More information

25 7 18 1 1 1.1 v.s............................. 1 1.1.1.................................. 1 1.1.2................................. 1 1.1.3.................................. 3 1.2................... 3

More information

) ] [ h m x + y + + V x) φ = Eφ 1) z E = i h t 13) x << 1) N n n= = N N + 1) 14) N n n= = N N + 1)N + 1) 6 15) N n 3 n= = 1 4 N N + 1) 16) N n 4

) ] [ h m x + y + + V x) φ = Eφ 1) z E = i h t 13) x << 1) N n n= = N N + 1) 14) N n n= = N N + 1)N + 1) 6 15) N n 3 n= = 1 4 N N + 1) 16) N n 4 1. k λ ν ω T v p v g k = π λ ω = πν = π T v p = λν = ω k v g = dω dk 1) ) 3) 4). p = hk = h λ 5) E = hν = hω 6) h = h π 7) h =6.6618 1 34 J sec) hc=197.3 MeV fm = 197.3 kev pm= 197.3 ev nm = 1.97 1 3 ev

More information

Abstract :

Abstract : 17 18 3 : 3604U079- Abstract : 1 3 1.1....................................... 4 1................................... 4 1.3.................................. 4 5.1..................................... 6.................................

More information

9 1. (Ti:Al 2 O 3 ) (DCM) (Cr:Al 2 O 3 ) (Cr:BeAl 2 O 4 ) Ĥ0 ψ n (r) ω n Schrödinger Ĥ 0 ψ n (r) = ω n ψ n (r), (1) ω i ψ (r, t) = [Ĥ0 + Ĥint (

9 1. (Ti:Al 2 O 3 ) (DCM) (Cr:Al 2 O 3 ) (Cr:BeAl 2 O 4 ) Ĥ0 ψ n (r) ω n Schrödinger Ĥ 0 ψ n (r) = ω n ψ n (r), (1) ω i ψ (r, t) = [Ĥ0 + Ĥint ( 9 1. (Ti:Al 2 O 3 ) (DCM) (Cr:Al 2 O 3 ) (Cr:BeAl 2 O 4 ) 2. 2.1 Ĥ ψ n (r) ω n Schrödinger Ĥ ψ n (r) = ω n ψ n (r), (1) ω i ψ (r, t) = [Ĥ + Ĥint (t)] ψ (r, t), (2) Ĥ int (t) = eˆxe cos ωt ˆdE cos ωt, (3)

More information

. (.8.). t + t m ü(t + t) + c u(t + t) + k u(t + t) = f(t + t) () m ü f. () c u k u t + t u Taylor t 3 u(t + t) = u(t) + t! u(t) + ( t)! = u(t) + t u(

. (.8.). t + t m ü(t + t) + c u(t + t) + k u(t + t) = f(t + t) () m ü f. () c u k u t + t u Taylor t 3 u(t + t) = u(t) + t! u(t) + ( t)! = u(t) + t u( 3 8. (.8.)............................................................................................3.............................................4 Nermark β..........................................

More information

No δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i x j δx j (5) δs 2

No δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i x j δx j (5) δs 2 No.2 1 2 2 δs δs = r + δr r = δr (3) δs δs = r r = δr + u(r + δr, t) u(r, t) (4) δr = (δx, δy, δz) u i (r + δr, t) u i (r, t) = u i δx j (5) δs 2 = δx i δx i + 2 u i δx i δx j = δs 2 + 2s ij δx i δx j

More information

ver.1 / c /(13)

ver.1 / c /(13) 1 -- 11 1 c 2010 1/(13) 1 -- 11 -- 1 1--1 1--1--1 2009 3 t R x R n 1 ẋ = f(t, x) f = ( f 1,, f n ) f x(t) = ϕ(x 0, t) x(0) = x 0 n f f t 1--1--2 2009 3 q = (q 1,..., q m ), p = (p 1,..., p m ) x = (q,

More information

(3) (2),,. ( 20) ( s200103) 0.7 x C,, x 2 + y 2 + ax = 0 a.. D,. D, y C, C (x, y) (y 0) C m. (2) D y = y(x) (x ± y 0), (x, y) D, m, m = 1., D. (x 2 y

(3) (2),,. ( 20) ( s200103) 0.7 x C,, x 2 + y 2 + ax = 0 a.. D,. D, y C, C (x, y) (y 0) C m. (2) D y = y(x) (x ± y 0), (x, y) D, m, m = 1., D. (x 2 y [ ] 7 0.1 2 2 + y = t sin t IC ( 9) ( s090101) 0.2 y = d2 y 2, y = x 3 y + y 2 = 0 (2) y + 2y 3y = e 2x 0.3 1 ( y ) = f x C u = y x ( 15) ( s150102) [ ] y/x du x = Cexp f(u) u (2) x y = xey/x ( 16) ( s160101)

More information

Microsoft Word - 信号処理3.doc

Microsoft Word - 信号処理3.doc Junji OHTSUBO 2012 FFT FFT SN sin cos x v ψ(x,t) = f (x vt) (1.1) t=0 (1.1) ψ(x,t) = A 0 cos{k(x vt) + φ} = A 0 cos(kx ωt + φ) (1.2) A 0 v=ω/k φ ω k 1.3 (1.2) (1.2) (1.2) (1.1) 1.1 c c = a + ib, a = Re[c],

More information

Anderson ( ) Anderson / 14

Anderson ( ) Anderson / 14 Anderson 2008 12 ( ) Anderson 2008 12 1 / 14 Anderson ( ) Anderson 2008 12 2 / 14 Anderson P.W.Anderson 1958 ( ) Anderson 2008 12 3 / 14 Anderson tight binding Anderson tight binding Z d u (x) = V i u

More information

Sturm-Liouville Green KEN ZOU Hermite Legendre Laguerre L L [p(x) d2 dx 2 + q(x) d ] dx + r(x) u(x) = Lu(x) = 0 (1) L = p(x) d2 dx

Sturm-Liouville Green KEN ZOU Hermite Legendre Laguerre L L [p(x) d2 dx 2 + q(x) d ] dx + r(x) u(x) = Lu(x) = 0 (1) L = p(x) d2 dx Sturm-Liouville Green KEN ZOU 2006 4 23 1 Hermite Legendre Lguerre 1 1.1 2 L L p(x) d2 2 + q(x) d + r(x) u(x) = Lu(x) = 0 (1) L = p(x) d2 2 + q(x) d + r(x) (2) L = d2 2 p(x) d q(x) + r(x) (3) 2 (Self-Adjoint

More information

untitled

untitled Unit 4. n 1 = n 1 ex[i(k x ωt + δ n )] n 1 : k: k = π/λ δ n : k = kxˆ, δ n = n 1 = n 1 os(k x x ωt) v = ω k k k Re(ω) > Im(ω) > Im(ω) < Im(k) E 1 = E 1 ex[i( k x - ωt)] E 1 : + v g ω ω ω ω = = xˆ + yˆ

More information

H 0 H = H 0 + V (t), V (t) = gµ B S α qb e e iωt i t Ψ(t) = [H 0 + V (t)]ψ(t) Φ(t) Ψ(t) = e ih0t Φ(t) H 0 e ih0t Φ(t) + ie ih0t t Φ(t) = [

H 0 H = H 0 + V (t), V (t) = gµ B S α qb e e iωt i t Ψ(t) = [H 0 + V (t)]ψ(t) Φ(t) Ψ(t) = e ih0t Φ(t) H 0 e ih0t Φ(t) + ie ih0t t Φ(t) = [ 3 3. 3.. H H = H + V (t), V (t) = gµ B α B e e iωt i t Ψ(t) = [H + V (t)]ψ(t) Φ(t) Ψ(t) = e iht Φ(t) H e iht Φ(t) + ie iht t Φ(t) = [H + V (t)]e iht Φ(t) Φ(t) i t Φ(t) = V H(t)Φ(t), V H (t) = e iht V (t)e

More information

Trapezoidal Rule θ = 1/ x n x n 1 t = 1 [f(t n 1, x n 1 ) + f(t n, x n )] (6) 1. dx dt = f(t, x), x(t 0) = x 0 (7) t [t 0, t 1 ] f t [t 0, t 1 ], x x

Trapezoidal Rule θ = 1/ x n x n 1 t = 1 [f(t n 1, x n 1 ) + f(t n, x n )] (6) 1. dx dt = f(t, x), x(t 0) = x 0 (7) t [t 0, t 1 ] f t [t 0, t 1 ], x x University of Hyogo 8 8 1 d x(t) =f(t, x(t)), dt (1) x(t 0 ) =x 0 () t n = t 0 + n t x x n n x n x 0 x i i = 0,..., n 1 x n x(t) 1 1.1 1 1 1 0 θ 1 θ x n x n 1 t = θf(t n 1, x n 1 ) + (1 θ)f(t n, x n )

More information

振動と波動

振動と波動 Report JS0.5 J Simplicity February 4, 2012 1 J Simplicity HOME http://www.jsimplicity.com/ Preface 2 Report 2 Contents I 5 1 6 1.1..................................... 6 1.2 1 1:................ 7 1.3

More information

R C Gunning, Lectures on Riemann Surfaces, Princeton Math Notes, Princeton Univ Press 1966,, (4),,, Gunning, Schwarz Schwarz Schwarz, {z; x}, [z; x] =

R C Gunning, Lectures on Riemann Surfaces, Princeton Math Notes, Princeton Univ Press 1966,, (4),,, Gunning, Schwarz Schwarz Schwarz, {z; x}, [z; x] = Schwarz 1, x z = z(x) {z; x} {z; x} = z z 1 2 z z, = d/dx (1) a 0, b {az; x} = {z; x}, {z + b; x} = {z; x} {1/z; x} = {z; x} (2) ad bc 0 a, b, c, d 2 { az + b cz + d ; x } = {z; x} (3) z(x) = (ax + b)/(cx

More information

xia2.dvi

xia2.dvi Journal of Differential Equations 96 (992), 70-84 Melnikov method and transversal homoclinic points in the restricted three-body problem Zhihong Xia Department of Mathematics, Harvard University Cambridge,

More information

d dt A B C = A B C d dt x = Ax, A 0 B 0 C 0 = mm 0 mm 0 mm AP = PΛ P AP = Λ P A = ΛP P d dt x = P Ax d dt (P x) = Λ(P x) d dt P x =

d dt A B C = A B C d dt x = Ax, A 0 B 0 C 0 = mm 0 mm 0 mm AP = PΛ P AP = Λ P A = ΛP P d dt x = P Ax d dt (P x) = Λ(P x) d dt P x = 3 MATLAB Runge-Kutta Butcher 3. Taylor Taylor y(x 0 + h) = y(x 0 ) + h y (x 0 ) + h! y (x 0 ) + Taylor 3. Euler, Runge-Kutta Adams Implicit Euler, Implicit Runge-Kutta Gear y n+ y n (n+ ) y n+ y n+ y n+

More information

24 I ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x

24 I ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x 24 I 1.1.. ( ) 1. R 3 (i) C : x 2 + y 2 1 = 0 (ii) C : y = ± 1 x 2 ( 1 x 1) (iii) C : x = cos t, y = sin t (0 t 2π) 1.1. γ : [a, b] R n ; t γ(t) = (x 1 (t), x 2 (t),, x n (t)) ( ) ( ), γ : (i) x 1 (t),

More information

all.dvi

all.dvi 29 4 Green-Lagrange,,.,,,,,,.,,,,,,,,,, E, σ, ε σ = Eε,,.. 4.1? l, l 1 (l 1 l) ε ε = l 1 l l (4.1) F l l 1 F 30 4 Green-Lagrange Δz Δδ γ = Δδ (4.2) Δz π/2 φ γ = π 2 φ (4.3) γ tan γ γ,sin γ γ ( π ) γ tan

More information

Introduction to Numerical Analysis of Differential Equations Naoya Enomoto (Kyoto.univ.Dept.Science(math))

Introduction to Numerical Analysis of Differential Equations Naoya Enomoto (Kyoto.univ.Dept.Science(math)) Introduction to Numerical Analysis of Differential Equations Naoya Enomoto (Kyoto.univ.Dept.Science(math)) 2001 1 e-mail:s00x0427@ip.media.kyoto-u.ac.jp 1 1 Van der Pol 1 1 2 2 Bergers 2 KdV 2 1 5 1.1........................................

More information

Shunsuke Kobayashi 1 [6] [11] [7] u t = D 2 u 1 x 2 + f(u, v) + s L u(t, x)dx, L x (0.L), t > 0, Neumann 0 v t = D 2 v 2 + g(u, v), x (0, L), t > 0. x

Shunsuke Kobayashi 1 [6] [11] [7] u t = D 2 u 1 x 2 + f(u, v) + s L u(t, x)dx, L x (0.L), t > 0, Neumann 0 v t = D 2 v 2 + g(u, v), x (0, L), t > 0. x Shunsuke Kobayashi [6] [] [7] u t = D 2 u x 2 + fu, v + s L ut, xdx, L x 0.L, t > 0, Neumann 0 v t = D 2 v 2 + gu, v, x 0, L, t > 0. x2 u u v t, 0 = t, L = 0, x x. v t, 0 = t, L = 0.2 x x ut, x R vt, x

More information

1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0

1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0 1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0 0 < t < τ I II 0 No.2 2 C x y x y > 0 x 0 x > b a dx

More information

1. R n Ω ε G ε 0 Ω ε B n 2 Ωε = with Bu = 0 on Ω ε i=1 x 2 i ε +0 B Bu = u (Dirichlet, D Ω ε ), Bu = u ν (Neumann, N Ω ε ), Ω ε G ( ) / 25

1. R n Ω ε G ε 0 Ω ε B n 2 Ωε = with Bu = 0 on Ω ε i=1 x 2 i ε +0 B Bu = u (Dirichlet, D Ω ε ), Bu = u ν (Neumann, N Ω ε ), Ω ε G ( ) / 25 .. IV 2012 10 4 ( ) 2012 10 4 1 / 25 1. R n Ω ε G ε 0 Ω ε B n 2 Ωε = with Bu = 0 on Ω ε i=1 x 2 i ε +0 B Bu = u (Dirichlet, D Ω ε ), Bu = u ν (Neumann, N Ω ε ), Ω ε G ( ) 2012 10 4 2 / 25 1. Ω ε B ε t

More information

n Y 1 (x),..., Y n (x) 1 W (Y 1 (x),..., Y n (x)) 0 W (Y 1 (x),..., Y n (x)) = Y 1 (x)... Y n (x) Y 1(x)... Y n(x) (x)... Y n (n 1) (x) Y (n 1)

n Y 1 (x),..., Y n (x) 1 W (Y 1 (x),..., Y n (x)) 0 W (Y 1 (x),..., Y n (x)) = Y 1 (x)... Y n (x) Y 1(x)... Y n(x) (x)... Y n (n 1) (x) Y (n 1) D d dx 1 1.1 n d n y a 0 dx n + a d n 1 y 1 dx n 1 +... + a dy n 1 dx + a ny = f(x)...(1) dk y dx k = y (k) a 0 y (n) + a 1 y (n 1) +... + a n 1 y + a n y = f(x)...(2) (2) (2) f(x) 0 a 0 y (n) + a 1 y

More information

Chebyshev Schrödinger Heisenberg H = 1 2m p2 + V (x), m = 1, h = 1 1/36 1 V (x) = { 0 (0 < x < L) (otherwise) ψ n (x) = 2 L sin (n + 1)π x L, n = 0, 1, 2,... Feynman K (a, b; T ) = e i EnT/ h ψ n (a)ψ

More information

Hilbert, von Neuman [1, p.86] kt 2 1 [1, 2] 2 2

Hilbert, von Neuman [1, p.86] kt 2 1 [1, 2] 2 2 hara@math.kyushu-u.ac.jp 1 1 1.1............................................... 2 1.2............................................. 3 2 3 3 5 3.1............................................. 6 3.2...................................

More information

Black-Scholes [1] Nelson [2] Schrödinger 1 Black Scholes [1] Black-Scholes Nelson [2][3][4] Schrödinger Nelson Parisi Wu [5] Nelson Parisi-W

Black-Scholes [1] Nelson [2] Schrödinger 1 Black Scholes [1] Black-Scholes Nelson [2][3][4] Schrödinger Nelson Parisi Wu [5] Nelson Parisi-W 003 7 14 Black-Scholes [1] Nelson [] Schrödinger 1 Black Scholes [1] Black-Scholes Nelson [][3][4] Schrödinger Nelson Parisi Wu [5] Nelson Parisi-Wu Nelson e-mail: takatoshi-tasaki@nifty.com kabutaro@mocha.freemail.ne.jp

More information

main.dvi

main.dvi 3 Discrete Fourie Transform: DFT DFT 3.1 3.1.1 x(n) X(e jω ) X(e jω )= x(n)e jωnt (3.1) n= X(e jω ) N X(k) ωt f 2π f s N X(k) =X(e j2πk/n )= x(n)e j2πnk/n, k N 1 (3.2) n= X(k) δ X(e jω )= X(k)δ(ωT 2πk

More information

[1] 1.1 x(t) t x(t + n ) = x(t) (n = 1,, 3, ) { x(t) : : 1 [ /, /] 1 x(t) = a + a 1 cos πt + a cos 4πt + + a n cos nπt + + b 1 sin πt + b sin 4πt = a

[1] 1.1 x(t) t x(t + n ) = x(t) (n = 1,, 3, ) { x(t) : : 1 [ /, /] 1 x(t) = a + a 1 cos πt + a cos 4πt + + a n cos nπt + + b 1 sin πt + b sin 4πt = a 13/7/1 II ( / A: ) (1) 1 [] (, ) ( ) ( ) ( ) etc. etc. 1. 1 [1] 1.1 x(t) t x(t + n ) = x(t) (n = 1,, 3, ) { x(t) : : 1 [ /, /] 1 x(t) = a + a 1 cos πt + a cos 4πt + + a n cos nπt + + b 1 sin πt + b sin

More information

2 (2016 3Q N) c = o (11) Ax = b A x = c A n I n n n 2n (A I n ) (I n X) A A X A n A A A (1) (2) c 0 c (3) c A A i j n 1 ( 1) i+j A (i, j) A (i, j) ã i

2 (2016 3Q N) c = o (11) Ax = b A x = c A n I n n n 2n (A I n ) (I n X) A A X A n A A A (1) (2) c 0 c (3) c A A i j n 1 ( 1) i+j A (i, j) A (i, j) ã i [ ] (2016 3Q N) a 11 a 1n m n A A = a m1 a mn A a 1 A A = a n (1) A (a i a j, i j ) (2) A (a i ca i, c 0, i ) (3) A (a i a i + ca j, j i, i ) A 1 A 11 0 A 12 0 0 A 1k 0 1 A 22 0 0 A 2k 0 1 0 A 3k 1 A rk

More information

数値計算:常微分方程式

数値計算:常微分方程式 ( ) 1 / 82 1 2 3 4 5 6 ( ) 2 / 82 ( ) 3 / 82 C θ l y m O x mg λ ( ) 4 / 82 θ t C J = ml 2 C mgl sin θ θ C J θ = mgl sin θ = θ ( ) 5 / 82 ω = θ J ω = mgl sin θ ω J = ml 2 θ = ω, ω = g l sin θ = θ ω ( )

More information

,. Black-Scholes u t t, x c u 0 t, x x u t t, x c u t, x x u t t, x + σ x u t, x + rx ut, x rux, t 0 x x,,.,. Step 3, 7,,, Step 6., Step 4,. Step 5,,.

,. Black-Scholes u t t, x c u 0 t, x x u t t, x c u t, x x u t t, x + σ x u t, x + rx ut, x rux, t 0 x x,,.,. Step 3, 7,,, Step 6., Step 4,. Step 5,,. 9 α ν β Ξ ξ Γ γ o δ Π π ε ρ ζ Σ σ η τ Θ θ Υ υ ι Φ φ κ χ Λ λ Ψ ψ µ Ω ω Def, Prop, Th, Lem, Note, Remark, Ex,, Proof, R, N, Q, C [a, b {x R : a x b} : a, b {x R : a < x < b} : [a, b {x R : a x < b} : a,

More information

第5章 偏微分方程式の境界値問題

第5章 偏微分方程式の境界値問題 October 5, 2018 1 / 113 4 ( ) 2 / 113 Poisson 5.1 Poisson ( A.7.1) Poisson Poisson 1 (A.6 ) Γ p p N u D Γ D b 5.1.1: = Γ D Γ N 3 / 113 Poisson 5.1.1 d {2, 3} Lipschitz (A.5 ) Γ D Γ N = \ Γ D Γ p Γ N Γ

More information

(time series) ( 225 ) / / p.2/66

(time series) ( 225 ) / / p.2/66 338 857 255 Tel : 48 858 3577, Fax : 48 858 3716 Email : tohru@ics.saitama-u.ac.jp URL : http://www.nls.ics.saitama-u.ac.jp/ tohru / / p.1/66 (time series) ( 225 ) / / p.2/66 / / p.3/66 ?? / / p.3/66 1.9.8.7.6???.5.4.3.2.1

More information

RIMS Kôkyûroku Bessatsu B3 (22), Numerical verification methods for differential equations: Computer-assisted proofs based on infinite dimension

RIMS Kôkyûroku Bessatsu B3 (22), Numerical verification methods for differential equations: Computer-assisted proofs based on infinite dimension 微分方程式の精度保証付き数値計算 : 逐次反復に基づく Title計算機援用証明 (Progress in Mathematics of Systems) Author(s) 渡部, 善隆 Citation 数理解析研究所講究録別冊 = RIMS Kokyuroku Bessa (22), B3: 45-55 Issue Date 22-4 URL http://hdl.handle.net/2433/9624

More information

(Bessel) (Legendre).. (Hankel). (Laplace) V = (x, y, z) n (r, θ, ϕ) r n f n (θ, ϕ). f n (θ, ϕ) n f n (θ, ϕ) z = cos θ z θ ϕ n ν. P ν (z), Q ν (z) (Fou

(Bessel) (Legendre).. (Hankel). (Laplace) V = (x, y, z) n (r, θ, ϕ) r n f n (θ, ϕ). f n (θ, ϕ) n f n (θ, ϕ) z = cos θ z θ ϕ n ν. P ν (z), Q ν (z) (Fou (Bessel) (Legendre).. (Hankel). (Laplace) V = (x, y, z) n (r, θ, ϕ) r n f n (θ, ϕ). f n (θ, ϕ) n f n (θ, ϕ) z = cos θ z θ ϕ n ν. P ν (z), Q ν (z) (Fourier) (Fourier Bessel).. V ρ(x, y, z) V = 4πGρ G :.

More information

2D-RCWA 1 two dimensional rigorous coupled wave analysis [1, 2] 1 ε(x, y) = 1 ε(x, y) = ϵ mn exp [+j(mk x x + nk y y)] (1) m,n= m,n= ξ mn exp [+j(mk x

2D-RCWA 1 two dimensional rigorous coupled wave analysis [1, 2] 1 ε(x, y) = 1 ε(x, y) = ϵ mn exp [+j(mk x x + nk y y)] (1) m,n= m,n= ξ mn exp [+j(mk x 2D-RCWA two dimensional rigoros copled wave analsis, 2] εx, εx, ϵ mn exp +jmk x x + nk ] m,n m,n ξ mn exp +jmk x x + nk ] 2 K x K x Λ x Λ ϵ mn ξ mn K x 2π Λ x K 2π Λ ϵ mn ξ mn Λ x Λ x Λ x Λ x Λx Λ Λx Λ

More information

01.Œk’ì/“²fi¡*

01.Œk’ì/“²fi¡* AIC AIC y n r n = logy n = logy n logy n ARCHEngle r n = σ n w n logσ n 2 = α + β w n 2 () r n = σ n w n logσ n 2 = α + β logσ n 2 + v n (2) w n r n logr n 2 = logσ n 2 + logw n 2 logσ n 2 = α +β logσ

More information

ランダムウォークの境界条件・偏微分方程式の数値計算

ランダムウォークの境界条件・偏微分方程式の数値計算 B L06(2018-05-22 Tue) : Time-stamp: 2018-05-22 Tue 21:53 JST hig,, 2, multiply transf http://hig3.net L06 B(2018) 1 / 38 L05-Q1 Quiz : 1 M λ 1 = 1 u 1 ( ). M u 1 = u 1, u 1 = ( 3 4 ) s (s 0)., u 1 = 1

More information

IPSJ SIG Technical Report Vol.2011-HPC-131 No /10/6 1 1 Parareal-in-Time Applicability of Time-domain Parallelism to Iterative Linear Calculus T

IPSJ SIG Technical Report Vol.2011-HPC-131 No /10/6 1 1 Parareal-in-Time Applicability of Time-domain Parallelism to Iterative Linear Calculus T 1 1 Parareal-in-Time Applicability of Time-domain Parallelism to Iterative Linear Calculus Toshiya Taami 1 and Aira Nishida 1 The time-domain parallelism, nown as Parareal-in-Time algorithm, has been applied

More information

Date Wed, 20 Jun (JST) From Kuroki Gen Message-Id Subject Part 4

Date Wed, 20 Jun (JST) From Kuroki Gen Message-Id Subject Part 4 Part 4 2001 6 20 1 2 2 generator 3 3 L 7 4 Manin triple 8 5 KP Hamiltonian 10 6 n-component KP 12 7 nonlinear Schrödinger Hamiltonian 13 http//wwwmathtohokuacjp/ kuroki/hyogen/soliton-4txt TEX 2002 1 17

More information

ma22-9 u ( v w) = u v w sin θê = v w sin θ u cos φ = = 2.3 ( a b) ( c d) = ( a c)( b d) ( a d)( b c) ( a b) ( c d) = (a 2 b 3 a 3 b 2 )(c 2 d 3 c 3 d

ma22-9 u ( v w) = u v w sin θê = v w sin θ u cos φ = = 2.3 ( a b) ( c d) = ( a c)( b d) ( a d)( b c) ( a b) ( c d) = (a 2 b 3 a 3 b 2 )(c 2 d 3 c 3 d A 2. x F (t) =f sin ωt x(0) = ẋ(0) = 0 ω θ sin θ θ 3! θ3 v = f mω cos ωt x = f mω (t sin ωt) ω t 0 = f ( cos ωt) mω x ma2-2 t ω x f (t mω ω (ωt ) 6 (ωt)3 = f 6m ωt3 2.2 u ( v w) = v ( w u) = w ( u v) ma22-9

More information

Untitled

Untitled II 14 14-7-8 8/4 II (http://www.damp.tottori-u.ac.jp/~ooshida/edu/fluid/) [ (3.4)] Navier Stokes [ 6/ ] Navier Stokes 3 [ ] Reynolds [ (4.6), (45.8)] [ p.186] Navier Stokes I 1 balance law t (ρv i )+ j

More information

ssp2_fixed.dvi

ssp2_fixed.dvi 13 12 30 2 1 3 1.1... 3 1.2... 4 1.3 Bravais... 4 1.4 Miller... 4 2 X 5 2.1 Bragg... 5 2.2... 5 2.3... 7 3 Brillouin 13 3.1... 13 3.2 Brillouin... 13 3.3 Brillouin... 14 3.4 Bloch... 16 3.5 Bloch... 17

More information

: u i = (2) x i Smagorinsky τ ij τ [3] ij u i u j u i u j = 2ν SGS S ij, (3) ν SGS = (C s ) 2 S (4) x i a u i ρ p P T u ν τ ij S c ν SGS S csgs

: u i = (2) x i Smagorinsky τ ij τ [3] ij u i u j u i u j = 2ν SGS S ij, (3) ν SGS = (C s ) 2 S (4) x i a u i ρ p P T u ν τ ij S c ν SGS S csgs 15 C11-4 Numerical analysis of flame propagation in a combustor of an aircraft gas turbine, 4-6-1 E-mail: tominaga@icebeer.iis.u-tokyo.ac.jp, 2-11-16 E-mail: ntani@iis.u-tokyo.ac.jp, 4-6-1 E-mail: itoh@icebeer.iis.u-tokyo.ac.jp,

More information

2014 3 10 5 1 5 1.1..................................... 5 2 6 2.1.................................... 6 2.2 Z........................................ 6 2.3.................................. 6 2.3.1..................

More information