(1) (François Viète : ) 1593 (Eectionum Geometricarum Canonica Recensio) 2 ( 1 p.372 pp ) 3 A D BAC CD CE DE BC F B A F C BF F D F C (

Similar documents
14 : n (1) n a n a n (2) a n n (1) 1 (n 1) a n 1 2 (n 2) a n 2 2 n 3 a n = a n 1 + a n 2 a 1 = 1 a 2 = 2 (2) a n = a n 1 + a n 2 ( ) ( a n = 1 1

1 1 (metamathematics) ( ) ( ) ( ) a b = c d = e f a b = c d = e f = pa + qc pb + qd = pa + qc + re pb + qd + rf a b = c d = e f = k ( 0) a = bk c = dk

1/68 A. 電気所 ( 発電所, 変電所, 配電塔 ) における変圧器の空き容量一覧 平成 31 年 3 月 6 日現在 < 留意事項 > (1) 空容量は目安であり 系統接続の前には 接続検討のお申込みによる詳細検討が必要となります その結果 空容量が変更となる場合があります (2) 特に記載


2012 A, N, Z, Q, R, C


1990 IMO 1990/1/15 1:00-4:00 1 N N N 1, N 1 N 2, N 2 N 3 N 3 2 x x + 52 = 3 x x , A, B, C 3,, A B, C 2,,,, 7, A, B, C

( )

CRA3689A

熊本県数学問題正解

さくらの個別指導 ( さくら教育研究所 ) A 2 P Q 3 R S T R S T P Q ( ) ( ) m n m n m n n n

x, y x 3 y xy 3 x 2 y + xy 2 x 3 + y 3 = x 3 y xy 3 x 2 y + xy 2 x 3 + y 3 = 15 xy (x y) (x + y) xy (x y) (x y) ( x 2 + xy + y 2) = 15 (x y)

HITACHI 液晶プロジェクター CP-AX3505J/CP-AW3005J 取扱説明書 -詳細版- 【技術情報編】

取扱説明書 -詳細版- 液晶プロジェクター CP-AW3019WNJ

(1.2) T D = 0 T = D = 30 kn 1.2 (1.4) 2F W = 0 F = W/2 = 300 kn/2 = 150 kn 1.3 (1.9) R = W 1 + W 2 = = 1100 N. (1.9) W 2 b W 1 a = 0

空き容量一覧表(154kV以上)


2/8 一次二次当該 42 AX 変圧器 なし 43 AY 変圧器 なし 44 BA 変圧器 なし 45 BB 変圧器 なし 46 BC 変圧器 なし

HITACHI 液晶プロジェクター CP-EX301NJ/CP-EW301NJ 取扱説明書 -詳細版- 【技術情報編】 日本語

1. 2 P 2 (x, y) 2 x y (0, 0) R 2 = {(x, y) x, y R} x, y R P = (x, y) O = (0, 0) OP ( ) OP x x, y y ( ) x v = y ( ) x 2 1 v = P = (x, y) y ( x y ) 2 (x

6kg 1.1m 1.m.1m.1 l λ ϵ λ l + λ l l l dl dl + dλ ϵ dλ dl dl + dλ dl dl 3 1. JIS 1 6kg 1% 66kg 1 13 σ a1 σ m σ a1 σ m σ m σ a1 f f σ a1 σ a1 σ m f 4

2001 Mg-Zn-Y LPSO(Long Period Stacking Order) Mg,,,. LPSO ( ), Mg, Zn,Y. Mg Zn, Y fcc( ) L1 2. LPSO Mg,., Mg L1 2, Zn,Y,, Y.,, Zn, Y Mg. Zn,Y., 926, 1

D 24 D D D

I II

IMO 1 n, 21n n (x + 2x 1) + (x 2x 1) = A, x, (a) A = 2, (b) A = 1, (c) A = 2?, 3 a, b, c cos x a cos 2 x + b cos x + c = 0 cos 2x a

?


欧州特許庁米国特許商標庁との共通特許分類 CPC (Cooperative Patent Classification) 日本パテントデータサービス ( 株 ) 国際部 2019 年 1 月 17 日 CPC 版のプレ リリースが公開されました 原文及び詳細はCPCホームページの C

1 1 H Li Be Na M g B A l C S i N P O S F He N Cl A e K Ca S c T i V C Mn Fe Co Ni Cu Zn Ga Ge As Se B K Rb S Y Z Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb T e

newmain.dvi

1/1 lim f(x, y) (x,y) (a,b) ( ) ( ) lim limf(x, y) lim lim f(x, y) x a y b y b x a ( ) ( ) xy x lim lim lim lim x y x y x + y y x x + y x x lim x x 1

(2018 2Q C) [ ] R 2 2 P = (a, b), Q = (c, d) Q P QP = ( ) a c b d (a c, b d) P = (a, b) O P ( ) a p = b P = (a, b) p = ( ) a b R 2 {( ) } R 2 x = x, y

(2016 2Q H) [ ] R 2 2 P = (a, b), Q = (c, d) Q P QP = ( ) a c b d (a c, b d) P = (a, b) O P ( ) a p = b P = (a, b) p = ( ) a b R 2 {( ) } R 2 x = x, y

04年度LS民法Ⅰ教材改訂版.PDF

29

untitled

.3. (x, x = (, u = = 4 (, x x = 4 x, x 0 x = 0 x = 4 x.4. ( z + z = 8 z, z 0 (z, z = (0, 8, (,, (8, 0 3 (0, 8, (,, (8, 0 z = z 4 z (g f(x = g(

Solutions to Quiz 1 (April 20, 2007) 1. P, Q, R (P Q) R Q (P R) P Q R (P Q) R Q (P R) X T T T T T T T T T T F T F F F T T F T F T T T T T F F F T T F

PROSTAGE[プロステージ]

) Euclid Eukleides : EÎkleÐdhc) : 300 ) StoiqeÐwsic) p.4647) ΑΒΓ ΒΑΓ ΓΑ Β ΒΓ ΑΓ ΓΑ Α G G G G G G G G G G G G G G G G ΑΒΓ ΒΑΓ = θ ΒΓ = a ΑΓ = b = c Α =


‚å™J‚å−w“LŁñfi~P01†`08

, = = 7 6 = 42, =

x = a 1 f (a r, a + r) f(a) r a f f(a) 2 2. (a, b) 2 f (a, b) r f(a, b) r (a, b) f f(a, b)


学習の手順

x V x x V x, x V x = x + = x +(x+x )=(x +x)+x = +x = x x = x x = x =x =(+)x =x +x = x +x x = x ( )x = x =x =(+( ))x =x +( )x = x +( )x ( )x = x x x R

r 1 m A r/m i) t ii) m i) t B(t; m) ( B(t; m) = A 1 + r ) mt m ii) B(t; m) ( B(t; m) = A 1 + r ) mt m { ( = A 1 + r ) m } rt r m n = m r m n B

linearal1.dvi

欧州特許庁米国特許商標庁との共通特許分類 CPC (Cooperative Patent Classification) 日本パテントデータサービス ( 株 ) 国際部 2019 年 7 月 31 日 CPC 版が発効します 原文及び詳細はCPCホームページのCPC Revision

() () () () () 175 () Tel Fax

R R 16 ( 3 )

x x x 2, A 4 2 Ax.4 A A A A λ λ 4 λ 2 A λe λ λ2 5λ + 6 0,...λ 2, λ 2 3 E 0 E 0 p p Ap λp λ 2 p 4 2 p p 2 p { 4p 2 2p p + 2 p, p 2 λ {

高校生の就職への数学II

PSCHG000.PS

名古屋工業大の数学 2000 年 ~2015 年 大学入試数学動画解説サイト

2 (1) a = ( 2, 2), b = (1, 2), c = (4, 4) c = l a + k b l, k (2) a = (3, 5) (1) (4, 4) = l( 2, 2) + k(1, 2), (4, 4) = ( 2l + k, 2l 2k) 2l + k = 4, 2l

さくらの個別指導 ( さくら教育研究所 ) 1 φ = φ 1 : φ [ ] a [ ] 1 a : b a b b(a + b) b a 2 a 2 = b(a + b). b 2 ( a b ) 2 = a b a/b X 2 X 1 = 0 a/b > 0 2 a

dynamics-solution2.dvi

6. Euler x

入試の軌跡

I. (CREMONA ) : Cremona [C],., modular form f E f. 1., modular X H 1 (X, Q). modular symbol M-symbol, ( ) modular symbol., notation. H = { z = x

1 Abstract 2 3 n a ax 2 + bx + c = 0 (a 0) (1) ( x + b ) 2 = b2 4ac 2a 4a 2 D = b 2 4ac > 0 (1) 2 D = 0 D < 0 x + b 2a = ± b2 4ac 2a b ± b 2

x () g(x) = f(t) dt f(x), F (x) 3x () g(x) g (x) f(x), F (x) (3) h(x) = x 3x tf(t) dt.9 = {(x, y) ; x, y, x + y } f(x, y) = xy( x y). h (x) f(x), F (x

(1) θ a = 5(cm) θ c = 4(cm) b = 3(cm) (2) ABC A A BC AD 10cm BC B D C 99 (1) A B 10m O AOB 37 sin 37 = cos 37 = tan 37

03J_sources.key


( ( 3 ( ( 6 (

A B 5 C mm, 89 mm 7/89 = 3.4. π 3 6 π 6 6 = 6 π > 6, π > 3 : π > 3

L

0 1

(, Goo Ishikawa, Go-o Ishikawa) ( ) 1

<93FA97A AC C837288EA97972E786C7378>

行列代数2010A

1 No.1 5 C 1 I III F 1 F 2 F 1 F 2 2 Φ 2 (t) = Φ 1 (t) Φ 1 (t t). = Φ 1(t) t = ( 1.5e 0.5t 2.4e 4t 2e 10t ) τ < 0 t > τ Φ 2 (t) < 0 lim t Φ 2 (t) = 0

.5 z = a + b + c n.6 = a sin t y = b cos t dy d a e e b e + e c e e e + e 3 s36 3 a + y = a, b > b 3 s363.7 y = + 3 y = + 3 s364.8 cos a 3 s365.9 y =,

1 1 n 0, 1, 2,, n n 2 a, b a n b n a, b n a b (mod n) 1 1. n = (mod 10) 2. n = (mod 9) n II Z n := {0, 1, 2,, n 1} 1.

untitled

1: *2 W, L 2 1 (WWL) 4 5 (WWL) W (WWL) L W (WWL) L L 1 2, 1 4, , 1 4 (cf. [4]) 2: 2 3 * , , = , 1

Part () () Γ Part ,

O E ( ) A a A A(a) O ( ) (1) O O () 467

18 ( ) I II III A B C(100 ) 1, 2, 3, 5 I II A B (100 ) 1, 2, 3 I II A B (80 ) 6 8 I II III A B C(80 ) 1 n (1 + x) n (1) n C 1 + n C


I ( ) 1 de Broglie 1 (de Broglie) p λ k h Planck ( Js) p = h λ = k (1) h 2π : Dirac k B Boltzmann ( J/K) T U = 3 2 k BT


Z: Q: R: C:

0.6 A = ( 0 ),. () A. () x n+ = x n+ + x n (n ) {x n }, x, x., (x, x ) = (0, ) e, (x, x ) = (, 0) e, {x n }, T, e, e T A. (3) A n {x n }, (x, x ) = (,

,. Black-Scholes u t t, x c u 0 t, x x u t t, x c u t, x x u t t, x + σ x u t, x + rx ut, x rux, t 0 x x,,.,. Step 3, 7,,, Step 6., Step 4,. Step 5,,.

42 3 u = (37) MeV/c 2 (3.4) [1] u amu m p m n [1] m H [2] m p = (4) MeV/c 2 = (13) u m n = (4) MeV/c 2 =

LCM,GCD LCM GCD..,.. 1 LCM GCD a b a b. a divides b. a b. a, b :, CD(a, b) = {d a, b }, CM(a, b) = {m a, b }... CM(a, b). q > 0, m 1, m 2 CM

DVIOUT-HYOU

untitled

LINEAR ALGEBRA I Hiroshi SUZUKI Department of Mathematics International Christian University

untitled

MS-1J/MS-1WJ(形名:MS-1/MS-1W)取扱説明書 - 詳細- 技術情報編

II 2 II

Microsoft Word - 里山ガイドライン.doc

I, II 1, A = A 4 : 6 = max{ A, } A A 10 10%

2 (2016 3Q N) c = o (11) Ax = b A x = c A n I n n n 2n (A I n ) (I n X) A A X A n A A A (1) (2) c 0 c (3) c A A i j n 1 ( 1) i+j A (i, j) A (i, j) ã i

SB-80DX SB-80DX (Jp) Jp

Transcription:

12 (Euclid (Eukleides : EÎkleÐdhc) : 300 ) (StoiqeÐwsic) ( ) 2 ( ) 2 16 3 17 18 (Introductio in Analysin Innitorum : 1748 ) 120 1

(1) (François Viète : 15401603) 1593 (Eectionum Geometricarum Canonica Recensio) 2 ( 1 p.372 pp.377-378) 3 A D BAC CD CE DE BC F B A F C BF F D F C ( 3) E AB = r AF = x BF = r + x F D = r 2 x 2 F C = r x BF F C = F D 2 BF : F D = F D : F C CD CE BC DE ADF 3 D F D 3 GF GF F D GF A B C G A F A AD AG AF B C F D BF F C AF AG AC AB BF F C AB AC AG AF BG F C GF BF BG F C ( 12) 3 x : y = y : x = d F D = y ( ) 2 d r = y 2 + x = BF = r + d 2 2 = ( ) 2 d y 2 + + d 2 2 = F C = r d ( ) 2 d 2 = y 2 + d 2 2 x = y 2 x 2

(2) (René Descartes : 15961650) 1637 ( ) (Discours de la méthode. Pour bien conduire sa raison, & chercher la verité dans les sciences) 3 (La Dioptrique) (Les Meteores) (La Géomètrie) 3 ( 1 ) ( 2 pp.35) 4 5 2 2 4 2 4 1 2 AB BD BC A C CA DE BE ( ) BE BD E D DE AC BC I E C D A B F G K H GH FG FH K K FIH G FH I GI ( ) 3

BD GH a b a + b a b a b ab a b a b a aa a2 a a 3 a 2 + b 2 a 2 + b 2 a 3 b 3 + abb C.a 3 b 3 + abb a 2, b 3 a 3 C.a3 b 3 + abb abb b 3 aabb b aabb 1 b 2 AB 1 AB 1 GH a BD b ( ) 1 ( ) ( ) a 2 a 3 4

x y ( ) 2 2 ( 2 pp.1820) 1 2 1 2 1 2 3 4 2 5 6 3 GL CNKL KN C EC CNKL KL BA GL G L CNKL AB EC AB A 1 C 1 C GA CB CB BA y x GA a KL b GA NL c NL LK c b CB y BK BK b c y G N C E K L B A 5

BL b c y b AL x + b y b CB LB c y b c y c a GA LA x + b y b 2 c 3 ab c y ab 1 xy + b yy by c yy cy c xy + ay ac b EC 1 CNKL CNK 1 GL EC 2 CNK L 1 KB (PĹppoc (Pappos) : 320 )) 5 2 1 3 4 2 5 6 3 y 2 = cy c xy + ay ac b C AB = x BC = y A ( AK x AG y ) C (x y) 2 2 y C F H I D G A B H E I x F 2 AB CDE CDE E D AB CD C HCI HCI (y a) 2 (x 2 +y 2 ) = b 2 y 2 DE = a CD = b 6

1 ( 2 p.5) 2 1 ( 2 p.10) (>Apollÿnioc (Apollonius) : 262 200?) 3 4 1 1 3 2 3 4 2 5 3 2 ( 2 pp.1213) AB AD EF GH C 1 CBG CDA CFE CHG CB CD CF CH 1 7

T S R E A B G H F C D AB CB AB A B x BC y 2 (2 ) AB A E G BC R S T ARB AB BR b AB x RB bx B C R CR y + bx R C B CR y bx C B R CR y + bx DRC CR CD c CR y + bx CD cy + bcx AB AD EF A E k EB k + x B E A k x E A B k + x ESB BE BS dk + dx y + dk + dx d BS CS y dk dx S B C C B S y + dk + dx FSC CS CF e CF ey + dek + dex AG l BG l x BGT BG BT fl gx y + fl fx f BT CT TCH TC CH g +gy + fgl fgx CH C 3 8

(3) (Pierre de Fermat : 16011665) (Ad locos planos et solidos isagoge : 1629 ) ( 6 p.128) 2 1 ( ) 1 (locus linearis) 2 2 1 2 ( 6 pp.128129) NZM N I NZ x NZI ZI y y dx = by I b : d = x : y x y NIZ N x Z M INZ N NZ NI 1 1 2 2 ( 6 pp.129130) R I O y N x Z M 2 xy = k 2 I NR ZI NZ M MO ZI NMO ( ) k 2 O NR NM 9

xy NZI NMO I x y xy d 2 + xy = rx + sy k 2 + xy = rx + sy X = x s Y = r y XY = k 2 rs x 2 = y 2 ( y = x ) x 2 = dy y 2 = dx b 2 x 2 = dy b 2 + x 2 = dy b 2 2dx x 2 = y 2 + 2ry b 2 x 2 = ky 2 x 2 + b 2 = ky 2 (x 2 + b 2 ) : y 2 x 2 + b 2 = ky 2 NO ZI b 2 : NR 2 O R N M R R RO N NZ x MR RO RO 2 OI 2 NR 2 : b 2 I y Z MR RO+RO 2 = RO (MR+RO) = RO MO (MR RO + RO 2 ) : OI 2 = NR 2 : b 2 MO OR : OI 2 = NR 2 : b 2 (MO OR + NR 2 ) : (OI 2 + b 2 ) = NR 2 : b 2 MN = NR MO = MR + RO = NR + NR + RO = NR + NO MO OR + NR 2 = (NR + NO) OR + NR 2 = NR OR + NO OR + NR NR = NR (OR + NR) + NO OR = NR NO + NO OR = NO (NR + OR) = NO NO = NO 2 = ZI 2 = y 2 OI 2 + b 2 = NZ 2 + b 2 = x 2 + b 2 y 2 : (x 2 + b 2 ) = NR 2 : b 2 NR 2 : b 2 (OI 2 + b 2 ) : (MO OR + NR 2 ) (x 2 + b 2 ) : y 2 I 10

( 3 pp.102103) 1 1 1 V 2 N M R IN IM IN IM INM O I NM = b ZI e N Z M NZ a 2a 2 + b 2 2ba + 2e 2 be NM Z 2 2 Z ZV ZV 4 NM VZ VOZ ZO ZM VO V VO OIR R RN RM RN RM RNM NM = b ZI = e NZ = MZ = a IN 2 = a 2 + e 2 IM 2 = (b a) 2 + e 2 (2a 2 + b 2 2ba + 2e 2 ) : be k : 1 4ZV : NM = k : 1 ZV = 1 bk ( ) 4 2 1 VO 2 = VZ 2 ZO 2 = 4 bk a 2 = 1 16 b2 k 2 a 2 V VO NM x ZI y ( x 2 + y 1 ) 2 4 bk = 1 16 b2 k 2 a 2 R (x y) x 2 + y 2 1 2 bky + 1 16 b2 k 2 = 1 16 b2 k 2 a 2 x 2 + y 2 = 1 2 bky a2 11

RN 2 + RM 2 = { (x a) 2 + y 2} + { (x + a) 2 + y 2} = 2x 2 + 2y 2 + 2a 2 ( ) 1 RN 2 + RM 2 = 2 bky a2 + 2a 2 = bky 2 RNM by ( RN 2 + RM 2) : RNM = bky : by = k : 1 ( 6 p.130) 2 (Tìpoi âpðpedoi : De Locis Planis) 2 (Apolloni Pergaei libri duo de locis planis restituti) 2 2 2 2 (Conics) 1 11 12 13 P J L X O B Z R E A M N H D K S G LZ ZH ZJ ( 8 pp.316317 7 p.53) latus rectum ( ) M DE ( BG) NM (linea ordinatim applicata : linea ordinata) ZH ZN (linea abscissa ) 2 2 (lineae coordinatae) (Gottfried Wilhelm Leibni : 16461716) 1692 12

(4) (Leonhard Euler : 17071783) x A AP ( 5 p.1) x y P PM ( 2 1 ) 1 RS 2 x RS x RS P A AP x = 0 P A AP x AP x RS A P AP x = AP P A ( 5 p.2 p.3 p.5 p.6) 4 x x y x x y x RAS x AP y PM AP B M R p P E A P D S m M 6 x y 12 AP x AP = x y PM = y 13

y y x 14 2 x y x A y RS x AB y y x x y = 0 ( 5 p.37) 67 x y y = 0 y = 0 x x x ( ) 1 0 = α + βx + γy 2 0 = α + βx + γy + δxx + εxy + ζyy 1 F. Viète(transl. by T. R. Witmer) The Analytic Art Dover 2006 2 R. ( ) ( 1 ) 1973 ( 48) 3 P. Tannery and C. Henry(ed.) uvres de Fermat Gauthier-Villars et Fils 1891 4 D. E. Smith A Source Book in Mathematics Dover 1959 5 L. ( ) 2005 ( 17) 6 ( 236) 1971 ( 46) 7 1980 ( 55) 8 I. Thomas(transl.) Greek Mathematical Works II Harvard U. P.(Loeb Classical Library) 2005 (1941) 9 1999 ( 11) 10 ( 18) 1978 ( 53) 11 2 2004 ( 16) 14