positron 1930 Dirac 1933 Anderson m 22Na(hl=2.6years), 58Co(hl=71days), 64Cu(hl=12hour) 68Ge(hl=288days) MeV : thermalization m psec 100

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1 positron 1930 Dirac 1933 Anderson m 22Na(hl=2.6years), 58Co(hl=71days), 64Cu(hl=12hour) 68Ge(hl=288days) MeV : thermalization m psec 100psec nsec E total = 2mc 2 + E e + + E e Ee+ Ee-c mc mc 0.511MeV - (0 ) 1

2 Positron annihilation lifetime measurement Doppler broadning - - Anguler correlation of annihilation radiation 2 e γ γ

3 Hartree-Fock-Slater ψ- [ 2 + V( r) ]ψ ( r) = E ψ ( r) (1) ψ+ [ 2 + V( r) ]ψ + ( r) = E + ψ + ( r) (2) ( p 1,p 2 ) ψ p1 ( r) = exp ir p 1 ψ p2 ( r) = exp ir p 2 (3) (h ) { } Γ( p)d 3 p d 3 rψ ( r)ψ + ( r)exp ir p 1 + p 2 M.J.Puska (LDA) LDA (Vc : Coulomb part) (Vcorr : correlation part) = V c ( r) + V corr n ( r) V r 2 d 3 p (4) [ ] (5) d

4 V c ( r) = i 2Z 2 r i ρ( t)dt 2 r i r 0 i r i ρ( t) dt t Z ri i t t t dt r(t) (2) Schrödinger Kimball and Shortley method (6)(5) n ε ( n) = i 1 n ψ h 2 + ( n) ψ + r i k i r k 6ψ + n 2 ( n) ψ + r i r i + V r n ( i)ψ + n+1 ( n +1) ψ + r i = k 6 + h 2 V r i 2 r i (6) (7) ( n) ψ + ( r k ) ( ε ( n) ) (8) λ = σ drn + [ ( ) + n c ( r)γ c + n d ( r)γ d ] (9) ( r) n v ( r)γ v n v r c r 0 σ = πr o 2 c R F (10)

5 nv nc d nd Γ(enhancement factor)(8) n + ( r) = ψ + ( r) 2 (11) σ ( 2) > σ ( 3) > σ ( 1) σ ( 3) σ ( 2) = 4( π 2 9) α 3π =1/372 α = e 2 /h 2 c =1/137

6 σ ( 2) = πr 2 Bc v φ = vn e λ = σ ( 2) φ λ = πr B 2 cn e τ = 1 λ 500 Positron lifetime (ps) Fe Mo Al Ni Number of vacancies Two State Trapping Model v f

7 n f ( t) = n 0 exp( λt) (19) nf t n n sec dn f dt = λ f n f κ v n f +κ v n v (20) dn v dt = λ vn v +κ v n f κ v n v (21) nf nv f v v v (20) (21)i Nf i Ni (20) (21) dn f dt dn i dt N = λ f N f κ i N f + κ i N i N i =1 N i=1 = λ i N i + κ i N f κ i N i i =1 N i =1 Ni(0)=0 Nf(0)=N0 Nf, Ni N f = N 0 exp λ 0 t κ i N i = N 0 λ 0 λ i λ 0 = λ f + κ i [ exp( λ i t) exp( λ 0 t) ] (22) (23) (24) T(t) (25)

8 T = λ 0 N f + N i = 2 λ i N i = N 0 λ 0 exp λ 0 t + N i =2 λ i κ i { exp( λ λ 0 λ i t) exp( λ 0 t )} i (26) τ 1 =1 λ f + I i = ( κ i ) τ n =1 λ n (27) κ i λ 0 λ i I 1 = 1 N i= 2 κ i λ 0 λ i τ = n i =1 τ i I i (28) (29) 1 1 (28) κ v I 2 = 1 τ 1 1 τ 2 (30) (24) τ 1 cal (31) =1 λ = 1 λ f +κ v = τ f 1 +τ f κ v (30), (31) v τ 1 cal = 1 I 2 1 τ f I 2 τ 2 (32) Fe f=110psec (4.12) κ v = I 2 ( 1 τ f 1 τ 2 ) I 1 = µ v c v (33)

9 C (26) (26) i=3 CONTIN-PALS-II Gregory (4.8) n n T( t) = I i λ i exp λ i t i=1 I (34) T( t) = I( λ)λ exp( λt) dλ 0 (35) I( ) (35) F(t) S(t)=F(t)*T(t) Sr(t), S(t) N F(t) T(t) ( t) = N r F( t) *T r ( t) S( t) = N F( t)* T( t) S r (4.18) S( t)* T r t = NN r 1 T t * S r t (36) (37)

10 Tr(t) S( s)t r ( s) = NN 1 r T( s)s r s T r ( t) = I( λ)exp( st) exp( λ r t )dt 0 (37) = λ r λ r + s (38) Intensity (%) S(t)(37) (38) S( t) = NN 1 r λ 1 1 r I r λ I( λ) { 1+ ( λ λ)s t 0 r r * exp ( λt )}dλ (39) = P( λ) s t 0 N L K( λ,t)dλ + β i L i t i =1 P λ (40) = λi( λ) (41) (41) RI (x10) Neutron Irradiation(KUR) Fe0.22%Cu Alloy at 100K -ray Ge-detector scintilator start signal -ray 1.275MeV 22 Ne 22 Na Positron Annihilation rate λ(/nsec) scintilator -ray 0.511MeV stop signal sample

11 (19) START SIGNAL Constant Fraction Discriminator High Voltaged Photomultiplier Preamplifier Amplifier Timing SCA BaF2 Identified Specimens High Voltaged BaF2 γ (1.28MeV) γ (0.511MeV) Photomultiplier 22Na (positron source) Preamplifier Amplifier FAST COINCIDENCE Timing SCA BIASED TIME TO PULSE HIGHT CONVERTER Multi Channel Analyzer STOP SIGNAL Constant Fraction Discriminator DELAY MeV 1/KT 0.025eV p L (i) γ 1, γ 2 E 1, E 2, m e +, m e m e + = m e c E 1, E 2 = 2mc 2 (42) 2E γ = E 1 + E 2 E 1 = E 2 (43)

12 E 1 = mc 2 = 0.511MeV (44) E 2 = mc 2 = 0.511MeV (45) (ii) p L p 1, p 2 2mc 2 = cp 1 + cp 2 (46) p 1 p 2 = p L (47) (46),(47) E 1 = cp 1 = mc 2 + cp L 2 = 0.511MeV + cp L 2 (48) E 2 = cp 2 = mc 2 cp L 2 = 0.511MeV cp L 2 (49) p L 0.511MeV cp L /2 511keV 180 py

13 I(θ)=π(p 2 F -(mc* θ) 2 ) θ p T /m 0 c (50) mrad m Positron Affinity A+ (ev) Positron Affinity Li Na Al K Sc V Mn Co Cu Ge Sr Zr Mo Ru Pd Cd Cs Lu Ta Re Ir Au Elements 2 (A,B) AB Δ AB = µ A µ B µ A µ B

14 µ A + µ B + Δ + AB = µ A B + µ + ΔE A,B + ΔE A,B + = Δ + AB Δ AB µ B B ( + µ + ) = µ A + µ + A A + A + = µ + + µ ΔE A,B + = A A B + A + ΔE A,B + ΔE A,B + 1 2

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